What is the force in the equation, F=ma?
Answers
ma= mass
M=mass
A=acceleration
Related Questions
What will be the final velocity of a car, if it starts to move from rest and accelerates at 10 m/s² after 5 seconds ?
Answers
Answer:
50m/s.
Explanation:
Answer:
\(V_f=50m/s\)
Explanation:
Use the the formula for final velocity (kinematic equation):
\(V_f=V_i+at\)
Final velocity = Initial velocity + acceleration times time
Given values:
Rest - indicates 0 initial velocity
Acceleration - 10 m/s^2
Time - 5 seconds
Insert the given values:
\(V_f=0+5\times10\)
\(V_f=50m/s\)
Thermal energy transfer portfolio 1
Answers
A thermal energy transfer portfolio would be an excellent way for students to showcase their knowledge and understanding of this important scientific concept.
Thermal energy transfer is the energy transfer between two or more objects that have different temperatures. This energy transfer can take place in three different ways: conduction, convection, and radiation. A portfolio is a collection of documents or pieces of work that demonstrate a person's skills, abilities, and achievements in a particular area.
Therefore, a thermal energy transfer portfolio would be a collection of documents or pieces of work that demonstrate a person's skills, abilities, and achievements related to thermal energy transfer. This portfolio could include lab reports, experimental data, diagrams, and explanations of the various ways thermal energy can be transferred.
For example, a student's thermal energy transfer portfolio might include:
1. A lab report detailing an experiment they conducted to measure the rate of heat transfer through different materials using conduction.
2. A diagram showing the process of heat transfer through convection in a fluid, such as air or water.
3. A written explanation of the concept of radiation and how it relates to thermal energy transfer.
4. A spreadsheet of data showing the temperature changes in a system as heat is transferred through it.
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The separation distance between two 2.0 kg masses is decreased by two-thirds. How is the gravitational force between them affected?
Answers
Given:
The mass of two objects is: m1 = m2 = m = 2 kg
The distance between the object is decreased by two-thirds
To find:
How on reducing the distance, the gravitational force between them affects them.
Explanation:
Let the distance between two objects each having mass "m" be "r". The gravitational force between them is given as:
\(F_1=G\frac{m_1\times m_2}{r^2}\)Here, G is the universal gravitational constant.
Substituting the values in the above equation, we get:
\(\begin{gathered} F_1=G\times\frac{2\text{ kg}\times2\text{ kg}}{r^2} \\ \\ F_1=G\times\frac{4\text{ kg}^2}{r^2}..........(1) \end{gathered}\)Now, the distance between the mass is reduced by two-thirds. Thus, the new distance between them will be "R" which is given as:
\(R=r-\frac{2}{3}r=r(1-\frac{2}{3})=\frac{r}{3}\)Now, the gravitational force between two masses with their distance of separation reduced by two-thirds is given as:
\(F_2=G\frac{m_1\times m_2}{R^2}\)Substituting the values in the above equation, we get:
\(\begin{gathered} F_2=G\times\frac{2\text{ kg}\times2\text{ kg}}{(\frac{r}{3})^2} \\ \\ F_2=G\times\frac{4\text{ kg}^2}{\frac{r^2}{9}} \\ \\ \begin{equation*} F_2=G\times\frac{9\times4\text{ kg}^2}{r^2} \end{equation*} \\ \\ F_2=9\times(G\times\frac{4\text{ kg}^2}{r^2})..........(2) \end{gathered}\)Substituting equation (1) in equation (2), we get:
\(\begin{gathered} F_2=9\times(G\times\frac{4\text{ kg}^2}{r^2}) \\ \\ F_2=9F_1 \end{gathered}\)From the above equation, we observe that the new gravitational force F2 between two masses when their distance of separation is reduced by two-thirds will be nine times that of the original value of gravitational force F1.
Final answer:
The new gravitational force F2 between two masses when their distance of separation is reduced by two-thirds will be nine times that of the original value of gravitational force F1.
Miles and Allison are conducting a science experiment on bacteria and
they have a different hypothesis about what is going to happen. After
repeating their experiment several times, they realize that the results of
the experiment do not clearly support either hypothesis. What should
Miles and Allison do next?
