Answer:
( 5, 0 )
Step-by-step explanation:
the x intercepts is (5,0) as u can see in tha pic
If A={s, t, a, r} and B={m, a, t, h}, find A ∩ B.
The given sets are
\(\begin{gathered} A=\mleft\lbrace s,t,a,r\mright\rbrace \\ B=\mleft\lbrace m,a,t,h\mright\rbrace \end{gathered}\)The given question is
\(A\cap B\)This means we need to list the comment elements in both sets
Since the common letters are t and a, then
\(A\cap B=\mleft\lbrace a,t\mright\rbrace\)if x represents a number, then write an expression for a number that is three more than the number,
Find the Laplace transform where of the function f(t) =
{ t, 0 < t < {π + t π < t < 2π where f(t + 2 π) = f(t).
The Laplace Transform of f(t) isL{f(t)} = L{t} + L{t + π}u(t − π) − L{t − 2π}u(t − 2π) + ...
= (1/s^2) + e^{−πs}(1/s^2) − e^{-2πs}(1/s^2) + ...= (1/s^2)[1 + e^{−πs} − e^{−2πs} + ...]
Given function is,f(t) ={ t, 0 < t < π π < t < 2π}
where f(t + 2 π) = f(t)
Let's take Laplace Transform of f(t)
L{f(t)} = L{t} + L{t + π}u(t − π) − L{t − 2π}u(t − 2π) + ...f(t + 2π) = f(t)
∴ L{f(t + 2 π)} = L{f(t)}⇒ e^{2πs}L{f(t)} = L{f(t)}
⇒ [e^{2πs} − 1]L{f(t)} = 0L{f(t)} = 0
when e^{2πs} ≠ 1 ⇒ s ≠ 0
∴ The Laplace Transform of f(t) is
L{f(t)} = L{t} + L{t + π}u(t − π) − L{t − 2π}u(t − 2π) + ...
= (1/s^2) + e^{−πs}(1/s^2) − e^{-2πs}(1/s^2) + ...
= (1/s^2)[1 + e^{−πs} − e^{−2πs} + ...]
The Laplace Transform of f(t) isL{f(t)} = L{t} + L{t + π}u(t − π) − L{t − 2π}u(t − 2π) + ...
= (1/s^2) + e^{−πs}(1/s^2) − e^{-2πs}(1/s^2) + ...= (1/s^2)[1 + e^{−πs} − e^{−2πs} + ...]
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Danielle sold a certain number of tickets to the school play, d. Sara sold 4 more tickets to the school play than the number Danielle sold. Brett sold 3 times as many as Danielle sold. The number of tickets that the 3 students sold altogether can be represented by the expression below. d+d+4+3d
Answer:
5d+4
Step-by-step explanation:
Number of ticket sold by Daniel = d .... 1
If Sara sold 4 more tickets to the school play than the number Danielle sold, the total number sold by Sarah is expressed as d+4 .... 2
If Brett sold 3 times as many as Danielle sold, the amount sold by Brett is 3×d = 3d ..... 3
The number of tickets that the 3 students sold altogether can be gotten by adding equation 1, 2 and 3 together as shown;
d+(d+4)+3d
Collect like terms
= d+d+3d+4
= 2d+3d+4
= 5d+4
Hence the number of tickets that the 3 students sold altogether is represented as 5d+4
Answer:
5d+4
Step-by-step explanation:
Have a good day
On Thursday afternoon at camp, Nora played basketball and went swimming before dinner. She started playing basketball at 2:50 P.M. and played for 1 hour and 45 minutes. Then she swam for 50 minutes. Dinner lasted for 1 hour. What time did dinner end?
Answer:
6:25 PM
Step-by-step explanation:
Start of dinner
2:50 PM + 1:45 + 0:50
convert it to minutes
2:50PM + 60+ 45 + 50
= 2:50Pm + 60 + (50 + 10) + (45 - 10)
= 4:50Pm + 35
= 4:50PM + 10 + 25
= 5:25PM
End of dinner
5:25PM + 1 = 6:25PM
A landscaping company is laying a triangular flower bed. The height of the trangle is 15ft. What lengths of the base will make the area at least 210ft squared?
Answer:
28 ft
Step-by-step explanation:
The height of the triangle = 15 ft
The least required area A = 210 ft^2
We know that the area of a triangle = 1/2bh
Where
b is the base
h is the height
Substituting, we have
210 = 1/2 x b x 15
210 = 15/2 x b
420/15 = b
b = 28 ft
John rides his bike 68 km south and then 6 km went. How far is he from his starting point?
