Enthalpy is the sum of the internal energy of a system and the product of its pressure and volume.
Enthalpy is represented by H, and the change in enthalpy is referred to as ΔH. When a chemical reaction occurs, it may either absorb or release energy. When energy is released, it is said to be exothermic, whereas when it is absorbed, it is said to be endothermic.
Standard enthalpy change is the enthalpy change that occurs when all of the reactants and products are in their standard states under standard conditions.
The standard enthalpy change of a chemical reaction is referred to as ΔHºrxn.
The enthalpy of formation of a compound, which is the enthalpy change that occurs when a compound is formed from its constituent elements in their standard states under standard conditions, is also frequently referred to as standard enthalpy change.
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What is the role of gravity in the solar system?
Answer:
Explanation:
Gravity is what holds the planets in orbit around the sun and what keeps the moon in orbit around Earth. ... Gravity creates stars and planets by pulling together the material from which they are made. Gravity not only pulls on mass but also on light.
Heat energy is _________.
ANSWER:Atoms
Explanation:
when heat energy is the result of movement of tiny particles called atoms. molecules or ions in solid liquids and gases heat energy can be transferred from one object to another the transfer or flow due to the difference in temperature between the two objects is called heat
For the following reaction, 11.4 grams of sulfur are allowed to react with 23.9 grams of carbon monoxide .
sulfur(s) + carbon monoxide(g) sulfur dioxide(g) + carbon(s)
What is the maximum amount of sulfur dioxide that can be formed? (grams)
What is the FORMULA for the limiting reagent?
What amount of the excess reagent remains after the reaction is complete? (grams)
The formula for limiting reagent is "S". The maximum amount of sulfur dioxide formed is 9.6g and the limiting reagent is 0.15 moles.
Limiting reagent is the reagent that limits or inhibit the formation of product.
As we know,
To calculate the number of moles we need to divide given mass by molar mass.
No. of moles = given mass/ molar mass.
For sulfur: -
No. of moles = 11.4 / 32
= 0.35 moles.
For carbon monoxide: -
No. of moles = 23.9 / 28
= 0.85 moles.
The chemical reaction would be S + 2 CO - SO2 + 2C
Here, we can see that 1 mole of sulfur is reacting with 2 moles of carbon monoxide. Therefore, 2/1 x 0.35 moles.
Therefore, excess amount of sulfur is 0.70.
Thus, carbon monoxide is the limiting reagent here.
For the excess amount of reagent is 0.85 - 0.70 = 0.15 moles.
By stoichiometry, we can conclude that 1 mole of sulfur gives 1 mole of sulfur dioxide.
For the excess amount of sulfur dioxide: -
Molar mass of sulfur dioxide = 64g.
Therefore, 0.15 = given mass of SO2 / 64
Mass of sulfur dioxide = 9.6 g.
For excess amount of carbon monoxide: -
Molar mass of carbon monoxide = 28g.
Therefore, 0.15 = given mass of CO / 28
Mass of carbon monoxide = 4.2 g.
Therefore, the maximum amount of sulfur dioxide produced is 9.6 g and the excess limiting reagent is 0.15 moles.
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Broken pieces of what types of rock are deposited into layers and cemented together to form sedimentary rock?
Select one:
a. sedimentary
b. igneous
c. metamorphic
d. all of these
Answer:
hey mate your answer is
D ALL OF THESE
HOPE IT HELPS YOU
To make sedimentary rock, broken bits of sedimentary, igneous, and metamorphic rocks get deposited in layers and bonded together.
So, option d. is correct.
Define sedimentary rock.Sedimentary rocks are created by the accumulation and deposition of mineral and organic particles just at earth's surface, followed by cementation. The processes that enable these particles that settle in place are referred to as sedimentation.
To make sedimentary rock, broken bits of sedimentary, igneous, and metamorphic rocks get deposited in layers and bonded together.
So, option d. is correct.
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A solution contains a mixture of cl- and br- ions. can both be positivevly identified?
Yes, \(Br^{-}\) and \(Cl^{-}\) ions both can be positively identified through precipitation reaction or precipitimetry.
Through titration employing precipitation reaction or precipitimetry, these two ions can both be positively identified. When exposed to Cl- and Br- ions, AgNO3 transforms into silver halides. AgNO3 with Cl- ions precipitates white because AgCl is not particularly soluble in water, whereas AgNO3 with Br- ions precipitates cream.
