what is 20 sqare in math please tell us

Examples of substantive procedures, which are used in auditing, include observation, inquiry, confirmation, and more.

Substantive procedures are specific audit procedures performed to gather evidence and assess the reasonableness of financial statement assertions. These procedures aim to obtain substantive evidence about the accuracy, completeness, and validity of the financial information.

Examples of substantive procedures include observation, where auditors directly witness a process or activity, such as counting physical inventory. Inquiry involves seeking information from management or other personnel regarding financial transactions or events. Confirmation refers to the direct communication with third parties, such as banks or customers, to verify the accuracy of reported balances or transactions.

Other examples of substantive procedures include analytical procedures, inspection of records and documents, and reperformance of calculations or controls. Therefore, all answer choices (A. observation, B. inquiry, C. All of these answer choices are correct, and D. confirmation) are valid examples of substantive procedures in auditing.

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\((36911.22/500) = 12x ln(1 + r)ln(36911.22/500) = 12x(0.0083333333)ln(36911.22/500) = 0\).0083333333x

Multiply both sides by 1000 and divide both sides by 0.0083333333 to get: x = 35.

Let x be the age of the person. When the person was born, their parents opened an investment account in their name and deposited $500 into the account.

Let A be the value of the investment account when the person is x years old.

The interest rate is 10% compounded monthly. Then, the monthly interest rate is

\(:r = (10/12)/100 = 0.0083333333\)

The account has earned interest for 12 * x months.

Hence, we have:

\(A = 500(1 + r)^(12x)\)

Now, we can solve for x.

A = 36911.22.

Hence:\(36911.22 = 500(1 + r)^(12x)\)

Take the natural logarithm of both sides to solve for x.

\(ln(36911.22/500) = 12x ln(1 + r)ln(36911.22/500) = 12x(0.0083333333)ln(36911.22/500) = 0.0083333333x\)

Multiply both sides by 1000 and divide both sides by 0.0083333333 to get: x = 35.

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In the word problem, if mike has 40 coins consisting of dimes and quarters and if the dimes were quarters and the quarters dimes, he would have 90 cents more, he has 17 quarters.

A word problem refers to a mathematical exercise where significant information on the problem is given in ordinary language and not mathematical notation.  Let x be the number of dimes (10 cents) and y be the number of quarters (25 cents). Hence, the total number of coins is:

x + y = 40

The amount of the total coins would be 0.1x + 0.25y.

If the dimes were quarters and quarters were dimes, he would have 90 cents more than the amount he has now.

Hence,

0.25x + 0.10y = 0.1x + 0.25y + 0.9

Solving,

0.25x – 0.1x = 0.25y – 0.1y +0.9

0.15x = 0.15y + 0.9

As x + y = 40, x = 40 – y

Substituting,

0.15 (40 – y) = 0.15y + 0.9

6 - 0.15 y = 0.15y + 0.9

0.15y + 0.15y = 6 – 0.9

0.3y = 5.1

y = 5.1/0.3 = 17

Hence, the number of quarters are 17.

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By using the triangular inequality, we conclude that the length of the last side is on the interval.

1.9 < x < 13.5

Remember that for a triangle with sides x, y, and z, the triangular inequality says that:

x + y > z

x + z > y

z + y > x

Here we know that two sides measure 5.8 and 7.7, then the last one will measure x, we will get:

x + 5.8 > 7.7

x + 7.7 > 5.8

5.8 + 7.7 > x

With the last inequality we get that:

13.5 > x

And the first one says that:

x > 7.7 - 5.8

x > 1.9

Then the possible values of x are:

1.9 < x < 13.5

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Answer:

13857552359

Step-by-step explanation:

13857552359.3

3 is less than 5, so round down to 13857552359

Answer:

what is given: 13857552359.3

Ones: 13857552359

Tens: 13857552360

Hundreds: 13857552400

Thousands: 13857552000

Millions: 13858000000

Hint: Each of the numbers are different

P.S I put all of them because you didnt say which whole number you wanted

Hope this helped!

Answer:

see explanation

Step-by-step explanation:

If the ratios of the 3 pairs of corresponding sides of the 2 triangles are equal , then the triangles are similar (SSS postulate )

the3 ratios of the 2 triangles , left to right are all equal to

\(\frac{3}{4}\)

Then the triangles are similar by the SSS postulate

the corresponding angles of similar triangles are congruent, then

∠ c = 60°

Also both triangles have 3 congruent sides and are therefore equilateral triangles with all angles equal to 60°, so

c = 60°

Answer:

Area of the parallelogram = 107,555 square feet

Step-by-step explanation:

Let

h = height of the parallelogram

sin (112°) = h/200 feet

h = sin(112°) × 200

h = 0.927184 × 200

= 185.4368 feet

h = 185.44 feet

Area of the parallelogram = base × height

= 580 feet × 185.44 feet

= 107,555.2 square feet

To the nearest square root = 107,555 square feet

Area of the parallelogram = 107,555 square feet

Answer:

The answer is 24.

