What is the atomic number of Gold

Answer:

4.7 x 10^14 Hz

Explanation:

From Bohr's theory, the energy absorbed or emitted (ΔE) by an atom transiting from one energy level to another is given as;

ΔE = E4 - E2

Where;

E4 = energy corresponding to the energy level n=4

E2 = energy corresponding to the level n= 2

ΔE = (-2.10 x 10-19) - ( - 5.20 x 10-19)

ΔE =3.1 x 10-19

But

ΔE = hf

h = Plank's constant

f= frequency of photon absorbed

f = ΔE/h = 3.1 x 10-19/6.6 x 10-34

f = 4.7 x 10^14 Hz

In the below equations, (s) indicates the solid phase and (aq) indicates the aqueous phase. When writing balanced chemical equations, it is important to follow the law of conservation of mass. It means that the mass of the reactants must be equal to the mass of the products formed.

The chemical equations for the following reactions occurring in aqueous solutions are:

1. Sodium Carbonate + Calcium Chloride:

Na2CO3 (aq) + CaCl2 (aq) → 2NaCl (aq) + CaCO3 (s)

2. Lead (II) Nitrate + Lithium Chloride:

Pb(NO3)2 (aq) + 2LiCl (aq) → 2LiNO3 (aq) + PbCl2 (s)

3. Iron (III) Chloride + Sodium Hydroxide:

FeCl3 (aq) + 3NaOH (aq) → 3NaCl (aq) + Fe(OH)3 (s)

4. Ammonium Iodide + Silver Nitrate:

NH4I (aq) + AgNO3 (aq) → AgI (s) + NH4NO3 (aq)

5. Barium Nitrate + Aluminum Sulphate:

Ba(NO3)2 (aq) + Al2(SO4)3 (aq) → 2Al(NO3)3 (aq) + 3BaSO4 (s)

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Carbon monoxide, caused by burned gas or diesel fuel, is carried away from the engine by the is exhaust system.

Carbon monoxide (CO) is a byproduct of incomplete combustion of fossil fuels, such as gas or diesel fuel. It is primarily produced in the engine during the combustion process. The exhaust system of a vehicle is responsible for carrying away the combustion gases, including carbon monoxide, from the engine and releasing them outside of the vehicle. The exhaust system typically includes components such as the exhaust manifold, catalytic converter, muffler, and tailpipe. These components work together to safely route the exhaust gases away from the engine compartment and ultimately out of the vehicle, minimizing the exposure to harmful emissions like carbon monoxide.

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The total number of atoms in the mixture containing 0.250 mol of Fe and 1.20 g of C is calculated to be 1.59 x 10^23 atoms.

To determine the number of atoms in the mixture, we follow these steps:

1. Calculate the number of moles of carbon (C) by dividing its mass by its molecular weight. The atomic weight of carbon is 12.011 g/mol, so its molecular weight is also 12.011 g/mol. Therefore, moles of C = 1.20 g / 12.011 g/mol = 0.0999 mol.

2. Use Avogadro's number (6.022 x 10^23 atoms/mol) to convert the number of moles of carbon into the number of atoms. Number of atoms of C = 0.0999 mol x 6.022 x 10^23 atoms/mol = 6.015 x 10^22 atoms.

3. Calculate the number of atoms of iron (Fe) by multiplying the number of moles of Fe (0.250 mol) by Avogadro's number. Number of atoms of Fe = 0.250 mol x 6.022 x 10^23 atoms/mol = 1.505 x 10^23 atoms.

4. Finally, determine the total number of atoms in the mixture by adding the number of atoms of C and Fe. Total number of atoms = 6.015 x 10^22 atoms + 1.505 x 10^23 atoms = 1.59 x 10^23 atoms.

Based on the calculations, the mixture containing 0.250 mol of Fe and 1.20 g of C consists of a total of 1.59 x 10^23 atoms. This value represents the combined number of atoms of carbon and iron present in the mixture.

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Answer:

9.90

Explanation:

Given [H+] = 1.25 x 10^-10 M, we can calculate the pH using the formula:

pH = -log10([H+])

pH = -log10(1.25 x 10^-10)

Using logarithmic properties:

pH = -log10(1.25) - log10(10^-10)

Since log10(10^-10) is equal to -10:

pH = -log10(1.25) - (-10)

pH = -log10(1.25) + 10

Now, evaluating the logarithm using a calculator:

pH = -0.0969 + 10

pH = 9.9031

Therefore, the pH of the solution with [H+] = 1.25 x 10^-10 M is approximately 9.9031. Rounding it to two decimal places, the pH is approximately 9.90.

