What is the formula for calculating resistance?
Volts / ohms
Volts x ohms
Volts / Current
Current / volts

Answers

Answer 1

The formula for calculating resistance is Volts / Current (option C). Details about resistance can be found below.

What is resistance?

Resistance is a force that tends to oppose motion. It is measured in a unit called ohms (Ω).

The electrical resistance of a circuit component or device is the ratio of the voltage applied to the electric current which flows through it.

The resistance of an object can be calculated by dividing the voltage (V) by its current (I) as follows:

R = V/I

Therefore, the formula for calculating resistance is Volts / Current.

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Related Questions

a certain screw jack has a pitch of 0.1cm and the diameter of the wheel to which the turning effect det up is 50cm. if the efficiency of the jack screw is 40%. what must be the force applied to lift a load of 25,000N?

Answers

A force of approximately 39.77 N must be applied to lift a load of 25,000 N, given the specified pitch of the screw jack and the efficiency of 40%.

The pitch of a screw jack is the distance traveled by the load for each revolution of the screw. In this case, the pitch is given as 0.1 cm, which means that for each complete turn of the screw, the load is lifted by 0.1 cm. The diameter of the wheel to which the turning effect is set up is given as 50 cm, which means that the circumference of the wheel is 50 cm x pi = 157.08 cm.

The efficiency of the jack screw is given as 40%, which means that the actual force required to lift the load is 1/0.4 = 2.5 times the ideal force. Therefore, the ideal force required to lift the load of 25,000 N is:

Ideal force = Load / Mechanical Advantage

The mechanical advantage of a screw jack is given by the formula:

Mechanical Advantage = circumference of wheel / pitch of screw

Substituting :

Mechanical Advantage = 157.08 cm / 0.1 cm = 1570.8

Ideal force = 25,000 N / 1570.8

Ideal force = 15.91 N (to two decimal places)

The actual force required to lift the load is 2.5 times the ideal force:

Actual force = 2.5 x 15.91 N

Actual force = 39.77 N (to two decimal places)

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HELLLLPPPP!!!!!
13.A car has an initial velocity of 2 m/s. If the car accelerates at 3 m/s?, how far will
it have gone after 10 seconds?

Answers

Answer:

170m

Explanation:

\(v_{f}=v_{i}+at\)

\(v_{f}=2+3\cdot10\)

\(v_{f}=32\ \frac{m}{s}\)

The final velocity is 32 meters per second

\(v_{f}^{2}=v_{i}^{2}+2ad\)

\(d=\frac{\left(v_{f}^{2}-v_{i}^{2}\right)}{2a}\)

\(d=170m\)

Therefore, the total distance travelled is 170m

4. A 1500 kg car is rolling at 2.0 m/s. You would like to stop the car by firing a 10 kg blob of
sticky clay at it. How fast should you fire the clay?

Answers

The clay must be 300 m/s fast in other to stop the car.

For the car to stop, The momentum of the car must be equal to the momentum of the clay.

Formula:

MV = mv................. Equation 1

Where:

M = mass of the carV = Velocity of the carm = mass of the clayv = velocity of the clay

Make v the subject of the equation.

v = MV/m................... Equation 2

From the question,

Given:

M = 1500 kgV = 2 m/sm = 10 kg

Substitute these values into equation 2

v = 1500(2)/10v = 300 m/s.

Hence, The clay must be 300 m/s fast in other to stop the car.

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A mass of 4.5 kg is attached to a spring with spring constant 0.5 N/m. The mass-spring system is hooked to a machine that applies a driving force to the mass that is equal to f(t)=5sin3t Newtons. The displacement of the mass-spring system from the spring equilibrium is measured to be 0.4 m, the mass having no initial velocity. Assume that there is no air resistance. Find the position of the mass as a function of time.

Answers

The position of the mass as a function of time is given by x(t) = 0.4sin(3t + φ), where φ is the phase constant.

In this mass-spring system, the driving force applied to the mass is given by f(t) = 5sin(3t) N. The equation of motion for a mass-spring system without air resistance is given by the second-order linear differential equation:

\(m * d^2x/dt^2 + k * x = f(t)\)

where m is the mass (4.5 kg), k is the spring constant (0.5 N/m), and x(t) represents the displacement of the mass from the equilibrium position.

