What is the equation of the line represented by the table below?

x y
-3 1
6 4
12 6
30 12

Answers

Answer 1

Answer:

\(\displaystyle y-1=\frac{1}{3}(x+3)\)

Step-by-step explanation:

Equation of a Line

The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:

\(\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\)

The table shows the relation between x and y. It contains the following points

(-3,1), (6,4), (12,6), (30,12).

Taking the two first points, we find the equation of the line:

\(\displaystyle y-1=\frac{4-1}{6+3}(x+3)\)

\(\displaystyle y-1=\frac{3}{9}(x+3)\)

Simplifying:

\(\displaystyle y-1=\frac{1}{3}(x+3)\)

To ensure the rest of the points belong to the line, we test them:

For the point (12,6):

\(\displaystyle 6-1=\frac{1}{3}(12+3)\)

\(\displaystyle 5=\frac{1}{3}(15)\)

5=5

Since equality is true, the point belongs to the line.

For the point (30,12):

\(\displaystyle 12-1=\frac{1}{3}(30+3)\)

\(\displaystyle 11=\frac{1}{3}(33)\)

11=11

Since equality is true, the point belongs to the line.

Thus, the equation of the line is:

\(\mathbf{\displaystyle y-1=\frac{1}{3}(x+3)}\)


Related Questions

Percy shuffles a standard $52$-card deck and starts turning over cards one at a time, stopping as soon as the first spade is revealed. What is the expected number of cards that Percy turns over before stopping (including the spade)

Answers

The expected number of cards Percy turns over before stopping = 3.78≈3

What is probability ?

Probability refers to the chance of occurrence of an event E.

Let E be an event and P(E) be the probability of E occurring.

Then, P(E) = \(\frac{Number Of Favourable Outcomes Of E}{Total Number Of Outcomes}\)

Now, given a 52-card deck; cards are turned over till a spade comes up.

Then, the number of cards turned over is the sum of all card over 'kth' card, having probability \(P_{k}\), where, the card 'k' comes up if no previous card was a spade.

=> \(P_{k}=\frac{\binom{39}{k}}{\binom{52}{k}} = \frac{39!(52-k)!}{52!(39-k)!}\)

\(\sum^{39}_{k=0} (P_{k})=\frac{39!}{52!} \sum^{39}_{k=0}(\frac{(52-k)!}{(39-k)!}=\frac{53}{14} = \frac{52+1}{13+1}=3.78\)

Hence, after 3.78≈3 cards, Percy will stop turning the cards.

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Line passes through point (3, 7) and has a slope of. The equation of the line is. If point A(x, 5) lies on the line, the value of x is

Answers

Therefore, the value of x is x = -2 / m + 3.

Supporting Answer: We have to find the equation of the line that passes through the point (3, 7) and has a slope of m. We use the point-slope form of the equation of the line, which is :y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope of the line. Thus, the equation of the line is: y - 7 = m(x - 3). Now, we are given that point A(x, 5) lies on the line. Hence, we substitute y = 5 and solve for x:x - 3 = (5 - 7) / mx - 3 = -2 / mmx = -2 / m + 3.

Equations act as a scale of balance. If you've ever seen a balancing scale, you know that it needs to have an equal amount of weight on both sides in order to be deemed "balanced". The scale will tip to one side if we just add weight to one side, and the two sides will no longer be equally weighted. Equations use the same reasoning. Anything on one side of the equal sign must have the exact same value on the opposite side in order for it to not be considered unequal.

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In circle I, IJ=4 and mJIK∠=90∘ Find the area of shaded sector. Express your answer as a fraction times π.

Answers

The area of the shaded sector is 4π square units.

To find the area of the shaded sector, we need to calculate the central angle formed by the sector. In this case, we are given that the angle JIK is 90 degrees, which means it forms a quarter of a full circle.

Since a full circle has 360 degrees, the central angle of the shaded sector is 90 degrees.

Next, we need to determine the radius of the circle. The line segment IJ represents the radius of the circle, and it is given as 4 units.

The formula to calculate the area of a sector is A = (θ/360) * π * r², where θ is the central angle and r is the radius of the circle.

Plugging in the values, we have A = (90/360) * π * 4².

Simplifying, A = (1/4) * π * 16.

Further simplifying, A = (1/4) * π * 16.

Canceling out the common factors, A = π * 4.

