what is science and why do we study science and what are the benefits we are going to get from it ?​

The Magnus effect can not be observed in skiing.

Magnus' effect: When there is relative motion between the spinning body and the fluid, a sideways force is generated on a rotating cylindrical or spherical solid immersed in the fluid (liquid or gas). The effect, bears the name H.G. Magnus Phenomenon, after the German scientist and chemist who first experimentally explored the effect in 1853.

The ball is pushed higher into the air by the Magnus Effect, which has an equal-and-opposite effect to the friction between the air and the ball.

A deflection in the direction perpendicular to the spinning axis and the velocity vector results from the spinning. Tennis players frequently use top or backspin when striking the ball.

When a fastball has a backspin, the upward Magnus Effect works against gravity to keep the ball in the air longer. When a curveball has topspin, however, the downward Magnus Effect works in favor of gravity to shorten the baseball's flight.

In skiing, there is no Magnus effect

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In which of these sports can one not observe the Magnus effect?

a) Baseball

b) Tennis

c) Basketball

d) Skiing

Answer:D

Explanation:

the energy transmission of a cell phone is best explained by a wave model

Answer:

1.4 kJ/s

Explanation:

See attached photo

Answer:

Approximately \((-1.6 \times 10^{5}\; \rm J)\) (assuming that the car was on level ground.)

Explanation:

When an object of mass \(m\) is moving at a speed of \(v\), the kinetic energy of that object would be \((1/2) \, m \cdot v^{2}\).

Initial kinetic energy of the car:

\(\begin{aligned}&\frac{1}{2}\, m \cdot v^{2} \\ &= \frac{1}{2}\times 1120\; \rm kg \times (17\; \rm m \cdot s^{-1})^{2} \\ &\approx 1.6\times 10^{5}\; \rm J \end{aligned}\).

After the car comes to a stop, the kinetic energy of this car would be \(0\; \rm J\) because the car would not be moving.

Change to the kinetic energy of the car: \(\text{Final KE} - \text{Initial KE} = -1.6 \times 10^{5}\; \rm J\).

If the car is traveling on level ground, friction would be the only force that contributed to this energy change. Hence:

\(\text{Work of friction} = \text{Energy change} = -1.6\times 10^{5}\; \rm J\).

The value of the work that friction did is negative. The reason is that at any instant before the car comes to a stop, friction would be exactly opposite to the direction of the movement of the car.

The work of a force on an object is the dot product of that force and the displacement of that object. The dot product of two vectors of opposite directions is negative. Hence, in this question, the work that friction did on the car would be negative because the friction vector would be opposite to the movement of the car.

The stream's velocity is 1.75 metres per second, and the discharge is 16.8 cubic metres per second.

Discharge has units of feet3/sec or cubic ft per second if length and duration are measured in feet and seconds, respectively (cfs). The cross-sectional area is calculated as Depth times Width. Due to the velocity reduction caused by friction at the channel's edges, the channel's form is crucial.

The cross-sectional area of the stream must be multiplied by the stream velocity in order to determine discharge.

The cross-sectional area of the image is:

A = (8 m) x (1.2 m) = 9.6 m²

1.75 metres per second is listed as the stream velocity.

So the discharge Q is:

Q = A x V

= (9.6 m²) x (1.75 m/s)

= 16.8 m³/s.

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The 1500 N force would need to act in the direction opposite the train car's movement, so if we take the current direction it's moving in to be positive, we have by Newton's second law

-1500 N = (15,000 kg) a   →   a = -0.10 m/s²

If t is the time it takes for the train to come to rest, then

-0.10 m/s² = (0 - 5.4 m/s) / t

t = (5.4 m/s) / (0.10 m/s²)   →   t = 54 s

To determine how many milliliters the patient need each meal we can use a rule of three:

then:

Hence the patient need 8 mL each meal; since the patient eats three meals per day he needs a total 24 mL per day of the medication.

Answer:

Explanation:

How much force is acting on a certain area

Answer:

Explanation:

Have y’all seen steeleflag19 at all on here?