To solve the equation, we assume the solution to be of the form x(t) = A * sin(ωt + φ), where A is the amplitude, ω is the angular frequency, and φ is the phase constant. Substituting this solution into the equation of motion and comparing the coefficients of sin(ωt) on both sides, we can determine the values of A and φ.

Given that the displacement of the mass is 0.4 m, we can deduce that A = 0.4. The angular frequency ω is determined by ω = sqrt(k / m).

Plugging in the given values of k and m, we get ω = sqrt(0.5 / 4.5). With these values, we can now express the position of the mass as a function of time:

x(t) = 0.4sin(ωt + φ)

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useful and inconvenience of frictional force of a soccor player running with soccer boots

Answers

They are useful in providing larger frictional force.

The force produced by two surfaces coming into contact and sliding against one another is referred to as frictional force.

The following variables impact the frictional force: Surface roughness and the amount of force pressing them together have the biggest impact on these forces.

Football shoes have spikes or studs because they offer more frictional force when running on grass than regular shoes do.

The studs make it easier for players to move faster and change directions rapidly without slipping while also preventing them from slipping on the grass.

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Help, I cant do it by myself and I really need this done. Please.

Part One

Text Version
Image shows a lake, a factory, a cloud in the sky, a cow, dead organisms, a tree, and the sun. An arrow from the sun to the tree is labeled A. An arrow from the sky to the tree is labeled B. The sky is labeled C above the cloud. The letter D is in the air and an arrow points from it down to dead organisms. An arrow points from dead organisms to the ground labeled E. An arrow points from the cow into to the sky labeled F. An arrow points from the factory to the sky labeled G. An arrow from the sky to the lake is labeled H above the lake.

Using the diagram above, match the description to the corresponding location in the carbon cycle model. Provide the letter only.
Carbon dioxide is converted to sugar used for food.
Location:
Carbon trapped in fossil fuels is converted to carbon dioxide.
Location:
Organic carbon is converted to fossil fuels.
Location:
Carbon dioxide is converted to carbonates.
Location:
Sugar is broken down and converted to carbon dioxide.
Location:


Part Two

Text Version
Images shows a lake labeled carbonates in water, a cow labeled animal respiration, a tree labeled photosynthesis, a factory labeled factory emissions, the sun labeled sunlight, a cloud labeled carbon dioxide in atmosphere, another tree labeled plant respiration, an arrow from organic carbon to dead organism, and fossils and fossil fuels. Arrows are labeled as follows: A from the sunlight to photosynthesis, B from carbon dioxide in atmosphere to photosynthesis, C from factory emissions to carbon dioxide in atmosphere, D from carbon dioxide in atmosphere to carbonates in water, E from dead organisms to fossils and fossil fuels, and F from plant respiration to the sky.





Using the diagram above, answer the following questions:
True or False. The arrow labeled C represents a transfer of chemical energy to mechanical energy. Explain why this is true or false.

True or False. The arrow labeled A represents a transfer of solar energy to chemical energy. Explain why this is true or false.

Which arrow or arrows represent a release of carbon dioxide? What process is occurring at the arrow(s) you selected?

Which arrow or arrows indicate a process that cycles carbon from living or nonliving organisms? Describe the process or processes you selected.

Which arrow or arrows represent reactions that demonstrate a conservation of mass and energy? Explain your answer.

Answers

Answer:

Part One:

Location: A - The arrow from the sun to the tree represents photosynthesis, where carbon dioxide is converted to sugar used for food.

Answer: A

Location: G - The arrow from the factory to the sky represents the release of carbon dioxide from factory emissions, which contributes to the conversion of carbon trapped in fossil fuels to carbon dioxide.

Answer: G

Location: E - The arrow from dead organisms to the ground represents the process where organic carbon is converted to fossil fuels over a long period of time.

Answer: E

Location: D - The arrow from the air to dead organisms represents the conversion of carbon dioxide to carbonates, which can be deposited in the ocean and form rocks over millions of years.

Answer: D

Location: F - The arrow from the cow to the sky represents animal respiration, where sugar is broken down and converted to carbon dioxide.

