what is the energy of a photon that emits a light frequency of 6.42X10(14)HZ? got it... 4.25 X10 (-19)J

The molality of the sodium ions and the sulfate ions are  44.5 and 10.66 respectively.

How do you calculate molality?

The total number of moles of solute per litre of solution is defined as the molarity of a specific solution. Because, unlike mass, the volume of a system changes with changes in physical circumstances of the system, the molality of a solution is reliant on changes in physical qualities of the system such as pressure and temperature. M, which stands for molarity, represents molarity. The molarity of a solution is one molar when one gramme of solute is dissolved in one litre of solution. As we know, the solvent and solute combine to create a solution, hence the total volume of the solution is measured.

molality of sodium was

=480.57/10.781

=44.5

molality of sulfate was

=28.93/2.712

=10.66

To learn more about molality follow the given link: https://brainly.com/question/23355302

#SPJ1

Answer:

A- Perform an experiment

Explanation:

The pH of acid is between 0-7 on pH scale while for base pH range is from 7-14. Thus the pOH of 0.04 M HCl is  12.6. pH is a unitless quantity. The correct option is option C.

pH is a measurement of amount of hydronium ion H₃O⁺ in a given sample. More the value of hydronium ion concentration, more will be the solution acidic.

On subtracting pH from 14, we get pOH which measures the concentration of hydroxide ion in a given solution. pH depend on the temperature. At room temperature pH scale is between 0 to 14. pH of neutral solution is 7.

The concentration of HCl is 0.04 M

Concentration of H₃O⁺=0.04 M

Mathematically,

pH=-log[H⁺]

Substituting the values

pH=-log[0.04 M]

     = 1.4

pOH = 14-pH = 12.6

Thus  the pOH of 0.04 M HCl is  12.6. The correct option is option C.

To learn more about pH, here:

https://brainly.com/question/27945512

#SPJ2

The percent by mass of nitrogen in ammonia (NH3) is approximately 82.15%

Calculating the mass of nitrogen to the total mass of the compound and then expressing the result as a percentage will allow us to determine the percent by mass of nitrogen in NH3 (ammonia).

Ammonia's molecular structure, NH3, indicates that it is made up of one nitrogen atom (N) and three hydrogen atoms (H). We must take both the molar masses of nitrogen and ammonia into account when calculating the percent by mass of nitrogen.

Nitrogen's (N) molar mass is roughly 14.01 g/mol. The molar masses of nitrogen and hydrogen are added to determine the molar mass of ammonia (NH3). Since hydrogen's molar mass is around 1.01 g/mol, ammonia's molar mass is:

(3 mol H 1.01 g/mol) + (1 mol N 14.01 g/mol) = 17.03 g/mol = NH3.

Now, we can use the following formula to get the nitrogen content of ammonia in percent by mass:

(Mass of nitrogen / Mass of ammonia) / 100% is the percentage of nitrogen by mass.

Ammonia weighs 17.03 g/mol and contains 14.01 g/mol of nitrogen by mass. By entering these values, we obtain:

(14.01 g/mol / 17.03 g/mol) 100% 82.15 % of nitrogen by mass

Ammonia (NH3) has a nitrogen content that is roughly 82.15 percent by mass.

For more questions on mass
https://brainly.com/question/24191825
#SPJ8

Answer:

14 elements

I hope this is correct answer please follow me

Answer:

The answer will be A. 7 elements

Explanation:

I took a test and I got it right hope this helps<3 ^^

A⁣⁣⁣⁣⁣nswer i⁣⁣⁣⁣s i⁣⁣⁣⁣n a p⁣⁣⁣⁣hoto. I c⁣⁣⁣⁣an o⁣⁣⁣⁣nly u⁣⁣⁣⁣pload i⁣⁣⁣⁣t t⁣⁣⁣⁣o a f⁣⁣⁣⁣ile h⁣⁣⁣⁣osting s⁣⁣⁣⁣ervice. l⁣⁣⁣⁣ink b⁣⁣⁣⁣elow!

bit.\(^{}\)ly/3a8Nt8n

The volume of the base that we are going to require in the process would be 28.5 mL

A neutralization reaction is a chemical reaction that occurs when an acid reacts with a base to form a salt and water. It is called a neutralization reaction because the resulting solution is neutral, with a pH of around 7.

