What is a hypothesis?
O proof and evidence of a scientific fact
O a question about nature and how it works
a series of steps to carry out an experiment
O a possible explanation of or answer to a scientific question

4.2228 g of solid potassium sulfide should be added to make an aqueous solution of 0.180 M potassium sulfide for an experiment in lab, using a 300 ml volumetric flask.

The given molarity of the aqueous solution of potassium sulfide is 0.180 M and the volume of the solution is 300 mL. We are required to find out the amount of solid potassium sulfide required to make the solution.

The formula to calculate the number of moles is: Number of moles = Molarity x Volume (in liters) 1. Convert the volume into liters.300 mL = 0.3 L2. Substitute the given values in the above formula.Number of moles = 0.180 M x 0.3 LNumber of moles = 0.054 mol3. The molecular formula of potassium sulfide is K2S. It means there are two moles of K for one mole of K2S. Hence, we can calculate the moles of K.Number of moles of K = 2 x 0.054

Number of moles of K = 0.108 mol4. The molar mass of K is 39.1 g/mol. Hence, we can calculate the mass of K required to make 0.108 mol.Number of grams of K = Number of moles x Molar massNumber of grams of K = 0.108 mol x 39.1 g/mol

Number of grams of K = 4.2228 g. Hence, 4.2228 g of solid potassium sulfide should be added to make an aqueous solution of 0.180 M potassium sulfide for an experiment in lab, using a 300 ml volumetric flask.

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Answer:

Explanation:

Position it is the energy of an object due to virtue of ur position

Answer:

I think it's the state of the surrounding water because if the water holds impurities it will float and if it doesn't have impurities it will sink

A submarine is able to raise and lower itself underwater. A rock sinks when it is dropped in a pool because it is denser than water. A piece of wood floats in the pool because it is less dense than water. If we want to change in sink or float of submarine then we must  change the state of surrounding water. Thus, option c is correct.

According to Archimedes's principle the upward buyout force that is exerted on a body immersed in a fluid whether fully or partially, is equal or less than the fluid that the body displaces.

Mathematically

Buyout force = Fb=-pgv

Where

p= density of fluid

g= acceleration due to gravity

v = Volume of fluid

So, if a object is floating in the water then buyout forces must be equal to their weight, and for that weight of water that is displaced by object must be greater than or equal to the weight of object. So object is floating.

Therefore, a submarine is able to raise and lower itself underwater. A rock sinks when it is dropped in a pool because it is denser than water. A piece of wood floats in the pool because it is less dense than water. If we want to change in sink or float of submarine then we must  change the state of surrounding water. Thus, option c is correct.

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450 grams of water are formed when 250g of ethane combusts with 300 g of oxygen.

Combustion, or burning, is a high-temperature exothermic redox chemical response among a fuel and an oxidant, generally atmospheric oxygen, that produces oxidized, frequently gaseous products, in a mixture termed as smoke.

calculation:-

C₂H₆ + 7/2O₂ => 2CO₂ + 3H₂O

30 gram of ethane produce = 54 gram of water

250 gram of ethane produces  = 54/30 × 250

                                                     = 450 grams of water  

Combustion, a chemical reaction between materials, commonly consisting of oxygen and typically observed by way of the generation of heat and light in the form of flame. Combustion is the clinical phrase that burns. throughout a combustion response, the fabric reacts with oxygen from the air and contributes energy to the surroundings as light and warmth. the products of the reaction to combustion are referred to as oxides.