Answer: F

Part Two:

True or False. The arrow labeled C represents a transfer of chemical energy to mechanical energy. Explain why this is true or false.

False. The arrow labeled C represents the transfer of chemical energy (carbon dioxide) from the factory emissions to the atmosphere. There is no mechanical energy involved in this process.

True or False. The arrow labeled A represents a transfer of solar energy to chemical energy. Explain why this is true or false.

True. The arrow labeled A represents photosynthesis, where solar energy is used to convert carbon dioxide into chemical energy in the form of sugar.

Which arrow or arrows represent a release of carbon dioxide? What process is occurring at the arrow(s) you selected?

Arrows C and F represent a release of carbon dioxide. Arrow C represents the release of carbon dioxide from factory emissions, while arrow F represents animal respiration where sugar is broken down to release carbon dioxide.

Which arrow or arrows indicate a process that cycles carbon from living or nonliving organisms? Describe the process or processes you selected.

Arrows B, D, and E indicate processes that cycle carbon from living or nonliving organisms. Arrow B represents photosynthesis where carbon dioxide is taken up by plants, arrow D represents the conversion of carbon dioxide to carbonates which can be deposited in the ocean and form rocks over millions of years, and arrow E represents the conversion of dead organisms into fossil fuels over a long period of time.

Which arrow or arrows represent reactions that demonstrate a conservation of mass and energy? Explain your answer.

All arrows in the diagram demonstrate the conservation of mass and energy. The carbon cycle is a closed system, meaning that the total mass of carbon in the cycle remains constant over time. Energy is also conserved as it is converted from one form to another throughout the cycle.

as you take a short canoe trip on the Brazos River you paddle your canoe 200 miles up the river in 420 seconds and then turn around and paddle 350 miles down the river in 280 seconds what was your average speed during your canoe trip in miles per second​

Answers

200 miles/420 secs = 10/21
350 mile/280 secs = 5/4

(5/4+10/21)/2= 145/168 miles per sec
or .86 miles/sec

What fossil fuels will be saved by increased use of nuclear power?

Answers

As countries cut their greenhouse gas emissions and move away from coal, oil and natural gas to stem the worst effects of global warming, nuclear power is emerging as the answer to fill the gap.

Why nuclear power is a problem?

Nuclear energy produces radioactive waste

A major environmental problem associated with nuclear energy is the generation of radioactive waste, such as uranium plant tailings, spent (spent) reactor fuel, and other radioactive waste. These substances remain radioactive for thousands of years and are harmful to human health.

How does nuclear energy work?

Nuclear energy is produced by the fission of uranium atoms (a process called fission). The heat is used to generate steam, which is then used in a turbine generator to generate electricity. Because nuclear power plants do not burn fuel, they do not emit greenhouse gases.

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The ancient view of an Earth-centered geocentric universe suggested that life elsewhere should be
a. rare
b. common
c. at the center of another, parallel universe
d. this view gives us no clue of the likelihood of life elsewhere

Answers

The ancient view of an Earth-centered geocentric universe suggested that life elsewhere should be "rare."The ancient view of an Earth-centered geocentric universe was dominated by the belief that the Earth was stationary and located at the center of the universe. Option A.

In this ancient view, the universe consisted of celestial objects like the planets, the sun, and the stars which were all thought to revolve around the Earth in a fixed circular path. According to this ancient view, life elsewhere should be "rare."This view proposed that the Earth was unique and was a special place created by the Gods for the human race.

It was believed that the Earth was protected by the celestial sphere, and it was the only planet in the universe where life existed. However, with modern scientific advancements and technological innovations, astronomers have discovered numerous planets beyond our solar system that could be habitable. As a result, it is now believed that life beyond Earth may not be as rare as the ancient view suggested.  Option A.

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the first element on the periodic table of elements is helium true of false

Answers

Answer:

false

Explanation:

it's hydrogen. also hydrogen has one proton and stuff and helium two

Calculate the impulse on the object during the first 10 seconds.

Calculate the impulse on the object during the first 10 seconds.

Answers

The impulse is given by the area under the graph of F vs t, on a given interval.

