Answer:
biking / jogging/ running, walking
Explanation:
Cardio workouts can strengthen your heart and blood vessel
which action will give you more momentum toward the north: throwing one shoe southward at 10 m/s or two shoes southward at 5 m/s?
Throwing one shoe southward at 10 m/s will give you more momentum toward the north.
Momentum is defined as the product of an object's mass and its velocity. The momentum of an object can be determined using the equation:
Momentum = mass × velocity
In this case, both scenarios involve throwing shoes southward, which means the velocity is directed to the south. The key difference is the magnitude of the velocity.
When throwing one shoe southward at 10 m/s, the velocity is higher compared to throwing two shoes southward at 5 m/s. Since momentum depends on velocity, the higher velocity of the single shoe results in a greater momentum.
The mass of the shoes does not play a role in determining which action gives more momentum toward the north since the mass is the same in both scenarios. Therefore, throwing one shoe southward at 10 m/s will give you more momentum toward the north compared to throwing two shoes southward at 5 m/s.
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Describe or identify some uses of an electromagnet.
Answer:
Electromagnets are widely used as components of other electrical devices, such as motors, generators, electromechanical solenoids, relays, loudspeakers, hard disks, MRI machines, scientific instruments, and magnetic separation equipment.Explanation:
A projectile of mass 0.2 kg and an initial velocity of 50 m/s collides with the end of a blade attached to a turbine. The rotational inertia of the turbine is 12.5 kg⋅m2 . Assume the loss of energy of the projectile in the collision is completely transferred to the blades, causing them to spin. If the final rebound velocity of the projectile after hitting a turbine blade is −25 m/s , which of the following is most nearly the rotational velocity of the turbine after the collision?
Answer:
5.5 rad/sec
Explanation:
Answer:
5.47 rad/s
Explanation:
We can solve this problem using the principle of conservation of energy and angular momentum.
First, let's find the initial kinetic energy of the projectile:
K1 = (1/2) * m * v1^2
= (1/2) * 0.2 kg * (50 m/s)^2
= 250 J
where v1 is the initial velocity of the projectile.
Next, let's find the final kinetic energy of the projectile:
K2 = (1/2) * m * v2^2
= (1/2) * 0.2 kg * (-25 m/s)^2
= 67.5 J
where v2 is the final velocity of the projectile after the collision.
The loss of energy in the collision is:
ΔK = K1 - K2
= 187.5 J
This energy is transferred to the blades, causing them to spin. Let's assume that all of this energy is converted to rotational kinetic energy of the turbine.
The final rotational kinetic energy of the turbine is:
K_rot = (1/2) * I * ω^2
where I is the moment of inertia of the turbine and ω is the final rotational velocity of the turbine.
Using the conservation of energy, we can equate the loss of kinetic energy in the collision to the gain in rotational kinetic energy of the turbine:
ΔK = K_rot
187.5 J = (1/2) * 12.5 kg m^2 * ω^2
ω^2 = (2 * 187.5 J) / (12.5 kg m^2)
ω^2 = 30
ω = 5.47 rad/s
Therefore, the rotational velocity of the turbine after the collision is 5.47 rad/s.
how much force must be exerted to accelerate a 240 n weight to 5.7 m/s2
To accelerate a 240 N weight to 5.7 m/s^2, a force of 1,368 N must be exerted.
The force required to accelerate an object can be calculated using Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the weight of the object can be considered as its mass, since weight is the force exerted by gravity on an object. Therefore, the mass (m) is 240 N (weight) divided by the acceleration due to gravity (9.8 m/s^2), which equals approximately 24.49 kg. To find the force (F) required to accelerate the object to 5.7 m/s^2, multiply the mass by the acceleration: 24.49 kg x 5.7 m/s^2 = 139.413 N, or approximately 1,368 N. Thus, a force of 1,368 N must be exerted to achieve the desired acceleration.
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What is the current produced by a potential difference of 120 volts through a resistance of 0.8 ohms
Answer:
150A
Explanation:
Given parameters:
Potential difference = 120V
Resistance = 0.8Ω
Unknown:
Current = ?
Solution:
From ohm's law;
I = \(\frac{V}{R}\)
I is the current
V is the voltage
R is the resistance
Now insert the parameters and solve;
I = \(\frac{120}{0.8}\) = 150A
You do work when you shovel your driveway. If you use a snow blower, is the work done more, less or the same? Explain.
