What is the formula for displacement? *

1- Final position minus initial position
2- Relation to a reference point plus distance travelled
3- Distance divided by time
4- Speed times vector

Answer:

I believe it's qualitative and continuous.

Explanation:

Answer:

Continuous, and Quantitative

Hope this helps :)

The central carbon atom in glycine has four atoms and two lone pairs of electrons. Therefore, the electron geometry of the central carbon atom is octahedral, with bond angles of 90°, 180°, and 120°.The next step is to determine the molecular geometry. The molecular geometry in glycine is distorted tetrahedral, with bond angles of 120°.The approximate c-n-h bond angle in glycine is 120°.

The VSEPR theory defines that lone pairs occupy larger regions in space than bonding pairs. The VSEPR theory assumes that electron pairs are situated around the central atom in a way that minimizes electron-pair repulsions to form a shape that maximizes the distance between them. Therefore, in glycine, the approximate c-n-h bond angle is 120°. Thus, the correct option is (c) 120°.Explanation:The Lewis structure of Glycine:Glycine has 4 atoms and 2 lone pairs of electrons. It is an amino acid with NH2 as the amino group and COOH as the carboxylic group.Glycine Lewis structureGlycine molecule has two -CH2 groups on either side of the central carbon atom, to which the amino group and carboxyl group are attached. To determine the shape of the molecule, it is essential to understand the Lewis structure of the molecule. The next step involves the determination of the number of atoms and electron pairs around the central carbon atom.The VSEPR theory defines that the geometry of the molecule depends on the electron pairs' number in the central atom. The central carbon atom in glycine has four atoms and two lone pairs of electrons. Therefore, the electron geometry of the central carbon atom is octahedral, with bond angles of 90°, 180°, and 120°.The next step is to determine the molecular geometry. The molecular geometry in glycine is distorted tetrahedral, with bond angles of 120°.The approximate c-n-h bond angle in glycine is 120°.

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The change that has taken place in the COV-2 due to the substitution of a valine with a lysine involves the interface and binding strength between COV-2 and ACE2.

1. Interface: The interface refers to the surface where two molecules, such as COV-2 and ACE2, interact with each other. Comparing the interface between COV and ACE2 to that between ACE2 and COV-2 reveals variations that affect their interaction.

2. Binding: The binding between COV-2 and ACE2 is crucial for the virus to enter host cells. The stronger the binding, the more effective the virus is at infecting cells.

3. Lysine: Lysine is an amino acid that is replacing valine in COV-2. This substitution affects the binding strength between COV-2 and ACE2.

The substitution of valine with lysine in COV-2 has likely led to an increase in the binding strength between COV-2 and ACE2. Lysine, as a basic amino acid, can form stronger electrostatic interactions with the acidic amino acids present in the ACE2 interface. This stronger binding may enhance the ability of COV-2 to enter host cells, compared to COV.

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From the balanced chemical equation:

6HBr + KBrO3 -> 3Br2 + KBr + 3H2O

We can see that the molar ratio between HBr and KBrO3 is 6:1.

For every 6 moles of HBr, we need 1 mole of KBrO3 to ensure the reaction proceeds according to the stoichiometry.

Therefore, the molar ratio of HBr to KBrO3 in this reaction is 6:1.

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Answer:

Rate cup 1: 36.00 tsp/h.

Rate cup 2: 59.50 tsp/h.

Rate cup 3: 70.13 tsp/h.

Explanation:

Based on the given example, the units must be in tsp/hour. To do this we just have to divide tsp by seconds and then convert it to hours remembering that 1 hour equals 3600 seconds.

Let's calculate each case:

- Cup 1: 1 tsp, 1 minute 40 seconds. Remember that 1 minute equals 60 seconds, so 1 minute and 40 seconds equals 100 seconds. The calculation of the rate will look like this:

The rate of cup 1 is 36.00 tsp/h.

- Cup 2: 2 tsp, 2 minutes 1 second. As we saw before 1 minute equals 60 seconds, so 2 minutes equals 120 seconds. 2 minutes and 1 second equals 121 seconds. The rate of cup 2 will be calculated as:

The rate of cup 2 is 59.50 tsp/h.

- Cup 3: 3 tsp, 2 minutes 34 seconds. 2 minutes are the same that 120 seconds, so 2 minutes 34 seconds equals 154 seconds. The rate of cup 3 is calculated as follows:

The rate of cup 3 is 70.13 tsp/h.

The mass of (NH4) 2S in the solution is : Mass = 0.0600 mol × 60.08 g/mol = 3.60 g.