Hence, the area of the shaded sector is 4π square units.

Therefore, the area of the shaded sector, expressed as a fraction times π, is 4π/1.

In summary, the area of the shaded sector is 4π square units, or 4π/1 when expressed as a fraction times π.

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The process to writing an equation using a table is....

Answers

Answer:

graphing

Step-by-step explanation:

ez

it’s GRAPHING obviously.

In a Healthy Jogging event, a few hundred participants were expected to jog 7 800 000 metres altogether. They had jogged 25 000 metres in the first few minutes. How many thousands must be added to 25 000 to make 7 800 000?

Answers

we have to add 7775000 to make 7800000 from 25000 which is calculated by using Substraction method.

Subtraction in mathematics is the process of subtracting one integer from another. In other terms, the result of subtracting two from five is three. After addition, subtraction is usually the second process you learn in math class.Subtraction is the action or procedure of determining the difference between two quantities or figures. The phrase "taking away one number from another" is also used to describe the process of subtracting one number from another.

Distance to be covered altogether= 7800000 m
THE distance has covered= 25000 m.

We can calculate the thousands needs to be added in 25000 to make it 7800000 by using Substraction method:-

7800000-25000= 7775000m

hence, to make 7800000 from 25000 we have to add 7775000.

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In which quadrant does θ lie if the following statements are true: csc θ> 0 and sec θ> 0

Answers

ANSWER

First quadrant

EXPLANATION

Those two trigonometric functions are the reciprocal of the sine and cosine functions:

\(\begin{gathered} \sec \theta=\frac{1}{\cos \theta} \\ \csc \theta=\frac{1}{\sin \theta} \end{gathered}\)

Therefore:

\(\csc \theta>0\Rightarrow\sin \theta>0\)

sinθ is greater than zero for the first and second quadrants.

Also:

\(\sec \theta>0\Rightarrow\cos \theta>0\)

cosθ is greater than zero for the first and fourth quadrants.

Hence, for cscθ>0 and secθ>0, angle θ lies in the first quadrant.

please help me its due TODAY !

please help me its due TODAY !

Answers

Answer:

1)  x = 32) ∠TAD  = 130°

Step-by-step explanation:

1)

∠AOB + ∠BOC = ∠AOC

(x + 7) + (x + 7) = 7x - 1

7 + 7 + 1 = 7x - x - x

15 = 5x

x = 15/5

x  = 3

2)

5x = 7x - 20

5x - 7x = -20

x = -20 / -2

x = 10

∠TAD = 180 - 5x

∠TAD  = 180 - 5(10)

∠TAD  = 130°

suppose that karen, sue, and peter all work 10 hours a day. in an hour, karen can make one widget or 3 thingamajigs. in an hour, sue can make one widget or one thingamajig. in an hour, peter can make 3 widgets or one thingamajig. if they all split their time evenly between making widgets and thingamajigs, how many thingamajigs can they make?

Answers

The three workers can produce 25 thingamajigs if they split their time evenly between producing widgets and thingamajigs.

Step 1: Calculate the production rate of each workerFirstly, calculate the production rate of each worker for both widgets and thingamajigs. In one hour, Karen can make 1 widget or 3 thingamajigs. In one hour, Sue can make 1 widget or 1 thingamajig. Lastly, Peter can make 3 widgets or 1 thingamajig in one hour.Karen's hourly production rate: 1 widget or 3 thingamajigsSue's hourly production rate: 1 widget or 1 thingamajigPeter's hourly production rate: 3 widgets or 1 thingamajig

Step 2: Calculate the total hourly production of the groupSecondly, calculate the hourly production of the entire group. To split their time evenly, they will have to spend 5 hours each producing widgets and thingamajigs.In 5 hours, Karen can produce 5 widgets or 15 thingamajigs (since her hourly production rate is 1 widget or 3 thingamajigs).In 5 hours, Sue can produce 5 widgets or 5 thingamajigs (since her hourly production rate is 1 widget or 1 thingamajig).In 5 hours, Peter can produce 15 widgets or 5 thingamajigs (since his hourly production rate is 3 widgets or 1 thingamajig).Step 3:

Calculate the total number of thingamajigsLastly, add up the total thingamajigs produced by each worker in 5 hours and you'll have the answer:15 (Karen's production) + 5 (Sue's production) + 5 (Peter's production) = 25 thingamajigsIn total, the three workers can produce 25 thingamajigs if they split their time evenly between producing widgets and thingamajigs.

