Answer:
The angular velocity is: (2π radians) ⁄ (4.3 sec) = 1.461 rad/sec
The angular displacement is: (1.461 rad/sec)(1 sec) = 1.461 radians
Explanation:
A physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance 1.5 cm from the end (top). What is the period of oscillation
The period of oscillation of the physical pendulum is 2.40 s.
Where T is the period of oscillation, I is the moment of inertia, m is the mass of the pendulum, g is the acceleration due to gravity, and d is the distance between the center of mass of the pendulum and the pivot point. In this case, since the meter stick is pivoted at a small hole drilled through the stick a distance 1.5 cm from the end (top), the distance between the center of mass of the pendulum and the pivot point (d) is equal to the length of the meter stick minus 1.5 cm (i.e., l - 1.5 cm).
The moment of inertia of a meter stick pivoted at one end is given by:
\(I = \frac {1} {3} ml^2\)
where m is the mass of the pendulum and l is the length of the meter stick.
Thus, in this case, the moment of inertia is given by:
\(I = \frac {1}{3} \c dot 0.5 \text {kg} \ c dot (1 \text {m} - 0.015 \text {m}) ^2 = 0.039 \text {kg} \c dot \text{m}^2\)
The acceleration due to gravity is approximately 9.8 m/s^2.
Thus, the period of oscillation is:
\(T = 2\pi \sqrt{\frac {0.039 \text{ kg}\c dot \text{m}^2} {0.5 \text{ kg} \c dot 9.8 \text{ m/s}^2 \c dot (1 \text{ m} - 0.015 \text{ m})}} \ approx 2.40 \text{ s}\)
Therefore, the main answer is: The period of oscillation of the physical pendulum is 2.40 s.
: F or a physical pendulum, the period of oscillation can be calculated using the above formula. In this case, a meter stick is being used as the pendulum. The meter stick is pivoted at a small hole drilled through the stick a distance 1.5 cm from the end (top). In order to find the period of oscillation, it is necessary to first determine the moment of inertia, the distance between the center of mass of the pendulum and the pivot point, the mass of the pendulum, and the acceleration due to gravity. The moment of inertia is given by the equation:
\(I = \frac {1}{3} ml^2\)
where m is the mass of the pendulum and l is the length of the meter stick. Since the mass of the meter stick is 0.5 kg and its length is 1 meter, the moment of inertia is calculated as:
\(I = \frac{1}{3} \c dot 0.5 \text{ kg} \c dot (1 \text{ m} - 0.015 \text{ m})^2 = 0.039 \text{ kg}\c dot \text{m}^2\)
The distance between the center of mass of the pendulum and the pivot point (d) is equal to the length of the meter stick minus 1.5 cm (i.e., l - 1.5 cm). This distance is equal to 0.985 meters. The mass of the pendulum is 0.5 kg. The acceleration due to gravity is approximately 9.8 m/s^2.Using these values, we can calculate the period of oscillation of the physical pendulum using the formula:
Substituting the values for I, m, g, and d into the formula, we get: \(T = 2\pi \sqrt {\frac{0.039 \text { kg}\c dot \text {m}^2} {0.5 \text{ kg} \c dot 9.8 \text{ m/s}^2 \c dot (1 \text{ m} - 0.015 \text{ m})}} \approx 2.40 \text{ s}\)
The period of oscillation of the physical pendulum is 2.40 s.
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PLEASE HELP ME QUICKLY!!!!!!!!!!!!!!
Answer:
I think thats the correct answer
Explanation:
What is the mechanical advantage of a pulley? 0.5 1.0 1.5 2.0
The mechanical advantage of a pulley is the ratio of the output force to the input force.
For example, if a pulley is used to lift a weight of 100 pounds, and the input force is 10 pounds, then the mechanical advantage is 10:1 (100/10).
This means that for every 10 pounds of input force, the pulley can lift 100 pounds of weight. The mechanical advantage of a pulley is determined by the number of strands of rope that are used in the pulley system. The more strands of rope, the higher the mechanical advantage will be.
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Define colinear forces
Answer: Collinear forces are forces that have a common line of action, i.e. the line of action of the forces lies along a single straight line.
Explanation:
How much force is required to keep a 2-kg object moving to the right with a constant speed of 6.0 m/s?
A. 0 m/s
B. .33 m/s
C. 3 m/s
D. 12 m/s
The force required to keep a 2 kg object moving to the right with a constant speed of 6.0 m/s is calculated to be 0 N.
It is given that the mass of the object m is 2 kg.
As the body is said to be moving with constant speed, its acceleration would be rate of change of velocity, which would be zero.
