Answers
Answer: rectilinear motion is another name for straight-line motion. this type of motion describes the movement of a particle or a body
Explanation:
Related Questions
the mass of a density bottle is 18.00g when empty 44.00g when full of water, and 39.84g when full up of a second liquid. calculate the density of the liquid where density of water =1000kgm³
Answers
The density of the second liquid is 0.812 g/cm³
To calculate the density of the second liquid, we need to use the principle of displacement. The mass of the liquid can be found by subtracting the mass of the empty density bottle from the mass of the bottle filled with the liquid. Therefore, the mass of the liquid is:
mass of liquid = mass of bottle + liquid - mass of empty bottle
mass of liquid = 39.84g + x - 18.00g
where x is the mass of the liquid.
We can now use the density formula, which is:
density = mass/volume
The volume of the liquid is equal to the volume of the density bottle that is filled with the liquid, which can be calculated by subtracting the volume of the empty bottle from the volume of the bottle filled with the liquid. Therefore, the volume of the liquid is:
volume of liquid = volume of bottle filled with liquid - volume of empty bottle
We can now substitute this expression into the density formula to get:
density of liquid = mass of liquid / (volume of bottle filled with liquid - volume of empty bottle)
We know that the density of water is 1000 kg/m³, which is equal to 1 g/cm³. We can use this to find the volume of the liquid by dividing the mass of water by its density:
volume of water = mass of water / density of water
volume of water = 44.00g / 1 g/cm³
volume of water = 44.00 cm³
Now, we can calculate the volume of the density bottle filled with the second liquid by using the principle of displacement:
volume of bottle filled with liquid = volume of water - volume of liquid
volume of bottle filled with liquid = 44.00 cm³ - (39.84g - 18.00g) / 1 g/cm³
volume of bottle filled with liquid = 44.00 cm³ - 21.84 cm³
volume of bottle filled with liquid = 22.16 cm³
Finally, we can substitute these values into the density formula to get:
density of liquid = x / 22.16 cm³
Solving for x, we get:
x = density of liquid x 22.16 cm³
Substituting x back into the mass equation, we get:
mass of liquid = 39.84g + (density of liquid x 22.16 cm³) - 18.00g
Solving for the density of the liquid, we get:
density of liquid = (mass of liquid - 21.84g) / 22.16 cm³
Substituting the given values, we get:
density of liquid = (39.84g - 21.84g) / 22.16 cm³ = 0.812 g/cm³
In conclusion, the density of the second liquid is 0.812 g/cm³. This value is less than the density of water, which means that the second liquid is less dense than water and will float on top of water.
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Select the correct answer.
These waves are traveling at the same
speed. Which wave has the highest frequency?
• A.
AAAAAA
• B.
AAAA
O c.
A
O D.
AAA
Answers
Answer:
A
Explanation:
Frequency is defined by repetitions or periods per second. If we take any segment from each graph, we would see that graph A has the most repetitions per second.
The period of A is the shortest since the frequency is equal to 1/T, the smaller the period, the higher the frequency.
A man is standing away from the School
Building at a distance of
300m . He claps his hands and hears an echo calculate the time interval of him hearing his echo
Answers
The time interval between the man clapping and hearing his echo is approximately 1.75 seconds.
What do you mean by echo?An echo is a repetition or reflection of a sound or signal. It can be caused by sound waves bouncing off a surface, signal interference, or the repetition of a message in communication.
The speed of sound in air at room temperature is approximately 343 meters per second. When a person claps, the sound waves propagate outward in all directions and reach the school building, where they bounce off and return to the person as an echo. The time it takes for the sound to travel the distance to the building and back to the person is the time interval between the clap and the echo.
To calculate the time interval, we can use the following formula:
time = distance / speed
where distance is the total distance traveled by the sound (twice the distance from the person to the school building), and speed is the speed of sound in air.
distance = 2 x 300m = 600m
speed = 343 m/s
time = 600m / 343 m/s = 1.75 seconds (rounded to two decimal places)
Therefore, the time interval between the man clapping and hearing his echo is approximately 1.75 seconds.