Granite will heat up the quickest among dry soil, granite, water, and wet soil due to its lower specific heat capacity.

To determine which substance will heat up the quickest among dry soil, granite, water, and wet soil, we need to consider their specific heat capacities. The substance with the lowest specific heat capacity will heat up the quickest.

Specific heat capacity is defined as the amount of heat energy required to raise the temperature of a substance by a certain amount. Different substances have different specific heat capacities due to variations in their molecular structure and composition.

Water has a relatively high specific heat capacity of about 4.18 J/g°C, meaning it requires a significant amount of heat energy to raise its temperature. Dry soil and granite, on the other hand, have lower specific heat capacities compared to water.

Wet soil is a mixture of dry soil and water, and its specific heat capacity will lie between the values of dry soil and water. Since water has a higher specific heat capacity than dry soil, wet soil is expected to have a higher specific heat capacity than dry soil as well.

Therefore, based on the comparison of specific heat capacities, the substance that will heat up the quickest is granite. Granite has a lower specific heat capacity than water and wet soil, making it more susceptible to temperature changes. Dry soil and wet soil, including water, will heat up at a slower rate compared to granite.

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Answer:

C6H12O6 is the final product of Calvin cycle light independent reactions

Explanation:

* steps in Calvin cycle

: carbon fixation

: reduction

: regeneration

for C6H12O6 it requires 2 molecules of PGAL or G3P

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The statement that describes the net force on an object is the sum of all forces acting on an object (option A).

Net force is sum of all forces acting on an object in a single plane.

When a force is applied to a body, not only is the applied force acting, there are many other forces like gravitational force, frictional force and the normal force that balances the other force.

The sum of all these forces acting on the object whether in the same or opposite direction is regarded as the net force.

Therefore, the statement that describes the net force on an object is the sum of all forces acting on an object.

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Answer:

AS USUAL SHE DID NOT TAKE PART

I’ll never forget what’s her name

A PE teacher and ogre she became

For I was such a sickly child

it really made this ogre wild

Held in my hand a medical certificate

exempted from all things physical

with Rheumatic Fever and St Vitus’ Dance

for me to take part ~ there was no chance

Instead I assisted the Deputy Head

with clerical duties I helped him instead

But clearly this really annoyed her

As she gave me her evil stare

She appeared to be looking right through me

No words were spoken ~ was I even there

Each and every year she wrote

inside my school report

A snide remark that ended with

“as usual she did not take part”

For I was told such illnesses

Could leave me with a weakened heart

And so upon Doctor’s orders

in PE I was not to take part

I can still see her face

As she filled me with fear

No compassionate words

from her lips I could hear

Whilst illnesses kept me off school for a year

It’s time I let go of this nasty so and so

For she left planet Earth a long time ago

And my heart ~ it still beats

I’m so glad to be here

With a smile on my face

I have no one to fear

Answer:

Explanation:

Physical education is important because it keeps you healthy and living longer

Answer:

The final area of the plate is 4.0000352 \(m^2\) if the temperature raised to 100 °C and the coefficient of linear expansion of iron is 1.1 x 10-7.

Expecting that the plate of iron is rectangular, we can involve the recipe for warm extension of solids to compute the last region of the plate. The equation for direct warm development is given by ΔL = αLΔT, where ΔL is the adjustment of length, α is the coefficient of straight extension, L is the first length, and ΔT is the adjustment of temperature.

Since the region of the plate is given by A = L*W, where L is the length and W is the width, we can involve the equation for straight warm extension to compute the adjustment of length of the plate and afterward use it to compute the last region.

ΔL = αLΔT = \((1.1 x 10^-7 m/oC)(2 m)(80 oC) = 1.76 x 10^-5 m\)

The last length of the plate is L + ΔL = 2 m + 1.76 x \(10^-5\) m = 2.0000176 m (approx.)

The last width of the plate is thought to be unaltered as it isn't impacted by the adjustment of temperature.

Thusly, the last region of the plate is A = L*W = (2.0000176 m)(2 m) = 4.0000352 \(m^2\) (approx.)

