what is a transformer? what are the primary and secondary coils and how does it make use of induction?

Hi there!

Recall the equation for momentum:
\(\large\boxed{p = mv}\)

p = linear momentum (kgm/s)
m = mass (kg)

v = velocity (m/s)

We can calculate each object's momentum and compare.

Cement truck:
\(p = 20000 \cdot 5 = 100000kg\frac{m}{s}\)

Race car:
\(p = 1000 \cdot 90 = 90000 kg\frac{m}{s}}\)

Since 100,000 > 90,000, the cement truck has the greater momentum.

The average velocity is given by

Where d is the distance covered and t is the time taken.

For the given case, we have

d = 75 m

t = 8.9 s

Therefore, the average speed of the hockey player is 8.43 m/s

The hockey player is moving at a speed of 9.5 m/s.

Answer:

0.36 m

Explanation:

The moment of inertial of a wheel can be calculated as

Where r is the radius of the wheel and m is its mass.

Solving the equation for r, we get

So, replacing I by 0.13 kg m2 and m by 0.98 kg, we get

Therefore, the radius of the wheel is 0.36 m

The part of the microscope that the objectives are attached to is called the (C) nosepiece.

The nosepiece is a rotating mechanism located below the microscope's body tube. It holds the objectives, which are the lenses responsible for magnifying the specimen. The nosepiece typically has multiple positions, allowing the user to switch between different objective lenses for varying levels of magnification.

This convenient feature eliminates the need to manually remove and replace objectives when changing magnification. By rotating the nosepiece, different objectives can be brought into position above the specimen. This allows for quick and efficient adjustments in magnification without disrupting the viewing process.

Hence, the nosepiece plays a critical role in the microscope's functionality by providing a convenient way to switch between objectives and adjust the magnification level.

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Here is the complete question:

What is the name of the part of the microscope that the objectives are attached to? (Choose the best answer)

A. Ocular

B. Stage

C. Nosepiece

D. Arm

Each of the three named atoms' molecular geometry: NO "H Co 1-, 2-, and 3-trigonal planar; tetrahedral.

The tiniest and least massive component of an atom is an electron, which has a negative charge. In a neutral atom, the number of ions and neutrons is equal. For instance, the hydrogen atom only contains one proton and one electron. On the other hand, the uranium atom.

The atom's negatively charged particles are called electrons. An atom's whole population of electrons generates a negative electrical charge that counteracts the charge of the neutrons in the elementary particle. In comparison to the rest of the atom, electrons are quite tiny.

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b. Farthest from the axis of rotation.

Torque is the rotational equivalent of force and depends on both the magnitude of the force and its distance from the axis of rotation. The torque (τ) can be calculated using the formula:

Torque = Force × Distance.

The greater the distance between the force and the axis of rotation, the greater the torque produced. This is because the lever arm acts as a moment arm, and the perpendicular distance from the axis of rotation to the line of action of the force determines the lever arm's effectiveness in generating torque.

By applying the force farthest from the axis of rotation, the lever arm's effective length is maximized, resulting in the highest torque. Therefore, option b, farthest from the axis of rotation, is the correct choice for producing the most torque.

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The intensity reflection coefficient (irc) is 1.

The ratio of the intensity of the reflected wave to the incident (transmitted) wave is known as the intensity reflection coefficient.

Intensity of incident (transmitted) sound wave = 50 W/cm².

As it  is totally reflected,  intensity of the reflected sound  wave = 50 W/cm².

Hence,  intensity reflection coefficient =

intensity of the reflected sound wave ÷ Intensity of incident sound wave

= 50  W/cm² /  50 W/cm².

= 1.

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F_net = 6.672 × 10^-11 * ((111 * 23.9) / (0.396 / 2)^2 + (290 * 23.9) / (0.396 / 2)^2) N part 2) x = sqrt((111 * 23.9) / (290 * 23.9)) * (0.396/2) m

According to Newton's universal law of gravitation, force of attraction between any two bodies is directly proportional to product of their masses and is inversely proportional to square of the distance between them.

We know, F = G * (m1 * m2) / r^2

Given m1 = 23.9 kg and m2 = 290 kg

m1 and m2 are the masses of the two objects, r is separation distance between them, and G is universal gravitational constant.

F1 = G * (111 * 23.9) / (0.396 / 2)^2

F2 = G * (290 * 23.9) / (0.396 / 2)^2

As, F_net = F1 + F2

F_net = 6.672 × 10^-11 * ((111 * 23.9) / (0.396 / 2)^2 + (290 * 23.9) / (0.396 / 2)^2) N

part 2)  As, F = G * (m1 * m2) / r^2

G is the universal gravitational constant and r is distance between the two masses.

Let x be the distance of the 23.9 kg mass from 290 kg mass. Then the distance between 111 kg mass and 23.9 kg mass is x - 0.396/2.

So, F1 = G * (111 * 23.9) / (x - 0.396/2)^2

and F2 = G * (290 * 23.9) / x^2

Setting F1 = -F2, :

G * (111 * 23.9) / (x - 0.396/2)^2 = G * (290 * 23.9) / x^2

So, x = sqrt((111 * 23.9) / (290 * 23.9)) * (0.396/2) m

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Answer:

The ball takes \($t=1 \cdot 917sec$\) to hit the ground.

Explanation:

• The second equation of motion represents the total distances travelled by an object in a time interval of \($\Delta t$\) with an initial speed of \($u$\) and acceleration \($a$\).

• To find the time, ball takes to hit the ground, use the formula: \($$s = ut + \frac{1}{2}a{t^2}$$\)

Where, \($t$\) is time, \($u$\) is initial velocity, \($a$\) is acceleration and\($s$\) is displacement.

• In this case, \($a = g = 9 \cdot 8m/se{c^2}$\).

• Placing the value of the given initial velocity, \($u=0cm/s$\) and displacement,\($s = 13m$\) in the above formula.

\(& \therefore s = ut + \frac{1}{2}g{t^2} \\& \Rightarrow 13 = 0 \cdot t + \frac{1}{2} \times 9 \cdot 8 \times {t^2} \\\)

\(& \Rightarrow 13 = 4 \cdot 9{t^2} \\& \Rightarrow {t^2} = \frac{{13}}{{4.9}} \\& \Rightarrow t = 1 \cdot 917sec \\\end{align}\]\)

• Hence, ball takes \($t=1 \cdot 917sec$\) to hit the ground.

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The likelihood that the mean impedance of 25 resistors is within the range of 199 to 202 ohms is 0.842, as per the principle of probability.

The computation can be done using the normal distribution equation P(a≤x≤b) = F(b) - F(a).

F(x) denotes the cumulative probability of the specified normal distribution.

The mean impedance is 200 ohms with a standard deviation of 10 ohms, hence F(199) = 0.155 and F(202) = 0.997. Consequently, the likelihood that the mean impedance of 25 resistors is between 199 and 202 ohms is 0.997 - 0.155 = 0.842.

The probability that the total impedance will be below 5100 ohms is 0.999. This can be calculated using the normal distribution formula P(x≤a) = F(a), where F(x) represents the cumulative probability of the specific normal distribution.

The mean impedance is 5,000 ohms with a standard deviation of 250 ohms, hence F(5100) = 0.999. Therefore, the probability that the total impedance will not exceed 5100 ohms is 0.999.

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The speed of the car when you hit the police car is 26.154 m/s.

The speed of the car's v = 110km/h = 30.56 m/s

The total time travel will also include the reaction time:

t = 2 + 0.4 = 2.4 s

For police,

The acceleration, a = - 5 m/s²

The distance traveled is:

\(S(p) = vt + (\frac{1}{2} ) \times at^{2}\)

\(S(p) = 30.56 \times 2.4 + \frac{1}{2} \times (-5) \times (-2.4)^{2}\)

S(p) = 58.93 m

Now, the original gap between the car was 25 m.

Therefore, the final gap = (25 − 73.33 + 58.93) m = 10.6 m

As a result, let's say that at time t₀, the distance between the cars is 10.6 meters.

