what is the change in internal energy of a system that takes in 4.23 106 j of heat, and does 4.50 105 j of work while dissipating 9.07 106 j of heat?

A(n) active solar system makes use of a secondary medium, such as water, to collect and convey the energy of the sun. Like passive systems, these are often used for heating buildings.

Active solar systems actively circulate a fluid medium, typically water or a heat-transfer fluid, between solar collectors and the building or storage system using mechanical equipment like pumps or fans. The fluid is circulated to provide room heating, water heating, or other heating applications once the solar collectors transfer the energy from the sun to it.

Active solar systems are those that employ solar collectors to heat water that is then circulated via pipes to produce hot water for residential usage or space heating. These systems can be used to heat buildings.

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Answer:

Explanation:

Welcome to Pagasi b,  new recruit.  You will enjoy your new, fresh , home planet.  Your new home world is more relaxed than earth, days are longer by about quadruple, as are the nights.   Also seasons are also about 4 times  as long on Pagasi b. one year on Pagasi b is a bit over 4 years on earth.  You'll get great harvests and plenty of time to rest up during the mild, yet cool winters.  If the equatorial region is too warm for you during summer you can always travel north as the planet is at a 79 degree axis tilt , and will provide much cooler climes as you travel north for summers.  Have a great day, day, day, day   :P

Answer:

d. collection of photo.....

Answer:

True

Explanation:

Mitosis is the process of cell division that produces two identical daughter cells. Occasionally mutations can occur during DNA replication or the other stages of mitosis. However, cells have mechanisms for DNA repair that can correct these mutations, ensuring the integrity of the genetic material.

Answer:

A. True

Explanation:

edge 2022

The blue, hotter stars tend to have shorter lifetimes than the , cooler stars; this is a true fact as the lifespan of a star is determined by its mass. Blue, hotter stars have higher masses than red, cooler stars.

The lifespan of a star is largely determined by its mass because a star's mass affects its internal pressure, temperature, and nuclear fusion rate, and more massive stars have stronger gravitational forces, which lead to higher pressures and temperatures in their cores. The rate of nuclear fusion reactions in a star determines how quickly it consumes its fuel, which in turn affects the lifespan of the star. Blue, hotter stars have a higher rate of nuclear fusion reactions and consume their fuel much more quickly than red, cooler stars.

Hence, the blue, hotter stars tend to have shorter lifetimes than the redder, cooler stars.

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Answer:

It would be PE=16kg * 9.8 m/s^2 * 1m = 160 J

Explanation:

The person who asked this question ended up answering his own question so I'm here to let you know all that the answer was founded by the person whos posted the question himself full credit goes to him :)

Answer:

The displacement of Sudhir is 0.781 km.

Explanation:

Given;

initial distance, d₁ = 0.4 km = 400 m, N60.0°W

final distance, d₂ = 0.5 km

Make a sketch of Sudhir motion to form a right angled triangle;

(Check image uploaded).

Apply cosine rule to determine d "displacement"

d² = 500² + 400² - (2 x 500 x 400 x cos 120)

d² = 410,000 - (400,000 x -0.5)

d² = 410,000 - (-200,000)

d² = 410,000  + 200,000

d² = 610,000

d = √610000

d = 781.03 m

d = 0.781 km

Therefore, the displacement of Sudhir is 0.781 km.

We want to explain why two different observes may measure different frequencies for the same vibrating object.

We will see that the two correct options are:

Let's assume that the vibrating object is a guitar string. Thus, the string makes a noise, and from that noise, we can estimate the frequency at which the string vibrates.

Now there appears a really cool effect, called the Doppler Effect. It says that the apparent change of frequency is due to the motion of the observer or the source of the frequency (or both).

For example, if you move towards the vibrating string, the perceived frequency will be larger, and you will hear a "higher" sound.

While if you move away from the string, the opposite happens, and you will hear a "lower" sound.

