What is the focal length of a lens?

A.
the distance between the object and the image
B.
distance between the object and the center of the lens
C.
the distance between the center of the lens and the image
D.
the distance between the focal point and the center of the lens

Answer: beryllium

Explanation: i took the test i got it right!!

Answer:

1.200 n/m to shoot20 feet

Explanation:

A slingshot is used to launch a 5.00-gram rock. The effective spring constant of the slingshot is 200 N/m.

Hooke's law is a law of physics that states that the force (F) needed to extend or compress a spring by some distance (x) scales linearly with respect to that distance—that is, Fₛ = kx, where k is a constant factor characteristic of the spring (i.e., its stiffness), and x is small compared to the total possible deformation of the spring. The law is named after 17th-century British physicist Robert Hooke. He first stated the law in 1676 as a Latin anagram. He published the solution of his anagram in 1678 as: ut tensio, sic vis ("as the extension, so the force" or "the extension is proportional to the force"). Hooke states in the 1678 work that he was aware of the law since 1660.

To apply this formula to the given values, we first need to convert the direction angle from degrees to radians, which is done by multiplying it by π/180. So, 306.7° * π/180 = 5.357 radians.

we used the formula for the component form of a vector to find the answer to the given question. This formula involves multiplying the magnitude of the vector by the cosine and sine of its direction angle converted to radians, respectively. After plugging in the given values and simplifying, we arrived at the component form (-175.5, 182.9) for the vector v.

To find the component form of a vector given its magnitude and direction angle, we use the following formulas ,v_x = |v| * cosθ ,v_y = |v| * sin(θ) where |v| is the magnitude, θ is the direction angle, and v_x and v_y are the x and y components of the vector.  Convert the direction angle to radians. θ = 306.7° * (π/180) ≈ 5.35 radians Calculate the x-component (v_x). v_x = |v| * cos(θ) ≈ 184.1 * cos(5.35) ≈ -97.1  Calculate the y-component (v_y).
v_y = |v| * sin(θ) ≈ 184.1 * sin(5.35) ≈ 162.5.

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(a)Since the image is larger than the object (m > 1) and assuming the object is upright, we can conclude that the mirror must be concave.(b) Therefore, the focal length of the mirror is approximately f = 2.732 m. (c) Therefore, the required radius of curvature of the mirror is approximately 2.732 m, and the mirror should be positioned approximately 3.861 m from the object.

To determine whether the mirror is required to be concave or convex, we can analyze the magnification of the mirror.

Given:

Size of the image: 4.10 times the size of the object

Distance from the object to the screen (image distance): 1.60 m

The magnification, m, is defined as the ratio of the image height to the object height. In this case, m = 4.10.

(a) To determine the type of mirror required, we need to consider the sign conventions. A positive magnification (m > 0) indicates an upright image, while a negative magnification (m < 0) indicates an inverted image.

Since the image is larger than the object (m > 1) and assuming the object is upright, we can conclude that the mirror must be concave (a concave mirror produces both upright and magnified images).

(b) To find the required radius of curvature of the mirror, we can use the mirror formula:

1/f = 1/d(o) + 1/d(i)

Where:

f is the focal length of the mirror

d(o) is the object distance (distance from the mirror to the object)

d(i) is the image distance (distance from the mirror to the screen)

Since the object distance (d(o)) is not given directly, we can use the relationship between d(o), d(i), and the magnification:

m = -d(i)/d(o)

Rearranging the equation, we have:

d(o) = -d(i)/m

Substituting the given values, we have:

d(o) = -1.60 m / 4.10

Now, we can substitute the values of d(o) and d(i) into the mirror formula and solve for the focal length:

1/f = 1/d(o) + 1/d(i)

1/f = 1/(-1.60 m / 4.10) + 1/1.60 m

Simplifying the equation gives:

1/f = -0.259 + 0.625

1/f = 0.366

Therefore, the focal length of the mirror is approximately f = 2.732 m.