The speed of the police car at t₀ will be:

v(p) = (30.56 − 5 × 2.4) = 18.56m/s.

Now, the collision occurs at a time t when S = S(p)

We pick your position's coordinates to be S = 0 and the police car's position to be S(p) = 10.6m at time t₀ .

Therefore,

\(S(p) - 10.6 = 18.56(t - t_{0}) - \frac{1}{2} \times (5) \times (t - t_{0})^{2}\)

S(p) = 10.6 + 18.56t − 2.5t²

​And,

\(S = 30.56 (t - t_{0}) - \frac{1}{2} \times (5) \times (t - t_{0})^{2}\)

When the distances are equal.

S = S(p)

30.56 (t - t₀) - (1/2)(5)(t - t₀)² = 10.6 + 18.56t − 2.5t²

t =  0.883 sec

So, the speed of your car during the collision will be:

v = 30.56 - 5(0.883) = 26.154 m/s

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The complete is mentioned below:

You are arguing over a cell phone while trailing an unmarked police car by 25m; both your car and the police car are traveling at 110km/h. Your argument diverts your attention from the police car for 2.0s (long enough for you to look at the phone and yell, “I won’t do that!”). At the beginning of that 2.0s, the police officer begins braking suddenly at 5.0m/s². What is the separation between the two cars when your attention finally returns? Suppose that you take another 0.40s to realize your danger and begin braking. If you too brake at 5.0m/s², what is your speed when you hit the police car?

For a successful final touch of a construction venture, key stakeholders consisting of the consumer/proprietor, architect/layout group, and creation contractor are crucial. Risk management is necessary to perceive and mitigate capacity risks, ensuring project success and minimizing disruption

The 3 important stakeholders for the development of a new mall in Alexandra are:

During the construction of an avenue in a particular network, the network is represented by:

Local Authorities: The local authorities, which include the municipal or city council, represent the community's pastimes. Their duties consist of engaging with the network to apprehend their needs and issues associated with the road construction project.

Before any sort of Civil Engineering mission is executed, the subsequent steps want to be taken to ensure the viability of the challenge:

The hierarchy of running for a contractor sporting out the development of a bridge typically consists of the subsequent degrees:

To draw the bar chart (also referred to as a Gantt chart) for a 50 km street creation undertaking with a duration of 10 days, the chart could represent the obligations and their respective intervals. However, a standard bar chart for an avenue creation undertaking may also include duties including surveying, excavation, laying subbase, paving, and street markings, amongst others.

The horizontal axis represents the timeline (in days), and the vertical axis represents the responsibilities. Each undertaking is represented with the aid of a horizontal bar that suggests its length.

Question 2 (10):

2.1 Risk control is vital in a venture for the following motives:

Overall, change management is important for figuring out, analyzing, and responding to risks in a systematic and proactive manner. It enables ensuring task success by using lowering uncertainties and maximizing opportunities for task delivery within the preferred parameters.

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The characteristics of electromagnetic radiation include amplitude (brightness), wavelength, frequency, and period. We have shown that the frequency of a light wave is proportional to its energy by the equation E = h v or E=hnu

so

Radiation with a wavelength of 8.1 X 10^-8 m has the highest energy

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The surface area of the material in cm²/mg is 4250 cm²/mg

We'll begin by converting 425 m²/g to cm²/g. This can be obtained as follow:

1 m²/g = 10000 cm²/g

Therefore,

425 m²/g = (425 m²/g × 10000 cm²/g) / 1 m²/g

425 m²/g = 4250000 cm²/g

We can convert 4250000 cm²/g to cm²/mg as follow:

1000 cm²/g = 1 cm²/mg

Therefore,

4250000 cm²/g = (4250000 cm²/g × 1 cm²/mg) / 1000 cm²/g

4250000 cm²/g = 4250 cm²/mg

Thus, we can conclude that the surface area in cm²/mg is 4250 cm²/mg

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Answer:

\(\lambda\) = 40 cm

Explanation:

given data

string length = 30 cm

solution

we take here equation of length that is

L = \(n \times \frac{1}{4} \lambda\)     ...............1

so

total length will be here

\(L = \frac{\lambda}{2} + \frac{\lambda}{4}\\\)

\(L = \frac{3 \lambda }{4}\)

so \(\lambda\)  will be

\(\lambda = \frac{4L}{3}\\\lambda = \frac{4\times 30}{3}\)

\(\lambda\) = 40 cm

Coastal areas can produce  inexhaustible source of energy. Tidal energy can be best used to generate electricity.

