What is the equation of the line that is perpendicular to the line y=3/5xplus 10 and passes through the point (15,-5)?

Answer:

2 cos (x + pi/2)

Step-by-step explanation:

Of the choices given, this looks like a cos curve that is shifted to the Left by pi / 2  and   multiplied to give an amplitude of 2

Answer: Percentage of cats = 28%

Therefore, percentage of dogs = (100-28)%

= 72%

Step-by-step explanation:

hope this helps have a great night❤️

Answer:

yea i think

Step-by-step explanation:

Answer:

no

Step-by-step explanation:

there are 3 feet in a yard. if we divide 12 by 3 to see how many feet there are, we get 4, not 36.

i hope this helps :))

Answer:

Step-by-step explanation:

(5x - 2)° = (4x + 5)°

5x - 2 = 4x + 5

x = 7

9514 1404 393

Answer:

  x = 2

Step-by-step explanation:

There are no algebraic methods for solving an equation like this.

The proof of Fermat's Last Theorem demonstrates that no integer x-value can possibly exist that is greater than 2. Trial and error (or your familiarity with Pythagorean triples) tells you that x=2 is a solution for this equation. Equations like this can be solved graphically, as in the attached.

Answer:

\( x =2\)

Step-by-step explanation:

Given :-

\({3}^{x} + {4}^{x} = {5}^{x} \)

And we need to find out the value of x. Well there is no specific method to solve the equation .This can be only done using the " Trial and error" Method.

\(\implies {3}^{2} + {4}^{2} = {5}^{2} \)

Verification :-

\(\implies {3}^{2} + 4^2 = 9+16=25=\boxed{5^2}\)

So , the value of x is 2 . We can here prove that , x does not have other roots other than 2 . For that , divide the both sides of equation by \(5^x\) , we have ,

\(\implies \dfrac{{3}^{x} + {4}^{x}}{5^x} = \dfrac{{5}^{x}}{5^x} \)

\(\implies \bigg( \dfrac{3}{5}\bigg)^x+ \bigg( \dfrac{4}{5}\bigg)^x = 1 \)

Now if we take the value of x greater than 2 or less than 2 , then the value 1 will not be satisfied for the values of x greater than or less than 2 .

That is ,

\(\implies \bigg( \dfrac{3}{5}\bigg)^x+\bigg( \dfrac{4}{5}\bigg)^x > \bigg( \dfrac{3}{5}\bigg)^2 +\bigg( \dfrac{4}{5}\bigg)^2 \)

Subsequently :-

\(\implies \bigg( \dfrac{3}{5}\bigg)^x+\bigg( \dfrac{4}{5}\bigg)^x > 1 \)

\(\implies \bigg( \dfrac{3}{5}\bigg)^x+\bigg( \dfrac{4}{5}\bigg)^x < \bigg( \dfrac{3}{5}\bigg)^2 +\bigg( \dfrac{4}{5}\bigg)^2 \)

Subsequently :-

\(\implies \bigg( \dfrac{3}{5}\bigg)^x+\bigg( \dfrac{4}{5}\bigg)^x <1\)

Hence 2 is the root of the given equation.

Answer:

Step-by-step explanation:

cc

The area of the roof is 1984 sq. ft. 1984 square feet of roofing is needed for the roof of a building that is 32 ft wide and 62 ft long.

Given, the length of the roof is 62 ft long and the width of the roof is 32 ft wide. Therefore, the area of the roof is length * width.

Area of the roof = length of the roof * width of the roof

Area = 62 ft * 32 ft

Area = 1984 sq. ft

Here, also given the slope of the roof is 1:2 which indicates the ratio of rise and run.

Slope of the roof = Rise / Run = 1 / 2

Then, the slope factor is \(\frac{\sqrt{\frac{ 1^{2} }{2 ^{2} } }}{12}\) = \(\frac{1}{24}\) = 0.04167

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The right question is:

How many square feet of roofing is needed for the roof of a building that is 32 ft wide and 62 ft long?

Now I am not sure what length you're supposed to find for problem 9, but x = 3.3 i think.

10.)

(14+x)+(x+21) = 13

2x+35=13

2x = -22

x = -11

FE = -11 + 14 = 3 units

11.)

10 + 2x - 10 = 3x - 8

2x = 3x - 8

-x = -8

x = 8

10 + 2(8) -10 = 16 units

Answer:

Negative Association because it is going down left to right

The box and whisker plot of the prices of some DVDs:

Minimum: 9.99

First Quartile: 12.99

Median: 15.99

Third Quartile: 19.99

Maximum: 26.99

The box and whisker plot shows that the median price of a DVD is $15.99. The prices range from $9.99 to $26.99. There are two outliers, one at $9.99 and one at $26.99.

The box and whisker plot can be used to identify the distribution of the data. In this case, the data is slightly skewed to the right, meaning that there are more DVDs priced at the lower end of the range than at the higher end.

The box and whisker plot can also be used to compare different sets of data. For example, we could compare the prices of DVDs from different stores or from different years.