Answer:
i would say either more or the same
Explanation:
In your own words explain how acceleration differs from uniform motion.
Explanation:
acceleration is the Changing of throut per unit time ....
and in uniform motion .....
in that the speed of an object is uniform means same
Which quantity is measured in newton seconds (Ns)?
impulse
moment
power
work done
Answer:
Impulse
Explanation:
Impulse is force times time
A block (5 kg) is pulled by a 50 N at an angle of 30◦tothe ground. The block experiences a 4,2 N frictional force and moves 2,60 m. The block starts from rest. Use the work-energy principle to calculate the speed of the block after the 2,60 m.
Please explain/name all formulas used.
The speed of the block after the 2,60 m is determined as 6.38 m/s.
What is the work done on the block?
The work done on the block is calculated by applying the principle of Newton's second law of motion to determine the net work done on the block as shown below.
W = F(net)d
where;
F(net) is the net forced is the distanceF(net) = Fcosθ - Ff
where;
F is the applied forceFf is the frictional forceF(net) = 50 cos(30) - 4.2
F(net) = 39.1 N
The speed of the block is calculated by applying the principle of work energy theorem.
K.E = W
¹/₂mv² = F(net)d
mv² = 2F(net)d
v² = [2F(net)d] / m
v = √[2F(net)d] / m]
v = √[2 x 39.1 x 2.6] / 5]
v = 6.38 m/s
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Which event is best demonstrated with the model below? plate plate Formation of a mid -ocean ridge An earthquake A volcanic eruption Formation of a mountain
URGENT
Is it
A
B
C
Or D
A: formation of mid ocean ridge
B: an earthquake
C: a volcanic eruption
D: formation of a mountain
Answer:
d i think
Explanation:
becuse
Answer:
B
Explanation:
A wooden block of 0.60 kg is placed on a rough surface where it is accelerated at the rate of 4 m/s2. If the force applied on the block is 12N,what frictionless force is affecting the motion of block?
Answer:
Take a look below
Explanation:
the lowest-intensity sound that is still audible has an intensity of approximately iear=10−12w/m2. consider a jet that flies at an altitude of 6500 m .
The altitude of the jet is important in determining the intensity of the sound that it produces. The intensity of the sound decreases as the distance from the source increases.
In this case, the sound wave has to travel a distance of 6500 meters from the jet to the listener on the ground. Assuming that the jet is producing a sound wave with an intensity of 100 W/m^2, the sound wave will experience a decrease in intensity as it travels from the source to the listener. The intensity of the sound wave will decrease as the square of the distance from the source. Therefore, the intensity of the sound wave at a distance of 6500 meters from the source will be:
I = (100 W/m^2) / (6500 m)^2 = 2.5 x 10^-8 W/m^2
This is much lower than the lowest-intensity sound that is still audible, which has an intensity of approximately iear=10^-12 W/m^2. Therefore, the sound produced by the jet at an altitude of 6500 meters will not be audible to the human ear.However, it is important to note that the intensity of the sound produced by the jet can vary depending on its speed and altitude. A faster jet or a jet flying at a lower altitude will produce a higher-intensity sound wave that may be audible to the human ear from the ground.
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How can you describe the path of the projectile motion?
Projectile motion is a motion where an object moves in a bilaterally symmetrical path
What is a Projectile motion ?Projectile motion is a form of motion experienced by an object or particle that is projected near Earth's surface and moves along a curved path under the action of gravity only.
If an object is thrown up by making a certain angle with respect to ground ( let say theta) up in the sky , it will reach a maximum height after which it follows a symmetrical path as it comes down due to the action of gravity . The path followed from the beginning till end will be a parabolic in this case .
It is a motion where an object moves in a bilaterally symmetrical path .
Projectile motion only occurs when there is only one force applied at the beginning of the trajectory, after been released object comes in the action of gravity .
General form of equation of trajectory of Projectile motion can be written as :
y = x tan(theta ) - g(x^2)/(2(u^2)cos^2(theta))
where y = horizontal component
x = vertical component
g = gravity
u = initial velocity
theta = angle of inclination of the initial velocity from horizontal axis
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List two objects here on Earth that are sources of radiant energy. How can you tell they emit radiant energy?
since a transformer typically consists of a primary and secondary coil wound over one another, two electromagnets exist in a transformer.
The given lens with a focal length of 200 mm can be adjusted within a range of 200.0 mm to 209.4 mm from the film. This adjustment corresponds to object distances ranging from approximately 1106.38 mm to infinity, allowing for a variety of focusing options.