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if m<DEC= (12x-3)°, m<BCE= (7x-26)°, and m<DAE= 72°, find each angle measure.​

if m&lt;DEC= (12x-3), m&lt;BCE= (7x-26), and m&lt;DAE= 72, find each angle measure.

Answers

The angle of each measure is:

m<DEC= 129°

m∠BCE = 51°

m∠ADE = 57°

m∠EDB = 123°

m∠DBC = 57°

What is meant by angle of measure in triangle?

Angle of measure is the measure of an angle formed by two rays with a common endpoint. Angle of measure is important to many mathematical and scientific fields, including geometry, trigonometry, and physics.

In geometry, angles are used to define shapes and measure the size of an object. For example, angles are used to determine the angles of a triangle, or the angles between the sides of a rectangle. Angle of measure is also important in trigonometry, as it is used to calculate the lengths of sides and angles in a triangle, as well as the area of a triangle.

Angle of measure is also used in engineering, navigation, and surveying. When designing a building or structure, angles are used to determine the strength and stability of the structure, as well as the angles of the beams and walls. In navigation, angles are used to calculate the direction of a ship or aircraft. Finally, in surveying, angles are used to measure the angles between points on a map or a landscape.

Given,

m∠DEC= (12x-3)°, m∠BCE= (7x-26)°, and m∠DAE= 72°

∠DEC+∠BCE = 180°

12x-3+7x-26 = 180°

19x - 29 = 180°

19x = 180+29

x = 209/19

x = 11

Substitute x=11 in m∠DEC= (12x-3)°, we get

m∠DEC= 129°

Substitute x=11 in m∠BCE= (7x-26)°, we get

m∠BCE = 51°

To find m∠ADE,

m∠ADE + m∠DAE + m∠DEA=180°

m∠ADE + 72° + 51° = 180°

m∠ADE = 57°

To find m∠EDB,

m∠EDB + m∠ADE=180°

m∠EDB = 180° - 57°

m∠EDB = 123°

To find m∠DBC,

m∠DBC = m∠ADE are corresponding angles, so

m∠DBC = m∠ADE = 57°

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Last week, Pauline worked 35 hours and made $280. The boss at Pauline’s company makes $600 a week. How many hours would Pauline need to work to make $600?

Answers

Pauline needs to work for 75 hours to make $600

Given that Pauline worked 35 hours and made $280, this can be written as:

35 hours = $280

If Pauline’s company makes $600 a week, this can be expressed as:

x = $600

35/x = 280/600

35/x = 28/60

28x = 35 * 60

28x = 2100

x = 2100/28

x = 75

This means that Pauline needs to work for 75 hours to make $600

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Answer:

Step-by-step explanation:

b^2 - a^2 = 28
Find b

Answers

Answer:

b=(28+a²)^½

Step-by-step explanation:

but i couldnt find the numerical value of b since the value of a wasn't given

In the figure below, I = 10 cm, w = 4 cm, and h = 3 cm. What is the length of r?

In the figure below, I = 10 cm, w = 4 cm, and h = 3 cm. What is the length of r?

Answers

Answer:

I think it would be 11.2

Step-by-step explanation:

because if I is 10 and it only goes across to the other side then it would only be 11.2

The lengths of the sides of a triangle are given. Classify each triangle as acute, right, or obtuse.
7.) 4, 5, 6
8.) 11, 12, 15
9.) 30, 40, 50

Answers

The given triangles are obtuse = 36 m, right angled = 225 m and right angled = 2500 m.

What is Triangle?

Triangle can be defined in which it consists of three sides, three angles and sum of three angles is always 180 degrees.

7.) This triangle is obtuse.

To see this, we can use the Pythagorean theorem:

4*4 + 5*5 = 16 + 25 = 41

6*6 = 36 m

Since 41 > 36, we know that the triangle is obtuse.

8.) This triangle is right.

To see this, we can again use the Pythagorean theorem:

11*11 + 12*12 = 121 + 144 = 265

15*15 = 225 m

Since 265 = 225 + 40, we know that the triangle is right.

9.) This triangle is also right.

We can use the same method as before:

30*30 + 40*40 = 900 + 1600 = 2500

50*50 = 2500 m

Since 2500 = 2500, we know that the triangle is right.

