what is sp hybridisation of carbon

Answer:

- P in PBr3 is +3.

- N in N2 is 0.

- As in H3AsO4 is +5.

Explanation:

Hello!

In this case, since the determination of the oxidation states is performed by using the well-known charge balances, we can proceed as shown below:

- P in PBr3: Here, bromide ions have an oxidation state of -1, so we follow:

\(P^xBr_3^-\\\\x-3=0\\\\x=+3\)

Thus, the oxidation state is +3.

- N in N2: Here, since nitrogen is bonding with nitrogen and it is neutral, we infer its oxidation state is 0.

- As in H3AsO4: Here, oxygen is -2 and hydrogen +1, so we follow:

\(H_3^+As^xO_4^{-2}\\\\3+x-8=0\\\\x=8-3\\\\x=5\)

Thus, the oxidation state is +5.

Best regards!

To balance the equation and identify the type of reaction, let's start by assigning coefficients to each compound: 2H2O + 1SO3 -> 1H2SO4

To balance the equation, we need to ensure that the number of atoms on both sides is the same. Here, we have two hydrogen (H) atoms on the left side and two on the right side, so hydrogen is already balanced.

We have two oxygen (O) atoms on the left side and four on the right side, so we need to balance oxygen by adding a coefficient of 2 in front of the water molecule:

2H2O + 1SO3 -> 1H2SO4

Now the equation is balanced with two hydrogen, four oxygen, and one sulfur (S) atom on both sides.

The type of reaction represented by this equation is a combination or synthesis reaction. In a combination reaction, two or more substances combine to form a new compound. In this case, water (H2O) and sulfur trioxide (SO3) combine to form sulfuric acid (H2SO4).

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The statement that is true of a Lewis base is that a Lewis base donates electron pairs (option A).

A Lewis base is any nucleophylic compound that can donate a pair of electrons and form a coordinate covalent bond.

On the other hand, a Lewis acid is any electrophylic compound that can accept a pair of electrons and form a coordinate covalent bond.

This means that a Lewis base can donate a pair of electrons to a Lewis acid to form a product containing a coordinate covalent bond. This product is also referred to as a Lewis adduct.

Therefore, option A is correct about Lewis base

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The enthalpy of combustion for 1kg of urea is -1223525.84 J/mol.

Urea is a compound that is used in fertilizers and in some plastics.The enthalpy of combustion for urea is the amount of energy that is released when urea is burned. In order to calculate the enthalpy of combustion for 1kg of urea, we need to use the information that is provided to us in the question. Let us start by writing down the balanced equation for the combustion of urea: CO(NH2)2 + 3/2 O2 → CO2 + 2H2O + N2
The balanced equation shows that 1 mole of urea reacts with 1.5 moles of oxygen gas to produce 1 mole of carbon dioxide, 2 moles of water, and 1 mole of nitrogen gas. The enthalpy change for this reaction is equal to the amount of energy that is released when 1 mole of urea is burned.
The heat of combustion (ΔHc) of urea is -632.6 kJ/mol. This means that 632.6 kJ of energy is released when 1 mole of urea is burned. We know that 12g of urea raised the temperature of water by 30°C. We can use this information to calculate the amount of energy that was released when 12g of urea was burned.
The specific heat capacity of water is 4.18 J/g°C. This means that it takes 4.18 J of energy to raise the temperature of 1 gram of water by 1°C. Therefore, it takes 4.18 x 1000 = 4180 J of energy to raise the temperature of 1 kg of water by 1°C.
We know that 12g of urea raised the temperature of water by 30°C. Therefore, the amount of energy that was released when 12g of urea was burned is:
Energy = mass x specific heat capacity x temperature change
Energy = 0.012 kg x 4180 J/kg°C x 30°C
Energy = 1497.6 J
We can now use this information to calculate the enthalpy of combustion for 1kg of urea:
Enthalpy of combustion = energy released / moles of urea burned
Enthalpy of combustion = 1497.6 J / (0.012 kg / 60.06 g/mol)
Enthalpy of combustion = - 1223525.84 J/mol
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Answer:

This question is asking to find the average speed during the dive. The answer is 22m/s.

Explanation:

Average speed of a substance can be calculated knowing it's distance over a particular amount of time.

The formula for average speed is:

Average speed (s) = Distance (d) / time (t)

In the case of this question where A peregrine falcon dives 176 meters through the air in 8 seconds, the distance of the falcon is 176m, while the time is 8s. Hence;

Average speed = 176/8

Average speed = 22

Therefore, the average speed of the falcon diver is 22m/s.

ANSWER

EXPLANATION

Lithium is a group 1 element with an atomic number of 3

At the neutral state, the number of electrons of an atom is equal to the number of protons of an atom.

Since the atomic number is 3, therefore, the number of protons will be 3

recall, the number of protons is equal to the number of electrons

Hence, the number of electrons is 3

Chemical elements of chemical compounds help compensate substances, which are made up of one or more reactants (also known as reactants) and one or more products (also known as products).

Chemical synthesis, or, alternatively, chemical breakdown into two or more separate molecules, occurs when one material reacts with another to create a new substance.These processes are referred to as chemical reactions, and they are typically irreversible barring additional chemical reactions.

An alteration of one or more compounds as one or more unique and fresh substances is referred to as a chemical change or chemical reaction.In those other terms, a chemical is an atomic rearrangement-based chemical process.

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Answer:

im pretty sure the answer is: alpha decay, beta decay, and gamma decay.

Explanation:

Answer:        HHHHHHHHHHHHHHHHHHHHHHAHAHHAHAHHAHHAHHAHHAHHAHAHAHHHAHAHAHHAHAHHA

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Explanation:

Answer:

0 587 mL

Explanation:

First we convert 180 grams of HCl into moles, using its molar mass:

Now we can use the number of moles and the given concentration to calculate the required volume, applying the definition of molarity:

Finally we convert liters into milliliters:

The closest answer is option C, 587 mL.

The volume needed to make an 8.40 M solution of HCl is 0.587 ml.

The correct option is C.

HCl is a strong acid. It is present in our stomach to help in digesting food.

Step1: covert 180 grams into moles

Molar mass of HCl is 36.46 g

\(\dfrac{180 g}{36.46 g/mol } = 4.94\; mol\; HCl\)

Step2: calculate the molarity

\(\rm Molality = \dfrac{mol}{L}\\\\\rm L = \dfrac{4.94 mol }{8.40 M} = 0.588 L\\\)

Covert the liters into ml

\(\dfrac{0.588 L}{1000} = 588 mL\)

Thus, the volume of the solution is 588 ml., nearest is option C, 587 ml.

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Answer:

C) one magnesium and one oxygen

According to the problem the specific heat of the metal is 0.0329 cal/g°C.

Specific heat is the amount of heat energy required to raise the temperature of a unit mass of a substance by one degree. It is usually expressed in units of joules per kilogram-kelvin (J/kg-K). It is an important physical property of a substance that affects the rate of heat transfer.

The specific heat of a metal can be calculated using the equation, q = mcΔT,
where q is the amount of heat energy,
m is the mass of the metal sample,
c is the specific heat, and
ΔT is the change in temperature. In this problem, q = 10.57 g × c × (24.15ºC - 22.50ºC) = 2.85 g × c.
The amount of heat energy required to raise the temperature of the water bath can be calculated using the equation q = mcΔT,
where q is the amount of heat energy, m is the mass of the water bath,
c is the specific heat of water (4.184 J/g°C), and
ΔT is the change in temperature. In this problem, q = 104.0 g × 4.184 J/g°C × (24.15ºC - 22.50ºC) = 86.67 J.
The specific heat of the metal can be calculated by dividing the amount of heat energy required to raise the temperature of the metal sample by the amount of heat energy required to raise the temperature of the water bath. This gives us c = 2.85 g × c / 86.67 J = 0.0329 cal/g°C.
Therefore, the specific heat of the metal is 0.0329 cal/g°C.

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The quantity of morphine, the nurse should administer is 0.3 ml.

Morphine is a drug which comes under the pain relieving drugs.

