What is the density of an object with a mass of 57.8g and a volume of 112.4mL?
Answers
Answer:
D=m/v
D=57.8/112.4
D=0.51423487544 g/mL^2
Explanation:
The density of an object with a mass of 57.8 g and volume of 112.4 mL is 514.23 mg/m L.
What do you mean by density?Density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume.
Density is commonly expressed in units of grams per cubic centimeter.
Density can also be expressed as kilograms per cubic metre .
To calculate the density of an object ,
Given,
Mass=57.8 g(57.8×1000=57800mG) convert grams into milligrams
Volume=112.4mL
We know ,
Density =mass/volume
=514.23mG/mL
The density of an object with a mass of 57.8g and volume of 112.4 mL is 514.23 mg/m L.
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Related Questions
Which of the following could potentially have a mutation? (Check all that may apply.)
Fungi
Animals
Bacteria
Viruses
Plants
Answers
Answer:
all of them
Explanation:
A liquid mixture containing 30.0 mole% benzene (B), 25.0 mole% toluene (T), and the balance xylene (X) is fed to a distillation column. The bottoms product contains 98.0 mole% X and no B; 96.0 mole% of the X in the feed is recovered in this stream. The overhead product is fed to a second column. The overhead product from the second column contains 97.0 mole% of the B in the feed to this column. The composition of this stream is 94.0 mole% B and the balance T. Calculate (i) the percentage of the benzene in the process feed that emerges in the overhead product from the second column and (ii) the percentage of toluene in the process feed that emerges in the bottom product from the second column.
Answers
Given data:
Mole% of benzene (B) = 30%
Mole% of toluene (T) = 25%
Balance = xylene (X)
Bottom product contains mole% of X = 98%
The overhead product from the second column contains mole% of B in the feed to this column = 97%Composition of overhead product = 94% B
Mole% of X recovered in the bottoms product = 96%
Let's solve the problem:Since the sum of mole% of benzene, toluene, and xylene is 100%, the mole% of X = 100 - 30 - 25 = 45%
In the feed, mole% of B = 30%, mole% of T = 25%, and mole% of X = 45%.
Calculation of benzene emerging in the overhead product from the second column:
Let's consider the flow rate of feed as 100 units, so the flow rate of B in the feed = 100 × 0.3 = 30 units.The flow rate of B in the overhead product of the first column = 30 × 0.03 = 0.9 units (since 97% of benzene in the feed is recovered in the overhead product).
Thus, the flow rate of benzene in the feed to the second column is 0.9 units.The composition of the overhead product from the second column is 94% benzene. Thus, the flow rate of benzene in the overhead product from the second column = 0.9 × 0.94 = 0.846 units.
The percentage of benzene emerging in the overhead product from the second column = (0.846/30) × 100 = 2.82%.
Hence, the percentage of benzene in the process feed that emerges in the overhead product from the second column is 2.82%.Calculation of toluene emerging in the bottom product from the second column:
Let's consider the flow rate of feed as 100 units, so the flow rate of T in the feed = 100 × 0.25 = 25 units.The flow rate of T in the overhead product from the first column = 25 × 0.04 = 1 unit (since 96% of the X in the feed is recovered in the bottoms product).
Thus, the flow rate of T in the feed to the second column is 25 - 1 = 24 units.The composition of the bottom product from the second column is 98% X. Thus, the flow rate of X in the bottom product from the second column = 24 × 0.98 = 23.52 units.
The flow rate of T in the bottom product from the second column = 100 - 30 - 23.52 = 46.48 units.The percentage of toluene in the process feed that emerges in the bottom product from the second column = (46.48/25) × 100 = 185.92%.
Hence, the percentage of toluene in the process feed that emerges in the bottom product from the second column is 185.92%.
Thus, the required answers are:
(i) The percentage of benzene in the process feed that emerges in the overhead product from the second column = 2.82%
(ii) The percentage of toluene in the process feed that emerges in the bottom product from the second column = 185.92%.
