What is Chemical bounding

Answers

Answer 1

Answer: Chemical bonding is the attraction between two or more atoms that allows them to be able to form a stable chemical compound.


Related Questions

Which of the following is a true statement?

All flat-topped hills are plateaus.
Volcanoes form all flat-topped hills.
All flat-topped hills are mesas.
Flat-topped hills can either be plateaus or mesas.

Answers

Answer:

D Flat Top Hills Can Be Plateaus or mesas

Explanation:

Convert 1020 mm Hg to atm

Answers

Answer:

1.34

Explanation:

Previously cooked food must reheated to

Answers

Previously cooked food must reheated to temperatures of at least 165°F.

What temperature must previously cooked food must reheated to?

When food is cooked, it should be eaten and any leftovers preserved.

Leftovers can be preserved by refrigeration.

However, when this refrigerated food is to be eaten again, it should be reheated before eating.

Previously cooked food must be heated to prevent spoilage and poisoning.

The addition of heat will prevent spoilage by:

Killing most microorganisms that may be present in the fooddenaturing the activity of the enzymes present in these organisms.

Previously cooked food must reheated to temperatures of at least 165 °F.
The process of reheating the food may be done in microwave oven or over a stove.

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Which of the following statements is true regarding soundwaves?
a. Soundwaves travel as longitudinal or transverse waves depending on the medium they’re traveling through.
b. Soundwaves travel as transverse waves only.
c. Soundwaves travel as longitudinal or transverse waves depending on the temperature of the medium.
d. Soundwaves travel as longitudinal waves only.

Answers

Answer:  Soundwaves travel as longitudinal or transverse waves depending on the temperature of the medium.

Explanation: i think its C

Which of the following statements is true?
A.
Chemical reactions can either absorb thermal energy or release thermal energy.
B.
Chemical reactions can only release thermal energy.
C.
Chemical reactions can only absorb thermal energy.
D.
Chemical reactions can neither absorb thermal energy nor release thermal energy.

Answers

The answer is A, as all chemicals reactions exchange energy with the surroundings by releasing Or absorbing heat

32. Describe how scientific notation makes it easier to
work with very large or very small numbers.

Answers

Scientific notation makes it easier to work with very large or very small numbers because it makes a very small or large number into a shorter one.

How scientific notation makes it easier to work with very large or very small numbers?

Scientific notation makes it easy to compare numbers that have very large values because all the zeroes have been replaced with small number which can be read easily. In scientific notation, numbers with a greater exponent are bigger than numbers with a small or less exponent because higher exponent shows the larger value and smaller value represents smaller value. So that's why scientific notation make easier to write or read a very large or small number.

So we can conclude that Scientific notation makes it easier to work with very large or very small numbers because it makes a very small or large number into a shorter one.

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How many grams of nitrogen in 7.3 x 10^24 molecules of NaNO3

Answers

Answer:

Explanation:

Convert molecules to moles:

1 mole of NaNO₃= 6.02 x 10^23 molecules of NaNO₃

7.3 x10^24/(6.02 x 10^23)=12mol NaNO₃

Find molar mass:

NaNO₃=1 mole of Na and 1mole of N and 3mole of O

Find grams:

14.01g x 12= 168.12 g of N

A sample of gas is put into a rigid (fixed volume) container at 3 oC and a pressure of 38.5 kPa. The container is then placed in an oven at 267 oC.

What pressure would you expect to measure for the gas in the container at this higher temperature?

Answers

We would expect to measure a pressure of approximately 75.25 kPa for the gas in the container at the higher temperature of 267 oC.

To determine the expected pressure of the gas in the container at the higher temperature, we can use the combined gas law, which relates the initial and final conditions of temperature and pressure in a fixed volume system. The combined gas law equation is given as:

(P1 * V1) / T1 = (P2 * V2) / T2

Where:

P1 = Initial pressure

V1 = Initial volume (which is fixed in this case)

T1 = Initial temperature

P2 = Final pressure (to be determined)

V2 = Final volume (which is fixed in this case)

T2 = Final temperature

In this scenario, the initial conditions are given as 3 oC (which is equivalent to 276 K) and 38.5 kPa. The final temperature is 267 oC (which is equivalent to 540 K). Since the volume is fixed, we can substitute the given values into the equation:

(38.5 kPa * V1) / 276 K = (P2 * V1) / 540 K

Simplifying the equation, we can cancel out V1:

38.5 / 276 = P2 / 540

Solving for P2:

P2 = (38.5 / 276) * 540 ≈ 75.25 kPa

Therefore, we would expect to measure a pressure of approximately 75.25 kPa for the gas in the container at the higher temperature of 267 oC.

