what is the focal length of 2.0 d reading glasses found on the rack in a pharmacy

Answer:

Alloys are just mixtures of metal and metalloids are metallic substances with properties of metal.

Answer:

metalloids are chemical elements that form substances that have properties of metals and non metals while alloys is a mixture of metals

Answer:

control group and experimental group

The net force on the box perpendicular to the floor is

∑ F[perp] = F[normal] - mg = 0

where mg is the weight of the box. Then

F[normal] = mg = 147 N

so that

F[friction] = 0.3 F[normal] = 44.1 N

The net force parallel to the floor is

∑ F[para] = F[applied] - F[friction] = ma

where a is the acceleration of the box. Then

F[applied] = (15 kg) a + 44.1 N

Then the work done by the applied force is

W[applied] = ((15 kg) a + 44.1 N) (1 m) = (15a + 44.1) J

We can't find the exact amount of work without any more information. If the box is pulled with constant speed, then a = 0 so the work would be 44.1 J.

Answer:toward the ceiling

Explanation:

if you use the right hand rule it will point to the ceiling

A 1600 kilogram small vehicle and a 20 000 kg truck traveling at a speed of 84.74 km/h have same amounts of kinetic energy .

A particle or an item that is in motion has a sort of energy called kinetic energy. An item accumulates kinetic energy when work, which involves the transfer of energy, gets done on it by exerting a net force.

Briefing :

Kinetic energy is that which is due to the movement of bodies and is calculated like this:

K = (1/2)mv² Formula (1)

Data for the truck

m = 20000 kg

v = 24 km/h

   = 24 *(1000m)/ (3600s)

v = 6.66m/s

Calculation of the kinetic energy of the truck

We replace data in the formula (1)

K = (1/2)mv²

K = (1/2)(20000)(6.66)²

K = 443556J

Data for the compact car

K = 443556 J

  = 443556 (N*m)

m = 1600 kg

Calculation of the speed  of the compact car

We replace data in the formula (1)

          K = (1/2)mv²

443556 = (1/2)( 1600)(v)²

443556 = ( 800)(v)²

v² = 443556/ (800)

\(v=\sqrt{\frac{443556}{800} }\)

v = 23.54m/s

1 km = 1000 m

1 h = 3600 s

v =23.54*(3600/1000)km/h

v =84.74 km/h

Therefore , speed of car is is 84.74 km/h

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The mass of the egg = 0.23 kg

The force, F = 16 N

The acceleration, a = 68.6 m/s²

The relationship between the force (F), acceleration (a), and mass (m) is:

F = ma

Substitute F = 16, a = 68.6, and solve for m

16 = 68.6m

m = 16/68.6

m = 0.23 kg

Answer:

B. A well-tested explanation for a widely accepted hypothesis

Explanation:

This is true about a scientific theory going by the fact of it being a well tested explanation. For example, in one of the Newtons law of motion which he stated to be "To every action, there is equal and opposite reaction", the hypothesis has been known till he was able to offer a well tested explanations with calculations showing that, it was actually true.

Since the lamp gives no light when the brightness control is at its lowest setting. The reason that the torch would still need a switch as well as the brightness control is because the switch can completely turn the lamp off, while the brightness control only adjusts the intensity of the light.

In the above case, there may be situations where it is necessary to completely turn the lamp off, such as when it is not needed or when it is being used in a place with sensitive equipment that could be affected by the light.

Additionally, the switch may be used to conserve energy by turning the lamp off when it is not needed.

In all, the switch allows the lamp to be turned off completely, while the brightness control adjusts the intensity of the light. Both the switch and the brightness control can be useful in different situations.

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The capacitance needed to store 19.0 μC of charge is 0.19 μF.

To calculate the required capacitance, we use the formula Q=C*V, where Q is the charge stored in coulombs (C), C is the capacitance in farads (F), and V is the voltage across the capacitor in volts (V).

Given the charge of 19.0 μC (1 μC = 10^-6 C), the voltage of 10.0 V, we can rearrange the formula to find C:

C = Q/V = 19.0 x 10^-6 C / 10.0 V = 1.9 x 10^-5 F = 0.19 μF

So the capacitance needed to store 19.0 μC of charge is 0.19 μF.

