what is diffrence between damping and undamping?​

When materials vibrate, waves are created that travel through the substance, and this energy is what we hear as sound. Earthquakes are earth vibrations that cause the (potential) energy held within rocks to be released (as a result of their pressure-generating relative positions). Seismic waves are produced by earthquakes.

How do sound waves and earthquakes compare?

The waves lose energy as they move through the air with sound or through the ground with shaking during an earthquake. Therefore, a band can be heard louder close to the stage than farther away, and an earthquake can be felt more strongly close to the fault than farther away.

In actuality, sound in the air cannot match how quickly earthquake waves move. In rock, the compressional or "P" wave of an earthquake moves at the In actuality, sound in the air cannot match how quickly earthquake waves move. The speed of a P wave is typically 10,000 mph. The speed of sound through air is roughly 750 mph.

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We can see here that the diagram that reveals the absorption of photons and production of electrons (photoelectric effect) used in solar PV systems is seen below.

A photon is a fundamental particle or quantum of light.

It is the smallest indivisible unit of electromagnetic radiation, which also includes radio waves, microwaves, X-rays, visible light, ultraviolet light, and infrared radiation. In scientific calculations, photons are represented by the symbol "c" and move at the speed of light in a vacuum while carrying energy.

Wave-particle duality is the idea that photons are both particles and have wave-like characteristics. This means that they can exhibit wave-like properties like interference and diffraction as well as discrete particle behavior, each with a distinct energy and momentum.

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To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.

The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.

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The coefficient of linear expansion, given that the length of the pipe increased by 1.5 cm is 1.67×10¯⁵ /°F

From the question given above, the following data were obtained

The coefficient of linear expansion can be obtained as illustrated below:

α = ∆L / L₁∆T

α = 0.015 / (10 × 90)

α = 0.015 / 900

α = 1.67×10¯⁵ /°F

Thus, we can conclude that the coefficient of linear expansion is 1.67×10¯⁵ /°F

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The net force on q1 is 9.94 N.

From Coulomb's Law, the force between two point charges is given by:

where;

All the charges have the same charge and magnitude and are separated by the same distance.

The force between q1 and q2 is:

F12 = (9 * 10⁹ N * m²/C²) * (-2.35 x 10⁻⁶ C)² / (0.100 m)²

F12 = 4.97 N

The positive sign indicates that the force is repulsive

Similarly, the force between q2 and q3 is:

(9 * 10⁹ N * m²/C²) * (-2.35 x 10⁻⁶ C)² / (0.100 m)²

F12 = 4.97 N

The positive sign indicates that the force is repulsive

The net force on q1 will be:

Fnet = F12 + F23

Fnet = 4.97 N + (4.97)

Fnet = 9.94 N

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Answer:

AS USUAL SHE DID NOT TAKE PART

I’ll never forget what’s her name

A PE teacher and ogre she became

For I was such a sickly child

it really made this ogre wild

Held in my hand a medical certificate

exempted from all things physical

with Rheumatic Fever and St Vitus’ Dance

for me to take part ~ there was no chance

Instead I assisted the Deputy Head

with clerical duties I helped him instead

But clearly this really annoyed her

As she gave me her evil stare

She appeared to be looking right through me

No words were spoken ~ was I even there

Each and every year she wrote

inside my school report

A snide remark that ended with

“as usual she did not take part”

For I was told such illnesses

Could leave me with a weakened heart

And so upon Doctor’s orders

in PE I was not to take part

I can still see her face

As she filled me with fear

No compassionate words

from her lips I could hear

Whilst illnesses kept me off school for a year

It’s time I let go of this nasty so and so

For she left planet Earth a long time ago

And my heart ~ it still beats

I’m so glad to be here

With a smile on my face

I have no one to fear

Answer:

Explanation:

Physical education is important because it keeps you healthy and living longer

Answer:

hey so this website called quiz-let helps you it will give u the answer for every question i use it sometimes when im confused on a test.

It takes 0 seconds for the catcher to stop the ball and the ball travels 0 meters before stopping.

To find the time it takes for the catcher to stop the ball, you can use the equation:

time = distance / velocity

In this case, the distance is zero (since the ball is stopped) and the velocity is 21.80 m/s. Plugging these values into the equation gives us:

time = 0 / 21.80

time = 0 s

So, it takes 0 seconds for the catcher to stop the ball.

To find the distance the ball travels before stopping, you can use the equation:

distance = 1/2 * acceleration * time^2

In this case, the acceleration is the force applied to the ball divided by the mass of the ball, or (-360 N) / (0.18 kg) = -2000 m/s^2. The time is the time it takes the ball to stop, which we just found to be 0 s. Plugging these values into the equation gives us:

distance = 1/2 * (-2000 m/s^2) * (0 s)^2

distance = 0 m

So, the ball travels 0 meters before stopping.

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Answer:

V₁ = 48 m/s

Explanation:

Using the Conservative Law of Momentum:

∑Qₓ = 0

Q₁ + Q₂ = 0

Q₁ = Q₂  (In absolute values)

Where:

Q₁: right before the impact

Q₂: right after the impact

So:

Q₁ = Q₂

m₁*V₁ + m₂*V₂ = m₁*V + m₂*V  (Because both ball and man moves together)

5 * V₁ + 75 * 0 = (5 + 75)*3

5V₁ = 80 * 3

V₁ = 240/5

V₁ = 48 m/s

I go to k12 too and i am writing this test now too. I am like pretty sure my answer is correct. I guess we can kinda help eachother with this assignment cuz i am sorta stuck too.

I dont know i hope this helped a bit I know its not much i need help with this too.

From my calculations, the value for Q is Q = 4472.08 Btu

To calculate the heat stored and released by the floor, we can use the formula:

Q = MCΔT

where Q is the heat stored or released, M is the mass of the concrete, C is the specific heat of the concrete, and ΔT is the temperature change.

First, we need to calculate the mass of the concrete:

Volume = length x width x height

Volume = 12' x 12' x (10/12)'

Volume = 120 cubic feet

1 cubic foot of concrete weighs about 150 pounds, so the mass of the concrete is:

M = 120 x 150 = 18,000 pounds

We need to convert the pounds to pounds-mass, which is:

M = 18,000 / 32.2 = 559.01 slugs

Next, we need to calculate the specific heat of the concrete. The specific heat of concrete varies depending on the composition of the concrete, but a typical value is 0.2 Btu/lb·°F.

Using this value, we can calculate the heat stored or released by the floor:

Heat stored = MCΔT

Heat stored = 559.01 x 0.2 x (75 - 55)

Heat stored = 559.01 x 4

Heat stored = 2236.04 Btu

Heat released = MCΔT

Heat released = 559.01 x 0.2 x (55 - 75)

Heat released = 559.01 x (-4)

Heat released = -2236.04 Btu

The negative sign indicates that heat is being released, which makes sense since the temperature of the floor is decreasing overnight.

The total heat stored and released by the floor on a daily basis is:

Q = |Heat stored| + |Heat released|

Q = 2236.04 + 2236.04

Q = 4472.08 Btu

Therefore, the closest answer to the heat stored and released by the floor on a daily basis is option D, 4,472 Btu.

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Answer: Water fills the bucket until its force/weight is greater than the block’s. The lever tilts over, causing the bucket to water the plant.

B. The normal force that is exerted on the coaster by the track at the lowest point is 4.7 x 10⁴ N.

Fₙ = mg + mv²/r

where;

Fₙ = (2,000 x 9.8) + (2,000 x 18²)/24

Fₙ = 46,600 N

Fₙ =  4.7 x 10⁴ N

Thus, the normal force that is exerted on the coaster by the track at the lowest point is 4.7 x 10⁴ N.

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From the definition of half life, the half life is when the number of daughter nuclei equals the number of parent nuclei.

The half life is the time required for only about half of the number of radioactive isotopes to  remain.

We know that, the half life of an isotope shows when the number of daughter nuclei equals the number of parent nuclei.

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Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

Answer:

68000

Explanation:

1 MHz = 1000 Hz

just multiply by 1000 :)

Yes , if we heat 50 grams of cold sand and 50 grams of cold water the temperature changes according to the density of material i.e. if sand is denser than water than the water will get heated faster than the given cold sand.

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Assuming that the arrow is launched vertically upward with an initial velocity v and air resistance is negligible, the time the arrow is in the air until it returns to launch height can be expressed as:

t = 2v/g

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Changing the green sum of forces arrow involves manipulating applied forces, frictional forces, and normal forces, allowing for adjustments in magnitude and direction through various means.

To change the green sum of forces arrow, you can employ the following three strategies:

Adjusting Applied Forces: By modifying the magnitude or direction of the applied forces, you can alter the green sum of forces arrow. If the applied forces are increased or directed in a different way, the green sum of forces arrow will change accordingly. For instance, increasing the magnitude of a pushing force will result in a larger green sum of forces arrow in that direction.

Modifying Frictional Forces: Frictional forces play a crucial role in determining the green sum of forces. By changing the coefficient of friction or applying lubricants, you can affect the magnitude of frictional forces acting on an object. Reducing friction will decrease the green sum of forces arrow, while increasing friction will have the opposite effect.

Varying Normal Forces: The green sum of forces arrow can be influenced by adjusting the normal forces acting on an object. Normal forces are perpendicular to the surface and counteract the weight of an object. By changing the angle or surface on which an object rests, you can modify the normal forces. This alteration will subsequently impact the green sum of forces arrow.

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Answer:

T = 99.51 hour

Explanation:

Mass of Uranus, \(M=8.68\times 10^{25}\ kg\)

The moon Umbriel orbits Uranus at a distance of \(2.66\times 10^8\ m\)

We need to find Umbriel's orbital period. Let it is T. Using Kepler's third law of motion to find it.

\(T^2\propto r^3\\\\T^2=\dfrac{4\pi^2r^3}{GM}\\\\T^2=\dfrac{4\pi^2\times (2.66\times 10^8)^3}{6.67\times 10^{-11}\times 8.68\times 10^{25}}\\\\T=358244.51\ s\)

As 1 hour = 3600 s

358244.51 s = 99.51 hour

Hence, Umbriel's orbital period is 99.51 hour.

Answer:

Explanation:

its 99.51 im not just saying that because of the person on top of me but i have all my notes from physics and from chemistry and from biology from when i was on acellus! but the top of me is right :)

The 10/90 principle can be a powerful tool for taking control of your situation and improving your life. By taking responsibility for what you can change and focusing on your reaction to the situation, you can make positive changes in your life and become the master of your own destiny.

The 10/90 principle refers to the idea that life is made up of 10% of what happens to you and 90% of how you respond to it. In other words, you may not be able to control what happens to you, but you can control your reaction to it. By taking responsibility for what you can change rather than being a victim of what you cannot change, you can take control of your situation and improve your life.One example of a situation where the 10/90 principle could be applied is losing a job. Losing a job can be a devastating experience, and it can be easy to feel like a victim in this situation. However, by applying the 10/90 principle, you can take control of your situation and make positive changes in your life.The first step in applying the 10/90 principle in this situation would be to take responsibility for what you can change. This could mean updating your resume, networking with others in your field, and applying for new jobs. By taking action and doing what you can to find a new job, you are taking control of your situation and improving your chances of finding a new job.
The second step would be to focus on your reaction to the situation. Instead of dwelling on the negative aspects of losing your job, try to focus on the positive aspects. This could mean using the extra time to pursue a new hobby or spend more time with family and friends. By focusing on the positive aspects of the situation, you are taking control of your reaction and improving your overall well-being.
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Answer:

(Question) Which type of wave needs a medium to travel?

(Answer) sound waves, because they travel by oscillating molecules

(Question) What do both sound and light waves transfer?

(Answer) energy

(Question) How does an increase in amplitude affect sound and light waves?

(Answer) louder sound and brighter light

(Question) What happens to the wavelength when the frequency increases?

(Answer) The wavelength decreases.

(Question) Which of the following is true about sound waves?

(Answer) Sound moves faster in the ocean than in the air.

Explanation:

i just finished the quick check UwU

The expression for the orbital period is T = \(4\pi R^{\frac{3}{2} } / \sqrt{G(4M+m)}\)

The force acting on one of the masses m by the other two is:

\(\frac{GMm}{R^{2} } + \frac{Gmm}{4R^{2} }\)

This acts as the centripetal force and hence = mRω^2

So, \(\frac{GMm}{R^{2} } + \frac{Gmm}{4R^{2} }\) = mRω^2

Solving this, we get ω = \(\sqrt{\frac{G(4M+m)}{4R^{3} } }\)

We know that time period T = 2\(\pi\)/ω

So , T = \(4\pi R^{\frac{3}{2} } / \sqrt{G(4M+m)}\)

i.e. The expression for the orbital period is T = \(4\pi R^{\frac{3}{2} } / \sqrt{G(4M+m)}\)

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A net force can act in the same direction as that of the current velocity of the object, in which case it will not change the direction in which the object moves.

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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The final temperature of the tea cup is 100°C.

The Internal energy is the energy of a substance due to to the constant random motion of its particles.

The symbol for internal energy of a substance is U and it is measured in Joules.

ΔU = q + W

In conclusion,  the final temperature of the tea cup at room temperature of 24 °C which is heated until it has twice the internal energy is 100°C.

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Answer:

The answer is below

Explanation:

Gravitational Potential energy is the energy stored by an object as a result of its vertical position or height.

Kinetic energy is the energy an object possesses due to its motion.

The law of conservation of energy states that energy cannot be created or destroyed but can be transformed from one form to another.

As the car accelerates down the hill, there is a change in gravitational potential energy as a result of  decrease in vertical height. Some of the gravitational potential energy would be changed into work done by friction while the rest would cause an increase in kinetic energy due to the car acceleration. Lastly, when the brake is applied to stop the car, the car would lose its kinetic energy.

At equal heat applied to both iron and water, the iron with smaller specific heat capacity will experience a more rapid temperature change.

The heat capacity of a substance is the amount of heat required to raise the temperature of entire mass of a substance.

Q = mcΔθ

where;

specific heat capacity of iron = 462 J/kgK

specific heat capacity of water = 4200 J/kgK

Δθ = Q/mc

Change in temperature is inversely proportional to specific heat capacity.

Thus, at equal heat applied to both iron and water, the iron with smaller specific heat capacity will experience a more rapid temperature change.

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The best way of presenting the information on density graphically would be to use a D, bar graph.

A bar graph is a type of chart that uses rectangular bars to represent data. The bars are typically arranged in columns, with the independent variable (in this case, the type of wood) on the x-axis and the dependent variable (in this case, the density) on the y-axis.

A bar graph is the best choice for this data because it allows for easy comparison of density of different types of wood. We can see at a glance which type of wood is the densest and which type of wood is the least dense.

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