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How many oxygen atoms are in 1.00 kg of carbon dioxide?

Answers

Answer: I believe its two

Explanation:

What is ΔG for the reaction at body temperature (37.0 °C) if the concentration of A is 1.6 M and the concentration of B is 0.50 M ?

Answers

Answer:

The Gibbs free energy is -2997.83 kJ mol-1.

Explanation:

The change in Gibbs free energy of the reaction \(\Delta G\) can be calculated using the formula.

\(\Delta G = -RTlnK\)

WHere R = Gas constant = 8.314KJ/Kmol

T = the temperature of the reaction in Kelvin = (37.0 + 273) = 310K

K = Raio of molar concentration of the two reactants = 1.6/0.5 = 3.2

Therefore,

\(\Delta G = -8.314 \times 310 \times ln (3.2) = -2997.83 kJ mol-1\)

Therefore the Gibbs free energy is -2997.83 kJ mol-1.

The negative sign indicates that the reaction is spontaneous.

The ΔG for the reaction at 37° C =   - 2997.83 kJ mol-1.

We can determine the value of ΔG using the formula below

ΔG = - RT*In k

where ; R ( gas constant )=  8.314K  J / Kmol

             T = Temperature of reaction = 37 + 273 = 310 k

             K = Ratio of conc =  1.6 / 0.5 = 3.2

Insert values in equation above

∴ ΔG = - 2997.83 kJ mol-1.

Hence we can conclude that the  ΔG for the reaction at 37° C =   - 2997.83 kJ mol-1.

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How many molecules of silver are in 20 grams

Answers

Answer: 0.9 moles

Explanation:1 mole of any molecule/atom contains an amount equal to its molecular/atomic weight. 20 grams of Silver contains 0.9 moles of Silver.

A 500 gram piece of metal had a volume of 2.75cm3. What is it’s density

Answers

Answer:

181.82 g/cm3

Explanation:

density is mass / volume so it is 500 / 2.75=181.82 g/cm3

Convert 12.3 newtons to pounds

Answers

2.7651500001 pound-force

i think thats the answer. Apologies if it isn't :)

melting point is defined as

Answers

Explanation:

The temperature which a given solid will melt

Answer:

the temperature at which a given solid will melt.

Explanation:

I don't know how to Explain it. (lol)

the average human lives 74 years. how many seconds is this? write your answer in scientific notation

Answers

Number of second in human lives in scientific notation is 3.9 × 10⁷ second

Given that;

Average human lives = 74 years

Find:

Number of second in human lives in scientific notation

Computation:

Number of second in human lives in scientific notation = 74 × 365 × 24 × 60

Number of second in human lives in scientific notation = 38,894,400

Number of second in human lives in scientific notation = 3.9 × 10⁷ second

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Calculate the pH and pOH of 500.0 mL of a phosphate solution that is 0.285 M HPO42– and 0.285 M PO43–. (Ka for HPO42- = 4.2x10-13 at 25°C)

Answers

Answer: when concentrations of acid and base are same, pH = pKa

PH = 12.38 pOH = 1.62

Explanation: pKa= -log(Ka)= 12.38. PH + pOH = 14.00

The pH of the solution is 12.38 and the pOH of the solution is  1.62.

Using the Henderson Hasselbalch equation;

pH = pKa + log [A-]/[HA]

Where;

pKa = - log Ka = -log[ 4.2x10-13] = 12.38

[A-] = [PO43–] = 0.285 M

[HA] = [HPO42-] = 0.285 M

Substituting values;

pH =  12.38 + [ 0.285 M]/[ 0.285 M]

pH = 12.38

But;

pH + pOH = 14

pOH = 14 - 12.38

pOH = 1.62

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what are the three important properties of acids

Answers

taste, smell, texture, reactivity
Taste, smell, texture, reactivity,.

