what is reduced and oxidized in the following reaction? 3 h2s (aq) 2 h (aq) 2 no3−(aq) → 3 s(s) 2 no(g) 4 h2o (ℓ)

Answer:

Explanation:

Ground state electron configuration of potassium (K) is 1s2 2s2 2p6 3s2 3p6 4s1. The valency of the element is determined by electron configuration in the excited state. This electron configuration shows that the last shell of the potassium atom has an unpaired electron (4s1). So the valency of potassium is 1.

Answer :position

Explanation:

Potential energy is the energy stored in an object due to its position

150  more liters of water does Ian drink than Farida.

Ian drinks = 278 liters

Farida drinks = 128 liters

Ian drink than Farida = 278-128 =150  liters .

We only have a three to five day survival time without fluids because approximately 60% of our body is made up of water .Addition to cleaning out waste and controlling body temperature, transporting nutrients, and being essential for digestion, water serves many other crucial tasks in the body.

small molecule of water. There are three hydrogen atoms and one oxygen atom in it. Hydrogen bonding, a force, is responsible for the adhesion of water molecules. Water is capable of incredible feats because of it.

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Answer: 1 5/8

Explanation:

Y-ray photons with a wavelength of 2.45×10-5 nm.  energy of photon is 8.11 × 10⁻¹²J.

given data is as follows :

wavelength = 2.45 × 10⁻⁵ nm

energy of photon is given by  the following formula , we get :

E = hf

where E = energy of photon

h = Planck constant = 6.63 × 10⁻³⁴ j.s

f = frequency

and frequency = c / λ

the formula will be:

E = h c / λ

c = speed of light = 3 × 10⁸ m/s

E = (6.63 × 10⁻³⁴ × 3 × 10⁸ ) / 2.45 × 10⁻⁵ × 10⁻⁹

E = 8.11 × 10⁻¹²J

Thus, Y-ray photons with a wavelength of 2.45×10-5 nm.  energy of photon is 8.11 × 10⁻¹²J.

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Answer: It is the number in the upper left (atomic number).

Explanation: The atomic number is normally the number of protons. I hope this helps.

Answer:

Objects with a higher density than the substance it is submerged in will sink. Objects with a lesser density than the substance it is submerged in will float. Sugar substitute is less dense than water and sugar or high fructose corn syrup is denser than water.

Explanation:

The oxide of the metal with the highest charge and smallest ionic radius is expected to have the greatest lattice energy.

Among the given options, the metal with the highest charge is beryllium (Be2+), which has a charge of +2. Beryllium also has a small ionic radius, meaning its ions are closely packed together. As a result, the oxide of beryllium (BeO) is likely to have the greatest lattice energy. Lattice energy is a measure of the energy released when gaseous ions come together to form a solid lattice structure. It is influenced by the magnitude of the charges on the ions and the distances between them. Higher charges and smaller ionic radii result in stronger attractions between ions, leading to higher lattice energy.

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The production of aluminum by the electrolytic reduction of alumina involves the oxidation of graphite at the anode, which produces carbon dioxide (CO2) gas. In order to calculate the mass of graphite that must be consumed to produce 1000 kg of aluminum, we need to use the stoichiometry of the reaction.

The balanced chemical equation for the reaction is:

2 Al2O3 + 3 C → 4 Al + 3 CO2

This equation tells us that for every 3 moles of graphite (C) consumed, we can produce 4 moles of aluminum (Al). We can use this information to calculate the amount of graphite required to produce a given amount of aluminum.To start, we need to determine the number of moles of aluminum in 1000 kg of the metal. The molar mass of aluminum is 26.98 g/mol, so:

1000 kg Al × (1000 g/kg) ÷ (26.98 g/mol) = 37,051.5 mol A

Next, we can use the stoichiometry of the reaction to determine the number of moles of graphite required to produce this amount of aluminum. For every 4 moles of Al produced, we need 3 moles of C:

37,051.5 mol Al × (3 mol C/4 mol Al) = 27,788.6 mol C

Finally, we can convert the number of moles of graphite to mass, using the molar mass of carbon (12.01 g/mol):

27,788.6 mol C × 12.01 g/mol = 333,391 g or 333.4 kg

Therefore, approximately 333.4 kg of graphite must be consumed in order to produce 1000 kg of aluminum by the electrolytic reduction of alumina.

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Answer:

d

Explanation:

The train will travel for 2 hours to travel a distance of 100 miles with a speed of 50m/h. Therefore, option (C) is correct.

The speed of a body is defined as the rate of change in the position of a body w.r.t. time.

Speed is a scalar parameter with both magnitude and no direction. A simple mathematical formula common way to determine speed.  

S = d / t

where S is the speed, d is the distance moved by a body and t is the time.

Although the SI unit for speed is the same as velocity is m/s and can also be expressed in miles per hour (mph), and kilometers per hour (kph).

Given, the distance traveled by train, d = 100 miles

The time taken by train = 2 hrs

The speed of the train = distance/ time = 100/2 = 50m/h

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Yes, the solubility information provided in the graph can be summarized as follows:

In summary, the solubility of barium nitrate (Ba(NO₃)₂) increases with temperature, with higher temperatures allowing for more solute to dissolve in the solvent (water).

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Answer:

octet rule

Explanation:

The notation for the enthalpy of the solution is ∆Hsol. The correct answer is option ∆Hsol.

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Answer:

D.

Explanation:

The valence electrons are located in the outermost shell.

C3 plants' leaves don't have Kranz anatomy. During cellular respiration, electrons that have lost their energy are transferred to the an inorganic molecule. Here, photosynthesis takes place after the stomata.

Plants use glucose as a source of energy and to create other compounds like starch and cellulose. Cell walls are constructed using cellulose. As a food source, starch is kept in seeds or other plant parts.

During photosynthesis, plants take up water (H2O) or co2 (CO2) from environment and the soil. In the plant cell, carbon dioxide is reduced, meaning means it gets electrons, whereas water is oxidised, meaning means it loses electrons. As a result, carbon dioxide is transformed into glucose and water into oxygen.

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Based on Lana's diagram, the correct statement that explains the results of asexual reproduction is C. The offspring are genetically identical to the parent, because each offspring receives a complete copy of a single parent's chromosomes.

In the diagram, the parent cell divides into two identical daughter cells, each of which contains a complete copy of the parent cell's genetic material.

This type of reproduction, where a single parent produces offspring that are genetically identical to itself, is called asexual reproduction. It is the process by which many unicellular organisms, such as bacteria and some protists, reproduce.

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Answer:

0.74 atm.

Explanation:

From the question given above, the following data were obtained:

Pressure of Ne (Pₙₑ) = 1.52 atm

Pressure of He (Pₕₑ) = 766 mmHg

Total pressure (Pₜ) = 3.27 atm

Pressure of Ar (Pₐᵣ) =?

Next, we shall convert the pressure of He from mmHg to atm. This can be obtained as follow:

760 mmHg = 1 atm

Therefore,

766 mmHg = 766 mmHg × 1 atm / 760 mmHg

766 mmHg = 1.01 atm

Finally, we shall determine the partial pressure of Ar. This can be obtained as follow:

Pressure of Ne (Pₙₑ) = 1.52 atm

Pressure of He (Pₕₑ) = 1.01 atm

Total pressure (Pₜ) = 3.27 atm

Pressure of Ar (Pₐᵣ) =?

Pₜ = Pₙₑ + Pₕₑ + Pₐᵣ

3.27 = 1.52 + 1.01 + Pₐᵣ

3.27 = 2.53 + Pₐᵣ

Collect like terms

3.27 – 2.53 = Pₐᵣ

Pₐᵣ = 0.74 atm

Thus the partial pressure of Ar is 0.74 atm.

The number of water molecules (H₂O) can be produced from 6 molecules of hydrogen gas (white) reacting with 6 molecules of oxygen gas (red) is 6 molecules.

The balanced chemical equation for the reaction between hydrogen and oxygen to form water is:

2H₂ + O₂ → 2H₂O

From this equation, we can see that 2 molecules of hydrogen (H₂) react with 1 molecule of oxygen (O₂) to form 2 molecules of water (H₂O).

Therefore, if we have 6 molecules of hydrogen gas and 6 molecules of oxygen gas, we can use stoichiometry to determine how many molecules of water will be produced.

6 molecules of H₂ = 6 x 2 = 12 hydrogen atoms

6 molecules of O₂ = 6 x 2 = 12 oxygen atoms

Since the ratio of hydrogen to oxygen in the reaction is 2:1, we have enough oxygen atoms to react with only 6 of the hydrogen atoms. This means that 6 molecules of water will be produced.