It's important to note that capacitance is expressed in farads and not microfarads (μF) in this formula. If you were using μF, you would need to convert the charge to microcoulombs (19.0 μC = 19.0 x 10^-6 C).

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Answer:

This question is incomplete, as it lacks options. The options are:

A. chemical energy is the same and additional energy is produced as heat and light.

B. chemical energy is more than the amount of heat and light

C. the amount of chemical energy is less than the amount of heat and light energy

D. the amount of chemical energy equals the amount of heat and light energy.

The answer is D

Explanation:

According to the first law of thermodynamics, which is the LAW OF CONSERVATION OF ENERGY, energy is neither created nor destroyed but can only be changed from one form to another. This law states that no energy in a system is lost, hence, the input energy must be equal to the output energy.

When a log of wood is burnt, the chemical energy stored in it is converted to heat energy and light energy. Based on the law of conservation of energy, the amount of chemical energy present in the log before the burning process must equal the amount of light and heat energy it changed to after the burning process.

That is, chemical energy = light energy + heat energy.

(a)The two balls will exert equal and opposing forces on one another during the head-on elastic impact, changing their velocities as a result. (b)the momentum of Ball A before the collision is 0.875 kgm/s.(c) The total momentum after collision 0.875 kgm/s.(d). the velocity of each Ball after the collision is 7.0m/s.  

(A) During the head-on elastic collision, the two balls will exert equal and opposite forces on each other, causing them to change their velocities. Ball A will slow down and Ball B will speed up until they both reach a new velocity after the collision.

(B) The momentum of Ball A before the collision can be calculated using the formula:

Momentum = mass x velocity

Momentum of Ball A = 0.25kg x 3.5m/s = 0.875 kgm/s

(C) The total momentum after the collision can be calculated using the principle of conservation of momentum, which states that the total momentum of a system remains constant if there is no external force acting on it. Since this is an elastic collision, the total momentum of the system before and after the collision remains the same.

Total momentum before collision = Total momentum after collision

Momentum of Ball A before collision = Momentum of Ball A after collision

Momentum of Ball B before collision = Momentum of Ball B after collision

Therefore, the total momentum after the collision is also 0.875 kgm/s.

(D) To determine the velocity of each ball after the collision, we can use the equations of conservation of momentum and conservation of kinetic energy for elastic collisions. The equations are:

Total momentum before collision = Total momentum after collision

1/2 x mass x (velocity)²before collision = 1/2 x mass x (velocity)² after collision

0.25kg x 3.5m/s = 0.25kg x vA + 0.25kg x vB

1/2 x 0.25kg x (3.5m/s)² = 1/2 x 0.25kg x (vA)² + 1/2 x 0.25kg x (vB)² (conservation of kinetic energy) Solving these equations simultaneously, we get:

vA = 0.0 m/s

vB = 7.0 m/s

Therefore, Ball A comes to a complete stop after the collision, and Ball B moves with a velocity of 7.0 m/s in the opposite direction.

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Lightning is an electrostatic discharge which occurs naturally within the storm. The electrostatic discharge is due to electrically charged regions in the storm.

Lightning can be defined as the naturally occurring electrostatic discharge during which two electrically charged regions positive and negative, both in the same atmosphere or with one on the ground, and other at a certain distance which temporarily neutralize each other, causing the instantaneous release of an average of about one gigajoule of energy from the effect.

The electric field within the storm is not the only field which develops. Below the negatively charged storm base in this region, positive charge begins to pool within the surface of the earth. This positive charge will then shadow the storm whichever direction it goes, and is responsible for the cloud-to-ground lightning.

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Change in length in meters is 0.21 m

volume is given by

 \(V_{f} = lwh\\\)

v = volume  \(V_{f}\) = Final  volume , \(V_{i}\) = initial volume

l = length

w = width

h = height

change in volume expansion,

\(V = \beta V_{i} T\)

where

t = change in temperature

\(\beta\) = coefficient of volume expansion

coefficient of volumetric expression defined as increasing volume per unit, original volume per Kelvin rising temperature.