To determine the range of object distances for which the lens can be adjusted, we can use the lens formula:
1/f = 1/d₀ + 1/dᵢ
Where:
f = focal length of the lens
d₀ = object distance
dᵢ = image distance
Given:
f = 200 mm
dᵢ range: 200.0 mm to 209.4 mm
To find the minimum object distance (d₀ min), we can use the maximum image distance (dᵢ max = 209.4 mm):
1/200 = 1/d₀ + 1/209.4
To solve for d₀, we rearrange the equation:
1/d₀ = 1/200 - 1/209.4
1/d₀ = (209.4 - 200)/(200 * 209.4)
1/d₀ = 9.4/(200 * 209.4)
d₀ = 1/(9.4/(200 * 209.4))
Calculating this expression, we find:
d₀ ≈ 1106.38 mm
Therefore, the lens can be adjusted for object distances ranging from approximately 1106.38 mm to infinity.
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6th grade science pls help
Answer:
D
Explanation:
I hope you get a good grade!
a ball spins on a 0.880-m-long string with a constant speed of 3.75 m/s. 1) calculate the acceleration of the ball. (express your answer to three significant figures.)
The acceleration of the ball spinning on a 0.880-m-long string with a constant speed of 3.75 m/s is approximately 16.1 m/s².When an object moves in a circular path with a constant speed, it experiences centripetal acceleration directed toward the center of the circle.
Acceleration is the rate at which an object's velocity changes over time. In this case, the ball is spinning on a string with a constant speed of 3.75 m/s and a length of 0.880 m. The acceleration can be determined using the formula for centripetal acceleration:
a = v² / r
where "a" is the acceleration, "v" is the velocity, and "r" is the radius or the length of the string. Plugging in the given values:
a = (3.75 m/s)² / 0.880 m
a = 14.06 m²/s² / 0.880 m
a ≈ 15.98 m²/s²
Rounding to three significant figures, the acceleration of the ball is approximately 16.1 m/s².
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6- A boy throws a ball with a horizontal velocity of 3.0 m/s, from a height of 5.2 m over the ground, what is the horizontal displacement of the ball?
A. 5.6 m
B. 4.0m
C. 3.1 m
D. 2.5 m
Answer:
Explanation:
Given:
V₀ = 3.0 m/s
H = 5.2 m
__________
L - ?
Time for the ball to fall vertically:
H = g·t²/2; ⇒ t = √ (2·H / g) = √ (2·5.2 / 9.8) ≈ 1.0 c
Move the ball horizontally:
L = V₀·t = 3.0·1.0 = 3.0 m
If a boy throws a ball with a horizontal velocity of 3.0 m/s, from a height of 5.2 m over the ground , then the horizontal displacement of the ball is 3.09 meters.
What are the three equations of motion?There are three equations of motion given by Newton,
v = u + at
S = ut + 1/2 × a × t²
v² - u² = 2 × a × s
As given in the problem If a boy throws a ball with a horizontal velocity of 3.0 m/s, from a height of 5.2 m over the ground
S = ut + 1/2 × a × t²
5.2 = 0 + 0.5 × 9.8 × t²
t² = 5.2 / 4.9
t = 1.03 seconds
The horizontal displacement of the ball = 1.03 × 3
= 3.09 meters
Thus, the horizontal displacement of the ball is 3.09 meters.
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A space probe recovered an 8.5-kg sample of rocks from the surface of Mars. The acceleration due to gravity on Mars is 3.7 meters per second squared. What is the weight of the sample of rocks on the surface of the earth?
Answer: 31N
Explanation:F = m x a
F = 8.5 x 3.7
F = 31.45
F = 31 (rounded)
F = 31 N
what is SI unit of Meter
Answer:
There is not such thing as SI unit of meter
Meter is SI unit for length
100 POINTS AND BRAINLY PLEASE HELP QUICK QUESTION I'M DESPERATE
Question 13(Multiple Choice Worth 2 points)
As a beginner bowler, Maria gets frustrated that her shots very rarely knock down any pins. Her Mom says that her arm movement looks awkward before releasing the ball. Maria feels like she needs to improve arm swing motion. How can Maria improve her bowling technique to be more successful?
Increase the weight of the ball to gain more control
Push the ball out away from her on the first step
Put more spin on the ball so that it curves prior to hitting the pins
Take fewer steps before releasing the ball to decrease her arm speed
Push the ball out away from her on the first step. Option B.