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Conclusion call the organized steps taken to answer a scientific problem.

The Scientific Method is defined as a logical and rational order of steps through which scientists come to conclusions related to the world around them. The Scientific Method helps in the organization of thoughts and procedures by which the scientists are in confident in the answers they find.

OBSERVATION is considered as the first step through which they get to know how they want to go about your research.

HYPOTHESIS is the step in which we think hypothetical means about the answer which we have to find.

PREDICTION is our specific belief about our scientific idea:like, If my hypothesis is true, then I predict we will discover this.

EXPERIMENT is defined as the tool that we invent to answer our question.

CONCLUSION is the answer which our experiment gives.

Thus, we concluded that the Conclusion call the organized steps taken to answer a scientific problem.

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The general shape of a diprotic acid with Ka1 >> Ka2 is a steep decline followed by a gradual decline, while a diprotic acid with Ka1 ≈ Ka2 shows a gradual decline followed by a steeper decline. In the case of a triprotic acid with Ka1 >> Ka2 >> Ka3, the curve consists of three gradual declines representing each neutralization step.

In a. The general shape of the curve for a diprotic acid with Ka1 >> Ka2 is a steep decline followed by a gradual decline. To determine pKa1, titrate the acid with a strong base, and pKa1 is the pH at the midpoint of the first equivalence point.

To determine pKa2, titrate the acid with a strong base after fully neutralizing the first proton, and pKa2 is the pH at the midpoint of the second equivalence point. The molecular weight can be determined by mass spectrometry or by summing the atomic masses of the constituent elements.

In b. The general shape of the curve for a diprotic acid with Ka1 ≈ Ka2 is a gradual decline followed by a steeper decline. The two equivalence points are closer together compared to the case of Ka1 >> Ka2.

In c. The general shape of the curve for a triprotic acid with Ka1 >> Ka2 >> Ka3 is a series of three gradual declines. Each equivalence point represents the neutralization of one proton, and the pKa values can be determined at the midpoints of the corresponding equivalence points.

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-2269.2kJ is the enthalpy change of a given equation for 4 moles  . the negative value indicates that the given reactions are spontaneous reactions .

These equations and enthalpy of reaction is  given by Hess’s law, the chemical equation can be treated as algebraic expressions . That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

P4(s) + 10 Cl2(g)--> 4 PCl5(s) ΔH°rxn= -1774.0 kJ

PCl3(l) + Cl2(g)--> PCl5(s) ΔH°rxn = -123.8 kJ  (  Multiply  by 4 )

then the value of enthalpy change  for equation 2 be  -495.2kJ

then according to enthalpy change equation

delta H = delta h1 - delta h2

delta H = -1774.0 -(- 495.2)

delta H = - 2269.2KJ

for 4 moles  the value of enthalpy change is -2269.2kJ

the value of enthalpy change for 1 mole is  - 567.3 KJ

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Answer:

s+o2=so2

Explanation:

i hope it will help u

Answer:

SI, The International System of Units is a scientific method of expressing the magnitudes or quantities.

Hope this helps!

The number of water molecules in the container when one electron is removed from every hundredth water molecule and placed in a container is 100. m from the water is 3.30 x 1025.

Given,1 liter of water = 1000 g of water1 mole of water molecules = 6.022 x 1023 particles.

Therefore, 55.5 moles of water molecules = 55.5 x 6.022 x 1023 particles = 3.33 x 1025 particles one electron is removed from every hundredth water molecule.

So, 1 electron is removed from 1% of water molecules. Therefore, the number of water molecules from which the electron is removed = (1/100) x 3.33 x 1025 = 3.33 x 1023 molecules.

Now, this electron is placed 100 m away from the water container. The distance between the water container and the electron is not relevant for finding the number of water molecules in the container, hence can be ignored.

So, the number of water molecules in the container = Total number of water molecules - number of water molecules from which electron is removed= 3.33 x 1025 - 3.33 x 1023 = 3.30 x 1025.

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Answer:

169.913616 g/mol

Explanation: This is weight of AsF5 molecular weight

Xenon and potassium do not form a bond. Xenon is a noble gas, and as such, it is chemically unreactive and does not form chemical bonds with other elements under normal conditions. Potassium, on the other hand, is an alkali metal and forms ionic bonds with other elements.

