What is a chi square test?

The statement that is not true: The arc is not a semicircle.

The diagram shows an arc that is formed by two points, point a and point b, with the same radius. The arc does not appear to be a semicircle because it is not a complete circle and the two points, a and b, do not appear to be the same distance from each other.

This means that the statement “The arc is a semicircle” is not true. Additionally, the arc could be an ellipse or some other curved shape, depending on the location of the two points, a and b, relative to each other.

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Answer:

\(5x - 2y = 10\) and \(y = 1 + x\)

\(5x = 10 + 2y\) and \(y = 1 + x\)

Step-by-step explanation:

Represent the cost of pencil with y and erasers with x.

So: The first statement implies that:

Cost of 5 erasers = 5x

Cost of 2 pencils = 2y

Difference: 5x - 2y = 10

The second statement implies that:

Pencil = 1 more than eraser.

i.e.

y = 1 + x

So, we have the following system of equations (1)

\(5x - 2y = 10\)

\(y = 1 + x\)

Another way of representing the equations is: (2)

\(5x = 10 + 2y\)

\(y = 1 + x\)

Answer:

83.54 in²

Step-by-step explanation:

Brₐinliest plz

Answer:here you go please and thankful

Step-by-step explanatio

Answer:

what grade are you in that requieres this type of math

Step-by-step explanation:

Answer:

B. x+1 / x+9

Step-by-step explanation:

Answer:

3zx-15z+12x-60

Step-by-step explanation:

first do parenthesis and distribute (z+4)(x-5) into zx-5z+4x-20

then distribute the 3 to get the answer

This is a negative number, there is no real value of c that satisfies the Mean Value Theorem.

What is mean value theorem ?

The Mean Value Theorem is a fundamental result in calculus that establishes a relationship between the values of a function and its derivative on an interval. The theorem states that if a function f(x) is continuous on a closed interval [a,b] and differentiable on the open interval (a,b), then there exists at least one point c in (a,b) where the slope of the tangent line to the curve at c is equal to the average slope of the curve over the interval [a,b]. In other words, there exists a point c where the instantaneous rate of change of the function equals the average rate of change of the function over the interval [a,b]. Mathematically, the theorem can be expressed as:

f'(c) = (f(b) - f(a))/(b - a)

According to the question:
To use the Mean Value Theorem, we need to verify that the following conditions are satisfied:

f(x) is continuous on the interval [-5,-1]

f(x) is differentiable on the interval (-5,-1)

If both of these conditions are satisfied, then there exists a value c in the interval (-5,-1) such that:

\(f'(c) = (f(-1) - f(-5))/(-1 - (-5)) = (f(-1) - f(-5))/4\)

So, let's check the conditions:

f(x) is continuous on [-5,-1]:

The function is continuous on the interval, except at x=0, where it has a vertical asymptote. However, since 0 is not in the interval [-5,-1], we can ignore this issue.

f(x) is differentiable on (-5,-1):

To check if f(x) is differentiable, we need to find its derivative:

\(f(x) = (x^2 - 4)/(2x) = (1/2)x - (2/x)\)

\(f'(x) = 1/2 + 2/x^2\)

Since f'(x) is defined and continuous on the interval (-5,-1), f(x) is differentiable on the interval (-5,-1).

Therefore, by the Mean Value Theorem, there exists a value c in the interval (-5,-1) such that:

\(f'(c) = (f(-1) - f(-5))/4\)

We can now find this value of c by solving for it:

\(f'(-5) = 1/2 + 2/25 = 29/50\)

\(f'(-1) = 1/2 + 2 = 5/2\)

\((f(-1) - f(-5))/4 = ((-1)^2 - 4)/(2(-1)) - ((-5)^2 - 4)/(2(-5)))/4\)

\(= (3/2 - 21/10)/4 = -3/20\)

Therefore, there exists a value c in the interval (-5,-1) such that:

\(f'(c) = -3/20\)

We can find this value of c by solving for it:

\(1/2 + 2/c^2 = -3/20\)

Multiplying both sides by \(c^2\):

\(c^2/2 + 2 = -3c^2/20\)

Multiplying both sides by 20:

\(10c^2 + 40 = -3c^2\)

\(13c^2 = -40\)

\(c^2 = -40/13\)

Since this is a negative number, there is no real value of c that satisfies the Mean Value Theorem.

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Step-by-step explanation:

The transformation y = sin(2x) affects the graph of y = sin(x) by compressing it horizontally.

The function y = sin(2x) has a coefficient of 2 in front of the x variable. This means that for every x value in the original function, the transformed function will have half the x value.

To see the effect of this transformation, let's compare the graphs of y = sin(x) and y = sin(2x) by plotting some points:

For y = sin(x):

x = 0, y = 0

x = π/2, y = 1

x = π, y = 0

x = 3π/2, y = -1

x = 2π, y = 0

For y = sin(2x):

x = 0, y = 0

x = π/2, y = 0

x = π, y = 0

x = 3π/2, y = 0

x = 2π, y = 0

As you can see, the y-values of the transformed function remain the same as the original function at every x-value, while the x-values of the transformed function are compressed by a factor of 2. This means that the graph of y = sin(2x) appears narrower or more "squeezed" horizontally compared to y = sin(x).

Therefore, the correct statement is: It is compressed horizontally.

Answer:

Week 1 = 80

Week 2 =88

Week 3 = 96.8

Week 4 = 106.48

Week 5 = 117.128

Step-by-step explanation:

Given

Week 1 = 80

Growth = 10%

Required

Fill week 1 to 5

We have week 1 already.

Week 2 is calculated as thus:

Week 2 = Week 1 + 10% * Week 1

Week 2 = 80 + 10% * 80

Week 2 = 80 + 8

Week 2 = 88

Week 3 is calculated as thus:

Week 3 = Week 2 + 10% *Week 2

Week 3 = 88 + 10% * 88

Week 3 = 88 + 8.8

Week 3 = 96.8

Week 4 is calculated as thus:

Week 4 = Week 3 + 10% * Week 3

Week 4 = 96.8 * 10% *96.8

Week 4 = 96.8 + 9.68

Week 4 = 106.48

Lastly, week 5 is calculated as thus:

Week 5 = Week 4 + 10% * Week 4

Week 5 = 106.48 + 10% * 106.48

Week 5 = 106.48 + 10.648

Week 5 = 117.128

Answer:

x = 4, -2

Step-by-step explanation:

x^2-2x=8

Move the constant term to the right side of the equation.

x^2 - 2x = 8

Take half of the coefficient of x and square it.

(-2/2)^2 = 1

Add the square to both sides of the equation.

x^2 - 2x + 1 = 8 + 1

Factor the perfect square trinomial.

(x - 1)^2 = 9

Take the square root of both sides of the equation.

x-1=\(\sqrt{9}\)
x-1=±3

Isolate x to find the solutions.

Taking positive

x=3+1=4

x=4

Taking negative

x=-3+1

x=-2

The solutions are:

x = 4, -2

Answer:

\(x = -2,\;\;x=4\)

Step-by-step explanation:

To solve the quadratic equation x² - 2x = 8 by factoring, subtract 8 from both sides of the equation so that it is in the form ax² + bx + c = 0:

\(x^2-2x-8=8-8\)

\(x^2-2x-8=0\)

Find two numbers whose product is equal to the product of the coefficient of the x²-term and the constant term, and whose sum is equal to the coefficient of the x-term.

The two numbers whose product is -8 and sum is -2 are -4 and 2.

Rewrite the coefficient of the middle term as the sum of these two numbers:

\(x^2-4x+2x-8=0\)

Factor the first two terms and the last two terms separately:

\(x(x-4)+2(x-4)=0\)

Factor out the common term (x - 4):

\((x+2)(x-4)=0\)

Apply the zero-product property:

\(x+2=0 \implies x=-2\)

\(x-4=0 \implies x=4\)

Therefore, the solutions to the given quadratic equation are:

\(\boxed{x = -2,\;\;x=4}\)

Answer:

x = 65.26 degrees or x = 245.26 degrees.

Step-by-step explanation:

To solve the equation 4tan(x)-7=0 for 0<=x<360, we can first isolate the tangent term by adding 7 to both sides:

4tan(x) = 7

Then, we can divide both sides by 4 to get:

tan(x) = 7/4

Now, we need to find the values of x that satisfy this equation. We can use the inverse tangent function (also known as arctan or tan^-1) to do this. Taking the inverse tangent of both sides, we get:

x = tan^-1(7/4)

Using a calculator or a table of trigonometric values, we can find the value of arctan(7/4) to be approximately 65.26 degrees (remember to use the appropriate units, either degrees or radians).