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The Lewis structure, electron domain, and molecular geometries of HCN are as follows: The Lewis structure of HCN is:
```H - C ≡ N. In this structure, hydrogen (H) forms a single bond with carbon (C), and carbon forms a triple bond with nitrogen (N). There are no lone pairs on the carbon or hydrogen atoms, but there is a lone pair on the nitrogen atom.

The electron domain geometry of HCN is linear because there are two electron domains around the central carbon atom: the bond with hydrogen and the triple bond with nitrogen. These electron domains spread out as far as possible from each other to minimize repulsion, resulting in a linear arrangement with an angle of 180 degrees.

The molecular geometry of HCN is also linear because the lone pair on nitrogen does not influence the overall shape of the molecule. Since there are no additional lone pairs on the central carbon atom, the bond between hydrogen, carbon, and nitrogen remains linear with an angle of 180 degrees.

In summary, the Lewis structure of HCN consists of a single bond between hydrogen and carbon, and a triple bond between carbon and nitrogen. Its electron domain and molecular geometries are both linear, with bond angles of 180 degrees.

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The fact that coal releases more heat than charcoal means that the chemical potential energy is lower in charcoal than in coal.

When the substance is burnt in oxygen, the chemical potential energy stored in the substance is converted into heat energy. The substance that has the most chemical potential energy releases the most energy when burnt.

In burning coal and charcoal, you notice that coal releases more heat energy than charcoal. This means that the chemical potential energy is lower in charcoal than in coal.

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The three (3) examples from the sword fighting scene that showed Inigo and the masked man's similarities are:

Inigo Montoya was one of the fictional character in the novel titled "The Princess Bride" and written by William Goldman's in 1973. Inigo hails from the village called Arabella and he was raised by his father Domingo Montoya, who was a master craftsman that makes sword.

In The Princess Bride, Inigo had a swordfight with a man in black (masked man) and they have the following things in common:

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Answer:

a quantity chosen as a standard in terms of which other quantities may be expressed.

Explanation:

Explanation:

Unit is a standard physical quantity defined and adopted by convention,with other quantity of same kind.

Answer:

(1) Nonbonding electron pairs are present on the F in the molecule HF. True

(2) The two atoms involved in a multiple covalent bond must always be atoms of the same element. False

(3) A molecule of hydrogen peroxide contains the same number of atoms as a molecule of sulfur trioxide does. True

Two of the three statements are true.

Explanation:

Non bonding electrons are also known as lone pairs. They are electron pairs present on an atom but are not involved in chemical bonding. They are usually localized on the atom of one of the bonding elements. In HF, there are three nonbonding electrons localized on the fluorine atom that do not participate in chemical bonding.

When multiple bonds are formed between atoms, they must not be atoms of the same element, for instance carbon and nitrogen forms multiple covalent bonds in chemical moieties such as they cyanide ion.

A molecule of hydrogen peroxide (H2O2) contains four atoms just as a molecule of sulphur trioxide(SO3) does.

The unknown metal X is iron metal as it reacts with copper sulfate solution but does not react with magnesium chloride.

Some metals are very reactive while other metals are less reactive or unreactive. When a more reactive metal is added to the solution of a less reactive metal, then the more reactive displaces the less reactive metal from its solution is known as a displacement reaction.

The general form of a single displacement reaction can be represented as:

\(A + BC \longrightarrow B + AC\)

When iron is placed in copper sulfate (CuSO₄) solution then the blue color of the copper sulfate solution turns a red-brown coating of copper metal deposited on the iron.

\(CuSO_4 (aq)+ Fe (s)\longrightarrow FeSO_4 (aq) +Cu(s)\)

Iron lies above the electrochemical series and is more reactive than copper. So it reacts with copper sulfate but does not give any reaction with magnesium chloride.

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a) In the reaction: \(Zn + 2H^+ - > H_2 + Zn_2^+\)

  The substance that is reduced is Zn (zinc), which gains electrons to form Zn2+.

  The substance that is oxidized is H+ (hydrogen), which loses electrons to form H2.

  Oxidizing agent (OA): H+