(c) To determine the position of the mirror relative to the object, we can use the mirror formula once again:

1/f = 1/d(o) + 1/d(i)

Rearranging the equation, we have:

1/d(o) = 1/f - 1/d(i)

Substituting the values of f and d(i) into the equation:

1/d(o) = 1/2.732 m - 1/1.60 m

Calculating the right-hand side of the equation gives:

1/d(o) = 0.366 - 0.625

1/d(o) = -0.259

Taking the reciprocal of both sides gives:

d(o) = -1/0.259 m

d(o) ≈ -3.861 m

Since the object distance cannot be negative, we discard the negative sign, and the mirror should be positioned approximately 3.861 m from the object.

Therefore, the required radius of curvature of the mirror is approximately 2.732 m, and the mirror should be positioned approximately 3.861 m from the object.

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Answer:

nuclear fusion plants are fossil fuels, if you are asking which of the following is a fossil fuel

Explanation:

The energy is negative and in the order of\(10^-6\)  J, we can express it as -36 µJ.

Therefore, the correct answer is D) -36 µJ.

We need to find the electric potential energy of a -3.0 µC charge placed at a point with an electric potential of 12 V.

We can use the formula:
Electric potential energy (U) = Charge (q) × Electric potential (V)
First, we need to convert the charge from µC to C:
\(-3.0 \mu C = -3.0 * 10^-6 C\)
Now we can plug the values into the formula:
\(U = (-3.0 *  10^-6 C) *  (12 V)\)
\(U = -36 * 10^-6 J.\)

Therefore, the correct answer is D) -36 µJ.

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The electric flux through the pyramid is approximately 37.29 N·m²/C.

To calculate the electric flux through the pyramid, we need to determine the net electric charge enclosed by the pyramid.

The electric flux is given by the equation Φ = q/ε₀, where Φ represents the electric flux, q is the net electric charge enclosed, and ε₀ is the electric constant.

In this case, we have a sphere with a charge of -0.2 x \(10^{(-9)}\) C and a cube with a charge of 0.53 x \(10^{(-9)}\) C inside the pyramid. The net charge enclosed is the sum of the charges of the sphere and the cube: -0.2 x \(10^{(-9)}\) C + 0.53 x \(10^{(-9)}\) C = 0.33 x \(10^{(-9)}\) C.

Now we can calculate the electric flux using the equation Φ = q/ε₀. The electric constant, ε₀, is a known value (approximately 8.85 x \(10^{(-12)}\) C²/N·m²). Plugging in the values, we get Φ = (0.33 x \(10^{(-9)}\) C) / (8.85 x \(10^{(-12)}\) C²/N·m²).

Simplifying the expression, we find Φ ≈ 37.29 N·m²/C.

Therefore, the electric flux through the pyramid is approximately 37.29 N·m²/C.

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Answer:

The main role of neutrons is to reduce electrostatic repulsion inside the nucleus.

Explanation:

:) Good luck my friend

An inductor is connected to an ac generator. As the generator's frequency increases, the current in the inductor decreases.

Inductors and chokes are basically coils or loops of wire that are either wound around a hollow tube former (air cored) or wound around some ferromagnetic material (iron cored) to increase their inductive value called inductance.

Inductors store their energy in the form of a magnetic field that is created when a voltage is applied across the terminals of an inductor.

The growth of the current flowing through the inductor is not instant but is determined by the inductors own self-induced or back emf value. Then for an inductor coil, this back emf voltage VL is proportional to the rate of change of the current flowing through it.

This current will continue to rise until it reaches its maximum steady state condition which is around five time constants when this self-induced back emf has decayed to zero. At this point a steady state current is flowing through the coil, no more back emf is induced to oppose the current flow and therefore, the coil acts more like a short circuit allowing maximum current to flow through it.

