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Jill would measure the meter stick to be approximately 0.959 meters long while she is traveling at a speed of 0.280c according to special relativity.

According to special relativity, when an object is moving at a significant fraction of the speed of light, length contraction occurs. This means that the length of an object in motion appears shorter to an observer in another reference frame.

In this case, Jill is traveling at a speed of 0.280c relative to an observer on Earth. To calculate the length contraction, we can use the Lorentz contraction formula:

L' = L * √(1 - (v^2/c^2))

L' is the measured length (in the spaceship's frame of reference)

L is the rest length (length of the meter stick on Earth)

v is the relative velocity (0.280c)

c is the speed of light

Assuming the rest length of the meter stick is 1 meter (L = 1 m), we can substitute the values into the formula:

L' = 1 m * √(1 - (0.280c)^2/c^2)

L' = 1 m * √(1 - 0.0784)

L' = 1 m * √(0.9216)

L' ≈ 0.959 m

Therefore, Jill would measure the meter stick to be approximately 0.959 meters long while she is traveling at a speed of 0.280c.

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The carbon isotope was cobined with the proton to produce the nitrogen isotope hence it is a fusion reaction.

The term nuclear fusion refers to a kind of reaction in which two nuclei fuse together to give rise to a single nuclei with the evolution of energy.

We can see that the carbon isotope was cobined with the proton to produce the nitrogen isotope hence it is a fusion reaction.

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Answer:

A. Nuclear fusion

Explanation:

got it right, trust

Answer:

Sling Psychrometer

Explanation:

A sling psychrometer measures relative humidity through the process of evaporation. It contains two thermometers. The cloth around one of the thermometers is wetted and slung around in the air so the moisture evaporates, which has a cooling effect. The relative humidity is then calculated using the difference in temperature for the two thermometers.

Answer:

Explanation:

Three screens are placed one behind the other and light falls on all of them from a torch . In this case a mirror can be only the last screen . In case of first or second screen being a mirror , light would not have reached the last screen because the nature of mirror is to reflect the light back.

Hence , the only possibility is that , the last screen is mirror.

The result of part (b), where the uncertainty in position is approximately equal to the length of the square well does not directly compare with the actual ground-state energy.

The uncertainty principle which states that there is a trade-off between the precision of measuring position and momentum, does not directly provide information about the energy levels of the system.

The actual ground-state energy can be calculated using the Schrödinger equation and depends on the specific properties of the system, such as the mass of the particle and the potential energy of the well.

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Answer:

Explanation:

Acceleration is the time rate of change, or the rate, of the velocity. Therefore, the slope y/x of a speed vs time graph would give the acceleration. If the acceleration is said to be positive, the graph would be a straight line that is at a constant increase over time.

If the length is doubled in a solenoid with n loops, a cross-sectional area a, and a current I, the magnetic field will half its initial value.

B = μo N I / L

B = Magnetic field

μo = Permeability constant

N = Number of turns

I = Current

L = Length of the coil

After the length of the coil is doubled,

L' = 2 L

B' = μo N I / L'

B' = μo N I / 2 L

B' = B / 2

If the length is doubled in a solenoid, its field will be half of its original value. A solenoid is a type of an electromagnet. It is formed by a helical coil of wire. The coil's diameter is less than its length. It generates a controlled magnetic field.

Therefore, when the length is doubled in a solenoid, its field will be half of its original value.

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Answer:

See below

Explanation:

Assuming no resistance

DISTANCE =  1/2 a t^2

443 = 1/2 (9.81)t^2      Shows t = 9.5 seconds

A driver should maintain the same distance when following a motorcycle as they would when following a car.

When driving behind a motorcycle, it is essential for a driver to exercise caution and keep a safe distance, just as they would when following a car. Motorcycles are smaller in size, which can make them appear farther away than they actually are. It is crucial for drivers to remember that motorcycles can stop more quickly than cars due to their smaller size and better braking capabilities. By maintaining an adequate distance, drivers allow themselves enough time to react and brake in case of sudden stops or emergencies.

Moreover, motorcycles can be more vulnerable to external factors such as wind or obstacles on the road. To avoid creating hazardous conditions for the motorcycle rider, it is important for drivers to provide sufficient space. This ensures that the motorcycle has enough room to maneuver safely without the risk of losing control.

Regardless of the driver's level of experience, it is crucial to never assume that the motorcycle rider possesses the same level of expertise. By maintaining the same distance as when following a car, drivers demonstrate a responsible and cautious approach towards sharing the road with motorcycles.

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The application of maximal voltage in the isolated skeletal muscle will recruit all the muscle fibres.