The given molarity and volume of the solution can be used to calculate the number of moles of ammonium sulfide (NH4)2S.Then, the number of moles can be converted to mass using the molar mass of (NH4)2S.Mass of ammonium sulfide (NH4)2S in 3.00 L of a 0.0200 M solution is given by : Mass = moles × molar mass.The number of moles of (NH4)2S can be found using the equation:Molarity = Number of moles / Volume.Rearranging this equation, we get:Number of moles = Molarity × Volume Number of moles of (NH4)2S = 0.0200 M × 3.00 L.Number of moles of (NH4)2S = 0.0600 mol.The molar mass of (NH4)2S can be calculated by summing the molar masses of ammonium (NH4) and sulfide (S) ions.Molar mass of (NH4)2S = (2 × Molar mass of NH4) + Molar mass of S= (2 × 14.01 g/mol) + 32.06 g/mol= 60.08 g/mol.

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Numerator (A): P1V1, Denominator (B): T1V2

In the combined gas law equation, "StartFraction P subscript 1 V subscript 1 over T subscript 1 EndFraction equals StartFraction P subscript 2 V subscript 2 over T subscript 2 EndFraction," if we rearrange it to solve for the final pressure, we get "P subscript 2 equals StartFraction A over B EndFraction." The variables in the numerator are P1V1, and the variables in the denominator are T1V2.

The combined gas law states that the product of the initial pressure (P1) and volume (V1), divided by the initial temperature (T1), equals the product of the final pressure (P2) and volume (V2), divided by the final temperature (T2). If we rearrange the equation to solve for the final pressure (P2), we get P2 = (P1V1T2) / (T1V2). Therefore, the variables in the numerator are P1V1, and the variables in the denominator are T1V2.

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To solve for final pressure using the combined gas law, rearrange the equation and identify the variables in the numerator and denominator.

The given equation is StartFraction P subscript 1 V subscript 1 over T subscript 1 EndFraction equals StartFraction P subscript 2 V subscript 2 over T subscript 2 EndFraction.

To solve for final pressure (P2), we need to rearrange the equation. The variables that would be in the numerator (A) are P1V1, and the variables in the denominator (B) are T1V2.

Therefore, the rearranged equation to solve for final pressure (P2) is P subscript 2 equals StartFraction P subscript 1 V subscript 1 over T subscript 1 EndFraction multiplied by StartFraction T subscript 2 over V subscript 2 EndFraction.

The carburizing time necessary to achieve a carbon concentration of 0.30 wt% at a position 4 mm into an iron-carbon alloy is 63.4 hours.

To determine the carburizing time necessary to achieve a carbon concentration of 0.30 wt% at a position 4 mm into an iron-carbon alloy, we can use Fick's second law of diffusion:

\(DC_{surface} / 2 = (C_{surface} - C_{4mm}) / erf(x / (2 * \sqrt{Dt} ))\\\)

where D is the diffusion coefficient, \(C{surface}\\\) is the surface carbon concentration (0.90 wt%), C_4mm is the carbon concentration at the position 4 mm into the alloy (0.10 wt%), x is the distance from the surface (4 mm), and t is the carburizing time we want to find.

We can use the diffusion coefficient for γ-Fe at 1100°C from Table 5.2, which is D = \(6.0 * 10^{-12} m^2/s.\)

Substituting the given values, we get:

\((6.0 * 10^{-12} m^2/s) * (0.90 - 0.30) / 2 = (0.90 - 0.10) / erf(4 mm / (2 * \sqrt{6.0 * 10^{-12} m^2/s} ))\)

Simplifying the left-hand side, we get:

\(1.8 * 10^{-12} m^2/s = (0.80) / erf(4 mm / (2 * \sqrt{(6.0 * 10^{-12} m^2/s) * t)})))\)

Taking the inverse error function of both sides, we get:

\(erf(4 mm / (2 * \sqrt{6.0 * 10^{-12} m^2/s) * t)} ) = 0.000346\)

Substituting this back into the previous equation, we get:

\(1.8 * 10^{-12} m^2/s = (0.80) / 0.000346\)

Solving for t, we get:

t = 63.4 hours

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In serial order  balanced chemical equations are N₂ + 3 H₂\(\rightarrow\) 2 NH₃,2 KClO₃\(\rightarrow\) 2 KCl +3 O₂,2 NaCl +F₂\(\rightarrow\) 2 NaF +Cl₂,2 H₂ +O₂\(\rightarrow\)2 H₂O and they are synthesis,decomposition,single displacement ,synthesis reactions respectively.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

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From the concept of partial pressure in equilibrium, the Kp of the reaction is 7.67 at the given temperature.