The key to consistent shots is the angle at which you pocket the ball. For right-handed bowlers, the pocket is between the 1st and 3rd pins. If you are left-handed it will be between pins 1 and 2. Keep your arms straight as you bring them back for the backswing and try to stay close to your body throughout the throw. Timing is important when releasing the ball.
A simple way to determine where the ball should exit the edge of the oil sample is simply to apply the rule of 31. Subtract 31 from the oil pattern distance. This will give you the board number where the ball ends the pattern. As a rule of thumb, right-handed bowlers place the inside of their left foot on the midpoint, and left-handed bowlers do the same with their right foot. Then stand with your other leg slightly behind you about 2 inches apart.
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Answer:
Maria can improve her arm swing motion in bowling by developing a free swing, where instead of controlling the ball with her arm, the ball controls her arm. This can be achieved by putting only mild to light grip pressure on the ball and pushing it back while standing relaxed. This will let the ball down and the gravitational energy will get her arm to the apex. As soon as she reaches the apex, she’ll have to slide forward and release the ball without pulling and grabbing.
Out of the options you provided, pushing the ball out away from her on the first step seems to be a good way for Maria to improve her arm swing motion in bowling.
So your answer would be (A) pushing the ball out away from her on the first step.
an electron is released from rest at the negative plate. with what speed will it strike the positive plate?
Speed will it strike the positive plate 74.736*10^6 m/s
r = distance = 3.7 mm
a) E = electric field between plates =
E = 38*10^-6 / 8.85*10^-12
= 4.293*10^6 N/C
from E = -dV / dr
dV = potential difference . take magnitude:
dV = E*dr
= 4.293*106*3.7*10-3
= 15.887 *103V
b) from F ( force) = q*E
also F = ma
so ma = qE
a( acceleration) = qE/ m
q = charge on electron, m= mass
a = 1.6*10^-19*4.293*10^6 / 9.1*10^-31
a = 7.548*1017 m/s2
u = initial velocity = 0 m/s ( at rest)
V = final velocity= ?, S = distance = r = 3.7 mm
v^2 = u^2+2as
putting values we get
Speed will it strike the positive plate 74.736*10^6 m/s
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Which statement accurately describes viscosity?
A. A liquid with larger molecules resists movement more than a liquid with smaller molecules does.
B. A material slows or completely blocks the flow of electrons through it.
C. A material with relatively weak bonds between its particles can be shaped into a thin sheet.
D. Attractive forces between molecules at the surface cause a liquid to resist spreading out.
The statement that accurately describes viscosity is option D: Attractive forces between molecules at the surface cause a liquid to resist spreading out. Option D
Viscosity is a measure of a fluid's resistance to flow. It quantifies how easily a fluid can be deformed or how readily it flows. In liquids, viscosity arises from the cohesive forces between molecules.
When molecules in a liquid are attracted to each other, they tend to stick together and resist movement. At the surface of the liquid, there is a greater degree of attractive forces between the molecules since they have fewer neighboring molecules to interact with.
This surface tension creates a resistance to the spreading out of the liquid and causes it to exhibit a more rounded or droplet-like shape.
The attractive forces between molecules at the surface of a liquid contribute to the cohesive forces within the liquid as a whole, resulting in a higher viscosity.
The stronger the attractive forces between the molecules, the higher the viscosity of the liquid. For example, honey has a higher viscosity compared to water because the molecules in honey have stronger attractive forces, making it flow more slowly.
Option A is not an accurate description of viscosity. Viscosity is not solely determined by the size of the molecules in a liquid but rather by the strength of the attractive forces between the molecules.
Option B describes electrical conductivity, not viscosity. It refers to a material's ability to slow down or impede the flow of electrons.
Option C describes the property of malleability, not viscosity. It refers to a material's ability to be shaped into a thin sheet without breaking.
Therefore, option D accurately describes viscosity by highlighting the role of attractive forces between molecules at the surface of a liquid in resisting the spreading out of the liquid
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A coffee machine transfers 12 kj of energy in 15 seconds. It uses 230 v mains supply. Use this information to work out the current through the coffee machine
The current through the coffee machine is 3.48 A.
To calculate the current flowing through the coffee machine, we use the formula below.
Formula:
E = VIt............. Equation 1Where:
E = Energy transfered by the machineV = Voltage of the main supplyI = current through the coffee,t = time.
Make I the subject of the equation.
I = E/Vt.............. Equation 2From the question,
Given:
E = 12 kJ = 12000 JV = 230 Vt = 15 seconds.Substitute these values into equation 2
I = (12000)/(230×15)I = 3.48 A.Hence, The current through the coffee machine is 3.48 A.
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Answer:3.48
Explanation:
Suggest any five activities where application of relation between pressure and area in day to day activities is used.
Five activities that will see the application of relation between pressure and area include:
Using a bicycle pump to inflate a tireAdjusting the water pressure in a showerheadOperating a hydraulic car liftOperating a hydraulic jackUsing a blood pressure cuffWhat are some examples that show pressure and area in real life ?When the handle of a pump is squeezed, the pressure inside the tire increases, causing the tire to inflate. By adjusting the size of the opening in the showerhead, the water pressure can be increased or decreased.
When a car is placed on a hydraulic lift, the pressure in the lift's cylinder is increased, causing the lift to raise the car off the ground. When a hydraulic jack is used to lift a heavy object, the pressure in the jack's cylinder is increased, causing the jack to lift the object.
A blood pressure cuff uses pressure to measure the blood pressure in a person's artery. The pressure in the cuff is increased until it is high enough to stop the flow of blood, and then the pressure is slowly released. The pressure readings at various points during this process can be used to determine a person's blood pressure.
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you see lightning and then hear thunder approximately 20 seconds later. what is the best estimate of the distance between you and the lightning strike?
The best estimate of the distance between you and the lightning strike is approximately 6860 meters.
The best estimate of the distance between you and the lightning strike can be calculated using the speed of sound in air, which is approximately 343 meters per second.
The time interval between seeing the lightning and hearing the thunder is 20 seconds, we can use the formula:
Distance = Speed × Time
Distance = 343 m/s × 20 s
Distance ≈ 6860 meters
When you see lightning, the light travels to your eyes almost instantaneously because light travels much faster than sound. However, sound travels at a much slower speed. The time interval between seeing the lightning and hearing the thunder is due to the time it takes for the sound waves to travel from the lightning source to your location.
By using the speed of sound in air, which is approximately 343 meters per second at room temperature, we can estimate the distance between you and the lightning strike. Multiplying the speed of sound by the time interval gives us the distance traveled by the sound waves.
In this case, if the time interval is 20 seconds, multiplying 343 m/s by 20 s gives us a distance of approximately 6860 meters. This means that the lightning strike occurred roughly 6860 meters away from your location. Keep in mind that this is an estimation, as the speed of sound can vary slightly depending on factors such as temperature and humidity.
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Which characteristic is used to measure the amount of light radiated by a star?
A.size
B.color
C.luminosity
D.temperature
if you were to stand up and sprint as fast as you could for about 10 seconds, what fuel sources would allow you to do this?
If you were to stand up and sprint as fast as you could for about 10 seconds, your body would primarily rely on stored carbohydrates (in the form of glycogen) as the main fuel source.
During high-intensity activities such as sprinting, the body's demand for energy increases rapidly. To meet this increased demand, the muscles break down glycogen into glucose, which is then converted into ATP (adenosine triphosphate), the primary energy currency of the cell.
In addition to glycogen, a small amount of fat may also be used as a fuel source during sprinting, but at such a high intensity, carbohydrates are the primary energy source.
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help pls
An observer moves to the left with some velocity, v, at the same time a sound wave source moves to the left with twice the velocity of the observer. How will the frequency of the source be shifted as it passes the observer?
The observed frequency will be greater than the source’s frequency.
The observed frequency will be less than the source’s frequency.
The observed frequency will be the same as the source’s frequency.
The source never passes the observer.
The observed frequency will be greater than the source’s frequency (option - A) is correct answer.
What happens if both the observer and the sound source move?If the source and observer are moving simultaneously in either case—moving observer or moving source—you'll notice that the frequency increases. The frequency decreases if they are drifting apart. Whether the source is moving or the observer is moving will affect how much the frequency changes.
Although the waves move at the same speed, the frequency that is observed is affected by any relative movement between the source and the observer. The wavelength changes along with the observed frequency. When an observer and a source are moving in the same direction, the frequency rises and the wavelength falls.
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different between SI system and CGS system
Answer:The SI system, for this reason, is also called the MKS system. CGS system: On the other side or the second self-consistent system uses centimetres, grams and seconds for length, mass and time.
Explanation: