What is the field of view? that is, what width on the microscope stage, in mm , fills the sensor?

Answers

Answer 1

The largest area that can be seen through a microscope eyepiece or a scientific camera is known as the field of vision (FOV) of a microscope, and it is typically expressed as a diameter measurement.

What is field of vision?

The size of the visible environment at any particular time is known as the field of vision (FOV). It is a solid angle through which a detector is sensitive to electromagnetic radiation in the case of optical instruments or sensors.

The term "field of view" is normally only used in the context of human and primate vision to refer to a restriction of what is visible by external apparatus, such as when wearing spectacles. The definition allows for eye movements, but when interpreted in this way, they do not alter the field of vision.

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Related Questions

If a baseball lands with a speed of 80 miles/hr after traveling with an acceleration of -6 miles/hr/sec for 5seconds, what was the initial speed at which the ball was hit?

Answers

We are given that an object falls with an acceleration of -6 miles/h/s. To determine the initial velocity we will use the following motion:

\(v_f=v_0+at\)

Where:

\(\begin{gathered} v_f,v_0=\text{ final and initial velocity} \\ a=\text{ acceleration} \\ t=\text{ time} \end{gathered}\)

Now, we solve for the initial velocity by subtracting "at" from both sides:

\(v_f-at=v_0\)

Now, we plug in the values:

\(80\frac{mi}{h}-(6\frac{mi}{hs})(5s)=v_0\)

Now, we solve the operations:

\(50\frac{mi}{h}=v_0\)

Therefore, the initial velocity is 50 mi/h.

A cloud directly above you is about 10° across. From the weather report you know that the cloud is at an altitude of 2200 m. How wide is the cloud?

Answers

Answer:

2 π Θ = 360      where Θ is the angle of 1 rad = 57.3 deg

W = R Θ = 2200 m * 10 / 57.3 = 384 m

Note: The difference between radian measure (distance along arc of circle) and the chord of a circle is quite small for 10 deg - probably the cloud is not completely flat anyway

Can a resultant forces' direction be north or south, or is it only East and West?

Answers

From anywhere. Resultant forces can act from any direction depending on the variables.

blue light of wavelength 480 nm is most strongly reflected off a thin film of oil on a glass slide when viewed near normal incidence. assuming that the index of refraction of the oil is 1.2 and that of the glass is 1.6, what is the minimum thickness of the oil film (other than zero)?

Answers

The minimum thickness of the oil film for blue light of wavelength 480 nm to be most strongly reflected off a glass slide with index of refraction 1.6 and an oil with index of refraction 1.2 is approximately 96 nm.

The condition for constructive interference (i.e. strong reflection) of light waves reflected from a thin film is given by 2nt = mλ, where n is the refractive index of the film, t is the thickness of the film, m is an integer representing the order of the interference, and λ is the wavelength of the incident light. In this case, we want to find the minimum thickness of the oil film for blue light of wavelength 480 nm (corresponding to m = 1) to be most strongly reflected when viewed near normal incidence.

Using the given refractive indices, we can calculate the reflection coefficient for the oil-glass interface using the Fresnel equations, which is approximately 0.05. Therefore, we want to choose the thickness of the oil film such that the distance traveled by the reflected wave in the oil film is equal to half the wavelength of the incident light, which leads to the condition 2nt = λ/2. Solving for t, we get t = λ/4n = (480 nm)/(4*1.2) ≈ 100 nm.

However, this calculation assumes that the light travels in a vacuum, whereas in reality it is traveling in the oil and glass media, which affects its effective wavelength. We can correct for this by dividing the thickness by the refractive index of the oil, which gives the minimum thickness as t = (480 nm)/(4*1.2)/1.2 ≈ 96 nm.

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Baker's weight and mass are measured on Earth and on the moon. Which measurement is the same in both places?

Answers

Answer: mass

The mass of a person is constant, weight is a force that is influenced by gravity.

What is the magnitude of the x-component of force ?

What is the magnitude of the x-component of force ?

