What is 6= x -15, I’m just trying not fail in the maths I’m already failing

The temperature at the point where the clouds begin to form is 77.65 °F

Given: The starting point is 1234 feet and air temperature is 79.4°F

You climb to where you notice clouds beginning to form.It can be observed that the temperature decreases by 3.5°F per 1000 feet as we go up.

Using this information, we can calculate the temperature at the point where the clouds start forming.

Let the height of the point where clouds begin to form be x feet above the starting point. As per the question, the temperature decreases by 3.5°F per 1000 feet as we go up.

Therefore, the temperature at the height of x feet can be calculated as:

T(x) = T(1234) - 3.5/1000 * (x - 1234)°F , where

T(1234) = 79.4°F

Substituting the value of x = 1234 + 500, (as we need to know the temperature at the point where clouds begin to form) we get:

T(1734) = T(1234) - 3.5/1000 * (1734 - 1234) °F

= 79.4 - 3.5/1000 * 500 °F

= 79.4 - 1.75 °F

= 77.65 °F

Therefore, the temperature at the point where the clouds begin to form is 77.65 °F

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Answer:

it not clear maybe you can take an other pohto

sorry

Step-by-step explanation:

Answer:

x=1

Step-by-step explanation:

it is

Answer:

3/20

Step-by-step explanation:

Answer: The answer is 8

Step-by-step explanation: 16 tablespoon is 1 cup now find half of 16. Half of 16 is 8. So 8 tablespoon should be equal 1/2 cup

The solutions for the quadratic equations ax² + bx = 0 are:

a) x=0 or x=-2 for x²+2x=0;

x=0 or x=2 for x²-2x=0;

x=0 or x=2 for -x²+2x=0;

x=0 or x=-2 for -x²-2x=0.

b) x=0 or x=-5/3 for 3x²+5x=0;

x=0 or x=5/3 for 3x²-5x=0;

x=0 or x=5/3 for -3x²+5x=0;

x=0 or x=-5/3 for -3x²-5x=0.

a) To solve the quadratic equations ax² + bx = 0, we need to factor out the common variable x, and then solve for x:

a) x²+2x=0

x(x+2)=0

x=0 or x=-2

b) x²-2x=0

x(x-2)=0

x=0 or x=2

c) -x² + 2x = 0

-x(x-2)=0

x=0 or x=2

d) -x²-2x=0

-x(x+2)=0

x=0 or x=-2

b) To solve the quadratic equations 3x²+5x=0, 3x²-5x=0, -3x²+5x=0, and -3x²-5x=0, we factor out the common variable x and then solve for x:

b) 3x²+5x=0

x(3x+5)=0

x=0 or x=-5/3

b) 3x²-5x=0

x(3x-5)=0

x=0 or x=5/3

c) -3x²+5x=0

x(-3x+5)=0

x=0 or x=5/3

d) -3x²-5x=0

x(-3x-5)=0

x=0 or x=-5/3

Therefore, the solutions for the quadratic equations ax² + bx = 0 are:

a) x=0 or x=-2 for x²+2x=0;

x=0 or x=2 for x²-2x=0;

x=0 or x=2 for -x²+2x=0;

x=0 or x=-2 for -x²-2x=0.

b) x=0 or x=-5/3 for 3x²+5x=0;

x=0 or x=5/3 for 3x²-5x=0;

x=0 or x=5/3 for -3x²+5x=0;

x=0 or x=-5/3 for -3x²-5x=0.

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The English translation of the question in the picture:

75. Solve the quadratic equations ax² + bx = 0

a) x²+2x=0,

x²-2x=0,

-x² + 2x = 0.

-x²-2x=0;

b) 3x²+5x=0,

3x²-5x=0.

-3x²+5x=0,

-3x²-5x=0;

Answer:

$4

Step-by-step explanation:

40/100=0.4

(10)0.4=4

Answer:

anything raised to the power of 3

Step-by-step explanation:

Something raised by the power of 2 has two equal dimensions. A cube has three equal dimensions.

Answer: The power of 3. So for example it would be x^3, and x is whatever number.

Step-by-step explanation:

The population of an island in 1950 was 2 million. The population grew exponentially for 63 years and reached 6.5 million in 2013. The carrying capacity of the island is estimated to be 10 million.

