what is meant by inertia​

Answer:

Step-by-step explanation:

What an interesting question!

The question is whether you use the interior or exterior angle. Let's take a few examples and see if we can answer that.

Equilateral triangle: would take 120 degrees.

Square: you can't tell, but 90 degrees would be a good choice.

Pentagon: 72 degrees

Hexagon: 60 degrees

Octagon: 45.

It looks like the pattern is just to take the number of sides and divide it into 360.  

Hence for a 96 n-gon the answer would be 360 / 96 = 3.75

Answer:

y = -2x - 3

Step-by-step explanation:

The slopes of two perpendicular lines are negative reciprocals of each other. So slope of s is -2

using m = -2, x = 2, y = -7

y = mx + b

-7 = (-2)(2) + b

-7 = -4 + b

b = -3

y = -2x - 3

The function f(x) is greater than zero when the value of x lies in between -3 and 5 and this can be determined by using the given graph.

Graph is a mathematical representation of a Networks and it's describes the relation between lines and points.

The graph of the function f(x) is given.

The following steps can be used in order to determine the interval for f(x):

Step 1 - The value of f(x) means the value of y.

Step 2 - The value of f(x) is positive when the graph of f(x) is in the first or in the second quadrant.

Step 3 - So, according to the graph function f(x) is positive when the value of x is in between -3 and 5.

Therefore, the correct option is 3).

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Answer:

i mean might as well get free points now that its 2 weeks old

Step-by-step explanation:

Answer:

Pythagorean Theorem: the diagonal of the football field is the hypotenuse. Let´s say the diagonal is C and the two other sides are A and B.

Width = A

Length = B

Diagonal = C

so: a2+b2=c

2502+1002=c2

2500+10000=c2

12500=c2

c=√12500

c=111.80 yards

Step-by-step explanation:

the ambitous jackle

The translation of the compound statement into propositional logic notation is as follows: T ∧ (E ↔ (F ∧ ¬O)).

In propositional logic notation, the compound statement is broken down into individual propositions using sentence letters and logical operators. Here, T represents "Today is Thanksgiving Day," E represents "I will eat the turkey," F represents "The turkey is free range," and O represents "The turkey has been tortured." The compound statement can be translated as T ∧ (E ↔ (F ∧ ¬O)), where ∧ represents the logical AND operator, ↔ represents the logical biconditional operator (if and only if), and ¬ represents the logical NOT operator (negation). This notation captures the conjunction of the conditions and the relationships between them.

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The required 24th derivative of the function  \(f(x) = cos(x)\) is also the function  \(f(x) = cos(x)\).

To find the 24th derivative of the function \(f(x) = cos(x)\), we can use the properties of the derivative of trigonometric functions.

The derivative of the function \(f(x) = cos(x)\) is given by:

\(f'(x) = -sin(x)\),

\(f''(x) = -cos(x)\)

\(f'''(x) = sin(x)\)

\(f''''(x) = cos(x)\)

\(24th=(-1)^{24}cosx=cosx\)

\((-1)^{24}cosx=cosx\)

Therefore, the 24th derivative of the function  \(f(x) = cos(x)\) is also the function \(f(x) = cos(x).\)

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When each vertex of the square is located on the circumference of the circle, each side of the square measures 5.971 cm.

As per Geometry and trigonometry, a square has equilateral triangle sides and four equal angles, making itself an equilateral quadrilateral. Other name for it is a triangle with two adjacent vertices that are the same length. An equilateral quadrant is one that has four equal ends and four equal angles, like a square. Angles that are 90 degrees or straight are square angles. The downtown's diagonals are also split at a right angles and are evenly spaced. a rectangle with approximately consecutive sides that is adjacent. a trapezoid with four equal sides and straight angles on all four sides. a parallelogram with two adjacent sides that seem to be equal and make a right angle. rhombus has straight sides.

given

If the square perfectly fits the circle, then the circle's diameter is the same as the square's diagonal. The square's diagonal also has a length of cm because each side of the square is cm long. The square's diagonal can be determined using the area of the circle, as shown below:

area = \(\pi\)*r *r

r*r = 56/pi

r = 4.22

As the square's diagonal and the circle's diameter are equal, x = 5.971 cm.

When each vertex of the square is located on the circumference of the circle, each side of the square measures 5.971 cm.

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The profit-maximizing output level and the associated profit are both zero.

What is the equivalent expression?

Equivalent expressions are expressions that perform the same function despite their appearance. If two algebraic expressions are equivalent, they have the same value when we use the same variable value.