John is approximately 68.26 km away from his starting point after riding 68 km south and then 6 km west.
To find out how far John is from his starting point after riding 68 km south and then 6 km west, we will use the Pythagorean theorem.
The Pythagorean theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. In this case, we will consider the 68 km south as one side, and the 6 km west as the other side, with the distance from the starting point being the hypotenuse.
Step 1: Square the lengths of the two given sides.
68^2 = 4624
6^2 = 36
Step 2: Add the squared values together.
4624 + 36 = 4660
Step 3: Find the square root of the sum to get the length of the hypotenuse (distance from the starting point).
√4660 ≈ 68.26 km
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Brand 1 of antifreeze clalms that it can withstand temperatures of -62°C. Brand 2 of antreeze claims that it can withstand temperatures 5°C below those of Brand 1. Which equation represents the temperatures Brand 2 can withstand? A. -62 + 5 = -57 B. -62 + 5 = -67C. +62 + (-5) = -67 -D. 62 + (-5) = -57
Answer:
-62 + (-5) = -67
Explanation:
If we need to find a temperature that is 5°C below, we need to subtract 5°C from the initial temperature.
For example, 5°C below 15°C is equal to:
15°C - 5°C = 10°C
If the initial temperature is -62°C, 5°C below is calculated as:
-62°C - 5°C
Since both numbers have a negative sign, we need to add the numbers and the result will also be negative.
It can also be written as:
-62 + (-5) = -67
It means that -67°C is 5°C below -62°C
Twice a number x is equal to 58
How can you write this in number form?
Thank you
Answer:
Something like:
2x = 58
Hopefully that's what you're talking about.
Answer:
2x = 58 [x = 29]
Step-by-step explanation:
Twice a number x is equal to 58 implies that 2 times x is 58 which means that the expression x with a coefficient of 2 is equal to a constant of 58.
2 × x = 58 → 2x = 58
_____________________
If you want the working x value for this equation, just divide both sides by 2.
2x = 58
÷2 ÷2
______
x = 29
Need help, look at attachment
Answer:
angle 1 and angle 8 are co exterior angles. so, their sum is equal to 180°.
28°+ angle 8 =180°
angle 8=180°-28°
angle 8=152°
In the rhombus shown above, AC = 20 and DB = 48. Find the perimeter of the rhombus.
Answer:
104
Step-by-step explanation:
A rhombus diagonal bisect each other so that means half of the diagonal is equal to the other half.
Applying that, this means
AE=ECDE=EBSince they are equal we can divide AC by 2 to find AE and EC.
20/2=10
AE=10, EC=10
Same for DB
48/2=24
DE=24, EB=24
A rhombus diagonals are perpendicular to each other so each middle angle will measure 90 degree.
Looking closer, a rhombus has 4 right triangles. We only need to use one.
Look at triangle AEB. We know AE=10 and EB=24 and Angle E=90. We can apply pythagorean theorem to find side AB.
\( {ae}^{2} + {db}^{2} = {ab}^{2} \)
\( {10}^{2} + {24}^{2} = {ab}^{2} \)
\(100 + 576 = ab {}^{2} \)
\(676 = {ab}^{2} \)
\( \sqrt{676} = 26\)
The perimeter of rhombus is equal to
4a, where a is the length of one side.
One side measures 26 so we can plug that in.
\(26 \times 4 = 104\)
The Red Line Below is Parallel To which of the following?
A. The x-axis
B. The origin
C. the y-axis
D. None of those
Answer:
C. y axis
Step-by-step explanation:
y axis is the answer
What is 75% of 400? Write and evaluate an expression
to find the answer. Then explain how to use the model
to justify the answer.
Answer:
300
Step-by-step explanation:
0.75 times 400 equals 300
What is the equation for the line that passes through the coordinates (-4,-12)and(16,3)
The equation of the line that passes through these coordinates is 3x-4y= 36
How to calculate slope?
If you have the coordinates of two points on a line, you can use the slope formula to determine that line's slope. m=(y2-y1)/(x2-x1), or the ratio of the change in the y values to the change in the x values, is the slope formula.
To find the equation of the line we first have to find the slope which is represented by m.