Answers

ANSWER

EXPLANATION

If force F keeps the object in equilibrium

Answer:

See below

Explanation:

Find the x components of all of the forces shown, add them together, the x-component of the force F will be exactly opposite ( same magnitude but 180 degrees different)

30 cos 55  +     40 cos 205   +   50 cos 320  =  19.26    <====x component sum of all of the forces shown

F  (the x component of ) will be   Either    - 19.26   At zero degrees

                                                                 Or 19.26 at 180 degrees

Which two options are forms of potential energy?
O A. Electrical energy
B. Elastic energy
O C. Magnetic energy
D. Light energy
O E. Sound energy

Answers

Answer(s): A and B :)

A. Electrical energy  B. Elastic energy  are the forms of potential energy.

What is potential energy?

Potential energy is the energy possess by an object because due to its position relative to other objects, stresses within itself, its electric charge, or other factors.

Types of Potential energy:

Elastic potential energy  - It is stored in objects that can either be stretched or compressed. The more the object is stretched or compressed, the more elastic potential energy it will  have. A classic example is a stretched rubber bandElectric potential energy - Is the energy that is needed to move a charge against an electric field. We need more energy to move a charge  in the electric field, but also more energy to move it through a stronger electric field.

Therefore,

Electrical energy , Elastic energy are the forms of potential energy.

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Prosody and automaticity are related to a decrease in reading fluency.

Answers

While prosody and automaticity are different aspects of reading fluency, they are closely intertwined. A deficit in one area can affect the other, leading to difficulties with overall reading proficiency.

Prosody and automaticity are two key components of reading fluency. Prosody refers to the rhythm, intonation, and expression with which we read aloud. It is the musicality of language that allows us to convey meaning beyond the literal words on the page. In contrast, automaticity refers to the ability to read words quickly and accurately, without conscious effort. This enables us to focus on higher-level comprehension and interpretation, rather than getting bogged down by decoding individual words.
Research has shown that both prosody and automaticity are important for developing strong reading skills. However, it is also true that problems with either component can lead to a decrease in reading fluency. For example, if a student struggles with decoding words, they may have to slow down to sound out each word, which can disrupt the natural flow of language and affect their prosody. Similarly, if a student has weak automaticity, they may be so focused on reading individual words that they don't have the mental capacity to attend to prosodic cues.
In conclusion, while prosody and automaticity are different aspects of reading fluency, they are closely intertwined. A deficit in one area can affect the other, leading to difficulties with overall reading proficiency. Therefore, it is important for educators to support students in developing both prosody and automaticity in order to promote strong, fluent reading skills.

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Which statement describes a question that can be answered by a scientific
investigation?
A. It is a question that can be answered by gathering other scientists'
opinions.
B. It is a question that can be answered by gathering data during an
experiment.
C. It is a question about a phenomenon of which no measurements
can be taken.
D. It is a question about the sequence of experimental steps.

Answers

Answer:

Its b

Explanation:

I just did this question

The question that can be answered by scientific investigation is that can be answered by gathering  data during an experiment. Thus option B is correct.

What is scientific investigation?

Investigation on a natural phenomenon or process to solve a scientific question or to solve a social or environmental issue by well designed experiments based on reasonable observations is called scientific investigation.

A scientific investigation includes, variables, hypothesis , observations, research  methodology. Scientific experiments have to well designed to address all the outcomes of the observations and  must be feasible to prove whether the hypothesis is true or not.

Scientific investigations cannot be conducted based on only opinions from scientists or scientific record. The data have to be collected through experiments conducted by well designed research methodology.

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Two particles each of mass m start to approach each other from a large separation due to mutual gravitational attraction. When separation becomes r, the magnitude of momentum of each particle in the frame of centre of mass is

Answer is option ( B )
I just need the explanation and want to verify the way I solved the answer! ​

Answers

We can use the conservation of momentum and the principle of conservation of energy to determine the magnitude of the momentum of each particle in the frame of the center of mass.

Initially, the two particles are at rest and separated by a large distance. Therefore, the initial momentum of the system is zero. As the two particles approach each other, they will accelerate towards one another due to their mutual gravitational attraction. The distance between them will decrease and their speed will increase.

