What is the electric field at a point


0. 300 m to the right of a


-4. 77*10^-9 C charge?


Include a + or - sign to indicate the


direction of the field.

Answer:

i only wrote this for points

Explanation:

Answer:

A compound has unique properties that are distinct from the properties of its elemental constituents. One familiar chemical compound is water, a liquid that is nonflammable and does not support combustion. It is composed of two elements: hydrogen, an extremely flammable gas, and oxygen, a gas that supports combustion.

Answer:

Please find the answer in the explanation.

Explanation:

The variable/s you can manipulate in the simulation to make all the items get the same proximate values for their acceleration will be the variable final velocity. Since all of them have zero initial velocity, the acceleration will tend to zero if they have a constant velocity.

If the final velocity is also zero or approximately equal to zero, that means the velocity is constant. And whenever there is constant velocity, the acceleration will be equal to zero.

Also, if the final velocity of all the parameters are very closed, they will surely have approximately same acceleration.

The variable which can be manipulated in the simulation will be the final

velocity.

The table shows all of them having the same initial velocity which is zero,

then the final velocity will have to be varied in order to get the same

proximate values for their acceleration.

Acceleration is the rate of change of velocity with time and when the velocity

is constant or equal to zero, the acceleration will be equal to zero.If the final

velocity of all the parameters are very close in value , then they will have

proximate values for acceleration.

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When information is encoded in atoms/molecules, the reproduction costs is nothing than it would be if the information were encoded in bits.

Molecules are:

A combination of two or more atoms from the same or different elements. When atoms of the same element are bonded together, it is called a molecular element (eg O2 or Oxygen).

If it's a matter of connecting atoms of different elements, we talk about composite molecules (e.g.

CO2 or carbon dioxide). If the smallest particles of metallic elements are atoms, then the smallest particles of non-metallic elements may be atoms or molecules. For example, the elements of the noble gas group (VIIIA) are composed of atomic particles. The halogen group elements (VIIA) consist of molecules of the element.

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Units that can be used to describe vector quantities are :

For velocity B.) Miles per hour

For displacement C.) Meters

The physical quantities for which magnitude and direction are defined are known as vector quantities. Some examples are displacement, force, torque, momentum, acceleration and velocity.

Meter is the only basic SI unit that is a vector and others are scalars. Derived quantities can be vector or scalar, but vector quantity must have meters in its definition and unit. Although speed is a scalar quantity but velocity is a vector quantity that specifies both a direction and magnitude.

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Answer:

an abbreviation formed from the initial letters of other words and pronounced as a word (e.g. ASCII, NASA ).

Explanation:

....

Answer:

Definition of acronym:a word (such as NATO,radar or laser)formed from the initial letter or letters of each of the successive parts or major parts of a compound term also :an abbreviation (such as FBI formed from initial letters:intialism.

Explanation:

Hope it helps

Answer:

C) ballon does determine the direction

Explanation:

Explanation:

its B, It would push it the opposite

You will hear a phenomenon called beating, with a beat frequency of 2 Hz, resulting in alternating constructive and destructive interference between the two tuning forks.

When you strike two tuning forks with slightly different frequencies (340 Hz and 342 Hz), the sound waves they produce will interfere with each other. This interference creates a pattern of alternating constructive and destructive interference.

Constructive interference occurs when the waves are in phase, making the sound louder, while destructive interference occurs when they are out of phase, making it quieter. The difference in frequencies (342 Hz - 340 Hz = 2 Hz) determines the beat frequency, which is the rate at which the loudness fluctuates. In this case, you will hear beats occurring 2 times per second, resulting in a rhythmic pulsing sound.

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Super-bright stars are not found near the Sun because they are short-lived and have a high mass. Such stars exhaust their fuel quickly and undergo explosive events, resulting in their short lifespan and absence in the vicinity of the Sun.

Super-bright stars, which can be more than 50,000 times more luminous than the Sun, are not found near the Sun due to their nature and lifespan. These extremely luminous stars are typically massive and have a high rate of energy production. However, their high mass leads to rapid consumption of fuel, causing them to burn through their hydrogen reserves relatively quickly. As a result, these stars have shorter lifespans compared to less luminous stars like the Sun. Since the Sun is a relatively long-lived star with a moderate luminosity, it does not fall into the category of super-bright stars. Therefore, super-bright stars are not commonly found in the immediate vicinity of the Sun.

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Sound intensity level (SIL) is measured in decibels (dB).

What is sound?

Sound is a type of energy created by the vibration of particles in a medium, such as air, that can be heard when it reaches a person or animal's ear. Sound can travel through solids, liquids, and gases, and can have different pitches and volumes.

Sound intensity level is defined as the ratio of the sound pressure to a reference pressure level. It is calculated using the following equation: SIL (dB) = 10 log10 (I/I_0), where I is the sound intensity and I_0 is the reference sound intensity equal to 10^−12 W/m^2.

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Water turns from a liquid to a solid/liquid/gas when it evaporates. Ice can also evaporate. Sublimation is the transformation of solid ice into a gas (water vapour).

