What is the answer of 14.8-4b-(17.1-3b)
the answer choices are:
A. 0.375
B. 3.75
C. 37.5
D. 375​

Answer:

a. 1750; b. 900; c. sean 50%, Adrian = 850/3500= 24.3%, James =25.7%

Step-by-step explanation:

Sean got half = 3500/2 =1750

Adrian = 850

James = 3500-1750-850 =900

ANSWER:

500.5 m²

STEP-BY-STEP EXPLANATION:

To know how much artificial grass should be purchased to cover the athletic field, we must calculate the area corresponding to the figure.

The area of a trapezoid has the following formula:

Where b is the small base, B is the large base and h is the height, we substitute and calculate the area, like this:

It is necessary to purchase the amount of 500.5 m² to be able to cover the athletic field

The lateral surface area is the surface area of the sides of any three dimensional figure. Each figure may have a different base, but the lateral surface area is found the same way. Find the perimeter of the base and then multiply it by the height for any three-dimensional prism.

To identify a sample representing the unhoused populations in Toronto, a researcher should use a stratified random sampling strategy.

Stratified random sampling involves dividing the population into subgroups or strata based on relevant characteristics, and then selecting a random sample from each stratum. In the case of studying the health needs of the unhoused populations in Toronto, stratified random sampling would be appropriate for several reasons: Heterogeneity: The unhoused populations in Toronto may have diverse characteristics, such as age, gender, ethnicity, or specific locations within the city. By using stratified sampling, the researcher can ensure representation from different subgroups within the population, capturing the heterogeneity and reducing the risk of biased results.

Targeted analysis: Stratified sampling allows the researcher to analyze and compare the health needs of specific subgroups within the unhoused population. For example, the researcher could compare the health needs of older adults experiencing homelessness versus younger individuals or examine variations between different ethnic or cultural groups.

Precision: Stratified sampling increases the precision and accuracy of the study findings by ensuring that each subgroup is adequately represented in the sample. This allows for more reliable conclusions and generalizability of the results to the larger unhoused population in Toronto.

Overall, stratified random sampling provides a systematic and effective approach to capture the diversity within the unhoused populations in Toronto, allowing for more nuanced analysis of their health needs.

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At each iteration of a 10-fold cross-validation with a data set of 80 observations, 72 observations are used for training.

In a k-fold cross-validation, the data set is divided into k subsets or folds. Each fold is used as a validation set, and the remaining folds are used for training. The process is repeated k times, with each fold serving as the validation set once.

Given:

Number of observations in the data set = 80

Number of folds in cross-validation (k) = 10

To determine the number of observations used for training at each iteration, we need to calculate the size of each fold.

Number of observations in each fold = Total number of observations / Number of folds

Number of observations in each fold = 80 / 10

Number of observations in each fold = 8

Therefore, at each iteration of the 10-fold cross-validation, 8 observations are used for training.

However, we want to know the total number of observations used for training, so we need to multiply the number of observations in each fold by the number of folds minus one.

Total number of observations used for training = Number of observations in each fold * (Number of folds - 1)

Total number of observations used for training = 8 * (10 - 1)

Total number of observations used for training = 8 * 9

Total number of observations used for training = 72

In a 10-fold cross-validation with a data set of 80 observations, 72 observations are used for training at each iteration.

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The values of determinant ,

\(\left|\begin{array}{ccc}3a&3b&3c\\-d&-e&-f\\4g&4h&4i\end{array}\right| = 72\)

\(\left|\begin{array}{ccc}a&b&c\\2d&2e&2f\\g+3a&h+3b&+3ci\end{array}\right| = - 12\)

The given determinant is,

\(\left|\begin{array}{ccc}a&b&c\\d&e&f\\g&h&i\end{array}\right| = -6\)

This is possible when we take,

a = -1 , e = 1, i = 6, b = c = 1

And d = g = h = 0

The the determinant becomes,

\(\left|\begin{array}{ccc}-1&1&1\\0&1&1\\0&0&6\end{array}\right|\)