We have that;

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

VB = CAVANB/CBNA

VB = 0.132 * 12 * 2/0.111 * 1

VB = 28.5 mL

We are going to use the base that would have a volume of 28.5 mL

Learn more about neutralization:https://brainly.com/question/14156911

#SPJ1

300.0 ml of 0.10 m CaCl₂ of the following solutions contains the greatest number of ions, assuming all these salts dissociate completely.

An is an atom or collection of atoms where the number of electrons and the number of protons are different. A positive ion, also known as a cation, is a particle that exists when the flow of atoms exceeds the number of protons. Ions are electrically charged particles that are created either by taking electrons out of neutral atoms to make positive ions or adding protons to neutral atoms to produce negative ions. The quantity of protons remains constant during the formation of an ion.

The number of moles in 300. mL of 0.10 M CaCl₂ is:

0.300 L * 0.10 Mol L = 0.030 mol

Each mole of CaCl₂ contains 3 moles of ions (1 Ca²⁺ and 2 Cl⁻). The moles of ions in 0.030 moles of CaCl₂ are:

0.30molNaCl * 3mol Ions / 1 mol NaCl = 0.90 mols

To know more about Ions visit:

https://brainly.com/question/14982375

#SPJ4

Answer: 6.02 × 10^24

Explanation:

Lewis structures, also known as Lewis dot diagrams, are a way to represent the valence electrons of atoms in a molecule. They show all the atoms in the molecule, but do not include lines for the bonds between C's and H's.

Structural formulas, on the other hand, show the arrangement of atoms in a molecule and the bonds between them. They do include lines for the bonds between C's and H's.

Molecular formulas simply give the number of each type of atom in a molecule, without showing their arrangement or bonds. For example, the molecular formula for water is H2O.

Condensed structural formulas are a shorthand way of representing structural formulas. They show the arrangement of atoms and the bonds between them, but do not include all the atoms or bonds. For example, the condensed structural formula for propane is CH3CH2CH3.

In summary, Lewis structures show all the atoms in a molecule but do not include lines for the bonds between C's and H's, structural formulas show the arrangement of atoms and the bonds between them, molecular formulas give the number of each type of atom in a molecule, and condensed structural formulas are a shorthand way of representing structural formulas.

Know more about formulas

https://brainly.com/question/22688504

#SPJ11

To calculate the molarity of the sodium hydroxide (NaOH) solution, we need to perform a titration with a standardized solution of hydrochloric acid (HCl). Here is the numerical setup for calculating the molarity of the NaOH solution:

Measure the volume of the HCl solution used in the titration. Let's say you used 25.0 mL of 0.100 M HCl.

Calculate the number of moles of HCl used in the titration: moles of HCl = M x V = 0.100 mol/L x 0.0250 L = 0.00250 mol.

Use the balanced chemical equation for the reaction between HCl and NaOH to determine the number of moles of NaOH that reacted with the HCl. The balanced chemical equation is:

HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)

Since the stoichiometry of the reaction is 1:1 between HCl and NaOH, the number of moles of NaOH that reacted is also 0.00250 mol.

4. Determine the volume of NaOH used in the titration. Let's say you used 30.0 mL of NaOH solution.

Calculate the molarity of the NaOH solution: Molarity of NaOH = moles of NaOH / volume of NaOH solution (in L) = 0.00250 mol / 0.0300 L = 0.0833 mol/L.

To determine the total volume of HCl(aq) and NaOH(aq) used in the titration, simply add together the volumes of HCl and NaOH that were used. In this example, the total volume would be 25.0 mL + 30.0 mL = 55.0 mL.

Learn more about titration, here;

https://brainly.com/question/31271061

#SPJ1

1. The % concentration is 20.7% and the molar concentration, Cm, is 1.5 M.

2. 7.8 grams of potassium sulfate will be formed.

3. 10.7 grams of ammonium chloride will be formed.

4. The volume of hydrogen gas that will be produced is 3.86 liters.

5. 21.43 grams of the 70% acetic acid is needed to prepare 500 grams of 3% acetic acid solution.