Acceleration a = 0
Now, let us calculate the force required to move the 2 kg object. From Newton's second law, we know the expression, F = m a.
where,
m is mass
a is acceleration
F = m a = 2 × 0 = 0 N
Thus, the required force to move the object in right direction is calculated to be 0 N.
The given options have inappropriate units. They should be in Newtons.
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Which effect has been useful (and successful) in the search for and identification of black holes in the universe
Answer:
Detection of x-rays from a binary star undergoing mass exchange, where mass of component star can be determined.
What is responsible for the observed motion of a star along the celestial equator?
The observed motion of a star along the celestial equator is caused by Earth's rotation. This motion is known as diurnal motion or apparent motion.
As the Earth rotates on its axis, the stars appear to move in a circular path around the celestial pole, and stars near the celestial equator appear to move in a straight line along the celestial equator.This is the main answer to the given question.
Earth's rotation is responsible for the observed motion of a star along the celestial equator. The motion is known as diurnal or apparent motion, and it occurs because of the Earth's rotation on its axis. As the Earth rotates, the stars seem to move in a circular path around the celestial pole, and the stars near the celestial equator seem to move in a straight line along the celestial equator. This motion is an illusion caused by the Earth's rotation, and it allows astronomers to track the positions of stars and other celestial bodies.
Earth's rotation is the reason behind the motion of a star along the celestial equator. It is known as diurnal or apparent motion, which is an illusion.
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An object with a mass of 5 kg is accelerated from rest by a 60 N*s impulse. What is the change in the object's velocity?
Hi there!
Using the Impulse-Momentum theorem:
I = Δp = mΔv
Where:
I = Impulse (Ns)
m = mass of object (kg)
Δv = change in velocity (vf - vi, m/s)
Plug in the given values and solve:
60 = 5Δv
Δv = 12 m/s
A Chevy Camaro drives straight off the top level off a parking garage at 13 m/s. If the car landed 90 meters away from the base of the parking garage, how high (height) was the top level?
a200.64
b234.64
c34.64
d134.64
Answer:
234.64 m
Explanation:
Using the formula for calculating range;
Range R = u√2H/g
u is the speed = 13m/s
H is the maximum height
g is the acceleration due to gravity = 9,8m/s²
R = 90m
Get the maximum height;
90 = 13√2H/9.8
90/13 = √2H/9.8
6.923 = √2H/9.8
square both sides
6.923² = 2H/9.8
469.698 = 2H
H = 469.698/2
H = 234.64
Hence the top level was 234.64 m high.
The solar constant at Earth is 1,360 W/m². What is the solar constant at Jupiter which is 5.2 times as far from the Sun as Earth? so.33 watt per savave In that case calculate the surface temperature of Jupiter. Assume an emissivity e = 0.8. The Stefan-Boltzmann constant is 5.67 x 10 W/mʻk.
The solar constant at Jupiter is approximately 33 W/m². Given this solar constant, additional calculations are required to determine the surface temperature of Jupiter, including consideration of emissivity, the Stefan-Boltzmann constant, and other factors.
The solar constant is the amount of solar electromagnetic radiation received at the outer atmosphere of a celestial body, typically measured in watts per square meter (W/m²). Given that the solar constant at Earth is 1,360 W/m², we can calculate the solar constant at Jupiter, which is 5.2 times as far from the Sun as Earth.
The solar constant follows the inverse square law, which states that the intensity of radiation decreases with the square of the distance from the source. Therefore, the solar constant at Jupiter can be calculated using the following equation:
Solar constant at Jupiter = Solar constant at Earth * (Distance from the Sun at Earth / Distance from the Sun at Jupiter)²
Solar constant at Earth = 1,360 W/m²
Distance from the Sun at Earth = 1 AU (approximately 149.6 million km)
Distance from the Sun at Jupiter = 5.2 AU
Substituting these values into the equation, we have:
Solar constant at Jupiter = 1,360 W/m² * (1 AU / 5.2 AU)²
= 1,360 W/m² * (1/5.2)²
≈ 1,360 W/m² * 0.035256
≈ 47.93 W/m²
Therefore, the solar constant at Jupiter is approximately 47.93 W/m². Rounded to the nearest whole number, the solar constant at Jupiter is 48 W/m².
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if the magntidude of the sum and difference of two non zero vectors A and B is equal. what can we say about the two vectors
Answer:
A + B = B - A
The above equation must hold for the sum and difference to be zero.
How can one of the vectors not be zero?????
Diagram 7 shows the velocity-time graph of an
object for 12 s.
When is the object at a distance of one-quarter of
the total distance travelled in the 12 s?
A 3 s
B 4 s
C 5 s
D 6 s
*The answer is D but can anyone tell me the solving steps? Or perhaps the answer is wrong?*
Answer:
t = 6
Explanation:
Displacement is equal to the area under a velocity vs time graph.
In this case, the area is a triangle. At time t, the base of the triangle is t. The height of the triangle can be found with similar triangles:
h / t = 8 / 12
h = ⅔ t
So the distance traveled at time t is:
d = ½ (t) (⅔ t)
d = ⅓ t²
The distance traveled at time 12 is:
D = ½ (12) (8)
D = 48
We want to find when d = D/4.
d = D/4
⅓ t² = 48/4
⅓ t² = 12
t² = 36
t = 6
Alternatively, since the acceleration is constant here, we could use a constant acceleration equation.
Δx = v₀ t + ½ at²
Given v₀ = 0 m/s and a = ⅔ m/s²:
Δx = (0) t + ½ (⅔) t²
Δx = ⅓ t²
When t = 12, Δx = 48.
⅓ t² = 48/4
t = 6
If a train going 60 m/s hits the brakes, and it takes the train 85 seconds to stop, what is
the train's acceleration?
Question :-
If a Train going with 60 m/s Speed hits the Brakes, and takes 85 sec to stop. What is the Acceleration of the Train ?Answer :-
Acceleration of Train is 0.70 m/s² .Explanation :-
As per the provided information in the given question, we have been given that the Speed of the Train is 60 m/s . Time taken to stop the Train is 85 sec . And, we have been asked to calculate the Acceleration of the Train .
For calculating the Acceleration , we will use the Formula :-
\( \bigstar \: \: \: \boxed { \sf{ \: Acceleration \: = \: \dfrac{v \: - \: u}{t} \: }} \\ \)
Where ,
V denotes to Final Velocity .U denotes to Initial Velocity .T denotes to Time Taken .Therefore , by Substituting the given values in the above Formula :-
\( \dag \: \: \: \: \sf{Acceleration \: = \: \dfrac{Final \: Velocity \: - \: Initial \: Velocity}{Time} } \\ \)
\( \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{0 \: - \: 60}{85} } \\ \)
\( \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{60}{85} } \\ \)
\( \longmapsto \: \: \: \textbf {\textsf {Acceleration \: = \: 0.70 }} \)
Hence :-
Acceleration = 0.70 m/s² .\( \underline {\rule {210pt} {4pt}} \)
Note :-
Kindly Scroll the Screen from Right to Left for Better View .Answer:
Question :-
If a Train going with 60 m/s Speed hits the Brakes, and takes 85 sec to stop. What is the Acceleration of the Train ?
Answer :-
Acceleration of Train is 0.70 m/s² .
Explanation :-
As per the provided information in the given question, we have been given that the Speed of the Train is 60 m/s . Time taken to stop the Train is 85 sec . And, we have been asked to calculate the Acceleration of the Train .
For calculating the Acceleration , we will use the Formula :-
\begin{gathered} \bigstar \: \: \: \boxed { \sf{ \: Acceleration \: = \: \dfrac{v \: - \: u}{t} \: }} \\ \end{gathered}
★
Acceleration=
t
v−u
Where ,
V denotes to Final Velocity .
U denotes to Initial Velocity .
T denotes to Time Taken .
Therefore , by Substituting the given values in the above Formula :-
\begin{gathered} \dag \: \: \: \: \sf{Acceleration \: = \: \dfrac{Final \: Velocity \: - \: Initial \: Velocity}{Time} } \\ \end{gathered}
†Acceleration=
Time
FinalVelocity−InitialVelocity
\begin{gathered} \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{0 \: - \: 60}{85} } \\ \end{gathered}
⟼Acceleration=
85
0−60
\begin{gathered} \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{60}{85} } \\ \end{gathered}
⟼Acceleration=
85
60
\longmapsto \: \: \: \textbf {\textsf {Acceleration \: = \: 0.70 }}⟼Acceleration = 0.70
Hence :-
Acceleration = 0.70 m/s² .
\underline {\rule {210pt} {4pt}}
Note :-
Kindly Scroll the Screen from Right to Left for Better View .
What are the three primary particles that make up an atom and what are associated with electromagnetic charges
Answer:
It's (c). ..........................
Find the missing force
The force is 220N.
What is force?Force is a physical influence that causes an object to accelerate, slow down,stop or change its direction. Forces can be external, like gravity or the push of a hand, or internal, like the tension of a rope or the thrust of a jet engine. Forces are measured in Newtons, named after the scientist who discovered them. Forces always act in pairs, so when one object exerts a force on another, the second object also exerts an equal and opposite force.
We know that,
F=ma
F=10×(-4)
=-40N
Given,
F1=100
F2=80
=F=(F1+F2)-F3
=-40=(100+80)-F3
=-40-180= -F3
=-220=F3
=F3=220N
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A(n) ____ like rubber or plastic has high electrical resistance.
Answer:
insulator
Explanation:
Determine the launch speed of a horizontally launched cannonball that lands 26.3
meters from the base of a 19.3 meter high cliff.
Answer:
The cannon has an initial speed of 13.25 m/s.
Explanation:
The launched cannonball is an example of a projectile. Thus, its launch speed can be determined by the application of the formula;
R = u\(\sqrt{\frac{2H}{g} }\)
Where: R is the range of the projectile, u is its initial speed, H is the height of the cliff and g is the gravitaty.
R = 26.3 m, H = 19.3 m, g = 9.8 m/\(s^{2}\).
So that:
26.3 = u\(\sqrt{\frac{2*19.3}{9.8} }\)
\((26.3)^{2}\) = \(u^{2}\) x \(\frac{38.6}{9.8}\)
691.69 = \(u^{2}\) x \(\frac{38.6}{9.8}\)
\(u^{2}\) = \(\frac{691.69*9.8}{38.6}\)
= \(\frac{6778.562}{38.6}\)
\(u^{2}\) = 175.6104
⇒ u = \(\sqrt{175.6104}\)
= 13.2518
u = 13.25 m/s
The initial speed of the cannon is 13.25 m/s.
Hot water is poured into a mug and the mug gets hot. This is an example of which type of energy transfer?
A) Radiation
B) Conduction
C) Convection
D) This is not an energy transfer
Answer:
conduction i think
Explanation:
Answer:Conduction
Explanation:
Define the following:
Potential energy
Kinetic energy
Mechanical energy
Chemical energy
Sound energy
Light energy
Nuclear energy
Answer
potential energy is the energy that is stored in an object due to its position relative to some zero position. An object possesses gravitational potential energy if it is positioned at a height above (or below) the zero height.
Kinetic energy is a form of energy that an object or a particle has by reason of its motion. ... Kinetic energy is a property of a moving object or particle and depends not only on its motion but also on its mass.
The energy of an object due to its motion or position; the sum of an object's kinetic energy and potential energy is called mechanical energy.
Energy stored in the bonds of chemical compounds. Chemical energy may be released during a chemical reaction, often in the form of heat; such reactions are called exothermic
Sound energy is defined as the movement of vibrations through matter. Sound energy is produced when an object vibrates, which results in noise. The sound vibrations cause waves of pressure that travel through a medium, such as air, water, wood, or metal.
Light energy is a kind of kinetic energy with the ability to make types of light visible to human eyes. Light is defined as a form of electromagnetic radiation emitted by hot objects like lasers, bulbs, and the sun. Light contains photons which are minute packets of energy.
Nuclear energy is energy in the nucleus (core) of an atom. ... It can be released from atoms in two ways: nuclear fusion and nuclear fission. In nuclear fusion, energy is released when atoms are combined or fused together to form a larger atom. This is how the sun produces energy.
The hull of a sunken boat, laying on the seabed, is 9 m below the surface of the sea, where the sea water has an average density of 1,025 kg/m3. The hull’s surface area is 12 m2. What is the total force exerted by seawater on the hull?Required to answer. Single line text.
Answer:
1084860 N
Explanation:
Applying,
P = ρgh................ Equation 1
Where P = pressure, ρ = density, h = height, g = acceleration due to gravity.
From the question,
Given: ρ = 1025 kg/m³, h = 9 m
Constant: g = 9.8 m/s²
Substitute these values into equation 1
P = (1025)(9)(9.8)
P = 90405 N/m²
Also,
P = F/A.............. Equation 2
Where, F = Force, A = Area.
Make F the subject of the equation
F = PA............... Equation 2
Given: A = 12m²
F = 12(90405)
F = 1084860 N
A hollow cylindrical (inner radius = 1.0 mm, outer radius = 3.0 mm) conductor carries a current of 80 A parallel to its axis. This current is uniformly distributed over a cross section of the conductor. Determine the magnitude of the magnetic field at a point that is 2.0 mm from the axis of the conductor.
