What is a negatively charged subatomic particle called?

Answers

Answer 1

Negatively charged subatomic particles are called atomic electrons.

Atoms are known to be made up of three particles, often called subatomic particles. Three subatomic particles are known, namely, proton, neutron and electron. Protons and electrons are two subatomic particles each carrying an electrical charge of one type or another.

The electrons in atoms are negatively charged subatomic particles.

Negatively charged subatomic particles called electrons can be free or attached to atoms (unbound). One of the three main types of particles in an atom is the electron bound to it; the other two are protons and neutrons. The nucleus us made of the above mentioned subatomic particles only.

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Answer 2

Answer:

I hope this helps.

Explanation:

What Is A Negatively Charged Subatomic Particle Called?

Related Questions

Would a molecule of O2 bind to one of the hemes of a hemoglobin molecule in the T state, which has no molecules of O2 bound

Answers

A molecule of O2 will not bind in T state due to low affinity

When T state is formed, it has a low affinity for oxygen. The molecule of O2 would bind to one of the hemes of a hemoglobin molecule in the R state rather than the T state. In the absence of oxygen, hemoglobin molecules tend to aggregate, making it easier for oxygen to bind when it becomes available. In the T state, the heme group is slightly distorted, causing the Fe2+ ion to lie slightly off the plane of the heme ring, and the distal histidine blocks the heme's coordination site, creating a smaller pocket that is unsuitable for oxygen binding.

This is because, in the T state, the Fe2+ ion is coordinated to 5 atoms: 4 pyrrole nitrogens and one imidazole nitrogen from a histidine residue. In the R state, however, oxygen binding causes a conformational change that pulls the histidine residue away from the heme iron, opening up a larger pocket that is more suitable for oxygen binding.

Hemoglobin is a protein that is responsible for transporting oxygen throughout the body in vertebrates. It consists of four subunits, each of which has a heme group that binds to oxygen. Hemoglobin has two different states: the relaxed state, known as the R state, and the tense state, known as the T state. In the R state, hemoglobin has a high affinity for oxygen, while in the T state, it has a low affinity for oxygen.The T state is formed when no oxygen is bound to the heme groups of hemoglobin.

When oxygen is present, it binds to the heme group, causing a conformational change in the protein that shifts it from the T state to the R state. In the R state, hemoglobin has a higher affinity for oxygen, making it easier for oxygen to bind to the protein and be transported throughout the body.

The molecule of O2 would not bind to one of the hemes of a hemoglobin molecule in the T state because it has a low affinity for oxygen in this state. Instead, the molecule of O2 would bind to one of the hemes of a hemoglobin molecule in the R state, which has a high affinity for oxygen. The T state is created when no oxygen is bound to the heme groups of hemoglobin, making it more difficult for oxygen to bind to the protein. In the R state, however, oxygen binding causes a conformational change that opens up a larger pocket that is more suitable for oxygen binding.

a molecule of O2 would not bind to one of the hemes of a hemoglobin molecule in the T state, which has no molecules of O2 bound. This is because hemoglobin has a low affinity for oxygen in the T state, making it more difficult for oxygen to bind to the protein.

Instead, the molecule of O2 would bind to one of the hemes of a hemoglobin molecule in the R state, which has a high affinity for oxygen. In the R state, oxygen binding causes a conformational change that opens up a larger pocket that is more suitable for oxygen binding.

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Substance Density (grams/cm3)Chloroform - 1.5Ebony wood - 1.2Mahogany wood - 0.85Oil - 0.9Water - 1.024.A block of ebony wood is placed in the container with the water, chloroform, and oil. On which layer does the ebony wood float?Select one:a. Chloroform.b. Oil.c. Water.d. None; it will sink.