The quantity of morphine is 0.05 mg/kg

The weight of the baby is 3 kg.

Available morphine is 0.5 mg/mL.

0.05 x 3 = 0.15 mg

then, 0.15 mg / 0.5 = 0.3

Thus, the quantity of morphine, the nurse should administer is 0.3 ml.

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Answer:

hola comoe stas

Explanation:

gracias x los puntos

The half life of the dubnium-261, given that 55 g of it has decayed to 1.72 g after 135 seconds is 27 seconds

To obtain the half life of the dubnium-261, we must first determine the number of half lives that has elapsed. This can be obtained as follow:

2ⁿ = N₀ / N

2ⁿ = 55 / 1.72

2ⁿ = 32

2ⁿ = 2⁵

n = 5

Now, we shall obtain the half-life of the dubnium-261. Details below:

n = t / t½

5 = 135 / t½

Cross multiply

5 × t½ = 135

Divide both sides by 5

t½ = 135 / 5

t½ = 27 secods

Thus, we can conclude that the half-life of the dubnium-261 is 27 seconds

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Answer:

Empirical formula of a compound means that it provides simplest ratio of whole number.

Explanation:

Mass of boron and chlorine is 9.224% and 90.74%

Answer:

0.437

Explanation:

Divide the length value by 1000 to get the answer.

Beta decay is a type of radioactive decay in which a beta ray is emitted from an atomic nucleus, and in this type of decay, one proton in the nucleus is transformed into a neutron and vice versa, therefore for Platinum 201 we have:

201/78 Pt (this is the platinum-201) -> 200/79 Au + antineutrino + electron

This is the formula for a Beta minus decay, where an electron is released

Element w is less reactive than elements x, y, and z. The element with the lower atomic number is typically less reactive.

Element w has an atomic number of 9, element x has an atomic number of 10, element y has an atomic number of 11, and element z has an atomic number of 12. Based on this information, we can conclude that element w is less reactive than elements x, y, and z.

This is because the reactivity of an element is largely determined by the number of valence electrons it has. Valence electrons are the electrons in the outermost shell of an atom that are involved in chemical reactions. Elements with fewer valence electrons are less reactive because they are more stable. Element w has only one valence electron, while elements x, y, and z have two, three, and four valence electrons, respectively.

In general, elements with a full outermost shell of electrons, such as the noble gases, are the least reactive because they are highly stable. Elements that are close to having a full outermost shell, such as element w, are also relatively stable and less reactive. On the other hand, elements with only a few valence electrons, such as the alkali metals, are highly reactive because they are trying to gain or lose electrons in order to achieve a full outermost shell.

Overall, the reactivity of an element is determined by its electronic structure, with elements having fewer valence electrons generally being less reactive than those with more. In the case of the elements w, x, y, and z, we can see that element w has the fewest valence electrons and is therefore the least reactive.

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Answer: They are versatile and perform a variety of tasks.

Explanation:

Answer:

may I know the directions?

Explanation:

pls put a deroction

a. 2-methyl-2-propanol

b. 2-butene 1-ol

c. 3-methyl 2-butanol

d. 3-methyl 2-pentanol

strontium sulfate (s) + lithium iodide (aq)  →  strontium iodide (aq) and lithium sulfate (aq).

The reaction between strontium sulfate (SrSO4) and lithium iodide (LiI) can be represented by the following balanced chemical equation:

SrSO4 (s) + 2 LiI (aq) → SrI2 (aq) + Li2SO4 (aq)

In this reaction, strontium sulfate (SrSO4) in its solid state reacts with lithium iodide (LiI) in its aqueous state to produce strontium iodide (SrI2) and lithium sulfate (Li2SO4), both in their aqueous forms. The reaction can be understood by examining the ionic compounds involved. Strontium sulfate dissociates into strontium ions (Sr2+) and sulfate ions (SO4^2-), while lithium iodide dissociates into lithium ions (Li+) and iodide ions (I^-). The ions then rearrange to form the products, with strontium combining with iodide to form strontium iodide, and lithium combining with sulfate to form lithium sulfate. It's important to note that this reaction occurs in an aqueous solution, indicating that lithium iodide is dissolved in water. The solid strontium sulfate reacts with the aqueous lithium iodide to produce the aqueous products. This reaction demonstrates the chemical combination of the ions present in strontium sulfate and lithium iodide to form different ionic compounds.