Therefore, The given triangles are obtuse , right angled and right angled.

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A survey was given to a random sample of 400 residents of a town to determine whether they support a new plan to raise taxes in order to increase education spending. Of those surveyed, 168 respondents said they were in favor of the plan. Determine a 95% confidence interval for the proportion of people who favor the tax plan, rounding values to the nearest thousandth.

Answers

The sample proportion of individuals who favor the tax plan is 168/400 = 0.42.

The standard error of the sample proportion is sqrt[(0.42)(0.58)/400] = 0.032.

Using a 95% confidence level, the critical value is 1.96.

The margin of error is 1.96 * 0.032 = 0.063.

The 95% confidence interval is 0.42 ± 0.063, which is (0.357, 0.483).

Therefore, we can be 95% confident that the true proportion of people who favor the tax plan is between 0.357 and 0.483.

if x+y=5 and xy=3
\( \sqrt{x } + \sqrt{y = } \)

Answers

Notice that if both \(x,y\) are positive, then

\(xy = 3 \implies \sqrt{xy} = \sqrt x \sqrt y = \sqrt3\)

We also have the binomial expansion

\(x + 2\sqrt{x}\sqrt{y} + y = \left(\sqrt x\right)^2 + 2 \sqrt x \sqrt y + \left(\sqrt y\right)^2 = \left(\sqrt x + \sqrt y\right)^2\)

Then

\(\left(\sqrt x + \sqrt y\right)^2 = (x + y) + 2\sqrt{xy} = 5 + 2\sqrt3 \\\\ \implies \sqrt x + \sqrt y = \boxed{\sqrt{5 + 2\sqrt3}}\)

Let's see if we can denest the radical. Suppose we could write

\(\sqrt{5 + 2\sqrt3} = a + b \sqrt c\)

for some non-zero integer constants \(a,b,c\) (and \(c>0\)). Squaring both sides gives

\(5 + 2\sqrt3 = a^2 + 2ab\sqrt c + b^2c\)

Let \(c=3\) and \(ab=1\). Then \(a^2 + b^2c = 5\), which gives

\(a^2 + 3b^2 = 5\)

\(a^2 + \dfrac3{a^2} = 5\)

\(a^4 - 5a^2 + 3 = 0\)

We can solve this with the quadratic formula. However, it'll lead to non-integer solutions for \(a,b\), so we cannot denest after all.

The isosceles triangle ABC has an area of 48 square units if AB=12 what is the perimeter of Abc in units?

Answers

Answer:

the answer would be 4 because you multiply

What is 4/9x - 3 > 7/3
SHOW WORK PLEASE!!
btw i'm gonna be asking a lot of questions for this halloween thing we have to do in math.

Answers

Answer:

\(x >12\)

\((12, \infty)\)

\(\{x\in\mathbb{R} : x>12 \}\)

Step-by-step explanation:

\(\dfrac{4}{9} x - 3 > \dfrac{7}{3}\)

\(\dfrac{4}{9} x > \dfrac{7}{3}+3\)

Multiply both sides by 9

\(4 x > 21+27\)

\(4 x > 48\)

Divide both sides by 4

\(x >12\)

We are given that angle ABC and are congruent, and that angle GHI and angle DEF are congruent. By the , the measure of angle ABC is equal to the measure of angle DEF, and the measure of angle GHI is equal to the measure of angle DEF. By the substitution property, the measure of angle ABC is equal to .

Answers

Answer:

By the Substitution property, the measure of angle ABC is equal to GHI.

Step-by-step explanation:

According to the Question,

Since we have,

Angle ABC and angle DEF are congruent ⇒ ∠ABC = ∠DEF-------(1 )  Similarly,angle GHI and angle DEF are congruent ⇒ ∠GHI = ∠DEF------(2)

On substituting the value of from equation (1) to equation (2)

We get, ∠ABC = ∠GHI ∴ ∠ABC ≅ ∠GHI

Thus, By the Substitution property  

The measure of angle ABC is equal to angle GHI.

a cylindrical tank of radius 2.5m and height 1.6m initially contains water of depth of 20cm .water is pumped into the tank at the rate of 1.35litres per second.giving your answer in the nearest minute calculate the time in hours and minute it takes to fill the tank​

Answers

20cm=0.2m
1.6m-0.2m=1.4m
radius=2.5, area of circle=19.635m^2
19.635m^2x1.4m=27.489m^3
1litre=0.001m^3
1.35litres=0.00135m^3
27.489^3/0.00135m^3=20362s
60s=1min
20362s/60s=339.37min
=5 hours and 39 minutes
(intermediate steps are left in 5s.f.)
hope this helps

in the frog markov chain what is the

Answers

(a) If the current distribution is Ps all other Pa 0.2, then in the next period, all states will have the same probability of 0.2, because the frog has a 0.2 probability of moving to any state.

(b) If the current distribution is Pz 0.5, Ps 0.5 all other Pa 0.2, then in the next period, the probabilities of being in state z and state s will each be 0.5 * 0.5 = 0.25, and the probabilities of being in all other states will be 0.2.

(c) If the current distribution is Pz 0.225, Pa 0.25, Pa 0.5, all other P; 0.2, then in the next period, the probabilities of being in each state will be the sum of the products of the current probability of being in that state and the transition probabilities from that state.

(d) If the current distribution is P: Pz 0.22, Pa 0.22, Pa 0.22, Ps 0.22. P6 0.2, then in the next period, the probabilities of being in each state will be the same as in the current period, because the frog has an equal probability of moving to any state.

Note that in each case, the probabilities must add up to 1, as they represent the entire possible states of the frog.

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Solve each equation. 4t = 48

Answers

The answer is t=12 divide 4t and 48 by 4

Yesterday, Sam had 149 baseball cards. Today, he gave m away. Using m, write an expression for the number of cards Sam has left.

Answers

Answer: 149 - m

He gave some away so we subtract

the qualified applicant pool for five management trainee positions consists of nine women and six men. (a) how many different groups of applicants can be selected for the positions? 3003 correct: your answer is correct. (b) how many different groups of trainees would consist entirely of women? 126 correct: your answer is correct. (c) probability extension: if the applicants are equally qualified and the trainee positions are selected by drawing the names at random so that all groups of five are equally likely, what is the probability that the trainee class will consist entirely of women? (round your answer to four decimal places.)

Answers

The favorable outcome is the number of all-women groups (126) and the total possible outcomes are all possible groups (3003). Therefore, P(all-women) = 126/3003 ≈ 0.0419 (rounded to four decimal places).

(a) To determine the number of different groups of applicants that can be selected for the positions, we use the combination formula: C(n, k) = n! / (k!(n-k)!) where n is the total number of applicants (9 women + 6 men = 15) and k is the number of positions (5). So, C(15, 5) = 15! / (5!(15-5)!) = 3003.

(b) To find the number of different groups of trainees consisting entirely of women, we use the same formula but with only the 9 women as applicants: C(9, 5) = 9! / (5!(9-5)!) = 126.

(c) To calculate the probability that the trainee class will consist entirely of women, we can use the formula P(event) = Number of favorable outcomes / Total possible outcomes. In this case, the favorable outcome is the number of all-women groups (126) and the total possible outcomes are all possible groups (3003). Therefore, P(all-women) = 126/3003 ≈ 0.0419 (rounded to four decimal places).

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SOMEONE PLZZZ HELP ME WITH THIS QUESTION!! I'd be immensely grateful :/

SOMEONE PLZZZ HELP ME WITH THIS QUESTION!! I'd be immensely grateful :/

Answers

Answer:

Step-by-step explanation:

First let's find the value of x :

We khow that the area of this triangle is 400 and it is given by the product of the base and the height over 2

the base is x the height is 2x Let A be the area : A= (2x*x)/2 =2x²/2  =x² so x²= 400 ⇒ x= 20≥ 0 because it's a distance

Let's find the hypotenuse :

The pythagorian theorem :

h²= x²+(2x)² h²= x²+ 4x²h²= 5x² x=20⇒ h²= 5*(20)²h²= 2000h= 20\(\sqrt{5}\) ≥0 because it is a distance

A) Given the area of a triangle is

B•h/2

B= x and H= 2x

Therefore 2x • x /2 = 400

2x^2 = 800

x^2 = 400

x = - or + 20

However since it’s the area it cannot be negative therefore the x value is 20

So the height is 40 (2x) while the base is 20 (x)

B) Given that the base is 20 and the height is 40, you can use Pythagoras Theorem where:

a^2 + b^2 = c^2

So 20^2 + 40^2 = 400 + 1600 = 2000

C^2 = 2000

C = square root 2000 ( insert in calculator and round up)

That gives you the hypotenuse.

1. Let p represent the true probability of a particular species of plant having a specific fungal infection. Five plants are tested, and four are found to have the fungus. (So the "observed data" is four infected plants.)
In a repetition of the experiment, we would interpret a result (i.e., the number of infected plants) to be at least as extreme as the observed data if four or five plants have the fungus. (We already know that the fungus is relatively uncommon, and so a "more extreme result" entails more infected plants than the observed data.)
(i) Use the binomial distribution to determine the probability of a result at least as extreme as the observed data, as a function of p.
(ii) While it can be difficult, in practice, to determine the exact confidence interval, we can calculate whether or not a selected choice of p lies within the confidence interval. For example, when p = 0.4, the probability of four or more infected plants is 0.087. Note that 0.087 > 0.025 (i.e., 2.5%). We can conclude that this choice of p must lie within the 95% confidence interval, because if p were larger than ph, then probability of four ore more infected pants would have to be larger than 0.025. Follow this approach to determine whether or not p = 0.3 or p = 0.2 lie within the 95% confidence interval.
(iii) Assume alternatively that we observed five (out of five) infected plants. Determine whether or not p = 0.3 lies within the 95% confidence interval, following the approach used above. In this case, note that a result as or more extreme than the observed data would be five out of five infected plants.
2. Now suppose we consider a different fungus, for which infected plants are relatively common. We test five plants, and we find that one of them has the fungus. In this setup, a result at least as extreme as the observed data would be zero or one infected plants.
(i) Determine if p = 0.6 or p = 0.7 lie within the 95% confidence interval.
(ii) Assume alternatively that we observed no infected plants among the five. Determine whether or not p = 0.7 lies within the 95% confidence interval.

Answers

(i) The number of infected plants among 5 plants follows a binomial distribution with parameters n = 5 and p.

We observed 4 infected plants. To determine the probability of a result at least as extreme as the observed data, we need to calculate the probabilities of 4 and 5 infected plants for a range of values of p and add them up.

The probability of 4 infected plants is:

P(X = 4) = 5C4 * p^4 * (1-p)^1 = 5p^4 * (1-p)

The probability of 5 infected plants is:

P(X = 5) = 5C5 * p^5 * (1-p)^0 = p^5

Therefore, the probability of a result at least as extreme as the observed data is:

P(X >= 4) = P(X = 4) + P(X = 5) = 5p^4 * (1-p) + p^5

(ii) To determine if p = 0.3 or p = 0.2 lie within the 95% confidence interval, we need to find the range of values of p such that the probability of a result at least as extreme as the observed data is less than or equal to 0.025. We can solve this numerically using the expression derived in part (i):

For p = 0.3:

P(X >= 4) = 5(0.3)^4 * (1-0.3) + (0.3)^5 = 0.0765

Since 0.0765 > 0.025, we cannot conclude that p = 0.3 lies within the 95% confidence interval.

For p = 0.2:

P(X >= 4) = 5(0.2)^4 * (1-0.2) + (0.2)^5 = 0.01024

Since 0.01024 < 0.025, we can conclude that p = 0.2 lies within the 95% confidence interval.

(iii) If we observed five infected plants out of five, then the probability of a result at least as extreme as the observed data is simply P(X = 5) = p^5. To determine if p = 0.3 lies within the 95% confidence interval, we need to find the range of values of p such that the probability of observing five infected plants is less than or equal to 0.025:

p^5 <= 0.025

p <= (0.025)^(1/5)

p <= 0.551

Since 0.3 < 0.551, we can conclude that p = 0.3 does not lie within the 95% confidence interval.

(i) The number of infected plants among 5 plants follows a binomial distribution with parameters n = 5 and p. We observed one infected plant. To determine if p = 0.6 or p = 0.7 lie within the 95% confidence interval, we need to find the range of values of p such that the probability of a result at least as extreme as the observed data (i.e., zero or one infected plants) is less than or equal to 0.025:

For p = 0.6:

P(X <= 1) = P(X = 0) + P(X = 1) = (0.4)^5 + 5(0.6)(0.4)^4 = 0.07808

Since 0.07808 > 0.025, we cannot conclude that p = 0.6

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1.A diameter of a sphere is measured to be 5.36 in. Find the radius of the spheres centimetres