1. Mass of potassium sulfate = 1.5 moles * (174.26 g/mol) = 261.39 g

Mass of water (H₂O) = 1000 g

% = (mass of solute/mass of solution) x 100

% = (261.39 g / (261.39 g + 1000 g)) x 100

% ≈ 20.7%

Cm = moles of solute / volume of solution

Moles of potassium sulfate (K2SO4) = 1.5 moles

Volume of water (H2O) = 1000 g / (density of water) = 1000 g / 1 g/mL = 1000 mL = 1 L

Cm = 1.5 moles / 1 L

Cm = 1.5 M

2. The balanced equation for the reaction is:

H₂SO₄ + 2 KOH → K₂SO₄ + 2 H₂O

Molar mass of sulfuric acid (H₂SO₄) = 98.09 g/mol

Moles of sulfuric acid = 10 g / 98.09 g/mol

Moles of sulfuric acid = 0.102 mol

Based on the mole ratio of the reaction, 0.102 moles of sulfuric acid will react to form 0.102 moles of potassium sulfate.

Molar mass of potassium sulfate = 174.26 g/mol

Mass of potassium sulfate = 0.102 mol x 174.26 g/mol

Mass of potassium sulfate ≈ 17.8 g

3. The balanced equation for the reaction is:

Molar mass of hydrochloric acid (HCl) = 36.46 g/mol

Moles of hydrochloric acid (HCl) = 7.3 g / 36.46 g/mol

Moles of hydrochloric acid ≈ 0.2 mol

Based on the mole ratio of the reaction, 0.2 moles of hydrochloric acid will react to form 0.2 moles of ammonium chloride.

Molar mass of ammonium chloride (NH₄Cl) = 53.49 g/mol

Mass of ammonium chloride = 0.2 mol x 53.49 g/mol

Mass of ammonium chloride ≈ 10.7 g

4. The balanced equation for the reaction is:

Molar mass of zinc (Zn) = 65.38 g/mol

Moles of zinc = 13 g / 65.38 g/mol

Moles of zinc ≈ 0.199 mol

Based on the mole ratio of the reaction, 0.199 moles of zinc will react to produce 0.199 moles of hydrogen gas.

Volume of sulfuric acid = 30 g / (density of H₂SO₄ )

The density of H₂SO₄ is 1.84 g/mL

Volume of sulfuric acid  = 30 g / 1.84 g/mL

Volume of sulfuric acid ≈ 16.3 mL or 0.0163 L

Using the ideal gas law, the volume of hydrogen gas produced will be:

V = nRT / P

V = (0.199 mol)(0.0821 L·atm/(mol·K))(273 K) / (1 atm)

V ≈ 3.86 L

5. Assuming that the concentrated original solution of acetic acid is 100% acetic acid (CH₃COOH).

Mass of acetic acid = 500 g x (3/100) = 15 g

The concentrated original solution, however, is 70% acetic acid.

70% acetic acid (mass) = 100% acetic acid (unknown mass)

0.7 * (unknown mass) = 15 g

Solving for the unknown mass:

unknown mass = 15 g / 0.7

unknown mass ≈ 21.43 g

Learn more about percentage concentration at: https://brainly.com/question/18761928

#SPJ1

The pressure of the chlorine gas at the given condition is 1.7 atm.

The pressure of the chlorine gas at the given condition is calculated by applying ideal gas law.

PV = nRT

where;

The number of moles of 25 g of chlorine is calculated as follows;

n = m/M

n = 25/71

n = 0.352

The pressure of the chlorine gas at the given condition is calculated as;

P = nRT/V

P = (0.352 x 0.0821 x 263) / (4.5)

P = 1.7 atm

Learn more about pressure of gas here: https://brainly.com/question/25736513

#SPJ1

If more energy is absorbed than what is released during bond breaking and forming, the reaction is endothermic.

When bonds in the reactants are broken in endothermic reactions, greater energy is absorbed than emitted when new bonds are created in the products.

The energy required to break existing bonds in endothermic processes is more than the energy released when new bonds are generated. In an exothermic process, more energy is generated when new bonds are created than is consumed when old ones are broken.

If more energy is absorbed than what is released during bond breaking and forming, the reaction is endothermic.

Learn more about endothermic reactions, here:

https://brainly.com/question/28909381

#SPJ1

Based on the methods used to separate the substance into its parts is substance U is a mixture because physical methods were used to separate its parts; option D.