Notice that the area under the given graph has the shape of a triangle. Its base has a "length" of 10 seconds, while its height is 5 Newtons. The area of a triangle is half the product of its base times its height. Then, the impulse on the object is:

\(\begin{gathered} I=\frac{1}{2}(10s)(5N) \\ =25N\cdot s \\ =25\operatorname{kg}\cdot\frac{m}{s} \end{gathered}\)

NEED HELP ASAP PLEASE
The drop time can be calculated as follows t = sqrt((2y)/g) where y is the vertical height of the table and g is the acceleration due to gravity (9.80 m/)How did the calculated drop time compare to the average of your measured drop times? Find the percent error using the following equation measured drop time - calculated drop time % 100 calculated drop time What factors might cause the differences?

NEED HELP ASAP PLEASE The drop time can be calculated as follows t = sqrt((2y)/g) where y is the vertical

Answers

did you end up getting the answer- im struggling

Answer:

I would think human error could cause differences like not pressing the stop watch on time.

Explanation:

Select the correct answer.

Good technique means that you are doing an exercise correctly.

A.

True

B.

False

Answers

The method you do an exercise to target particular muscle groups is known as technique.

Why is proper technique crucial when exercising?

When workouts are performed properly, the muscles and joints that are being particularly targeted by the movement get the load. When an exercise is performed improperly, it frequently results in the loading of other joints and muscles as well as a reduction in the benefit to the target muscles.

Is weight more significant than technique?

Whatever your weightlifting objectives, using perfect form is the first and most crucial step. Technique has a greater influence than weight used, whether you're trying to bulk up or tonify. Bad form simply won't yield the same outcomes.

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8. The force constant of a spring is 150. N/m. (a) How much force is required to stretch the spring 0.25 m? (b) How much work is done on the spring in that case?

Answers

Answer:

a) 37.5N

b) 9.375Joules

Explanation:

a) According to Hooke's law

F = ke

k is the spring constant

e is the extension;

F = 150 * 0.25

F = 37.5N

b) Work done on the spring = 1/2ke^2

Work done on the spring = 1/2 * 150 * 0.25^2

Work done on the spring  = 75 * 0.0625

Work done on the spring  = 9.375Joules

(a)  The force required to stretch the spring is of 37.5 N.

(b)  The work done on the spring is of 4.6775 J.

Given data:

The force constant of a spring is, k = 150 N/m.

The stretching distance of spring is, x = 0.25 m.

(a)  

When some force is experienced on the spring, then due to this force then it will displace. Then, the expression for the force applied on the spring is given as,

\(F = k \times x\)

Solve by substituting the values as,

\(F = 150 \times 0.25\\\\F = 37.5 \;\rm N\)

Thus, we can conclude that the force required to stretch the spring is of 37.5 N.

(b)

And the expression for the work done on the spring is given as,

\(W = \dfrac{1}{2}kx^{2}\)

Solving as,

\(W = \dfrac{1}{2} \times 150 \times 0.25^{2}\\\\W = 4.6875 \;\rm J\)

Thus, we can conclude that the work done on the spring is of 4.6775 J.

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mple lever. A lift is used to carry boxes to the top floor of a hotel 20 m high. A total weight of 100 kg of boxes was carried up in 20 seconds. If the useful output of the engine driving the lift mechanism is 1.2 kilowatt, calculate the efficiency of the engine of the lift mechanism. (a) (i) What is meant by a​

Answers

The efficiency of the system of the levers is  122%.

What is the efficiency?

We have to note that the efficiency is the ratio of the work out put to the work out put multiplied by 100. In this case, we are told that a lift is used to carry boxes to the top floor of a hotel 20 m high. A total weight of 100 kg of boxes was carried up in 20 seconds. and that  the useful output of the engine driving the lift mechanism is 1.2 kilowatt.

Work input = 100 Kg * 9.8 m/s^2* 20 m = 19600 J

Work output = 1.2 kilowatt * 10^3 * 20 = 24000 J

Then we have;

Efficiency = Work out put/ Work input * 100

= 24000/19600 * 100

= 122%

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2. (Free-fall problem) A ball is thrown up in the air. 10 seconds later it reaches the top of its trajectory. What was the original velocity it was thrown upward with?​

Answers

Explanation:

Using kinematics,

t = 10s

v = 0m/s

a = -9.8m/s^2

Therefore u = v - at = 0 - (-9.8)(10) = 98m/s.