  Reducing agent (RA): Zn

b) In the reaction: \(NH + H_2O - > NH_3 + OH\)

  This reaction does not involve a redox process. It is a simple acid-base reaction where NH acts as a base and H2O acts as an acid.

c) In the reaction: \(Br2 + 2 Agl - > 12 + 2 AgBr\)

  The substance that is reduced is Br2 (bromine), which gains electrons to form 2 Br-.

  The substance that is oxidized is Agl (silver iodide), which loses electrons to form 2 Ag.

  Oxidizing agent (OA): Br2

  Reducing agent (RA): Agl

d) In the reaction: \(Pb + PbO_2 + 2 SO_4^2- + 4H - > 2 PbSO_4 + 2 H_2O\)

  The substance that is reduced is \(PbO_2\) (lead dioxide), which gains electrons to form \(PbSO_4\).

  The substance that is oxidized is Pb (lead), which loses electrons to form \(PbSO_4\).

  Oxidizing agent (OA): \(PbO_2\)

  Reducing agent (RA): Pb

e) In the reaction: \(4H + 2 NO_3- + Zn - > Zn_2+ + 2 H_2O + 2 NO_2\)

  The substance that is reduced is \(NO_3^-\)(nitrate), which gains electrons to form \(NO_2\).

  The substance that is oxidized is Zn (zinc), which loses electrons to form \(Zn_2^+\).

  Oxidizing agent (OA): \(NO_3^-\)

  Reducing agent (RA): Zn

f) In the reaction: \(2 OH + 2 MnO_2 + 3 H_2O_2 - > 2 MnO_4^- + 4 H_2O\)

  The substance that is reduced is MnO2 (manganese dioxide), which gains electrons to form \(MnO_4^-\).

  The substance that is oxidized is H2O2 (hydrogen peroxide), which loses electrons to form \(H_2O\).

  Oxidizing agent (OA): \(H_2O_2\)

  Reducing agent (RA): \(MnO_2\)

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Tea bags are initially extracted with deionized water because it is a safe and readily available solvent that can effectively extract the water-soluble compounds in tea leaves

Tea bags are initially extracted with deionized water because it is a safe and readily available solvent that can effectively extract the water-soluble compounds in tea leaves. Dichloromethane, on the other hand, is a highly volatile and toxic organic solvent that is not suitable for use in food or beverage processing.

Moreover, dichloromethane is not a suitable solvent for extracting the desirable components of tea because it is not selective in extracting the specific components of interest. Instead, it would extract a wide range of compounds, including unwanted and potentially harmful ones, such as pesticides or heavy metals that could be present in the tea leaves.

Therefore, for safe and effective extraction of the desired components of tea, deionized water is the preferred choice.

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Tea bags are initially extracted with deionized water because it is a safe and readily available solvent that can effectively extract the water-soluble compounds in tea leaves

Tea bags are initially extracted with deionized water because it is a safe and readily available solvent that can effectively extract the water-soluble compounds in tea leaves. Dichloromethane, on the other hand, is a highly volatile and toxic organic solvent that is not suitable for use in food or beverage processing.

Moreover, dichloromethane is not a suitable solvent for extracting the desirable components of tea because it is not selective in extracting the specific components of interest. Instead, it would extract a wide range of compounds, including unwanted and potentially harmful ones, such as pesticides or heavy metals that could be present in the tea leaves.

Therefore, for safe and effective extraction of the desired components of tea, deionized water is the preferred choice.

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Answer: d. energy must transfer to the carbon dioxide from its surroundings.

Explanation:

Sublimation is the phase change from a solid to a gas, meaning that the particles will have more kinetic energy (since particles in the solid phase are more ordered than particles in the gas phase, and thus particles in the gas phase have more energy). Thus, for sublimation to occur, the particles need more energy, which must come from its surroundings.

Explanation:

solute is the substance being dissolved so that is the 2 tablespoons of lemonade and the 2 cups of water is the solvent.

Chemical reactions must satisfy the law of conservation of mass, where the total mass of reactants is equal to the total mass of products. Balancing equations ensures this equality by adjusting coefficients.

1. H: + O2 —> H2O (balanced)

2. 2H2 + O2 —> 2H2O (balanced)

3. CH4 + O2 —> CO2 + H2O (unbalanced)

4. CH4 + O2 —> CO2 + 2H2O (unbalanced)

5. CH4 + 2O2 —> CO2 + 2H2O (balanced)

6. C2H5 + 5O2 —> 4H2O + 3CO2 (balanced)

7. C3H8 + 5O2 —> 4H2O + 3CO2 (balanced)

8. NaOH + H2SO4 —> Na2SO4 + H2O (balanced)

9. 2NaOH + H2SO4 —> Na2SO4 + 2H2O (balanced)

In a balanced chemical reaction, the number of atoms of each element on the reactant side must be equal to the number of atoms of the same element on the product side. The law of conservation of mass states that the total mass before a chemical reaction is the same as the total mass after the chemical reaction. Therefore, a balanced chemical equation ensures that the total mass of all reactants is equal to the total mass of all products, confirming the law of conservation of mass.

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Gene Vincent and Eddie Cochran were particularly popular with teenagers and young adults during the 1950s.

Gene Vincent and Eddie Cochran were American rock and roll musicians who gained popularity in the 1950s. They were part of the rockabilly movement, which combined elements of country music with rhythm and blues.

Gene Vincent was known for his hit song 'Be-Bop-A-Lula,' which became a rock and roll classic. Eddie Cochran was known for his energetic performances and songs like 'Summertime Blues' and 'C'mon Everybody.'

Both artists had a significant impact on the development of rock and roll music and were particularly popular with teenagers and young adults during their time.

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Gene Vincent and Eddie Cochran were particularly popular with the youth and rock and roll enthusiasts of the late 1950s and early 1960s.

Gene Vincent and Eddie Cochran were particularly popular with the youth and rock and roll music enthusiasts of the late 1950s and early 1960s. Their energetic performances and rebellious image resonated with the emerging teenage audience at the time.

They were influential figures in the rockabilly and rock and roll genres, known for their hits such as "Be-Bop-A-Lula" by Gene Vincent and "Summertime Blues" by Eddie Cochran. Their music and style captured the spirit of youthful rebellion and played a significant role in shaping the early rock and roll era.

Gene Vincent and Eddie Cochran were influential figures in the rock and roll music scene of the late 1950s and early 1960s. They were particularly popular with the teenage audience of the time, as their music and persona embodied the rebellious and energetic spirit of the youth culture.

Gene Vincent, born Vincent Eugene Craddock, rose to fame with his hit song "Be-Bop-A-Lula" in 1956. Known for his distinctive vocal style and wild stage presence, Vincent became a rockabilly icon. His music blended elements of rock and roll, rhythm and blues, and country, creating a unique sound that resonated with young listeners. Songs like "Bluejean Bop" and "Race with the Devil" further solidified his popularity.

Eddie Cochran, on the other hand, was a multi-talented musician, singer, and songwriter. He gained fame with his upbeat and catchy songs, such as "Summertime Blues" and "C'mon Everybody." Cochran's music was characterized by his skillful guitar playing, heartfelt lyrics, and a distinctive rock and roll sound. His contributions to the genre and his early death at the age of 21 in a tragic car accident solidified his status as a rock and roll legend.

Both Gene Vincent and Eddie Cochran were known for their electrifying live performances and their impact on the rock and roll genre. Their music resonated with young audiences who were seeking an outlet for their rebellious spirit and love for energetic, guitar-driven music. Their influence can still be felt in the development of rock music and the inspiration they provided to subsequent generations of musicians.

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Answer:

It is true. a) 0.25 mol

Explanation:

Hello there?

To begin solving this problem, you have to write down the chemical equation and make sure it is well balanced.

The chemical equation is;

3Mg(s) + N2(g) => Mg3N2(s)

1 mole of Mg = 24g

We have 18g of Magnesium (Mg) reacting with Nitrogen gas (N2)

From our equation,

Mole ratio = 3 : 1, (Mg : N2)

1 mol Mg = 24g

x mol Mg = 18g

x mol Mg = (18/24) = 0.75 mol Mg

But mole ratio = 3 : 1 (Mg : N2)

This means that 3 => 0.75 mol Mg

What about ratio 1 of N2?

N2 = (0.75 mol ÷ 3)/1

= 0.25 mol N2

I hope this helps you to understand better. Have a nice studies.

The energy provided by the snack is obtained as 1254 J/g.

The calorimeter is used to measure the energy content of food. The food is burnt in the calorimeter in order to determine the amount of energy that it contains. The mass of the food burnt is converted to energy.

Mass of food burnt = 3.52 g - 1.52 g = 2 g

The energy that is provided by the snack in J/g = 2,508 J/ 2 g

= 1254 J/g

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Option (C) is correct. One should count the atoms of each element on both sides of the chemical equation to make sure they are equal and decide whether the equation is balanced and appropriately constructed.

The number of moles of a substance created or consumed during the chemical reaction is indicated by the coefficients next to the entity symbols.

Verify each answer to verify sure the result does not result in the original equation's denominator being equal to zero. a denominator in the original equation can be made zero if a solution can be discovered.

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Question:

What is a method you could use to determine if an equation is written in the correct way and balanced?

One method to determine if an equation is written in the correct way and balanced is to check that the number and type of atoms are the same on both sides of the equation by using the Law of Conservation of Mass.

0.84 milligrams of a 2. 000 mg sample remain after 6. 55 years, according to radioactive decay.

Given data,

\(t\frac{1}{2} of Co-60 = 5.20years\)

amount of sample = 2.000mg initially = 0.002grams

According to radioactive decay,

\(N_{t} = N_{0}e^{-λt}\)

(\(N_{0} - 0.002\) )λ = \(\frac{0.693}{t\frac{1}{2} }\) = \(\frac{0.693}{5.20}\)  = 0.133

According to radioactive decay,

\(N_{t} = N_{0}e^{-λt}\)

\(lnN_{t} = lnN_{0}\) - λt

\(lnN_{t}\) = ln0.002 - (0.133×6.55)

       = -6.21 - 0.87 = -7.08 = 0.00084g = 0.84mg

Therefore, 0.84 milligrams of a 2. 000 mg sample remain after 6. 55 years.

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NADPH production occurs in the pentose phosphate pathway and in the light-dependent reactions of photosynthesis and provides important biosynthetic capabilities, including fatty acid and nucleotide synthesis. NADPH also serves an important role in red blood cells, reducing oxidized glutathione so that it can eliminate reactive molecules, such as hydrogen peroxide, from damaging cellular components.

NADH (Nicotinamide adenine dinucleotide) and NADPH (Nicotinamide adenine dinucleotide phosphate) are coenzymes that play important roles in cellular metabolism as electron carriers, providing reducing power for various biochemical reactions. They are involved in numerous redox reactions in cells and are essential for energy production, biosynthesis of macromolecules such as proteins, nucleic acids, and lipids, and in antioxidant defense mechanisms. NADH and NADPH act as crucial cofactors in cellular processes, providing reducing equivalents for the synthesis of bonds and other important biochemical reactions in cells.

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Where's the question (s)?

Answer:

63.546

Explanation:

The Average atomic mass is calculated using the formula:

sum of the product of the atomic masses and their relative abundances all divided by 100 or total abundance

The list that  only includes terms that describe Cesium (Cs) is option (b) i.e atom, element, pure substance .

Atom, is the smallest unit of matter that has the characteristic properties of a chemical element .The atom is the basic building block of chemistry.

Element  is a pure substance consisting of only one type of atom which all have the same numbers of protons. Elements are chemically the simplest substances and hence cannot be broken down using chemical reactions.

Hence ,in the list that  only includes terms that describe Cesium (Cs) is option (b) i.e atom, element, pure substance .

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Answer:

people who discover new things fyi you dont have any answer choices on there

Explanation:

there are different type of scientist

Answer:

A scientist asks questions about the world.

Explanation:

Mass of CO₂ produced : 58.67 g

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

CS₂ + 3O₂  -------> CO₂ + 2SO₂

mol of CO₂ based on mol of O₂ as a limiting reactant(CS₂ as an excess reactant)

From the equation, mol ratio of mol CO₂ : mol O₂ = 1 : 3, so mol CO₂  :

\(\tt \dfrac{1}{3}\times 4=\dfrac{4}{3}\)

mass  CO₂ (MW= 44 g/mol) :

\(\tt \dfrac{4}{3}\times 44=58.67~g\)

The initial product formed at the anode will be chlorine gas (Cl2) and some amount of hypochlorous acid (HClO) and hydrochloric acid (HCl) due to the reaction between Cl2 and water.

During electrolysis of an aqueous solution, the anode is the electrode where oxidation takes place. At the anode, chloride ions (Cl-) and hydroxide ions (OH-) are the two possible ions that can be oxidized. In this case, the solution contains FeCl3 and CuBr2, so both Fe3+ and Cu2+ ions are present in the solution. However, Fe3+ is a stronger oxidizing agent than Cu2+ and hence, Fe3+ ions will be preferentially oxidized at the anode over Cu2+ ions.
The oxidation of Fe3+ ions at the anode can produce two possible products:
Fe2O3 and Cl2 gas. However, in the presence of water, Cl2 gas reacts with water to form hypochlorous acid (HClO) and hydrochloric acid (HCl).

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Answer:

Coffee Filter.

Tea-bags.

Water Filters.

Sand Filtration.

HEPA Air Filters.

Automotive Filters.

Belt Filters.

Dialysis.

Explanation: