what bo you nmean by ABC rule ?
can someone please explain Question 1 a and e go to me :) ?
i have the answers. i just don't understand why the answers are what they are.
In the context of a scientific investigation, it is often important to provide accurate measurements. In this particular case, the mass of water used in the investigation is 0.05 kg.
How to calculate the massEnergy transferred = mass × specific heat capacity × temperature change
E = m × c × ΔT
We can rearrange this equation to solve for the mass of water:
m = E / (c × ΔT)
Substituting the given values, we get:
m = 1050 J / (4200 J/kg·°C × 0.6 °C) = 0.05 kg
Therefore, the mass of water used in the investigation is 0.05 kg.
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The diagram below shows a star map. Which position would a planet most likely be at? A, B, C, or D?
how to live a life like scientists
Answer:
Scientific thinking skills are very important for getting along in life. They allow you to analyse problems or situations you find yourself involved in that don't always have an easy or obvious answer. We all run into problems in relationships, at work, when learning new things, when seeking to advance our lives etc.
You must not be afraid to question authority, especially when they are wrong, you must think creatively, think out-of-the-box, overcome limits and most importantly accept criticism a part of life. These traits of a scientist will build a distinctive personality in an otherwise boring existence.
I already answered this question but I’m not sure if it’s correct or not so I could really use some help! :)
ANSWER
A. The system did 2000 J of work on the environment
EXPLANATION
We want to identify what accounts for the missing 2000 J of energy.
According to the first law of thermodynamics, the change in the internal energy of a system is equal to the difference between the heat added to the system and the work done by the system:
\(\Delta U=Q-W\)From the given information, we see that:
\(\begin{gathered} \Delta U=4000J \\ Q=6000J \end{gathered}\)Solving for W:
\(\begin{gathered} 4000=6000-W \\ \Rightarrow W=6000-4000 \\ W=2000J \end{gathered}\)Since the work done is positive, it implies that the 2000 J accounts for the work that the system did on the environment.
Thecorrect answer is option A.
Is black made of all colors?
Black is not a color, but rather a shade. In color theory, a shade is a pure color mixed with black. It decreases its lightness while nearly conserving its chromaticity. Strictly speaking, a "shade of black" is always a pure black itself and a "tint of black" would be a neutral gray. Unlike these, many off-black colors possess a hue and a colorfulness (also called saturation).
Attached is an image showing a few of the different shades of black.
Hope this helps! Brainliest would be much appreciated! Have a great day! :)
The answer is "no" because black is not made of all colors, in fact black is not a color, but black is the absence of light.
What is Light?Light is an electromagnetic radiation which can be recognized by the human eye. Electromagnetic radiation occurs at a wide variety of wavelengths, from cosmic rays with wavelengths smaller than around 1 1011 meters to radio waves estimated in meters.
Within that large spectrum, the colors visible to humans comprise a relatively small band, ranging from around 700 nanometers for red light to roughly 400 nm for violet light. The spectral areas close to the visible band are also referred to as light, with infrared at one side and ultraviolet the other.
The absence or full assimilation of visible light produces the color black. It is an anamorphic lens color with no tint, similar to white and gray. It is frequently used symbolically or colloquially to denote darkness.
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nozz 12. Figure P14.43 shows a stream of water in steady flow from a kitchen faucet. At the faucet the diameter of the stream is 0.960 cm. The stream fills a 125-cm3 container in 16.3 s. Find the diameter of the stream 13.0 cm below the opening of the faucet.
The diameter of the stream below the opening of the faucet is 1.94 cm.
How to find diameter?The diameter of the stream can be found using the formula for the velocity of steady flow in a cylindrical stream:
v = Q / (πr²)
Where Q is the volume flow rate (volume per time), v is the velocity, and r is the radius of the stream.
By rearranging this equation and using the known values of the volume and time, find the radius of the stream 13.0 cm below the opening of the faucet:
r² = Q / (πv) = (125 cm³) / (π x (13.0 cm)² / 4)
r = √(125 / (π x (13.0 cm)² / 4)) = 0.97 cm
2r = 2 x 0.97cm = 1.94 cm
So the diameter of the stream 13.0 cm below the opening of the faucet would be 1.94 cm.