Then the only thing that impacts in how we perceive the frequency is our velocity relative to the source.

So, why do observers A and B measure different frequencies?

The two correct answers are:

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Your Answers for Redshift and Blueshift Quick Check are down here ↓

Which situations might cause two observers (A and B) to measure different frequencies for the same vibrating object? Select the two correct answers. (2 points)

Observer A is stationary and Observer B is moving. * A = yes

Observer A and Observer B are moving at different speeds relative to each other. * B = yes

Observer A and Observer B are stationary but at different distances from the vibrating object. No

Observer A and Observer B are both stationary and at the same distance from the object. No

Why do scientists observe blueshift in certain stars?(1 point)

Light wave frequencies increase as an object moves toward the observer. * A = yes

Stars with lower temperatures emit more light waves at the blue end of the spectrum. No

Light wave frequencies decrease as an object moves toward the observer. No

Stars with higher temperatures emit more light waves at the blue end of the spectrum. No

When will a scientist observe redshift in the spectrum of a distant space object?(1 point)

when the object is stationary. No

when the object is moving toward the scientis. No

when the object is moving away from the scientist * C = yes

when the object is in the same frame of reference as the scientist. No

Hope this helps :) . Your Welcome, and Hope you guys are doing good in school!!

The equilibrium height to which the wire CD will rise is given by the expression h = μ₀I² / 2π λg

A region in which the force of magnetism acts is known as the magnetic field, and it surrounds magnetic materials or a moving electric charge. Moving magnetic dipoles and electric charges produce a magnetic field, which acts as a force field on other nearby magnetic dipoles and moving charges.

Magnetic field at a distance h produced by a current carrying wire

B = μ₀I/ 2πh

Magnetic force due to the present current carrying wire can be calculated by the formula

F = B I  L

And we also know that F = mg

On equating these mg = B I L

( μ₀I/ 2πh ) I = ( m/ I ) g = λg

thus we get the value of h as

h = μ₀I² / 2π λg

Thus, the equilibrium height to which the wire CD will rise is given by the expression h = μ₀I² / 2π λg .

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Answer:

Explanation:

Answer:

C. the blue colour of the Earth's sky

Explanation:

The Pleiades is a cluster of sister stars that are among the closest star cluster to earth.

The reflection nebula of the Pleiades is due to the scattering of the blue light from the hot blue luminous stars that dominate the star cluster. Th blue light is scattered from dust molecules, thought to be predominantly carbon compound like diamond dusts, and other compounds like iron.

The blue colour of the Earth's sky is the closest terrestrial phenomenon to the reflection nebula. On a clear cloudless day, molecules in the air scatter the blue component of light more than the other component colours of white light, giving the sky its characteristic blue coluor.

The common characteristics of the luminous nebula and the Earth's blue sky is that they both have their light scattered by the presence of small particles.

When an alpha particle (^4He) strikes a stationary gold nucleus (^197Au) head-on, the kinetic energy of the alpha particle is transferred to the gold nucleus through a process called elastic scattering. Elastic scattering occurs when the particles do not stick together after collision and energy is conserved.

The fraction of the alpha particle's kinetic energy transferred to the gold nucleus depends on the masses of the two particles and their velocities. The ratio of the masses of the gold nucleus and the alpha particle is about 50:1, which means that the gold nucleus is much heavier than the alpha particle.

Due to conservation of momentum, the alpha particle's velocity decreases significantly after the collision, while the velocity of the gold nucleus increases slightly. Therefore, only a small fraction of the alpha particle's kinetic energy is transferred to the gold nucleus, which is approximately 0.04% or 1/2500th of the initial energy of the alpha particle.

In summary, when an alpha particle strikes a stationary gold nucleus head-on, only a small fraction of the alpha particle's kinetic energy is transferred to the gold nucleus, which is approximately 0.04%.

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Answer:

The combination of cells in which the negative terminal of a first cell is connected with the positive terminal of second cell and the negative terminal of a second cell is connected to the positive terminal of a third cell and so on is known as series combination of cells.