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fluorine gas and water vapor react to form hydrogen fluoride gas and oxygen. what volume of hydrogen fluoride would be produced by this reaction if 3.05 ml of water were consumed? also, be sure your answer has a unit symbol, and is rounded to 3 significant digits.
Answers
Fluorine gas and water vapor react to form hydrogen fluoride gas and oxygen. The volume of hydrogen fluoride produced by a reaction if 3.05 ml of water were consumed is 6.10 ml.
The balanced reaction between fluorine gas and water vapor is
2F₂(g)+2H₂O(g)→4HF(g)+O₂(g)
To find out the volume of hydrogen fluoride produce, we need to use Avogadro's law equation which is given as
V₁/n₁=V₂/n₂
Where, V₁=3.05 ml, n₁=2, n₂=4, V₂=?
Rearrange the formula for V₂
V₂=(V₁×n₂/n₁)
Plug all the values in the formula
V₂=(3.05 ml×4/2)
V₂=12.2 ml/2
V₂=6.10 ml
Therefore, the volume of hydrogen fluoride(HF) produced by the reaction if 3.05 ml of water were consumed is 6.10 ml.
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Consider the following reaction: 2NO(g)+O2(g)⇌2NO2(g) The data in the table show the equilibrium constant for this reaction measured at several different temperatures.
Temperatures: Kp:
170K 3.8*10^-3
180K 0.34
190K 18.4
200K 681
Part A Use the data to find ΔH∘rxn and ΔS∘rxn for the reaction.
i found ΔH∘rxn = 114 kJ but i dont know how to get ΔS∘rxn. please help and show work
.
Answers
Using the data in the table that shows the equilibrium constant for the reaction measured at several different temperatures, the ΔH∘rxn and ΔS∘rxn for the reaction is 114 kJ/mol and -188.54 J/(mol·K), respectively.
To find ΔH∘rxn and ΔS∘rxn for the reaction, we can use the Van't Hoff equation:
ln(K₂/K₁) = -(ΔH∘rxn/R)(1/T₂ - 1/T₁)
where K₁ and K₂ are the equilibrium constants at temperatures T₁ and T₂, R is the gas constant (8.314 J/mol·K), and ln is the natural logarithm.
Using the data from the table, we can calculate ΔH∘rxn and ΔS∘rxn as follows:
ln(0.34/3.8 x 10⁻³) = -(ΔH∘rxn/8.314)(1/180 - 1/170)
ΔH∘rxn = 114 kJ/mol
Solving for ΔS°rxn, we'll use the Van't Hoff equation:
ln(Kp) = -ΔH°rxn / R * (1/T) + ΔS°rxn / R
We can rewrite the equation as:
ΔS°rxn = R * (ln(Kp) + ΔH°rxn / R * (1/T))
You've already found ΔH°rxn = 114 kJ = 114,000 J. Now, choose one of the data points from the table (temperature and Kp) to calculate ΔS°rxn. Let's use the first data point:
T = 170 K
Kp = 3.8 x 10⁻³
R (gas constant) = 8.314 J/(mol·K)
Plug in the values:
ΔS°rxn = 8.314 * (ln(3.8 x 10⁻³) + 114,000 / (8.314 * 170))
ΔS°rxn ≈ -188.54 J/(mol·K)
So, the values of ΔH∘rxn and ΔS∘rxn for the reaction are 114.3 kJ/mol and -188.54 J/(mol·K), respectively.
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Change 60. miles/hour to km/min?
Answers
hope this helps
Calculate the amount of heat needed to convert 230.0g of ice at -10C to water at 0C
Answers
Answer:
It would take approximately 81.65 kJ (or 81,650 J) of heat to convert 230.0g of ice at -10C to water at 0C.