The right response is sublimation. Without passing through a liquid phase, sublimation is the transformation of a solid into a gaseous phase of matter. Deposition, which occurs when water vapour transforms straight into ice, such as in snowflakes and frost, is the reverse of sublimation.

A specific amount of solid ice will have a smaller volume when it transforms into liquid water because melting ice produces denser water.

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\(h=v_i_yt+\frac{1}{2}gt^2\\ \\h=\frac{1}{2}(9.81m/s^2)(4s)^2\\\)

h = 78.48 m

Answer:

Explanation:

where h is the height of the cliff, g is the acceleration due to gravity, and t is the time it takes for the ball to hit the ground.

where d is the distance traveled, v is the initial horizontal velocity, and t is the time it takes to travel the distance.

Since the ball is projected horizontally, its initial horizontal velocity is constant, and we can assume it is the same as the speed at which it hits the ground. Therefore, we can write:

Substituting in the given values, we get:

Answer:

The alkaline earth metals are the elements that correspond to group 2 of the modern periodic table. This group of elements includes beryllium, magnesium, calcium, strontium, barium, and radium. The elements of this group are quite similar in their physical and chemical properties.

Explanation:

When waves spread out when they pass through a hole or past the edge of a barrier, this is called diffraction.

An interruption that moves momentum and energy from one place in a medium to another is known as a wave. For instance, we can observe the movement of the wave crest from one side to the other in a specific amount of time as an ocean wave moves in medium water.

Most often, wind is what produces waves. The rubbing together of wind and surface water produces wind-driven waves, also known as surface waves. A wave crest is produced when wind continuously disturbs the ocean or lake's surface while it blows across it.

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Answer:

Explanation:

For every action (or force), there is an equal and opposite action (or force).

Answer:

Exothermic because energy is a product

Explanation:

Since energy is a product, heat was released, meaning that the reaction is exothermic.

(6) The angular speed of the blade is 293.2 rad/s.

(7) The linear speed of the tips of the blades in miles per hour is 305.4  mph.

(8) The linear speed of the tips of the blades in feet per second is 8.71 ft/s.

(9) The linear speed in miles per hour in which he is traveling is 10.78 mph.

(6) The angular speed of the blade is calculated as follows;

Diameter of the blade = 9 inches, radius = 4.5 inches

angular distance of the blade = 2800 rev/min

ω = 2800 rev/min  x 2π rad/rev  x  1 min / 60s

ω = 293.2 rad/s

(7) The linear speed of the tips of the blades in miles per hour is calculated as;

v = ωr

the angular speed, ω = 5 rev/s  x 2π rad/rev = 31.42 rad/s

r = 14 ft = 0.0027 mile

the linear speed, v = 31.42 rad/s  x 0.0027  mile = 0.085 mi/s

= 0.085 mi/s x 3600 s / hr = 305.4  mph

(8) The linear speed of the tips of the blades in feet per second is calculated as;

r = 25 inch = 2.08 ft

ω = 40 rev/min  x  2π rad/rev  x 1 min / 60s = 4.19 rad/s

the linear speed = v = 4.19 rad/s x 2.08ft = 8.71 ft/s

(9) The linear speed in miles per hour in which he is traveling is calculated as;

Diameter = 28 inches, radius = 14 inches

14 inches = 0.00022 mile

ω = 130 rev/min  x  2π rad/rev   x   60 min/1 hr = 49,008.85 rad/hr

the linear speed, v = 49,008.85 rad/hr x  0.00022 mile = 10.78 mph

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Answer:

is the process of spreading

Answer: 10cm/12cm

Explanation A fly is sitting at the midpoint of a wooden chord of a circular wheel. The wheel has a radius of  and the chord has a length of   a How far from the hub (center) is the fly

Answer:

Explanation:

As the velocity of light is constant so the acceleration of the light is equal to zero.

a=

dt

dv

​

If light travels in a straight line at a constant speed of 3.0 x 10 8 m/s for 4.1 years to reach the earth from the nearest star 3.9 x 10 13 km away then its acceleration would be zero meters/second².

There are three equations of motion given by  Newton

The first equation is given as follows

v = u + at

the second equation is given as follows

S = ut + 1/2×a×t²

the third equation is given as follows

v² - u² = 2×a×s

As given in the problemLight travels in a straight line at a constant speed of 3.0 x 10 8 m/s for 4.1 years to reach the earth from the nearest star 3.9 x 10 13 km away.

As we know that acceleration is only possible when there is change in velocity, given that light is travelling with constant speed therefore the acceleration of the light must be zero.

Thus, the acceleration of the light would be zero .

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In order to lift a bucket of concrete, you must pull up harder on the bucket than it pulls down on you is referred to as a false statement.

This is referred to as an external agent which is capable of influencing the motion of an object or body. It is also capable of changing the state of rest of a body and the unit in Newton.

When lifting the bucket, the total opposite forces and not only the weight which is what pulls it down must be overcome in other to lift the object or body successfully which is why false was chosen.

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Answer:

5m/s

Explanation:

400m/ 20+60s

= 400/ 80 m/s

5 ms-1

Answer:  The equation relating to mass and weight is Wo = mog

Explanation: Wo = weight of the object in newtons

mo = mass of the object in kilograms

g = acceleration due to gravity (9.81 m/s2 on Earth)

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The instantaneous angular velocity of the disk at the end of the 10.0 s is 20 rad/s.

To solve this problem, we will use the following terms: angular displacement (θ), initial angular velocity (ω₀), angular acceleration (α), time (t), and final angular velocity (ω).
Step 1: Use the formula for angular displacement: θ = ω₀t + 0.5αt². We know that θ = 25 rad, t = 5.0 s, and ω₀ = 0 (starting from rest).
25 = 0(5) + 0.5α(5)²
Step 2: Solve for angular acceleration (α):
25 = 0 + 0.5α(25)
25 = 12.5α
α = 2 rad/s²
Step 3: Use the formula for final angular velocity: ω = ω₀ + αt. We know that

ω₀ = 0, α = 2 rad/s², and t = 10.0 s (since we want to find the angular velocity at the end of 10.0 s).
ω = 0 + 2(10)
Step 4: Solve for instantaneous angular velocity (ω):
ω = 20 rad/s
The instantaneous angular velocity of the disk at the end of the 10.0 s is 20 rad/s.

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The ratio of z to h can be determined by comparing the densities of freshwater and saltwater. The density of a substance is defined as its mass per unit volume.

In this case, the density of freshwater is given as\(1.000 g/cm^3\), while the density of salt water is given as \(1.025 g/cm^3\). To find the ratio of z to h, we need to consider the relationship between density and volume. The density of a substance can be expressed as the ratio of its mass to its volume.

Let's assume z and h represent the volumes of freshwater and saltwater, respectively. Since density is constant for each type of water, we can set up the following equation:

\(1.000 g/cm^3\) (density of freshwater) = \(1.025 g/cm^3\) (density of saltwater)

By canceling out the units, we get:

\(1.000 (g/cm^3) = 1.025 (g/cm^3)\)

Since the densities are equal, we can conclude that the ratio of z to h is 1:1.

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Answer:

8. sketches and models helped the astronauts in their training program as they prepare for their missions

9. before building the Mars lander , students need to sketch their design

The depth of the beam h is approximately 15.4 cm and the width of the beam b is approximately 14.8 cm.

stress on the beam = σ = Mc/I

where M is the bending moment, c is the distance from the neutral axis to the extreme fiber, and I is the moment of inertia of the cross section.

The maximum bending moment occurs at the center of the beam

M = Pl/4

where P is the load and l is the length of the beam

moment of inertia of a rectangular cross section= I = (bh³)/12

b = width of the beam

h = depth of the beam

M = (40 kn)(2 m)/4 = 20 knm

I = (b(0.12 m)³)/12 = (b/10000) m⁴

Substituting these values into the expression for stress

σ = (20 kn m)(c)/((b/10000) m⁴)

The distance c is related to the depth h by:

c = h/2

substituting σ and τm into the expression for maximum shear stress

τm = (3/2)σ

h = √((6M)/(πbσm))

  = √((6(20 kn m))/(πb(12 mpa))) ≈ 0.154 m ≈ 15.4 cm

b = (4Pl)/(σmπh²)

  = (4(40 kn)(2 m))/(12 mpa π(0.154 m)²) ≈ 14.8 cm

The depth of the beam is approximately 15.4 cm and the width of the beam is approximately 14.8 cm.

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The ball is in the air for 0.05 seconds after it leaves the launcher. By analyzing the impulse experienced by the ball, we can determine the final velocity of the ball

To determine the time the ball is in the air after it leaves the launcher, we can use the concept of impulse. Impulse is defined as the product of force and time, and it is equal to the change in momentum of an object.

Impulse (J) = Force (F) * Time (Δt)

We know that the net force acting on the ball is 60 N and the time it is applied is 0.05 seconds. The mass of the ball is 0.3 kg.

The impulse can also be expressed as the change in momentum (Δp) of the ball:

Δp = m * Δv

Where:

m is the mass of the ball,

Δv is the change in velocity.

Since the ball starts from rest, the change in velocity (Δv) is the final velocity (v) of the ball after it leaves the launcher.

By rearranging the equation for impulse, we can solve for the final velocity:

Δv = J / m = F * Δt / m

= 60 N * 0.05 s / 0.3 kg

Simplifying the calculation:

Δv = 10 m/s

Now, to find the time the ball is in the air after it leaves the launcher, we divide the displacement of the ball by the final velocity.

The displacement of the ball is given by:

Δs = v * t

Since the initial velocity is 0 m/s and the final velocity is 10 m/s, the displacement is:

Δs = 10 m/s * t

We want to find the time (t) when the displacement is zero, as the ball reaches the highest point in its trajectory. Therefore, we set Δs = 0 and solve for t:

10 m/s * t = 0

This implies that the ball is in the air for 0.05 seconds after it leaves the launcher.

The ball remains in the air for 0.05 seconds after it leaves the launcher. By analyzing the impulse experienced by the ball, we can determine the final velocity of the ball and use it to find the time it takes for the ball to reach its maximum height. This calculation helps us understand the motion of objects under the influence of external forces and provides insights into projectile motion.

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