However, in an alternating current circuit which contains an AC Inductance, the flow of current through an inductor behaves very differently to that of a steady state DC voltage. Now in an AC circuit, the opposition to the current flowing through the coils windings not only depends upon the inductance of the coil but also the frequency of the applied voltage waveform as it varies from its positive to negative values.

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Answer:

250

Explanation:

Volume = (Force)/(Density)g

The density of air is 1.29 kg/m^3, the force is 3160 and gravity is 9.8

(3160)/(1.29)9.8 = 249.9 (rounded to 250)

I put that in and it is correct.

Answer:

V1 = 4/3 pi R^3 = pi D^3 / 6     D = 2 R       volume of sphere

V2 = pi r^2 L = pi d^2 L / 4       volume of wire

V2 / V1 = 1 = 3/2 d^2 L / D^3     since volumes are equal

L = 2/3 D^3 / d^2 = 2/3 * 6^3 / .02^2 = 360,00 cm = 3600 m

Answer:

moon

Explanation:

cause yes

The force is acting in the +K direction since it is perpendicular to both the velocity and the magnetic field. Force on electron = 3.08 x 10⁻¹⁷ N

Current I = 26 A

Electron velocity V = 4.77 x 10 m/s

Distance r = 1.3 cm

= 1.3 x 10⁻² m 1.

Find the magnetic field:

Formula used to calculate magnetic field is:

B= μ0×I2πr

Where, μ0 = 4π×10⁻⁷B

= μ0×I2πrB

= 4π×10⁻⁷×26 2π×1.3×10⁻²B

= 2.02 × 10^-5 T2.

Find the force acting on the electron, when it moves in the direction directly away from the wire:

Formula to calculate force on electron is:

F= qVBsinθ

Where,F = Force acting on electron

V = Velocity of electron

B = Magnetic field

q = charge of an electron

θ = Angle between the direction of motion of an electron and direction of the magnetic field that, the electron is moving in a direction directly away from the wire, so it is moving perpendicular to the wire.

Therefore, θ = 90 degrees.

So the force can be calculated as:

F= qVB sin 90

F= qVB

Therefore,F = 1.6×10⁻¹⁹×4.77×10×2.02 × 10⁻⁵

F = 3.08 x 10⁻¹⁷ N3.

Find the force acting on the electron, when it moves in the direction parallel to the wire in the direction of the current:

the electron is moving parallel to the wire, so the angle between the direction of motion of the electron and direction of the magnetic field is 0 degrees.

So the force can be calculated as:

F= qVBsinθ

F = 0N₄.

Find the force acting on the electron, when it moves in the direction perpendicular to the wire and tangent to a circle around the wire in the +J direction:

Here, the angle between the direction of motion of the electron and direction of the magnetic field is 90 degrees.

So,θ = 90 degrees

Therefore, the force on the electron can be calculated as:

F= qVB sin 90

F= qVB

Therefore,F = 1.6×10⁻¹⁹ ×4.77×10×2.02 × 10⁻⁵ F

= 3.08 x 10⁻¹⁷ N

The force is acting in the +K direction since it is perpendicular to both the velocity and the magnetic field.

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A power station works in terms of energy transfers by the process of Fuel Combustion, Steam Generation,  Steam Turbine, Generator, Electrical Transmission and Distribution and Consumption.

A power station is a facility that generates electricity by converting various forms of energy into electrical energy. The overall process involves several energy transfers. Here is a description of how a typical power station works:

1. Fuel Combustion: The power station burns fossil fuels like coal, oil, or natural gas in a boiler. The combustion of these fuels releases thermal energy.

2. Steam Generation: The thermal energy produced from fuel combustion is used to heat water and generate steam. This transfer of energy occurs in the boiler.

3. Steam Turbine: The high-pressure steam from the boiler is directed onto the blades of a steam turbine. As the steam passes over the blades, it transfers its thermal energy into kinetic energy, causing the turbine to rotate.