What happened to Mendeleev's mother after he was accepted into St. Petersburg University?

Answers

Answer:

his mother died i think

Explanation:

Although he was not accepted, his mother was determined to give her son a first-class education and they walked to St. Petersburg. Dmitri was accepted into the Institute of Pedagogy on a full scholarship. That same year his mother died and at the age of sixteen, Dmitri was orphaned.

what is pure substance
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what is pure substancesubscribe this channel

Answers

A pure substance is a material made of only one type of particle.

What is pure substance?

A substance that has fixed in chemical composition throughout is called a pure substance such as water, air and nitrogen. The  pure substance doesn't have to be of a single element or compound. A pure substance consists only of one element for the or one compound. a mixture consists of two or more different substances, not chemically joined together.

Examples of pure substance include tin, sulfur, diamond, water, pure sugar (sucrose), table salt (sodium chloride) and the  baking soda (sodium bicarbonate). Crystals, in general, are pure substances.

Elements are the pure substances that cannot be broken down into simpler substances by any physical or chemical means we know  as they have only one kind of atom at the  entire composition. Thus when gold is tjr broken down it still remains gold and hence is considered a pure substance is and an element.

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The rotational spectrum of 79BrºF shows a series of equidistant lines spaced 0-714 33 cm - apart. Calculate the rotational constant B, and hence the moment of inertia and bond length of the molecule. Determine the wavenumber of the J = 9+= 10 transition, and find which transition gives rise to the most intense spectral line at room temperature (say 300 K).
and calculate the number of revolutions per second which the Brf molecule undergoes when in (a) the J = 0 state, (b) the J = 1 state, and (c) the J = 10 state. Hint: Use E = {lwin conjunction with Eqs (2.10) and (2.13), but remember that here w is in radians per second.[its Q season 2 from fundamentals of molcular spectruscopy . banwell.c.n]​

Answers

In the J = 0 state, the BrF molecule does not undergo any revolutions per second. In the J = 1 state, it undergoes approximately 0.498 revolutions per second, and in the J = 10 state, it undergoes approximately 15.71 revolutions per second.

To calculate the rotational constant B, we can use the formula:

B = 1 / (2 * π * Δν)

Where:

B = rotational constant

Δν = spacing between consecutive lines in the rotational spectrum

Given that the spacing between consecutive lines is 0.71433 cm^(-1), we can substitute this value into the formula:

B = 1 / (2 * π * 0.71433 cm^(-1))

B ≈ 0.079 cm^(-1)

The moment of inertia (I) of the molecule can be calculated using the formula:

I = h / (8 * π^2 * B)

Where:

h = Planck's constant

Given that the value of Planck's constant (h) is approximately 6.626 x 10^(-34) J·s, we can substitute the values into the formula:

I = (6.626 x 10^(-34) J·s) / (8 * π^2 * 0.079 cm^(-1))

I ≈ 2.11 x 10^(-46) kg·m^2

The bond length (r) of the molecule can be determined using the formula:

r = sqrt((h / (4 * π^2 * μ * B)) - r_e^2)

Where:

μ = reduced mass of the molecule

r_e = equilibrium bond length

To calculate the wavenumber (ν) of the J = 9+ to J = 10 transition, we can use the formula:

ν = 2 * B * (J + 1)

Substituting J = 9 into the formula, we get:

ν = 2 * 0.079 cm^(-1) * (9 + 1)

ν ≈ 1.58 cm^(-1)

To determine the most intense spectral line at room temperature (300 K), we can use the Boltzmann distribution law. The intensity (I) of a spectral line is proportional to the population of the corresponding rotational level:

I ∝ exp(-E / (k * T))

Where:

E = energy difference between the levels

k = Boltzmann constant

T = temperature in Kelvin

At room temperature (300 K), the population distribution decreases rapidly with increasing energy difference. Therefore, the transition with the lowest energy difference will have the most intense spectral line. In this case, the transition from J = 0 to J = 1 will have the most intense spectral line.