The value of ΔG° for this reaction is approximately -45.6 kJ/mol.

To find the value of ΔG° for the reaction N₂(g) + 3H₂(g) ⇌ 2NH₃(g), we can use the following equation:

ΔG° = -RT ln(K)

Where ΔG° is the standard Gibbs free energy change (kJ/mol), R is the gas constant (8.314 J/mol⋅K), T is the temperature in Kelvin (25°C = 298K), and K is the equilibrium constant (1.0×10⁸).

ΔG° = - (8.314 J/mol⋅K) × (298 K) × ln(1.0×10⁸)
ΔG° = - (8.314 J/mol⋅K) × (298 K) × 18.42

To convert J to kJ, divide by 1000:
ΔG° = - (0.008314 kJ/mol⋅K) × (298 K) × 18.42
ΔG° ≈ -45.6 kJ/mol

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2,2,4-trimetilpentano is the answer.

Answer:

Explanation: I also have a question if anyone can help in chem please

Answer:

The number of protons in the nucleus of the atom is equal to the atomic number (Z).

The number of electrons in a neutral atom is equal to the number of protons.

Hope it worked

Answer:

The greater Earth's axial tilt angle, the more extreme our seasons are, as each hemisphere receives more solar radiation during its summer

Explanation:

Answer:

Option B, In a space-filling model of a molecule, the radii of the spheres in a space-filling model are proportional in size to the radii of the atoms

they represent

Explanation:

In a space-filling model of a molecule, atoms are represented as sphere. The radius of the sphere is equal to the radius of the atom and the distance between the center of one sphere to the center of other represents the distance between the atomic nuclei

Option B is correct

Option A is incorrect, as dots are used in the space filling model to represent the atoms

Option C is incorrect because radii of atom do not represents the length of the bonds in a space-  filling model

Gas chromatography can be used to tentatively identify a compound from its retention time. D. Retention time.

What is chromatography? Chromatography is a method of separating out chemicals from a mixture by moving them through a material. Chromatography is a popular method for identifying and separating different chemical components in a complex mixture. The working principle of Chromatography is that the components of a mixture are separated based on their ability to adhere to a surface, i.e. the stationary phase, and their capacity to move across that surface, i.e. the mobile phase.

Gas chromatography is a powerful analytical method for the separation and quantitation of organic compounds based on their molecular characteristics. Gas chromatography is an essential method used in analytical chemistry for the qualitative and quantitative analysis of mixtures of substances. In gas chromatography, the components in a mixture are vaporized and then separated based on their distribution between a stationary liquid phase and a mobile gas phase that passes through the stationary phase. Each component is identified based on its retention time, which is the amount of time it takes for the component to travel through the column and reach the detector. Therefore, a compound can tentatively be identified by gas chromatography from its retention time. Answer: D. Retention time.

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Answer:

14660.75 kJ.

Explanation:

We are given from the question above that the pressure inside is represented by this equation:

P = Po + C(1-(D1/D))(D1/D).

Thus, P = 100 + C (1 - 1/4) (1/4). Therefore, P  which is = 400 is;

400 = 100 + C (1 - 1/4) (1/4).

Hence, C = 1600. And the equation can be written as P = 100 + 1600 (1 - (D1/D))(D1/D).

The work done during the entire process, w = (work done during the process 1 to 2) + (work done duringbthe process 2 to 3 ).

Therefore, work done during the process 1 to 2 = P(V2 + V1) = 100( π/6 - 0).

{NB: V2 is gotten from π/6 × D^3. Where D^3 = 1. }

Hence, work done during the process 1 to 2 = 52.36 kJ.

So, the work done duringbthe process 2 to 3 ) is going to be the integration of PdV. Where P = 100 + 1600 (1 - (D1/D))(D1/D) and dV = π/2 D^2 dD. Taking the upper and the lower limit as 4 and 1 respectively.

After the integration (kindly check attached picture for the process) the work done duringbthe process 2 to 3  = 14.61 × 10^3 kJ.  

Therefore, The work done during the entire process, w = (work done during the process 1 to 2) + (work done duringbthe process 2 to 3 ).

The work done during the entire process, w = 52.36 kJ + 14.61 × 10^3 kJ.   = 14660.75 kJ.

11 grams of CO2 must be collected from the reaction in order to infer that the solid that remains is pure tungsten.

A chemical reaction is a process in which reactants react chemically and convert into products by chemical transformation. For example, Respiration – we inhale oxygen which reacts with glucose and produces carbon dioxide, water and energy.

When atoms establish or break chemical bonds, chemical processes take place. Reactants are the substances that begin a chemical reaction, while products are the compounds that are created as a result of the reaction.

Given:

WO3 = 37.0 g

Chemical reaction,

2WO3(s) + 3C(s) ↔ 2W(s) + 3CO2(g)

(37 grams WO3) / (232 grams) = 0.159 moles WO3(0.159 moles WO3) x (3 moles CO2 / 2 moles WO3) = 0.239 moles CO2(0.239 moles CO2) x (44 grams CO2) = 10.5 grams

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Answer:

True. The limiting reagent is the reactant that is completely consumed in a chemical reaction and limits the amount of product that can be formed. The theoretical yield is the maximum amount of product that can be obtained from the limiting reagent, assuming that the reaction goes to completion and no side reactions occur. However, in practice, it is common for side reactions to occur, which can reduce the actual yield of the product. Therefore, while the limiting reagent does control the theoretical yield of a reaction, the actual yield may vary due to the presence of side reactions or other factors that can affect the efficiency of the reaction.

Explanation:

After heating the assembly to 60°C, all the water will evaporate, and no liquid water will be left in the flask.

To determine whether all of the water will evaporate or if some liquid water will remain in the flask, we need to consider the conditions of temperature, pressure, and the vapor pressure of water at that temperature.

The vapor pressure of water increases with heating. At 60°C, the vapor pressure of water is approximately 1493 Pascal (Pa) or 0.0149 atmospheres (atm). If the flask is completely evacuated, the pressure inside the flask is essentially zero. Therefore, the water will tend to evaporate to establish equilibrium with the vapor pressure at that temperature.

However, if the flask remains sealed, the pressure inside the flask will increase as the water evaporates. Eventually, the pressure will reach the vapor pressure of water at 60°C, and the liquid water will stop evaporating.

To determine whether all the water evaporates or not, we need to compare the vapor pressure of water at 60°C with the pressure inside the flask when it reaches equilibrium. If the vapor pressure is higher than the pressure inside the flask, some liquid water will remain.

Given that the flask is evacuated and sealed, the initial pressure inside the flask is essentially zero. If we assume the temperature remains constant at 60°C, all the water will evaporate since the vapor pressure at 60°C (0.0149 atm) is higher than the initial pressure inside the flask.

Therefore, after heating the assembly to 60°C, all the water will evaporate, and no liquid water will be left in the flask.

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Answer:

6.094 j/g°C is the answer

Answer:

A chemical change occurred, a gas and precipitate was produced

Explanation:

From the question , we are informed of science lab, where Cash mixes two clear liquids together in a beaker. Bubbles are produced, and a white solid forms and settles to the bottom.

In this case the change that took place is chemical change ( is one where new product are formed after two substance react) the bubbles that is produced signify the presence of gas in the product, white solid formed is reffered to as a precipitate( which is reffered to as solid that is been formed from a particular solution).

Answer:

inert ; take up electrons

Answer:

The claim is: Therefore Mitosis requires less energy than sexual reproduction does.

Explanation:

Answer:

The answer is

210.6+14.57=225.17mm.

Answer:

Explanation:

0.15 MG +1.15 MG +2.051 MG

the pH of the given buffer solution is 3.08.

The given buffer solution is made up of 60 mL of 0.25 M HCOOH and 10.0 mL of 0.500 M NaXOOH and we are to determine its pH.

The first step in solving this problem is to determine the moles of each species in the buffer. This can be accomplished by using the following equation:

n(HCOOH) = 0.25 moles/L x 0.060 L = 0.015 moles of HCOOHn

(NaXOOH) = 0.500 moles/L x 0.010 L = 0.005 moles of NaXOOH

Next, we need to calculate the concentration of the buffer:

Concentration of buffer = moles of HCOOH / total volume of buffer= 0.015 moles / (0.060 + 0.010) L = 0.1875 M

Now that we have the concentration of the buffer, we can use the Henderson-Hasselbalch equation to determine the pH:

pH = pKa + log ([A-] / [HA])

where pKa = 3.75 for HCOOHpH = 3.75 + log [(0.005 moles / 0.070 L) / (0.015 moles / 0.070 L)]= 3.75 + log [0.07143 / 0.21428]= 3.75 + (-0.6706)= 3.08

Therefore, the pH of the given buffer solution is 3.08.

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A solution containing 1 mol of a strong electrolyte will have a greater effect on the colligative properties of the solution than 1 mol of a nonelectrolyte. A strong electrolyte will dissociate or ionize in an aqueous solution, and therefore the total number of dissolved solute particles is greater for 1 mol of a strong electrolyte than for 1 mol of a nonelectrolyte solute.

An electrolyte is a material that separates into charged ions when it is in contact with water. Cations are positively charged ions. Anions are ions that are negatively charged. A substance that may conduct an electric current when melted or dissolved in water is known as an electrolyte.

A substance is referred to as a strong electrolyte if the physical or chemical process that produces the ions is virtually 100% effective (all of the dissolved molecules give ions). Weak electrolytes are those in which only a very small portion of the dissolved substance goes through the ion-producing process.

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Answer:

Increasing the H+/H3O+ will decrease the pH, while increasing the OH- ions will increase the pH

Explanation:

so pH=-log(H), which means that the smaller H gets to 0, the more the pH rises. The larger the H+ gets, the smaller the pH
if H is 1, then pH is 0
if H is 0.1, then pH is 1
if H is 0.01, then pH is 2
and so on
if H is 0.00000000000001, then the pH is 14
When OH goes up, H goes down, so
if OH is 0.00000000000001, then the ph is 0
if OH is 0.0000000000001, then the pH is 1
and so on
If the OH is 1, then the pH is 14

The concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B].

We use the initial concentration of A and B and the rate constant of the reaction to find the rates at these concentrations. Using the integrated rate law for a second-order reaction, we find the concentration of A after 30 seconds to be 0.0934 M.

Given reaction obeys the rate law, rate=k[A]²[B].

Here, the initial concentration of A= 0.10 M,

initial concentration of B = 0.05 M, and

rate constant, k = 2.0 × 10⁻⁴ M⁻¹s⁻¹

We have to find the concentration of A, after 30 seconds.

To find the concentration of A, we need to know the rate at 0.10 M and 0.05 M. Therefore, we have to calculate the rates at these concentrations.

rate1 = k[A]²[B]

= (2.0 × 10⁻⁴ M⁻¹s⁻¹)(0.10 M)²(0.05 M)

= 1.0 × 10⁻⁷ M/srate2

= k[A]²[B] = (2.0 × 10⁻⁴ M⁻¹s⁻¹)(0.09 M)²(0.04 M)

= 6.48 × 10⁻⁸ M/s

Using the integrated rate law for a second-order reaction: [A] = [A]₀ - kt where [A]₀ = initial concentration of A, k = rate constant, and t = time in seconds.

We know [A]₀ = 0.10 M and k = 2.0 × 10⁻⁴ M⁻¹s⁻¹.

Substituting the values in the above equation, we get: [A] = [A]₀ - kt= 0.10 M - (2.0 × 10⁻⁴ M⁻¹s⁻¹)(30 s)≈ 0.0934 M

Therefore, the concentration of A in the vessel after 30 seconds is 0.0934 M.

This question requires us to calculate the concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B].

We are given the initial concentration of A and B and the rate constant of the reaction. To find the concentration of A after 30 seconds, we need to calculate the rates at the initial concentrations of A and B.

Using the integrated rate law for a second-order reaction, we can find the concentration of A at any given time. We substitute the given values in the formula and solve for [A]. We get the concentration of A as 0.0934 M after 30 seconds. This calculation is based on the assumption that no other reaction is important.

The concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B]. We use the initial concentration of A and B and the rate constant of the reaction to find the rates at these concentrations. Using the integrated rate law for a second-order reaction, we find the concentration of A after 30 seconds to be 0.0934 M. This calculation assumes that no other reaction is important.

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Answer:

Explanation:

The balanced chemical equation is Cl2 + 2KBr → 2KCl + Br2. The amount of bromine is calculated as follows:

11.0 g KBr (1mol KBr/119.002g KBr * 1mol Br2/2mol KBr * 159.808g Br2/1mol Br2= 7.39 g Br2.)

Answer:

C) 0.121 M

Explanation:

HCl + H₂O = H₃O⁺ + OH⁻

.121M              .121M

HCl is a strong acid . It will dissociate almost 100 % so the concentration of acid and hydronium ion formed will be equal . It is to be noted that hydronium ion is formed due to association of H⁺ and H₂O . H⁺ is formed due to ionisation of HCl .

So concentrtion of hydronium ion ( H₃O⁺ ) will be .121 M.

19 ml of a 5m solution of sodium borate must be added to a 200 ml solution of 50mm boric acid in order for the ph to be 9.6

Here pH=Pka-log[A]/[B]

= 9.6=9.24-log[A]/[B]

= log[A]/[B]=-0.36

Here for ml molarity formula is used

Molarity=mass/volume here mass of sodium borate is 381g/mol and volume of solution is 200ml

mass/volume=381/200=1.905/5.0×50=19ml

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