Step-by-step explanation:

The answer is the original number and then you divide it in half and then add the half   Hope it helps and stay healthy!

The required answer to the subtraction problem 83,456 - 728.88 is, 82,727.12

Subtraction is mathematical terminology that helps and elaborates the decrease in the original value by some value.

Here,
To perform the subtraction, you line up the decimal points and subtract the digits in each place value starting from the right. In this case, you subtract 8 from 6, which requires borrowing 1 from the digit to the left, giving you 16 - 8 = 8 in the one's place. You then subtract 2 from 5, giving you 3 in the tenth place. Continuing this process, you get the result of 82,727.12.

Thus, the answer to the subtraction problem 83,456 - 728.88 is, 82,727.12

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Answer:

2

Step-by-step explanation:

j(-1)=4(-1)^2 -(-1) -3 = 4+1-3 =5-3 =2

Answer: D. SSS

Step-by-step explanation:

The solution would be SSS because the image shows that AB is congruent to DE, BC is congruent to EF, and AC is congruent to DF. Because the image shows that all three sides are congruent to their corresponding side on the other triangle, with no mention of angles, the triangles are congreunt through the SSS theorem.

Answer: There will be approximately 2202646.66 organisms after 10 days.

Step-by-step explanation:

Since at the beginning of the experiment there were 100 organisms and after 2 days there were 200 organisms, we know that the population of the organism increased by a factor of 2 over this time period. This means that k, the exponential growth rate, can be calculated as follows:

k = log(200 / 100) / log(2)

= log(2) / log(2)

= 1

We can now use the formula p(t) = aekt to calculate the number of organisms after 10 days. Since k is equal to 1, we can simplify the formula to p(t) = ae^t:

p(10) = ae^10

We know that at the beginning of the experiment, the number of organisms was 100, so we can set p(0) = 100 and solve for a:

p(0) = 100 = ae^0

a = 100

We can now use this value of a to calculate the number of organisms after 10 days:

p(10) = 100e^10

= 100 * 22026.465795

= 2202646.65795

\(\\ \rm\Rrightarrow \dfrac{(11^6.6^9)^2}{11^3}\)

\(\\ \rm\Rrightarrow \dfrac{11^{6(2)}.6^{9(2)}}{11^3}\)

\(\\ \rm\Rrightarrow \dfrac{11^{12}.6^{18}}{11^3}\)

\(\\ \rm\Rrightarrow \dfrac{11^{12-3}6^{18}}{}\)

\(\\ \rm\Rrightarrow 11^96^{18}\)

Answer:

B

Step-by-step explanation:

\(\sf Given \: expression\: :\dfrac{(11^6 \cdot 6^9)^2}{11^3}\)

\(\sf Apply\:exponent\:rule\quad (a^b)^c=a^{bc} :\)

\(\sf \implies \dfrac{11^{6 \times 2} \cdot 6^{9\times2}}{11^3}\)

\(\sf \implies \dfrac{11^{12} \cdot 6^{18}}{11^3}\)

\(\sf \implies \dfrac{11^{12}}{11^3} \cdot 6^{18}\)

\(\sf Apply\:exponent\:rule\quad \dfrac{a^b}{a^c}=a^{b-c} :\)

\(\sf \implies 11^{12-3} \cdot 6^{18}\)

\(\sf \implies 11^{9} \cdot 6^{18}\)

Enzo's net worth = Enzo's assets - Enzo's liabilities. The resulting number is his net worth.

Enzo's net worth = (Enzo's cash + Enzo's investments + Enzo's property + Enzo's other assets) - (Enzo's loans + Enzo's credit card debt + Enzo's other liabilities)

Enzo's net worth is calculated by subtracting his liabilities from his assets. Enzo's assets include cash, investments, property and other assets he may own. His liabilities include any loans he has taken out, any credit card debt, and any other liabilities he may have. To find Enzo's net worth, you would add up all of his assets and subtract from that all of his liabilities. The resulting number is his net worth.

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Answer:

360

Step-by-step explanation:

hope this helps.

The correct answers are:

a. The null and alternative hypotheses are:

A. H0: μd ≠ 0, The null hypothesis states that there is no difference in the average test score before and after the review course.