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How is a conductor different from an insultator?
a. the free movement of electrons within a conductor permits the transfer of change
b. The free movement of protons within a conductor permits the transfer of change
c. there is no free movement of electrons within a conductor
d. there is no free movement of protons within a conductor
Answers
Answer:
a. the free movement of electrons within a conductor permits the transfer of change
Explanation:
Most conductors have more electrons than protons as well. And when you move from one conductor to another, the net charge on the conductor changes by the addition or subtraction of electrons only. In other words, all metals are charged and are considered to have a “positive charge.” A conductor permits energy, such as electric charge or heat, to flow freely through it.
How does an electrometer differ from a voltmeter? What is meant by an electrical ground? What must you do before each measurement in this experiment and why?
Answers
Answer:
n an electrometer, it is built in such a way that its resistance in parallel is extremely high
Ground in a circuit is a reference point from which voltages are measured
all the instruments must be grounded and we must ground ourselves
Explanation:
When you build a voltmeter you have a resistance in parallel with the galvanometer, therefore when measuring the voltage of a circuit, so that there is no effect (load effect) by the voltmeter, a resistance must be much greater than the resistance where it is is measuring.
In an electrometer, it is built in such a way that its resistance in parallel is extremely high in the order of 10¹²Ω, so its load effect is very small and can be measured with high resistance mu
Electric ground in home and industrial installations is a protection system consisting of a metal piece connected to a buried ground electrode.
Ground in a circuit is a reference point from which voltages are measured and is common to all parts of the circuit
In an experiment where an electrometer is used, all the instruments must be grounded and we must ground ourselves, since it must be an instrument where very small voltages are measured at high impedances.
A meter stick is attached to one end of a rigid rod with negligible mass of length l = 0.302 m. The other end of the light rod is suspended from a pivot point, as shown in the figure below. The entire system is pulled to a small angle and released from rest. It then begins to oscillate. A meter stick hung from a rod of length l. The rod is attached to the ceiling. The rod and meter stick extend downward in a straight line making a small angle with the vertical. (a) What is the period of oscillation of the system (in s)? (Round your answer to at least three decimal places.)
Answers
The period of oscillation of the system nearest to three decimal places
= 1.092 seconds
The period of an oscillation occurring in a system is the time taken to complete one cycle.
The formula that is used to calculate the period of oscillation (T) is
= 2π√\(\frac{l}{g}\)
But,
π = 3.14159 (constant)
g= 10m/s² (acceleration due to gravity)
l = 0.302 m
Therefore T = 2 × 3.14159 × √\(\frac{0.302}{10}\)
= 6.28318 x √0.0302
= 6.28318 x 0.17378
= 1.09189s
= 1.092 seconds ( to the nearest three decimal places)
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A flat screen tv uses 120 watts. How much energy is used up if it is left on for 15 min?
A.) 4j
B.) 15j
C.) 0.67j
D.) 108,000j
Answers
Answer:
d
Explanation:
An astronaut measure the period of a mass spring system on Earth. How would the period be affected if the astronaut measured the period of the same mass spring system on the moon? (Moon's gravity = 1/6 Earth's gravity.)
Answers
An astronaut measure the period of a mass spring system on Earth.
The period of a mass spring system on the moon would be longer than the period on Earth. This is because the period of a mass spring system is dependent on the square root of the ratio of the mass to the spring constant, and the acceleration due to gravity. Since the acceleration due to gravity on the moon is only 1/6th of that on Earth, the restoring force on the mass will be weaker, resulting in a longer period. Therefore, the astronaut would measure a longer period for the same mass spring system on the moon than on Earth.
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Some nitrogen at 80.0 psi gauge pressure occupies 13.0 ft^3. Find its volume, in ft^3, at 50.0 psi gauge pressure.
Answers
Answer:
20.8 ft³
Explanation:
The following data were obtained from the question:
Initial pressure (P1) = 80 psi
Initial volume (V1) = 13 ft³
Final pressure (P2) = 50 psi
Final volume (V2) =?
The new volume of the gas can be obtained by using the Boyle's law equation as shown below:
P1V1 = P2V2
80 × 13 = 50 × V2
1040 = 50 × V2
Divide both side by 50
V2 = 1040 / 50
V2 = 20.8 ft³
Thus, the volume of the gas at a pressure of 50 psi is 20.8 ft³
What type of tv uses a VfL for backlighting
Answers
A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.
LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.
The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.
Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.