[OU.04]Two stars, Star 1 and Star 2, are at almost equal distances from Earth. The table below shows the masses of the two stars.


Name of Star Mass of Star (in million solar masses)
Star 1 3.61
Star 2 11.73
I am lost on this question HELP
Which of these statements is most likely correct about the stars?
Earth exerts a greater gravitation force on Star 1 than on Star 2.
Earth exerts a greater gravitation force on Star 2 than on Star 1.
Star 1 attracts Star 2 with a greater gravitational force than Star 2 attracts Star 1.
Star 2 attracts Star 1 with a greater gravitational force than Star 1 attracts Star 2.

Answers

Answer: Which of these statements is most likely correct about the stars?

Star 2 attracts Star 1 with a greater gravitational force than Star 1 attracts Star 2.

No, because Third Newton Law states that both forces are equal in magnitude.

Earth exerts almost equal gravitation force on both the stars.

No, because the Universal Gravitational Law, estblished by Newton, states the atraction force to two masses is proportional to the product of the masses.

Star 1 attracts Star 2 with a greater gravitational force than Star 2 attracts Star 1.

No (same reason for the first statement)

Earth exerts greater gravitation force on Star 2 than on Star 1.

Right. This is the correct statement. Given the mass of Star 2 is greater than the mass of Star 1, by the Universal Gravitational Law, the earth exerts greater gravitational attraction on Star 2.

Explanation:

:)

A car is launched by a spring and goes to the top of a loop. Fill in the energy bar chart by drawing a vertical bar(s) in the correct position (both Initial & Final conditions).

Answers

Answer:

A) the initial point all energy is elastic potential and the final point all energy is kinetic

B) a bar graph the two bars have the same height and the sum of their height is the initial energy

C) two bars, one for the  kinetic energy and the other for the gravitational potential energy.

Explanation:

A) For this exercise we must use the energy conservation relations

starting point. When the spring is compressed

        Em₀ = K_e = ½ k x²

end point, at the bottom of the loop

        Em_f = K = ½ m v²

energy is conserved

        Em₀ = Em_f

         ½ k x² = ½ m v²

         v = \(\sqrt{ \frac{k}{m} }\)   x

In a bar graph the initial point all energy is elastic potential and the final point all energy is kinetic

B) intermediate point in a quarter of the radius

In this case we use the lower part of the loop as the starting point and the quarter part of the bow as the end point.

        Em₀ = K

         Em_f = K + U = ½ m v² + m g R

in a bar graph the two bars have the same height and the sum of their height is the initial energy

C) End point highest part of the loop

   starting point, bottom of loop

         Emo = K = ½ m v₀²

from part A of the exercise we saw that it is equal to the elastic energy of the spring

    final point. Highest part of the loop

         Emf = K + U

         Em_f = ½ m \(v_{f}^2\) + mg (2R)

         

where R is the radius of the loop

         Em₀ = Em_f

        1/2 m v₀² = 1/2 m v_{f}^2+ mg 2R

        v₀² = v_f^2 + 4gR

In a bar graph there are two bars, one for the  kinetic energy and the other for the gravitational potential energy. The sum of the heights of these bars is the initial energy, so the energy is transformed but not created or destroyed in the process.

please help with how to set up
the questions thanks!
9. A race car is awaiting the start of a race. Once the light turns green, the car accelerates at a to the top speed v in time t. (a) What force is supplied by the engine? (b) How far does the car tra

Answers

(a)The mass of the race car is ma.(b) The initial velocity (v₀) is assumed to be zero since the car is at rest before accelerating.

(a) To calculate the force supplied by the engine, we can use Newton's second law of motion, which states that the force (F) acting on an object is equal to its mass (m) multiplied by its acceleration (a):

F = m × a

The mass of the race car is ma.

(b) To determine how far the car travels, we can use the equation of motion that relates displacement (d), initial velocity (v₀), acceleration (a), and time (t):

d = v₀ × t + (1÷2) × a× t²

The initial velocity (v₀) is assumed to be zero since the car is at rest before accelerating.

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--The question is incomplete, the complete question is given:

" A race car is awaiting the start of a race. Once the light turns green, the car accelerates at a to the top speed v in time t. (a) What force is supplied by the engine? (b) How far does the car travel before it reaches top speed?"--

Which best explains how the diffraction pattern observed in young’s experiment supports the wave theory of light?.

Answers

Answer: the airy pattern can only arise from wave propagation

Explanation:if particles went in straight lines through a slit, they would progate linearly and not interfere. The airy pattern arises from diffraction as waves interfere, producing peaks (constructive interference where peaks of waves from each slit coincide) and troughs (destructive interference where peaks and troughs of waves from each slit cancel out). If intensity rather than field is measured nodes occur where 0 values line up instead of troughs

Geologists know the past temperature of the planet based on rock and fossil evidence. Why do you think it is difficult to determine what has caused climate change in the distant past?

Answers

Answer: Greenhouse gases affect how much of the Sun's energy the Earth loses back to space. Predicting global temperature change is hard, even though the principle sounds easy. In simple terms, energy reaches Earth from the Sun.

Explanation:

The lowest-frequency component of a complex period sound is its. A. treble. B. bass. C. fundamental frequency. D. phase. E. amplitude.

Answers

The lowest-frequency component of a complex periodic sound is its fundamental C. frequency.

In a complex periodic sound, such as a musical tone or a harmonic waveform, multiple frequencies combine to form the overall sound. These frequencies are called harmonics or overtones, and they are integer multiples of the fundamental frequency. The fundamental frequency is the lowest and most prominent frequency in the sound, determining its perceived pitch. The treble and bass refer to different regions of the frequency spectrum, with treble generally representing higher frequencies and bass representing lower frequencies. While the fundamental frequency contributes to the perception of bass, it is not exclusive to the lowest frequency range. Phase refers to the relative timing or alignment of the waveform and does not specifically describe the lowest-frequency component. Amplitude relates to the strength or intensity of the sound wave and is not directly associated with the lowest-frequency component.

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what is the energy of the photon emitted by a harmonic oscillator with stiffness 34 n/m and mass 8.4 × 10−26 kg when it drops from energy level 6 to energy level 3?

Answers

Main Answer: The energy of the photon emitted by the harmonic oscillator when it drops from energy level 6 to energy level 3 is approximately -3.00 x 10^-1 Joules.

Supporting Question and Answer:

What is the relationship between the energy levels of a harmonic oscillator and the energy of the emitted photon?

The energy of the emitted photon is determined by the difference in energy levels of the harmonic oscillator.

Body of the Solution:To calculate the energy of a photon emitted by a harmonic oscillator when it drops from one energy level to another, we can use the formula:

E = hf

where E is the energy of the photon,

h is Planck'sconstant(approximately 6.626 x 10^-34 J·s), and f is the frequency of the emitted photon.

The frequency of the emitted photon can be determined using the formula:

f = (E2 - E1) / h

where E2 and E1 are the energies of the initial and final energy levels, respectively.

Given:

Stiffness of the harmonic oscillator (k) = 34 N/m

Mass of the oscillator (m) = 8.4 x 10^-26 kg

Initial energy level (E1) = 6

Final energy level (E2) = 3

First, let's find the frequency (f):

f = (E2 - E1) / h

= (3 - 6) / (6.626 x 10^-34 J·s)

≈ -4.54 x 10^33 Hz (negative sign indicates emission)

Now, we can calculate the energy of the photon (E):

E = hf = (-4.54 x 10^33 Hz) x (6.626 x 10^-34 J·s)

≈ -3.00 x 10^-1 J (negative sign indicates emission)

Final Answer: Therefore, the energy of the photon emitted by the harmonic oscillator when it drops from energy level 6 to energy level 3 is approximately -3.00 x 10^-1 Joules.

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The energy of the photon emitted by the harmonic oscillator when it drops from energy level 6 to energy level 3 is approximately -3.00 x \(10^{-1\)Joules.

What is the relationship between the energy levels of a harmonic oscillator and the energy of the emitted photon?