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The maximum width of the slit (in nm) for which no diffraction minima are observed is 569 nm.

The maximum width of the slit (in nm) for which no diffraction minima are observed is calculated by applying the following equation.

sinθ = mλ/a

where;

Substitute the given parameters and solve for the maximum width of the slit (in nm) for which no diffraction minima are observed.

sin(90) = (1 x 568.7 nm) / a

1 = (568.7 nm) / a

a = (568.7 nm) /1

a = 568.7 nm

to the closest integer = 569 nm

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Answer:

A high EQ (emotional intelligence)

In today's transitioning workplace, having a high EQ is the most important trait of a good boss. Bosses must be able to discern between their own personal beliefs and the thoughts and beliefs of others, and other generations (boomers, Gen X, xennials, millennials and now Gen Z).

Explanation:

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Boron

Sillicon

Germanium

Arsenic

Antimony

Tellurium

Pelorium

Metallic characteristics: lustrous, solid at room temperature

In-between characteristics: semiconducting, amphoteric

Nonmetallic: brittle

It is reasonable to conclude that science teachers generally agree that practical science is beneficial. Therefore, option (A) is correct.

Practical science refers to hands-on activities, experiments, and applications of scientific concepts in real-world settings. Science teachers, who are experts in their field and experienced in teaching science, understand the importance of practical science in facilitating students' understanding, engagement, and application of scientific principles.

Practical science allows students to develop critical thinking, problem-solving, and inquiry skills, as well as promoting a deeper understanding of scientific concepts. It also fosters curiosity, creativity, and a passion for science, making it an effective and essential component of science education.

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Answer:

A

Explanation:

One of the main benefits of informational interviewing is that it allows the person conducting the interviews to gain insights and information about a particular career or industry.

Given,

diameter of the circle, d=0.9 mm=0.9×10⁻³ m

The radius is given by,

Therefore the radius of the circle is,

The area of the circle is given by,

On substituting the know values,

Therefore the area of the circle is 6.36×10⁻⁷ m ²

\( \huge\fbox\red{Lean}\ \)

\( \small\mid{ \underline{ \overline{ \tt \: －ɪƭ'ꜱ \: ʙᴙᴜᴛᴀʟ \: σʋʇ \: ɦэŗǝ}} \mid} \)

Answer:

\(lean \: is \: the \: measure \: of \: fat \\ you \: can \: remembar \: by \: using \\ \: the \: term \: lean \: meat \: usually \: used \: to \: \\ eat \\ thank \: you\)

ANSWER:

STEP-BY-STEP EXPLANATION:

1)

For the case of m1, the force scheme would be like this:

We do the summation of force in each direction:

Answer:

Pretty sure its D.

radiation, chemotherapy, and bone marrow transplant

Explanation:

Radiation, chemotherapy, and bone marrow transplant are the typical treatment for Hodgkin's disease. Therefore, option (D) is correct.

Hodgkin lymphoma can be described as a type of lymphoma, in which cancer forms from a specific type of white blood cell known as lymphocytes, where multinucleated Reed-Sternberg cells are present in the lymph nodes.

The most common symptom of Hodgkin's lymphoma is the painless enlargement of lymph nodes. Hodgkin lymphoma can be treated with radiation therapy, chemotherapy, and stem cell transplantation. The treatment generally depends on how advanced cancer has favorable features.

Radiation and chemotherapy drugs increase the risk of other cancers, lung disease, or heart disease over the subsequent decades.

Hodgkin lymphoma can be distinguished from non-cancerous causes of lymph node swelling and from other cancer. Definitive diagnosis is by lymph node biopsy. Blood tests are performed to assess the function of major organs and safety for chemotherapy.

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Answer:

1- 66mL

2-16mL

3-7.8mL

Explanation:

they are numbered from left to right, and have the number of the values. Dont forget the measurements, because sometimes if they are forgotten, they are counted wrong.

Answer: a rubber band

Explanation: A rubber band has no conductivity and no electricity would be able to flow whereas steel and copper and aluminum would be able to allow electricity to flow due to how they are built