The neuromuscular junction allows transmission of signals to motor units that further transmit the singal inside the cell of skeletal muscle. The depolarization, repolarization and hyperpolarisation of nerves are the associated features that lead to changes.

The subsequent effect is release of calcium ions from sarcoplasmic reticulum which initiates biochemical pathways involving changes in protein structure. The locomotory proteins are further activated leading to contractility in muscles.

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Answer:

false

Explanation:

Projectile motion is an item or particle that is projected near the Earth's surface and travels along a curved route. The given statement is false.

An item or particle that is projected near the Earth's surface and travels along a curved route under the influence of gravity solely is said to be in projectile motion. Galileo demonstrated that this curved route is a parabola, although it might also be a line in a particular situation when it is hurled directly upwards.

As we can see in the image below, during a projectile motion the components of the acceleration are horizontal and vertical components. Therefore, the statement "For a horizontally-launched projectile, the vertical component of acceleration is zero while the horizontal component of acceleration is constant and non-zero" is false.

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The equation for Newton's second law of motion is F = ma, and the S.I unit of force is Newtons.

Newton's second law of motion states that the acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass.

Mathematically, the Newton's second law is given as;

F = ma

where;

The S.I units of the physical quantities used in the above equations are;

mass = kg

acceleration = m/s²

force = N

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Explanation:

Acceleration and the other term are the same physical phenomenon - just with opposite affects. Acceleration increases velocity, while the other term that begins with the letter "R" reduces.

***(Brainly's language filter is blocking the use of the second term in my answer.)***

Acceleration is defined as the rate of change of the velocity of an object per unit of time...

\(a = \frac{dv}{dt}\)

Acceleration would be a POSITIVE (+) quantity, while the r-word would be negative (-).

The man acquires a velocity of approximately -0.00195 m/s in the opposite direction.

To solve this problem, we can use the principle of conservation of momentum. According to this principle, the total momentum before the interaction is equal to the total momentum after the interaction.

The momentum of an object is given by the product of its mass and velocity (p = mv). Let's denote the initial velocity of the man as v_m and the final velocity of the man as v'_m. The initial velocity of the stone is 0 m/s, and its final velocity is 2.5 m/s.

The total momentum before the interaction is zero since the stone is initially at rest:

Initial momentum = m_man * v_man + m_stone * v_stone = 78 kg * v_man + 0 kg * 0 m/s = 78 kg * v_man

The total momentum after the interaction is the sum of the individual momenta of the man and the stone:

Final momentum = m_man * v'_man + m_stone * v'_stone = 78 kg * v'_man + 0.061 kg * 2.5 m/s

Since the total momentum is conserved, we can equate the initial and final momenta:

78 kg * v_man = 78 kg * v'_man + 0.061 kg * 2.5 m/s

Now we can solve for v'_man, which is the final velocity of the man:

78 kg * v_man - 0.061 kg * 2.5 m/s = 78 kg * v'_man

78 kg * v'_man = 78 kg * v_man - 0.061 kg * 2.5 m/s

v'_man = (78 kg * v_man - 0.061 kg * 2.5 m/s) / 78 kg

Plugging in the values, we have:

v'_man = (78 kg * v_man - 0.061 kg * 2.5 m/s) / 78 kg

Since the man is initially at rest (v_man = 0 m/s), we can simplify the equation to:

v'_man = (0 - 0.061 kg * 2.5 m/s) / 78 kg

v'_man = -0.1525 m/s / 78 kg

v'_man ≈ -0.00195 m/s

Therefore, the man acquires a velocity of approximately -0.00195 m/s in the opposite direction as a result of shoving the stone.

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Answer:

B. Electrical energy transforms into mechanical energy.

Explanation:

In the case when the wire loop transforms between the two permanent magnets in a generator so here the electrical energy turns to mechanical energy as there is a working principle behind the generator that the electrical energy would turns into mechanical energy

Therefore as per the given scenario, the option b is correct

And, the rest of the options are wrong

The total charge flown across any cross section of the wire in time interval 0-T is determined from the area under the curve as ¹/₂i₀T.

option (2) is the correct answer.

The total charge flown across any cross section of the wire in time interval 0-T is calculated as follows;

The total charge flowing = area under the curve

area under the curve = ¹/₂ x base of the triangle x height of the triangle

area under the curve = ¹/₂ x T  x i₀

area under the curve = ¹/₂i₀T

Thus, the total charge flown across any cross section of the wire in time interval 0-T is determined from the area under the curve as ¹/₂i₀T.

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The movement of the school bus that is powered by petroleum as chemical potential energy is an example of Kinetic energy. This is because the chemical potential energy from the petroleum is transferred through the engine, converting it into kinetic energy which then moves the bus.

