What is an extremophile? What domain is known for these organisms?

Answer:

Anstree species was preserved as a fossil in the Arizona desert. The species is now extinct. its because we preserved it right so that mean even to it fell down its still alive for the simple reason that we dint ruin it

In order to solve this question, we can use the titration formula, in which we take the volume of both acid and base, and the concentration of the base in order to find the concentration of the acid. The formula is:

Ma*Va = Mb*Vb

We have:

Ma = ?

Va = 30.00 mL of HCl

Mb = 0.1051 M of NaOH

Vb = 47.52 mL of NaOH

Now we add these values into the formula:

Ma*30 = 0.1051*47.52

30Ma = 4.9943

Ma = 0.1665 M is the molar concentration for the acid

The half-life for the decomposition of NOCl when the concentration of NOCl is 0.15 M and rate constant is 8.0*10^-8 L mol^-1s^-1 is approximately 2.31 hours.

How to calculate the half-life for the decomposition of NOCl?

The second-order reaction can be represented as:

2 NOCl → 2 NO + Cl2

The rate law for the reaction is:

rate = k[NOCl]^2

where k denotes the rate constant and [NOCl] the NOCl concentration.

The half-life (t1/2) for a second-order reaction can be calculated using the following equation:

t1/2 = 1 / (k[NOCl]₀)

where [NOCl]₀ is the initial concentration of NOCl.

Substituting the given values, we get:

t1/2 = 1 / (8.0*10^-8 L mol^-1s^-1 × 0.15 M)

t1/2 = 8333.33 s

Therefore, the half-life for the decomposition of NOCl when the concentration of NOCl is 0.15 M is 8333.33 s or approximately 2.31 hours.

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The percent by mass of the carbon is 30.4%.

The term percentage has to do with the ratio of the mass of a particular atom to the total mass of the compound multiplied by one hundred. Thus the first step is to find the total mass or the molar mass of the compound.

Molar mass = 40 + 2(2(12) + 3(1) + 2(16))

= 40 + 2(24 + 3 + 32)

= 40 + 2(59)

= 40 +118

= 158

Thus the mass of carbon is;

4(12)/158 * 100/1

= 30.4%

Thus carbon is only about 30.4% by mass of the compound.

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Answer:

\(r=25M^{-1}s^{-1}[A]^2\)

Explanation:

Hello there!

In this case, according to the given information for this chemical reaction, it is possible for us to set up the following general rate law and the ratio of the initial and the final (doubled concentration) condition:

\(r=k[A]^n\\\\\frac{r_1}{r_2} =\frac{k[A]_1^n}{k[A]_2^n}\)

Next, we plug in the given concentrations of A, 0.2M and 0.4 M, the rates, 1.0 M/s and 4.0 M/s and cancel out the rate constants as they are the same, in order to obtain the following:

\(\frac{1.0}{4.0} =\frac{0.2^n}{0.4^n}\\\\0.25=0.5^n\\\\n=\frac{ln(0.25)}{ln(0.5)} \\\\n=2\)

Which means this reaction is second-order with respect to A. Finally, we calculate the rate constant by using n, [A] and r, to obtain:

\(k=\frac{r}{[A]^n} =\frac{1.0M/s}{(0.2M)^2}\\\\k=25M^{-1}s^{-1}\)

Thus, the rate law turns out to be:

\(r=25M^{-1}s^{-1}[A]^2\)

Regards!

Answer:

The time required to decompose the substance is 360 seconds.

The density of the iron pyrite cube is 1.343 g/cm³.

Given,

Side of iron pyrite cube = 0.31 cm

Mass of iron pyrite = 0.040 g

The volume of iron pyrite cube = s³ cm³

Or, volume = 0.029791 cm³

We have to find the density of the sample.

Density is defined as the mass per unit volume. Or, it is the ratio of mass to the volume of the substance.

Using the formula for density, we get,

Density = mass/volume

Or, density = 0.40/0.029791

Or, density = 1.343 g/cm³

Hence, the density of the iron pyrite cube is 1.343 g/cm³.

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Answer:

Covalent bond involves the sharing of electrons, while metallic bonds have strong attractions and ionic bonds involve the transferring and accepting of electrons from the valence shell. The adhering property of an atom, in order to arrange themselves in a most stable pattern by filling their outermost electrons orbit

Explanation:

hope it helps:)

Answer:Exposure to extremely high levels of americium, as has been reported in some animal studies, has resulted in damage to organs such as the lungs, liver, kidneys, and thyroid. It is rare, however, that a person would be exposed to amounts of americium large enough to cause harmful effects in these organs.