To find the minimum value of SRATC, we need to first find the expression for SRATC:

SRATC = SRTC/q = (200 + 109 + 2q)/q = 309/q + 2

To minimize SRATC, we need to differentiate it with respect to q and set it equal to zero:

d(SRATC)/dq = -309/q² = 0

Solving for q, we get q = √(309).

Substituting q back into the expression for SRATC, we get the minimum value of SRATC:

\(SRATC_{min}\) = 309/√(309) + 2 ≈ 17.22

Therefore, the value of q that minimizes SRATC is √(309) and the minimum cost value of SRATC is approximately $17.22.

If the market price is $90, the profit-maximizing value of q can be found by setting marginal cost equal to price:

MC = d(SRTC)/dq = 109 + 4q/3 = 90

Solving for q, we get q = (3/4)(90 - 109) = -14.25, which is not a feasible value since q has to be non-negative.

Therefore, the firm would not produce any output at a price of $90.

If we assume that the firm can produce any positive amount of output, the profit-maximizing value of q would be where marginal cost equals marginal revenue, which is also equal to price under perfect competition.

Since marginal revenue equals price for a perfectly competitive firm, we have:

MR = price = $90

Setting MR = MC, we get:

90 = 109 + 4q/3

Solving for q, we get q = (3/4)(90 - 109) = -14.25, which is not a feasible value.

Therefore, the firm would not produce any output at a price of $90, regardless of the assumption of being able to produce any positive amount of output.

Hence, the profit-maximizing output level and the associated profit are both zero.

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Answer:

60+50+10=120

120-100=20

10 students got failed in both the subject see the attached Venn diagram

A diagram that shows mathematical or logical sets as closed curves or circles inside of a rectangle (the universal set), with the intersections of the circles signifying the sets' common constituents.

Given, Out of 100 students who appeared in the grade 8 annual examination of Ram Janaki Secondary School, 60 students passed in Mathematics, 50 in Science, and 20 students in both subject.

Passed in mathematics = 60

passed in science = 50

passed in both subjects = 20

Hence, failed in both subjects = 100 - ( 60 + 50 - 20 ) = 10

Therefore, failed students in both subjects are 10 see the Venn diagram below.

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A Negative correlation coefficient means that as one variable increases, the other decreases (i.e., an inverse relationship).

Answer: it is the 4 one which is 3(5-n)=2n+16

Therefore, there are 1320 ways the teams can win gold, silver, and bronze medals in the science competition.

To determine the number of ways the teams can win gold, silver, and bronze medals, we can use the concept of permutations. For the gold medal, there are 12 teams to choose from, so we have 12 options. Once a team is awarded the gold medal, there are 11 teams remaining.

For the silver medal, there are now 11 teams to choose from since one team has already received the gold medal. So we have 11 options. Once a team is awarded the silver medal, there are 10 teams remaining. For the bronze medal, there are 10 teams to choose from since two teams have already received medals. So we have 10 options.

To find the total number of ways, we multiply the number of options at each step:

Total number of ways = 12 * 11 * 10

Total number of ways = 1320

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we have

5/x=15/24

solve for x

Multiply in cross

15*x=24*5

x=24*5/15

x=8

If the endpoints of DE where D(-3, y) and E(x, 6) with the midpoint M(4, 2), the length of DE is 16.12 units

The formula for calculating the midpoint is expressed as;

\(M(x,y)=(\frac{x_1+x_1}{2}, \frac{y_1+y_2}{2})\)

For the x-coordinate points:

X = -3+x/2

4 * 2 = -3 + x

8 = -3 + x

x = 8 + 3

x = 11

Get the value of y;

2 = y+6/2

y+6 = 2 * 2

y + 6 = 4

y = 4 - 6

y = -2

Hence the coordinates of D and E are D(-3, -2) and E(11, 6)

\(D=\sqrt{(6-(-2))^2+(11-(-3))^2}\\D=\sqrt{8^2+14^2}\\D=\sqrt{64 + 196}\\D= \sqrt{260}\\D= 16.12units\)

Hence the length of DE is 16.12 units

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The public library used 83 square feet of glass to build the aquarium.

To calculate the total square footage of glass used to build the aquarium, we need to consider the surface area of each side of the rectangular prism.

The rectangular prism has a base with dimensions of 6 feet by 2.5 feet. Since the top of the aquarium is open, we only need to consider the four sides (front, back, and two sides) and the bottom.

The area of each side can be calculated by multiplying the length by the width.

Front and back sides:

Area = length \(\times\)  height = \(6 ft \times 4 ft = 24\) square feet.

Side 1:

Area = width \(\times\) height \(= 2.5 ft \times 4 ft = 10\)  square feet

Side 2:

Area = width \(\times\) height \(= 2.5 ft \times 4 ft = 10\) square feet

Bottom:

Area = length \(\times\) width \(= 6 ft \times 2.5 ft = 15\) square feet

To find the total square footage of glass used, we sum up the areas of all the sides:

Total area = Front + Back + Side 1 + Side 2 + Bottom

= 24 sq ft + 24 sq ft + 10 sq ft + 10 sq ft + 15 sq ft

= 83 square feet.

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Answer:

(0.5, 8.5)

Step-by-step explanation:

use this formula ((x1+x2/2), (y1+y2/2)) if you use desmos graphing calculator and you type this formula in, all you have to do it put in the correct numbers and you get your midpoint.

Hope this helped :)

The midpoint of the segment between the points (−5,13) and (6,4) are (0.5 and 8.5)

We have given that, the points (−5,13) and (6,4)

We have to determine the midpoints

((x1+x2/2), (y1+y2/2))

x1=-5,x2=6,y1=13 and y2=4

-5+6/2=1/2=0.5

and next is,

13+4/2=17/2=8.5

The midpoint of the segment between the points (−5,13) and (6,4) are (0.5 and 8.5)

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The average rate of change per minute in the amount downloaded is 11.5 megabytes per minute

File size: 1400 megabytes

Start time of download: 7:00 pm

File size remaining to be downloaded: 825 megabytes

Time after one has done homework: 7:50 pm

Time elapsed: 50 minutes

File size downloaded: Total file size - File size remaining to be downloaded

= 1400 - 825 = 575 megabytes

Average rate of change per minute = File size downloaded/Time elapsed in minutes

= 575/50

= 11.5 megabytes per minute

So, the average rate of change per minute in the amount of download is 11.5 megabytes per minute

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For future reference, you multiply the rows of the first matrix by the columns of the second matrix.

A equation of the tangent line to the curve is y = 3x + 3

The term tangent line in math is calculated as an equation of the tangent line we have to find the derivative of the function and its value at the given point.

And then we have to the function given is a product of an exponential and cosine function. We will have to use product rule.

Finally, we have to write the equation of tangent line by point slope form.

Here we have the curve equation as,

=> y = 3eˣcos(x)

Now, we have to calculate the derivative y' from the given equation, then we get,

=> y' = = 3(eˣ (−sin x) + (cos x) eˣ)

Now, it can be simplified as,

=>y' = 3eˣ(cos x − sin x)

Here we have given that the the slope of the tangent line at (0, 3), then the value of

=> 3e⁰(cos0−sin0) = 3(1−0) = 3

Then the equation is written as

=> y − 3 = 3(x − 0)

=> y = 3x + 3

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The interquartile range of the given data set is 2.16.

The given data is 2.35, 1.56, 1.77, 2.45, 6.02, 4.38, 2.77, 5.23, 2.22 and 3.26.

The Interquartile Range (IQR) formula is a measure of the middle 50% of a data set. The smallest of all the measures of dispersion in statistics is called the Interquartile Range. The difference between the upper and lower quartile is known as the interquartile range.

Formula to find the interquartile range is Interquartile range = Upper Quartile - Lower Quartile =Q2=Q3-Q1

The  order of the given data is 1.56, 1.77, 2.22, 2.35, 2.45, 2.77, 3.26, 4.38, 5.23, 6.02.

Here,

Q1= 1/4 (n+1) = 11/4= 2.75

= 2.22

Q3 = 3/4 (n+1) = 8.25

= 4.38

Q2 =4.38-2.22

= 2.16

Therefore, the interquartile range of the given data set is 2.16.

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The answer is the lower bound theorem identifies -2 as a lower bound for the real zeros of f(x). The upper bound theorem does not specify any upper bound for the real zeros of (x)

The Lower bound theorem states that "If the terms of a polynomial are arranged in descending order of their degrees, then the absolute value of the quotient of the constant term and the coefficient of the term of the highest degree gives a lower bound for the absolute value of its zeros." Let's examine whether the lower bound theorem identifies -2 as a lower bound for the real zeros of f(x) and whether 3 is an upper bound for the real zeros of (x).

As f(x) = 56 = x + 17x² + 11x + 23Since f(x) is not arranged in descending order of their degrees, we have to rearrange it as follows. 17x² + 11x + x + 23 + 56 = 17x² + 12x + 79 on rearranging the equation we have: 17x² + 12x + 79 = 0Hence the constant term is 79 and the coefficient of the term of the highest degree is 17. Thus, using the lower bound theorem, we can evaluate that a lower bound for the absolute value of the zeros of the polynomial is 79/17 ≈ 4.65 Since -2 is less than the calculated lower bound of 4.65, it is indeed a lower bound for the real zeros of f(x). Now, for (x), the constant term is 0, and the coefficient of the term of the highest degree is 1. Thus, using the upper bound theorem, we can evaluate that an upper bound for the absolute value of the zeros of the polynomial is 1/0, which is equal to infinity. Since infinity is not a number, 3 cannot be an upper bound for the real zeros of (x).

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Answer:

3^6

Step-by-step explanation:

3^8 * 3^-2

3^(8-2)

3^6

If the average of vehicles is 35.7 mpg then

(a) the variable is found to be "average miles per gallon .

(b) The variable is quantitative .

In the question ,

we are studying about the average miles per gallon (mpg) for new hybrid small cars .

by consumer reports the random sample of such vehicles gave an average of 35.7 mpg .

Part (a)

here the variable is "average miles per gallon(mpg) " , because it varies with the different cars .

Part(b) ;

This variable is Quantitative , because here we are studying about the term "how much" that means : average miles per gallon .

Therefore , the variable is "average miles per gallon" and is quantitative .

The given question is incomplete , the complete question is

The average miles per gallon (mpg) for all new hybrid small cars , Using Consumer Reports, a random sample of such vehicles gave an average of 35.7 mpg.

(a) Identify the variable.

(b) Is the variable quantitative or qualitative ?

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Answer:

2(4)-3+5

Step-by-step explanation:

8-3+5

13-3

10

Answer:

i would say a

Step-by-step explanation:

Answer:

x > -12

Step-by-step explanation:

Think of X as 1, so its kinda like 1x, so (1x+4=5x). Times the 2, = 10x.

1. X + 4 = 5x

2. 5x · 2 = 10x

3. Place the variables, X > -12

Answer: X > -12

Step-by-step explanation:

cotA + tanA

= cosA / sinA+ sinA/ cosA

= cos2A + sin2A / sinA* cosA

= 1 / sinA* cosA

=1/ sinA * 1/ cosA

= cosecA *secA

=secAcosecA

\(\frac{cos^2A + sin^2A}{sinAcosA}\)Answer:

Step-by-step explanation:

cotA + tanA = secAcosecA

LHS=cotA + tanA

=\(\frac{cosA}{sinA}\) + \(\frac{sinA}{cosA}\)

take lcm of the denominator

=\(\frac{cosA*cosA + sinA*sinA}{sinAcosA}\)(COS^2A + sin^2A =1)

=\(\frac{1}{sinAcosA}\)

=1/sinA * 1/cosA

=cosecA*secA

=secAcosecA

therefore LHS=RHS

hence proved.

Answer:

We conclude that:

Yes; Each input has only one output.

Step-by-step explanation:

From the given arrow diagram, we can easily determine the table

x            y

2           24

4           8

6          16

8          32

10         32

From the table, it is clear that each input has only one output, in other words, each possible x  value is leading to exactly one y value.

Meaning there is no repetition of any domain (x) value.

Therefore, we conclude that:

Yes; Each input has only one output.

The greatest common factor (GCF) of -8dm² and 24d²m is 8dm. This can be determined by identifying the common factors and taking the highest power of each factor.

To find the greatest common factor (GCF) of -8dm² and 24d²m, we need to determine the largest expression that can divide both terms without leaving any remainder.

Let's break down each term into its prime factors:

-8dm² can be expressed as (-1) * 2³ * d * m²

24d²m can be expressed as 2³ * 3 * d² * m

To find the GCF, we look for the common factors between the two expressions. The highest power of each common factor is taken.

The common factors between the two expressions are 2, d, and m. We take the highest power of each factor, which is 2³ * d * m. Simplifying this, we get 8dm.

Therefore, the greatest common factor of -8dm² and 24d²m is 8dm.

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To calculate Randy's commission, we need to find 4.5% of the amount he sold in car stereos.

First, we convert the percentage to decimal form by dividing it by 100:

4.5% = 4.5/100 = 0.045

Next, we multiply the amount Randy sold by the commission rate:

Commission = $765.86 * 0.045

Commission = $34.4637 (rounded to four decimal places)

Therefore, Randy earns approximately $34.46 in commission.

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