\(\beta \\\) = 210×10⁻⁶ C⁻¹

\(V_{i} = lwh_{i}\)  

\(V_{f} - V_{i} = \beta V_{i}T\)

on solving we get,

\(h_{f} =\) 210×10⁻⁶ × 1 + 1000 = 1000.21m

Change in length=  \(h_{f} -h_{i}\)  = 0.21 m

Change in length in meters is 0.21 m

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The graphs display the function solution y = ex and three numerical solutions -Euler, Improved Euler, and Runge-Kutta- at different intervals. The Relative Deviation on the right measures the difference between the numerical solutions and the exact function solution.

The analysis of each set of graphs involves comparing the numerical solutions (Euler, Improved Euler, and Runge-Kutta) with the exact function solution y = ex. The Relative Deviation provides an indication of how closely the numerical solutions approximate the exact solution.

To analyze each set of graphs, follow these steps:

By examining the graphs and assessing the Relative Deviation, one can analyze the accuracy and performance of the numerical solutions -Euler, Improved Euler, and Runge-Kutta- in approximating the exact function solution y = ex at different intervals or iterations.

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Radius of the planet's orbit is 2.15 * \(10^{-6}\) m

Radius of the orbit can be calculated by applying Kepler's third law, which  compares the motion characteristics of different planets, i.e. it compares the orbital period and the radius of the orbit.

Where

T = Time period = 300Days ( Period)

r = radius

G =   Gravitational constant = 6.67 * \(10^{-11}\) m³/Kgs

M =  Mass of the object, sun in this case = 1.99 * \(10^{30}\) kg

Then, rearranging the Kepler's equation,

\(R^{3} = GMT^{2} /4\pi ^{2}\)

R³ = 100 * \(10^{-19}\)

R = 2.15 * \(10^{-6}\) m

The radius of the planet which is reported to orbiting for 300 days is 2.15 * \(10^{-6}\) m

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Answer:

Explanation:

The sense of weightlessness in orbiting satellite is because of the lack of any contact-forces. ... Thus, both the astronaut and the satellite have the same value of g, which is again equal to the centripetal acceleration of the satellite. These two neutralize each other, causing everything to appear weightless.

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The momentum expectation value of the free particle wavefunction e −ikx is -k, while the momentum expectation value of the free particle wavefunction e +ikx is +k.

This tells us that free particles described by e −ikx are moving in a direction opposite to the direction of k, while free particles described by e +ikx are moving in the direction of k.

This indicates that the direction of motion of the free particles is determined by the sign of k, with particles moving in the opposite direction for negative k values and particles moving in the same direction for positive k values. In other words, the sign of k determines the direction of the momentum of the free particles.

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Answer:

The dimension of thermal conductivity is M1L1T−3Θ−1, expressed in terms of the dimensions mass (M), length (L), time (T), and temperature (Θ). Other units which are closely related to the thermal conductivity are in common use in the construction and textile industries.

Explanation:looked it up for ya

The final velocity of the red-blue carts system is 5 cm/s.

The final speed of the two carts, that is the red cart and the blue cart system after the collision is calculated by applying the principle of conservation of linear momentum.

Pi = Pf

m₁u₁ + m₂u₂ = v ( m₁ + m₂ )

where;

m₁u₁ + 0 = v ( m₁ + m₂ )

m₁u₁ = v ( m₁ + m₂ )

v = ( m₁u₁ ) / ( m₁ + m₂ )

The final velocity of the red-blue carts system is calculated as;

v = ( 50 kg cm/s ) / ( 5 kg + 5kg )

v = 5 cm/s

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The complete question is below:

A red cart is moving rightward with a momentum of 50 kg cm/s when it collides with a blue cart of equal mass that is initially at rest. The two carts stick together and move to the right with the same speed after the collision. What is the final velocity of the two carts system after the collision if the mass of the blue cart is 5 kg.

Answer:

The Acceleration of the object = 6.4 m/s²

Explanation:

Mass of block (m) = 5 kg

Action force on block, (F₁) = 40 N

To Find:

Acceleration of the object (a) = ?

Required solution:

Frictional force opposing the motion (F₂) = 8 N

Here in this question we have to find Acceleration of the object. So, firstly we have to find Net force of block after that we will find Acceleration of the object on the basis of conditions given above

⇒ Net force = Action force on block - Opposing friction force

⇒ F = F₁ - F₂

⇒ F = 40 - 8

⇒ F = 32 N

Now, we have to two elements that used in formula, Net force and Mass of block.