A very light cream precipitate results from mixing cream and white ppt.
Both halides react as described below:
\(AgNO_{3}+ XCl\)\(= AgCl_{whiteppt.}\)
\(AgNO_{3}+ XBr\) \(= AgBr_{creamppt.}\)
Now, While AgBr does not dissolve in diluted ammonia, this AgCl precipitate does to create an Ag-diammonium ion combination. Two facts, including the fact that the ppt shade is now darker than the prior pale cream, demonstrate this. As a result of the addition of an ammonia solution, it becomes less concentrated, although some cream precipitates persist.
Second, concentrated ammonia dissolves the AgBr precipitate. AgBr precipitates dissolve when cream precipitate is filtered and concentrated ammonia is added. In solution Br- ions are confirmed by this.
\(Ag^{+}+NH_{3}\) ⇄ \((AgNH_{3} )_{2} ^{+}\)
The foregoing reaction switches in the right direction after the addition of diluted ammonia solution, and more and more Ag+ ions are complexed, producing the soluble form of Ag-diammonium complex.
Brown globules are produced when CHCl3 is added to the mixture and agitated.
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An element is
A) made of only one kind of atom.
B) made of compounds from the periodic table.
C) made of different atoms physically combined together.
D) made of different kinds of atoms chemically combined.
25 POINTS! How does bond energy determine whether a chemical reaction is exothermic or endothermic?
Please help!!!! Best answer will get brainliest
Answer:
covalent network
Explanation:
trust me on this one
An atom's electron configuration ends with 3p4. if another atom has seven more electrons, what would be the continuation of the electron configuration? 3p63d34s2 3p43d54s2 3p64s23d3 3p44s23d5
The continuation of the electron configuration is 3p6 4s2 3d3.
Electronic configuration ends up with = 3p4
So, here principle quantum number(n) =3
Atom which ends up with 3p4 configuration = S
Sulphur(s) = [Ne] 3s2 3p4
So atomic number of Sulphur (s) =16
After adding 7e in it -
Atomic number = 16+7 =23
Now atomic no. =23 (after adding 7 more electrons)
So electronic configuration with atomic no. =23
Atomic number (23) - [Ne] 3s2 3p6 4s2 3d3
Now electronic configuration will ends up with= 3d3
Electrons belong to the primary technology of the lepton particle's own family and are typically thought to be fundamental particles because they have no recognized additives substructure.
For most realistic purposes, an electron is a structureless particle with an intrinsic angular momentum or spin. simply two numbers — the electron's mass and its electric price — gasoline the equations that describe its behavior. From this 'sensible electron' version, physicists constructed present-day microelectronics.
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how many atoms are in the compound 2HCIO3
Answer:
6 atoms
Explanation:
Hey there!
To find out how many atoms are in this compound, we have to add up all of the atoms
2H means there are 2 atoms
Then we have Cl which is 1 more atoms
Last, we have O₃ which gives us 3 atoms
Now we do basic math:
2 + 1 + 3 = 6
So there are 6 atoms in this compound
HF or HCl which can form the hydrogen bond? Explain your answer.
Answer:
can only form one hydrogen bond each
Explanation:
can only form one hydrogen bond each
"Orbitals of equal energy are each occupied by one electron before any is occupied by a second electron, and all electrons in singly occupied
orbitals must have the same spin" is a statement of
Select one:
a the Pauli exdusion principle,
b. the Aufbau principle.
the quantum effect
d. Hund's rule
Answer: the Aufbau principle.
Explanation:
Which statement correctly describes electrochemical cells?
A. Electrochemical cells involve only oxidation reactions.
B. Electrochemical cells involve only reduction reactions.
C. Electrochemical cells involve oxidation-reduction reactions.
D. Electrochemical cells do not involve oxidation-reduction reactions.
Answer: C. Electrochemical cells involve oxidation-reduction reactions.
Explanation: Oxidation occurs at the anode, and reduction occurs at the cathode.
what kind of chemical formula would an ionic compound have if the compound consists of a face centered cubic lattice with
The formula of ionic compound forming face centered cubic lattice will be AB₃
The face centered cubic lattice has atom present at corner as well as all the faces of unit cell. suppose the we have two atom A and B forming FCC.
Atom present in corner contribute = 1/8
Atom present in face contribute = 1/2
A atom present in the corner = 8 x 1/8
A atom = 1 atom
B atom present in the faces of unit cell = 6 x 1/2
B atom = 3 atom
Chemical formula of ionic compound = AB₃
Hence, ionic compound exist in AB₃ formula in FCC.
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can we observe a lunar eclipse during a new moon phase? explain your answer.
please help me thx
subject is science
Answer: There is no eclipse. However, two or four times a year, the Moon travels through some portion of the Earth's penumbral or umbral shadows, resulting in one of the three types of eclipses mentioned above. When the Moon crosses between the Earth and the Sun, this occurs. This is only possible when the Moon is in its New Moon phase.
Explanation:
HOPE THIS HELPS!!! : )
(e) (i) What are the number average (Mn) and weight average (Mw) molecular weights of a polymer with equal number of chains with molecular weights of 2100, 6600 and 12000 mixed together? (ii) What is the answer if "equal number of chains" is replaced by "equal weights of chains"? (iii) What is the degree of polymerization (DP) of the polymer in the first question, if the repeating units of the three different chains have molecular weights of 126, 324 and 300?
(e) (i) Number average (Mn) = 6,900g/mol
(ii) Mn will remain the same in this case as it does not depend on weight.= 6,900g/mol
(iii) The degree of polymerization (DP) is 4492.
(i) Number average (Mn)
The number average molecular weight (Mn) is the sum of the molecular weights of all polymer chains divided by the total number of polymer chains.
Weight average (Mw)
The weight average molecular weight (Mw) is the sum of the product of the molecular weight and the fraction of the total polymer chains that have that molecular weight.
Using the given formula, let's first calculate the Mn:
(2100 + 6600 + 12000) / 3 = 6,900g/mol
Let's now calculate the Mw:
[(2100 x 2100) + (6600 x 6600) + (12000 x 12000)] / (2100 + 6600 + 12000)= 9966.67g/mol
(ii) Equal weights of chains
Mn will remain the same in this case as it does not depend on weight.
Mw, on the other hand, will change.
The following formula will be used:
2100 x (1/3) + 6600 x (1/3) + 12000 x (1/3) = 6,900g/mol
(iii) The degree of polymerization (DP)
DP refers to the number of repeating units in the polymer chain.
We can calculate the DP using the following formula:
DP = (Mn / M) * NA where M is the molar mass of the repeating unit, and NA is Avogadro's number.
Using the Mn value from part (i) and the given molecular weights for the repeating units, we can calculate the DP:
DP = (6,900 / ((126 + 324 + 300) / 3)) * 6.02 × 1023= 4492.45 (approximately 4492)
Therefore, the degree of polymerization is 4492.
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The weight average molecular weight (Mw) of the polymer will be \($$M_w=\frac{1\times2100^2+1\times6600^2+1\times12000^2{1\times2100+1\times6600+1\times12000}=8,580\;g/mol$$\).
Weight average molecular weight (Mw) of the polymer will be \($$M_w=\frac{1.0587\times2100^2+1.0587\times6600^2+1.0587\times12000^2{1.0587\times2100+1.0587\times6600+1.0587\times12000}=8,825\;g/mol$$\).
The degree of polymerization of the polymer in the first question is 25.01.
Number average (Mn) and weight average (Mw) molecular weights of a polymer are calculated using the following formula:
\($$M_n = \frac{\sum N_iM_i}{\sum N_i}$$\)
and
\($$M_w = \frac{\sum N_iM_i^2}{\sum N_iM_i}$$\)
where Ni is the number of chains with molecular weight Mi.
(i) When the number of chains with molecular weights of 2100, 6600, and 12000 are mixed together:
Molecular weight (M) Number of chains (N) 2100 1 6600 1 12000 1
Total 3
The number average molecular weight (Mn) of the polymer will be:
\($$M_n=\frac{1\times2100+1\times6600+1\times12000}{1+1+1}= 6,900\;g/mol$$\)
The weight average molecular weight (Mw) of the polymer will be:
\($$M_w=\frac{1\times2100^2+1\times6600^2+1\times12000^2}{1\times2100+1\times6600+1\times12000}=8,580\;g/mol$$\)
(ii) When the equal weights of chains are mixed together:
The total weight of the chains is:
2100 + 6600 + 12000 = 20,700 g
Number of chains with molecular weight 2100 = 2100 x n1
Number of chains with molecular weight 6600 = 6600 x n2
Number of chains with molecular weight 12000 = 12000 x n3
So, the total weight of each group of chains will be
n1M1 + n2M2 + n3M3.