At some point, the particles will be at a separation r and will have a velocity v relative to the center of mass. The magnitude of the momentum of each particle can be calculated as follows:

Conservation of momentum:

The total momentum of the system is conserved, so the momentum of the two particles must be equal in magnitude and opposite in direction.

m1v1 + m2v2 = 0

Centre of mass:

The center of mass of the system is given by:

r_com = (m1r1 + m2r2) / (m1 + m2)

Since the particles are initially at rest, their initial positions are given by:

r1 = -r2 = r_initial

At separation r, the positions of the particles are given by:

r1 = r_com + r / 2

r2 = r_com - r / 2

Conservation of energy:

The total energy of the system is conserved. Initially, the particles are at rest and have no potential or kinetic energy. At separation r, the kinetic energy of the system is given by:

KE = (1/2) m1v1^2 + (1/2) m2v2^2

The potential energy of the system is given by:

PE = -G m1 m2 / r

where G is the gravitational constant.

At separation r, the total energy of the system is:

E = KE + PE

Substituting the expressions for KE and PE:

E = (1/2) m1v1^2 + (1/2) m2v2^2 - G m1 m2 / r

Since the total energy is conserved, the value of E is the same at all separations.

Substituting for v1 and v2 from the conservation of momentum equation:

v1 = - v2

We can express the momentum of each particle in terms of the relative velocity v and the masses m1 and m2:

p1 = m1 v / 2

p2 = - m2 v / 2

Substituting these expressions into the equation for the center of mass:

r_com = (m1r1 - m2r2) / (m1 - m2)

we can eliminate v and obtain an expression for the momentum of each particle in terms of the masses and separation:

p1 = p2 = (m1 m2 v) / (m1 + m2)

Substituting the expression for v from the conservation of energy equation:

v^2 = 2 G m1 m2 / (r (m1 + m2))

we obtain the final expression for the magnitude of the momentum of each particle:

p1 = p2 = sqrt(2 G m1 m2 r / (m1 + m2))

Therefore, the magnitude of the momentum of each particle in the frame of the center of mass is given by:

p1 = p2 = sqrt(2 G m1 m2 r / (m1 + m2))

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The electric current in which electrons move at an even rate and flow only in one direction is called a: a) load b) closed circuit c) general shock d) direct current.

Answers

Electric current is the flow of electric charge through a conductor. This flow of charge can occur in different ways, resulting in different types of current. In direct current (DC), the electrons move at an even rate and flow only in one direction. In other words, the flow of charge is unidirectional, from the negative terminal to the positive terminal of a source of electricity, such as a battery or a generator.

In a DC circuit, the direction of the current remains the same over time, unlike in alternating current (AC) circuits, where the direction of the current changes periodically. DC is commonly used in electronic devices and equipment that require a constant and reliable flow of electrical energy. For example, batteries, electronic circuits, and some motors use DC.

DC is also used in certain applications where the flow of current needs to be controlled in one direction only. For example, in electroplating, where a metal is deposited onto a surface by an electric current, DC is used to ensure that the metal ions move in one direction only and are deposited uniformly on the surface.

In summary, DC is a type of electric current in which the flow of electrons is unidirectional, moving from the negative to the positive terminal of a source of electricity. It is commonly used in electronic devices and equipment that require a constant and reliable flow of electrical energy.

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suppose that at midnight you observe the moon due south on the meridian. where will it be two nights later at the same time? group of answer choices

Answers

Suppose that at midnight you observe the Moon due south on the meridian. It will be about 26 degrees east of my meridian two nights later at midnight. Therefore, option (b) It will be about 26 degrees east of my meridian, is correct.

When you observe the moon due south on the meridian, it is at the highest point it can be in the sky at your position. The moon's movement in the sky is from east to west. As a result, two nights later at midnight, it will be about 26 degrees east of your meridian. On Earth, the sky is divided into 24 time zones, with each time zone spanning 15 degrees of longitude. The sky can be seen in its entirety over a period of one year by an observer in Bellingham. The sky is constantly changing as the earth rotates on its axis, causing the stars to appear in different positions each night. In Bellingham, the observer can see roughly half of the overall sky over the course of one year.

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Correct question:

Suppose that at midnight you observe the Moon due south on the meridian. Where will it be two nights later at midnight?

a.It will be about 26 degrees west of my meridian.

b.It will be about 26 degrees east of my meridian.

c.It will be about 26 degrees north of my meridian.

d.It will be about 26 degrees south of my meridian.

Over a period of one year, how much of the overall (night) sky would a Bellingham observer be able to see?

what is the efficiency of an engine that puts out 250 J of work for every 500 J of heat put into it?

Answers

If you put 300 J of heat into an engine with an efficiency of 0.35, how much work can be done? 3. How much energy must be put into an engine with an efficiency of 0.6 if 270 J of work are required? 4. An engine with an efficiency of 0.425 uses 1200 J of energy. Find the amount of energy wasted by the engine. 5. Calculate the efficiency of an engine operating between temperatures of 258 K and 600 K 6. An engine runs with its exhaust (cold) reservoir at a temperature of 200 K. To what temperature should the input (hot) temperature be set if an efficiency of 0.8 is desired? 7. Complete the following table of temperatures. Fahrenheit Celsius Kelvin 213 15 98.6 75 408

Use all three of Newton's laws of motion to
describe what happens when a car starts
off at rest, is pushed across a platform, and
then accelerates downward.

Answers

Initially the car is at rest (.Newton’s 1st Law says the car will remain at rest unless an unbalanced force acts). When pushed, the contact force on the car is equal to an equal force on the person pushing it (Newton’s 3rd Law). If the forces on the car are unbalanced it will accelerate downward (Newton’s 2nd law= the force is equal to the rate of change of momentum of the car)

What are the basic formulas to convert linear velocity to angular velocity and vice versa?

Answers

The conversion between linear velocity and angular velocity is an essential concept in physics, particularly in the study of rotational motion.

In rotational motion, an object rotates around an axis, and its motion is described in terms of angular velocity. Linear velocity, on the other hand, refers to the speed of an object moving along a straight line.

To convert linear velocity to angular velocity, you can use the formula ω = v / r, where ω represents the angular velocity, v represents the linear velocity, and r represents the radius.

This formula states that the angular velocity is equal to the linear velocity divided by the radius of rotation. The radius is the distance between the axis of rotation and the point at which the linear velocity is measured.

Conversely, to convert angular velocity to linear velocity, you can use the formula v = rω, where v represents the linear velocity, ω represents the angular velocity, and r represents the radius.

This formula states that the linear velocity is equal to the product of the radius and the angular velocity.

The formulas are crucial in various fields of physics, including engineering, mechanics, and astronomy, as they enable scientists and engineers to determine the relationship between linear velocity and angular velocity.

By applying these formulas, they can calculate the rotational speed of objects, such as gears and wheels, and design machines that operate efficiently and safely.

In conclusion, understanding the conversion between linear velocity and angular velocity is essential in physics and related fields.

The formulas ω = v / r and v = rω provide a simple yet powerful method for converting between these two types of velocity, enabling researchers and engineers to study and design rotational motion with accuracy and precision.

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The vernal equinox marks the first day of spring. What happens on this day? The north pole is tilted toward the sun. Day and night on Earth are equal. The south pole gets 24 hours of daylight. Earth's rotation on its axis slows down.

Answers

Answer:

Day and night on Earth are equal.

Explanation:

Vernal means fresh or new like the spring. The vernal equinox, because it signals the beginning of spring. On this day, the Sun is exactly above the Equator and day and night are of equal length. In the northern hemisphere, the vernal equinox is around March 20 or 21 when the Sun crosses the celestial equator going north while in the southern hemisphere, the vernal equinox is around September 22 or 23 when the Sun moves south across the celestial equator.

What is the specific heat of a 3. 78 kg object that absorbs 678 J as the temperature increases by 4. 25 K?

Answers

The specific heat of a  3. 78 kg object that absorbs 678 J is 42.2 J/(kg-K).

As per the given information in the question:

Specific heat = 3.78 kg

Absorption of the object = 678 J

Temperature increase = 4.25 K

Specific heat has units of J / (kg C).

Substituting the values in the formula,

Specific Heat = 678 / 3.78 kg * 4.25 C) = 42.2   J/(kg-K)

The specific heat is defined as the amount required to raise the temperature of a unit mass of a substance by 1 degree Celsius.

This is expressed mathematically as

Q= mc∆T

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If a book has a weight of 23.3 N on earth, what is its mass

Answers

Answer:

2.38 kg

Explanation:

by definition, weight in physics is the force of gravity (Fg)

Fg = mass x gravity or mg

gravity is 9.8 m/s^2

N = kg m/s^2

Fg = mg

23.3 kg m/s^2 = 9.8 m/s^2 x m

23.3 kg m/s^2 / 9.8 m/s^2 = m    >>> m/s^2 cancel out

23.3/9.8 = 2.37755 kg

m = 2.38 kg

a 240 turn solenoid having a length of 29 cm and a diameter of 10 cm carries a current of 0.32 a. calculate the magnitude of the magnetic field b with arrow inside the solenoid.

Answers

The magnitude of magnetic field inside the solenoid is found to be 6 × 10⁻⁵ T.

The number of turns in the solenoid is 240 and the length of the solenoid is 29 cm with the diameter of 10 cm and it is carrying a current of 0.2 ampere.

The magnitude of the magnetic field with the arrow inside the solenoid can be given by,

B = uni

Where B is the magnetic field, u is the magnetic constant, n is the number of turns and I is the current in the coil. This doesn't depend on the length and area of solenoid.

So, putting values, for the solenoid to find magnetic field,

B = 4π × 10⁻⁷ x 240 × 0.2

B = 6 × 10⁻⁵ T.

So, the value of the magnetic field in the solenoid is 6 × 10⁻⁵ T.

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The work done on an object is equal to the force times the distance moved in the direction of the force. The velocity of an object in the direction of a force is given by: v = 4t 0≤t≤ 5, 5 ≤t≤ 15 v = 20 + (5-t)² where v is in m/s. With step size h=0. 25, determine the work done if a constant force of 200 N is applied for all t a) using Simpson's 1/3 rule (composite formula) b) using the MATLAB function trapz

Answers

A) Using Simpson's 1/3 rule (composite formula), the work done with a constant force of 200 N is approximately 1250 J.

B) Using the MATLAB function trapz, the work done is approximately 7750 J.

Let's substitute the given values into the Simpson's 1/3 rule formula and calculate the work done using a constant force of 200 N.

A) Force (F) = 200 N (constant for all t)

Velocity (v) = 4t (0 ≤ t ≤ 5) and v = 20 + (5 - t)² (5 ≤ t ≤ 15)

Step size (h) = 0.25

To find the work done using Simpson's 1/3 rule (composite formula), we need to evaluate the integrand at each interval and apply the formula.

Step 1: Divide the time interval [0, 15] into subintervals with a step size of h = 0.25, resulting in 61 equally spaced points: t0, t1, t2, ..., t60.

Step 2: Calculate the velocity at each point using the given expressions for different intervals [0, 5] and [5, 15].

For 0 ≤ t ≤ 5: v = 4t For 5 ≤ t ≤ 15: v = 20 + (5 - t)²

Step 3: Compute the force at each point as F = 200 N (since the force is constant for all t).

Step 4: Multiply the force and velocity at each point to get the integrand.

For 0 ≤ t ≤ 5: F * v = 200 * (4t) For 5 ≤ t ≤ 15: F * v = 200 * [20 + (5 - t)²]

Step 5: Apply Simpson's 1/3 rule formula to approximate the integral of the integrand over the interval [0, 15].

The Simpson's 1/3 rule formula is given by: Integral ≈ (h/3) * [f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + 2f(x4) + ... + 4f(xn-1) + f(xn)]

Here, h = 0.25, and n = 60 (since we have 61 equally spaced points, starting from 0).

Step 6: Multiply the result by the step size h to get the work done.

Work done: 1250 J

B) % Define the time intervals and step size

t = 0:0.25:15;

% Calculate the velocity based on the given expressions

v = zeros(size(t));

v(t <= 5) = 4 * t(t <= 5);

v(t >= 5) = 20 + (5 - t(t >= 5)).^2;

% Define the force value

F = 200;

% Calculate the work done using MATLAB's trapz function

\(work_t_r_a_p_z\) = trapz(t, F * v) * 0.25;

% Display the result

disp(['Work done using MATLAB''s trapz function: ' num2str(\(work_t_r_a_p_z\)) ' J']);

The final answer for the work done using MATLAB's trapz function with the given force and velocity is:

Work done using MATLAB's trapz function: 7750 J

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how much work is done lifting a 35 pound object from the ground to the top of a 45 foot building if the cable used weighs 2 pounds per foot?

Answers

24,576.11 joules work is done lifting a 35 pound object from the ground to the top of a 45 foot building if the cable used weighs 2 pounds per foot.

The work done while lifting a 35 pound object from the ground to the top of a 45-foot building using a 2-pound per foot cable can be determined by calculating the potential energy of the object at the top of the building.

The potential energy of an object is given by the formula;

Potential Energy = mgh

where m is the mass of the object in kilograms,

g is the acceleration due to gravity which is approximately 9.81 m/s², and

h is the height of the building in meters.

To begin, the 35-pound object needs to be converted to kilograms as follows:

1 pound = 0.45359237 kilograms

Therefore, 35 pounds = 35 x 0.45359237 = 15.875198 kg

The cable weighs 2 pounds per foot, and the height of the building is 45 feet.

Therefore, the total weight of the cable is:

2 pounds per foot x 45 feet = 90 pounds or 40.82331 kg

The total mass, M, of the object and the cable can be found by adding the mass of the object, m, to the mass of the cable,

C.M = m + C

Therefore,

M = 15.875198 + 40.82331M = 56.698508 kg

Now that the total mass of the object and the cable has been found, the potential energy of the object at the top of the building can be calculated.

Potential Energy = mgh

Potential Energy = (56.698508)(9.81)(45)

Potential Energy = 24,576.10561 joules

Therefore, the work done lifting the 35 pound object from the ground to the top of a 45-foot building using a 2-pound per foot cable is approximately 24,576.11 joules.

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Describe such a motion from everyday experience?​

Describe such a motion from everyday experience?

Answers

Answer:

I drive my car at a speed of 30m/s is speed

I drive my car at a speed of 30m/s northward is velocity

A crane uses an average force of 5,200 N to left a girder 25m. How much work does the crane do on the girder?

Answers

Answer:

130,000 J

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 5200 × 25

We have the final answer as

130,000 J

Hope this helps you

Manu took a pebble and a sheet of paper both weigh one gram. His friend told that if we drop both at the same time, the pebble will fall straight to the floor, while the paper will slowly drift to the ground. Do you think friction have any role in this case? How can we relate that to the topic which we are learning today?

Answers

Answer: friction has no role to play in this case. because friction usually occurs between to parts which come in contacts. examples (a)our joints in the human body (b)two mechanical parts (shafts).

Explanation:

However what this topic relates to is gravity. The pebble and paper both weigh one gram, but have different density this is the sole reason why if both are drop from same height the pebble would reach the ground faster than the paper because it is more denser. unlike the paper with a lesser density which would take a longer time to reach the ground.

Can someone help me plz

Can someone help me plz

Answers

Answer:

Oceanographers can measure the salinity of a body of water in several ways, but the two most common methods are using a hydrometer set or a salinometer.

A hydrometer set consists of a cylinder, a hydrometer, a thermometer, and a temperature-salinity-density or TSD graph.

Explanation:

Hope this helps

if so please mark brainlist! thx

Answer:

B

because measuring the density of the water

Problem 11.14 A woman of mass m stands at the edge of a solid cylindrical platform of mass M and radius R. At t 0, the platform is rotating with negligible friction at angular velocity wo about a vertical axis through its center, and the woman begins walking with speed v (relative to the platform) toward the center of the platform

Answers

This can be expressed as,T2 = (M + m)aT1 = Mg/2where,T2−T1= (M + m)a − Mg/2 Solving the above equations will give the value of α and then we can find out the final velocity of the platform.

Here's the solution to the given problem: Let the origin of our coordinate system be located at the center of the platform. We can assume that there is no friction between the platform and the ground. If v  Rw, the woman will collide with the center of the platform after the platform stops moving because it is not able to move with the required speed to reach the center of the platform before it stops. The net torque about the origin, assuming that the angular momentum is conserved, is Iα = τ, or, assuming that the angular momentum is conserved,T2−T1=IwoR2wR2+mr2αT2 = Mg/2 + Mv/RT1 = (M + m)g/2Let a be the speed of the platform just after the woman reaches the center, which is given by a = v + αr. This can be expressed as,T2 = (M + m)aT1 = Mg/2where,T2−T1= (M + m)a − Mg/2Solving the above equations will give the value of α and then we can find out the final velocity of the platform.