Overall, the box and whisker plot is a useful tool for visualizing and summarizing data.

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The probabilities are P(a golf ball then a basketball) is 0.0451, P(a football then a baseball) is 8.33%, P(basketball, then not a football) is 0.0864 and  P(two baseballs) is 0.15.

For the first probability, we want to find the probability of drawing a golf ball first and a basketball second. There are a total of 25 balls in the bag, so the probability of drawing a golf ball first is 3/25. After drawing a golf ball, there are 22 balls left in the bag, including 3 basketballs.

Therefore, the probability of drawing a basketball second is 7/22. Since we want both events to occur, we multiply the probabilities together to get:

P(a golf ball then a basketball) = 3/23 * 7/22 ≈ 0.0451

For the second probability, we want to find the probability of drawing a football first and a baseball second. There are a total of 25 balls in the bag, so the probability of drawing a football first is 5/25.

After drawing a football, there are 24 balls left in the bag, including 10 baseballs. Therefore, the probability of drawing a baseball second is 10/24. Since we want both events to occur, we multiply the probabilities together to get,

P(a football then a baseball) = 5/25 * 10/24

= 1/12

= 0.0833

In percentage it will be 8.33%.

For the third probability, we want to find the probability of drawing a basketball first and then any ball that is not a football. There are a total of 25 balls in the bag, so the probability of drawing a basketball first is 3/25.

After drawing a basketball, there are 24 balls left in the bag, including 5 footballs. Therefore, the probability of not drawing a football second is (24-5)/24 = 19/24. Since we want both events to occur, we multiply the probabilities together to get,

P(basketball, then not a football) = (3/25) * (1 - 5/24)

= 0.0864

For the fourth probability, we want to find the probability of drawing two baseballs. There are 10 baseballs in the bag, so the probability of drawing a baseball first is 10/25. After drawing a baseball, there are 9 baseballs left in the bag out of a total of 24 balls.

Therefore, the probability of drawing another baseball second is 9/24. Since we want both events to occur, we multiply the probabilities together to get:

P(two baseballs) = 10/25 * 9/24

= 3/20

= 0.15

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Answer:

14 inches

Step-by-step explanation:

area of a circle = \(\pi r^{2}\)

We know the area = 153.86

So substitute and solve for radius.

153.86 = (3.14) * \(r^{2}\)

153.86/3.14 = \(r^{2}\)

49 = r^2

take square root of both sides

7 = r

The diameter is double the radius. Diameter = 2r

So 2 * r = 2 * 7 = 14 inches

Answer:

distances = 1.5 miles

Step-by-step explanation:

To solve this problem, we must first determine the difference between the times taken to reach school when walking and when cycling. In other words, we have to figure out how much time is saved by cycling rather than walking.

Let's assume that Julian's class starts at 10:30 am.

• When walking, he is 5 minutes late for class. Therefore, he would reach school at 10:35 am.

• When cycling, he is 16 minutes early for class. Hence, he would reach school at 10:14 am.

Therefore, the difference is 35 - 14 = 21 minutes

This means that Julian arrives 21 minutes earlier when cycling than he would if he had walked.

Next, let's assume the distance between Julian's house and school is x miles.

Since \(\mathrm{time \ taken = \frac{distance}{speed}}\), the time taken when walking and cycling is x/3 hours and x/10 hours respectively.

We know that the difference between these times is 21 minutes, i.e. \(\frac{21}{60}\) hours.

Therefore,

\(\frac{x}{3} - \frac{x}{10} = \frac{21}{60}\)

⇒ \(\frac{10x}{30} - \frac{3x}{30} = \frac{21}{60}\)      [Making the denominators of the fractions equal]

⇒ \(\frac{10x-3x}{30} = \frac{21}{60}\)

⇒ \(7x = \frac{21}{60} \times 30\)       [Multiplying both sides of the equation by 30]

⇒ \(7x = 10.5\)

⇒ \(x = \bf 1.5\)

Therefore, the distance between Julian's house and his school is 1.5 miles.

The solution to the given initial-value problem (IVP) y"-y = 0, y(0) = 5, y'(0) = 3 is y(x) = 4e^x + (5/2)e^(-x).

The solution to the given initial-value problem (IVP) y"-y = 0, y(0) = 5, y'(0) = 3 can be found by solving the second-order linear homogeneous differential equation and applying the initial conditions. The general solution of the equation is y(x) = C₁e^x + C₂e^(-x), where C₁ and C₂ are constants determined by the initial conditions.

Applying the initial condition y(0) = 5, we have 5 = C₁ + C₂.

Differentiating the general solution, we obtain y'(x) = C₁e^x - C₂e^(-x).

Applying the second initial condition y'(0) = 3, we have 3 = C₁ - C₂.

Solving the system of equations formed by the initial conditions, we find C₁ = (8/2)e^(0) = 4 and C₂ = (5/2)e^(0) = 5/2.