However, we need to be careful here, because the tangent function has a period of 180 degrees (or pi radians), which means that it repeats every 180 degrees. Therefore, there are actually two solutions to this equation in the given domain of 0<=x<360: one in the first quadrant (0 to 90 degrees) and one in the third quadrant (180 to 270 degrees).

To find the solution in the first quadrant, we can simply use the value we just calculated:

x = 65.26 degrees (rounded to two decimal places)

To find the solution in the third quadrant, we can add 180 degrees to the first quadrant solution:

x = 65.26 + 180 = 245.26 degrees (rounded to two decimal places)

So the solutions to the equation 4tan(x)-7=0 for 0<=x<360 are:

x = 65.26 degrees or x = 245.26 degrees.

Since the test statistic is not greater than the critical value, the null hypothesis cannot be rejected. Therefore, the claim that the mean score is 71 is not rejected.

1. We are given the population of statistics final exams and asked to test the claim that the mean score is 71 using an alternative hypothesis that the mean score is different from 71. We are also given the sample statistics including the sample size (n = 26), the sample mean (ã = 72), and the sample standard deviation (s = 18). We are asked to use a significance level of α = 0.05.

2. Since we are assuming that the population is normally distributed, we will use a two-tailed z-test to test the claim.

3. The null hypothesis is that the mean score is 71 and the alternative hypothesis is that the mean score is different from 71.

4. The test statistic is calculated as:

Test statistic = (sample mean - population mean) / (standard deviation/√n)

= (72 - 71) / (18/√26)

= 0.283

5. The critical values for a two-tailed z-test with a significance level of α = 0.05 are 1.645 for both the positive and negative critical values.

6. Since the test statistic (0.283) is not greater than the critical value

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Answer:

will you help me with grade 9 math, algebra 2 please

Step-by-step explanation:

The missing ordered pairs that satisfy the equation y = 2x + 4 are (3, 10) and (2, 8).

The equation given is y = 2x + 4. To compute the missing x and y values, we need to substitute the given ordered pairs into the equation and solve for the missing variable.

Let's assume we have an ordered pair (x, y) that satisfies the equation y = 2x + 4.

For example, let's say one missing value is x = 3. We can substitute this into the equation:

y = 2(3) + 4

y = 6 + 4

y = 10

So, the missing ordered pair is (3, 10).

Similarly, if another missing value is y = 8, we can substitute this into the equation and solve for x:

8 = 2x + 4

4 = 2x

x = 2

So, the missing ordered pair is (2, 8).

In summary, the missing x and y values that satisfy the equation y = 2x + 4 are (3, 10) and (2, 8).

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Answer:

i dont know

Step-by-step explanation:

?????????????????????????

Answer:

88 points.

Step-by-step explanation:

Answer:

You will have to have 88 points i think

Step-by-step explanation:

Answer:

Step-by-step explanation:

In a triangle, the sum of the three interior angles is always 180 degrees. Therefore, we can set up an equation based on this fact to find the measure of angle A.

Since AB is congruent to BC, angles A and C are congruent. Let's call their measure y:

y + y + (x+2+ x+23) = 180

Simplifying and combining like terms:

2y + 2x + 25 = 180

Subtracting 25 from both sides:

2y + 2x = 155

Dividing both sides by 2:

y + x = 77.5

Since we want to find the measure of angle A, which is x+23, we can substitute y = x+23 into the equation:

x+23 + x = 77.5

Simplifying and combining like terms:

2x + 23 = 77.5

Subtracting 23 from both sides:

2x = 54.5

Dividing both sides by 2:

x = 27.25

Therefore, the measure of angle A is:

x + 23 = 27.25 + 23 = 50.25 degrees

Multiply the numerator and denominator by 1 - sin(x) :

\(\dfrac{1}{1 + \sin(x)} \times \dfrac{1 - \sin(x)}{1 - \sin(x)} = \dfrac{1 - \sin(x)}{1 - \sin^2(x)} = \dfrac{1-\sin(x)}{\cos^2(x)}\)

Now separate the terms in the fraction and rewrite them as

\(\dfrac1{\cos^2(x)} - \dfrac{\sin(x)}{\cos^2(x)} = \sec^2(x) - \tan(x) \sec(x)\)

and you'll recognize some known derivatives,

\(\dfrac{d}{dx} \tan(x) = \sec^2(x)\)

\(\dfrac{d}{dx} \sec(x) = \sec(x) \tan(x)\)

So, we have

\(\displaystyle \int \frac{dx}{1 + \sin(x)} = \int (\sec^2(x) - \sec(x) \tan(x)) \, dx = \boxed{\tan(x) - \sec(x) + C}\)

which we can put back in terms of sin and cos as

\(\tan(x) - \sec(x) = \dfrac{\sin(x)}{\cos(x)}-\dfrac1{\cos(x)} = \dfrac{\sin(x)-1}{\cos(x)}\)

We are given with a Indefinite integral , and we need to find it's value ,so , let's start

\({:\implies \quad \displaystyle \sf \int \dfrac{1}{1+\sin (x)}dx}\)

Now , Rationalizing the denominator i.e multiplying the numerator and denominator by the conjugate of denominator i.e 1 - sin(x)

\({:\implies \quad \displaystyle \sf \int \bigg\{\dfrac{1}{1+\sin (x)}\times \dfrac{1-\sin (x)}{1-\sin (x)}\bigg\}dx}\)

\({:\implies \quad \displaystyle \sf \int \dfrac{1-\sin (x)}{1-\sin^{2}(x)}dx\quad \qquad \{\because (a-b)(a+b)=a^{2}-b^{2}\}}\)

\({:\implies \quad \displaystyle \sf \int \dfrac{1-\sin (x)}{\cos^{2}(x)}dx\quad \qquad \{\because \sin^{2}(x)+\cos^{2}(x)=1\}}\)

\({:\implies \quad \displaystyle \sf \int \bigg\{\dfrac{1}{\cos^{2}(x)}-\dfrac{\sin (x)}{\cos^{2}(x)}\bigg\}dx}\)

\({:\implies \quad \displaystyle \sf \int \bigg\{\sec^{2}(x)-\dfrac{\sin (x)}{\cos (x)}\times \dfrac{1}{\cos (x)}\bigg\}dx\quad \qquad \bigg\{\because \dfrac{1}{\cos (\theta)}=\sec (\theta)\bigg\}}\)

\({:\implies \quad \displaystyle \sf \int \{\sec^{2}(x)-\tan (x)\sec (x)\}\quad \qquad \bigg\{\because \dfrac{\sin (\theta)}{\cos (\theta)}=\tan (\theta)\bigg\}}\)

Now , we know that ;

Using this we have ;

\({:\implies \quad \displaystyle \sf \int \sec^{2}(x)dx-\int \tan (x)\sec (x)dx}\)

Now , we also knows that ;

Where C is the Arbitrary Constant . Using this

\({:\implies \quad \displaystyle \sf \tan (x)-\sec (x)+C}\)

\({:\implies \quad \bf \therefore \quad \underline{\underline{\displaystyle \bf \int \dfrac{1}{1+\sin (x)}dx=\tan (x)-\sec (x)+C \:\: \forall \:\: C\in \mathbb{R}}}}\)

Answer:

x < 3 1/4

See picture below.

Step-by-step explanation:

1/2 x - 3 < -1 3/8

1/2 x < -11/8 + 24/8

1/2 x < 13/8

x < 13/4

x < 3 1/4

Answer:

y = \(\frac{2}{3}\) x + 3

Step-by-step explanation:

y = mx + b is the slope intercept form of a line.  You need to know the m (slope) and the b (y intercept) to write the equation.

We are given the m (slope) to be \(\frac{2}{3}\).  We will use 3 from the point given for our x and the 5 from the point given for our y.  We will use these to solve for the b (y-intercept)

y = mx + b

5 = \(\frac{2}{3}\) (3) + b

5 = \(\frac{2}{3}\) · \(\frac{3}{1}\) + b

5 = \(\frac{6}{3}\) + b

5 = 2 + b  Subtract 2 from both sides

3 = b

We can now write the equation.  Our slope (m) is  \(\frac{2}{3}\) and our y-intercept (b) is 3.

y = \(\frac{2}{3}\) x + 3

Helping in the name of Jesus.

Answer:

  $142.32, profit on sale of the policy

Step-by-step explanation:

You want to know the expected value of a $280,000 life insurance policy sold for $270, if the probability the insured will live for the year is 0.999544.

The insurance company expects to have to pay the $280,000 death benefit for 0.000456 of the policies issued. That means their expected payout on any one policy is ...

  0.000456 × $280,000 = $127.68

The company gets a premium of $270 for the policy, so the expected value of the policy to the company is ...

  $270 -127.68 = $142.32

The expected value of the policy to the company is $142.32.

This represents its profit from sale of the policy.

__

Additional comment

Of course, the company has expenses related to the policy, perhaps including a commission to the agent selling it, and expenses related to handling claims. That is to say that not all of the difference between the premium and the average death benefit is actually profit. It is what might be called "contribution margin."

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The volume of the largest right circular cylinder is \(=\frac{4\pi r^3}{3\sqrt{3} }\) cu. unit

Now, According to the question:

The given sphere is of radius R.

Let h be the height and r be the radius of the cylinder inscribed in the sphere.

We know that:

Volume of cylinder

V = \(\pi R^2h\)    .....(1)

In right Triangle OBA

\(AB^2 + OB^2 = OA^2\)

\(R^2 + \frac{h^2}{4} = r^2\)

So, \(R^2 = r^2 - \frac{h^2}{4}\)

Putting the value of \(R^2\) in equation (1), We get

V = \(\pi (r^2 - \frac{h^2}{4} )h\)

V = \(\pi (r^2h - \frac{h^3}{4} )\)   ....(2)

dV/dh = \(\pi (r^2 - \frac{3h^2}{4} )\) .....(3)

For, Stationary point, dV/dh = 0

\(\pi (r^2 - \frac{3h^2}{4} )\) = 0

\((r^2 - \frac{3h}{4} )\)   => \(h^2 - \frac{4r^2}{3}\) => \(h - \frac{2r}{\sqrt{3} }\)

Now, \(\frac{d^2V}{dh^2} = \pi (-\frac{6}{4}h )\)

\([\frac{d^2V}{dh^2}]_a_t_h_=_\frac{2r}{\sqrt{3} }\)   = x[-3/2 , \(2r/\sqrt{3}\)]< 0

Volume is maximum at h = 2r/\(\sqrt{3}\)

Maximum volume is :

\(= \pi (r^2.\frac{2r}{\sqrt{3} }- \frac{1}{4}.\frac{8r^3}{3\sqrt{3} } )\)

\(=\pi (\frac{2r^3}{\sqrt{3} }-\frac{2r^3}{3\sqrt{3} } )\)

\(=\pi (\frac{6r^3-2r^3}{3\sqrt{3} } )\)

\(=\frac{4\pi r^3}{3\sqrt{3} }\) cu. unit

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The new coordinates of the reflected point will be (2, 2).

In mathematics, reflection is a transformation that "flips" an object over a line or plane. Reflection is a type of symmetry, where an object appears exactly the same after being reflected as it did before.  

When a point is reflected across the y-axis, its x-coordinate changes sign while its y-coordinate remains the same.  

Here we have

The point (-2, 2) is reflected across the y-axis

When a point is reflected across the y-axis, its x-coordinate changes sign while its y-coordinate remains the same.

The new coordinate of the point = (-(-2), 2) = (2, 2)

Therefore,

The new coordinates of the reflected point will be (2, 2).

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Answer:

see explanation

Step-by-step explanation:

(a)

5% of N 80000

= \(\frac{5}{100}\) × 80000

= 0.05 × 80000

= N4000 ← VAT

(b)

total cost = 80000 + 4000 = N84000

Answer:

linear function

Step-by-step explanation:

straight line then add up

Answer:

one over five (m-100)

Step-by-step explanation:

the answer to your question is the 2nd one

Answer:

1 / [ 5(m - 4) ] is equivalent to one over five m -20

Step-by-step explanation:

one over five(m − 4)

5(m − 4)

Factor the denominator:

1 / [ 5m - 20 ]  =  1 / [ 5(m - 4) ]