Explanation:

hope this helps to u

Answer:

Battery.

Answer:

Batteries are systems that store chemical energy and then release it as electrical energy when they are connected to a circuit. Batteries can be made from many materials, but they all share three main components: a metal anode, a metal cathode and an electrolyte between them. The electrolyte is an ionic solution that allows charge to flow through the system. When a load, such as a light bulb, is connected, an oxidation-reduction reaction occurs that releases electrons from the anode while the cathode gains electrons

Explanation:

The speed of the object just after it comes away from the stick at t = 2.74 ms is: 1.36 m/s.

The horizontal force on an object can be calculated using the formula given below:
F = ma
Where, m = mass of the object
a = acceleration of the object

Here, the given force is:
F = at - bt²
Where, a = 1500 N/(ms)
b = 20 N/(ms)²
t = 2.74 ms

We can substitute these values in the given equation to calculate the force:
F = at - bt²
F = 1500 × 2.74 - 20 × (2.74)²
F = 4110 - 155.68F = 3954.32 N

The final velocity of an object can be calculated using the formula given below:
v = u + at
Where, v = final velocity
u = initial velocity
a = acceleration
t = time taken

We know that the object is initially at rest. Therefore, the initial velocity of the object is zero.
u = 0a = F/m = 3954.32/1.67 = 2366.77 m/s²t = 2.74 ms

We can substitute these values in the above equation to calculate the final velocity:
v = u + atv = 0 + 2366.77 × 2.74 × 10⁻³v = 6.4768 m/s

The speed of the object just after it comes away from the stick at t = 2.74 ms is 1.36 m/s (as we are looking for the speed and not velocity, we need to take the magnitude of velocity).

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Pound and Rebka did an experiment of general relativity to test Einstein’s theory. When two identical atomic clocks (one on the ground floor, one on the top floor) were compared, then: B. The clock on the top floor ran a tiny bit slower.

General relativity is a theory of gravity capable of curving and warping space. Albert Einstein claimed that time is relative. It depends on how strong gravity affects it. The further an object is to the ground, the weaker the gravity and the slower the pace of time it experiences. That is why the clock on the top of a building runs a tiny bit slower than on the ground floor.

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Given what we know, we can confirm that less helium is present in the upper atmosphere of Saturn due to Helium precipitation.

On Saturn, helium is able to remain in liquid form, due to many internal and external factors of the planet, this means that helium can form precipitation and rain back down onto the planet. For this reason, it does not stay in the atmosphere for long. This process also produces Saturn's internal energy by releasing gravitational energy in the process.

Therefore, we can confirm that less helium is present in the upper atmosphere of Saturn due to Helium precipitation.

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The solution of Sulfuric Acid (H2SO4) has the following mole fractions:

To solve this problem the formula and the procedure that we have to use is:

Where:

Information about the problem:

We calculate the moles of the H2SO4 and of the H2O from the Pm:

MW = ∑ AWT

MW (H2SO4)= AWT (H) * 2 + AWT (S) + AWT (O) * 4

MW (H2SO4)= (1 g/mol * 2) + (32,064 g/mol) + (16 g/mol * 4)

MW (H2SO4)= 2 g/mol + 32 g/mol + 64 g/mol

MW (H2SO4)=  98 g/mol

MW (H2O)= AWT (H) * 2 + AWT (O)

MW (H2O)= (1 g/mol * 2) + (16 g/mol)

MW (H2O)= 2 g/mol + 16 g/mol

MW (H2O)=  18 g/mol

Having the Pm we calculate the moles of H2SO4:

n = m / MW

n(H2SO4) = m(H2SO4) / MW (H2SO4)

n(H2SO4) = 17.75 g / 98 g/mol

n(H2SO4) = 0.1811 mol

With the density and the volume of the solution we get the mass:

ρ(solution)= m(solution) /v(solution)

m(solution) = v(solution) * ρ(solution)

m(solution) = 100 ml * 1.094 g/ml

m(solution) = 109.4 g

Having the mass of the solution we calculate the mass of the water in the solution:

m(H2O) = m(solution) - m solute (H2SO4)

m(H2O) = 109.4 g - 17.75 g

m(H2O) = 91.65 g

We calculate the moles of H2O:

n = m / MW

n(H2O) = m(H2O) / MW (H2O)

n(H2O) = 91.65 g / 18 g/mol

n(H2O) = 5.092  mol

We calculate the total moles of solution:

total moles of solution = n(H2SO4) + n(H2O)

total moles of solution = 0.1811 mol + 5.092  mol

total moles of solution = 5.2731 mol

With the moles of solution we can calculate the mole fraction of each component:

mole fraction (H2SO4)= moles of (H2SO4) / total moles of solution

mole fraction (H2SO4)= 0.1811 mol / 5.2731 mol

mole fraction (H2SO4)= 0.034

mole fraction (H2O)= moles of (H2O) / total moles of solution

mole fraction (H2O)= 5.092  mol / 5.2731 mol

mole fraction (H2O)= 0.966

In chemistry a solution is known as a homogeneous mixture of two or more components called:

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To correctly integrate signals in a proton spectrum, special acquisition conditions include high signal-to-noise ratio, sufficient spectral resolution, accurate baseline correction, precise pulse calibration, and proper spectral referencing.

The integration of signals in a proton spectrum requires specific acquisition conditions to ensure accuracy. Firstly, a high signal-to-noise ratio is essential. The signal strength should be significantly higher than the noise level to achieve reliable integration. Increasing the signal-to-noise ratio improves the accuracy of peak integration and minimizes the impact of background noise.

Secondly, sufficient spectral resolution is necessary. The spectrum should be acquired with a resolution that allows for the distinction of individual peaks and avoids overlap. Higher resolution enables better separation of peaks, leading to more accurate integration.

Proper baseline correction is another crucial condition. The baseline, representing the signal level in the absence of peaks, must be correctly subtracted or corrected. Baseline distortions or variations can introduce errors in integration, so accurate baseline correction is vital.

Precise pulse calibration is also required. The pulse length and power applied during signal acquisition should be accurately calibrated to ensure consistent and precise excitation of proton spins. Incorrect pulse calibration can lead to signal distortions and affect integration accuracy.

Lastly, proper spectral referencing is important. The spectrum should be referenced to a known reference compound or internal standard. Spectral referencing allows for accurate determination of chemical shift values, which is crucial for peak identification and integration.

By adhering to these special acquisition conditions, such as maintaining high signal-to-noise ratio, sufficient spectral resolution, accurate baseline correction, precise pulse calibration, and proper spectral referencing, the integration of signals in a proton spectrum can be performed correctly, providing reliable and accurate quantitative information about the proton-containing compounds in the sample.

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The wave that is the largest in the electrocardiogram is the R wave.

In electrocardiography, R wave is the most substantial upward deflection in the QRS complex, which is the primary waveform complex that shows ventricular depolarization on an electrocardiogram (ECG). The R wave represents the earliest phase of ventricular depolarization in the cardiac cycle. Furthermore, the amplitude of the R wave varies depending on the individual's heart size, age, and sex, as well as the ECG machine's gain settings. The R wave's normal amplitude varies between 5 and 30 millimeters in a standard ECG recording.

Apart from the R wave, the Q wave and S wave are also part of the QRS complex, which represents ventricular depolarization. The Q wave, which is the first downward deflection after the P wave, is typically small and narrow. The S wave, which is the second downward deflection in the QRS complex, is also typically small and narrow.

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The volume of water inside the tank is approximately 14.3 m^3.

To calculate the volume of water, we use the formula for the volume of a cylinder, which involves multiplying the area of the base (π * radius^2) by the height of the cylinder. By subtracting the depth of the water from the length of the tank, we determine the height of the water level. Plugging the values into the formula, we calculate the volume of water to be approximately 14.3 cubic meters. This represents the amount of space occupied by the water inside the tank. The result is rounded to three significant figures to provide a reasonable level of precision in the measurement.

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The correct answer is(b). There is a physical change from the solid state to a gas state where energy between the molecules increases.

During sublimation, carbon dioxide transitions directly from the solid state (dry ice) to the gas state without passing through the liquid phase. In this process, individual molecules of carbon dioxide gain energy from the surroundings, leading to an increase in their kinetic energy and molecular movement.

As a result, the carbon dioxide molecules separate from each other and form a gas. This phase change is considered a physical change rather than a chemical change since the chemical composition of carbon dioxide remains the same throughout the process.

Therefore, the sublimation of carbon dioxide results in a physical change where the molecules transition from the solid state to the gas state, gaining energy and increasing their molecular movement.

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Answer:

28 will be the right answer I think

Answer:

Because they absorb and emit heat more steadily than land, oceans help moderate temperatures in coastal areas, making winters warmer and summers cooler. Winds that blow in from across the oceans bring more rainfall and higher humidity.

Explanation:

Answer:

1298.5watt

Explanation:

Power is defined as the rate at which work is done

Expressed mathematically as;

P = F × d/ t; F = force or weight of object ;d is height or distance sustain and t is time covered

Hence for 1 person the power consumption is ;

Note weight =mass× acceleration of free fall due to gravity,g

g is known as 9.8m/S2

Time taken is 1min which is 60 sec

60 ×9.8 × 5.3/60 = 51.94 watt

Hence for 25 persons we have

25 × 51.94 =1298.5watt

1.3kilo watt( kilo is 1000)

The work done by the escalator is 3,080.4 joules and the power requirement of the escalator to move 25 passengers every minute is approximately 51.34 watts.

The Work Done is calculated as:

Force (F) = 60 × 9.8

Distance (d) = 5.30 meters

Work (W) = F × d

Work (W) = (60 × 9.8) × 5.30

Work (W) = 3,080.4 joules

The Power is calculated as:

Time (t) = 1 minute

Power (P) = Work / Tim (t)

Power (P) = 3,080.4 / 60

Power (P) = 51.34 watts

Therefore, the power requirement of the escalator to move 25 passengers every minute is approximately 51.34 watts.

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Work done when a 100 lb rock is lifted to height of 3 ft is 9652.215 ft-lb.

The work done on an object is equal to the force applied to it multiplied by the distance over which the force is applied. In this case, the force applied is the weight of the rock, which is equal to the force of gravity acting on it.

The weight of an object is given by the formula:

W = mg

Where m is the mass of the object (in this case, 100 lb) and g is the acceleration due to gravity (approximately 9.8 m/s^2 or 32.17405 ft/s^2).

So the weight of the rock is:

W = (100 lb)(32.17405 ft/s^2) = 3,217.405 ft-lb

The work done on the rock is equal to the force applied (its weight) multiplied by the distance it is lifted (3 ft), so the work done is:

Work = (3,217.405 ft-lb) x (3 ft) = 9652.215 ft-lb

Therefore, the work done when a 100 lb rock is lifted to a height of 3 ft is 9652.215 ft-lb.

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The magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

Given that a racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction).

mass m  = 42g = 42/1000 = 0.042kg

initial velocity before collision u = 7 m/s

It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/s to the left (-x direction). That is,

velocity after collision v = 7 m/s

To calculate the magnitude of the racquetball's change in momentum, we will use the formula below

Change in momentum = Mv - Mu

Since momentum is a vector quantity, we will consider the direction.

Change in momentum = 0.042 x 7 - ( 0.042 x - 7)

Change in momentum = 0.294 + 0.294

Change in momentum = 0.588 kgm/s

Therefore, the magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

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