Answers

Determining if an object will float or sink is based on the density of the object and also the density of the solution, the lower the density, more likely the object is to float, and if the density is higher, therefore the object is heavier and it will sink. In our question we have ebony wood with a density of 1.2, the only possible layer that this material can float is on Chloroform, that has a higher density, therefore the answer is letter A

A shard of crockery found in an archaeological site is carbon-dated and registers 8.55 disintegrations/min g of carbon. Crockery made today has a C-14 decay rate of 15.3 disintegrations/min.g of carbon. How old is the shard? C-14 has a half-life of 5715 years. 4.81×10^ 3yr 2.10×10 ^3yr 1.21×10−4yr 3.20×10 ^3 yr

Answers

The correct option is 3.20 × 10³ yr.The formula for calculating the age of a sample using radiocarbon dating is:A = A0 e^(kt), where:

A = the final amount of the sampleA0

= the initial amount of the samplee

= the mathematical constant approximately equal to 2.71828k

= the proportion of 14C relative to 12C, expressed as a rate constant (which is why this equation is referred to as the "rate equation")t = time (in years)Using the given information, we can calculate the age of the shard as follows:

A0/A = \(2^_(t/T)\), where:

A0/A = the fraction of original C-14 remainingT

= the half-life of C-14t

= the age of the sampleUsing the half-life of C-14 (T = 5715 years), we can calculate the fraction of original C-14 remaining in the shard as follows:

A0/A = (8.55 disintegrations/min.g of carbon) / (15.3 disintegrations/min.g of carbon)

= 0.5593Then we can use this fraction to calculate the age of the shard as follows

:0.5593 =\(2^_(-t/5715)\)

Taking the natural logarithm of both sides:ln(0.5593)

= \(ln(2^{(-t/5715)})\)

Using the logarithmic identity ln(a^b) = b ln(a):

ln(0.5593) = (-t/5715) ln(2)Solving for t:t

= (-ln(0.5593)) / (ln(2) / 5715)

≈ 3212 years

Therefore, the shard is approximately 3212 years old. Rounding to two significant figures gives an answer of 3.2 × 10³ yr. Hence, the correct option is 3.20 × 10³ yr.

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Calculate the density of a 38.6 g cube of gold with a volume of 2 cm³?

Answers

Answer:

Density, \(d=19.3\ g/cm^3\)

Explanation:

Given that,

Mass of gold is 38.6 g

Volume, V = 2 cm³

We need to find the density of gold cube. The density of an object is defined as how much mass it has divided by its volume. So,

\(d=\dfrac{38.6\ g}{2\ cm^3}\\\\d=19.3\ g/cm^3\)

So, the density of the cube of gold is \(19.3\ g/cm^3\).

What did scientists believe about caloric? State two examples of the scientific phenomena that the caloric theory explained

Answers

Answer:

that it was difficult, bc they didnt accept the particle model of matter, air molecule get warmer and explains charles law (i think)

o
Plants rely heavily on _______
in the nitrogen cycle to incorporate nitrogen into organic come pounds
1 oxygen
2 viruses
3 bacteria
4 fungi

Answers

Answer:

3. Bacteria

Explanation:

If you don't trust me, search it up!

Elements A,B,C and D have atomic numbers 11,18,1 and 17 respectively. Give the chemical formulae of the compound formed between:
a) A and D
b) B and C

Answers

Answer: a ) NaCl

b) No compound.

Explanation:

Atomic number of A is 11 , thus it is sodium. It has electronic configuration of 2,8,1 and thus has 1 valence electron and can form \(Na^+\).

Atomic number of B is 18 , thus it is argon. It has electronic configuration of 2,8,8 and thus it is an inert gas.

Atomic number of C is 1 , thus it is hydrogen. It has electronic configuration of 1. It can only share electrons.

Atomic number of D is 17 , thus it is chlorine. It has electronic configuration of 2,8,7 and thus has 7 valence electron and can form \(Cl^-\).

a) A and D :

Here Sodium is having an oxidation state of +1 called as \(Na^+\) cation and anion is \(Cl^-\). Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral \(NaCl\)

b) B and C

As B is an inert gas , it wont combine with C.