The slope or m is given by : y₂ - y₁ / x₂ - x₁
thus, m= 3-(-12)/ 16-(-4)
m= 3+12/ 16+4 = 15/20
m= 3/4
The equation of a slope is y-y₁=m (x-x₁)
y- (-12) = 3/4 (x- (-4))
y+12 = 3/4 (x+4)
On solving it further we get:
4y+48= 3x+12
3x-4y= 36
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HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP
HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP
Answer:
first Q . mirror
Second Q. sight and touch
Answer: Smoothest surface: mirror
senses being used: sight and touch
hope this helps!
Step-by-step explanation:
Theresa and Raul purchased a house 10 years ago for $200,000. They made a down payment of 20% of the purchase price and secured a 30 year conventional home mortgage at 6% per year compounded monthly on the unpaid balance. The house is now worth $380,000. How much equity do Teresa and Raul have in their house now (after making 120 monthly payments)? Please show all work.
2. Emon is securing a 7-year balloon mortgage for $280,000 to finance the purchase of his first home. The monthly payments are based on a 30 year amortization. If the interest rate is 2.9% per year compounded monthly, what will be his balloon payment at the end of the 7 years? Please show all work.
Theresa and Raul have approximately $264,875.60 in equity in their house after making 120 monthly payments. Emon’s balloon payment at the end of 7 years is approximately $190,347.68.
Let’s calculate the equity that Theresa and Raul have in their house now:
1. Initial purchase price: $200,000
Down payment: 20% of $200,000 = $40,000
Loan amount: $200,000 - $40,000 = $160,000
2. Monthly interest rate: 6% / 12 months = 0.06 / 12 = 0.005
Number of monthly payments: 30 years * 12 months = 360 months
To calculate the monthly payment, we can use the formula for a fixed-rate mortgage:
Monthly payment = P * r * (1 + r)^n / ((1 + r)^n – 1)
Where:
P = Loan amount = $160,000
R = Monthly interest rate = 0.005
N = Number of monthly payments = 360
Using this formula, we can calculate the monthly payment:
Monthly payment = $160,000 * 0.005 * (1 + 0.005)^360 / ((1 + 0.005)^360 – 1)
≈ $959.37
Now, let’s calculate the total amount paid over the 120 monthly payments:
Total amount paid = Monthly payment * Number of monthly payments
= $959.37 * 120
= $115,124.40
Finally, to calculate the equity, we subtract the total amount paid from the current house value:
Equity = Current house value – Total amount paid
= $380,000 - $115,124.40
= $264,875.60
Therefore, Theresa and Raul have approximately $264,875.60 in equity in their house now.
Now let’s calculate Emon’s balloon payment at the end of 7 years:
1. Loan amount: $280,000
2. Monthly interest rate: 2.9% / 12 months = 0.029 / 12 = 0.00242
Number of monthly payments: 7 years * 12 months = 84 months
To calculate the monthly payment, we can use the same formula as before:
Monthly payment = P * r * (1 + r)^n / ((1 + r)^n – 1)
Where:
P = Loan amount = $280,000
R = Monthly interest rate = 0.00242
N = Number of monthly payments = 360
Using this formula, we can calculate the monthly payment:
Monthly payment = $280,000 * 0.00242 * (1 + 0.00242)^84 / ((1 + 0.00242)^84 – 1)
≈ $1,125.32
Since the monthly payments are based on a 30-year amortization, at the end of 7 years, there will still be a remaining balance on the loan.
Remaining balance = Loan amount – (Monthly payment * Number of monthly payments)
= $280,000 – ($1,125.32 * 84)
≈ $190,347.68
Therefore, Emon’s balloon payment at the end of 7 years would be approximately $190,347.68.
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the output of the statement: cout << pow(2.0, pow(3.0, 1.0)) << endl; is . a. 6.0 b. 7.0 c. 8.0 d. 9.0
The output of the statement: cout << pow(2.0, pow(3.0, 1.0)) << endl; is
c. 8.0.
Given statement:
output :
The output of a computer or word processor is the information that it displays on a screen or prints on paper as a result of a particular program.
cout << pow ( 2.0 , pow ( 3.0 , 1.0 )) << endl;
= pow ( 3.0 , 1.0 )
= 3^1
= 3.0
cout << pow ( 2.0 , 3.0 ) << endl;
= pow ( 2.0 ,3.0 )
= 2.0^3.0
= 8.0
Therefore The output of the statement: cout << pow(2.0, pow(3.0, 1.0)) << endl; is c. 8.0.
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find the area inside one loop of the curve. r2 = 8 sin(8), r ≥ 0
Therefore, the area inside one loop of the curve is 1/2 square units.
The curve is a limacon with a loop. Using polar coordinates, the equation can be written as:
r = √(8sin(8))
The area inside one loop of the curve is given by:
A = (1/2) ∫θ2 -θ1 r(θ)² dθ
where θ1 and θ2 are the angles at which the curve intersects itself and forms a loop.
Solving for r(θ) = √(8sin(8)), we get:
A = (1/2) ∫0^(π/4) [√(8sin(8))]² dθ
Simplifying, we get:
A = 2 ∫0^(π/4) sin(8) dθ
Using the substitution u = 8θ, du/dθ = 8, and dθ = du/8, we get:
A = (1/4) ∫0^2π sin(u) du
Evaluating the integral, we get:
A = (1/4) [-cos(u)]₀²π = (1/4)(2) = 1/2
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in the number 89.567 what number is the least value?
Answer:
In the number 89.567, the least value is 0, which is the least value of the decimal part of the number. The integer part of the number, which is 89, is greater than 0, so the least value in the number is in the decimal part.
Determine whether each of these proposed definitions is a valid recursive definition of a function f from the set of nonnegative integers to the set of integers. If f is well defined, find a formula for f(n) when n is a nonnegative integer and prove that your formula is valid.
f(0) = 1, f(n) = f(n – 1) – 1 for n ≥ 1
Choose the correct statement.
(You must provide an answer before moving to the next part.)
After considering the given data we conclude that the correct statement that satisfy the given question is \(f(n) = 2 - n\)concerning nonnegative integer.
The given definition is a valid recursive definition of a function f from the set of nonnegative integers to the set of integers. The formula for f(n)
Here,
n = nonnegative integer is f(n) = 2 - n.
Now to evaluate that this formula is valid, we can apply mathematical induction.
First, we show that the formula holds for n = 0. Since f(0) = 1 by definition, we have f(0) = 2 - 0 = 1.
Next, we assume that the formula holds for some arbitrary nonnegative integer k.
That is, we assume that f(k) = 2 - k. We then show that the formula also holds for k + 1. By definition of the function f, we have f(k + 1) = f(k) - 1. Substituting our assumption into this equation gives:
f(k + 1) = (2 - k) - 1 = 1 - k
This is precisely the formula we would expect if f(k + 1) were equal to 2 - (k + 1). Therefore, by mathematical induction, we have shown that the formula \(f(n) = 2 - n\)is valid for all nonnegative integers n.
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The lengths of the legs of a right triangle are given. Find the hypotenuse.a =8. b = 15The length of the hypotenuse, C, is
Solution:
Concept:
To solve the length of the hypotenuse, we will use the Pythagoras theorem below
\(\begin{gathered} hypotenus^2=opposite^2+adjacent^2 \\ c^2=a^2+b^2 \\ where, \\ a=8 \\ b=15 \end{gathered}\)By substituting the values, we will have
\(\begin{gathered} c^{2}=a^{2}+b^{2} \\ c^2=8^2+15^2 \\ c^2=64+225 \\ c^2=289 \\ c=\sqrt{289} \\ c=17 \end{gathered}\)Hence,
The length of hypotenuse C , is
\(\Rightarrow c=17\)A deck of cards was shuffled and after each shuffle, the suit of the top card was recorded. The table shows theprobability of each outcome. What is the probability that the top card is not a heart?
Answer:
\(0.72\)Explanation:
Here, we want to get the probability that the top card is not a heart card
Mathematically, the sum of the probability that an event will occur and that the event will not occur is 1
Let the event that a heart card is the top card be H
\(P(H)\text{ + P(H') = 1}\)We already have P(H) as 0.28
Thus:
\(\begin{gathered} 0.28\text{ + P(H') = 1} \\ P(H^{\prime})\text{ = 1-0.28} \\ P(H^{\prime})\text{ = 0.72} \end{gathered}\)Suppose that the individuals are divided into groups j = 1,..., J each with n, observations respectively, and we only observe the reported group means y, and j. The model becomes ÿj = Bīj + Uj, (2) Derive an expression for the standard error of the OLS estimator for 3 in terms of ij and Tij indicates ; of individual i belonging to group j. (6 marks) σ, where What are the consequences of heteroskedasticity in the errors for the OLS estimator of the param- eters, their usual OLS standard errors reported by statistical packages, and the standard t-test and F-test for these parameters? (4 marks)
Heteroskedasticity in the errors has an impact on the accuracy of the standard errors estimated using Ordinary Least Squares (OLS) and can affect hypothesis tests. To address this concern, it is advisable to utilize robust standard errors, which provide more reliable inference regarding the parameters of interest.