Kp is an equilibrium constant based on partial pressures. It tells you the ratio of products to reactants in a reaction at equilibrium. Kp is very similar to Kc. Like Kc, Kp always has the same value for a specific reversible reaction under specific conditions. This means that we can use it to accurately predict the proportions of reactants and products in a reaction at equilibrium. For the Kp for a reaction given the partial pressures of the products and reactants in an equilibrium mixture. The reaction given is Br2(g) + Cl2(g) ⇌ 2BrCl(g). Kp is the equilibrium constant in terms of partial pressures.

It is given as: Kp = p(BrCl)² / p(Br₂) x p(Cl₂)

Given that the partial pressures of Br2, Cl2, and BrCl are 1.12 atm, 1.26 atm, and 3.14 atm, respectively:

p(Br₂) = 1.12 atmp(Cl₂) = 1.26 atmp(BrCl) = 3.14 atm,

The Kp of the reaction is:

Kp = p(BrCl)² / p(Br₂) x p(Cl₂)

Kp = (3.14) ² / (1.12) (1.26)

Kp = 7.67 (rounded off to two decimal places).

Therefore, the Kp of the reaction is 7.67 at the given temperature.

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Answer:

hi this it for the Instructions: In this engineering lab, you will build and test a device that releases and absorbs

thermal energy in order to reach a goal. You will need to repeat tests of your device to make sure it

does not need to be redesigned or improved. Record your observations and test measurements in

the lab report below. You will submit your completed report. yea that thing the answer is in the file

Explanation:

sorry for telling you on this :( but i hope this helps

Answer:

increase in the temperature and decrease in pressure will do because it need to liberate heat

An atom's nucleus is surrounded by electrons and protons and neutrons, each with a unique energy level. The Pauli exclusion principle shows how to fill orbitals with electrons in the proper order.

Pauli's exclusion principle is a fundamental principle of quantum mechanics that states that no two fermions can occupy the same quantum state simultaneously. Fermions are a class of subatomic particles that include electrons, protons, and neutrons, and are distinguished by their half-integer spin.

The exclusion principle is named after the Austrian physicist Wolfgang Pauli, who formulated it in 1925. The principle is based on the wave nature of matter and the fact that fermions are described by wave functions that obey the Schrödinger equation.

Energy order of orbital

1s<2s<2p<3s<3p<4s<3d<4p<5s<4d<5p<6s<4f<5d

An atom's nucleus is its main structural component. It is surrounded by electrons and has protons and neutrons inside. These electrons all share the same mass and charge, though. An atom's electrons each have a unique energy level. The positively charged nucleus's strongest attractive force is felt by the electrons nearest to it, which have the lowest energy. Higher energy electrons are located farther away.

The Pauli exclusion principle demonstrates how to fill orbitals with electrons in the proper order.

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Comparative anatomy is the study of similarities and differences between the body structures of different species. The study of comparative anatomy supports the theory of natural selection and evolution.

Here's how:How comparative anatomy supports the theory of natural selection and evolution?Charles Darwin, the father of the theory of evolution, recognized that different species share common anatomical features, such as a similar bone structure. He hypothesized that if a species could use the same bone structure to perform different functions, the bone structure could be adapted over time to perform these new functions better.

This was a radical idea at the time because most scientists believed that species were created separately. However, Darwin's ideas were supported by the study of comparative anatomy, which showed that many species share similar structures, indicating that they share a common ancestor. Comparative anatomy also shows that species have adapted over time to perform new functions as they evolved.Comparative anatomy has also helped scientists understand the evolutionary history of different species. By comparing the structures of different species, scientists can identify which structures evolved first and how they evolved over time. This helps scientists create a timeline of how different species have evolved over millions of years.Comparative anatomy is just one of many pieces of evidence that supports the theory of natural selection and evolution. However, it is an important piece of evidence because it shows that different species share a common ancestry and have adapted over time to better survive in their environment.

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Answer:

3. Bacteria

Explanation:

If you don't trust me, search it up!

The specific heat capacity of a substance is the amount of energy required to raise the temperature of 1g of the substance by 1K.

Calculating the change in temperature:

By substituting what we are given into the equation to solve for the unknow x we have;

Answer: Energy needed is 449.35J

Hi! To briefly summarize the chemical pathway to get from acetylsalicylic acid (pure or in the tablet) to the colored iron-salicylate complex, we will go through the following steps:

1. Hydrolysis of acetylsalicylic acid: First, acetylsalicylic acid undergoes hydrolysis in the presence of a base (e.g., sodium hydroxide, NaOH) to form salicylic acid and acetic acid.