O A. assume Miles hypothesis is correct
O B. revise their hypotheses and do another test
C. change their results to match one of their hypotheses
O D. repeat the experiment until it supports one of their hypotheses
Answers
I
Do you guys think people used energy before the modern times? Why or why not?
Answers
Answer:
do you mean before we used fossil fuels? steam.before steam? fire was used for like ...125,000 years ago. we were not smart back then but we were smart enough.
Explanation:
What are one or two things that you know about collisions?
Answers
Answer: In science collisions can be elastic, meaning they conserve both momentum and kinetic energy, or inelastic, meaning they conserve momentum but not kinetic energy.
Explanation: I hope that helped yall!
who is the president of kenya
Answers
Who is the president of Kenya?
Answer:Uhuru Kenyatta
Answer:
Uhuru Muigai Kenyatta
Explanation:
He was born on 26 October 1961.
He is a Kenyan politician, businessman, and the fourth and current President of the Republic of Kenya.
Using the fft function in MATLAB, plot the magnitude spectrum versus frequency for the signal g(t)=exp(−10t)u(t) for 0≤t≤1 with Δt=0.01. Determine the number of points in the signal. Use 450 zeros for precede and trail and determine the period T. B. Separately, plot the continuous magnitude transform given by: G(f)= 10+j2πf
1
[1−e −(10+j2πf)
] Utilize the same separation in frequencies. C. Using the fft function in MATLAB, plot the magnitude spectrum versus frequency for the signal: g(t)=sinc(πt). Assume Δt=0.01, and use 450 zeros for precede and trail and determine the period T.
Answers
The magnitude spectrum versus frequency for the signal g(t) = exp(-10t)u(t) and the continuous magnitude transform, and to determine the number of points in the signal and the period, the provided MATLAB code can be used.
A. To plot the magnitude spectrum versus frequency for the signal g(t) = exp(-10t)u(t) for 0 ≤ t ≤ 1 with Δt = 0.01 and determine the number of points in the signal:
```matlab
% Define parameters
delta_t = 0.01; % Sampling interval
t = 0:delta_t:1; % Time vector
g = exp(-10*t).*(t >= 0); % Signal definition
% Pad with zeros
N_zeros = 450;
g_padded = [zeros(1, N_zeros), g, zeros(1, N_zeros)];
% Compute the Fourier Transform
G = fft(g_padded);
% Compute the magnitude spectrum
G_mag = abs(G);
% Determine the number of points in the signal
num_points = length(g_padded);
% Determine the period
T = num_points * delta_t;
% Determine the frequency vector
Fs = 1/delta_t; % Sampling frequency
f = (-Fs/2 : Fs/num_points : Fs/2 - Fs/num_points);
% Plot the magnitude spectrum versus frequency
plot(f, G_mag);
xlabel('Frequency');
ylabel('Magnitude Spectrum');
title('Magnitude Spectrum versus Frequency');
```
B. To plot the continuous magnitude transform given by G(f) = (10 + j2πf) / (1 - e^(-(10 + j2πf))) and utilize the same frequency separation:
```matlab
% Define frequency range
f = -Fs/2 : Fs/num_points : Fs/2 - Fs/num_points;
% Evaluate the expression for G(f)
G_continuous = (10 + 1j * 2 * pi * f) ./ (1 - exp(-(10 + 1j * 2 * pi * f)));
% Plot the continuous magnitude transform
plot(f, abs(G_continuous));
xlabel('Frequency');
ylabel('Magnitude');
title('Continuous Magnitude Transform');
```
C. To plot the magnitude spectrum versus frequency for the signal g(t) = sinc(πt) assuming Δt = 0.01 and determine the period T:
```matlab
% Define parameters
delta_t = 0.01; % Sampling interval
t = -1:delta_t:1; % Time vector
g = sinc(pi*t); % Signal definition
% Pad with zeros
N_zeros = 450;
g_padded = [zeros(1, N_zeros), g, zeros(1, N_zeros)];
% Compute the Fourier Transform
G = fft(g_padded);
% Compute the magnitude spectrum
G_mag = abs(G);
% Determine the number of points in the signal
num_points = length(g_padded);
% Determine the period
T = num_points * delta_t;
% Determine the frequency vector
Fs = 1/delta_t; % Sampling frequency
f = (-Fs/2 : Fs/num_points : Fs/2 - Fs/num_points);
% Plot the magnitude spectrum versus frequency
plot(f, G_mag);
xlabel('Frequency');
ylabel('Magnitude Spectrum');
title('Magnitude Spectrum versus Frequency');
```
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the power in an electrical circuit is given by the equation p=/2 R, where /is the current flowing through the circuit and R is the resistance of the circuit. what is the power in a circuit that has a current of 12
A. 120 watts
B. 8.3 watts
C.144 watts
D. 14,400 watts
Answers
Complete Question:
What is the power in a circuit that has a current of 12 amps and a resistance of 100 ohms?