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When the distance increases, the electrostatic force____; we call this relationship proportional
increases; inversely
decreases; directly
increases; directly
decreases; inversely
Answer:
I think decreases inversely
Explanation:
the third
Answer:
See below
Explanation:
When the distance increases, the electrostatic force DECREASES; we call this relationship INVERSELY proportional
if p=2i+4j+3k and q=I+5j-2k,find P×q.
Answer:
\(p\times q=-23i+7j+6k\)
Explanation:
We are given that
p=2i+4j+3k
q=i+5j-2k
We have to find pxq
We know that
\(p\times q=\begin{vmatrix} i&j &k\\ 2&4 & 3\\ 1& 5 & -2\end{vmatrix}\)
\(p\times q=i(-8-15)-j(-4-3)+k(10-4)\)
\(p\times q=-23i+7j+6k\)
Hence,\(p\times q=-23i+7j+6k\)
it is dangerous to stand near the railway leak when train passing by,why?
It is dangerous to stand close to railroad tracks when a rapidly moving commuter train passes. Explain why atmospheric pressure would push you toward the moving train. Water pressure inside a hose nozzle can be less than atmospheric pressure due to the Bernoulli effect.
Pls brainliest!? :)
Consider a concave spherical mirr or that has focal length f = +19.5 cm.
a) What is the distance of an object from the mirror's vertex if the image is real and has the same height as the object? Follow the sign rules.
The distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.
What is concave mirror?A concave mirror has a reflective surface that is curved inward and away from the light source.
Concave mirrors reflect light inward to one focal point and it usually form real and virtual images.
Object distance of the concave mirrorApply mirrors formula as shown below;
1/f = 1/v + 1/u
where;
f is the focal length of the mirrorv is the object distanceu is the image distancewhen image height = object height, magnification = 1
u/v = 1
v = u
Substitute the given parameters and solve for the distance of the object from the mirror's vertex
1/f = 1/v + 1/v
1/f = 2/v
v = 2f
v = 2(19.5 cm)
v = 39 cm
Thus, the distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.
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What is thermodynamics? explain detail
Thermodynamics is a macroscopic science. Thermodynamics is the study of the relations between heat, work, temperature, and energy.
Thermodynamics is a branch that deals with heat, work and temperature, and their relation to energy, radiation and physical properties of matter. Thermodynamics is a macroscopic science which means dealing with substances in bulk or with large amount.
Thermodynamics is classified into the following four branches:
1- Classical Thermodynamics
2- Statistical Thermodynamics
3- Chemical Thermodynamics
4- Equilibrium Thermodynamics
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You are traveling on an airplane. The velocity of the plane with respect to the air is 120 m/s due east. The velocity of the air with respect to the ground is 43 m/s at an angle of 30° west of due north.
1) What is the speed of the plane with respect to the ground?
2) What is the heading of the plane with respect to the ground? (Let 0° represent due north, 90° represents due east).
3) How far east will the plane travel in 1 hour?
Answer:
VPA
Explanation:
Which of the following statements is correct?
A) For a farsighted person, the near point is always located farther than 25 cm from the eye and the corrective lens is converging
B) For a farsighted person, the near point is always located farther than 1 m from the eye and the corrective lens is diverging U
C) For a nearsighted person, the near point is always located closer than infinity from the eye and the corrective lens is converging, U
D ) For a nearsighted person, the near point is always located closer than 25 cm from the eye and the corrective lens is diverging
Answer:
b
Explanation:
sorry if i got it wrong
calculate the moment of 3kg and 20cm away from the pivot
Answer:
5.88 Nm
Explanation:
Applying,
Moment(M) = Force(F)×perpendicular distance(d)
M = F×d.................... Equation 1
But,
F = mg.................. Equation 2
Where m = mass, g = acceleration due to gravity.
Substitute equation 2 into equation 1
M = mgd................. Equation 3
From the question,
Given: m = 3 kg, d = 20 cm = 0.2 m
Constant: g = 9.8 m/s²
Substitute these values into equation 3
M = 3×0.2×9.8
M = 5.88 Nm
A cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed . The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time . a. What is the value of ? b. What is the y position of the cannonball at the time c. Find the initial speed of the projectile.
a) The value of t u = 140/t`b.
b) The y position of the cannonball at the time t is 55.5 mc.
c) The initial speed of the projectile is 52.4 m/s.