Xenon and potassium are two different elements that do not form a chemical bond. Xenon is a noble gas and is chemically unreactive, meaning it does not form chemical bonds with other elements. Noble gases are characterized by their full valence shell of electrons, which makes them stable and resistant to chemical reactions. Potassium, on the other hand, is an alkali metal and is highly reactive, meaning it readily forms ionic bonds with other elements. Ionic bonds are formed between positive and negative ions and are held together by electrostatic forces. Since xenon and potassium do not form a bond, it would not be classified as a covalent or ionic bond. The concept of covalent and ionic bonds only applies to chemical bonds between atoms.

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The number 0.00208 has three significant figures. Significant figures are the digits in a number that carry meaningful information about its precision. In the case of 0.00208, the digits 2, 0, and 8 are all significant.

Zeros that appear before the first nonzero digit (leading zeros) are not considered significant. Therefore, the leading zero in 0.00208 is not counted as a significant figure.

To summarize, the number 0.00208 has three significant figures: 2, 0, and 8.

If we write the number as 0.002080, the trailing zero after the 8 would be considered significant, indicating that there are four significant figures in the number.

If we express the number in scientific notation, such as 2.08 x 10^(-3), the digits 2, 0, and 8 remain significant, regardless of the exponent. Hence, there are still three significant figures in the number.

It's important to note that significant figures are not limited to decimal numbers. They are also relevant in whole numbers and in calculations involving measurements with uncertainties.

Understanding the concept of significant figures allows us to maintain consistency and precision in calculations and measurements. By recognizing the significant figures in a number, we can appropriately determine the number of decimal places to retain in the result of a calculation or measurement.

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According to the question, the student set out to study the influence of temperature of water on the time for sugar to dissolve but a different amount of water and a different temperature of water was used in each trial. This experiment is wrong because the student changed more than one independent variable.

The aim of the student in the experiment was to determine the influence of temperature of water on the time for sugar to dissolve.

This experiment should have one independent variable (temperature) and one dependent variable (time for sugar to dissolve).

However, the student also changed the amount of water used at each trial meaning that another independent variable has been introduced. This makes it difficult for us to arrive at reliable conclusions from the experiment.

The amount of water ought to have been held constant throughout the experiment.

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The standard cell potential at 25 degrees C for the given cell reaction is; -2.00 V.

To calculate the standard cell potential at 25 degrees C for the given cell reaction, we need to use the following equation;

E°cell = E°red, cathode - E°red, anode

where E°red, cathode is the standard reduction potential for the reduction half-reaction occurring at the cathode, and E°red, anode is the standard reduction potential for the reduction half-reaction occurring at the anode.

The half-reactions for the given cell reaction are;

Cathode; Cu²⁺(aq) + 2e⁻ → Cu(s)

Anode; Al³⁺(aq) + 3e⁻ → Al(s)

Using the standard free energies of formation (ΔG°f) for each species in Appendix C, we can calculate the standard reduction potentials (E°red) for each half-reaction using the following equation;

ΔG° = -nFE°red

where n is number of electrons transferred in the half-reaction, F is Faraday constant (96,485 C/mol), and E°red is standard reduction potential.

For the cathode half-reaction;

Cu²⁺(aq) + 2e⁻ → Cu(s)

ΔG°f(Cu²⁺(aq)) = -166.1 kJ/mol

ΔG°f(Cu(s)) = 0 kJ/mol

ΔG° = ΔG°f(Cu(s)) - ΔG°f(Cu²⁺(aq)) = 166.1 kJ/mol

n = 2 (since 2 electrons are transferred)

E°red,cathode = -ΔG°/(nF) = -0.34 V

For the anode half-reaction;

Al³⁺(aq) + 3e⁻ → Al(s)

ΔG°f(Al³⁺(aq)) = -524.2 kJ/mol

ΔG°f(Al(s)) = 0 kJ/mol

ΔG° = ΔG°f(Al(s)) - ΔG°f(Al³⁺(aq)) = 524.2 kJ/mol

n = 3 (3 electrons are transferred)

E°red,anode = -ΔG°/(nF) = 1.66 V

Therefore, the standard cell potential at 25 degrees C for the given cell reaction is;

E°cell = E°red,cathode - E°red,anode

E°cell = (-0.34 V) - (1.66 V)

E°cell = -2.00 V

The negative sign indicates that the cell reaction is not spontaneous under standard conditions.

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