Answer:
D. 14,400 watts
Explanation:
The electrical power of an electric circuit can be defined as a measure of the rate at which energy is either produced or absorbed in the circuit.
Mathematically, electrical power is given by the formula;
\( Electrical \; power = current * voltage \)
This ultimately implies that, the quantity (current times voltage ) is electrical power and it is measured (S.I units) in Watt (W).
Given the following data;
Current = 12 AmperesResistance = 100 OhmsTo find the power in the circuit, we would use the following formula;
Power = I²R
Where;
I is current measured in Amperes.R is resistance measured in Ohms.Power = 12² * 100
Power = 144 * 100
Power = 144,000 Watts
When a golf ball is hit, it travels at 41 meters per second. The mass of a golf ball is 0.045kg. Calculate the kinetic energy of the golf ball.
Answers
Answer:
75.645 J
Explanation:
The kinetic energy is related to the mass and velocity by the formula ...
KE = 1/2mv²
For the given mass of 0.045 kg, and velocity of 41 m/s, the kinetic energy is ...
KE = 1/2(0.045 kg)(41 m/s)² = 75.645 J
__
The unit of energy, joule, is a derived unit equal to 1 kg·m²/s².
when we compare the true total mass of a galaxy cluster with the mass measured by adding up all the stars in all the galaxies of the cluster, we find that the true cluster mass
Answers
The true total mass of a galaxy cluster is much greater than the mass measured by adding up all the stars in all the galaxies of the cluster.
This is because the majority of the mass in a galaxy cluster is actually in the form of dark matter, which cannot be detected through traditional methods like observing stars. Dark matter is a mysterious substance that interacts only through gravity and is thought to make up about 85% of the matter in the universe.
Therefore, the true total mass of a galaxy cluster is much higher than what is visible through telescopes. Scientists use a variety of methods, such as gravitational lensing and the motions of the galaxies within the cluster, to estimate the amount of dark matter present and thus determine the true mass of the cluster. Understanding the distribution and amount of dark matter in galaxy clusters is an important part of studying the large-scale structure of the universe.
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a non-relativistic particle of mass m with kinetic energy 0.01 ev has wavelength of 0.1 nm. if the energy were quadrupled, to 0.04 ev, the wavelength would be closest to
A) 0.05 nm
B) 0.2 nm
C) 0.025 nm
D) 0.4 nm
E) Can't be found without knowing the mass of the particle.
Answers
To find the relationship between the energy and the wavelength of a non-relativistic particle, we can use the de Broglie wavelength equation:
λ = h / √(2 * m * E)
where λ is the wavelength, h is the Planck's constant, m is the mass of the particle, and E is the kinetic energy of the particle.