4. Generator: The rotating steam turbine is connected to a generator. The mechanical energy of the turbine is transferred to the generator, where it is converted into electrical energy through electromagnetic induction.

5. Electrical Transmission: The electrical energy generated by the generator is sent to a transformer, which steps up the voltage for efficient transmission over long distances through power lines.

6. Distribution and Consumption: The transmitted electricity is then distributed to homes, businesses, and industries through a network of power lines. At the consumer end, the electrical energy is converted into other forms for various uses, such as lighting, heating, and running electrical appliances.

In summary, a power station converts thermal energy from fuel combustion into mechanical energy through steam turbines and finally into electrical energy through generators. The generated electricity is then transmitted, distributed, and utilized for various purposes.

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The scale will read 147N

The mass of the object, m = 15 kg

Since I am on the earth, the acceleration due to gravity on the earth is:

g = 9.8 m/s²

The scale will read the weight of the object, and is calculated below

The weight, W = mg

W = 15(9.8)

W = 147 N

Therefore, the scale will read 147N

Answer:5mph

Explanation:

The average velocity of a man who runs forward at 8 m/s for 9 s and back again at 5 m/s for 3 s after an 8 s break is 7.25 m/s.

The average velocity of the man in this scenario can be found by dividing the total distance traveled by the total time spent moving.

The total distance traveled while running forward is 8 m/s * 9 s = 72 m, and the total distance traveled while running back is 5 m/s * 3 s = 15 m.

The total distance traveled is 72 m + 15 m = 87 m. The total time spent moving is 9 s + 3 s = 12 s.

Therefore, the average velocity is 87 m / 12 s = 7.25 m/s.

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The speed of this child from this surface would be 14.69 m / s

We have the formula for energy conservation as:

E - potential = E - kinetic

We have the following details with which we are to solve the problem

weight of child w = 350 N

length of rope L = 7.2m

angle θ = 12 degrees

we would have the solution as

m x 9.8m/s² x (10.2 + 1.79 - 7.2 x cos 12) = 1/2 mv²

we would have to solve out the expression that we have above. Such that :

9.8m * (11.99 - 0.9781) = 1/2 mv²

107.9 m = 1/2 mv²

cancel out m

107.9 = 0.5v²

divide through by 0.5

107.9 / 0.5 = v²

215.8 = v²

v = √215.8

v = 14.69

Hence the speed of the child at the surface of the water would be given as 14.69 m / s

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Answer:

1476 J

Explanation:

From the question,

Net Work done = Net force× distance moved by net force.

W' = (F-F')×d................... Equation 1

Where W' = Net work done, F = force applied, F' = Frictional force, d = distance moved.

Given: F = 150 N, F' = 37 N, d = 12 m

Substitute these values into equation 1

W' = (150-37)×12

W' = 123×12

W' = 1476 J.

hence the Net Work done by the object is 1476 J

The Kinetic energy when the child gets off halfway is 500 joules.

Kinetic energy is the kinetic energy of a body and can be observed as the motion of a body or subatomic particles. All moving objects have a certain amount of kinetic energy.

The potential energy of the children on the trampoline is

PE=1000J

At the top of the trampoline, children only have potential energy. Along the way, children have both kinetic and potential energy. At the bottom of the trampoline, children have only kinetic energy.

Based on the above statement, the child's kinetic energy is halved and calculated as:

PE + K.E = 1000J

P.E = K.E from the law of conservation of energy

2CU = 1000 years

Ke = ¹/₂ × 1000 J

Ke = 500 joules

So the correct option is C.  

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Answer:

Crumple Zones are parts of a car that are designed to deform and absorb large amounts of energy from car collisions and impacts. This helps reduce the force that acts on the driver in a car accident [1]. 2: Newton's Second Law states that Force= Mass x Acceleration

Explanation:

The pivot is located 0.1 meters to the left of the 0 cm mark.