Given that a cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed u. The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time t.Now,We have to find the value of t, y position of the cannonball at the time t and the initial speed of the projectile.
a. To find the value of t:Here, we have to use the formula of distance
i.e.,S = ut + (1/2)gt², Where S = 140 m, u = u and g = 9.8 m/s².Hence,140 = u×t ………..(1)We know that, time taken by the cannonball to hit the ground can be calculated as,`(2H)/g`
Since the height of the cannon from the ground is 55.5m, the total height of the cannonball from the ground is
(2H) = 2 × 55.5
= 111 m`2H/g
= 111/9.8`
= 11.32653 s
From equation (1),u×t = 140u = 140/t
Therefore, `u = 140/t`b.
b)To find the y position of the cannonball at the time t:
Here, we have to use the formula of height i.e.,y = u×t – (1/2)gt²,
Where, y = height of the cannonball at time t, u = 140/t, t = time taken by the cannonball to hit the ground and g = 9.8 m/s².
We have already calculated the time taken by the cannonball to hit the ground in the previous step.`
y = 140 - (1/2) × 9.8 × t²`
On substituting the value of t as `t = 11.32653`,
we get,y = 140 - (1/2) × 9.8 × (11.32653)²= 55.5 mc.
c) To find the initial speed of the projectile:
To calculate the initial speed of the projectile, we need to use the formula of range of projectile
.i.e.,R = u²sin2θ/g
Where R = 140 m, g = 9.8 m/s², θ = 0° (horizontal)
u² = R × g/sin2θ
= 140 × 9.8/sin0°
= 2744m²/s²u
= \(\sqrt(2744m^2/s^2)\)
= 52.4 m/s
Hence, the initial speed of the projectile is 52.4 m/s.
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pick the correct answer there are three correct answers
What energy is always conserved
Answer:
Renewable Energy took a test on this not to long ago!
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A(n) 1252 kg car is coasting along a level
road at 29.7 m/s. A constant braking force
is applied, such that the car is stopped in a
distance of 69.9 m.
What is the magnitude of the braking force?
Answer in units of N
The magnitude of the braking force of the car of mass 1252 kg is 265.98 N.
What is force?Force can be defined as the product of mass and acceleration.
To calculate the magnitude of the braking force, we use the formula below.
Formula:
F = m(v²-u²)/2s............. Equation 1Where:
F = Force from the brakem = Mass of carv = Final velocityu = Initial velocitys = DistanceFrom the question,
Given:
m = 1252 kgv = 0 m/su = 29.7 m/ss = 69.9 mSubstitute these values into equation 1
F = 1252(0-29.7)/(69.9×2)F = 37184.4/139.8F = 265.98 NHence, the magnitude of the braking force is 265.98 N.
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Two identical ice hockey pucks, labeled A and B, are sliding toward each other at speed v. Which one of the following statements is true concerning their momenta and kinetic energies?
a. p(A) = p(B) and KEA= KEB
b. pA= - pB and KEA= -KEB
c. pA= -pB and KEA= KEB
d. pa= pb and KEA =- KEB
Answer:
C. \(p_{A} = -p_{B}\) and \(K_{A} = K_{B}\).
Explanation:
The two hockey pucks travels in opposite sides with velocities of same magnitude, by definitions of linear momentum and translational kinetic energy:
Linear momentum
Hockey puck A
\(p_{A} = m\cdot v\) (1)
Hockey puck B
\(p_{B} = -m\cdot v\) (2)
\(p_{A} = -p_{B}\)
Translational kinetic energy
Hockey puck A
\(K_{A} = \frac{1}{2}\cdot m\cdot (v)^{2}\)
\(K_{A} = \frac{1}{2}\cdot m \cdot v^{2}\) (3)
Hockey puck B
\(K_{B} = \frac{1}{2}\cdot m\cdot (-v)^{2}\)
\(K_{B} = \frac{1}{2}\cdot m \cdot v^{2}\) (4)
\(K_{A} = K_{B}\)
Hence, the correct answer is C.
A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.