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Prior Knowledge Questions (Do these BEFORE using the Gizmo.) Strings of holiday lights can be designed in one of two ways. In some strings of lights, each light is connected to the others along a single wire (in series). In others, each light is attached to its own wire (in parallel). Suppose a single light bulb burns out. How do you think this will affect lights that are strung along a single wire
Answers
Answer:
They would go out
Explanation:
This is because, in a series connection, the same current passes through each light. Since the current is the same, if one light burns out, it cuts off the rest of the other lights and thus, no current flows in the string again.
Whereas, in a parallel connection, each light is attached to its own wire and thus has a different current flowing through it than the rest of the other wires. If one of the lights goes out, current stops flowing through it but, it doesn't affect the other lights.
Problem B.2: Escaping a Star (6 Points) It takes many years for a photon produced in a star's centre to reach its surface and escape into space. This is due to its constant interaction with other particles. To estimate the time it takes for a photon to escape a star's interior, we assume that the photon is deflected in equal time intervals into a random direction in a two-dimensional space (i.e., a random walk): At each step i, the photon moves a constant distance in an angle, thus changing its position: cos(4) sin(y) Ai, - c (a) Determine the distance R(n) from the centre (0,0) after n steps.
Answers
Answer:
This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.
The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.
The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).
The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:
R(n) = √(X² + Y²)
Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.
However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:
<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2
<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2
Because <X²> = <Y²>, we can write:
<R²> = <X²> + <Y²> = n A²
So, the root mean square distance (the square root of the mean square displacement) after n steps is:
R(n) = √(<R²>) = √(n) * A
Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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Wondering if someone can please explain why this question is unsound;
Given that v= frequency x lambda and the frequency of a wave under investigation is 15Ghz with a wavelength of 0.2m, select the correct answer below.
a. v= 7.5 x 10^1 0 m/s
b. None of these answers are correct.
c. v= 1.3 x 10^-11 m/s
d. The question is unsound.
e. v= 3x10^9 m/s
Answers
Explanation:
The question is sound. The frequency and wavelength are given so you can solve for wave's velocity. It's just a matter of changing the notation.
\(v = \nu \lambda = (15×10^9\:\text{Hz})(0.2\:\text{m})\)
\(= 3×10^9\:\text{m/s}\)
Consider a wheel (solid disk) of radius 1.12 m, mass 10 kg and moment of inertia 1 2 M R2 . The wheel rolls without slipping in a straight line in an uphill direction 37◦ above the horizontal. The wheel starts at angular speed 12.0536 rad/s but the rotation slows down as the wheel rolls uphill, and eventually the wheel comes to a stop and rolls back downhill. How far does the wheel roll in the uphill direction before it stops?
Answers
Answer:
d= 23.25 m
Explanation:
Assuming no other external forces acting on the disk, total mechanical energy must be conserved.Taking the initial height of the disk as the zero reference for the gravitational potential energy, initially. all the energy is kinetic.This kinetic energy is part translational kinetic energy, and part rotational kinetic energy, as follows:\(E_{o} = K_{transo} + K_{roto} (1)\)
When the disk rolling uphill finally comes to an stop, its energy is completely gravitational potential energy, as follows:\(E_{f} = m*g*h (2)\)
Since the angle with the horizontal of the track on which the disk is rolling, is 37º, we can express the height h in terms of the distance traveled d and the angle of 37º, as follows:\(h = d* sin 37 (3)\)
Replacing (3) in (2):\(E_{f} = m*g* d * sin 37 (4)\)
Since the wheel rolls without sleeping, this means that at any time there is a fixed relationship in the translational speed and the angular speed, as follows:\(v = \omega * R (5)\)
For a solid disk, as mentioned in the question, the moment of inertia is just 1/2*M*R².The rotational kinetic energy of a rotating rigid body can be written as follows:\(K_{rot} = \frac{1}{2}* I * \omega^{2} (6)\)
Replacing I from (6) and ω from (5), and remembering the definition of the translational kinetic energy, we can solve (1) in terms of v, m and r as follows:\(E_{o} = K_{transo} + K_{roto} = \frac{1}{2}* m* v^{2} +(\frac{1}{2}* \frac{1}{2}) *m*r^{2}*(\frac{v}{r}) ^{2} = \\ \frac{3}{4} * m * v^{2} (7)\)
Since (4) and (7) must be equal each other, we can solve for d as follows:\(d =\frac{3}{4} * \frac{v^{2}}{g*sin37} = \frac{3}{4}*\frac{(\omega*r)^{2}}{g*sin 37} (8)\)
Replacing by the values, we finally get:\(d =\frac{3}{4}*\frac{(\omega*r)^{2}}{g*sin 37} = \frac{3}{4} *\frac{(12.0536rad/sec*1.12m)^{2}}{9.8 m/s2*0.601} = 23. 25 m.\)
A kicked ball rolls across the grass and eventually comes to a stop in 4.0 sec. When the ball was kicked, its initial velocity was 20 mi/ hr. What is the acceleration of the ball as it rolls across the grass?
Answers
Answer:
-2.24 m/s²
Explanation:
Given:
v₀ = 20 mi/hr = 8.94 m/s
v = 0 m/s
t = 4.0 s
Find: a
v = v₀ + at
0 m/s = 8.94 m/s + a (4.0 s)
a = -2.24 m/s²
the ratio of force between two charges in vacuum to that the force between two same charges when a medium is placed between them
Answers
The ratio of the force between two charges in a vacuum to the force between two charges when a medium is placed between them is called relative permittivity
What should you know about relative permittivity?Relative permittivity has another term dielectric constant. The dielectric constant measures how well a material can store electrical energy in an electric field. Its equation is ε = ε₀ / εᵣ
ε₀ is the vacuum permittivity, and εᵣ is the relative permittivity or dielectric constant of the medium.
The dielectric constant is different depending on the material.
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50
1. Force = ? N mass = 65 kg acceleration = 25 m/s2 (Record your answer
by number only and don t.include units...)
Answers
Answer: el pepe
Explanation:
Answer:
8125 N.
Explanation:
F = M A
M is mass
A is acceleration
F = 65 X 25
F = 8125 N.
4) Collision in which K.E and momentum of system remain same is called__________
(*)Elastic Collision
(*) Inelastic collision
(*) Conserved collision
(*) Linear collision
Answers
A collision that is elastic occurs when there is no net loss of kinetic energy in the system as a result of the collision. Kinetic energy and momentum are both conserved in elastic collisions.
Give an example of an elastic collision.When two balls collide at a pool table, that is an instance of an elastic collision. When you throw a ball on the ground and it bounces back into your hand, there is no net change in the kinetic energy, making it an elastic collision.
Give an illustration of what an elastic collision is.Two balls colliding at a pool table is an example of an elastic collision. When a ball is tossed to the ground and subsequently returns to your hand, there is no net change in the kinetic energy, making it an elastic collision.
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Which types of light are not absorbed by the genetic material
Answers
Answer:
I know only one type of light that is absorbed by genetic materail and that is UV light
Explanation:
Two identical billiard balls are rolling toward each other at the same speed. What will be true after they collide head–on?
Answers
Answer:
They will be moving away from each other at the same speed.
Explanation:
The final speed may be identical to the initial speed if the collision is perfectly elastic. The final speed will be zero if the collision is perfectly in-elastic.
In all likelihood, the final speed will be slightly slower than the initial speed.
Which phrase describes the energy transformation that happens in a
generator?
A. Electrical energy into chemical energy
ООО
B. Electrical energy into mechanical energy
C. Chemical energy into electrical energy
O
D. Mechanical energy into electrical energy
SI
Answers
Answer:
Mechanical energy into electrical energy
Explanation:
Answer:
ExplanMechanical energy into electrical energy
SIation:
A 2.5-kg rock is dropped off a 32-m cliff and hits a spring, compressing it 57 cm. What is the spring constant? Round your answer to two significant figures.
The spring constant, k, is
StartFraction N over m EndFraction.
Answers
Answer: 4800 N/m
Explanation:
Given
mass of rock \(m=2.5\ kg\)
Height of cliff \(h=32\ m\)
compression in the spring \(x=57\ cm\)
Here, potential energy is converted into kinetic energy which in turn converts to elastic potential energy of the spring
\(\Rightarrow mgh=\dfrac{1}{2}kx^2\\\\\Rightarrow k=\dfrac{2mgh}{x^2}\\\\\Rightarrow k=\dfrac{1568}{0.3249}\\\\\Rightarrow k=4826.100\approx 4800\ N/m\)
Answer:
480
Explanation:
2021
What’s Newton’s second law? Explain and mention some examples in daily life
Answers
F = m•a
An example of this would be hitting a ball. If you hit the ball, it will move however fast you hit the ball. The harder you hit the ball, the faster it will move.
hope this helps and brainliest please
Answer:
Newton's second law states that .
The rate of change of linear momentum is directly proportional to the force applied.Formulically
F=maF=Force
m=mass
a=acceleration
The best example is hitting a tennis ball.
A long piece of wire with a mass of 0.100 kg and a total length of 4.00 m is used to make a square coil with a side of 0.100 m. The coil is hing along a horizontal side, carries a 3.80 A current, and is placed in a vertical magnetic field with a magnitude of 0.010 0 T.
a, Determine the angle that the plane of the coil makes with the vertical when the coil is in equilibrium. b Find the torque acting on the coil due to the magnetic force at equilibrium.
Answers
The torque is equal to zero since the coil is in equilibrium. As a result, will also equal zero, indicating that the coil's plane is parallel to the vertical direction at equilibrium.
Calculation-The current-carrying coil in a magnetic field is given by:
τ = μ * B * I * A * sin(θ)
where:
τ = torque (in Nm)
μ = magnetic moment of the coil (in Am^2)
B = magnetic field strength (in T)
I = current flowing through the coil (in A)
A = area of the coil (in m^2)
θ = angle between the plane of the coil and the magnetic field (in radians)
μ = N * A * I
N = number of turns of the coil
A = area of the coil (in m^2)
I = current flowing through the coil (in A)
the equations to calculate the angle θ:
m = 0.100 kg (mass of the wire)
L = 4.00 m (total length of the wire)
side length = 0.100 m
I = 3.80 A (current flowing through the coil)
B = 0.0100 T (magnetic field strength)
Calculations:
A = side length^2 * N = 0.100^2 * 1 = 0.0100 m^2
μ = N * A * I = 1 * 0.0100 * 3.80 = 0.0380 Am^2
Now we can rearrange the equation for torque to solve for θ:
θ = arcsin(τ / (μ * B * I * A))
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What happens to the mechanical advantage of a machine if the output force is less than the input force? What must happen to output distance? Give an example of a machine that does this?
Answers
Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?
Answers
The diameter of the smaller end of the pipe is approximately 0.78 meters.
To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.
The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity
Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2
Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2
Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30
Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30
0.36 * 13 = (diameter2/2)^2 * 30
4.68 = (diameter2/2)^2 * 30
Dividing both sides by 30:
0.156 = (diameter2/2)^2
Taking the square root of both sides:
0.39 = diameter2/2
Multiplying both sides by 2:
0.78 = diameter2
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Galileo Galilei made several discoveries with his new telescope. Discuss the discoveries involving Venus, the Milky Way and Jupiter, and explain the significance of each.
Answers
Answer:
c
Explanation:
Answer:
c
Explanation:
A balloon is rubbed with a cloth. A second balloon is just touched by a cloth.A. Rubbing doesn't change its chargeB. Rubbing removes all of the chargeC. The touched balloon gets a greater chargeD. The rubbed balloon gets a greater charge
Answers
ANSWER:
D. The rubbed balloon gets a greater charge
STEP-BY-STEP EXPLANATION:
If we rub the two bodies against each other, we increase the contact between them, and then the passage of electrons from one body to another is greater, that is to say, in the case of rubbing some of the electrons are released, and remain attached to the balloon. Whereas when it is only touched this does not happen.
So the correct answer is D. The rubbed balloon gets a greater charge
Two bumper car in an amusement park ride collide elastically as on approaches the other directly from the rear. Car A has a mass of 450kg and car B 550kg, owing to differences in passenger mass. If car A approaches at 4.5m/s and car B is moving at 3.7m/s, calculate (a) their velocities after collision, and (b) the change in momentum of each.
Answers
Answer:
VA = 3.62 m/s
VB = 4.42 m /s
Change of momentum of A = -396 kgm/s
Change of momentum of B = 396 kgm/s
Explanation:
Asuming A and B move to the right after the collision
pbefore = pafter
4.5*450 + 3.7*550 = 450VA + 550VB
In a elastis collition, the coefficient of restitution is 1
1 = (VB - VA)/(4.5 - 3.7)
VB - VA = 0.8
VB = 4.42 m/s
VA = 3.62
Change of momentum of A = 450*(3.62-4.5) = -396 kgm/s
Change of momentum of B = 550*(4.42-3.7) = 396 kgm/s