Separation techniques are techniques employed in the separation of mixtures of substances.

Mixtures are substance made up of two or more components physically joined together.

Considering the substance which is being separated, the separation techniques employed are physical separation techniques, hence the substance is a mixture.

In conclusion, physical separation techniques are employed in the separation of mixtures.

Learn more about separation techniques of mixtures at: https://brainly.com/question/4825542

#SPJ1

The percentage composition or mass percentage is an important method to calculate the concentration of a solution. The percent composition of Oxygen in the compound is 36.79 %.

The mass percentage of a particular component in the compound can be defined as the ratio of the mass of that particular component to the total mass of the compound.

% Mass = Mass of the component / Total mass of the compound × 100

Here 'C' and 'O' combines to form CO₂.

Mass of CO₂ = 12.7 + 2 × 17.7 = 48.1 g

% Mass of 'O' = 17.7 /  48.1 × 100 = 36.79 %

Thus the percent composition of oxygen is 36.79 %.

To know more about % Mass, visit;

https://brainly.com/question/8339943

#SPJ1

Answer:

Methyl pentanoate.

Explanation:

Hello there!

In this case, according to the given information, we can see the correct structure will be:

                             O

                              ||

CH3CH2CH2CH2COCH3

Which matches with the structure of an ester due to the -COO- functional group. In such a case, the first part of the name is in function of the right side of the ester, in this case, methyl, followed by the left side, pentanoate, as it has five carbon atoms and is an ester (similar to an inorganic salt, but organic) and therefore, the name will be methyl pentanoate.

Regards!

Answer:

This is True

Explanation:

If you look at the elemetnts and use notes, you can see it is a represetaive element. have a nice day! good luck!

Answer:

1.12 moles

Explanation:

To find the amount of moles, you need to use the Ideal Gas Law:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas constant (0.08206 atm*L/mol*K)

-----> T = temperature (K)

After converting the temperature from Celsius to Kelvin, you can plug the given values into the equation and solve for "n".

P = 1.00 atm                     R = 0.08206 atm*L/mol*K

V = 25.0 L                        T = 0. °C + 273 = 273 K

n = ? moles

PV = nRT

(1.00 atm)(25.0 L) = n(0.08206 atm*L/mol*K)(273 K)

25.0 = n(22.4)

1.12 = n

Answer:

1) temperature,

2) plant, physical, cracks, grow

3) freeze-thaw, physical

4) rain, chemical, acid rain, fossil

Explanation:

I'm not too sure if all of these are correct, but I hope this helps

Answer:

Carbon dioxide and oxygen

Explanation:

Answer:

-3

Explanation:

just took the unit test

The oxidation number of N in the compound, NH₃ is -3

This is a number assigned to an element in a chemical combination which indicates the number of electron(s) lost or gained.

NH₃ = 0

N + 3H = 0

N + (3×1) = 0

N + 3 = 0

Collect like terms

N = 0 - 3

N = -3

Learn more about oxidation number:

https://brainly.com/question/4681909

#SPJ9

Ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)) mixture could be a useful buffer in a solution. Option C

A buffer is a solution that can resist changes in pH when small amounts of acid or base are added. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer system works by the principle of Le Chatelier's principle, where the equilibrium is shifted to counteract the changes caused by the addition of an acid or a base.

In option A, acetic acid (\(CH_3CO_2H\)) is a weak acid, but hydrochloric acid (HCl) is a strong acid. This combination does not form a buffer because HCl is completely dissociated in water and cannot provide a significant concentration of its conjugate base.

Option B consists of sodium hydroxide (NaOH), which is a strong base, and elemental sodium (Na), which is a metal. This combination does not form a buffer as there is no weak acid-base pair involved.

Option D contains acetic acid (\(CH_3CO_2H\)), a weak acid, and ammonia (\(NH_3\)), a weak base. Although they are weak acid and base, they do not form a buffer system together as they are both weak acids or bases and lack the required conjugate acid-base pair.

Option C, ammonia (\(NH_3\)), is a weak base, and ammonium chloride (\(NH_4Cl\)) is its conjugate acid. This combination can form a buffer system. When ammonia reacts with water, it forms ammonium ions (NH4+) and hydroxide ions (OH-).

The ammonium ions act as the weak acid, while the ammonia acts as the weak base. The addition of a small amount of acid will be counteracted by the ammonium ions, and the addition of a small amount of base will be counteracted by the ammonia, thus maintaining the pH of the solution relatively stable.

Therefore, option C, consisting of ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)), is the suitable mixture that could be a useful buffer in a solution.

For more such question on buffer visit:

https://brainly.com/question/13076037

#SPJ8

Answer: D - 126.4g

Explanation:  

% Yield = Actual Yield/Theoretical Yield

38% = Actual Yield/332.5

38/100 = Actual Yield/332.5

(.38)(332.5) = 126.35 g = 126.4 g Actual Yield

Answer:

is D. the correct answer

Explanation:

I'm not sure if it is. Please let me know if I'm mistaking.

Problem 1:

we need 80 g of the 15% solution and 120 g of the 20% solution.

Let x be the mass of the 15% solution needed and y be the mass of the 20% solution needed.

x + y = 200 (total mass of the two solutions)

0.15x + 0.2y = 0.17(200) (total amount of solute in the two solutions)

Solving these equations,  x = 80 g and y = 120 g.

Therefore, we need 80 g of the 15% solution and 120 g of the 20% solution.

Problem 2:

we need 120 g of the 18% solution and 180 g of the 5% solution.

Let x be the mass of the 18% solution needed and y be the mass of the 5% solution needed.

x + y = 300

0.18x + 0.05y = 0.07(300)

Solving these equations, x = 120 g and y = 180 g.

Therefore, we need 120 g of the 18% solution and 180 g of the 5% solution.

Problem 3:

The mass percentage of the final solution is 135 g/550 g × 100% = 24.55%.

The total mass of the final solution is 200 g + 350 g = 550 g.

The total amount of solute in the final solution is:

0.15(200 g) + 0.20(350 g) = 65 g + 70 g = 135 g.

Therefore, the mass percentage of the final solution is 135 g/550 g × 100% = 24.55%.

Problem 4:

The mass percentage of the final solution is 110 g/335 g × 100% = 32.84%.

The total mass of the final solution is 300 g + 35 g = 335 g.

The total amount of solute in the final solution is:

0.15(300 g) + 35 g = 75 g + 35 g = 110 g.

Therefore, the mass percentage of the final solution is 110 g/335 g × 100% = 32.84%.

Problem 5:

The mass percentage of the final solution is 18.18%.

Calculate the final mass of the solution:

Final mass = 400 g + 150 g = 550 g

Calculate the mass of solute in the 25% solution:

Mass of solute = 0.25 x 400 g = 100 g

Calculate the mass percentage of the final solution:

Mass percentage = (mass of solute ÷ final mass) x 100%

Mass percentage = (100 g ÷ 550 g) x 100%

Mass percentage = 18.18%

To know more about mass of solutions, visit:

https://brainly.com/question/29482678

#SPJ1

Answer:

pp

Explanation:

Explanation:

goodluck to your test!

The arrow in a chemical reaction can be translated as the following:

A. yields

C. react to form

The concentration of the HNO₃ solution needed to neutralize the 27.60 mL of 1.00 M NaOH is 2.76 M

The balanced equtaion is given below:

HNO₃ + NaOH —> H₂O + NaNO₃

Now, we shall obtain the concentration of the HNO₃ solution needed for the neutralization reaction. This is shown below:

CaVa / CbVb = nA / nB

(Ca × 10) / (1 × 27.6) = 1

(Ca × 10) / 27.6 = 1

Cross multiply

Ca × 10 = 27.6

Divide both side by 10

Ca = 27.6 / 10

Ca = 2.76 M

Thus, the concentration of the HNO₃ solution needed is 2.76 M

Learn more about titration:

https://brainly.com/question/27817549

#SPJ1

The molarity of the solution is equal to 0.500M.

To calculate the molarity of a solution, one must use the value of the amount of moles and the volume, so that:

                                                 \(M = \frac{mol}{v}\)

So, applying the values ​​given in the question we have:

                                         \(M = \frac{1mol}{2L}\)

                                       \(M = 0.5mol/L\)

So, the molarity of the solution is equal to 0.500M.

Learn more about mole calculation in: brainly.com/question/2845237