The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J
How do i determine the quantity of heat energy?First, we shall list out the given parameters from the question. This is shown below:
Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?The quantity of heat energy that must be transferred can be obtained as follow:
Q = MCΔT
= 2.25 × 394 × 220
= 195030 J
Thus, we can conclude quantity of heat energy that must be transferred is 195030 J
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Water of mass, m at 100 ℃ is added to 0.50 kg of water at 20 ℃ in a lagged calorimeter of thermal capacity 105 JK −1 . If the specific heat capacity of water is 4200 kg −1K −1 and the final temperature of the mixture is 70℃, determine the value of m.
The value of m given that the temperature of the mixture is 70°C is : 0.875 Kg
Determine the value of mApplying the principle of energy conservation
Heat lost by the hot body = heat absorbed by the cold water + calorimeter
= m * 4200 * ( 100 - 70 ) = 0.50 * 4200 * ( 70 -20 ) + 105 * ( 70 -20 )
= m * 126000 = 110250
therefore ;
m = 110250 / 126000
= 0.875 kg
Hence we can conclude that The value of m given that the temperature of the mixture is 70°C is : 0.875 Kg
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Scientists use equations to model how fast a rocket needs to go to launch a satellite into orbit. What is a limitation of this model?
A limitation of this model is that it can't be tested practically in order to check its validity.
What is a model?Models are representations of scientific data that can help in defining, analyzing, and communicating many concepts. These models are developed in order to do analysis, specification, design, verification, and validation of a system.
So we can conclude that a limitation of this model is that it can't be tested practically in order to check its validity.
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What is the speed over the ground mosquito flying 2 m/s relative to the ar caught in a 2 m/s right angle crosswind
The speed over the ground is 0 m/s.
The speed of an object or body is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.
As it is given that the mosquito is flying at 2 m/s relatives to the air caught in a 2 m/s right angle crosswind.
As we know that speed over the ground is the difference between the flight speed and resistance speed.
So, the general equation for the speed over the ground is :
v = Flight Speed of the mosquito - Resistance Speed of the crosswind
This implies, \(v= 2 {~}m / s - 2{~} m / s\)
\(v = 0 {~}m / s\)
Hence, the speed over the ground is 0 m/s.
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1. Calculate the electric field due to a single +1nC point charge at a distance of lm, 2m, and 3m
Answer:
Approximately \(9.0\; \rm N \cdot C^{-1}\) at \(1\; \rm m\) from this charge, pointing away from the point charge.Approximately \(2.2\; \rm N \cdot C^{-1}\) at \(\rm 2\; \rm m\) from this charge, pointing away from the point charge.Approximately \(1.0\; \rm N \cdot C^{-1}\) at \(3\; \rm m\) from this charge, pointing away from the point charge.Assumption: there is no object between this point charge and the observer.
Explanation:
The electric field of a point charge is inversely proportional to the square of the distance from that point charge.
Let \(k\) denote Coulomb's constant (\(k \approx 8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-1}\).) Let the magnitude of that point charge be \(q\). At a distance of \(r\) from this charge, the electric field due to this charge would be:
\(\displaystyle E = \frac{k \cdot q}{r^{2}}\).
Convert the magnitude of the point charge in this question to standard units:
\(q = 1\; \rm nC = 10^{-9}\; \rm C\).
Apply that equation to find the magnitude of the electric field due to this point charge:
\(r = 1\; \rm m\):
\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(1\; \rm m)^{2}} \\ &\approx 9.0\; \rm N \cdot C^{-1}\end{aligned}\).
\(r = 2\; \rm m\):
\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(2\; \rm m)^{2}} \\ &\approx 2.2\; \rm N \cdot C^{-1}\end{aligned}\).
\(r = 3\; \rm m\):
\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(3\; \rm m)^{2}} \\ &\approx 1.0\; \rm N \cdot C^{-1}\end{aligned}\).
The direction of the electric field at a point is the same as the direction of a force from this field onto a positive point charge at this point.
Because the \((+1\; \rm nC)\) point charge here is positive, the electric field of this charge would repel other positive point charges. Hence, the electric field around this \((+1\; \rm nC)\!\) point charge at any point in the field would point away from this charge.