If the population growth rate in the future is similar to the last 50 years, what will the population be in 2050

The population is given to be increasing exponentially, which means it will follow the equation:

\($P(t) = P_0 e^{rt}$\)Here,\($P(t)$\) is the population after a period of time \($t$, $P_0$\) is the initial population, $r$ is the annual growth rate (which we are given is the same as the growth rate of the last 50 years), and \($t$\) is the time.

We can find the annual growth rate $r$ using the formula:\($$r = \frac{\ln{\frac{P(t)}{P_0}}}{t}$$\)
We know\($P_0 = 2$ million, $P(t) = 6.5$ million, and $t = 63$\) years. Substituting these values, we get:

\($r = \frac{\ln{\frac{6.5}{2}}}{63} = 0.032$\) (rounded to 3 decimal places)

Since the carrying capacity of the island is 10 million, we know that the population will not exceed this limit.

Therefore, we can use the logistic model to find the population growth over time. The logistic growth model is:

\($$\frac{dP}{dt} = r P \left(1 - \frac{P}{K}\right)$$\)

where $K$ is the carrying capacity of the environment. This can be solved to give:\($P(t) = \frac{K}{1 + A e^{-rt}}$\)

where \($A = \frac{K-P_0}{P_0}$. We know $K = 10$ million, $P_0 = 2$ million, and $r = 0.032$\). Substituting these values, we get:\($A = \frac{10-2}{2} = 4$\)

Therefore, the equation for the population of the island is:\($P(t) = \frac{10}{1 + 4 e^{-0.032t}}$\)

To find the population in 2050, we substitute\($t = 100$\) (since 63 years have already passed and we want to find the population in 2050, which is 100 years after 1950):

\($P(100) = \frac{10}{1 + 4 e^{-0.032 \times 100}} \approx \boxed{8.76}$ million\)
Therefore, the estimated population of the island in 2050, assuming constant carrying capacity and consumption per capita, is approximately 8.76 million.

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Hello !

Answer:

\(\boxed{\sf Option\ C \to A=155ft}\)

Step-by-step explanation:

To calculate the area of this figure, we will divide it into three smaller figures as shown in the attached file.

Now that we have three rectangles A, B, and C.

The formula to calculate the area of a rectangle is:

\(\sf A_{rec} = Length\times Width\)

Let's calculate the area of the 3 rectangles using the previous formula :

\(\sf A_A=12\times 5=60ft\)

\(\sf A_B = 7\times5=35ft\)

\(\sf A_C=12\times 5 =60ft\)

Now we can calculate the total area of the figure.

\(\sf A=A_A+A_B+A_C\\A=60+35+60\\\boxed{\sf A=155ft}\)

Have a nice day ;)

Answer:

let x =the price of the items

25x/100=$30

$30×100=25x

$3000=25x

divide both sides by 25

$3000/25=25x/25

$120=x

therefore the price is $120

Answer:

37.5

Step-by-step explanation:

30 x 0.25 =  7.5

30 +7.5

37.5

The number of solutions to a system of linear equations can be determined by solving the equations and checking for consistency. If the system is consistent, it has one unique solution. If the system is inconsistent, it has no solution. If the system is dependent, it has infinitely many solutions.

The number of solutions to a system of linear equations can be determined by solving the equations and checking for consistency. If the system is consistent, it has one unique solution. To check for consistency, the equations must be solved and the solutions compared. If all the solutions are the same, then the system is consistent and has one unique solution. If the solutions are different, then the system is inconsistent and has no solution. If all variables are linearly dependent, then the system is dependent and has infinitely many solutions. To determine if the variables are linearly dependent, one must check for a linear combination of the variables that yields the zero vector. If the linear combination exists, the system is dependent and has infinitely many solutions.

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Answer: the right side subtracted 4 when they were supposed to add in the row before the solution.

Step-by-step explanation: you have to subtract or add from both sides, they have to be the same, when solving equations like these. the answer should be 5.

A- The Sum of the series is 2 - 20 + 200 .. is 2/11. B- the 12th term of the geometric sequence is option C -112.

We can observe that each term in the series is obtained by multiplying the previous term by -10.

Let the first term be a = 2, and the common ratio be r = -10.

Using the formula for the sum of an infinite geometric series, we have:

So = a / (1 - r)

So = 2 / (1 - (-10))

So = 2 / 11

So the sum of the given series is 2/11.

b- We can use the formula for the nth term of a geometric sequence to find the 12th term.

aₙ = a1×rⁿ-¹

where a1 is the first term and r is the common ratio.