B. H1: μd > 0, The alternative hypothesis states that the average test score is higher after the review course compared to before.

b. To calculate the appropriate test statistic, we can use the paired t-test for matched pairs. The formula for the test statistic is:

t = (mean of the differences - hypothesized mean) / (standard deviation of the differences / √n)

Interpretation:

The critical value(s) depend on the degrees of freedom and the chosen significance level (α). Since the degrees of freedom in this case are n - 1 = 9 - 1 = 8, you would need to consult the t-distribution table or use statistical software to find the critical value(s) for α = 0.01.

To interpret the results of the hypothesis test, you compare the calculated test statistic to the critical value(s). If the test statistic is greater than the critical value(s), you reject the null hypothesis. If the test statistic is less than the critical value(s), you fail to reject the null hypothesis.

c. The p-value is the probability of observing a test statistic as extreme as the one calculated, assuming the null hypothesis is true. To find the p-value, you would need to consult the t-distribution table or use statistical software.

Interpretation:

If the p-value is less than the chosen significance level (α = 0.01), you reject the null hypothesis. If the p-value is greater than or equal to the significance level, you fail to reject the null hypothesis.

d. The assumptions that need to be made in order to perform this procedure are:

A. The samples are dependent (matched pairs).

B. The differences between the measurements are normally distributed.

C. The matched-pair differences have a constant variance.

D. The matched-pair differences are randomly and independently selected from the population.

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Answer:

You can form a proportion to solve this problem.

Step-by-step explanation:

The proportion can look like this (there are other ways to write an equal proportion but this is just one of the ways you could go about it :)

\(\frac{2.25}{12}\)=\(\frac{x}{32}\)

12x=72

x=6 cups of flour

Hope this helps!! :)

Answer:

You can form a proportion to solve this problem.

Step-by-step explanation:

The proportion can look like this (there are other ways to write an equal proportion but this is just one of the ways you could go about it :)

=

12x=72

x=6 cups of flour

Answer:

50%

Step-by-step explanation:

its half of a whole making it 50 percent

Answer:

50%

Step-by-step explanation:

as a fraction it is 1/2

Answer

(24,9.5) using the midpoint formula

Answer:

(12, 9.5)

Step-by-step explanation:

The solution of expression is,

⇒ 2 (x - 3) / (x + 1)

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The expression is,

⇒ (x² - 6x + 9) / (2x³ + 5x) ÷ (x² - 2x - 3) / (4x² + 10)

Now, We can simplify the expression as;

⇒ (x² - 6x + 9) / (2x³ + 5x) ÷ (x² - 2x - 3) / (4x² + 10)

⇒ (x² - 6x + 9) / (2x³ + 5x) × (4x² + 10) / (x² - 2x - 3)\

⇒  (x² - 6x + 9) × 2 (2x² + 5) / x (2x²+ 5) (x² - 2x - 3)

⇒  2 (x² - 6x + 9) / (x² - (3 - 1)x - 3)

⇒ 2 (x² - (3 + 3)x + 9) / (x² - 3x + 1x - 3)

⇒ 2 (x² - 3x - 3x + 9) / (x (x - 3) + 1(x - 3)

⇒ 2 (x (x - 3) - 3 (x - 3) ) / (x - 3) (x + 1)

⇒ 2 (x - 3)² / (x - 3) (x + 1)

⇒ 2 (x - 3) / (x + 1)

Thus, The solution of expression is,

⇒ 2 (x - 3) / (x + 1)

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Answer:

9

Step-by-step explanation:

cuz yes

Answer:

D.200.9 FT

Step-by-step explanation:

SHADOW: 46 = 110

Building:   /84.  /x

110*84=9240

9240/46= 200.86

rounded: 200.9

I do my math different, so sorry if it's confusing

Answer: 200.9

Step-by-step explanation: Im not 100 sure I just divided 200.9/110 like 84/46

Given phrase as numerical expression: 114 < -49

and the numerical expression is mathematically incorrect.

In this question, we have been given a phrase.

We need to write a numerical expression for the phrase and simplify.

Given phrase is: '114 less than -49'

We can write this in mathematical expression form as,

114 < -49

Now add 49 to both the sides.

114 +49 < -49 + 49

163 < 0

which is False.

Therefore, given phrase as numerical expression: 114 < -49

and the numerical expression is mathematically incorrect.

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Derek will need approximately $15,631,115.49 in his retirement account on his 65th birthday.

Let A be the amount Derek needs to have in his retirement account on his 65th birthday.Assuming the interest rate of 10%, A will grow to A * 1.1 dollars on his 66th birthday.

On his 66th birthday, Derek will withdraw $161,349.00 and the amount remaining in his account will grow to (A - 161,349.00) * 1.1 dollars. This will be his new amount, which will grow to (A - 161,349.00) * 1.1^2 dollars on his 67th birthday.

Derek will continue this pattern until his 89th birthday. At this point, the amount remaining in his account will be exactly zero since he will have withdrawn all of his money on his 89th birthday.

We can therefore set up the following equation to solve for A:

A * 1.1^21 + (A - 161,349.00) * 1.1^20 + (A - 161,349.00 * 2) * 1.1^19 + ... + (A - 161,349.00 * 23) * 1.1 = 0

Simplifying this equation by factoring out A and solving for it yields:

A * (1.1^21 + 1.1^20 + 1.1^19 + ... + 1.1 - 23) = 161,349.00 * (1 + 1.1 + 1.1^2 + ... + 1.1^23)

A = (161,349.00 * (1 + 1.1 + 1.1^2 + ... + 1.1^23)) / (1.1^21 + 1.1^20 + 1.1^19 + ... + 1.1 - 23)

A ≈ $15,631,115.49

Therefore, Derek will need approximately $15,631,115.49 in his retirement account on his 65th birthday.

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Possible causal reasons for the correlation between time spent playing video games and aggression are:

1. Video games cause aggression: This suggests that playing violent video games leads to aggressive behavior. To study this causal hypothesis, one possible approach would be to randomly assign participants to play either a violent or non-violent video game for a certain amount of time and then measure their level of aggression using a standardized aggression scale. This could be repeated with different samples to increase the reliability of the results.

2. Aggressive individuals seek out violent video games: This suggests that individuals who are already predisposed to aggression are more likely to choose to play violent video games. To test this hypothesis, researchers could administer an aggression scale to participants before asking them to report how often they play video games, and what types of games they prefer. The correlation between aggression scores and the amount of time spent playing violent video games would then be calculated.

3. A third variable is responsible for the relationship: This suggests that there is a third variable that causes both increased video game play and aggression. For example, this third variable could be stress levels, which may increase the likelihood of both playing video games and displaying aggressive behavior. To study this hypothesis, researchers could measure stress levels in participants and then ask them to report how often they play video games and their level of aggression. The correlation between stress levels and both video game play and aggression could then be calculated.

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Answer:

sum of five and 3 is divided by n

Answer:

Step-by-step explanation:

(a) To find the probability that it is raining when you arrive in Oneirabad on a random day, we need to use the law of total probability.

Let A be the event that it is raining, and B be the event that it is the Wet season.

P(A) = P(A|B)P(B) + P(A|B')P(B')

Given that the Wet season lasts for 1/3 of the year, we have P(B) = 1/3. The probability that it is raining during the Wet season is 3/4, so P(A|B) = 3/4.

The Dry season lasts for 2/3 of the year, so P(B') = 2/3. The probability that it is raining during the Dry season is 1/6, so P(A|B') = 1/6.

Now we can calculate the probability that it is raining when you arrive:

P(A) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it is raining when you arrive in Oneirabad on a random day is 13/36.

(b) Given that it is raining when you arrive, we can use Bayes' theorem to calculate the probability that your visit is during the Wet season.

Let C be the event that your visit is during the Wet season.

P(C|A) = (P(A|C)P(C)) / P(A)

We already know that P(A) = 13/36. The probability that it is raining during the Wet season is 3/4, so P(A|C) = 3/4. The Wet season lasts for 1/3 of the year, so P(C) = 1/3.

Now we can calculate the probability that your visit is during the Wet season:

P(C|A) = (3/4)(1/3) / (13/36)

= 1/4 / (13/36)

= 9/52

Therefore, given that it is raining when you arrive, the probability that your visit is during the Wet season is 9/52.

(c) Given that it is raining when you arrive, the probability that it will be raining when you return to Oneirabad in a year's time depends on the season. If you arrived during the Wet season, the probability of rain will be different from if you arrived during the Dry season.

Let D be the event that it is raining when you return.

If you arrived during the Wet season, the probability of rain when you return is the same as the probability of rain during the Wet season, which is 3/4.

If you arrived during the Dry season, the probability of rain when you return is the same as the probability of rain during the Dry season, which is 1/6.

Since the season you arrived in is independent of the weather when you return, we need to consider the probabilities based on the season you arrived.

Let C' be the event that your visit is during the Dry season.

P(D) = P(D|C)P(C) + P(D|C')P(C')

Since P(C) = 1/3 and P(C') = 2/3, we can calculate:

P(D) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it will be raining when you return to Oneirabad in a year's time, given that it is raining when you arrive, is 13/36.

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Answer:

The area would be 80