Since this is an upper triangular matrix,

Therefore,

Determinant be the product of diagonal element,

Thus,

⇒  -1x1x6 = -6

Now using these values we can calculate the further given determinants,

Q4: Given that,

\(\left|\begin{array}{ccc}3a&3b&3c\\-d&-e&-f\\4g&4h&4i\end{array}\right|\)

Therefore put the values of a, b, c, d, e, f, g, h, and i defined above,

\(\left|\begin{array}{ccc}3(-1)&3(1)&3(1)\\0&-1&-1\\0&0&4(6)\end{array}\right|\)

Therefore, Determinant be,

⇒ -3 x  (-1) x 24 = 72

Hence,

\(\left|\begin{array}{ccc}3a&3b&3c\\-d&-e&-f\\4g&4h&4i\end{array}\right| = 72\)

Q5 : Given determinant is,

\(\left|\begin{array}{ccc}a&b&c\\2d&2e&2f\\g+3a&h+3b&+3ci\end{array}\right|\)

put the values of a, b, c, d, e, f, g, h, and i defined above,

we get,

\(\left|\begin{array}{ccc}-1&1&1\\0&2&2\\-3&3&9\end{array}\right|\)

= -1(12) -1(6) + 1(6)

= -12

Hence, The determinant be

\(\left|\begin{array}{ccc}a&b&c\\2d&2e&2f\\g+3a&h+3b&+3ci\end{array}\right| = - 12\)

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The complete question is attached below:

The total time they will be driving the second day is 8 hours

The total distance they are planning to go  = 900 miles

Distance travelled on first day = 420 miles

Distance yet to be  travelled on second day = Total distance - distance covered = 900 miles- 420 miles= 480 miles

The speed of the car = 60 miles per hour

60 miles of distance covered in time = 1 hour

1 mile of distance covered in time = 1 hour /60 miles = 1 minute

This is solved using Unitary Method

1 hour = 60 minutes

480 miles can be covered in time = 1 minute × 480 miles

                                                         = 480 minute

                                                         =8 hours

Hence, The total time they will be driving the second day is 8 hours

Distance and displacement are two quantities that appear to mean the same thing but have very different meanings and definitions. Distance is defined as "how much ground an object has covered during its motion," whereas displacement is defined as "how far out of place an object is."

Distance is defined as an object's total movement without regard for direction. Distance can be defined as how much ground an object has covered regardless of its starting or ending point.

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Answer:

\(\frac{1}{3}\)

Step-by-step explanation:

(33*3+1 )/3 = 100/3%

Then you need to convert that to decimal by dividing 100

100/300 = 0.3333

which is 1/3 in decimal form

Answer:

mean: 65

median: 9

Step-by-step explanation:

You take all the numbers you have and add them up. Make it simple by adding smaller numbers together. Then once you have the total which is 65 you divide it by the total of numbers you have and then round because after dividing you get 8.125 and the safest way to round is to 9.

Answer:

2

Step-by-step explanation:

i say 2 because you need a controlled variable and then the one subject to change (sorry if not)

Answer: 40 ft by 4 ft

Step-by-step explanation:

See attached picture

False. if you are given a graph with two shif table lines, the correct answer will always require you to move both lines.

In a graph with two shiftable lines, the correct answer may or may not require moving both lines. It depends on the specific scenario and the desired outcome or conditions that need to be met.

When working with shiftable lines, shifting refers to changing the position of the lines on the graph by adjusting their slope or intercept. The purpose of shifting the lines is often to satisfy certain criteria or align them with specific points or patterns on the graph.

In some cases, achieving the desired outcome may only require shifting one of the lines. This can happen when one line already aligns with the desired points or pattern, and the other line can remain fixed. Moving both lines may not be necessary or could result in an undesired configuration.

However, there are also situations where both lines need to be shifted to achieve the desired result. This can occur when the relationship between the lines or the positioning of the lines relative to the graph requires adjustments to both lines.

Ultimately, the key is to carefully analyze the graph, understand the relationship between the lines, and identify the specific criteria or conditions that need to be met. This analysis will guide the decision of whether one or both lines should be shifted to obtain the correct answer.

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Answer:

I believe its 2/3

Step-by-step explanation:

Answer:

42.2

Step-by-step explanation:

4.2×(6÷2+8)-4

Using : "BODMAS" .. principle

first solve the bracket (6÷2+8)

6÷2 =3. and 3+ 8=11

so now we have, 4.2×11-4

now multiplication first, so 4.2 × 11

=46.2

46.2-4= 42.2

This Bay store can also be described as a big box retailer store.

Big Box Retailer

A big box retailer is a physically enormous retail store that is typically a component of a chain of stores (also known as a hyper store, supercenter, superstore, or megastore). By extension, the phrase, big box retailer can also refer to the business that runs the store.

The Bay Store as a Big Box

There are numerous retail chains that only operate in Canada, aside from the large American big box retailer stores like Walmart Canada and the formerly-existent Target Canada. These include places like Hudson's Bay by Home Outfitters, Loblaws by Real Canadian Superstore, Rona, Winners by HomeSense, Canadian Tire by Mark's & Sport Chek, Shoppers Drug Mart, Chapters by Indigo Books and Music, Sobeys, and several others.

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Given:

Distance traveled, d = 398 miles

Average speed, v = 49 miles per hour.

Let's find the time it took you to drive.

To find the time, apply the formula:

Thus, we have:

Therefore, the estimated time it took to drive is 8 hours.

ANSWER:

8 hours.

Answer:

32

Step-by-step explanation:

Answer:

Answer: A). -8 < x < 2

Step-by-step explanation:

\({ \rm{ - 3 <( x + 5) < 7}} \\ \\ { \rm{( - 3 - 5) < x < (7 - 5)}} \\ \\ { \boxed{ \rm{ - 8 < x < 2}}}\)

Step-by-step explanation:

To determine if a system of two equations with two unknowns has infinite solutions using matrices, you can perform Gaussian elimination or row reduction on the augmented matrix of the system. If the reduced form of the matrix is the identity matrix, then the system has a unique solution. If the reduced form is a row of zeros except for the last column, then the system has no solution. If the reduced form has a row with all zeros except for the last column being non-zero, then the system has an infinite number of solutions.

In other words, the system has infinite solutions if the row reduced form of the augmented matrix has a row of the form [0 0 c], where c is a non-zero scalar. This means that there is a non-trivial solution that satisfies the equation, indicating that there are infinitely many solutions.

if the installment option is used, the total amount paid over the 240-month term would be $1,080,000. This includes both the principal amount of $550,000 and the interest accumulated over the repayment period.

To determine the total amount if the installment option is used, we need to calculate the total repayment over the 240-month term.

The installment amount per month is $4,500, and the repayment term is 240 months.

Total repayment = Installment amount per month * Repayment term

Total repayment = $4,500 * 240

Total repayment = $1,080,000

Therefore, if the installment option is used, the total amount paid over the 240-month term would be $1,080,000. This includes both the principal amount of $550,000 and the interest accumulated over the repayment period.

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It is false as the left and right ends of the normal probability distribution extend indefinitely, approaching but never touching the horizontal axis.

The statement is false because the left and right ends of the normal probability distribution do not extend indefinitely. In reality, the normal distribution is defined over the entire real number line, meaning it extends infinitely in both the positive and negative directions. However, as the values move further away from the mean (the center of the distribution), the probability density decreases. This means that although the distribution approaches but never touches the horizontal axis at its tails, the probability of observing values extremely far away from the mean becomes extremely low. Thus, while the distribution theoretically extends infinitely, the practical probability of observing values far from the mean decreases rapidly.

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Answer:

4805.38

Step-by-step explanation:

982×5.47=5371.54

598×78=46,644

5371.54-46644=4805.10

4805.10+28=4805.38

=====================================================

Work Shown:

Your teacher gave you the wrong formula. You should use the nPr formula instead of nCr. This is because order matters when forming passcodes.

For instance, the password 3CJ5 is different from J5C3

For this problem, we have n = 6 different characters and we're selecting r = 4 of them.

\(_n P _r = \frac{n!}{(n-r)!}\\\\_6 P _4 = \frac{6!}{(6-4)!}\\\\_6 P _4 = \frac{6!}{2!}\\\\_6 P _4 = \frac{6*5*4*3*2*1}{2*1}\\\\_6 P _4 = \frac{720}{2}\\\\_6 P _4 = 360\\\\\)

A slightly alternative method is to notice there are 4 slots to fill. Each slot being a digit in the passcode.

For the first slot we have 6 choices. The second has 5 choices since we can't reuse whatever goes in the first slot. We count our way down until all four slots are filled. We then multiply out the values to get

6*5*4*3 = 30*12 = 360

which is the number of permutations where we pick four items from a pool of six total.

To find the expected value of your wait time, we need to multiply the value of each possible outcome by its probability and then add up all the products. In this case, there are two possible outcomes: waiting 3 minutes or waiting 7 minutes.

The probability of waiting 3 minutes is 1/2, and the probability of waiting 7 minutes is also 1/2. Therefore, the expected value of your wait time is:

(3 minutes * 1/2) + (7 minutes * 1/2) = 5 minutes

So, on average, you can expect to wait about 5 minutes for the train.

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Answer:

3 down 2 right

Step-by-step explanation:

A is at Y = 1, A’ is at Y = 4

4-1 = 3

It moved up 3 units.

A is at X = 1, A’ is at x = -1

1 - -1 = 2

It moved to the left 2 units.

The monthly mortgage payment for the family is approximately $4,774.15.

The house price is $1,000,000, and the family makes a 20% down payment, which amounts to $200,000. The remaining amount to be financed through the mortgage loan is $800,000.

To calculate the monthly mortgage payment, we use the formula for a fixed-rate mortgage:

M = P * r * (1 + r)^n / ((1 + r)^n - 1),

where M is the monthly payment, P is the principal loan amount, r is the monthly interest rate, and n is the total number of payments.

First, we convert the annual interest rate to a monthly rate by dividing it by 12: 5% / 12 = 0.0041667.

Next, we calculate the number of monthly payments by multiplying the total number of years by 12: 30 * 12 = 360.

Using the formula, we substitute the values:

M = $800,000 * 0.0041667 * (1 + 0.0041667)^360 / ((1 + 0.0041667)^360 - 1).

Evaluating this expression, we find that the monthly mortgage payment is approximately $4,774.15 for the family.

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In summary, fy(a,b) is the slope of the tangent line to the surface defined by f(x, y) at the point (a, b) in the y-direction.

The given expression represents the partial derivative of f(x, y) with respect to y, evaluated at (a, b):

fy(a,b) = lim┬(y→b)⁡〖[f(a,y) - f(a,b)]/(y - b)〗

Geometrically, this partial derivative represents the slope of the tangent line to the surface defined by f(x, y) at the point (a, b) in the y-direction.

To see why this is the case, consider the following argument:

Let L be the limit in the expression given above.

Let h = y - b be the change in the y-coordinate from b to y.

Then, we can rewrite the limit as:

fy(a,b) = lim┬(h→0)⁡〖[f(a,b + h) - f(a,b)]/h〗

This expression represents the average rate of change of f(x, y) with respect to y over the interval [b, b + h].

As h approaches 0, this average rate of change approaches the instantaneous rate of change, which is the slope of the tangent line to the surface defined by f(x, y) at the point (a, b) in the y-direction.

Therefore, fy(a,b) is the partial derivative of f(x, y) with respect to y, evaluated at (a, b).

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