The energy of the emitted photon is determined by the difference in energy levels of the harmonic oscillator.


To calculate the energy of a photon emitted by a harmonic oscillator when it drops from one energy level to another, we can use the formula:

E = hf

where E is the energy of the photon,

h is Planck's constant (approximately 6.626 x \(10^{-34\) J·s), and f is the frequency of the emitted photon.

The frequency of the emitted photon can be determined using the formula:

f = (E2 - E1) / h

where E2 and E1 are the energies of the initial and final energy levels, respectively.

Given:

Stiffness of the harmonic oscillator (k) = 34 N/m

Mass of the oscillator (m) = 8.4 x \(10^{-26\) kg

Initial energy level (E1) = 6

Final energy level (E2) = 3

First, let's find the frequency (f):

f = (E2 - E1) / h

= (3 - 6) / (6.626 x\(10^{-34\) J·s)

≈ -4.54 x \(10^{33\) Hz (negative sign indicates emission)

Now, we can calculate the energy of the photon (E):

E = hf = (-4.54 x \(10^{33\) Hz) x (6.626 x\(10^{-34\) J·s)

≈ -3.00 x \(10^{-1\) J (negative sign indicates emission)

Therefore, the energy of the photon emitted by the harmonic oscillator when it drops from energy level 6 to energy level 3 is approximately -3.00 x \(10^{-1\) Joules.

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Lucy and JoJo need to make 140 cupcakes for the school dance. Lucy made 35 of the cupcakes. JoJo made 42 cupcakes What fraction of the cupcakes do Lucy and JoJo still need to make?

Answers

Answer:

9/20

Explanation:

According to this question, Lucy and JoJo need to make 140 cupcakes for the school dance. Lucy made 35 of the cupcakes while JoJo made 42 cupcakes. This means that in total, (42 + 35) cupcakes has been made by both Lucy and JoJo

That is, 77 cupcakes out of 140 has been made. This is 77/140 i.e. 11/20

Since 77/140 cupcakes has been made, Lucy and JoJo still need to make;

140 - 77 = 63 cupcakes to meet up their target for the school dance.

This means that the fraction left is 63/140

63/140 in its lowest term is 9/20

Hence, 9/20 of the cupcakes still need to be made by Lucy and JoJo.

Explanation: 140 - 35 = 105 - 42 = 63

yare yare daze

I use tusk act 4 main

You carry a 20 N bag of dog food up a 6.0 m flight of stairs. How much work was done?

Answers

Answer:
120 J

Explanation:


Formula Of Work= Work= Force x Displacement

Work= 20 N x 6.0

Work= 120 Joules

The reason I put joules because the Unit of work is joules

what is the thermal energy

Answers

Answer:

heat energy

Explanation:

heat is the flow of thermal energy. A whole branch of physics

it’s the same as heat energy.

What is the acceleration of a car that goes from 5m/s to 95m/s in 10s?
A. 45m/s^2
B. 100m/s^2
C. -9m/s^2
D. 9m/s^2

Answers

Initial velocity=u=5m/sFinal velocity=95m/s=vTime=t=10s

\(\\ \tt\longmapsto Acceleration=\dfrac{v-u}{t}\)

\(\\ \tt\longmapsto Acceleration=\dfrac{95-5}{10}\)

\(\\ \tt\longmapsto Acceleration=\dfrac{90}{10}\)

\(\\ \tt\longmapsto Acceleration=9m/s^2\)

a loop with a break in it that prevents current form flowing is called a(n) blank circuit

Answers

Answer: it is called a open circuit

Explanation:

Work, Power, and Energy

A 3 kg ball falls from a height of 45 meters to a height of 32 meters. Calculate the amount of work done by gravity.
When writing your answer, please include the formula you used! Thank you!

Answers

Answer:

383.2

Explanation:

W=m×g(9.8)×(change in height)

=3×9.8× (45-32)

=3×9.8×13

=383.2

how much kinetic energy does an 8 kg bowling ball have when it is thrown 9 m/s. down the alley

Answers

Answer:

324 J

Explanation:

KE= 1/2 m*v^2

1/2*8*9^2

324 joules (=^w^=) woof woof

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