To calculate the number of revolutions per second, we can use the formula:

ω = 2 * π * B * J

Where:

ω = angular frequency (in radians per second)

J = rotational quantum number

For J = 0:

ω = 2 * π * 0.079 cm^(-1) * 0 = 0 rad/s

For J = 1:

ω = 2 * π * 0.079 cm^(-1) * 1 ≈ 0.498 rad/s

For J = 10:

ω = 2 * π * 0.079 cm^(-1) * 10 ≈ 15.71 rad/s

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A gas has a volume of 50.0 mL at a temperature of 10.0 K and a pressure of 760. kPa. What will be the new volume when the temperature is changed to 20.0 K and the pressure is changed to 380. kPa?

Answers

When the temperature changes to 20.0 K and the pressure changes to 380 kPa, the new volume will be approximately 0.2 L (200.0 mL).

To solve this problem using the gas laws, we need to use the Ideal Gas Law. This law states that the product of the pressure and the volume of a gas is proportional to the absolute temperature.

The equation of the Ideal Gas Law is the following:

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{\dfrac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2} } \end{gathered}$} }\)

Where:

P₁ = initial pressure = 760 kPaV₁ = initial volume = 50.0 mL = 0.050 LT₁ = initial temperature = 10.0 KP₂ = Final pressure = 380 kPaT₂ = final temperature = 20.0 KV₂ = Final volume = ?

We clear for V₂:

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\frac{P_1V_1T_2}{P_2T_1 } } \end{gathered}$} }\)

Where:

P₁ = initial pressure V₁ = initial volumeT₁ = initial temperatureP₂ = Final pressureT₂ = final temperatureV₂ = Final volume

Substituting the known values:

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\frac{760\not{kPa}\times0.050 \ L\times20.0\not{k} }{ 380\not{kPa}\times10.0\not{k} } } \end{gathered}$} }\)

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\frac{760 \ L}{3800 } } \end{gathered}$} }\)

\(\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2\approx0.2 \ Liters} \end{gathered}$} }}\)

When the temperature changes to 20.0 K and the pressure changes to 380 kPa, the new volume will be approximately 0.2 L (200.0 mL).

Which of the following is a correct statement regarding the free energy?
It is energy available to create bonds.
It always has the same value.
It is stored between atoms.
It is known as kinetic energy.

Answers

Answer:

A

Explanation:

3. A Wilkinson’s catalyst is widely used in the hydrogenation of alkenes. Show a catalytic cycle, including: i. chemical structure of the catalyst, with complete stereochemistry ii. molecular geometry of catalyst iii. type of reactions involved iv. the appropriate starting material, reagent and solvent v. major and minor end-products vi. all intermediates, for each reaction stated in (iii)

Answers

We can see here that the catalytic cycle for the hydrogenation of alkenes using Wilkinson's catalyst involves several steps.

What are the steps involved?

Here's an overview of the catalytic cycle, including the necessary details:

i. Chemical structure of the catalyst:

Wilkinson's catalyst, also known as chloridotris(triphenylphosphine)rhodium(I), has the following chemical structure: [RhCl(PPh3)3]

ii. Molecular geometry of the catalyst:

The Wilkinson's catalyst has a trigonal bipyramidal geometry around the rhodium center. The three triphenylphosphine (PPh3) ligands occupy equatorial positions, while the chloride (Cl) ligand occupies an axial position.

iii. Type of reactions involved:

The catalytic cycle involves several reactions, including:

Oxidative addition: The rhodium center undergoes oxidative addition, reacting with molecular hydrogen (H2) to form a dihydride intermediate.Alkene coordination: The alkene substrate coordinates to the rhodium center, forming a π-complex.Hydrogenation: The coordinated alkene undergoes hydrogenation, resulting in the addition of hydrogen atoms to the double bond and formation of a metal-alkyl intermediate.Reoxidation: The metal-alkyl intermediate reacts with a hydrogen molecule to regenerate the rhodium dihydride species.

iv. Starting material, reagent, and solvent:

The starting material is an alkene, and the reagent is Wilkinson's catalyst ([RhCl(PPh3)3]). The reaction is typically carried out in a suitable solvent, such as dichloromethane (CH2Cl2) or tetrahydrofuran (THF).

v. Major and minor end-products:

The major end-product of the hydrogenation reaction is the fully saturated alkane, resulting from the addition of hydrogen across the double bond. The minor end-product may include cis- or trans-configured alkanes if the original alkene substrate possesses geometric isomers.

vi. Intermediates:

The intermediates in the catalytic cycle include:

Rhodium dihydride complex: [RhH2(PPh3)3]Alkene-Rhodium π-complex: [Rh(η2-alkene)(PPh3)3]Metal-alkyl intermediate: [Rh(alkyl)(PPh3)3]

These intermediates play a crucial role in facilitating the hydrogenation reaction and enabling the catalytic cycle to proceed.

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Qué uso le darías en la vida diaria ayuda

Answers

Answer:

ako po kailangan ko po nga ayuda

Explanation:

thanks for the points ❤️

Dolphins have the same arm structure as wolves. What type of evidence for evolution does this represent?


A. DNA

B. vestigial structures

C.homologous structures

D. embryology

Answers

The answer is C, homologous structures

Vinegar is sold at the grocery store with a concentration of 5.0 % acetic acid. How many grams of acetic acid are in 28 g of Vinegar?

Answers

White vinegar typically consists of 93%–96% water and 4–7% acetic acid. It can be used to cooking, bake, cleaning, and get rid of weeds. It can also help you lose weight and lower your blood sugar and cholesterol. Consumption is safe in moderation, but excessive consumption or when combined with certain medications could be harmful.

Apple cider vinegar is widely used in cooking and as a salad dressing because it contains acetic acid and nutrients like vitamins C and B vitamins. But at the same time, it's been utilized customarily as medication. It helps in losing weight.

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How many electrons would be too many for a nitrogen atom

Answers

3 would be the answer

To determine the concentration of SO4 2– ion in a sample of groundwater, 100.0 mL of the sample is titrated with 0.0250 M Ba(NO3)2, forming insoluble BaSO4. If 7.48 mL of the Ba(NO3)2 solution is required to reach the end point of the titration, what is the molarity of the SO4 2–?

Answers

Answer:

1.87x10⁻³ M SO₄²⁻

Explanation:

The reaction of SO₄²⁻ with Ba²⁺ (From Ba(NO₃)₂) is:

SO₄²⁻(aq) + Ba²⁺(aq) → BaSO₄(s)

Where 1 mole of  SO₄²⁻ reacts per mole of Ba²⁺

To reach the end point in this titration, we need to add the same moles of Ba²⁺ that the moles that are of SO₄²⁻.

Thus, to find molarity of SO₄²⁻ we need to find first the moles of Ba²⁺ added (That will be the same of SO₄²⁻). And as the volume of the initial sample was 100mL we can find molarity (As ratio of moles of SO₄²⁻ per liter of solution).

Moles Ba²⁺:

7.48mL = 7.48x10⁻³L ₓ (0.0250moles / L) = 1.87x10⁻⁴ moles of Ba²⁺ = Moles of SO₄²⁻

Molarity SO₄²⁻:

As there are 1.87x10⁻⁴ moles of SO₄²⁻ in 100mL = 0.1L, molarity is:

1.87x10⁻⁴ moles of SO₄²⁻ / 0.1L =

1.87x10⁻³ M SO₄²⁻

which of the following labels are used for quantum numbers to describe the state of an electron inside an atom? select all that apply.


m

mo

ms

Answers

Quantum numbers can be shown by;

ms

What is a quantum number?

When we talk about the quantum numbers that describe an electron, we are looking at the number that can be used to show the designation of an electron in an atom. Thus the position of the electron that can be found in the atom is shown by the use of the quantum numbers.

There are four sets of quantum numbers and they are;

1) orbital quantum number (l)

2) Spin quantum number (ms)

3) Magnetic quantum number (ml)

4) Principal quantum number (n)

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Why are zeppelin filled with hydrogen a bad idea?

Answers

the fire that destroyed due to the extremely flammable aluminium /iron oxide  based  applied to the outer skin of the craft. This was struck by lightning and caught fire well before the hydrogen ignited.

Explanation:

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