To determine the position of the pivot, ensure that the rule is horizontally balanced. This means that the sum of the clockwise moments must equal the sum of the anticlockwise moments.

Clockwise moments = 6N x 0.15m = 0.9Nm

Anticlockwise moments = 4N x 0.3m + 3N x d, where d is the distance of the pivot from the 0cm mark.

Since the metre rule is horizontally balanced:

0.9 = 1.2 + 3d

3d = -0.3

d = -0.1m

The position of the pivot is 0.1m to the left of the 0cm mark.

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The intensity of the beam is 1.21*10^7  W/m^2 and the intensity is define as number of photons per unit time.

Radiation beam is energy in the form of waves of particles. There are two forms of radiation which are  non-ionizing and ionizing.

Non-ionizing radiation has less energy than ionizing radiation; it does not possess enough energy to produce ions.

Ionizing radiation is capable of knocking electrons out of their orbits around atoms, upsetting the electron/proton balance and giving the atom a positive charge.

Alpha radiation consists of alpha particles that are made up of two protons and two neutrons each and that carry a double positive charge. Due to their relatively large mass and charge, they have an extremely limited ability to penetrate matter.

We know that,

Iabsorbed=P/A ------(1)

where P is the power and A is the area.

P= E/t-------(2)

using (2) and (1)

Iabsorbed=E/tA-----(3)

Now area,

A=πr^2 = 1.19*10^-5 m^2

putting in (3), we get

Iabsorbed = 1.09*10^7 W/m^2

Given only 90% of the beam is absorbed So,

I/100=1.19*10^-5/90

Now the intensity is,

I=1.19*10^-5*100/90

I=1.21*10^7 W/m^2.

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The true total mass of a galaxy cluster is much greater than the mass measured by adding up all the stars in all the galaxies of the cluster.


This is because the majority of the mass in a galaxy cluster is actually in the form of dark matter, which cannot be detected through traditional methods like observing stars. Dark matter is a mysterious substance that interacts only through gravity and is thought to make up about 85% of the matter in the universe.

Therefore, the true total mass of a galaxy cluster is much higher than what is visible through telescopes. Scientists use a variety of methods, such as gravitational lensing and the motions of the galaxies within the cluster, to estimate the amount of dark matter present and thus determine the true mass of the cluster. Understanding the distribution and amount of dark matter in galaxy clusters is an important part of studying the large-scale structure of the universe.

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Answer:

if an object starts from rest it's initial velocity is zero

Answer:

the answer is b.

plsss pa brainliest po ako

Answer:

a. Light bulb - electrical to light

b. Firework - chemical to light / thermal / sound

c. Flute - kinetic to sound

d. Leaf-  solar to chemical

Answer:

131 N

Explanation:

F = 82.0 kg x 1.60 m/s^2 = 131.2 N

To find the slope of the position-time relationship for the bowling ball using the "rise over run" algorithm, you'll first need the coordinates obtained in part b. The slope represents the rate of change of position with respect to time, and in this context, it is equal to the ball's velocity.

Using the "rise over run" algorithm, the slope (velocity) can be calculated by dividing the change in position (rise) by the change in time (run). In this case, the coordinates represent the position and time values, with the first coordinate being the initial position and time, and the second coordinate being the final position and time.

Assuming you have two coordinates (x1, y1) and (x2, y2), where x values represent time and y values represent position:

Slope = (y2 - y1) / (x2 - x1)

Once you have the coordinates from part b, plug the values into the formula above to calculate the slope. This will give you the velocity of the bowling ball, which represents the relationship between the position and time for the given motion.

For example, if the coordinates from part b are (0.4 s, 2.5 m) and (0.8 s, 5 m), the slope would be:

Slope = (5 m - 2.5 m) / (0.8 s - 0.4 s) = 2.5 m / 0.4 s = 6.25 m/s

In this example, the slope (velocity) of the position-time relationship for the bowling ball is 6.25 m/s.

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