A solution was made using NaOH, the pH of the solution was found to be 11.452. What is the concentration of the hydroxide ion, OH^- in this solution

Answers

Answer:

i think it is 0.002831392

Explanation:

pOH = 14 - 11.452 = 2.548

pOH = -log(OH)

2.548 = -log(OH)

10^(-2548) = 0.002831392

20
Syrus has always done well in school and enjoys science, but every year when it is time to choose classes he struggles. He fears he will pick the
wrong classes and miss out on something amazing! How might going to college and pursuing a science major help Syrus?
O A.
He will have a dedicated student buddy to help him map his courses.
O B.
He won't have to pick his classes as they will be laid out for him.
O C.
He will get help from his parents in planning his four-year college curriculum before he starts.
O D.
He will have a meeting with a consultant from the National Science Board to help him choose his course plan.
Reset
Next

Answers

Syrus has always done well in school and enjoys science and the correct option is (B) i.e. He won't have to pick his classes as they will be laid out for him.

Pursuing a science major in college would help Syrus because he would not have to pick his classes as they will be laid out for him. When Syrus declares a science major, he will be given a specific curriculum to follow, which will ensure that he takes all the necessary classes to achieve his degree. This takes the pressure off of Syrus to choose his own classes and ensures that he is on the right track towards his career goals. While there may be some flexibility in choosing elective courses within the science major, the core courses will be predetermined.

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17 OT-
2021
Subject Chemistry Date
7 Evaluate and discuss how do you think
the Number of the Valence electrons
relates to con elements Chemical properties
show many Valence election are found
in the following Atoms.​

Answers

please urgent please helpjlsldşdşödde
17 OT-2021Subject Chemistry Date7 Evaluate and discuss how do you thinkthe Number of the Valence electronsrelates

Did Christopher (Chris Gardner's son) face challenges during this time? Identify some of those challenges. ​

Answers

Yes, Christopher Gardner's son faced challenges during this time. One of the challenges he faced was homelessness and poverty, as he and his father struggled to make ends meet while living on the streets.

Without a secure place to reside, a person is said to be homeless. This condition can be brought on by a number of things, including poverty, unemployment, mental illness, and addiction. Increased risk of sickness, exposure to violence, and lack of access to basic essentials like food, water, and shelter are just a few of the detrimental effects of homelessness on a person's health and wellbeing. It takes a mix of governmental changes and supportive services to help people rebuild their lives to combat homelessness, a complicated and enduring problem that impacts people and communities all over the world.

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the decomposition of hydrogen peroxide is catalyzed by iodide ion what happen to catalyst concentration

Answers

The decomposition of hydrogen peroxide into water and oxygen is a slow process, but it can be catalyzed by iodide ion. The iodide ion acts as a catalyst by lowering the activation energy required for the reaction to occur.

During the reaction, the iodide ion is oxidized to form iodine, which then reacts with hydrogen peroxide to form water and oxygen. The iodine can then react with more hydrogen peroxide to continue the reaction.

The concentration of the catalyst, iodide ion, affects the rate of the reaction. An increase in the concentration of the iodide ion will increase the rate of the reaction, as there will be more catalyst available to facilitate the reaction. Conversely, a decrease in the concentration of the iodide ion will slow down the rate of the reaction.

However, once the reaction has finished, the concentration of the catalyst will remain the same. This is because the catalyst is not consumed in the reaction and can be used again in subsequent reactions. Therefore, the concentration of the catalyst will remain constant as long as there is enough iodide ion present to catalyze the reaction.

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Which fossil could help scientists know more about the kind of food eaten by an animal that lived millions of years ago?
A) teeth
B) skull
C) backbone
D) leg bones

Answers

Answer:

A. teeth

Explanation:

It contains a protien called collagen, which absorbs chemical elements from the food that an individual eats, so scientists are able to obtain information about animals diet by studying the chemical elements found in fossilised teeth.

Answer:

Teeth

Explanation:

They can see the shape of the teeth and try to figure out what they ate

All of the following are functions of the citric acid cycle except a. production of ATP. b. production of NADH. c. production of FADH2. d. release of carbon dioxide. e. adding electrons and protons to oxygen, forming water.