Now, we can calculate the values of n1, n2, and n3 as follows:
n1 = 6600 x n2n2 = 12000 x n3M1 + M2 + M3 = 2100 + 6600 + 12000 = 20700n1M1 + n2M2 + n3M3 = 20700
Equating the value of n1 in terms of n2 and n3 and substituting it in the equation above:
n1 = 6600 x n2
\($$\frac{6600}{n1}=n2$$\)
\($$\frac{12000}{n2}=n3$$\)
\($$n1=\frac{20700}{2100+6600+12000}=0.1739$$\)
n2 = 0.0208, n3 = 0.0052
Therefore, the number of chains with molecular weight 2100 = 0.1739 x 2100 / 6600 x 0.1739 x 6600 = 0.0208 x 12000 / 6600 x 0.0208 x 6600 = 0.0052 x 2100 / 6600 x 0.0052 x 12000 ≈ 1.0587
Number average molecular weight (Mn) will be:
\($$M_n=\frac{1.0587\times2100+1.0587\times6600+1.0587\times12000}{1.0587+1.0587+1.0587}= 7,170\;g/mol$$\)
Weight average molecular weight (Mw) of the polymer will be:
\($$M_w=\frac{1.0587\times2100^2+1.0587\times6600^2+1.0587\times12000^2}{1.0587\times2100+1.0587\times6600+1.0587\times12000}=8,825\;g/mol$$\)
(iii) The degree of polymerization (DP) of the polymer in the first question will be:
Number of chains with molecular weight 2100 = 1
Number of chains with molecular weight 6600 = 1
Number of chains with molecular weight 12000 = 1
The molecular weight of the repeating units of the three different chains have molecular weights of 126, 324, and 300 respectively.
Therefore, the degree of polymerization (DP) of the polymer in the first question will be:For 2100 chain,
\($$n_1=\frac{2100}{126}=16.67$$\)
For 6600 chain,
\($$n_2=\frac{6600}{324}=20.37$$\)
For 12000 chain,
\($$n_3=\frac{12000}{300}=40.00$$\)
So, the average degree of polymerization (DP) is:
\($$DP=\frac{1\times16.67+1\times20.37+1\times40.00}{1+1+1}=25.01$$\)
Therefore, the degree of polymerization of the polymer in the first question is 25.01.
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be sure to answer all parts. determine δngas for each of the following reactions: (a) mgco3(s) → mgo(s) co2(g)
The appropriate response is: MgCO₃ (s) → MgO (s) + CO₂ (g)
According to this equation, 1 mole of magnesium carbonate reacts to produce 1 mole of magnesium oxide and 1 mole of carbon dioxide, and 117.3 kJ is absorbed.
What Are the Health Benefits of Magnesium Carbonate?
Magnesium carbonate is a naturally occurring white, powdered substance that is commonly advertised as a health supplement. It can be found in dolomite and magnesite. Magnesium, a mineral that your body needs to function properly, is the main component of this product. According to MedlinePlus, the average human body weighs 25 g of magnesium, half of which is found in bone. Beyond its function in the prevention and treatment of magnesium shortage, magnesium carbonate possesses a wide range of therapeutic qualities. Always get medical advice before using magnesium carbonate to treat, prevent, or cure any ailment.
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which change in the protonation state of glu487 is most likely responsible for the change in mp activity at either low or high ph? the change in activity at:
The pH dependence of the protonation state of glu487 is most likely responsible for the change in MP activity.
As the Glu487 have deprotonation, the pH becomes high. According to the pH-dependence of MP activity, activity reduces at both low and high pH levels. The main reason for decreased activity at low pH and high pH is the protonation of functional groups, respectively, and deprotonation of functional groups. According to the question, before being attacked by a nucleophile the substrate is protonated by Glu487 . The pKa of the side chain is always much greater in the enzyme active site than it is in solution to act as a Bronsted acid during catalysis ; otherwise, it would exist in the deprotonated form in the active site. If the pH elevated enough than there occurs the change in the protonation.
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The law of reflection states that the angle of incidence and the angle of reflection are always
Answer:
The law of reflection states that the angle of incidence and the angle of reflection are always equal.
(subject is astronomy)
Part B When writing a science paper, you need several different sources of information. These sources can be books or websites. Remember to use the most credible sources. Some websites present things as evidence that may not have a scientific base. You must be able to identify reliable sites so the data in your presentation is credible. Sources that end in .edu (school and college websites) and .gov (government websites such as NASA.gov) are the most trustworthy. However, sometimes students, not scientists, write content for .edu websites. Because the content may not have been checked by scientists, read any .edu website carefully to determine whether it is reliable. Some .org and .com sites, such as Smithsonian.com, are also credible, but you have to read the content carefully to determine how legitimate it is. When you review a source, ask yourself these questions about the website’s author, content, and sources: Who authored the article? Is the author a scientific expert in stars and galaxies? What is the purpose of the article? Does the article state facts that can be proven by evidence, or is it made up of opinions? When was the article written? Do other credible sources support the statements in this article? Which scientific studies support the information in the article? Find two to three credible websites that you can use to find information for your paper. Write them down. They can be e-books, magazines, websites, and so on. Also, write down one to two sentences for each source explaining how the source will help you. Show how you will cite your sources at the end of your presentation using MLA (Modern Language Association) citation methods.
In the liberal arts and humanities, MLA (Modern Language Association) style is most frequently used to compose papers and cite sources.
Thus, Brief parenthetical citations in the text that are keyed to an alphabetical list of the works cited at the end of the work are a feature of the MLA style.
With the publication of the most recent edition, the MLA citation style has undergone substantial alterations.
Building trust in the knowledge and ideas we share with one another may be more crucial than ever, and for almost a century, this has been the guiding principle of MLA style, a set of writing and documentation.
Thus, In the liberal arts and humanities, MLA (Modern Language Association) style is most frequently used to compose papers and cite sources.
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4) For each NADH oxidized in the ETC, 3 ATP are produced; and for each FADH₂ oxidized in the ETC, 2 ATP are produced. [4] a) Determine the number of NADH formed throughout aerobic cellular respiration.. b) Determine the number of FADH₂ formed throughout aerobic cellular respiration. c) Determine the total number of ATP produced throughout aerobic cellular respiration (include ATP created through oxidative phosphorylation and substrate-level phosphorylation). d) What is the net production of ATP throughout aerobic cellular respiration? 5) Write the net chemical equation for aerobic cellular respiration including net ATP.
a) The number of NADH formed throughout aerobic cellular respiration is 10.
b) The number of FADH₂ formed throughout aerobic cellular respiration is 2.
c) The total number of ATP produced throughout aerobic cellular respiration, including ATP created through oxidative phosphorylation and substrate-level phosphorylation, is 34.
d) The net production of ATP throughout aerobic cellular respiration is 30.
During aerobic cellular respiration, NADH and FADH₂ are produced in the earlier stages of cellular respiration, namely glycolysis, the transition reaction, and the Krebs cycle. Each molecule of glucose generates a total of 10 NADH molecules. These 10 NADH molecules are produced through the following processes: 2 NADH in glycolysis, 2 NADH in the transition reaction, and 6 NADH in the Krebs cycle.In contrast, only 2 FADH₂ molecules are produced throughout the entire process of aerobic cellular respiration. Both FADH₂ molecules are generated in the Krebs cycle.Regarding ATP production, each NADH molecule oxidized in the electron transport chain (ETC) generates 3 ATP molecules, while each FADH₂ molecule oxidized in the ETC produces 2 ATP molecules. Considering the 10 NADH and 2 FADH₂ produced, we calculate the ATP production as follows:
(10 NADH * 3 ATP/NADH) + (2 FADH₂ * 2 ATP/FADH₂) = 30 ATP.Therefore, the net production of ATP throughout aerobic cellular respiration is 30 ATP. This accounts for the ATP generated through oxidative phosphorylation, which occurs in the ETC, as well as the ATP produced through substrate-level phosphorylation, which occurs in glycolysis and the Krebs cycle. The net chemical equation for aerobic cellular respiration, including the net ATP, can be summarized as:
C6H12O6 + 6O2 → 6CO2 + 6H2O + 30 ATP
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Which of the following actions describes deposition?
breaking rock into smaller pieces
dropping sediment in one location, where it builds up
moving rock from one location to another
flowing soil or mud due to gravity
The following actions describe deposition as flowing soil or mud due to gravity. Option D.
Sedimentation is the accumulation of sediments carried by the wind running water sea or ice. Sediments are carried as pebbles sand mud, or dissolved salts in water. A deposition is the direct transition of a substance from the gaseous state to the solid state on cooling without going through the liquid state.
Sedimentation is the geological process in which sediments soils and rocks are added to form landforms or land masses. Wind ice water and gravity cause previously weathered surface material to deposit and lose sufficient kinetic energy within the fluid to form a layer of sediment. Several factors influence how sediment settles. Sediment is removed from new surface locations. Precipitation is the change of state of a gaseous substance into a solid.
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Create a table showing how each type of radiation
affects the atomic number and mass number of an
atom.
The emitting element's atomic number and atomic mass number are both reduced by 2 and 4 respectively by alpha radiation. The atomic number of an element is increased by 1 by beta radiation, but the atomic mass number is unaffected. The atomic number or the atomic mass number are unaffected by gamma radiation.
What is radiation ?An unstable atom will release energy on its own to move into a more stable state, which is radioactivity. The energy that is released by a radioactive atom is known as ionizing radiation. The term "radioactive isotope" refers to radioactive atoms of the same element with varying neutron counts.
Alpha radiation decreases the atomic number and atomic mass number of the emitting element by 2 and 4 correspondingly. Beta radiation raises an element's atomic number by 1, but it has no effect on its atomic mass number. Gamma radiation has no impact on the atomic number or atomic mass number.
The atomic or mass number are unaffected by the emission of gamma rays, however the nucleus will become more stable. The most significant change in atomic number and mass number is brought on by alpha radiation.
A table showing how each type of radiation affects the atomic number and mass number of an atom is attached in the image below.
Thus, The emitting element's atomic number and atomic mass number are both reduced by 2 and 4 respectively by alpha radiation.
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What two types of elements are ionic compounds made of?
Answer:
ionic compounds are made from metal and non mental elements
Explanation:
in this case it is know as an ionic compound because it contains a charge. For example, NaCl is simply a compound as it contains no charges (the charges cancel out as Cl is -1 and Na is +1)
but OH- is an ionic compound as it has a charge if -1 (O has a -2 charge and H has a +1 charge, so -2+1=-1 so OH has -1 charge)
The National Integrated Ballistic Information Network has information about what? DNA Bullets Fingerprints Irises
Answer:
Bullets
Explanation:
Ballistics is the analysis of projectiles and the only projectile in the list is a bullet.
2/3 CHM-251 Laboratory 7. Simmanic Acid Burmination Rev 11-08 Stereochemical results of syn and anti addition CHM-251 Laboratory 7. Simmanis Acid Bramination Rev 11-08 1/3 |CHM-251 Organic Chemistry and Laboratory Laboratory 7. The Bromination of trans-Cinammic Acid Ref. Modern Projects and Experiments in Organic Chemistry: Minical and Standard Taper Microscale, 2 EdJerry Mohriz. et a Freeman Press (2003), Experiment 16.2 pages 139-142. Laboratory Objectives: 1. Observe the bromination of an alkene as a representative addition reaction. 2. Perform TLC methods development to determine an appropriate solvent system to separate reactants and products in an organic reaction. 3 Use TLC as a means of determining how many products form in a reaction and as a method for determining if a reaction is complete. 4. Examine how the anti stereochemistry of brominations can be observed in acyclic sytems Introduction: The most common alkene reaction is electrophilic addition such that the double bond is replaced by two sigma bonds. Electrophilic addition reactions include reactions with polar reagents such as HBr, polarizable molecules such as bromine, and the use of noble metal (Pd, Pt) catalysts with non-polar molecules such as hydrogen. In all addition reactions the products have more atoms than the corresponding alkene. This laboratory will examine bromine addition to the double bond of cinnamic acid. Bromination of alkenes is a relatively straightforward reaction. Liquid bromine is hazardous in that it is corrosive and an oxidizing reagent. However, bromine is soluble in 2. number of solvents and bromine solutions in water and in organic solvents reduce the hazards of working with bromine substantially. Cinnamic acid (structure below) will react with bromine to give 2,3-dibromo-3-phenylpropionic acid which is the product corresponding to the addition of bromine across the double bond. Brominations, exhibit trans stereochemistry which means that the bromines will be in a trans relationship if a cyclic alkene reacts. Cyclohexene would then be expected to give trams 1,2-dibromocyclohexane as a bromination product . In the case of - cinnamic acid there is no ring to observe the trans positions of the bromines. However the anti addition of bromine can still be confirmed if we examine the stereochemical consequences of this reaction in greater detail. It turns out that the product of anti and syn addition are stereoisomers of one another but not in a cis trans sense. In this case we have an example of a diastereomers (stereoisomers that are not mirror images of one another). The relationship between cis and trans 1,2-dibromocyclohexane is also diastereomeric but obvious to us since we see the bromines on the same or different sides of the ring. For cinnamic acid the two possible isomers are less obvious but are called the meso form and the D.L pair' (and both exist as a pair of mirror images or enantiomers). The designations threo and enthro are also used to differentiate these possible isomers which is based on the stereochemistry associated with the carbohydrates (sugars) threose and erythose? In order to see how these are different we will need to carefully consider the 3-D relationships that result from both syn and anti addition. Experimental: Bromination of Cinnamic Acid Transfer trans-cinnamic acid (150 mg, 1.0 moles) to a 5.0 mL conical vial containing a magnetic stir vane (triangular stir bar) and combine with 1.5 mL of dichloromethane. Set in an sand bath and stir the mixture until the cinnamic acid dissolves. Add 200 LL of 1.0 Mbromine in dichloromethane solution and connect a condenser to the vial. Heat the reaction mixture until the dichlormethane is refluxing. Once reflux has been achieved add four additional portions of the 1.0 M bromine solution waiting for the bromine color to disappear prior to each new addition Monitor the reaction by TLC after the last addition and reflux for 10 minutes. If cinnamic
The objective of the CHM-251 Laboratory 7 is to observe the bromination of trans-cinnamic acid and examine the stereochemical consequences of the reaction to determine the anti and syn addition of bromine.
TLC methods are also used to separate reactants and products, determine the number of products formed, and if the reaction is complete. The bromination of alkenes is an electrophilic addition reaction, and bromine exhibits trans stereochemistry.
In the case of trans-cinnamic acid, the anti addition of bromine can still be confirmed by examining the stereochemical consequences of the reaction, which results in two diastereomers - the meso form and the D.L pair - that exist as a pair of mirror images or enantiomers. The experiment involves adding 1.0 M bromine solution to the reaction mixture and monitoring the reaction by TLC.
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when a tennis ball is dropped from a high distance is it elastic or inelastic collision? explain?
Answer:
An elastic collision.
Explanation:
When a ball is dropped to the ground, one of four things may happen: It may rebound with exactly the same speed as the speed at which it hit the ground. This is an elastic collision.
I’m having trouble on problem number 5. and I can’t find the answer, and I could really use some help.
Saponification is the formation of a sodium carboxylate bt the reaction of sodium hydroxide on aSteroidTriglycerideWaxMethyle ester
Saponification is a chemical reaction that involves the formation of a sodium carboxylate (also known as soap) through the reaction of sodium hydroxide with certain types of organic compounds.
These organic compounds can include steroids, triglycerides, waxes, and even methyl esters. When sodium hydroxide is added to these compounds, it causes a chemical reaction that breaks down the ester bonds and releases the fatty acid components. The fatty acid components then react with the sodium hydroxide to form the sodium carboxylate or soap. This process is commonly used in the production of soap and other cleaning products.
saponification is a process in which a triglyceride (fat or oil) reacts with sodium hydroxide (a strong base) to produce glycerol and sodium carboxylate salts, which are commonly known as soap. The reaction can be summarized in the following steps:
1. Sodium hydroxide (NaOH) is mixed with a triglyceride, which consists of a glycerol molecule bound to three fatty acid chains.
2. The base (NaOH) breaks the ester bonds between the glycerol molecule and the fatty acid chains, releasing glycerol and free fatty acids.
3. The sodium ions (Na+) from the sodium hydroxide react with the carboxylate groups (COO-) of the free fatty acids to form sodium carboxylate salts (soap).
This reaction is used in the production of soap and in the conversion of fats and oils to various other useful products.
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an equimolar mixture of two optical isomers is called a
An equimolar mixture of two optical isomers is called a racemic mixture or a racemate.
Both enantiomers or optical isomers, are equally present in a racemic mixture. Enantiomers are molecules that share the same connectivity and chemical formula but differ in how they are arranged in three dimensions, creating mirror-image structures. The polarised light plane can rotate in opposing orientations for each enantiomer.
However, when they are combined in equal amounts, their optical rotations cancel one another out, resulting in a racemic mixture that is net optically inactive. Racemic mixes, which differ from their individual enantiomers in a variety of ways, are frequently seen in chemical and biological systems.
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