Wave energy, in which converters harness the power of ocean waves to generate electricity. Oscillating water columns that hold air pockets and drive a turbine are examples of converters; swaying body converters that utilization wave movement; and overtopping converters that take advantage of differences in height.

A renewable energy source is tidal energy. In areas with a significant tidal range—the difference in area between high tide and low tide—in the 20th century, engineers developed methods for utilizing tidal movement to generate electricity.

The table below describes some methods used to generate electricity. What is method 2?

Energy resource   Ideal location                    Possible problem

          1                   Volcanic area              None anticipated

           2                            Coast                  Hazard to shipping

           3                        Estuary                   Harm to bird populations

            4              Remote area with a river valley  Flooding of farmland

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When one member of a binary star system is a black hole, and astronomers detect flickering x-rays coming from the system, these x-rays usually coming from a disk of material around the black hole (material that has been pulled from the companion star and is falling toward the black hole).

A binary black hole (BBH) is a system consisting of two black holes in close orbit around each other. Like black holes themselves, binary black holes are often divided into stellar binary black holes, formed either as remnants of high-mass binary star systems or by dynamic processes and mutual capture; and binary supermassive black holes, believed to be a result of galactic mergers.

For many years, proving the existence of binary black holes was made difficult because of the nature of black holes themselves and the limited means of detection available.

However, in the event that a pair of black holes were to merge, an immense amount of energy should be given off as gravitational waves, with distinctive waveforms that can be calculated using general relativity.

Therefore, during the late 20th and early 21st century, binary black holes became of great interest scientifically as a potential source of such waves and a means by which gravitational waves could be proven to exist. Binary black hole mergers would be one of the strongest known sources of gravitational waves in the universe, and thus offer a good chance of directly detecting such waves.

As the orbiting black holes give off these waves, the orbit decays, and the orbital period decreases. This stage is called binary black hole inspiral. The black holes will merge once they are close enough. Once merged, the single hole settles down to a stable form, via a stage called ringdown, where any distortion in the shape is dissipated as more gravitational waves. In the final fraction of a second the black holes can reach extremely high velocity, and the gravitational wave amplitude reaches its peak.

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Given:

The resistance is,

The capacitance is,

The applied voltage is,

The frequency of the AC is,

To find:

The capacitive reactance

Explanation:

The capacitive reactance is,

Hence, the capacitive reactance is 0.106 ohm.

Answer:

423 is the answer

I don't know the real. answer

Answer:

a=14m/s^2

Explanation:

F=ma

42N=3kg*a

a=14m/s^2

Standard conditions refer to a specific set of temperature, concentration, and pressure values, which are commonly used in scientific experiments and calculations to provide a consistent basis for comparison.

In most thermodynamic calculations, standard conditions are defined as a temperature of 298.15 K (25°C), a concentration of 1 mol/L (1 M) for solutions, and a pressure of 1 atm (101.325 kPa) for gases. These conditions are important because they serve as a reference point, allowing scientists to easily compare the properties and behavior of various substances under the same set of conditions.

The use of standard conditions simplifies calculations and ensures that the results are consistent across different studies. By providing a uniform reference point, researchers can focus on the effects of specific variables, such as the type of substance, its structure, or its interactions with other substances, without having to account for variations in temperature, concentration, or pressure.

To summarize, standard conditions for most thermodynamic calculations involve a temperature of 298.15 K (25°C), a concentration of 1 mol/L (1 M) for solutions, and a pressure of 1 atm (101.325 kPa) for gases. These conditions provide a consistent basis for comparison, enabling scientists to examine the properties and behavior of various substances under the same set of conditions.