2. The speed of light is about 3.00×10⁸m/s. Convert this figure to miles per hour

3. A certain car has a fuel efficiency of 25.0 miles per gallon. Express this efficiency in kilometers per liter​

Answers

Answer:

Question 1:

\({ \tt{1 \: in = 2.54 \: cm}} \\ { \tt{5.36 \: in = (5.36 \times 2.54) \: cm}} \\ { \tt{ diameter= 13.6144 \: cm}} \\ \\ { \tt{radius = ( \frac{1}{2} \times 13.6144)}} \\ \\ { \tt{radius = 6.8072 \: cm}}\)

Question 2:

\({ \tt{ \frac{3.00 \times {10}^{8} \: m}{1 \: s} = \frac{( \frac{1}{1609}) \times 3.00 \times {10}^{8} \: mi }{( \frac{1}{3600} ) \: h} }} \\ \\ = { \tt{(1.86 \times {10}^{5}) \times 3600 }} \\ \\ = { \tt{ 6.71 \times {10}^{8} \: mi {h}^{ - 1} }}\)

Question 3;

\({ \tt{ \frac{25.0 \: mi}{1 \: } = \frac{1.609 \times 25.0 \: km}{3.785 \: l} }} \\ \\ { \tt{ = 10.627 \: km {l}^{ - 1} }}\)

1.A diameter of a sphere is measured to be 5.36 in. Find the radius of the spheres centimetres 2. The

Ari is setting up a fish tank for his goldfish. The tank holds 15 gallons of water. If each gallon of water weighs 8.3 pounds, how much will the water in Ari's fish tank weigh?

Pls answer​

Answers

Answer:

124.5

Step-by-step explanation:

All you need to do is multiply.

15*8.3=124.5

This is because The total water in Ari's fish tank has 15 gallons, and each gallon has 8.3, so you multiply.

Home Depot is delivering washing machines to buyers. The washing machines are rectangular prisms that measure 5 ft x 5 ft x 6 ft. These machines are then packed into a delivery truck with dimensions of 30 ft x 15 ft x 12½ ft.

What is the volume of a washing machine Please show work

Answers

Step-by-step explanation:

Volume of Washing machine = Volume of Rectangle

= Length x Width x Height

= 5 x 6 x 6

\( = 180ft^{3} \)

I need help and pls explain ASAP!!!

I need help and pls explain ASAP!!!

Answers

Answer:

10 hours at $140

Step-by-step explanation:

Well, uhh...

"same amount of money" means the same value on the y axis

looking at the graph one can see they intercept at point (10,140)

so if they both work 10 hours, their total individual money will be $140

Answer:

10 hour because you will need to find the time the line intercect(meaning cross each other) and it was at 10 hour for 140 dollar

Step-by-step explanation:

four runners were randomly sampled and it was determined that, in their running, they ran 23, 19, 23, and 23 miles per week, respectively. if we wish to test the claim that the population mean running time is less than 21 miles per week, what conclusion should be reached at the 1% level of significance? based upon the appropriate null and alternative hypotheses we:

Answers

Reject the claim by accepting H0.

What is null hypothesis and alternate hypothesis?

The null hypothesis and the alternative hypothesis are types of conjectures used in statistical tests, which are formal methods of reaching conclusions or making decisions on the basis of data.

Explanation for the answer:

Mean of observations, x bar \(=\frac{(23+19+23+23)}{4}=22\)

Then for each number: subtract the Mean and square the result:

\(1+9+1+1=12\)

Sample Variance:

       \(\frac{12}{3} = 4\)

Sample Standard Deviation:

\(\sqrt{4} = 2\)\((\sqrt{4})^{0.5} = 1.1412\)

Standard error,

  \(se = (\frac{s}{n} )^{0.5}\)

\(se = (\frac{1.1412}{4} )^{0.5}\)

\(se = 0.5341\)

Hypothesis,

\(H_0: Xbar \geq 21, against\)

\(H_1: Xbar < 21\\\)  (Lower tailed test)        

t-statistic:  

\(t-statistic=\frac{xbar-Xbar}{se}=\frac{22-21}{0.5341}=1.8723\)

p value for 3 (=n-1) degrees of freedom = 0.039805 or 3.9805%

As p-value < 1% (level of significance), so, we reject the null hypothesis. Hence, the mean running time of runners is not significantly atleast 21 miles.    

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