Kinetic energy refers to the energy of an object in motion. It is defined as the work required to bring a body of a given mass from a state of rest to a state of motion. It is measured as the amount of work needed to accelerate a body of a given mass to a given speed. Kinetic energy is proportional to the square of the object's speed, which means that as the object's speed increases, so does its kinetic energy. Therefore, the movement of the bus, which is an object in motion, is an example of kinetic energy.

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The water pressure at a depth of 145 m behind the Hoover Dam in Nevada is 13,940,010 N/m²

To find the water pressure at a depth of 145 m behind the Hoover Dam in Nevada, we will use the water pressure formula, which includes the terms "water pressure" and "density".

The water pressure formula is: P = ρgh

Where:
P = water pressure (in N/m²)
ρ = density of water (in N/m³)
g = acceleration due to gravity (9.81 m/s²)
h = depth of water (in meters)

Given the weight density of water is 9800 N/m³, and the depth (h) is 145 m:

Step 1: Plug in the given values into the formula:
P = (9800 N/m³)(9.81 m/s²)(145 m)

Step 2: Multiply the values:
P = 9800 x 9.81 x 145

Step 3: Calculate the final result:
P = 13,940,010 N/m²

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Initial speed of the coin (u)= 0 (As the coin is released from rest)

Acceleration due to gravity (a) = g = 9.81 m/s²

Time of fall (t) = 1.5 s

From equation of motion we have:

\( \boxed{ \bf{v = u + at}}\)

By substituting values in the equation, we get:

\( \longrightarrow \) v = 0 + 9.81 × 1.5

\( \longrightarrow \) v = 14.715 m/s

\( \therefore \) Speed of the coin as it hits the ground/Final speed of the coin = 14.715 m/s

The speed of the coin as it hits the ground is 14.715 m/s.

We can solve the problem above using the equation of acceleration under gravity.

⇒ Equation:

v = u+gt................... Equation 1

⇒ Where:

From the question,

⇒ Given:

Substitute these values into equation 1

Note the speed has a negative sign because it acts in the same direction as the acceleration due to gravity

Hence, the speed of the coin as it hits the ground is 14.715 m/s.

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The acceleration of the rock thrown with the velocity of 15 m/s and taking 20 seconds to come back is 2.97 \(m/s^2\),  and the direction of acceleration is downward.

When an item is moving, its velocity indicates how quickly its location is changing as seen from a specific point of view and as measured by a specific unit of time. When time is constant, speed and distance are directly proportional, when the distance is constant,

Given:

The velocity of the rock, v = 15 m/s,

The time taken to go and return t = 20 seconds,

Now, calculate the distance traveled by the rock,

d = v/t

d = 15/10  (Time taken to go upward is half of the total time)

d = 1.5 meters

So, calculate the acceleration by the second equation of motion,

\(s = vt + 1/2at^2\)

Substitute the values,

\(1.5 = 15*10 + 1/2 * a * 10^2\)

\(a = -2.97 \ m/s^2\)

Therefore, the acceleration of the rock thrown with the velocity of 15 m/s and taking 20 seconds to come back is 2.97 \(m/s^2\) And the direction of acceleration is downward.

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Answer: TOTAL DISPLACEmENT = 312.5 m

Explanation:  BY USING FORmULA OF AREA OF TRIANGLE

                        TOTAL DISPLACEmENT = 1/2 BASE X ALTITUDE

                                                                   = 1/2 (25-0)(35-10)

                                                                   =  1/2 (25)(25)

                                                                   =  625/2

                                                                   =  312.5 m

Answer:

B or D

Explanation:

The angular velocity of the turntable is 4.19 radians/second . The angular accelatation of the turntable is 8.38 radians/second².

The torque on the grammaphone record is 0.0419 Nm. The rotational kinetic energy is 0.0439 J. . The work done by the torque in 0.2 s is 0.00702 J.

The turntable has a uniform angular velocity of 40 rounds per minute. To convert this to radians per second, we can use the following conversion factors:

1 round = 2π radians (since there are 2π radians in a complete circle)

1 minute = 60 seconds

So, the angular velocity (ω) can be calculated as:

ω = 40 rounds/minute × (2π radians/round) × (1 minute/60 seconds)

ω ≈ 4.19 radians/second

The record accelerates uniformly to the angular velocity of the turntable in 0.5 seconds. Let's denote the angular acceleration as α. We can use the formula:

ω = ω₀ + αt

Plugging in the values, we get:

4.19 = 0 + α(0.5)