Therefore, the particular solution to the IVP is y(x) = 4e^x + (5/2)e^(-x).

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Answer:

Step-by-step explanation:

The triangle is being reflected over the y-axis.

A(x, y) → (x, -y)

A(1, 4) → (1, -4)

A'(1, -4)

B(x, y) → (x, -y)

B(4, 3) → (4, -3)

B'(4, -3)

C(x, y) → (x, -y)

C(2, 1) → (2, -1)

C'(2, -1)

Hope this helps!

To find the differential equation for a family of curves, we need to find an equation that relates the variables involved in the curves. For example, consider the family of curves given by:

y = mx + c

where m and c are constants. To find the differential equation for this family of curves, we can take the derivative of both sides with respect to x:

dy/dx = m

This is the differential equation for the family of curves.

To find the family of orthogonal trajectories, we need to find a new family of curves that intersect the original family of curves at right angles. We can use the fact that the product of the slopes of two perpendicular lines is -1. So, if the differential equation for the original family of curves is:

dy/dx = f(x, y)

then the differential equation for the family of orthogonal trajectories is:

dy/dx = -1/f(x, y)

To find a specific orthogonal trajectory, we need to solve this differential equation for y as a function of x.

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Answer:

5

Step-by-step explanation:

Since we have given that

If x =1 and y =3

= 2(1) × 3(3)

= 2×9

= 18

Answer:

To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12. If we know the value of our variables, we can replace the variables with their values and then evaluate the expression.

Step-by-step explanation:

hope this helps you :)

The correct answer from the choices given will be -13 - 4i. The numerical part is the real number while the term containing i is the imaginary part.

A complex number is one that both a real and an imaginary component, both of which are preceded by the letter I which stands for the square root of -1.

The given complex number as;

\(\rm 13 + 4 i + n =0\)

By transfeering the left-hand side term to the right-hand side the sign will change. We will get the value of n as;

\(\rm n=-13 - 4i\)

Hence the correct answer from the choices given will be -13 - 4i.

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Answer: Its D and for the second part its B

Step-by-step explanation:

Answer:

1 slice will be left because there are 16 slices and 15 guests

Step-by-step explanation:

Answer:

i. 13.23

ii. 20.58

iii. 76.77

iv. 84.48

Step-by-step explanation:

Here , we are to calculate the square root of we have of the decimal numbers and correct to two decimal places.

i. √(175.01) = 13.229 = 13.23

ii. √(423.74) = 20.5849 = 20.58

iii. √(5893.27) = 76.767 = 76.77

iv. √(7136.8) = 84.4795 = 84.48

Kindly note that the approximation to two decimal places are the figures after the equal to

Answer:

TV #3

Step-by-step explanation:

The others cost more.

Answer:

Step-by-step explanation:

interval in mathematics stands for a set of real numbers,

denoted by [a,b] where a and b are the starting and ending real numbers both inclusive respectively.

thus, interval [a,b] is the set of real numbers starting from a to b both are real numbers and are included.

Answer: -46 15/100

Explanation: (see pic attached)

Answer:

46 3/20

Step-by-step explanation:

Rewrite the decimal number as a fraction with 1 in the denominator

46.15=46.15/1

Multiply to remove 2 decimal places. Here, you multiply top and bottom by 10^2 = 100

46.15/1 x 100/100= 4615/100

Find the Greatest Common Factor (GCF) of 4615 and 100, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 5

4615/100 divided by 5/5= 923/20

Simplify the improper fraction

46 3/20

In conclusion

46.15= 46 3/20

I hope that helped ;)

The sum for each geometric sequence is 62.

Given:

Geometric sequence,

2 4 8 16 32

Number of terms n = 5

First term a = 2

common ratio r = 4/2

= 2

Sum \(S_5 = a(r^n-1)/r-1\)

= 2(2^5 - 1)/2-1

= 2(32 - 1)/1

= 2(31)/1

= 2*31

= 62

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Answer:

1222222222

Step-by-step explanation:

By working with percentages, we want to see how much did Gautam lost or win in the whole transaction. We will see that he loses 41.20 AED in the whole transaction.

We know that both games cost 4120 AED each.

With one, he loses 5%, meaning that he sells it at 95% of the original price, so he sells it at:

(4120 AED)*(95%/100%) = (4120 AED)*0.95 = 3914 AED

For the other he wins 4%, so he sells it at 104% of the original price, it is:

(4120 AED)*(104%/100%) = (4120 AED)*1.04 = 4284.80 AED.

The whole transaction will be:

3914 AED + 4284.80 AED - 4120 AED - 4120 AED = -41.20 AED

This means that in the whole transaction he loses 41.20 AED.

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Answer:

BEA and AED are supplementary angles  whose sum is 180°

Step-by-step explanation:

complete question is:

Consider rectangle ABCD with diagonals BD and AC  intersecting at E.

Which is true about the angle relationships in the  rectangle? Check all that apply.

Answer:

it is abd

Step-by-step explanation: