What is the amount of heat required to complete MELT a 200 gram sample of H2O(s)

The volume of hydrogen gas produced in the reaction of 73 grams of zinc and 73 grams of hydrochloric acid (under normal conditions) is approximately 22.4 liters.

To calculate the volume of hydrogen gas produced in the reaction of zinc and hydrochloric acid, we need to use the principles of stoichiometry and the ideal gas law.

First, let's write the balanced chemical equation for the reaction between zinc (Zn) and hydrochloric acid (HCl):

Zn + 2HCl →\(ZnCl_2\)+ H2

From the equation, we can see that one mole of zinc reacts with two moles of hydrochloric acid to produce one mole of hydrogen gas. To determine the number of moles of zinc and hydrochloric acid, we need to convert the given masses into moles.

The molar mass of zinc (Zn) is approximately 65.38 g/mol, so 73 grams of zinc is equal to:

73 g Zn * (1 mol Zn / 65.38 g Zn) ≈ 1.116 mol Zn

Similarly, the molar mass of hydrochloric acid (HCl) is approximately 36.46 g/mol, so 73 grams of HCl is equal to:

73 g HCl * (1 mol HCl / 36.46 g HCl) ≈ 2.002 mol HCl

According to the balanced equation, the reaction produces one mole of hydrogen gas for every two moles of hydrochloric acid. Therefore, since we have 2.002 moles of HCl, we expect to produce half that amount, or approximately 1.001 moles of hydrogen gas.

To calculate the volume of hydrogen gas, we can use the ideal gas law, which states:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. In this case, we assume the reaction is conducted under normal conditions, which means a pressure of 1 atmosphere and a temperature of 273.15 Kelvin.

Rearranging the equation to solve for V, we have:

V = nRT / P

Substituting the values, we get:

V = (1.001 mol) * (0.0821 L·atm/(mol·K)) * (273.15 K) / (1 atm) ≈ 22.4 L

Therefore, the volume of hydrogen gas produced in the reaction is approximately 22.4 liters.

For more such information on: volume

https://brainly.com/question/29796637

#SPJ8

Answer:

\(210.7~g~MgCO_3\)

Explanation:

We have to start with the reaction:

\(MgCO_3~->~MgO~+~CO_2\)

We have the same amount of atoms on both sides, so, we can continue. The next step is to find the number of moles that we have in the 110.0 g of carbon dioxide, to this, we have to know the atomic mass of each atom:

C: 12 g/mol

O: 16 g/mol

Mg: 23.3 g/mol

If we take into account the number of atoms in the formula, we can calculate the molar mass of carbon dioxide:

\((12*1)+(16*2)=44~g/mol\)

In other words: \(1~mol~CO_2=~44~g~CO_2\). With this in mind, we can calculate the moles:

\(110~g~CO_2\frac{1~mol~CO_2}{44~g~CO_2}=25~mol~CO_2\)

Now, the molar ratio between carbon dioxide and magnesium carbonate is 1:1, so:

\(2.5~mol~CO_2=2.5~mol~MgCO_3\)

With the molar mass of \(MgCO_3\) (\((23.3*1)+(12*1)+(16*3)=84.3~g/mol\). With this in mind, we can calculate the grams of magnesium carbonate:

\(2.5~mol~MgCO_3\frac{84.3~g~MgCO_3}{1~mol~MgCO_3}=210.7~g~MgCO_3\)

I hope it helps!

Answer:

Chemical, Mechanical, and Nuclear Energy

Explanation:

Answer: 5,266

Explanation:

5,266

The heat transfer mechanism through the space between the Sun and the Earth is radiation.

the processes of heat transfer refer to the processes by which heat is transferred from one material to another or from one point to another.

Heat transfer involves the movement of heat from a region or material at a higher temperature to another region or body at a lower temperature.

There are three major processes of heat transfer, and they are:

The process of heat transfer by either conduction or convection requires a material medium through which the heat will travel.

However, heat transfer by radiation does not require a material medium and is responsible for the transfer of heat from the sun through space to the earth.

Learn more about the radiation of heat at: https://brainly.com/question/20493362

#SPJ1

Answer:

true

Explanation:

The volume of the tank is approximately 130.75 m³.

To solve this problem, we need to use the concept of air and water vapor mixture. The given data includes the mass of dry air and water vapor, temperature, and total pressure. We can calculate the specific humidity, relative humidity, and volume of the tank using the following steps:

(a) Specific humidity:

The specific humidity (ω) is defined as the ratio of the mass of water vapor (m_w) to the total mass of the air-water vapor mixture (m_t):

ω = m_w / m_t

Given that the mass of water vapor is 0.17 kg and the total mass of the mixture is 15 kg + 0.17 kg = 15.17 kg, we can calculate the specific humidity:

ω = 0.17 kg / 15.17 kg ≈ 0.0112

So, the specific humidity is approximately 0.0112.

(b) Relative humidity:

Relative humidity (RH) is the ratio of the partial pressure of water vapor (P_w) to the saturation vapor pressure of water (P_ws) at the given temperature, multiplied by 100:

RH = (P_w / P_ws) * 100

To find the relative humidity, we need to determine the saturation vapor pressure at 30°C. Using a vapor pressure table or equation, we can find that the saturation vapor pressure at 30°C is approximately 4.246 kPa.

Given that the total pressure is 100 kPa, the partial pressure of water vapor is 0.17 kg / 15.17 kg * 100 kPa = 1.119 kPa.

Now we can calculate the relative humidity:

RH = (1.119 kPa / 4.246 kPa) * 100 ≈ 26.34%

So, the relative humidity is approximately 26.34%.

(c) Volume of the tank:

To find the volume of the tank, we can use the ideal gas law equation:

PV = nRT

Where P is the total pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to calculate the number of moles of dry air and water vapor in the tank. The number of moles (n) can be obtained using the equation:

n = m / M

Where m is the mass and M is the molar mass.

The molar mass of dry air is approximately 28.97 g/mol, and the molar mass of water vapor is approximately 18.015 g/mol.

For dry air:

n_air = 15 kg / 0.02897 kg/mol ≈ 517.82 mol

For water vapor:

n_water = 0.17 kg / 0.018015 kg/mol ≈ 9.43 mol

Now we can calculate the volume using the ideal gas law:

V = (n_air + n_water) * R * T / P

Given that R is the gas constant (8.314 J/(mol·K)), T is the temperature in Kelvin (30°C + 273.15 = 303.15 K), and P is the total pressure (100 kPa), we can calculate the volume:

V = (517.82 mol + 9.43 Mol) * 8.314 J/(mol·K) * 303.15 K / (100,000 Pa) ≈ 130.75 m³

for more questions on volume

https://brainly.com/question/29796637

#SPJ8

LI Is added an aqueous solution of FeClz Pb(CIO4l2 Ba(OH)2 Ca(NO3h2

An aqueous solutions is one in whichever the solvents is liquidity H2O. That is, solutes (dissolved) ions and molecules are surrounded by water molecules and incorporated into the network of bonds within the water. The dissolves species then spread throughout to the water.

We have with the sum, I is in the questions and we're going to add it and reaction it with another compounds in orders to get a solid-state. So we're asked what that other, what other compounds we should adherence. So if we looking at sustainability rules, things with lithium-ion are always valuables. But I died forms insolubles products with silver Mercury and led to. So if we look at our possible options, you'll noticed that we have a word, two per chlorate. So if we were to add this, where to get lead to iodide and that would be a solid. So with these kinds of problems you're selling due to ability rules would be really helpful for figuring out the what else you could add to make a precipitate.

To know more about aqueous solution click-

https://brainly.com/question/19587902

#SPJ4

Answer:

the image is not clear....

Answer:

\(\Delta S=6045.8\frac{J}{K}\)

Explanation:

Hello,

In this case, we can compute the change in the entropy for vaporization processes in term of the enthalpy of vaporization as shown below:

\(\Delta S=\frac{m*\Delta H}{T}\)

Whereas the temperature is in Kelvins. In such a way, the entropy results:

\(\Delta S=\frac{1.00kg*2256x10^3\frac{J}{kg} }{(100+273.15)K}\\\\\Delta S=6045.8\frac{J}{K}\)

Best regards.

Explanation:

its hard its either B or C i dont wanna be wrong;-;

Answer:

The Juice wouldnt be a metal, Salt isnt that effective in juice if you have sensitive tastebuds. Your answer is C. THe Juice is an acid

Explanation:

The advantage of using telescopes launched into orbit around Earth or sent out into deep space is that the images gathered are usually clearer because they do not have to look through our atmosphere.

