What is the driving force behind paper chromatography.

Answer:

A

Explanation:

A, because the chemical causes a varies of heat waves that warms your hand but it also create good light to see in the dark

Answer:

Explanation:

To find the number of calcium atoms in a 30.5-g sample, we need to use the molar mass of calcium and Avogadro's number.

The molar mass of calcium (Ca) is approximately 40.08 g/mol.

First, let's find the number of moles of calcium in the 30.5-g sample:

moles = (mass of the sample) / (molar mass of Ca)

moles = 30.5 g / 40.08 g/mol ≈ 0.7607 moles

Now, we will use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of calcium atoms in the sample:

number of atoms = (number of moles) × (Avogadro's number)

number of atoms = 0.7607 moles × 6.022 x 10^23 atoms/mol ≈ 4.58 x 10^23 atoms

So, the 30.5-g sample of calcium contains approximately 4.58 x 10^23 calcium atoms.

A 2p electron is an electron in the second energy level (n=2) and p orbital. The correct sets of quantum numbers for a 2p electron are (2,1,0,-1/2), (2,1,0,+1/2), and (2,1,+1,-1/2).

The p orbital has l=1, which means there are three possible values for ml (-1, 0, +1). The electron spin quantum number, ms, can have two possible values (+1/2 or -1/2).
Therefore, the possible sets of quantum numbers for a 2p electron are:
(2,1,-1,+1/2) - incorrect because ml cannot be greater than l (1)
(2,0,+1,+1/2) - incorrect because there is no 2p orbital with l=0
(2,1,0,-1/2) - correct
(2,1,0,+1/2) - correct
(2,-1,+1,+1/2) - incorrect because ml must be between -l and +l
(2,1,4,+1/2) - incorrect because ml cannot be greater than l (1)
(2,1,-1,+1/2) - incorrect because this set is the same as the first one
(2,0,+1,-1/2) - incorrect because there is no 2p orbital with l=0
(2,1,+1,-1/2) - correct

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Answer:

I did not understand the question

Yes, the IR spectrum allow you to confirm that the structure of the product is a combination of the two reactants.

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Answer:

hormones or D

Explanation:

:-)

Answer:

D. Hormones

Explanation:

Endocrine glands release hormones into the bloodstream. This lets the hormones travel to cells in other parts of the body.

Answer:

E)All areas of the Earth will have twelve hours of light followed by twelve hours of dark.

Explanation:

Sana maka tulong

Answer:

E

Explanation:

guy above said so

Answer:

Ridges

Explanation:

Ridges separate watersheds

Hope this helped!

The rate order for the hydrolysis of PCA is 2nd order with respect to PCA.

The rate order for the hydrolysis of PCA (p-chloroacetophenone) can be determined by analyzing the given data. The rate of a reaction is determined by the rate law, which is expressed as the rate = k [A]^m [B]^n, where k is the rate constant, [A] and [B] are the concentrations of the reactants, and m and n are the order of the reaction with respect to A and B, respectively. From the given data, it can be observed that the concentration of water is constant while the concentration of PCA varies. By analyzing the data, it can be seen that when the concentration of PCA is doubled, the rate of the reaction quadruples. This indicates that the reaction is second order with respect to PCA, as doubling the concentration of PCA increases the rate by a factor of 2^2 = 4.

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Answer:

Fluorine(F),chroine(CI),bromine(BR),iodine(I)astatine(AT)

Explanation:

friend me when u say thank u

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Actually Welcome to the concept of Ions .

If we see the reaction.

H2SO4 ==> 2H+ + (SO4)2-

Here you can see, H+ ( Hydrogen ions) and (SO4) 2- ( sulphate ions) are the ions when the H2SO4 is dissolved in water.

The mass of the sample of barium is 14.48 grams.

Density is a physical property that measures the amount of mass per unit volume of a substance. It represents how tightly packed the particles are within a given volume.

The formula to calculate density is:

Density = Mass / Volume

In this case, we are given the volume of the barium (4.00 cm³) and the density of barium (3.62 g/cm³). We can rearrange the formula to solve for mass:

Mass = Density x Volume

Substituing the values, we get:

Mass = 3.62 g/cm³ x 4.00 cm³

By Calculating the product, we get:

Mass = 14.48 g

Therefore, the mass of the sample of barium is 14.48 grams.