Explanation:
To calculate the amount of heat needed to convert ice at -10°C to water at 0°C, we need to consider two steps:
1. Heating the ice from -10°C to 0°C (heat required to raise the temperature of ice)
2. Melting the ice into water at 0°C (heat required to change the state of ice)
Let's first calculate the heat required for step 1:
Q1 = m × c × ΔT
where Q1 is the heat required, m is the mass of the ice, c is the specific heat capacity of ice, and ΔT is the change in temperature.
The specific heat capacity of ice is 2.09 J/g°C, and ΔT is (0°C - (-10°C)) = 10°C.
So, Q1 = 230.0 g × 2.09 J/g°C × 10°C = 4827 J
Now, let's calculate the heat required for step 2:
Q2 = m × Lf
where Q2 is the heat required, m is the mass of the ice, and Lf is the latent heat of fusion of ice.
The latent heat of fusion of ice is 334 J/g.
So, Q2 = 230.0 g × 334 J/g = 76820 J
Therefore, the total amount of heat needed to convert 230.0g of ice at -10C to water at 0C is:
Qtotal = Q1 + Q2 = 4827 J + 76820 J = 81647 J
Therefore, it would take approximately 81.65 kJ (or 81,650 J) of heat to convert 230.0g of ice at -10C to water at 0C.
CNH Radiology centre provides services for X-Ray procedures on per patient basis, $100 per patient:
According to the forcast, its patient number in 2018 will be 2000 for Q1, 6000 for Q2, 8000 for Q3, 4000 for
04. Generally, around 70% of the X-ray procedure revenue will be collected in current quarter and rest 30%
will be collected in next quarter. At the last quarter of 2017, outstanding Accounts Receivable shows
S90,000 on its Dec31, 2017 balance sheet.
Four X-Ray films will be used up for each of patient. Desired ending inventory is 10% of next quarter's need
The 2017 04 ending inventory are 400 sheets and the 2018 Q4 desired ending inventory are 1000 sheets.
The Average purchase cost per sheet will be $4.74 for Q1, $3.919 for Q2. $3.385 for Q3 and $3.624 for Q4
accordingly.
Generally, it takes 1.5 hour for the X-ray technician to complete X-Ray procedure for each patient.
The hourly pay rate for technician is average $20 per labour hour.
CNH's overhead costs can be generally divided into two categories---variable part and fixed part. Please
note its predetermined overhead rate for the year will be $5 per labor hour. According to the data,
Its fixed part of the overhead costs are stable every year-…-$242,400 including $60,000 amortization.
Radiology centre's cash balance at the end of 2017 was $42,500. Its office building administrative cost will
be Q1 $93,000; Q2 $130,900, Q3 $184,750, Q4 $129,150 respectively. According to the management, Radiology
centre will have equipment purchase in 2018, Q1 $89,400, Q2 $66,204, Q3 $1,602, Q4 $29,393.
Please make a cash budget to see if the Radiology centre has enough cash-in flow to cover the expenditures.
If Radio centre fall into deficiency, it will have to finance from the bank. The borrowing interest rate is 10%.
If there is a cash excess during the budget period, funds borrowed in previous periods can be repaid. Please
Note that Radiology centre must maintain at least keep $40,000 cash balance each quarter just in case 9$,
the emergency.
revenue budget
Answers
Revenue Budget: Projected revenue for CNH Radiology Centre in 2018:
Q1: $200,000 (2000 patients * $100 per patient)
Q2: $600,000 (6000 patients * $100 per patient)
Q3: $700,000 [($800,000 * 70%) + ($400,000 * 30%)]
Q4: $480,000 [($400,000 * 70%) + ($0 * 30%)]
Based on the forecasted patient numbers and the revenue per patient, the revenue budget for CNH Radiology Centre in 2018 is as follows. In Q1, with 2000 patients, the revenue is projected to be $200,000. In Q2, with 6000 patients, the revenue is expected to reach $600,000. For Q3, the revenue is calculated by considering 70% of the expected revenue from Q3 patients and 30% from Q4 patients. Thus, the total revenue for Q3 is projected to be $700,000. Similarly, for Q4, the revenue is calculated using 70% of the expected revenue from Q4 patients and 30% of the revenue from Q1 patients, as there are no forecasted patients for Q4. Therefore, the total revenue for Q4 is expected to be $480,000.