What is an atmosphere?

The atmosphere can distort and blur images, making it difficult to observe distant objects with high precision. By placing telescopes in space, scientists can avoid this problem and obtain much clearer and more detailed images of objects in the universe. Additionally, space telescopes can observe a wider range of the electromagnetic spectrum, including ultraviolet and infrared radiation, which are absorbed by Earth's atmosphere.

What is telescopes?

A telescope is an instrument used to observe and study distant objects in space by collecting and focusing electromagnetic radiation. Telescopes can be used to study visible light, infrared radiation, ultraviolet radiation, X-rays, and other forms of electromagnetic radiation. They are important tools in astronomy and have helped scientists make many discoveries about the universe. There are many different types of telescopes, including refracting telescopes, reflecting telescopes, and radio telescopes.

To know more about atmosphere, visit:

https://brainly.com/question/28310375

#SPJ1

Answer:

Your answer is 209 J.

Explanation:

First find △T by subtraction of two temperatures.

△T = 18°C - 13 °C

= 5°C.

Q=mc△t

where,

m= mass.

c = Specific Heat .

t = temperature.

As, Specific Heat capacity of water is 4.18 J/g°C

= 10 × 4.18× 5

= 209 Joules.

When a 10g sample of liquid water increases in temperature from 13°C to 18°C, then the amount of gained energy is 209 joules.

The amount of energy which is gained by any sample will be calculated as:

Q = mcΔT, where

Q = gained energy

m = mass of sample = 10g

c = specific heat of water = 4.18 J/g°C

ΔT = change in temperature = 18 - 13 = 5°C

On putting values we get

Q = (10)(4.18)(5)

Q = 209 Joules

Hence required amount of energy is 209 joules.

To know more about gained energy, visit the below link:

https://brainly.com/question/21704399

We can see that an atom with 14 protons, 14 neutrons, and 16 electrons is unstable, and has a -2 charge.

So the correct option is the third one.

An atom with 14 protons, 14 neutrons, and 16 electrons is not stable. The number of protons in an atom, also known as its atomic number, determines its element and its chemical properties. In this case, the atom has 14 protons, which corresponds to the element silicon (Si) on the periodic table.

For an atom to be stable, it should have a balanced number of protons and electrons. Electrons are negatively charged particles that orbit the nucleus of an atom in energy levels or electron shells. The number of electrons in a stable atom should be equal to the number of protons, resulting in a neutral charge overall.

In this case, the atom has 14 protons and 16 electrons, which means it has two more electrons than protons, resulting in a net charge of -2. This is an example of an ion.

Learn more about atoms.

https://brainly.com/question/17425565

#SPJ1

Answer:

4

Explanation:

water would be produced from 4 molecules of methane (CH4) reacting with 8 molecules of oxygen (O2)

The products of the combustion of hydrocarbon are 4 molecules of carbon dioxide and 8 molecules of water.

A combustion reaction can be described as a reaction that produces fire and takes place at a high temperature. It is an exothermic reaction as well as a redox reaction that usually takes place between a fuel and mostly oxygen gas.

Examples of Combustion Reactions such as during the combustion of 4 molecules of methane reacting with 8 molecules of oxygen gas to give carbon dioxide and two molecules of water.

\(4CH_4 + 8O_2\longrightarrow 8H_2O + 4CO_2\)

Oxygen is the essential reactant for combustion because the combustion is not possible in the absence of oxygen. Complete combustion takes place when a fuel burns completely to produce heat with oxygen and carbon dioxide.

The burning of wood fuels in the presence of air is an example of combustion. The carbon present in wood reacts with oxygen gas in the air to liberate heat and form gaseous products.

Learn more about combustion reaction, here:

brainly.com/question/12172040

#SPJ2

The value of Kp for the given reaction at equilibrium is approximately 192,986.689 L atm mol⁻¹.

To calculate the equilibrium constant Kp for the given reaction, we can use the relationship between Kc and Kp, which is expressed as:

Kp = Kc * (RT)^Δn

Where:

- Kp is the equilibrium constant in terms of partial pressures.

- Kc is the equilibrium constant in terms of concentrations.

