What is an amu?

lol I'm asking alot of questions






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Answer:

200 J

Explanation:

Given that,

Force, F = 20 N

Distance covered in the direction of force, d = 10 m

We need to find the effort made by Mrs. Lasarati. It  will be given by :

W = Fd

W = 20 N × 10 m

W = 200 J

So, the required effort made by Mrs. Lasarati is 200 J.

The mass trend that among four moons is highest close to Jupiter and decreases with distance, with the inner circular members of this group being slightly lesser than the two end moons.

There are several satellites in operation. They are used for a number of purposes, including as the weather forecasting, amateur radio, television broadcasting, and the Global Positioning System. They use telescopes to look out at the planetary system in order to do research and collect data.

According to UNOOSA statistics from the Concerned Scientists, there are 8,261 satellites orbiting Earth as of December 2022, although only 4,852 among them are currently in use.

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Normal forces are those that are directed upward force and stop the rider from falling downhill. The normal force is the pressure that surfaces provide to stop solid objects from piercing one another.

In touch, normal force is a force. Two surfaces cannot exert a normal force on one another if they are not in contact.

The Tornado is a roller coaster that features a vertical cylinder that spins quickly around its vertical axis. The rider is pushed against the inside wall of the cylinder by the rotation of the tornado, and the cylinder's floor falls away. Normal forces are those that are directed upward and stop the rider from falling downhill.

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The moon of Jupiter, Ganymede is the largest moon in the solar system. The mass of Jupiter when the orbital period and the distance from the centre of the orbit are given is calculated to be 1.57 × 10²⁷ kg.

The time required to complete one revolution in an orbit around the planet is known as the Orbital Time period of motion. The orbital distance's cube is directly proportional to the square of the time period.

Given that,

Orbital distance R = 1.07 × 10⁹ m

Time period T = 6.18 × 10⁵ s

We know the formula of time period as,

T² = 4 π² R³/ G M

where, M is the mass of Jupiter

G is the gravitational constant

(6.18 × 10⁵)² = 4 π² (1.07 × 10⁹)³/(6.67 × 10⁻¹¹) M

Making M as subject, we have,

M = 4 π² (1.07 × 10⁹)³/[ (6.67 × 10⁻¹¹) (6.18 × 10⁵)²] = 1.57 × 10²⁷ kg

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Answer:

25cm^2

Explanation:

area of square = side × side

length of side given = 5

area of this square = 5× 5

= 25cm^2

hope it helps

Answer:

25cm^2

Explanation:

Answer:

long stapler

Explanation:

The speed of the probe as it passes through point is 32.5 mm/h^2.

To determine the speed of the space probe as it passes through point b, we need more information such as the distance between points a and b and the time it takes the probe to travel that distance. Without this information, we cannot calculate the speed at point b.

However, we can use the given information to calculate the acceleration of the probe using the formula:

Acceleration (a) = (final velocity (vf) - initial velocity (vi)) / time (t)

Since the probe is fired from the earth, we can assume that its initial velocity is 0. Therefore, we can simplify the equation to:

Acceleration (a) = vf / t

Using the given velocity (va = 32.5 mm/h) and assuming it takes the probe 1 hour to travel from point a to point b, we can calculate the acceleration:

Acceleration (a) = 32.5 mm/h / 1 h = 32.5 mm/h^2.

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The kinetic energy acquired by the nail is: 91.5 J.

Kinetic energy is a form of energy that is associated with the motion of an object. It is the energy of a body or a system due to its motion. It is represented by the symbol K and is calculated by multiplying half of the object's mass with its velocity squared. Kinetic energy is always greater than zero and is equal to the amount of work needed to accelerate the body from its initial velocity to its final velocity.

The kinetic energy acquired by the nail when it is struck by the hammer can be estimated using the equation
KE = (1/2) mv^2
where m is the mass of the nail and v is the speed of the hammer.
In this case, m = 11.5 g and v = 4.36 m/s.
Therefore, the kinetic energy acquired by the nail is:
KE = (1/2) * 11.5 g * (4.36 m/s)^2
= 91.5 J.