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If the density of a gas is 1.2 g/L at 745 torr and 20 degree celsius, what is its molecular mass?R = 0.0821 L.atm/K.mol
Answers
The question requires us to calculate the molecular mass of a gas, given its density (1.2 g/L) and conditions of pressure (745 torr) and temperature (20°C).
Density is defined as the mass of a compound over its volume. From this definition, we can calculate the molecular mass of the gas knowing the density, as given by the question, and the volume of 1 mol of the gas.
\(\text{density = }\frac{mass}{\text{volume}}\to\text{mass = volume }\times\text{ density}\)We can calculate the volume of a gas considering the equation of Ideal Gases:
\(P\times V=n\times R\times T\)where P is the pressure of the gas, V is its volume, n is the number of moles, R is the constant of gases and T is the temperature.
Note that the constant of gases R was given in units of L.atm/K.mol, while the pressure and temperature were given in Torr and °C, respectively. Thus we need to convert these values to the appropriate units.
Knowing that 1 Torr corresponds to 0.00131579 atm:
1 Torr --------------------- 0.00131579 atm
745 Torr ---------------- x
Solving for x, we have that 745 Torr corresponds to 0.980 atm.
To convert the temperature from Celsius degrees to Kelvin, we must add 273.15:
T = 20 + 273.15 K = 293.15 K
Therefore, the pressure and temperature we'll use in our calculation are 0.980 atm and 293.15 K. Also, since we are calculating the molecular mass, we'll consider 1 mol of gas.
Rearranging the equation of ideal gases to calculate the volume and applying the values to the equation, we'll have:
\(\begin{gathered} P\times V=n\times R\times T\to V=\frac{n\times R\times T}{P} \\ V=\frac{(1mol)\times(0.0821L.atm/K.mol)\times(293.15K)}{(0.980\text{atm)}}=24.6L \end{gathered}\)Therefore, the volume of 1 mol of the gas under the conditions given is 24.6L.
Next, we'll use this value to calculate the molecular mass using the density given by the question:
\(\begin{gathered} \text{mass = volume }\times\text{ density} \\ \text{mass = 24.6L}\times1.2g/L \\ \text{mass = }29.5g/\text{mol} \end{gathered}\)Therefore, the gas given by the question presents 29.5g per mol.
Changes in ______move matter from one state to another.
temperature
pressure
density
location
Answers
Answer:
temperature
Explanation:
The decomposition of 65.9 g ammonium nitrate yields how many liters of dinitrogen monoxide at 2.65 atm and 303 k?
(N= 14.01 g/mol, H= 1.008 g/mol, O=16.00 g/mol)
NH4NO3(s) -> N2O(g)+2H2O(g)
Hint: R = 0.0821 L atm/(mol K)
Answers
It’s 7.72 it took a while but I found the answer
Please help this is due soon
Answers
2. Se combinan 40 g de SO2 y 25 g de O2 determine el porcentaje en masa del exceso con respecto a su masa inicial. P.A. (S = 32; O = 16) SO2 + O2 SO3
Answers
Answer:
60%
Explanation:
En la reacción:
2SO₂ + O₂ → 2SO₃
Donde 2 moles de SO₂ reaccionan por mol de O₂.