- R is the ideal gas constant (0.08206 L atm K⁻¹ mol⁻¹).

- T is the temperature in Kelvin.

- Δn is the change in the number of moles of gas (sum of products - sum of reactants).

In this case, the reaction involves four moles of gas on the left-hand side (reactants) and five moles of gas on the right-hand side (products). Therefore, Δn = 5 - 4 = 1.

Given that Kc = 2367 at 999 K, we can substitute these values into the equation:

Kp = 2367 * (0.08206 L atm K⁻¹ mol⁻¹ * 999 K)^1

Simplifying the expression:

Kp = 2367 * (81.367 L atm mol⁻¹)

Calculating the product:

Kp ≈ 192,986.689 L atm mol⁻¹

Therefore, the value of Kp for the given reaction at equilibrium is approximately 192,986.689 L atm mol⁻¹.

For more questions on equilibrium, click on:

https://brainly.com/question/517289

#SPJ8

Step 1 - Understanding the relation between volume and temperature for a gas sample

There are three main variables that can change the state of a gas sample: temperature, pressure and volume. If the pressure (P) is kept constant, the volume (V) becomes proportional to the temperature (T) in K:

Step 2 - Substituting the values in the equation above

We know, from the exercise, that V1 = 9.02 L and T1 = 585.57 K, and V2=2.24 L. Substituting these values in the equation above:

Answer:

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

Explanation:

We consider the system formed by the molybdenum metal and water as our system, a control mass inside an insulated cup, that is, a container that avoids any energy and mass interactions between system and surroundings.

From statement we notice that metal is cooled down whereas water is heated. According to the First Law of Thermodynamics, we know that:

\(Q_{metal} - Q_{water} = 0\)

\(Q_{metal} = Q_{water}\)

Where:

\(Q_{water}\) - Heat received by water, measured in joules.

\(Q_{metal}\) - Heat released by metal, measured in joules.

Now we expand this identity by definition of sensible heat:

\(m_{metal}\cdot c_{metal}\cdot (T_{m,o}-T) = m_{water}\cdot c_{water}\cdot (T-T_{w,o})\)

The specific heat of the metal is cleared within equation above:

\(c_{metal} = \frac{m_{water}\cdot c_{water}\cdot (T-T_{w,o})}{m_{metal}\cdot (T_{m,o}-T)}\)

If we know that \(m_{water} = 0.237\,kg\), \(m_{metal} = 0.244\,kg\), \(c_{water} = 4186\,\frac{J}{kg\cdot ^{\circ}C}\), \(T_{w,o} = 10\,^{\circ}C\), \(T_{m,o} = 100.10\,^{\circ}C\) and \(T = 15.30\,^{\circ}C\), the specific heat of molybdenum is:

\(c_{metal} = \frac{(0.237\,kg)\cdot \left(4186\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (15.30\,^{\circ}C-10\,^{\circ}C)}{(0.244\,kg)\cdot (100.10\,^{\circ}C-15.30\,^{\circ}C)}\)

\(c_{metal} = 254.119\,\frac{J}{kg\cdot ^{\circ}C}\)

The specific heat of molybdenum is 0.254 joules per gram-Celsius.

Answer:

Approximately \(8.41\) (assuming that the solution is at \(\rm 25^\circ C\), under which \(K_{\rm w} = 10^{-14}\).)

Explanation:

Let \({\rm [H^{+}]}\) and \({\rm [OH^{-}]}\) denote the concentration of \(\rm H^{+}\) and \(\rm OH^{-}\) respectively.

Let \(K_{\rm w}\) denote the self-ionization constant of water. The exact value of \(K_{\rm w}\!\) depends on the temperature of the solution. \(K_{\rm w} =10^{-14}\) at \(\rm 25^\circ C\).

The product of \({\rm [H^{+}]}\) and \({\rm [OH^{-}]}\) in a solution (with \(\rm M\), or moles per liter, as the unit) is supposed to be equal to the \(K_{\rm w}\) value of that solution at the corresponding temperature. In other words:

\({\rm [H^{+}]} \cdot {\rm [OH^{-}]} = K_{\rm w}\).

Rearrange to obtain an expression for \({[\rm OH^{-}]}\):

\(\begin{aligned}{\rm [OH^{-}]} &= \frac{K_{\rm w}}{[\rm H^{+}]}\end{aligned}\).

Assume that the solution in this question is at \(\rm 25^\circ C\) (for which \(K_{\rm w} =10^{-14}\).) For this solution:

\(\begin{aligned}{\rm [OH^{-}]} &= \frac{K_{\rm w}}{[\rm H^{+}]} \\ &= \frac{10^{-14}}{2.6 \times 10^{-6}}\approx 3.85\times 10^{-9}\; \rm M\end{aligned}\).

Hence, the \(\rm pOH\) of this solution would be:

\(\begin{aligned}\rm pOH &= -\log_{10}{\rm [OH^{-}]} \\&\approx -\log_{10} (3.85 \times 10^{-9}) \approx 8.41 \end{aligned}\).

The vapor pressure of butane in the lighter at 25.0 °C is approximately 0.493 atm.

We are given that the boiling point of butane at 1 atm pressure is -1.0 °C, which is equivalent to 272.15 K. At this temperature, the vapor pressure of butane is 1 atm. We are also given that the enthalpy of vaporization of butane is 22.44 kJ/mol and R = 8.314 x 10⁺³ kJ/mol K.

We want to find the vapor pressure of butane at 25.0 °C, which is equivalent to 298.15 K. Substituting these values into the Clausius-Clapeyron equation, we get:

ln(P2/1 atm) = (-22.44 kJ/mol / (8.314 x 10⁻³ kJ/mol K)) * (1/298.15 K - 1/272.15 K)

Solving for P2, we get:

P2 = 1 atm * e⁻²² kJ/mol / (8.314 x 10⁻³ kJ/mol K)) * (1/298.15 K - 1/272.15 K)]

P2 = 0.493 atm

Learn more about pressure on

https://brainly.com/question/28012687

#SPJ1

Answer:

Yes

Explanation:

I doesn't change the substance or the chemical properties of the substance.

Answer:

D

Explanation:

It means entry by force.

\(\\ \sf\longmapsto Density=\dfrac{Mass}{Volume}\)

\(\\ \sf\longmapsto Density=\dfrac{400}{112}\)

\(\\ \sf\longmapsto Density=3.57g/mL\)

Answer:

Cellular respiration uses energy in glucose to make ATP. Aerobic (“oxygen-using”) respiration occurs in three stages: glycolysis, the Krebs cycle, and electron transport.

Explanation:

In glycolysis, glucose is split into two molecules of pyruvate. This results in a net gain of two ATP molecules.

Explanation:

A process where two or more number of miscible liquids present in different fractions are separated by boiling at different temperatures is called fractional distillation.

The sudden decrease in temperature is because the compounds having lower boiling point have completed the distillation before vapor of the higher boiling point can actually fill the distillation head.

The reaction's chemically balanced equation is as follows:3CCl4 + 3N2 + 6H2 = 3CH4 + 3 N2Cl4

The reaction's chemically balanced equation is as follows:3CCl4 + 3N2 + 6H2 = 3CH4 + 3 N2Cl4A chemical reaction that has the same number of moles in the reactant and product sides is said to have a balanced chemical equation.

Determining that the chemical reaction is a balanced chemical equation, it follows the law of conservation of mass.

The missing image, which is included below, shows what the picture represents:

The side that reacts:

Three molecules each of CH4 and N2Cl4

The component side:

6 molecules of H2, 3 molecules each of CCl4, N2, and 3.

Consequently, the following is the reaction's balanced chemical equation:

3CCl4 + 3N2 + 6H2 = 3CH4 + 3 N2Cl4

To learn more about chemically balanced equation refer

https://brainly.com/question/11904811

#SPJ1

Answer:

Following are the difference in homolytic and hetrolytic bond dissociation.

Energy released during Homolytic fission is lower than the Hetrolytic fission as the electron distribution to its fragments is uniform in homolytic whereas electron distribution to its fragments is uniform in hetrolytic fission.

Thus bonds form in hetrolytic fission is more stronger than the the bonds formed in homolytic fission.

Hence, more energy is required to break the bonds of hetrolytic fission as compared to homolytic fission

Thus, homolytic dissociation energy of H-H (104 KJ/mol) is lower than its heterolytic bond dissociation energy (401 KJ/mol)