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a bicycle frame has a 10kg frame and each wheel has a mass of 2 kg. the bicycle's speed is 10m/s what is the total kinetic energy of a single wheel

Answers

The kinetic energy of one wheel of a bicycle with a frame mass of 10 kg and a mass of each wheel of 1 kg, moving at a speed of 10 m/s, is 0.029 J.  

The kinetic energy of a wheel can be calculated using the following formula:

KE = 1/2 * m *\(v^2\)

where KE is the kinetic energy, m is the mass of the wheel, and v is the velocity of the wheel.

The mass of a single wheel is the mass of the frame plus the mass of the wheel, which is:

m = m_frame + m_wheel

= 10 + 1

= 11 kg

The velocity of the wheel is given by the velocity of the bicycle, since the wheels are attached to the frame and rotate with it. The velocity of the bicycle is given by the speed of the bicycle and its direction, which we can assume is along the positive x-axis. Therefore, the velocity of the wheel is:

v = 10 m/s * cos(θ)

where θ is the angle of the wheel with respect to the positive x-axis.

Since the wheel is a cylindrical hoop or ring, we can assume that its mass is evenly distributed around its circumference. Therefore, its mass per unit length is simply its mass divided by its circumference, which is:

m/L = 11 kg / π * 2π * 25.4 mm

= 0.29 kg/mm

The kinetic energy of the wheel can be calculated using the following formula:

KE = 1/2 * m *\(v^2\)

= 1/2 * 0.29 kg/mm * (10 m/s\()^2\)

= 0.029 J

Therefore, the kinetic energy of one wheel of a bicycle with a frame mass of 10 kg and a mass of each wheel of 1 kg, moving at a speed of 10 m/s, is 0.029 J.  

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Full Question ;

bicycle has a 10.0kg frame and each wheel has a mass of 1.00kg. The bicycle's speed is 10.0m/s. What is the kinetic energy of One wheel? Consider the wheel as a cylindrical hoop or ring.

Starting from rest, you pushed a 10.0 kg lawnmower a distance of 25 meters by applying a force of 75 N at an angle 35 degrees below horizontal, as shown below. Use work and energy principles to calculate how fast the lawn mower is moving (in m/s) at the end of the 25 meters.

Starting from rest, you pushed a 10.0 kg lawnmower a distance of 25 meters by applying a force of 75

Answers

The lawn mower is moving with a velocity of 17.53 m/s


Definition of Energy and Work

Energy is the ability to do work while Work is defined as the product of force and distance moved in the direction of the force. Both work and energy are measured in Joule (J)

Work = Force (F) × distance (d) = FdCosθ

With the above formula, we can obtain the energy used in pushing the lawn mower as illustrated below

From the question given above, the following data were obtained:

•Force (F) = 75 N

•Distance (d) = 25 m

•Angle (θ) = 35°

Energy (E) =?

E = FdCosθ

E = 75 × 25 × Cos 35

E = 1535.91 J

Definition and Determination of the velocity

Velocity is the rate of change of displacement with time.

Velocity and energy are related according to the following equation:

E = ½ × mass (m) × square velocity (v²)

E = ½mv²

With the above formula, we can obtain the velocity of the lawn mower as follow

•Mass (m) = 10 Kg

•Energy (E) = 1535.91 J

•Velocity (v) =?

E = ½mv²

1535.91 = ½ × 10 × v²

1535.91 = 5 × v²

Divide both side by 5

v² = 1535.91 / 5

Take the square root of both side

v = √(1535.91 / 5)

v = 17.53 m/s

Thus, the lawn mower is moving with a velocity of 17.53 m/s






Learn more about energy:
https://brainly.com/question/10703928

How does the line energy of an object change if the objects speed doubles?

Answers

Answer:

A

Explanation:

The kinetic energy decreases to half its original value.

This figure shows a
O a. transverse wave
O c. electromagnetic spectrum
Ob. decibel scale
Od compressional wave

This figure shows aO a. transverse waveO c. electromagnetic spectrumOb. decibel scaleOd compressional

Answers

Answer:

transverse i think

Explanation:

It’s a I did this before
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