Explanation:

Cyclohexene is a cyclic, six-membered hydrocarbon that contains one double bond. The types of reactions that can occur in cyclohexene would be those that are typical with alkenes generally.

The pi-bonded electrons in the double bond are nucleophilic. So, electrophilic addition reactions could occur with cyclohexene. For example,

cyclohexene + HBr → bromocyclohexane

cyclohexene + H2O/H+ → cyclohexanol

cyclohexene + Br2 → trans-1,2-dibromocyclohexane (racemic)

The latter is a common test for alkenes where one adds bromine to a sample to see if there is decolorization, which would indicate the presence of nucleophilic pi bonds. Bromine, which is dark reddish-brown, will become clear as it reacts with an alkene to form a colorless haloalkane.

Cyclohexene can also be converted to the fully saturated cyclohexane by hydrogenation: cyclohexene + H2/Pd → cyclohexane.

Answer:

yes

Explanation:

Answer:

Explanation:

HF + H2O reacts to form H3O+ (hydronium ion) and F- (fluoride ion).

Percentage Weight-in-volume is defined as the number of grams of a solute in a 100 ml (milliliters) solution.

Percentage Weight-in-volume can tell us about the degree of concentration of a given solution.

The solute can be crystalline or non-crystalline in nature.

The number of grams of glucose present in a 5% glucose solution is 5 grams.

a% of a glucose solution = a grams of glucose in a 100 mL solution

Hence, 5% glucose solution = 5 grams of glucose / 100 mL solution

Therefore, the number of grams of glucose present in a 5% glucose solution is 5 grams.

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1) Chemical equation.

2) Types of reaction.

Synthesis: a compound is made from simpler materials.

Decomposition: a compound is broken down into simpler compounds.

Single replacement: one element that starts out by itself replaces another element in a compound.

Double replacement: positive and negative ions in two compounds switch places.

Combustion: a compound containing Carbon and Hydrogen combines with Oxygen gas and produces carbon dioxide and water.

3) The chemical reaction above is a combustion where C10H22 combines with O2.

.

Answer:

The reaction will give off 140 kJ of heat.

Explanation:

The every mole of propane burned, 4 moles of water vapor are produced. Therefore, 0.700 L of propane gas will produce 4 times the volume of water vapor. Hence, 0.700 L of propane gas will produce 4 * 0.700 L = 2.800 L of water vapor.

The balanced equation for the complete combustion of propane (C3H8) with oxygen (O2) to produce carbon dioxide (CO2) and water vapor (H2O) is:

C3H8 + 5O2 → 3CO2 + 4H2O

According to the balanced equation, it is evident that 5 moles of oxygen gas are required to burn 1 mole of propane gas completely. To determine the volume of oxygen gas needed, we need to use the ideal gas law, which states that equal volumes of gases at the same temperature and pressure contain an equal number of molecules.

Given that 0.700 L of propane gas is being burned, we can assume the same volume of oxygen gas is needed. So, 0.700 L of oxygen gas will be required.

From the balanced equation, we can see that for every mole of propane burned, 3 moles of carbon dioxide are produced. Since the volume of gases is directly proportional to the number of moles, we can conclude that 0.700 L of propane gas will produce 3 times the volume of carbon dioxide gas. Therefore, 0.700 L of propane gas will produce 3 * 0.700 L = 2.100 L of carbon dioxide gas.

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Answer:

1.6 L CH3OH

Explanation:

3.20 L H2 x (1 mol H2/22.4 L H2) x (1 mol CH3OH/2 mol H2) x (22.4 L CH3OH/1 mol CH3OH) = 1.60 LCH3OH

1.602 liters of CH₃OH gas are formed when 3.20 L of H₂ gas are completely reacted at STP according to the following chemical reaction:

CO(g) + 2 H₂(g) → CH₃OH(g)

Remember 1 mol of an ideal gas has a volume of 22.4 L at STP

To find the volume of CH₃OH gas formed when 3.20 L of H₂ gas is completely reacted, we need to use stoichiometry and the given balanced chemical equation.

The balanced equation is:

CO(g) + 2 H₂(g) → CH₃OH(g)

From the balanced equation, we can see that 1 mol of CO reacts with 2 moles of H₂ to produce 1 mole of CH₃OH.

Step 1: Convert the given volume of H₂ gas to moles at STP.

Using the information provided, 1 mol of any ideal gas at STP (Standard Temperature and Pressure) occupies 22.4 L.

Number of moles of H₂ gas = Volume of H2 gas at STP / Volume of 1 mol of H₂ gas at STP

Number of moles of H₂ gas = 3.20 L / 22.4 L/mol

Number of moles of H₂ gas = 0.14286 moles (rounded to 5 decimal places)

Step 2: Use stoichiometry to find the moles of CH₃OH formed.

From the balanced equation, we know that 1 mol of CO reacts with 2 moles of H₂ to produce 1 mole of CH₃OH.

Since the ratio of H₂ to CH₃OH is 2:1, the number of moles of CH₃OH formed will be half of the moles of H₂ used in the reaction.

Number of moles of CH₃OH = (1/2) * Number of moles of H₂

Number of moles of CH₃OH = (1/2) * 0.14286

Number of moles of CH₃OH = 0.07143 moles (rounded to 5 decimal places)

Step 3: Convert the moles of CH₃OH to volume at STP.

Using the information provided, 1 mol of any ideal gas at STP (Standard Temperature and Pressure) occupies 22.4 L.

Volume of CH₃OH gas at STP = Number of moles of CH₃OH * Volume of 1 mol of CH₃OH gas at STP

Volume of CH₃OH gas at STP = 0.07143 moles * 22.4 L/mol

Volume of CH₃OH gas at STP = 1.602 L (rounded to 3 decimal places)

Therefore, approximately 1.602 liters of CH₃OH gas are formed when 3.20 liters of H₂ gas are completely reacted at STP.

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Answer:

Molarity= Moles of solute/Volume of solution(in litres)

Solute:NaOH

Moles =mass/Molar Mass

Molar mass of NaOH= 22.9+16+1=39.9g/mol

Substituting

m=80/39.9

=2.0moles

Volume has to be in litres

There's 1000ml to a litre

So 500ml equals 0.5litres

Molarity = 2/0.5

= 4M.

Answer: American red squirrel

Explanation:

The American red squirrel is the smallest squirrel. The color of the fur may vary from season to season. The color of the squirrel can also vary depending of the environment in which it lives. In summer the black stripe appears on the sides over the white fur. It has a backbone and like other mammals nurses the offsprings. It has a bushy tail. It is a native of North America. Red fur appear on the back and white on the belly. Strong claws, strong muscles, and compact body are other key features of the squirrel.

20.23 mL is the volume of 0.5 moles of methanol, if it has a density of 0.792 g/mL.

Methanol (CH3OH), also known as methyl alcohol, wood alcohol, or wood spirit, is the most basic of a large group of organic compounds known as alcohols. It is made up of a methyl group (CH3) connected to a hydroxy group (OH).

The destructive distillation of wood once produced methanol. The direct combining of hydrogen and carbon monoxide gas in the presence of a catalyst is the foundation of the modern method for making methanol. Syngas, a blend of carbon monoxide and hydrogen produced from biomass, is being used more frequently to create methanol.

The formula for density is

Density = mass/volume

Here, density is given that is 0.792 g/ml

mass is 0.5 moles which is equal to 16.02g      (substance mass conversion)

Now we need to find volume that is

V = mass/density

V =  16.02g/0.792 g/mL

V = 20.23 mL

Thus, 20.23 mL is the volume of 0.5 moles of methanol

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Explanation:

To solve this question, we will use the Clayperon Equation:

P.V = n.R.T

where:

P = 101.28 kPa

1 atm = 101,325 Pa

x atm = 101,280 Pa

x = 1 atm

V = 37.058 L

n = we don't know

R = 0.082 atm.L/K.mol

T = -139.88 ºC = -139.88+273.15 = 133.27 K

1*37.058 = n*0.082*133.27

n = 0.29 moles

Answer: 0.29 moles

Answer:

See Explanation

Explanation:

There is a concept in chemistry called the denticity of  a ligand. The denticity of a ligand refers to the number of donor groups in a given ligand that can bond to a central metal atom or ion. In other words, it is the number of bonding positions available in a ligand.

Ammonia has only one bonding position(monodentate ligand); that is, the lone pair on its nitrogen atom. Hence, six ammonia ligands are required to form an octahedral complex with the nickel center.

However, ethylenediamine has two positions available for bonding to a central metal atom or ion. These are the two nitrogen atoms present in the molecule. Hence, each molecule of ethylenediamine is bidentate, bonding to the nickel using two "teeth". Hence, three ethylenediamine molecules form six bonds to the nickel center as required in an octahedral complex.

The standard deviation of the sample is 0.579, rounded to the correct number of significant figures.

To calculate the standard deviation of the sample, we need to follow these steps:

To find the mean, we sum up all the data points and divide by the number of data points. Let's calculate it:

(3.09 + 4 + 2.775 + 2.5 + 3.80) / 5 = 16.165 / 5 = 3.233

To do this, we subtract the mean (3.233) from each data point and square the result:

(3.09 - 3.233)^2 = 0.020049

(4 - 3.233)^2 = 0.586489

(2.775 - 3.233)^2 = 0.209025

(2.5 - 3.233)^2 = 0.537289

(3.80 - 3.233)^2 = 0.323329

To find the variance, we sum up the squared differences from step 2 and divide by the number of data points:

(0.020049 + 0.586489 + 0.209025 + 0.537289 + 0.323329) / 5 = 1.676181 / 5 = 0.3352362

√0.3352362 = 0.579 (rounded to three significant figures)

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Answer:

Mean: 350

Median: 300

Range: 650

Mode: 300

Explanation:

Mean: 800+300+150+300+200= 1750, 1750 divided by 5 = 350

You add up all the numbers then you divide it by the TOTAL NUMBER of NUMBERS to find the mean.

Median: (150, 200, 300, 300, 800)

To find Median put the numbers in order from greatest to least then you choose the middle number.

Range: Range is the distance from the smallest number to the largest the way to solve this is (Highest number) - (lowest number). In your case its 800-150 which equals 650

Mode: The mode is the value that appears most frequently in a data set.

Brainliest?

Since Lutetium-177 is a beta and gamma emitter, the daughter nuclide produced from the decay of this radioisotope is 177Hf.

Beta emission of a radioisotope yields a  daughter nuclide whose amass number is the same as that of its parent nucleus but its atomic number is greater is greater than that of the parent nucleus by 1 unit.

Also, gamma emission does not lead to any change in the mass number of atomic number of the daughter nucleus produced.

Hence, the stable daughter nuclide, 177Hf is produced.

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Answer:

molecules will speed up

Explanation:

Answer:

Nickel Nitrate

The balanced chemical equation for the combustion of \(CH_{3}\) (methane) is:

\(CH_{4} + 2O_{2} = > CO_{2} + 2H_{2} O\)

From the balanced equation, we can see that for every mole of \(CH_{4}\) combusted, one mole of \(CO_{2}\) is formed.

Given that 25 moles of \(CH_{3}\) (methane) combust, we can assume that it refers to 25 moles of \(CH_{4}\) since they have the same chemical formula.

Therefore, the number of moles of \(CO_{2}\) formed will also be 25 moles, as the reaction produces an equal number of moles of \(CO_{2}\).

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Since the number of atoms which are reacting are equal to the number of to the number of atoms in the product, this reaction demonstrates that matter is neither created nor destroyed in a chemical reaction.

Any system that is closed to all exchanges of matter and energy is subject to the law of conservation of matter, which is a general law of physics and chemistry. This law states that regardless of how the components rearrange themselves, the mass of an object or group of things remains constant over time.

A chemical reaction is a procedure that causes one group of chemical components to change chemically into another. Chemical reactions, which can frequently be described by a chemical equation, traditionally include changes that solely affect the locations of electrons in the formation and dissolution of chemical bonds between atoms, with no change to the nuclei.

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Salt equivalent weight = (0.185 g) / (Moles of salt)

The results from the acid-base titration may be used to compute the equivalent weight of the nickel salt.

To begin, determine the number of moles of HCl utilized in the reaction:

HCl moles = 0.1013 N * (0.0630 L) = 0.006426 moles

Next, compute the moles of OH- ions that interacted with the HCl:

OH- moles = 0.006426 moles

We now understand how one mole of OH- interacts with one mole of H+. As a result, the number of moles of H+ in the reaction equals the number of moles of OH-.

Finally, the moles of nickel salt present in the sample may be estimated as follows:

(Moles of H+) / (n + p) = Moles of salt

By dividing the mass of the salt sample by the number of moles of salt, the equivalent weight of the salt (mass of salt containing one mole of NH3) may be calculated:

Salt equivalent weight = (0.185 g) / (Moles of salt)

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