Net force of the block (F) = 32 N

Mass of block (m) = 5 kg

And we have to find Acceleration of the object.

We can find Acceleration of the object by using the Second law of Newton which says F = ma

Here,

F is the Force in N.

m is the Mass in kg.

a is the Acceleration in m/s².

So let's find Acceleration (a) !

† From second law of Newton

⇛ F = ma

⇛ a = F/m

⇛ a = 32/5

⇛ a = 6.4 m/s²

The value that we get by solving the equation is 3. This we get by solving the equation and with the help of given values of u and t.

In mathematical formulas, the equals sign is used to indicate that two expressions are equal. The meaning of the word equation and its cognates might vary slightly depending on the language. For example, an equation in English is defined as any properly expressed formula that consists of two expressions connected by the equals sign, whereas an equation in French is defined as having one or more variables.

According to the question, the given values are :

u = 11 and,

t = 9.

The given equation is :

3 + 11 t - 9 u

Substitute the given values of u and t in the equation :

3 + 11 (9) - 9 (11)

= 3

Hence, after solving the equation, the value we get is 3.

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Answer:

R = -2500N

Explanation:

Use formula ΣF = Ma. We can split the Net Force into two parts: Fe - Ff  =  Ma.

Fe is the force developed by the engine: 4000N

Ff (R) is the air resistance projected on the vehicle. This is the value we're looking for.

Mass: 1000kg

Acceleration: 1.5m/s^2

Next, just plug in the values and solve.

▪4000N - Ff  =  (1000kg)(1.5m/s^2)

▪Ff = 1500N - 4000N

▪Ff = -2500N

R = -2500N.

The air resistance acting on the car is R = -2500N.

Part A: The car experiences an acceleration of 9.3 m/s² when towed.

Part B: The notebook reaches you with a speed of 16.9 m/s in 1.6 seconds.

Part C: The speed of the falling notebook midway is 12.8 m/s.

Part A: To calculate the acceleration generated in the car, we need to determine the net force acting on it. We can start by calculating the force of friction using the formula:

Force of friction = coefficient of friction × normal force

The normal force is the force exerted by the ground on the car, which is equal to its weight:

Normal force = mass × acceleration due to gravity

Given that the mass of the car is 1100 kg and the acceleration due to gravity is approximately 9.8 m/s²:

Normal force = 1100 kg × 9.8 m/s² = 10780 N

Now we can calculate the force of friction:

Force of friction = 0.35 × 10780 N = 3773 N

The net force acting on the car is the difference between the applied force (horizontal pull) and the force of friction:

Net force = applied force - force of friction

Net force = 14000 N - 3773 N = 10227 N

Using Newton's second law (F = ma), we can calculate the acceleration:

Net force = mass × acceleration

10227 N = 1100 kg × acceleration

acceleration = 10227 N / 1100 kg ≈ 9.3 m/s²

Therefore, the acceleration generated in the car is approximately 9.3 m/s².

Part B: To calculate the speed of the notebook as it reaches you, we can use the equation for free fall motion:

v = \(\sqrt{(2gh)}\)

Given that the height from which the notebook is dropped is 13 m:

v =\(\sqrt{ (2 × 9.8 m/s^2 × 13 m)}\) ≈ 16.9 m/s

Therefore, the speed of the notebook as it reaches you is approximately 16.9 m/s.

Part C: To calculate the time taken by the notebook to reach you, we can use the equation for free fall motion:

t = \(\sqrt{(2h / g)}\)

Using the same height of 13 m:

t =\(\sqrt{ (2 × 13 m / 9.8 m/s^2) }\)≈ 1.6 s

Therefore, the time taken by the notebook to reach you is approximately 1.6 seconds.

To calculate the speed of the falling notebook midway between the window and the ground, we can use the equation for free fall motion:

v = \(\sqrt{(2gh)}\)

Given that the height from the midpoint to the ground is 6.5 m:

v = \(\sqrt{(2 × 9.8 m/s² × 6.5 m)}\) ≈ 12.8 m/s

Therefore, the speed of the falling notebook midway between the window and the ground is approximately 12.8 m/s.

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Percentage increase in Tension = 4.34%

To answer your question, we need to use the wave speed formula and consider the relationship between wave speed, tension, and percentage increase.

The wave speed formula is v = √(T/μ), where v is the wave speed, T is the tension, and μ is the linear mass density. Since the wave speed is increased by 2.13%, the new wave speed (v') can be expressed as v' = v * 1.0213.

We want to find the percentage increase in tension, so we can set up the following equation:

v'² = (T' * 1.0213)² = T' / μ

Solve for T':

T' = μ * (v * 1.0213)²

Now, we can find the percentage increase in tension:

Percentage increase = ((T' - T) / T) * 100

Substitute T' with the expression we found earlier:

Percentage increase = ((μ * (v * 1.0213)² - T) / T) * 100

Simplifying this equation, we find that the percentage increase in tension should be approximately 4.34%.

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Answer:

x = 4.32 [m]

Explanation:

We must divide this problem into three parts, in the first part we must use Newton's second law which tells us that the force is equal to the product of mass by acceleration.

∑F = m*a

where:

F = force = 700 [N]

m = mass = 2030 [kg]

a = acceleration [m/s²]

Now replacing:

\(F=m*a\\700=2030*a\\a = 0.344[m/s^{2}]\)

Then we can determine the final speed using the principle of conservation of momentum and amount of movement.

\((m_{1}*v_{1})+Imp_{1-2}=(m_{1}*v_{2})\)

where:

m₁ = mass of the car = 2030 [kg]

v₁ = velocity at the initial moment = 0 (the car starts from rest)

Imp₁₋₂ = The impulse or momentum (force by the time)

v₂ = final velocity after the impulse [m/s]

\((2030*0) + (700*5)=(2030*v_{2})\\3500 = 2030*v_{2}\\v_{2}=1.72[m/s]\)

Now using the following equation of kinematics, we can determine the distance traveled.

\(v_{2}^{2} =v_{1}^{2}+2*a*x\)

where:

v₂ = final velocity = 1.72 [m/s]

v₁ = initial velocity = 0

a = acceleration = 0.344 [m/s²]

x = distance [m]

\(1.72^{2}=0^{2} +(2*0.344*x) \\2.97 = 0.688*x\\x = 4.32 [m]\)

answer :

force is called the magnetic force of repulsion, and it happens when two magnets have the same poles (either both north or both south) and they push away from each other.

When all the domains in a material are aligned in the same direction, the material becomes strongly magnetized.

explanation :

magnetic domains in the rings were stable and strong enough to resist the force of gravity.

In the case of the levitating rings, the magnetic domains were aligned in such a way that they created a strong magnetic field, which allowed the rings to levitate in mid-air.

tiny regions within ferro magnetic  material that have their own magnetic fields are called magnetic domains.

Magnetic domains in the rings refer to the tiny regions within the ring's ferro magnetic material that have their own magnetic fields.

Frosted glass is made of glass with a scratched surface and it is translucent because of its partial transparency.

Technically speaking, frosted glass is a transparent sheet of glass that has been etched or sandblasted to become opaque. The glass appears translucent as a result of light scattering during transmission, obstructing visibility even while light is transmitted through it.

Therefore, Translucent materials include certain polymers and frosted glass. Only a portion of the light that strikes transparent materials goes through. The materials prevent the light from passing through them directly.

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Answer:

D : An electron may act with either particle-like or wave-like characteristics.  

Explanation:

This is the whole basis of the Schrödinger equation.

The other options are correct, but they do not state the dual nature of the electron.

Ideally in no air resistance, the ball will return to the thrower's hand with a speed of 10 m/s. Thus, the correct option is B.

Speed is the distance covered by an object with respect to time taken. It can also be defined as the change in the position of an object with respect to time. It is a scalar quantity as it has only magnitude and no direction.

The ball which is thrown straight upward in the sky with a speed of 10 m/s will return back to the thrower's hands with a speed of 10m/s in the ideal case of no air resistance because during this situation, no acceleration takes place. At the highest point, the velocity of the ball is zero however the ball is still under the influence of gravity, here the acceleration due to gravity is acting downwards on the ball.

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