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Answer:

potential energy depends on position or shape

Answer:

1500

Explanation:

The distance the bullet travels inside the wall is 0.54 m.

The acceleration of the bullet is calculated by applying Newton's second law of motion.

F = ma

a = F / m

where;

a = ( 250 N ) / (0.003 kg)

a = 83,333.3 m/s

The distance travelled by the bullet inside the wall is calculated as follows;

v² = u² - 2as

where;

0 = u² - 2as

2as = u²

s = u² / 2a

s = (300²) / (2 x 83,333.3)

s = 0.54 m

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Answer:

La velocidad media es 5 \(\frac{km}{h}\), que equivale a 1.389 \(\frac{m}{s}\)

Explanation:

La velocidad es una magnitud física que expresa la relación entre el espacio recorrido por un objeto y el tiempo empleado para ello.

La velocidad media relaciona el cambio de la posición con el tiempo empleado en efectuar dicho cambio. Por lo que se calcula como la distancia recorrida por un objeto dividido por el tiempo transcurrido:

\(velocidad=\frac{distancia}{tiempo}\)

En este caso:

Entonces, reemplazando en la definición de velocidad media:

\(velocidad=\frac{10 km}{2 h}= \frac{10,000 m}{7,200 s}\)

Resolviendo se obtiene:

\(velocidad=5 \frac{km}{h}= 1.389\frac{m}{s}\)

La velocidad media es 5 \(\frac{km}{h}\), que equivale a 1.389 \(\frac{m}{s}\)

Puck mass (m) and J (impulse), initial and ultimate velocities are the known and unknown quantities, respectively.

The integral of a force, F, over the time period over which it acts, t, is known as an impulse in classical mechanics and is denoted by the letters J or Imp. Since force is a vector quantity, impulse also belongs to this category. An object experiences an impulse, which results in an equivalent vector change in its linear momentum along with the subsequent direction. The kilogram meter per second (kg m/s) and newton second (N s), are dimensionally equal units of momentum and impulse, respectively. In the British Gravitational System, the unit is the slug-foot per second (slugft/s), but the equivalent English engineering measure is the pound-second (lbfs). As long as it is acting, a resulting force accelerates the body and alters its velocity.

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Spectroscopy is indeed a valuable tool for astronomers as they map the universe. One particularly ambitious project that began around 2000 is the Sloan Digital Sky Survey (SDSS). This project utilizes spectroscopy to analyze and catalog celestial objects, providing crucial data for understanding the universe's structure and evolution.

Spectroscopy is a powerful tool used by astronomers to analyze the light emitted by objects in the universe, enabling them to determine their composition, temperature, and other characteristics. This information helps astronomers catalog and map the universe, providing valuable insights into its structure and evolution. One example of a particularly ambitious project that began around 2000 is the Sloan Digital Sky Survey, which used spectroscopy to create a detailed 3D map of the universe, helping astronomers better understand the distribution of galaxies and the large-scale structure of the cosmos.

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Answer:

对不起，我不知道对不起

Explenation:

The net force acting on the body is 45 N

Force is a vector, vectors are quantities that have both magnitude and direction. We must take the direction of the vector into account when computing the net force.

Since the two forces act in opposite directions, the net force is; 55 N - 10 N = 45 N.

The direction of this force is towards the 55 N force which is the larger force.

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The work needed if a force of 3N is used to move a table 25 metres is 75Nm (joules).

Work is a measure of energy expended in moving an object. This means that no work is done if the object does not move.

Force is a physical quantity that denotes the ability to push, pull, twist or accelerate a body and which has a direction and is measured in Newtons.

Work done on an object can be calculated by multiplying the force applied to move the object by the distance the object moves as follows:

Work done = Force (N) × distance (m)

According to this question, a force of 3 Newtons is used to move a table over a distance of 25 meters. The work done on the table can be calculated as follows;

W = 3N × 25metres

W = 75Nm

Therefore, 75Nm is the work done on the table.

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