El peso atómico del SO₂ es:
1S = 32g/molₓ1 = 32g/mol
2O = 16g/molₓ2 = 32g/mol
SO₂ = 32g/mol + 32g/mol = 64g/mol
Y el peso atómico de O₂ es:
2O = 16g/molₓ2 = 32g/mol
Las moles de SO₂ y O₂ son:
SO₂: 40g ₓ (1mol / 64g) = 0.625 moles
O₂: 25g ₓ (1mol / 32g) = 0.7813 moles
Para una completa reacción de SO₂ se necesitan:
0.625 moles SO₂ ₓ (1mol O₂ / 2 mol SO₂) = 0.3125 moles de O₂
Así, las moles en exceso de O₂ son:
0.7813 moles - 0.3125 moles = 0.4688 moles O₂
En gramos:
0.4688 moles O₂ ₓ (32g / mol) = 15g O₂ están en exeso.
El porcentaje en exceso es:
15g / 25g ₓ 100 =
60%Which substance have the same number of carbon (C) atoms?
Answers
Answer:
Carbon monoxide
Explanation:
Carbon dioxide and carbon monoxide have the same number of carbon atoms.
Mark Brainliest
materials that are attracted to magnets
Answers
Ferromagnetic metals are those that naturally draw magnets; these magnets will adhere to such metals hard. Ferromagnetic metals are, for instance, iron, cobalt, steel, gold, manganese, gadolinium, & lodestone.
Describe ferromagnetic metals.Ferromagnetic materials are common metals that exhibit a strong magnetic repulsion as a result of their high magnetic permeability. The term "magnetic permeability" refers to a material's induced magnetization brought on by the presence of a magnetic field.
Which ferromagnetic material is the strongest?The world's strongest magnetic material, Nd2Fe14b, is made of neodymium combined with iron, boron, and minute amounts of other elements like dysprosium and praseodymium.
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Which of the following ions (if equal in concentration) will contribute most to elevating the boiling point of H₂O? A. Fe3+ B. Ca2+ C. All would contribute equally D. Na+
Answers
A. Fe3+. This is because Fe3+ has a higher charge than Ca2+ and Na+, which means it has a stronger attraction to the water molecules and therefore causes more disruption to the water's ability to vaporize.
Additionally, the concentration of Fe3+ ions would need to be much lower than Ca2+ and Na+ ions to have the same effect on the boiling point of water due to its higher charge.
The boiling point elevation depends on the number of ions present in the solution. In this case, if all ions have equal concentration, Fe3+ (A) will contribute most to elevating the boiling point of H₂O, because it has the highest charge and will produce more ions when dissolved in water.
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Pronpane, C3H8, can be used as a fuel in your home, car, or barbecue grill because it is easliy liquefied and transportef. if 454g of propane is burned, what mads (in grams) of oxygen, O2, is required for complete combustion?
Answers
Taking into account the reaction stoichiometry, 1650.91 grams of O₂ is required to react with 454 grams of C₃H₈.
Reaction stoichiometryIn first place, the balanced reaction is:
C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
C₃H₈: 1 moleO₂: 5 molesCO₂: 3 molesH₂O: 4 molesThe molar mass of the compounds is:
C₃H₈: 44 g/moleO₂: 32 g/moleCO₂: 44 g/moleH₂O: 18 g/moleBy reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
C₃H₈: 1 mole ×44 g/mole= 44 gramsO₂: 5 moles ×32 g/mole= 160 gramsCO₂: 3 moles ×44 g/mole= 132 gramsH₂O: 4 moles× 18 g/mole= 72 gramsMass of O₂ requiredThe following rule of three can be applied: If by reaction stoichiometry 44 grams of C₃H₈ react with 160 grams of O₂, 454 grams of C₃H₈ react with how much mass of O₂?
mass of O₂= (454 grams of C₃H₈×160 grams of O₂) ÷44 grams of C₃H₈
mass of O₂= 1650.91 grams
Finally, 1650.91 grams of O₂ is required.
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The atmospheric pressure of Venus is 1.0 x 102 atm. How many
mmHg is this?
Answers
Answer:
76000
Explanation:
1*10^2 atm *760 mmHg = 76000
What is the density of a liquid with a mass of 31.1415 g and a volume of 30.13 ml?