Answers

All of the following are functions of the citric acid cycle except the addition of electrons and protons to oxygen, forming water. So, the right choice for answer is option (e).

The citric acid cycle (also known as the Krebs cycle) is the second stage of aerobic cellular respiration. This catabolic pathway occurs in the mitochondrial matrix. The produced products during the citric acid cycle are the following:

CO₂ For every molecule of acetyl-CoA that enters the cycle, two molecules of carbon dioxide are produced.ATP - In fact, a GTP is produced with each cycle. GTP is energetically equivalent to ATP, the only difference being that GTP is based on guanine while ATP is based on adenine.NADH - For every molecule of acetyl-CoA that enters the cycle, three molecules of NAD⁺ are reduced to three NADH.

The citric acid cycle, a series of reactions that take up acetyl-CoA and produce carbon dioxide, NADH, FADH₂ and ATP or GTP. Therefore, all options shown are functions of the citric acid cycle, except for option (e) which adds electrons and protons to oxygen, forming water.

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The higher equivalent burst rate of the neuron in the lower trace was ___________ Hz. (round up to the nearest one thousandth) The two features of the encoded information in the activity of the neuron in the lower trace are ________ with a mean spike rate of ________ Hz; and interburst of both short and long durations. The firing rate of the neuron in the upper trace is________ Hz. Source: http://jn.physiol ogy.org/cgi/content/fulV98/4/1898 FIG. 4. Spontaneous electrical discharge of 2 spiral ganglion cells, 1 from an older P36 (102 dpc) kitten (top trace: sg9 1) and 1 from a P5 (71 dpc) neonatal kitten (bottom trace sg15 14). Twenty-five seconds of data are shown for both animals. Top trace reflects steady near stochastic discharge of a mature SGC. Discharge rate was 88 spikes/s, CVi 0.89, and burst index (B)-0.9. Bottom trace shows prominent bursting periods of the P5 SGC. This cell discharged slowly on average (mean spike rate 1.8 spikes/s) with repeated periods of intense activity separated by long silent periods. Interval coefficient of variation (CV) 4.1, B 8.8. This recording segment showed an equivalent burst rate approaching 10 bursts/min, but over the entire 6-min period, burst rate was much lower (4.1 bursts/min) because there were several very long periods with no activity (data not shown).

Answers

The firing rate of the neuron in the upper trace is 88 Hz.

From the lower trace, we can conclude that the neuron exhibits prominent bursting periods.

The firing rate of the neuron in the lower trace is found to be 1.8 spikes/s.

The interval coefficient of variation (CV) is 4.1.

The burst index is 8.8.

To calculate the equivalent burst rate of the neuron in the lower trace, we use the formula: Equivalent burst rate = Burst Index × (Mean Burst Frequency).

Plugging in the values, the equivalent burst rate is calculated as: Equivalent burst rate = 8.8 × (1.8 / 4.1) = 150 Hz.

Therefore, the higher equivalent burst rate of the neuron in the lower trace is 150 Hz.

The two features of the encoded information in the activity of the neuron in the lower trace are bursts with a mean spike rate of 1.8 Hz and interburst of both short and long durations.

The firing rate of the neuron in the upper trace is 88 Hz.

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Give reasons why an element can be broken down...pls explain widely​

Answers

Elements cannot be broken down into another substance.

For the reaction

if 5. 0 mol of CO2 are produced, how many moles of O2 were reacted?

a. None of these

b. 3. 3 mol

c. 12. 5 mol

d. 7. 5 mol

e. 6. 2 mol

Answers

If 5.0 mol of the CO₂ are produced, the number of the moles of the O₂ were reacted is 10 mol. The correct option is a. none of these.

The chemical equation is as :

CH₄ + 2O₂ → CO₂ + 2H₂O

The number of the moles of the CO₂ = 5 mol

The number of the moles of the CO₂ = mas / molar mass

The molar mass of the CO₂ = 44 g/mol

The 2 moles of the O₂ produced by the 1 mole of the CO₂

The number of the moles of the O₂ = 2 × 5 mol

The number of the moles of the O₂ = 10 mol.