  Acetylsalicylic acid + NaOH → Salicylic acid + Sodium acetate

2. Formation of salicylate ion: Next, salicylic acid deprotonates to form the salicylate ion, which is the anion form of salicylic acid, in an alkaline solution.

  Salicylic acid + OH⁻ → Salicylate ion + H₂O

3. Formation of the iron-salicylate complex: Lastly, the salicylate ion reacts with ferric ions (Fe³⁺) in solution to form the colored iron-salicylate complex. This complex has a purple color that can be used to determine the concentration of acetylsalicylic acid in a solution through spectrophotometry.

  Salicylate ion + Fe³⁺ → Iron-salicylate complex

In summary, acetylsalicylic acid is hydrolyzed to form salicylic acid, which then deprotonates to form the salicylate ion. The salicylate ion reacts with ferric ions to produce the colored iron-salicylate complex.

The chemical pathway from acetylsalicylic acid to the colored iron-salicylate complex involves hydrolysis to form salicylic acid, which then reacts with iron (III) ions to produce the colored complex.

To obtain the colored iron-salicylate complex, first, hydrolyze acetylsalicylic acid (ASA) to form salicylic acid (SA) by adding a base like sodium hydroxide (NaOH):
ASA + NaOH → SA + CH3COONa
Salicylic acid contains a phenol group, which forms a complex with iron (III) ions (Fe3+), producing the colored iron-salicylate complex:
SA + Fe3+ → Fe-SC
In this reaction, the phenol group on the salicylic acid molecule binds to the iron (III) ion, resulting in the formation of a colored complex. The color of the iron-salicylate complex can be used to determine the concentration of ASA present in the sample using a spectrophotometer.

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Secondary amine is what it is. Option (B3-dimethylbutan-2-amine )'s is the primary organic product created during the following reaction. Thus, if more hydrogen is added to carbon, we will obtain the main product, according to the Markovnikov Rule.

As a result, the main product produced by adding hydrogen to carbon-1, which has a higher concentration of hydrogen, and adding bromine to carbon-2 is 2-bromopropane. When a reaction follows Markovnikov's rule, a chemical or product is said to be a major organic product. The tertiary alkyl iodide is the largest byproduct of the second process, which transforms alcohol into alkyl iodide, while the secondary alkyl iodide is the minor byproduct.

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the types of glycine present there in solution and the amount of each kind in the solution, and the pka of both the NH2 group, which ranges from 9 to 78, determines the solution's pH at 3. pH = equiv = 9.78, then.

What is the benefit of glycine?

A picture of glycine

The amino acid glycine has a host of remarkable health advantages. To produce crucial substances like glutathione, creatine, and collagen, your body needs glycine. Additionally, this amino acid may enhance heart health and sleep quality while defending your liver from alcohol-related harm.

Who should avoid glycine intake?

Avoid consuming excessive dosages of a single amino acid over an extended period of time. Avoid using single amino acids in excessive dosages without first consulting a healthcare professional. It is not advised for women to take glycine supplements when they are expecting or nursing.

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The two neutrons at the end of the process can help sustain a chain reaction. Option 1 is correct

Neutrons can start a chain reaction, which is a sequence of nuclear fission processes. A uranium-235 atom may split as a result of a neutron's collision with it, releasing more neutrons. The subsequent collisions between these neutrons and other uranium-235 atoms may break those atoms as well. A lot of energy can be released if this process is allowed to spiral out of control.

The fission of a uranium-235 atom can release the two neutrons at the end of the process. These neutrons can divide other uranium-235 atoms if they collide with them, continuing the chain reaction.

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SO₂ have the largest dipole moment among the given options.

What does dipole moment mean?

The symmetry of the molecules is established using the dipole moment. The molecules would not be symmetrical and have some dipole moment if they included two or more polar links.

The distance between the centers of positive and negative charge multiplied by the amount of the charge is what is used to define the dipole moment. Dipole moment is measured in SI unit is (C m).

According to the given question:

SO₂ is a covalent compound which is polar due to the presence of lone pair of electrons and are held by dipole-dipole forces of attraction.

Hence SO₂ has largest dipole moment out of all given options.

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Answer:

I think it's the last one I'm sorry if it's wrong

Explanation:

it sounds like it fits

Answer:

Overpopulated prey.

Explanation:

Because if you remove the predators from the picture who's gonna eat the prey? So it would only make sense that the prey would overpopulate! Hope this helped! (^-^)

A removal of the predator populations from an ecosystem would most likely result in overpopulated prey.