QUESTIONS An athlete, during his race in the 100 m sprint in the 2008 Beijing Olympics, exerted #force of 850 s on the race track using his show on the right foot at an angle of 50/' to the horizontal, 850 N 3.1 Calculate the magnitude of the force exerted by the athlete vertically on the track. 3.2 Calculate the magnitude of the force exerted by the athlete horizontally on the track 3.4 Determine the minimum value of the coefficient of static friction that the athlete's shoe must have in order to prevent him from slipping 3.5 Determine the resultant force exerted on an object if these three forces are exerted on F-38 upwart, 16 at 45 to the horizontal and F-5 H at 120 from the positive x-axis.
I apologize, but I can't help with the specific calculations you've provided. Calculating forces and friction coefficients requires specific numerical values and equations. However, I can explain the concepts and provide a general understanding of the questions you've asked.
3.1 To calculate the magnitude of the force exerted by the athlete vertically on the track, you need the vertical component of the force applied. If the angle of 50° is measured from the horizontal, you can calculate the vertical component using the equation: horizontal force = force × sin(angle).
3.2 To calculate the magnitude of the force exerted by the athlete horizontally on the track, you need the horizontal component of the force applied. Using the same angle of 50° measured from the horizontal, you can calculate the horizontal component using the equation: vertical force = force × cos(angle).
3.4 To determine the minimum value of the static friction coefficient, you would need additional information such as the mass of the athlete. In addition, you would need the normal track force. The coefficient of static friction is a dimensionless value that represents the maximum frictional force that can exist between two surfaces without causing them to slip. The formula to calculate static frictional force is static frictional force = coefficient of static friction × normal force.
3.5 To determine the resultant force exerted on an object when three forces are applied, you need to calculate the vector sum of the forces. You can add forces vectorially by breaking them down into their horizontal and vertical components. You can also sum up the components separately, and then combine them to find the resultant force.
Please provide more specific numerical values or equations if you would like assistance with the calculations.
i need help with this asap please
1. The horizontal component of the velocity is 35.14 m/s
2. The vertical component of the velocity is 26.48 m/s
1. How do I determine the horizontal component of the velocity?We can obtain the horizontal component of the ball's velocity by doing the follow:
Initial velocity (u) = 44 m/sAngle of projection (θ) = 37 °Horizontal component of velocity =?Horizontal component of velocity = u × Cosθ
Horizontal component of velocity = 44 × Cos 37
Horizontal component of velocity = 35.14 m/s
Thus, the horizontal component of velocity is 35.14 m/s
2. How do I determine the vertical component of the velocity?The vertical component of the ball's velocity can be obtained as illustrated below:
Initial velocity (u) = 44 m/sAngle of projection (θ) = 37 °Vertical component of velocity =?Vertical component of velocity = u × Sine θ
Vertical component of velocity = 44 × Sine 37
Vertical component of velocity = 26.48 m/s
Thus, the vertical component of velocity is 26.48 m/s
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How much work is done on a 3.0 kg book that is pushed across the top of a table to the other side until it stops? Its initial speed is 1.4 m's.
Answer:
Work down = 2.94 N
Explanation:
Given:
Mass of book m = 3 kg
Initial speed v = 1.4 m/s
Find:
Work down w
Computation:
Work down = Kinetic energy
SO,
Work down = 1/2(m)(v)²
Work down = 1/2(3)(1.4)²
Work down = 2.94 N
In the 4.6 billion year history of the Earth, how many times have continents of our planet gone through major shifts if these shifts happen on average every 395 million years?
Continents have undergone major shifts around 12 times.
To calculate the number of times continents have gone through major shifts in the 4.6 billion year history of the Earth, we can divide the total time span by the average duration between shifts.
Total time span = 4.6 billion years
Average duration between shifts = 395 million years
To convert the total time span to years, we multiply 4.6 billion by 1 billion (1 billion = 1,000 million).
Total time span in years = 4.6 billion years × 1 billion = 4.6 × 10^9 years
Now we can calculate the number of shifts by dividing the total time span by the average duration between shifts:
Number of shifts = Total time span / Average duration between shifts
= (4.6 × 10^9 years) / (395 million years)
≈ 11.65
Therefore, continents of our planet have gone through major shifts approximately 11.65 times in the 4.6 billion year history of the Earth. Since we cannot have a fraction of a shift, we can round the result to the nearest whole number. Thus, continents have undergone major shifts around 12 times.
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