We are given two terms in the sequence:

a7 = 7

a56 = ?

We can use these to find a1 and r.

First, we can find the common ratio:

r = a7 / a6 = 7 / (a7 / r) = 7 / a56

Next, we can use the formula to find a1:

aₙ = a2×rⁿ-¹

Substituting the values we know:

r = 7 / a56

Simplifying:

a1= a56^6

Now we can use the formula to find a12:

a12 = a1 * r^(12-1)

Simplifying:

a12 = 7^11 * a56^(-5)

Therefore, the 12th term of the sequence is a negative number, and the only negative option given is (c) -112. So the answer is (c) -112.

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the average number of calls that arrived between 8:00 am and 8:10 am during the working days of any month is Option(c) a parameter.

A parameter is a special type of mathematical variable. An equation that uses parametric variables that can have multiple values is referred to as a parametric equation. Parameter values are kept constant when using the function. Statisticians use parameters to estimate population characteristics numerically.

Parameters can be used in a variety of ways in real-life scenarios, including in statistics. Parameters are estimations of populations in statistics. The mean and standard deviation are two of the most common statistical parameters. In various statistical tests, these estimates are used to calculate the test statistic.

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There are 11 tests taken during the semester ratio.

If the ratio of quizzes to tests is 6:1, then the total number of parts in the ratio is 6+1 = 7.

Let x be the number of parts that represent quizzes, and y be the number of parts that represent tests. Then we have:

x + y = 7 (because there are 7 total parts in the ratio)

x/y = 6/1 (because the ratio of quizzes to tests is 6:1)

Simplifying the second equation, we get:

x = 6y

Substituting this into the first equation, we get:

6y + y = 7

7y = 7

y = 1

So the number of parts that represent tests is 1, and the number of parts that represent quizzes is 6. Therefore, if there are 77 grades taken during the semester, then there is 1/7 of the grades taken for each part of the ratio.

The number of grades for tests is:

1/7 × 77 = 11

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Marshall is wondering whether he can participate in the LLP again next year. The statement that is true is "He can participate in the LLP again, but only to the extent that his existing LLP balance is less than $20,000.

The Lifelong Learning Plan is a program that helps Canadian residents finance their post-secondary education through their registered retirement savings plans (RRSP). If an individual is attending school full-time, they can withdraw up to $10,000 a year from their RRSP under the program, or up to $20,000 in total. There are certain rules that must be followed by an individual participating in the LLP. For example, withdrawals must be made within four years of enrolling in an eligible educational program, and repayments must begin within the same period.

Here are the statements: Provided he repays his LLP balance in full by the end of this year, Marshall can participate in the LLP again next year.Marshall can only participate in the LLP once over his lifetime. However, his wife can make a LLP withdrawal from her RRSP on his behalf. He can participate in the LLP again, but only to the extent that his existing LLP balance is less than $20,000. He can only participate in the LLP a second time if he repays his LLP balance in full and waits 5 years before he returns to school.The correct statement is: He can participate in the LLP again, but only to the extent that his existing LLP balance is less than $20,000.

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Answer:

the mean is 3

Pls mark Brainliest :)

Step-by-step explanation:

\(~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$ 30000\\ P=\textit{original amount deposited}\dotfill & \$20000\\ r=rate\to 9\%\to \frac{9}{100}\dotfill &0.09\\ t=years \end{cases} \\\\\\ 30000 = 20000[1+(0.09)(t)] \implies \cfrac{30000}{20000}=1+0.09t\implies \cfrac{3}{2}=1+0.09t \\\\\\ \cfrac{3}{2}-1=0.09t\implies \cfrac{1}{2}=0.09t\implies \cfrac{1}{2(0.09)}=t\implies 5.6\approx t\)

The range is the weight of her identical twin sister Kathy is 119 < x < 137 i.e [ 119, 137 ].

In mathematics, inequality is a relationship between two expression or values which are not equal to each other. The symbols include in inequality are "<" , "≤" , ">" , "≥" , "≠".

We have, Research shows that difference in weight of identical twins.

Weight of Kim = 127 pounds

The difference in weight of twins is less than 6 pounds . Let the weight of Kim's sister Kathy be "x pounds". Now, the inequality of difference in their weights,

either x - 127 < 6 or 127 - x < 6

=> either x < 6+ 127 or -x < 6 - 127

=> either x< 133 or -x < - 119

=> either x < 137 or x > 119

So, range of weight of her sister Kathy is 119 < x < 137.

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The most specific name for the figure is an isosceles trapezoid

From the question, we have the following parameters that can be used in our computation:

The figure

The properties of the given figure are

Using the above as a guide, we have the following:

The figure is a trapezoid

Because the nonparallel sides are congruent, then the most specific name for the figure is an isosceles trapezoid

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after 14 years, there will be approximately 1.97g of the radioactive substance remaining.

To solve this problem, we can use the concept of exponential decay for radioactive substances. The decay of a radioactive substance can be modeled by the equation:

N(t) = N₀ * e^(-kt),

where N(t) is the amount of substance at time t, N₀ is the initial amount of substance, e is the base of the natural logarithm, k is the decay constant, and t is the time elapsed.

In this case, we are given that the initial amount N₀ is 10g and the amount after 9 years N(9) is 5g. We can use this information to find the value of k.

5 = 10 * e^(-9k).

Divide both sides of the equation by 10:

0.5 = e^(-9k).

Take the natural logarithm of both sides:

ln(0.5) = -9k.

Solve for k:

k = ln(0.5) / -9.

Now that we have the value of k, we can use it to find the amount of substance after 14 years, N(14):

N(14) = N₀ * e^(-kt).

N(14) = 10 * e^(-ln(0.5) / -9 * 14).

N(14) = 10 * e^(14 * ln(0.5) / 9).

N(14) ≈ 10 * 0.197 = 1.97.

Therefore, after 14 years, there will be approximately 1.97g of the radioactive substance remaining.

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The volume of the given triangular prism is 315 cm³.

The volume of a triangular prism, we need to multiply the base area of the triangular base by the height of the prism.

The triangular base has a base length of 5 cm and a height of 7 cm, and the height of the prism is 9 cm.

Calculate the area of the triangular base.

The area of a triangle can be calculated using the formula:

Area = (base length × height) / 2

Plugging in the values, we have:

Area = (5 cm × 7 cm) / 2

Area = 35 cm²

Calculate the volume of the prism.

The volume of a prism can be calculated by multiplying the base area by the height of the prism.

Volume = Base area × Height

Volume = 35 cm² × 9 cm

Volume = 315 cm³

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Answer:

25

Step-by-step explanation:

130+25+25=180

..........

.....

Answer:

50 is your answer.

Step-by-step explanation:

=180 - 130 ( a triangle have only 180 degree )

= 50

The correct expression representing the value stored in the variable x after executing the given program is: a. 2*3*3*3 This is because the program starts with x having a value of 2 and then multiplies x by 3 four times in a row.

The expression that represents the value stored in the variable x as a result of executing the program is option D: 24*4*4*4. This is because the program starts with the x being assigned the value 2, and then the instruction "XX * 3" is executed 4 times.

This means that the value of x is multiplied by 3, four times in a row. So, the final value of x will be 2 * 3 * 3 * 3 * 3, which simplifies to 24 * 4 * 4 * 4.

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y₁ =  [1  -4  0  1] and y₂ = [5  1  -6  -1] is the orthogonal basis for w using Gram-Schmidt process.

Given,

The set;

x₁ = [1  -4  0  1]

x₂ = [7  -7  -6  1]

We have to produce the orthogonal basis for w using the Gram-Schmidt process;

Here,

y₁ = x₁ =  [1  -4  0  1]

Now,

Solve for y₂

y₂ = x₂ - [x₂y₁ / y₁y₁] y₁

That is,

y₂ = [7  -7  -6  1] - ( [7  -7  -6  1] [1  -4  0  1] / [1  -4  0  1] [1  -4  0  1] ) × [1  -4  0  1]

y₂ =  [7  -7  -6  1] - (7 + 28 - 0 + 1) / (1 + 16 + 0 + 1) × [1  -4  0  1]

y₂ = [7  -7  -6  1]  - 36/18 × [1  -4  0  1]

y₂ =  [7  -7  -6  1] - 2  × [1  -4  0  1]

y₂ =  [7  -7  -6  1] - [2  8  0  2]

y₂ = [5  1  -6  -1]

That is,

The orthogonal basis for w using Gram-Schmidt process is,

y₁ =  [1  -4  0  1] and y₂ = [5  1  -6  -1]

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