Given that the initial kinetic energy is 0.01 eV and the initial wavelength is 0.1 nm, we can substitute these values into the equation:
0.1 nm = h / √(2 * m * 0.01 eV)
Now, we can square both sides of the equation to eliminate the square root:
(0.1 nm)^2 = (h^2) / (2 * m * 0.01 eV)
Simplifying further:
0.01 nm^2 = (h^2) / (2 * m * 0.01 eV)
Next, we are given that the energy is quadrupled to 0.04 eV. Let's calculate the new wavelength using the same equation:
λ' = h / √(2 * m * 0.04 eV)
Again, we square both sides of the equation:
(λ')^2 = (h^2) / (2 * m * 0.04 eV)
Simplifying:
0.04 nm^2 = (h^2) / (2 * m * 0.04 eV)
Now, we can compare the two equations:
0.01 nm^2 = (h^2) / (2 * m * 0.01 eV)
0.04 nm^2 = (h^2) / (2 * m * 0.04 eV)
We notice that the only difference between the two equations is the factor of 0.01 and 0.04 in the denominator. So, if we quadruple the energy, the new wavelength will be reduced by a factor of √4 = 2. Therefore, the new wavelength will be 0.1 nm / 2 = 0.05 nm.
Thus, the closest answer choice is A) 0.05 nm.
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if the motorcyclist applies the front brake too hard, theRear brake does not functionFront brake can lock up and skidRear brake can lock up and skidHand control operates the rear brake
Answers
If the motorcyclist applies the front brake too hard, the front brake can lock up and skid, Option b is correct.
When a motorcyclist applies the front brake too hard, the front wheel can lock up and skid, causing the rider to lose control of the motorcycle. This happens because the front brake is responsible for most of the motorcycle's stopping power, and if it is applied too forcefully, the wheel can stop rotating altogether.
It is essential for motorcyclists to be aware of proper braking techniques and to apply the brakes smoothly and evenly to avoid skidding and accidents. Hence option b is correct choice.
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Please help will give brainliest
Answers
Answer:
1. The human exerts a force when he pulls the bow back and launches it.
2. Gravity causes the arrow to fall down, and air resistance slows the arrow down, as it is in the opposite direction.
3. If the arrow has more mass, it would require to have a greater force exerted on it to make it fly farther. So the archer would most likely not reach as high of a top speed.
Explanation:
brainliest :)
QUESTION: Is there a relationship between height and shoe size? Write a one sentence
summary of your graph.
J
Answers
Answer:
There is no particular relationship between the height and shoe size. But the shoe sizes in males is usually bigger than females. And the shoe size tends to get bigger when the person is taller.
Explanation:
A 20 N force is necessary to stretch a spring 0.5 m. What is the spring constant of this spring?
Answers
Answer: The spring constant of a given spring is \(40 N/m\).
Explanation:
Given,
Force (F) = 20N
The displacement of the spring\(= x = 0.5 m\)
To find: Spring constant (k) = ?
As we know that,
Hook's law states that,
\(F = k\) · \(x\)
Therefore, \(k = \frac{F}{x}\)
\(k = \frac{20}{0.5}\)
\(k = \frac{(20)(10)}{5}\)
\(k = 40 N/m\)
Hence, The spring constant of a given spring is \(40 N/m\).
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anyone know the answer ?
Answers
Answer:
a,c,d I thought these are the true statements about these graph
The number of objects that have been observed to be orbiting in the kuiper belt is approximately.
Answers
The hundreds of thousands of icy bodies larger than 100 km have been observed to be orbiting in the Kuiper belt is approximately.
What is Kuiper belt?
The region beyond Neptune known as the Kuiper Belt is made up of countless stellar objects orbiting the sun. Solid methane, ice, and ammonia make up belt objects. The belt's orbit deviates from the orbital plane and can be inclined by up to 19 degrees. Scientists searched for Planet X as a possible explanation for the origin of the belt.
What is orbit?
An orbital is a region where it is possible to estimate the likelihood of finding any electron, whereas an orbit is a fixed path that electrons follow around the atom's nucleus.
The Kuiper Belt is thought to contain a trillion comets or more and hundreds of thousands of icy bodies bigger than 100 km (62 miles).
Therefore, there may be hundreds of thousands of icy bodies larger than 100 km have been observed to be orbiting in the Kuiper belt is approximately.
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X-rays of wavelength 9. 74×10?2 nm are directed at an unknown crystal. The second diffraction maximum is recorded when the X-rays are directed at an angle of 21. 9 ? relative to the crystal surface.
What is the spacing between crystal planes? In m
Answers
The spacing between crystal planes is 2.78 × 10⁻¹⁰ m. The Bragg's Law can be used to find the spacing between the crystal planes.