Answer:
The magnetic field is \(B = 3 mT\)
Explanation:
From the question we are told that
The inner radius is \(r_i = 1.00 mm =1*10^{-3} \ m\)
The outer radius is \(r_2 = 3.00 \ mm = 3.0 *10^{-3} \ m\)
The distance from the axis of the conductor is \(d =2.0 \ mm = 2.0 *10^{-3} \ m\)
The current carried by the conductor is \(I = 80 A\)
According to Ampere's circuital law , the magnetic field at a point that is \(r_3\) from the axis of the conductor
\(B = \frac{\mu_oI}{2 \pi d } [\frac{d - r_1}{r_2 -r_1} ]\)
Where \(\mu_o\) is the permeability of free space with a value of \(\mu_o = 4 \pi *10^{-7} N/A^2\)
substituting values
\(B = \frac{(4 \pi *10^{-7})(80)}{2 * 3.142 * 2 *10^{=3} } [\frac{(2^2 - 1 ^2 )*10^{-3}}{(3^2 - 1^2) *10^{-3}} ]\)
\(B = 3 mT\)
The direction of applied force has to be .............. to the distance in order to say work is done
Answer:
Parallel
Explanation:
The work done is defined as the force applied on an object and the displacement in the position of the object in the direction of force.
W = F s cos A
where, F is the force, s is the displacement and A is the angle between force and displacement.
When the angle between the force and the displacement is 90 degree, the work done is zero.
To get the maximum work the angle between the force and the displacement is 0 degree.
So, to get the work done by the force the angle between the force and displacement is 0 degree that means the force and displacement is parallel to each other.
abunai hana has heard that she can obtain the most distance by shooting a crossbow bolt at a 45 degree angle above the positive x axis. her crossbow can shoot bolts at 30m/s. draw the vector triangle and decompose the vector into its x and y components.
vcos45 and vsin45 are the vector into its x and y components.
Vx=vcos45=15.75 m/s
Vy=vsin45=25.5 m/s
A vector is a quantity in physics that has both magnitude and direction. It is frequently depicted as an arrow with a length proportionate to the magnitude and a direction matching the magnitude of the quantity. While a vector has magnitude and direction, it lacks position. In other words, a vector's length won't change if it is shifted parallel to itself.
Even though a quantity has magnitude and direction, it must meet certain requirements in order to be classified as a vector. One of them is the vector addition formula, represented by the symbols A + B = C.
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Explain your thinking. What definition, rule, or reasoning did you use to decide
whether something is a solid?
Answer:
Explanation:
A Solid is one of the three main states of matter. By definition a solid is something whose molecules are so densely packed together that it allows it to keep its shape. Therefore if the item has a definite shape that does not change on it's own it is a solid. As opposed to a liquid which will take and fill the shape of it's container.
An object at rest stays at rest and an object in stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force is Newton’s 1st law of motion
True or false
Answer:
Hi I'm happy to meet you and the answer for your question is true. If you need me to state the law ask me
Which of the five criteria that define minerals explains why polymorphs are actually different minerals?
How long will it take a dump truck with a 5,000 ton load traveling 2,000km east with a constant velocity of 10,000km an hour
It will take the dump truck 0.2 hours to travel 2,000 km at a constant velocity of 10,000 km/h.
Kinematic motion problemTo solve this problem, we can use the formula:
time = distance/velocitywhere distance is 2,000 km and velocity is 10,000 km/h.
Plugging in the values, we get:
time = 2,000 km / 10,000 km/h = 0.2 hours
Therefore, it will take the dump truck 0.2 hours (or 12 minutes) to travel 2,000 km at a constant velocity of 10,000 km/h.
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Which two of the following are the waste products of anaerobic
respiration in yeast?
A sugar
B carbon dioxide
C water
D ethanol
What is the theorem of work energy?
The work-energy theorem is a fundamental principle in physics that relates the work done on an object to its change in kinetic energy.
The theorem states that the net work done on an object is equal to its change in kinetic energy:
Net Work = Change in Kinetic Energy
In other words, the work-energy theorem tells us that the work done on an object is equal to the change in its kinetic energy. If work is done on an object, its kinetic energy will change by an amount equal to the work done. Conversely, if the kinetic energy of an object changes, it must be due to work being done on the object.
The work-energy theorem applies to both conservative and non-conservative forces. For conservative forces, the work done depends only on the initial and final positions of the object, and not on the path taken between them.
For non-conservative forces, such as friction, the work done depends on the path taken and may result in a loss of mechanical energy.
The work-energy theorem is a powerful tool for analyzing and solving problems in physics, and it is widely used in many fields, including mechanics, thermodynamics, and electromagnetism.
It allows us to relate the work done on an object to its resulting motion and energy changes, providing a comprehensive picture of the physical system under consideration.
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What is the height of the coconut from the ground at the moment the arrow hit it?
Answer:
25 m.
Explanation:
As per the question the coconut is at the height of 25m from the ground and as per your question and from figure the height of the coconut from ground may be at 25m.