In the presence of heteroskedasticity, the OLS estimator for the parameters remains unbiased, but the usual OLS standard errors reported by statistical packages become inefficient and biased. This means that the estimated standard errors do not accurately capture the true variability of the parameter estimates. As a result, hypothesis tests based on these standard errors, such as the t-test and F-test, may yield misleading results.
To address heteroskedasticity, robust standard errors can be used, which provide consistent estimates of the standard errors regardless of the heteroskedasticity structure. These robust standard errors account for the heteroskedasticity and produce valid hypothesis tests. They are calculated using methods such as White's heteroskedasticity-consistent estimator or Huber-White sandwich estimator.
In summary, heteroskedasticity in the errors affects the accuracy of the OLS standard errors and subsequent hypothesis tests. To mitigate this issue, robust standard errors should be employed to obtain reliable inference on the parameters of interest.
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What is the property of
(9+x)+y=9+(x+y)
The property of (9+x)+y=9+(x +y) is associative property.
What is meant by associative property?According to the associative property, the product of a multiplication problem is unaffected by the way the elements are arranged in the problem. The associative feature of various binary operations in mathematics states that the outcome will not change if the parentheses in an expression are rearranged. Associativity is a recognized rule of replacement for logical proof expressions in propositional logic. The grouping symbols can be altered during addition or multiplication without changing the outcome, according to the associative property. The formula is (a +b)+c=a+(b +c). The distributive property is a method of multiplication that entails dividing a number by each individual addend of another integer.
Given equation is,
(9+x)+y=9+(x +y)
It is of the form (a +b)+c=a+(b +c)
So, This equation belongs to associative property.
Therefore, the property of (9+x)+y=9+(x +y) is associative property.
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note: i dont want to answer the question below i want you to
explain only my questions i will ask now...
b1=10
62=8
b3-a=15
b3-b=10
b4=9
i want to ask... now in question i want to
calculate
The given information consists of a series of equations involving variables b1, b3, and b4, as well as the constant values 8, 9, and 10. The objective is to calculate the value of b3.
To find the value of b3, we need to analyze the given equations and use algebraic techniques to solve for the unknown variable.
From the equations given, we can observe that b1 = 10, b4 = 9, and 62 = 8. These values provide fixed points of reference.
Next, we examine the equations involving b3. We have two equations: b3 - a = 15 and b3 - b = 10. However, there is no information provided about the values of a and b. Without additional information or constraints, we cannot determine the specific value of b3.
It is important to note that the solution to the problem depends on having all the necessary information or additional equations that can be used to solve for the unknowns. In this case, the lack of information about the values of a and b prevents us from calculating the exact value of b3.
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X-2.5= -3 solve each equation for x
Answer:x=-0.5
Step-by-step explanation:
You would add the 2.5 on both sides of the equal sign
What is the remainder when you divide 2x3 4x2 - x 3 by x 2?.
the answer is 5 hope this helps lol
Consider the quadratic expression \(t^2+4t-77\).
a. Factor using the area model.
b. Factor using the distributive property.
The expression \(t^2 + 4t - 77\) can be factored as
(t + 7)(t - 11) using the area model (a)(t + 11)(t + 7) using the distributive property (b)The general form of the quadratic expression is \(ax^2 + bx + c\), where a, b, and c are coefficients.
Here, a = 1, b = 4, and c = -77.
First, we find two numbers that multiply to c and add up to b. In this case, -7 and 11 fit the criteria.
Now, we write the expression as:
\(t^2 + 4t - 77 = (t + 7)(t - 11)\)
So the expression \(t^2 + 4t - 77\) can be factored as (t + 7)(t - 11) using the area model.
The distributive property states that for any numbers a, b, and c, we have \(a(b + c) = ab + ac.\)
Here, we can factor the expression \(t^2 + 4t - 77\)as:
\(t^2 + 4t - 77 = t^2 + (4 * 11)t - (7 * 11)\)
\(= t^2 + 44t - 77\)
Now, we can use the distributive property to factor the expression as:
\(t^2 + 44t - 77 = (t + 11)(t + 7)\)
So the expression \(t^2 + 4t - 77\) can be factored as (t + 11)(t + 7) using the distributive property.
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solve for m
m-2.02= -0.58
Solve the equation.
5x = 3x²+1
5+ 13
a
5-√13
c.
-5+ √13
5- V13
X=
or
or
12
12
6
6
b.
-5+ √13
5-√3
d.
S+~13
5- 13
Of
12
or
12
6
6