Answers
The liquid with a mass of 31.1415 g and a volume of 30.13 ml has a density of: 1.033 g/ml
The density formula and the procedure we will use is:
d = m/v
Where:
v= volumed= densitym= massInformation about the problem:
m = 31.1415 gv =30.13 mld= ?Applying the density formula we get:
d = m/v
d = 31.1415 g/30.13 ml
d = 1.033 g/ml
What is density?It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.
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WRITE AND BALANCE THE FOLLOWING EQUATIONS: Ca + H,O -> Ca(OH), + AI(NO3)3 +_ H,SO - Al2(SO )3 + HNO3 *If the equation is already balanced- write "balanced" in the answer box.
Answers
The balanced equation becomes: 2Ca + 2H2O -> 2Ca(OH)2 + 2Al(NO3)3 + H2SO4 -> Al2(SO4)3 + HNO3
Now, the equation is balanced with equal numbers of atoms on both sides.
The given equation is: Ca + H2O -> Ca(OH)2 + Al(NO3)3 + H2SO4 -> Al2(SO4)3 + HNO3
To balance the equation, we need to ensure that the number of atoms on both sides of the equation is equal.
First, let's balance the calcium (Ca) atoms. There is one Ca atom on the left side and two Ca atoms on the right side. To balance this, we need to put a coefficient of 2 in front of Ca on the left side.
The balanced equation becomes: 2Ca + H2O -> Ca(OH)2 + Al(NO3)3 + H2SO4 -> Al2(SO4)3 + HNO3
Next, let's balance the hydrogen (H) atoms. There are two H atoms in H2O and two H atoms in H2SO4 on the left side. On the right side, there are four H atoms in Ca(OH)2 and three H atoms in HNO3. To balance this, we need to put a coefficient of 2 in front of H2O on the left side.
The balanced equation becomes: 2Ca + 2H2O -> Ca(OH)2 + Al(NO3)3 + H2SO4 -> Al2(SO4)3 + HNO3
Now, let's balance the oxygen (O) atoms. There are four O atoms in Ca(OH)2 on the right side. To balance this, we need to put a coefficient of 2 in front of Ca(OH)2 on the right side.
The balanced equation becomes: 2Ca + 2H2O -> 2Ca(OH)2 + Al(NO3)3 + H2SO4 -> Al2(SO4)3 + HNO3
Finally, let's balance the aluminum (Al) atoms. There is one Al atom on the right side. To balance this, we need to put a coefficient of 2 in front of Al(NO3)3.
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Writing chemical formulas cross cross method worksheet
Please help ASAP.
Answers
The chemical formulas cross method worksheet are listed below in the answer.
What are chemical formulas?A chemical formula lists the constituent components of a compound together with how many atoms of each are present in the complex's smallest unit, whether it be a molecule or a formula unit. We can name simple compounds based on their chemical formulas by using the names of the elements and a few simple criteria.
What is cation?Cations are positive-charged ion particles. Atoms or molecules that are ionic are charged. If an electron or more are lost from a balanced atom, it will change into a positively charged cation. When a balanced atom gains one or more electrons, an anion, a negatively charged atom, forms.
1. Na₂so₄
4. Kcl, , , K₃PO₄, KNO₃, K₂SO4
5. Mg₂Cl₂, Mg₃ (Po₄)₂, Mg₃ (No₂)₂, Mgso₄
6. AlCl₃, AlPo₄, Al (No₃)₃, Al₂(so₄)₃
7. HCl, H₃PO₄, HNO₃, H₂SO₄
8. FeCl₂, Fe(PO₄)₂, Fe(NO₃)₂, FeSo₄
The chemical formulas cross cross method worksheet are listed above.
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why is mass number always a whole number?
Answers
what is the ionic equation for potassium fluoride and ammonium nitrate
Answers
Answer:
kf+Nh4 no3 --> kno3+nh4f
Chloroform (CHCl3), an important solvent, is produced by a reaction between methane and chlorine.