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Answer:

3.39e+20

Explanation:

Answer:

1kg/L

Explanation:

1.) convert grams to kilograms

1000g÷1000=1kg

2.)use formula to find density

\(density = \frac{mass}{volume} \)

= 1kg/1.0L

=1kg/L

The density of a 1000g substance that fills a 1.0L container is equal to 1 g/ml.

Density is a physical property that expresses the relationship between the volume and mass of the substance. The substance with more mass will be denser when the two substances have equal volumes.

Density is the ratio of the mass to the volume of the object. The mathematical relation of the density is:

Density = Mass/Volume

The density does not depend on the amount of substance therefore density is an intensive property.

Given, the mass of the substance = 1000 g

The volume of the container filled with it = 1 L = 1000 ml

Then the density of the substance = 1000 g/ 1000 ml = 1 g/ml

Therefore, the density of the given substance is equal to 1 g/ml.

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The structure at the end of the arrow while the ph of the urine is 8.5 is called option C: Ammonium biurate crystal

Ammonium biurate crystals, also called uric acid ammonium biurate crystals or thorn-apple crystals, are a specific kind of crystal that can be found in urine. These crystals are made up of a mix of ammonium, uric acid, and biurate.

They look different and have shapes similar to flower arrangements. Ammonium biurate crystals are often found in the urine of people with specific health problems, especially those with liver disease or a condition where blood goes around the liver.

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Hybridization is the mixing of atomic orbitals to form hybrid orbitals that have different shapes and energies than the original atomic orbitals. These hybrid orbitals then participate in bonding with other atoms to form molecules.

a. COCl2 (carbon is the central atom):

- Carbon has four valence electrons and can form four covalent bonds.
- The carbon atom is hybridized to form sp3 hybrid orbitals, which are formed by mixing one 2s orbital and three 2p orbitals.
- The oxygen and chlorine atoms each have one lone pair of electrons and are therefore sp3 hybridized as well.
- The structure of COCl2 is tetrahedral, with the carbon atom at the center and the oxygen and chlorine atoms at the corners.
- The hybrid orbitals of the carbon atom overlap with the p orbitals of the oxygen and chlorine atoms to form four sigma bonds and two pi bonds, as shown in the following diagram:

C: sp3
O: sp3
Cl: sp3

b. BrF5:

- Bromine has seven valence electrons and can form up to seven covalent bonds.
- The bromine atom is hybridized to form sp3d2 hybrid orbitals, which are formed by mixing one 4s orbital, three 4p orbitals, and two 4d orbitals.
- The fluorine atoms each have one lone pair of electrons and are therefore sp3 hybridized.
- The structure of BrF5 is square pyramidal, with the bromine atom at the apex and the fluorine atoms at the corners of the base.
- The hybrid orbitals of the bromine atom overlap with the p orbitals of the fluorine atoms to form five sigma bonds and two pi bonds, as shown in the following diagram:

Br: sp3d2
F: sp3

c. XeF2:

- Xenon has eight valence electrons and can form up to eight covalent bonds.
- The xenon atom is hybridized to form sp3 hybrid orbitals, which are formed by mixing one 5s orbital and three 5p orbitals.
- The fluorine atoms each have three lone pairs of electrons and are therefore unhybridized.
- The structure of XeF2 is linear, with the xenon atom in the center and the fluorine atoms on either side.
- The hybrid orbitals of the xenon atom overlap with the p orbitals of the fluorine atoms to form two sigma bonds and two pi bonds, as shown in the following diagram:

Xe: sp3
F: unhybridized

d. I3:

- Iodine has seven valence electrons and can form up to seven covalent bonds.
- The iodine atoms are each unhybridized and have one lone pair of electrons.
- The structure of I3 is linear, with the two iodine atoms on either end and the third iodine atom in the center.
- The bond between the center iodine atom and the two end iodine atoms is a sigma bond, while the bonds between the end iodine atoms and the center iodine atom are pi bonds, as shown in the following diagram:

I: unhybridized
a. COCl2 (carbon is the central atom)
Hybridization: sp²
Structure: O=C-Cl-Cl (trigonal planar geometry)
Bonds: σ(C-O): O 2p + C sp²
         σ(C-Cl): Cl 3p + C sp² (two times)

b. BrF5
Hybridization: sp³d²
Structure: Br surrounded by 5 F atoms in a square pyramidal geometry
Bonds: σ(Br-F) for all 5 bonds: F 2p + Br sp³d²

c. XeF2
Hybridization: sp³d
Structure: Xe in the center with 2 F atoms in a linear geometry
Bonds: σ(Xe-F) for both bonds: F 2p + Xe sp³d

d. I3¯
Hybridization: sp³d for central I atom
Structure: Linear with central I surrounded by 2 other I atoms
Bonds: σ(I-I) for both bonds: I 5p + central I sp³d
         The I3¯ ion also has 3 lone pairs on each terminal I atom, and 2 lone pairs on the central I atom.