The number of the moles of the O₂ required to produced 5 mol of the CO₂ is the 10 mol of the O₂. The correct option is a.

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Lactose (milk sugar) is a carbohydrate that is formed by combining galactose and glucose. Which term best describes this molecule? monosaccharide disaccharide monomer starch

Answers

Explanation:

lactose is disaccharide

because it contains 1 monosaccharide galactose +

1 monosaccharide glucose

The correct answer to the question is: disaccharide

Monosaccharides are simple sugar which can not be hydrolysed into simpler or smaller molecules.

Disaccharides are sugars produced by the condensation of two monosaccharides with the elimination of a water molecule.

monosaccharide + monosaccharide <=> Disaccharide + water

A Monomer is a small molecule which can combine with other similar molecules to form a large molecule called polymer. Thus, a monomer of starch is simply a small molecule that combines together to form a polysaccharide called starch. The monomer of starch is glucose.

Glucose and galactose combined to form lactose i.e

Glucose + Galactose => Lactose

The above is simply a demonstration of how disaccharides are produced.

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a patient with a core body temperature of 35° on the celsius scale has a core body temperature of ____ on the fahrenheit scale.

Answers

The answer will be 95 degrees

In your own words, describe the process of convection.

Answers

Answer:

the movement caused within a fluid by the tendency of hotter and therefore less dense material to rise, and colder, denser material to sink under the influence of gravity, which consequently results in transfer of heat

Explanation:

<3

Answer:

Convection when heat travels through metal or appliances.

Explanation:

a student takes an ir spectrum of an unknown compound. the ir spectrum shows significant stretches at 3453 cm-1 (m, br), 3322 cm-1 (m, br), 3111 cm-1 (m, sh), 1512 cm-1 (s, sh), and 1260 cm-1 (s, sh). which possible compound is it? key: s

Answers

The possible compound of the student's unknown IR spectrum is 2-Butanol.IR spectrum is a technique that is used to detect the functional group present in the compound.

The given unknown IR spectrum shows the presence of significant stretches at 3453 cm-1 (m, br), 3322 cm-1 (m, br), 3111 cm-1 (m, sh), 1512 cm-1 (s, sh), and 1260 cm-1 (s, sh). The above-mentioned significant stretches are associated with the following functional groups:3453 cm-1 (m, br) - corresponds to the O-H stretch of a carboxylic acid, phenol, or alcohol.3322 cm-1 (m, br) - corresponds to the O-H stretch of a carboxylic acid, phenol, or alcohol.3111 cm-1 (m, sh) - corresponds to the C-H stretch of a terminal alkyne or a primary amine.1512 cm-1 (s, sh) - corresponds to the C=C stretch of an aromatic ring.1260 cm-1 (s, sh) - corresponds to the C-O stretch of an ether or ester.Using the above explanation, the possible compound of the student's unknown IR spectrum is 2-Butanol.

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Time value (lo2, cfa2) what is the time value of a call option? of a put option? what happens to the time value of a call option as the maturity increases? what about a put option?

Answers

The time value of an option is the premium that the buyer of the option pays for the possibility of the underlying asset moving in a favorable direction before the option expires. The time value of a call option is the premium paid for the right to buy the underlying asset at the strike price before the option expires. The time value of a put option is the premium paid for the right to sell the underlying asset at the strike price before the option expires.

As the maturity of a call option increases, the time value typically increases as well. This is because the longer the option has until expiration, the more time there is for the underlying asset to move in a favorable direction and for the buyer of the option to realize a profit.

On the other hand, as the maturity of a put option increases, the time value typically decreases. This is because the longer the option has until expiration, the more time there is for the underlying asset to move in an unfavorable direction and for the buyer of the option to realize a loss.

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The activation energy Ea of a reaction is Ea = 43.5Kj.mol. Estimate the variation in the rate k of the reaction when the temperature is raised from 300K to 310K.(R = 8.314 J.K.mol)

Answers

Answer

The variation in the rate k (k1/k2) is 0.5707 s^-1

Step-by-step explanation:

Given the following parameters

Activation energy = 43.5Kj.mol

T1 = 300K

T2 = 310K

R = 8.314 J.Kmol

\(K\text{ =A}e^{-\frac{Ea}{RT}}^{}^{}\)\(\begin{gathered} \text{where K = rate constant},\text{ Ea = Activation energy, R= gas constant and T = temperature} \\ \ln (k)\text{ = }\ln A\text{ - }\frac{Ea}{RT} \\ \text{ A is a constant} \\ \text{ if the reaction occurs at two temperature T1 and T2} \\ \ln k1\text{ = }\ln A\text{ - }\frac{Ea}{RT1}--------\text{ equation 1} \\ \ln k2\text{ = }\ln A\text{ - }\frac{Ea}{RT2}\text{ --------- EQUATION 2} \\ \text{ substracting equation 1 from 2},\text{ we have} \\ \ln (\frac{k1}{k2})\text{ = }-\frac{Ea}{RT1}\text{ + }\frac{Ea}{RT2} \\ \ln (\frac{k1}{k2})\text{ = }\frac{Ea}{R}(\frac{1}{T2}\text{ - }\frac{1}{T1}) \\ \\ \ln (\frac{k1}{k2})\text{ = }\frac{43500}{8.314}(\frac{1}{310}\text{ - }\frac{1}{300}) \\ \ln (\frac{k1}{k2})\text{ = 5232.139 }(0.00322\text{ - 0.003333)} \\ \ln (\frac{k1}{k2})\text{ = 5232.139 (}-\text{ 0.0001071)} \\ \ln (\frac{k1}{k2})\text{ = -0.560851} \\ \text{Take the exponential of both sides} \\ \frac{k1}{k2}\text{ = }e^{-0.560851} \\ \frac{k1}{k2\text{ }}=0.5707s^{-1} \end{gathered}\)

What is the name of Se2Cl7?

What is the name of Se2Cl7?

Answers

Answer:

diselenium heptachloride

Explanation:

Se2Cl7

Se = selenium

Cl = chlorine

Don't forget the "-ide"

Diselenium heptachloride

What is the name of Se2Cl7?

A patient’s blood sample is 8.5mL, and 3 drops of a chemical are added to test the solution. Each drop is 0.05mL. What is the final volume of the solution

Answers

Answer:

4tbs

Explanation:

A 75-lb dog must be dewormed. If the daily dose of the dewormer is 1 tsp/25 lb of body weight for 3 days, approximately how much should be given each day?

1 tbs = 3 tsp

answer: 1 tbs

Which of the following statements about the best Lewis structure of CIF3 is True? 1) The central atom of Cl has an octet. II) The formal charges on all atoms are zeros. III) There are totally 7 lone pairs of electrons in the molecule, a) both 1 and 11 b) I only c) only 11 d) both II and III e) all are true

Answers

The central atom of Cl has an octet is not true because the Lewis structure does not permit. The formal charges on all atoms are zeros is true. There are totally 7 lone pairs of electrons in the molecule is true. Therefore, the correct answer for this question is d) both II and III.


I) The central atom of Cl has an octet.
This statement is not true. In the Lewis structure of ClF3, chlorine (Cl) is the central atom. It is surrounded by three fluorine (F) atoms and has two lone pairs of electrons. This means that the central atom of Cl has 10 electrons around it (3 single bonds with F and 2 lone pairs), which is known as an expanded octet.


II) The formal charges on all atoms are zeros.
This statement is true. In the Lewis structure of ClF3, the formal charge of the central chlorine atom is zero because it shares one electron with each of the three fluorine atoms and retains four of its original seven electrons. Each fluorine atom also has a formal charge of zero because it shares one electron with chlorine and retains six of its original seven electrons. Therefore, all atoms have a formal charge of zero.


III) There are totally 7 lone pairs of electrons in the molecule.
This statement is true. In ClF3, the central chlorine atom has 2 lone pairs of electrons, and each of the three fluorine atoms has 3 lone pairs of electrons. In total, there are 2 + 3(3) = 2 + 9 = 11 lone pairs of electrons in the molecule.

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What is the oxidation number of the monatomic ions of the following elements?
a. Cs
b. Ba
c. As
d. Sr
e. Rb

Answers

The oxidation number of the monatomic ions of the following elements are a. Cs (cesium): +1, b. Ba (barium): +2, c. As (arsenic): -3, d. Sr (strontium): +2, e. Rb (rubidium): +1.

The oxidation number of the monatomic ions of cesium, barium, arsenic, strontium, and rubidium are +1, +2, -3, +2, and +1, respectively. Below is an explanation of how the oxidation number of each element was obtained.

Oxidation state refers to the oxidation number of an atom, which indicates its state of oxidation or reduction in a chemical reaction. The oxidation state can be determined by adding up the valence electrons of an atom in its neutral state and subtracting the valence electrons that it has either gained or lost in a compound.Cesium has one valence electron, which it gives up to form an ion with a charge of +1. Therefore, the oxidation number of Cs is +1.Barium has two valence electrons, which it gives up to form an ion with a charge of +2. Therefore, the oxidation number of Ba is +2.

Arsenic has five valence electrons, but it prefers to gain three electrons to complete its outer shell of eight electrons, resulting in a charge of -3. Therefore, the oxidation number of As is -3.Strontium has two valence electrons, which it gives up to form an ion with a charge of +2. Therefore, the oxidation number of Sr is +2.Rubidium has one valence electron, which it gives up to form an ion with a charge of +1. Therefore, the oxidation number of Rb is +1. So, the oxidation number of the monatomic ions of cesium, barium, arsenic, strontium, and rubidium are +1, +2, -3, +2, and +1, respectively. Below is an explanation of how the oxidation number of each element was obtained.

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Please solve number 5!! I’ll mark most brainliest!

Please solve number 5!! Ill mark most brainliest!

Answers

D. 5.25 ml
Jejsjsnxnnsnsbdbbdbdbd

Answer: 5.248

Explanation: 0.53/0.1010 = 5.24752475248, and round to the thousandths.

//_20 points_//
Select the correct answer. What is the Ksp expression for this dissolving reaction? Na3PO4(s) 3Na+(aq) + PO4-3(aq)
A. Ksp= [Na+] [PO4]3
B. Ksp= [Na+]3 [PO4]3
C. Ksp= [Na+] [PO-4]3
D. Ksp= [Na+]3 [PO4-3]
E. Ksp= [Na+3] [PO4]3

Answers

Answer:

Letter D...................

In the previous step, you determined
0.25 mol HCI reacts. The molar mass
of Mg is 24.31 g/mol.
What mass of Mg is required?


PLEASE HELP ASAP

In the previous step, you determined0.25 mol HCI reacts. The molar massof Mg is 24.31 g/mol.What mass

Answers

Approximately 3.04 grams of magnesium would be required to react with 0.25 moles of hydrochloric acid.

To determine the mass of Mg required, we need to use the balanced chemical equation for the reaction between hydrochloric acid (HCl) and magnesium (Mg):

2HCl + Mg → MgCl2 + H2

From the balanced equation, we can see that 2 moles of HCl react with 1 mole of Mg. Therefore, if 0.25 mol of HCl reacts, we would need half of that amount, which is 0.125 mol of Mg.

To calculate the mass of Mg required, we need to multiply the number of moles of Mg by its molar mass. The molar mass of Mg is given as 24.31 g/mol. Therefore, the mass of Mg required can be calculated as follows:

Mass of Mg = Number of moles of Mg × Molar mass of Mg

Mass of Mg = 0.125 mol × 24.31 g/mol

Mass of Mg = 3.04 g

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