Bragg's Law states that when X-rays of wavelength λ fall on the crystal, the maxima of diffraction will be observed when the path difference between the two rays is an integral multiple of the wavelength (2d sinθ = nλ, where n=1, 2, 3.....).Where d is the spacing between the crystal planes θ is the angle between the incident X-rays and the crystal planes
The maximum diffraction was recorded at 21.9°, thus,
θ = 21.9°λ
= 9.74×10⁻² nm
= 9.74×10⁻¹¹ m
From Bragg's law: 2d sinθ
= nλ2d
= nλ/sinθ
Substitute the values in the equation, we have:
2d = (1)(9.74 × 10⁻¹¹)/sin(21.9°)d
= (9.74 × 10⁻¹¹)/(2 × sin(21.9°))d
= 2.78 × 10⁻¹⁰ m
This is the spacing between the crystal planes.
The spacing between crystal planes is 2.78 × 10⁻¹⁰ m.
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Question 7 (1 point)
An air mass exists off the Pacific coast of California. What type of air mass is this and
what are its main characteristics?
Choose ALL that apply
Lesson 1.07
Maritime
Polar
Continental
Polar
Maritime
Polar
Maritime
Tropical
Maritime
Tropical
Continental
Tropical
Maritime
Tropical
forms over warm water
warm, humid air mass
its a polar air mass
brings rainy or muggy weather
Answers
Answer:
Forms over water, warm humid air mass, it's a polar air mass
Explanation: I think that's right sorry if it's not..
GL! :)
calculate the tension in a cable used to pull a 1000-kg object straight upward at an acceleration of 0.7 m/s2. (use g = 9.8 m/s2.)
Answers
The tension in the cable required is 10500 N to pull a 1000-kg object straight upward at an acceleration of 0.7 m/s²
Mass of the object = 100kgs
Acceleration = 0.7 m/s²
Acceleration due to gravity = 9.8 m/s²
When an object is moved straight upward, acceleration force and gravitation force will act on the object. So we need to consider the acceleration due to gravity here.
The weight of the object can be calculated as:
Weight = mass x acceleration due to gravity
Weight of object = 1000 kg * 9.8 m/s²
Weight of object = 9800 N
The tension in the cable can be calculated by using the formula:
Tension = Weight + (mass x acceleration)
Tension = 9800 N + 1000 kg * 0.7 m/s²
Tension = 9800 N + 700 N
Tension = 10500 N
Therefore, we can conclude that the tension in the cable is 10500 N.
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Calculate the frequency of a vibrating body if it vibrates 400 times in 20 seconds. Identify the category of sound it belongs to.(sonic sound/ ultrasound/ infra sound)
Answers
The category of sound is a sonic sound
Answer:
F+20Hz
Explanation:
A tow truck pulls a 7,800 N car 5m out of a ditch in 6.5 seconds. How much power does the
tow truck have?
Answers
Answer:
p=6000W
Explanation:
p=w/t
w=f*d=7800*5=39000 J
therefore,
p=39000/6.5=6000 W
Answer:
p=6000W
Explanation:
What is the purpose of the Stanford Encyclopedia of Philosophy?
Answers
The Stanford Encyclopedia of Philosophy is an online encyclopedia that provides reliable and up-to-date information on philosophical issues.
The Stanford Encyclopedia of Philosophy (SEP) is an online reference work that aims to provide high-quality, peer-reviewed articles on a wide range of philosophical topics.
Its purpose is to serve as a reliable and accessible resource for students, scholars, and anyone interested in philosophy.
The SEP was established in 1995 by Edward N. Zalta, a senior research scholar at Stanford University, and has since become one of the most respected and widely used resources in the field. The encyclopedia's articles are written by experts in their respective fields and undergo a rigorous process of peer review to ensure their accuracy and quality.
One of the primary aims of the SEP is to provide a comprehensive overview of philosophical topics, including both historical and contemporary perspectives. The encyclopedia also seeks to promote interdisciplinary engagement by including articles on topics that overlap with other disciplines, such as science, mathematics, and politics.
Overall, the Stanford Encyclopedia of Philosophy serves as an invaluable resource for anyone seeking to deepen their understanding of philosophy and its place in the world. Its commitment to rigorous scholarship and accessibility make it a valuable tool for both experts and newcomers to the field.
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How far has a dolphin traveled in kilometers if it swims for 1.8 h at 5.6 km/h ?
Answers
Answer:
distance = 6.26342 miles
Explanation:
HELP PLS, Order the following mass measurements from least to greatest.
AYUDA PORFAVOR!!! Ordenar de menor a mayor las siguientes medidas de masa.
Answers
Answer:
3, 2, 1
Explanation:
They can all be expressed in mg by recognizing that 1000 μg = 1 mg.
In milligrams, the measurements are ...
1) 11.6
2) 1.021
3) 0.31
Least-to-greatest the order is ...
(3) 0.31 mg; (2) 1.021 mg; (1) 11.6 mg
A. It Implies That M Is Finitely Generated. B. It Implies That M Has Nonzero Elements Of Nonzero Order. C. When Every Non-Null Element Has Null . D. In The Case That The Ring R Is A Body. E. None Of The Above Alternatives Gives A
Which of the following alternatives give a true statement. Justify your answer.
A modulus M over a ring R has a finite basis:
a. It implies that M is finitely generated.
b. It implies that M has nonzero elements of nonzero order.
C. When every non-null element has null .
d. in the case that the ring R is a body.
e. None of the above alternatives gives a true statement.
Which of the following statements are true?
a. If a subset of a module generates that whole module, then the subset cannot be
empty.
b. Every submodule S of a module M verifies the inequality C. Two different subsets of M have to generate two different submodules of M.
d. If S generates a submodule N of the module M, then contains S.
e. Neither statement is true.
Answers
The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.
When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.
According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.
According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.
According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.
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A group of people are pushing a stalled car with a mass of 700kg. If they push with a net force of 200 Newtons for 8 seconds, what is the cars final velocity
Answers
A 700 kg car that has stalled is being pushed by a group of people. The final velocity of the car will be 2.28 seconds if they push with a net force of 200 Newtons for 8 seconds.
What does a change in momentum mean?The change in momentum (Δp ) is defined as the change in the product of an object's mass and velocity. A force is required to change the momentum of an object. The momentum of the item may change due to the applied force, as well as its direction.
Why is an impulse a change in momentum?Any moving object can have momentum because momentum is defined as mass in motion. The impulse of an item is equal to its change in momentum. Impulse is defined as a force multiplied by a time period. Instead of being the same as momentum, impulse is the change in momentum of an object.
Impulse = Impulsive force x Impact time
Impulse = 200N x 8s = 1600Ns
To calculate final velocity of car,
Impulse = change in momentum
1600 = 700 (v-0)
1600 = 700v
v = 1600/700
v = 2.28 m/s
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the electric field strength 3.0 cm c m from the surface of a 10-cm c m -diameter metal ball is 50,000 n/c n / c . part a what is the charge (in nc n c ) on the ball?
Answers
The required magnitude of charge on the ball when diameter of the ball is given is calculated to be 35.56 nC.
The strength of the electric field is 50,000 N/C.
The ball's diameter is d = 10 cm = 0.1 m
The distance r = 3 cm = 0.03 m
Electric field strength is given by the expression,
E = kq/(r + d/2)²
where,
k is coulomb's constant
q is charge
Entering the values into the equation, we have,
E = kq/(r + d/2)²
50000 = (9× 10⁹ q)/(0.03 + 0.1/2)²
50000 × 0.0064 = 9× 10⁹ q
9× 10⁹ q = 320
q = 320/9 × 10⁻⁹
q = 35.56 × 10⁻⁹ C = 35.56 nC
Thus, the magnitude of charge on the ball is given as 35.56 nC.
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a. (2pts) When the frequency of a wave increases, what happens to the wavelength of the wave?
b. (2pts) When the wavelength of a wave increases, what happens to the frequency of the wave?
please help as soon as possible i really appreciate it
Answers
A) if frequency increases, wavelength will decrease
B) if wavelength increases, frequency will decrease
Hope this helped.