CH4(g) + 3 Cl2(g) CHCl3(g) + 3 HCl(g)
How many grams of CH4 is needed to produce 56.0 g CHCl3?
Answers
If your solid camphor product has a melting point slightly lower than you expect, what can you conclude about the product
Answers
If your solid camphor product has a melting point slightly lower than you expect, you can conclude that the product may be impure or contain some contaminants.
The melting point of a substance is a physical property that can be used to determine its purity. Pure substances generally have a specific and well-defined melting point.
However, when impurities or contaminants are present, the melting point may be altered. In the case of your camphor product, a lower melting point indicates that there could be impurities mixed with the camphor, which are affecting its melting behavior.
A lower melting point than expected for your solid camphor product suggests that it might not be completely pure, and it likely contains some impurities or contaminants.
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Which of the following explains a difference between genes and chromosomes
Answers
Answer:
Dude I need the answers so i can help you!
Explanation:
Give me the answers plz
true statements about ozone include which of the following? i. ozone is a precursor of acid rain. ii. contact with ozone can be injurious to human health. iii. ozone absorbs some wavelengths of ultraviolet radiation (a) ii only (b) iii only (c) i and iii only (d) ii and iii only (e) i, ii, and iii
Answers
The statements (ii) and (iii) are the true statement which include about ozone . So, option (d) is correct choice.
The ozone layer is the layer that surrounds the earth and contains a high concentration of O₃ ozone. Ozone O₃ is a gas molecule composed of three oxygen atoms. Ozone is commonly known as photochemical "smoke" and is harmful to respiration.
It is formed by the dissociation of two atoms forming oxygen. It is a harbinger of acid rain. Exposure to ozone can harm human health. Ozone absorbs some wavelengths of ultraviolet radiation and protects the earth's surface from dangerous radiation. Therefore, it is clear from the above discussion that (ii) and (iii) are correct statements about ozone.
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can someone please help me i don't know these question bc my family celebrates thanksgiving differently. plz and thank you :3
Easy: How many turkeys are consumed on Thanksgiving day in America?
Medium: How long did the first Thanksgiving Celebration last?
Hard: When was the first NFL football game on Thanksgiving?
Fun: Who was the first president to pardon a turkey?
Answers
Answer:
Easy 46 million turkeys
Medium three days
Hard: 1934
Fun: The first President on record issuing a "pardon" to his turkey was Ronald Reagan.
Explanation:
hop tis helped
is Sulfuric Acid soluble if placed in water
Answers
Answer: Yes, sulfuric acid is highly soluble in water.
Explanation:
What type of eclipse may result in our day time skies becoming darkened?
Answers
Answer:
Hope it help you
Stayhomestaysafe
Plz mark my answer brainliest✍️✍️
Explanation:
When the Moon blocks a certain part, it is known as a partial solar eclipse. This causes the day to turn dark and during the eclipse, it is not considered safe to look at the sun without protective gear on.
REAL NAME - SHRESTH DUBEY
Explanation: In a solar eclipse, the Moon moves between the Earth and the Sun. When this happens, part of the Sun's light is blocked. The sky slowly gets dark as the Moon moves in front of the Sun. When the Moon and Sun are in a perfect line, it is called a total eclipse.
Isomers are ______ compounds that have ______ molecular formula. multiple choice question. different, the same the same, different the same, the same different, different
Answers
Isomers are different compounds that have the same molecular formula.
In chemistry the type of compounds that have the same molecular formula but have a different chemical structure are known as Isomers. The isomers have different chemical and physical properties each other, so they can be considered as a total different compound, this is because they have a different arrangement of its atoms.
What is an atom?the atom is the smallest part of the composition of matter, it is indivisible and is composed of a nucleus that has protons and neutrons, and around the nucleus there are the electrons.
Learn more about the atom at: brainly.com/question/17545314
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