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Answer:

[Ar]4s2

Explanation:

Here are the electron configurations for calcium (Ca) and promethium (Pm) in noble gas notation:

Calcium (Ca):

1s2 2s2 2p6 3s2 3p6 4s2

Or in noble gas notation:

[Ar] 4s2

The electron configuration starts with a full 1s orbital, then a full 2s orbital and 2p subshell.

Then the 3s orbital is full and 3p orbital is full, matching the electron configuration of argon. Thus we write [Ar].

After the noble gas core, the next electron go into the 4s orbital, so we write 4s2.

Promethium (Pm):

1s2 2s2 2p6 3s2 3p6 4s2 3d1 4p6 5s2 4d1 6s2

Or in noble gas notation:

[Xe] 6s2 4f4

The electron configuration is similar up to argon.

After the argon core, the electrons fill the 4s and 3d orbitals, then the 4p.

The electron configuration then matches that of xenon, so we write the xenon core as [Xe].

The remaining electrons go into the 6s and 4f orbitals, shown after the noble gas core.

In summary:

Calcium electron configuration in noble gas notation:

[Ar] 4s2

Promethium electron configuration in noble gas notation:

[Xe] 6s2 4f4

The electron configuration in noble-gas notation for Ca (Calcium) is [Ar] 4s2, while for Pm (Promethium), it's [Xe] 6s2 4f5.

The electron configuration of an atom presents the distribution of electrons in atomic orbitals. It's helpful when understanding its atomic structure and chemical behavior.

For the element Ca (Calcium), which is atomic number 20, the noble gas prior to it on the periodic table is [Ar] (Argon). So, the electron configuration in noble-gas notation for Ca is [Ar] 4s2.

For Pm (Promethium), atomic number 61, the closest noble gas is [Xe] (Xenon), thus the notation starts with [Xe]. Pm falls in the 6th period, f-block, therefore following [Xe], the notation should be [Xe] 6s2 4f5.

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Answer:

calculate the ray diagram of image formed by convex lens having focal length 2cm if lighting candle is placed 4cm away from lens also calculate the mangnification of lens

Answer:

Since the equation for amount remaining is (1/2)^n, where n stand for the number of half lives, after 2.3 half lives the equation is (1/2)^2.3. This makes the answer about   1/4.92, which converts to about 20% of the original amount.

Explanation:

Since the equation for amount remaining is (1/2)^n, where n stand for the number of half lives, after 2.3 half lives the equation is (1/2)^2.3. This makes the answer about   1/4.92, which converts to about 20% of the original amount.

Answer:

C.) No, because the Moon reflects most of the Sun's light rather than

absorbing it

Explanation:

:p

Answer:

Your bones and muscles work together to support and move your body. Your respiratory system takes in oxygen from the air. ... Your circulatory system carries oxygen, water, and nutrients to cells throughout your body. Wastes from the cells are eliminated by your respiratory system, your excretory system, and your skin.

Explanation:

Answer:

among these which is not a base is CaSO4

Answer:

\(\% m=40.46\%\)

Explanation:

Hello there!

in this case, according to the given information, it turns out firstly necessary for us to write up the chemical equation as shown below:

\(BaCl_2+Na_2SO_4\rightarrow BaSO_4+2NaCl\)

Thus, we calculate the mass of BaCl2 stoichiometrically related to the produced 1.658 g of precipitate in order to discard it from the sample:

\(m_{BaCl_2}=1.658gBaSO_4*\frac{1molBaSO_4}{233.38 gBaSO_4} *\frac{1molBaCl_2}{1molBaSO_4}*\frac{208.23 gBaCl_2}{1molBaCl_2}\\\\m_{BaCl_2}=1.479gBaCl_2\)

Thus, the mass percentage is calculated as shown below:

\(\% m=\frac{1.479g}{3.656g}*100 \% \\\\\% m=40.46\%\)

Regards!