α = 4.19 / 0.5

α ≈ 8.38 radians/second²

The moment of inertia of the grammaphone record (I) is given as 5.0 x 10^(-3) kgm². We can use the formula:

τ = Iα

Plugging in the values, we get:

τ = (5.0 x 10^(-3)) x 8.38

τ ≈ 0.0419 Nm

The rotational kinetic energy (K) can be calculated using the formula:

K = 0.5 * I x ω²

Plugging in the values, we get:

K = 0.5 * (5.0 x 10^(-3)) * (4.19)²

K ≈ 0.0439 J

The work done (W) by the torque can be calculated using the formula:

W = τ * θ

Plugging in the values for α and t = 0.2s, we get:

θ ≈ 0.5 * 8.38 * (0.2)²

θ ≈ 0.1676 radians

Now, we can calculate the work done:

W = 0.0419 * 0.1676

W ≈ 0.00702 J

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An object's mass remains unchanged everywhere while the weight of an object depends on gravity, it is a measurement of how much gravity has an impact on an object. Therefore, an object’s mass, rather than its weight is used to indicate the amount of matter it contains.

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The range of a projectile is related to its maximum height by the equation \(\begin{equation}R = \frac{2 v^2 \sin{\theta} \cos{\theta}}{g}\). For projectiles with the same range, the product of the maximum height and the cosine of the launch angle is constant.

The range (R) of a projectile is the horizontal distance traveled by the projectile before it lands. The maximum height (h) of the projectile is the vertical distance reached above the initial launch height.

To find the relation between R, h₁, and h₂, we can use the fact that the range of a projectile is related to its maximum height through a specific equation.

The equation relating the range, maximum height, and the acceleration due to gravity (g) is given by:

\(\begin{equation}R = \frac{2 v^2 \sin{\theta} \cos{\theta}}{g}\)

where:

R is the range,

v is the initial velocity of the projectile,

θ is the launch angle, and

g is the acceleration due to gravity.

Now, let's consider two projectiles with maximum heights h1 and h₂. For both projectiles, the range R is the same. Let's assume the initial velocities of the projectiles are v₁ and v₂, and the launch angles are θ₁ and θ₂, respectively.

Using the equation for range, we can write the following expressions for the ranges of the two projectiles:

\(R_1 = \frac{2 v_1^2 \sin{\theta_1} \cos{\theta_1}}{g} \\\\R_2 = \frac{2 v_2^2 \sin{\theta_2} \cos{\theta_2}}{g}\)

Since R₁ = R₂, we can equate the two expressions:

\(\frac{2 v_1^2 \sin{\theta_1} \cos{\theta_1}}{g} = \frac{2 v_2^2 \sin{\theta_2} \cos{\theta_2}}{g}\)

Canceling out the common factors and rearranging the equation, we get:

v₁² * sinθ₁ * cosθ₁ = v₂² * sinθ₂ * cosθ₂

From this equation, we can see that the product of the initial velocity squared and the sine of the launch angle and the cosine of the launch angle is the same for both projectiles. Therefore, we can conclude that the range of a projectile is the same when the maximum heights h₁ and h₂ satisfy the condition:

h₁ * cosθ₁ = h₂ * cosθ₂

This means that the product of the maximum height and the cosine of the launch angle is constant for projectiles with the same range.

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Answer:

350 miles

Explanation:

because multiply 70 times 5 and you will get 350

To accelerate water in a horizontal pipe at a rate of 27 m/s^2, a pressure gradient of 364,500 Pa/m is required. This can be found using Bernoulli's equation, which relates pressure, velocity, and elevation of a fluid along a streamline.

Assuming the water in the pipe is incompressible and the pipe is frictionless, the pressure gradient required to accelerate the water at a rate of 27 m/s²can be found using Bernoulli's equation, which relates the pressure, velocity, and elevation of a fluid along a streamline.

Since the pipe is horizontal, the elevation does not change and can be ignored. Bernoulli's equation then simplifies to:

P1 + 1/2ρV1² = P2 + 1/2ρV2²

where P1 and V1 are the pressure and velocity at some point 1 along the streamline, and P2 and V2 are the pressure and velocity at another point 2 downstream along the same streamline.

Assuming that the water enters the pipe at rest (V1 = 0) and accelerates to a final velocity of 27 m/s (V2 = 27 m/s), and the density of water is 1000 kg/m³, we can solve for the pressure gradient along the streamline:

P1 - P2 = 1/2ρ(V2² - V1²) = 1/2(1000 kg/m³)(27 m/s)² = 364,500 Pa/m

Therefore, the pressure gradient required to accelerate water in a horizontal pipe at a rate of 27 m/s² is 364,500 Pa/m.

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