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Answer:

Given

mass of H2O (m) =35.6g

molarmass (mr) = H2O ), 1x2+16=18g/mol

moles of H2O (n) =?

sln

n=m/mr

n=35.6g/18g/mol

n=1.978moles

the moles of H2O are 1.978moles

Answer:

The Temperature will Increase, and the fire will Blow

Explanation:

I hope I could help

The final volume of the hydrogen gas in the 3.0 L container is 1 L.

Let's solve this question according to Charles's Law, which states that the volume of a given mass of gas at constant pressure varies directly with the absolute temperature if the pressure remains constant. A 3.0 L container holds a sample of hydrogen gas at 300 K. The temperature decreases to 100 K, and the pressure remains constant. Therefore, let's assume that the volume of the hydrogen gas initially is V1 = 3.0 L, and the temperature initially is T1 = 300 K. After that, let's assume the final temperature is T2 = 100 K. We have to find the final volume of the gas, which is V2. Charles's Law equation is given as follows: V1/T1 = V2/T2. Now let's substitute the values in the equation.V1/T1 = V2/T2 = (3.0 L)/(300 K) = (V2)/(100 K). Cross-multiplying will give us: 300V2 = 3.0 × 100Thus, V2 = 1 L. Thus, the final volume of the gas is 1 L.

Charles's Law states that the volume of a given mass of gas at constant pressure varies directly with the absolute temperature if the pressure remains constant. We can use this law to find the final volume of the hydrogen gas in a 3.0 L container that is cooled from 300 K to 100 K while the pressure remains constant. We can assume that the initial volume of the hydrogen gas is V1 = 3.0 L, and the initial temperature is T1 = 300 K. We need to find the final volume of the gas, which is V2. According to Charles's Law, V1/T1 = V2/T2We can substitute the values in the equation:(3.0 L)/(300 K) = (V2)/(100 K). Cross-multiplying will give us: 300V2 = 3.0 × 100Thus, V2 = 1 L. Therefore, the final volume of the hydrogen gas in the 3.0 L container is 1 L.

According to Charles's Law, the final volume of a given mass of gas at constant pressure varies directly with the absolute temperature if the pressure remains constant. A 3.0 L container holds a sample of hydrogen gas at 300 K, and the temperature decreases to 100 K, while the pressure remains constant. The final volume of the hydrogen gas in the 3.0 L container is 1 L.

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The reagent sequence that accomplishes the following transformation is first bromine, second NaNH₂, and the third is hydronium ion. bromination of alkene occurs in the first step. Therefore, option D is correct.

The bromination of an alkene is a chemical reaction where a bromine atom (Br) adds to the carbon-carbon double bond of the alkene. It results in the formation of a vicinal dibromide.

The reaction is typically carried out in the presence of a bromine source, such as elemental bromine (Br₂) or a bromine compound like N-bromosuccinimide (NBS).

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Your question is incomplete, most probably the full question is this:

what reagent sequence might accomplish the following transformation?

Answer:

Five.

Explanation:

The third principal energy level has one s orbital, three p orbitals, and five d orbitals, which can each hold up to 10 electrons. This allows for a maximum of 18 electrons.

Answer:

48.075g(or 48g in correct sig figs)***

Explanation:

\(\frac{0.75mol}{1} *\frac{64.1g}{1 mol}\)=48.075g

*64.1g is the mass of SO2 which is calculated by simply taking the mass of sulfur and oxygen(but doubling it since there are two oxygens) and adding them together(32.1+2x16.0)

**btw the mol units cancel because of dimensional analysis in case anyone was wondering why

***if your teacher is like mine and specifically wants your answer in correct sig figs, use the answer in parentheses as the original problem only has 2 sig figs

The bones are approximately 7539 years old.

A radioactive substance follows the model of exponential decay. This is the model that predicts the half-life of substances. It is given by the following exponential equation.

\(A = A_{0}e^{-kt}\)

Where

\(A_{0}\)     is the initial amount present at the start,

t  is the time, and

k  is the constant that governs the rate of decay. Use this model to solve the age of the bones.

Evaluating the question :

When a radioactive substance reaches its half-life, half its original amount will be decayed away due to radiation. Using the exponential decay model,

                                              \(A = A_{0} e^{-kt}\)

substitute \(A = \frac{1}{2} A_{0}\),   and the half-life of the element to determine k completing the full model of the decay.

                                     \(\frac{1}{2}A_{0} = A_{0} e^{- 5750k}\)

The first thing to do, is to divide both sides with \(A_{0}\)

                                       \(\frac{\frac{1}{2}A_{0} }{A_{0} } = \frac{A_{0}e^{-kt} }{A_{0} } \\ \frac{1}{2} = e^{-5750k}\)

Now, take the natural logarithm of both sides of the equation.

                                        \(ln(\frac{1}{2}) = ln e^{-5750k}\)

                                       \(ln(\frac{1}{2}) = -5750k\)

Divide both sides of the equation with  −5750, then evaluate using a logarithm table or a calculator.

                                  \(k = 1.2054734\)× \(10^{-4}\)

Now, that the constant is determined, this means the exponential decay of the radioactive substance is modeled by the following equation.

                                   \(A = A_{0} e^{- 1.2054734 * 10^{-4} }\)

The bones that were found lost 59.7% of the carbon-14 originally present. Using symbols, this can be written as,

                                           \(A = A_{0} - 59.7%\\\\A = A_{0} ( 1 - 0.597)\\\\A = 0.403A_{0}\)

This means that only 40.3 %  of the radioactive substance remained. Substitute this to the mathematical model above, then solve for the time in years.

                               \(0.403A_{0} = A_{0} e^{-1.2054734 *10^{-4} }\)

Now, take the natural logarithm of both sides of the equation.

                                      \(ln0.403 = -1.2054734 *10^{-4} t\)

Now, solve for t by dividing both sides of the equation with −1.2054734 ×

\(10 ^{-4}\)

Evaluate using a logarithm table or a calculator.t = 7539.10 years

Therefore, the bones are approximately 7539  years old.

The half-life of a radioactive isotope is that the amount of time it takes for one-half of the radioactive isotope to decay. The half-life of a selected radioactive isotope is constant; it is unaffected by conditions and is independent of the initial amount of that isotope

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It will take approximately 76.8 seconds (or 1.28 minutes) to plate out 4.56 g of Ni metal from the solution using a current of 50.5 amps in the electrolytic cell.

To determine the time required to plate out 4.56 g of Ni metal from a solution of Ni^2+ using a current of 50.5 amps in an electrolytic cell, we need to use Faraday's law of electrolysis and consider the molar mass of Ni.

The molar mass of Ni is approximately 58.69 g/mol. From the balanced equation, we know that the stoichiometric ratio between Ni^2+ and Ni is 1:1.

First, we need to calculate the number of moles of Ni using the given mass:

Moles of Ni = Mass of Ni / Molar mass of Ni

Moles of Ni = 4.56 g / 58.69 g/mol ≈ 0.0778 moles

According to Faraday's law, the amount of substance (moles) deposited or liberated during electrolysis is directly proportional to the quantity of electricity (Coulombs) passed through the electrolytic cell. The relationship can be expressed as:

moles of substance = (current × time) / (Faraday's constant × charge per mole)

In this case, the charge per mole is the number of electrons transferred, which is 2 for Ni^2+ to Ni.

Rearranging the equation, we can solve for time:

time = (moles of Ni × Faraday's constant × charge per mole) / Current

Substituting the known values:

time = (0.0778 moles × 96,485 C/mol × 2) / 50.5 A

Calculating this, we find:

time ≈ 76.8 seconds

Therefore, it will take approximately 76.8 seconds (or 1.28 minutes) to plate out 4.56 g of Ni metal from the solution using a current of 50.5 amps in the electrolytic cell.

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Answer:

D

Explanation:

Option D is the correct Lewis structure of ozone.

Ozone is known to be an allotrope of oxygen which has three atoms of oxygen.

In the Lewis structure of ozone, one pair of oxygen is actually double-bonded while the other is single-bonded. In this structure, two oxygen atoms carry charges. In the drawing the Lewis structure of ozone, we discover that one oxygen atom of the ozone has a -1 charge and while another oxygen atom of the ozone has a +1 charge.

Answer: an iceberg

Explanation: the reason for this is because it has much more mass then a hot cup of coffee even the the temputure of coffee is much warmer