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A  hybrid electric vehicle (hev) gasoline engine usually uses a low viscosity of engine oil.

The viscosity of engine oil recommended for a hybrid electric vehicle  gasoline engine depends on  several prevailing conditions such as;

The most hybrid electric vehicle gasoline engines typically require low-viscosity engine oils, such as 0W-20, 5W-20, or 5W-30.

These oils have a lower viscosity, which helps reduce friction and improve fuel efficiency.

So we can conclude that a  hybrid electric vehicle (hev) gasoline engine usually uses a low viscosity of engine oil.

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Answer:

0.02 Hertz

Explanation:

Answer:

other answer is correct it is 0.02 Hz

Explanation:

Answer: By studying seismic waves scientists have learned about the layers of the Earth.

Answer:

3.5 Hours

Explanation:

I believe all that has to be done is dividing 84 by 24, which results in 3.5, or 3 and a 1/2 hours.

Answer:

C. 1.42 s

Explanation:

Givens:

length = 0.5m

gravity = 9.807 m/s

Solve:

T = 2π√(L/g)

T = 2π√(0.5/9.807)

T = 2π√(0.0509)

T = 2π * 0.22579

T = 6.28318 * 0.22579

T = 1.418 ≈ 1.42s

The minimum period for a satellite in orbit around a spherical planet of uniform density can be derived by considering the gravitational force and the centripetal force acting on the satellite. By equating these forces, the minimum period can be determined.

The gravitational force acting on the satellite is given by the equation F_grav = (G * M * m) / r^2, where G is the gravitational constant, M is the mass of the planet, m is the mass of the satellite, and r is the distance between the center of the planet and the satellite.

The centripetal force required to keep the satellite in orbit is given by F_centripetal = (m * v^2) / r, where v is the velocity of the satellite.

By equating the gravitational force and the centripetal force, we have (G * M * m) / r^2 = (m * v^2) / r.

Simplifying the equation, we can solve for the velocity of the satellite, v, in terms of the gravitational constant, the mass of the planet, and the distance between the satellite and the planet.

The period of the satellite is given by the equation T = (2 * pi * r) / v, where T is the period and r is the distance between the center of the planet and the satellite.

By substituting the expression for v into the period equation, we can derive the minimum period for a satellite in orbit around a spherical planet of uniform density.

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Answer:

Explanation:

b )

Normal force R = mgcosθ

= 76.6 x 9.8 x cos 38

R = 591.5 N

c )

Force of friction

= μ R

μ is coefficient of friction .

= .15 x 591.5

= 88.73 N

d )

Net force

= mg sinθ - friction

= 76.6 x 9.8 x sin 38 - 88.73

= 462.16 - 88.73

= 373.43 N

Acceleration = 373.43 / 76.6

a = 4.87 m / s²

e )

v² = u² + 2 a s

s = 40.5 m

a = 4.87

u = 0

v² = 0 +2 x 4.87 x 40.5

= 394.5

v = 19.86 m /s

f )

v = u + a t

19.86 = 0 + 4.87 t

t = 4 .07 s

Answer:

All 3 cards are completely different

According to the given question, the correct answer is: The peak height in a mass spectrum is determined by the relative abundance of a particular ion.

The peak height in a mass spectrum is determined by the relative abundance of a particular ion. In a mass spectrum, each peak represents a specific ion with a particular mass-to-charge ratio (m/z). The height of a peak corresponds to the number of ions with that specific m/z value detected by the mass spectrometer.

To summarize the steps:
1. Ions are generated from the sample in the mass spectrometer.
2. Ions are separated based on their mass-to-charge ratio (m/z).
3. The mass spectrometer detects the ions and records their abundance.
4. A mass spectrum is produced, with peaks representing the different ions.
5. The height of each peak corresponds to the relative abundance of that specific ion.

So, the correct answer is: The peak height in a mass spectrum is determined by the relative abundance of a particular ion.

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Answer:

The time taken is missing in the question. The time is 18 minutes.

The answer is 34.3 km/hr

Explanation:

Average velocity is the speed or the velocity which is required to cover a distance in a time interval.

The time taken is = 18 min

                            = 18/60 hours

The distance from the university to her home is = 10.3 km

Therefore, the average velocity is = displacement/time taken

                                                         = 10.3 / (18/60) km/hr

                                                         = 34.3 km/hr

Hence, the average velocity is 34.3 km/hr

The correct statement summarizing the events in the early universe according to the Big Bang theory is option D.

After the forces of the cosmos came together, there was a time of inflation. Then subatomic matter and antimatter particles appeared, the majority of which annihilated to produce photons. Protons, neutrons, electrons, and neutrinos were among the particles that did not decay, though. During the first three minutes, protons and neutrons fused, revealing the universe's basic chemical make-up.

All of the fundamental forces of nature were combined in the early moments of the Big Bang. But the forces split into various interactions as the cosmos grew and contracted. This trend was accompanied by inflation, a rapid expansion. After inflation, a hot, thick soup of energy flooded the entire cosmos.

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The orbits of disk stars in the Milky Way Galaxy are most like the orbits of planets in the solar system. These orbits have no common orbital plane and range from circular to highly elongated. Therefore, the correct option is 3. planets, no common orbital plane, range from circular to highly elongated.

The Milky Way galaxy is a collection of stars, gas, and dust that are gravitationally bound to each other. The stars in the Milky Way are divided into different populations based on their location and motion within the galaxy.

One of the populations is the disk stars, which are located in a flattened disk-like structure that surrounds the central bulge of the galaxy.

The orbits of disk stars in the Milky Way are most like the orbits of planets in the solar system. This is because both types of objects have orbits that are roughly coplanar (i.e., in the same plane), but there is no common orbital plane for all of the objects.

In other words, the orbits of both disk stars and planets are oriented in different directions relative to each other.

Additionally, the orbits of disk stars and planets can range from circular to highly elongated. A circular orbit is one where the object moves at a constant distance from the center of mass, while an elongated orbit is one where the object's distance from the center of mass varies over time.

The range of orbits for disk stars and planets can vary depending on their initial conditions and interactions with other objects in the galaxy or solar system.

Therefore, option 3, "planets, no common orbital plane, range from circular to highly elongated," is the correct choice for describing the orbits of disk stars in the Milky Way galaxy.

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correct question

The orbits of disk stars in the Milky Way Galaxy are most like the orbits of _____ in the solar system. These orbits have _____ and _____. choose the correct option

1. comets, no common orbital plane, range from circular to highly elongated

2. planets, no common orbital plane, are nearly circular

3. planets, no common orbital plane, range from circular to highly elongated

4. comets, nearly the same orbital plane, range from circular to highly elongated

5. planets, nearly the same orbital plane, are nearly circula

The actual length of line AB is 147.4 m.  We know that the extension produced in a body, E = (FL) / (A × Y) where F = Force applied, L = Length of the object A = Cross-sectional area of the object, Y = Young's modulus of elasticity

Now, as the extension is not given, we cannot directly calculate the length of the line AB.

Hence, we consider the actual length of the line as l. Therefore, the extension produced due to the weight of the tape is l - L. Now, we know that the extension produced due to the weight of the tape is negligible in comparison to the extension produced due to the weight of the line AB.

Hence, the extension produced in the tape can be neglected in this case.

Therefore, the extension produced is due to the weight of the line AB.

That is,E = (F + 120)l / (11.25 × 200) where F + 120 is the force applied to measure the length of AB.

On simplification, we get E = (l / 2000) (F + 120) / (11.25) .....(1)

Now, as per the given data, when the line AB was measured, it was measured as 150 m.

Therefore, the actual length of the line is l - (extension produced due to the weight of the line AB).

Therefore, the length of line AB, l = 150 + (l - L) .......(2)

On substituting the value of l from equation (2) in equation (1), we get E = [(150 + l - L) / 2000] (F + 120) / (11.25)

On simplification, we get,8.89 E = (l + 150 - 30) (F + 120)

On substituting the values of E and F, we get8.89 × [(l - 30) / 2000] × [F + 120]

= (l + 120) (11.25)

On simplification, we get  l = 147.4 m.

Therefore, the actual length of line AB is 147.4 m.

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Answer:

A. amplitude

Explanation:

please vote me brainliest?? thanks:)

Answer:

1450.4 KN\(m^{2}\)

Explanation:

Pressure = ρhg

where: ρ is the density of the liquid, h is the height and g the force of gravity.

Total pressure exerted by the liquids at the base = Pressure of oil + Pressure of water + Pressure of mercury

So that,

i. Pressure of oil = ρhg

(ρ = 0.8 g/cm³ = 800 kg/m³)

                        = 800 x 5 x 9.8

                        = 39200

Pressure of oil = 39200 N\(m^{2}\)

ii. Pressure of water = ρhg

(ρ = 1 g/cm³ = 1000 kg/m³)

                                      = 1000 x 8 x 9.8

                                     = 78400

Pressure of water = 78400 N\(m^{2}\)

ii. Pressure of mercury = ρhg

(ρ = 13.6 g/cm³ = 13600 kg/m³)

                      = 13600 x 10 x 9.8

                      = 1332800

Pressure of mercury = 1332800 N\(m^{2}\)

So that,

Total pressure exerted by the liquids at the base = 39200 + 78400 + 1332800

                                               = 1450400

                                               = 1450.4 KN\(m^{2}\)

Total pressure exerted by the liquids at the base is 1450.4 KN\(m^{2}\).

For an object that is only 150 years old, there would still be a significant amount of carbon-14 present in the sample, which would make it difficult to accurately determine the age of the object. The age of the sample is 23,108 years.

We know that;

0.693/t1/2 = 2.303/t log (No/N)

0.693/5700 = 2.303/t log (80/5)

0.693/5700 = 2.773/t

1.2 * 10^-4 = 2.773/t

t = 2.773/1.2 * 10^-4

t = 23,108 years

Carbon-14 dating is a radiometric dating method used to determine the age of organic materials up to approximately 50,000 years old. Carbon-14 (14C) is a radioactive isotope of carbon that decays over time, and the amount of 14C remaining in a sample can be used to determine its age.

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When an airplane travels 640 miles from Topeka to Houston in 3. 2 hours, going against the wind. The return trip is with the wind and takes only 2 hours. Then the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

Let Va is the velocity of the airplane

Va is the velocity of the wind

When flying against the wind then

(Va+Vw)*(3.2 hours) = 640

3.2Va + 3.2Vw = 640

3.2Vw = 640 - 3.2Va

Vw = 200 - Va----------------(1)

When flying with the wind:

(Va-V)*(2 hours) = 640km

2Va - 2Vw = 640

Va - Vw = 320 ----------------(2)

Putting the value of VW in equation (2) we get

Va - (200-Va) = 320

2Va = 320 +200

2Va = 520

Va = 260

Putting this value in equation (2)

Vw =Va - 360

Vw = 100

Therefore the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

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5

i need points sorry if its wrong

Answer:

im not really sure, sorry

The maximum kinetic energy of the ejected photoelectrons is approximately 1.922 x 10⁻¹⁸ eV.

To determine the maximum kinetic energy of the ejected photoelectrons, we can use the equation for the kinetic energy of a photoelectron:

KE = E - W

First, let's calculate the energy of the incident photon using the equation:

E = hc / λ

where:

h is Planck's constant (approximately 4.136 x 10⁻¹⁵ eV·s),

c is the speed of light (approximately 3 x 10⁸ m/s),

λ is the wavelength of the incident light.

Converting the wavelength to meters:

λ = 150 nm = 150 x 10⁻⁹ m

Substituting the values into the equation:

E = (4.136 x 10⁻¹⁵ eV·s x 3 x 10⁸ m/s) / (150 x 10⁻⁹ m)

  = 8.272 x 10⁻¹⁸ eV

Now we can calculate the maximum kinetic energy of the photoelectron:

KE = E - W

  = (8.272 x 10⁻¹⁸ eV) - (6.35 eV)

  = 1.922 x 10⁻¹⁸ eV

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