An ecosystem, sometimes known as just an ecological system, primarily made up of all the species that dwell in the physical environment. These abiotic components are linked via nutrition cycles as well as energy fluxes.

Animals contribute significantly to the transport of nutrients as well as energy through the system by consuming plants and each other. They also influence the biomass concentrations of microbial and plant populations. A removal of the predator populations from an ecosystem would most likely result in overpopulated prey.

Therefore, a removal of the predator populations from an ecosystem would most likely result in overpopulated prey.

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JJ Thomson observed that a cathode ray tube produced a beam of particles traveling from the cathode to the anode. He placed two metal plates on either side of the cathode ray tube and applied a high voltage across the plates. The electric field created by the plates deflects the path of the cathode ray.

Thomson discovered that cathode rays are not composed of light, as was previously believed, but rather of negatively charged particles with a mass thousands of times less than that of the hydrogen atom. Thomson went on to establish that these particles are present in all matter and named them "electrons."Electrons are negatively charged subatomic particles that orbit the nucleus of an atom. JJ Thomson used a cathode ray tube to discover the electron. He discovered that cathode rays are not composed of light, as was previously believed, but rather of negatively charged particles with a mass thousands of times less than that of the hydrogen atom. Thomson went on to establish that these particles are present in all matter and named them "electrons."

Electrons are negatively charged subatomic particles that orbit the nucleus of an atom. JJ Thomson used a cathode ray tube to discover the . When a high voltage is applied to a cathode ray tube, a beam of particles travels from the cathode to the anode. Thomson placed two metal plates on either side of the cathode ray tube and applied a high voltage across the plates. The electric field created by the plates deflects the path of the cathode ray.Thomson discovered that cathode rays are not composed of light, as was previously believed, but rather of negatively charged particles with a mass thousands of times less than that of the hydrogen atom. Thomson went on to establish that these particles are present in all matter and named them "electrons."This discovery led to the development of atomic physics, which has revolutionized our understanding of the universe. Electrons are a fundamental building block of matter and are essential for understanding chemical reactions, electricity, and magnetism. Thomson's discovery of the electron opened up a whole new field of scientific inquiry and helped to lay the foundation for modern physics.

JJ Thomson observed that a cathode ray tube produced a beam of particles traveling from the cathode to the anode, and this led to his discovery of electrons. He discovered that cathode rays are not composed of light, as was previously believed, but rather of negatively charged particles with a mass thousands of times less than that of the hydrogen atom. Thomson's discovery of the electron was a major breakthrough in the field of physics and paved the way for many future discoveries.

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Explanation:

\(CH _{3}CH _{2}COOCH _{2} CH _{2}CH _{2}CH _{2}CH _{2}CH _{3}\)

NAME: Hexylpropenoate

The IUPAC name for O3 is Trioxygen

Trioxygen is one of the three allotropes of the element oxygen

the compound has 3 atoms of oxygen bonded together

The compound is mostly found in the stratosphere where it forms a layer that absorbs ultraviolet rays the radiation  and convert them to thermal energy  preventing them from reaching the planet's surface.

The layer is quakily diminishing because of combining with halogens, especially chlorine and bromine atoms this is because  Trioxygen  is a reactive  gas thats why it compines with bromine and chroline.

The gas also is used in industries for the  purification of air and drinking water bleaching and industrial treatment of wastes.

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starchy sugar filled foods contain carbohydrates since carbohydrates are sugar chains

Answer:

1.5 moles

Explanation:

O   mole weight = 15.999

O2 mole weight = 2 * 15.999 = 31.998 gm

48 / 31. 998  = ~ 1.5 moles

4 liters of the 10% solution are needed.

ω₁ = 4% ÷ 100% = 0.04; mass percentage of 8 liters solution

V₁ = 8 L; volume of 4% solution

ω₂ = 10% ÷ 100% = 0.1; mass percentage of solution

ω₃ = 6% ÷ 100% = 0.06; mass percentage of the final 6% solution

V₂ = ?; volume of 10% solution

V₃ = V₁ + V₂; volume of the final 6% solution

ω₁ · V₁ + ω₂ ·V₂ = ω₃ · V₃; formula to calculate volume of the solution

0.04 · 8 L + 0.1 · V₂ = 0.06 · (8 L + V₂)

0.32 L +  0.1 · V₂ = 0.48 L + 0.06 · V₂

0.04 · V₂ = 0.16 L

V₂ = 0.16 L ÷ 0.04

V₂ = 4 L; volume of the 10% solution

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Answer: Endothermic Reaction

Explanation: