What is 1 1/7 x 3/5 pleaseeeeeeeee help

Answer:

Area= 706.86 cm²

Circumference= 94.35 cm

Diameter= 30 cm

\(\large\huge\green{\sf{Given:-}}\)

\(\large\huge\green{\sf{ToFind:-}}\)

\(\large\huge\green{\sf{FormulaRequired:-}}\)

\(\large\huge\green{\sf{solution:-}}\)

Area of pizza= πr²

= 3.14 x (15)²

= 3.14x 225

= 706.5

= 706cm²(approx)

for finding diameter ,

___________________

i hope it will be helpful:)

The composite function that can be used to calculate the final price of Jonah's car is f[c(p)] = 0. 9265p.

A composite function is a function that is in another function, such that on solving the composite function the result is the same as the function solve individually.

We know that the sale price of Jonah's car is c(p) = 0. 85p, where p is the original price of the car. Also, the tax on the car is 9% of the sale price, and the final price of the car is f(c) = 1. 09c, including tax, therefore, the composite function can be written as,

\(f(c) = 1.09 c\)

We already know the value of c, therefore,

\(f(c(p)) = 1.09 (0.85p)\\\\f(c(p)) = 10.9265(p)\)

Hence, the composite function that can be used to calculate the final price of Jonah's car is f[c(p)] = 0. 9265p.

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An example of a complex number in standard form is (5 + 4i), where i is the imaginary unit.

example to solve (x + 5i)(2x - 3i):

Step 1: Multiply the real numbers together:

x × 2x = 2x²

Step 2: Multiply the imaginary numbers together:

5i × -3i = -15i²

Step 3: Multiply the real and imaginary parts together:

x × -3i = -3ix and 2x × 5i = 10xi

Step 4: Add all the terms together:

2x² - 15i² + -3ix + 10xi = 2x² - 15i² - 3ix + 10xi

Step 5: Simplify the terms:

2x² - 15i² - 3ix + 10xi = 2x² - 18ix - 15i²

The product of two complex numbers (x + 5i)(2x - 3i) can be found by multiplying the real numbers together, the imaginary numbers together, and the real and imaginary parts together, then adding all of the terms together and simplifying.

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Answer:

A)  

\(\begin{array}{|c|c|c|}\cline{1-3} t & H(t) & g(t)\\\cline{1-3} 1 & 60 & 20.4\\\cline{1-3} 2 & 76 & 30.8\\\cline{1-3} 3 & 60 & 41.2\\\cline{1-3} 4 & 12 & 51.6\\\cline{1-3} \end{array}\)

Between 3 and 4 seconds.

B)  The baseballs will collide between 3 and 4 seconds.

Step-by-step explanation:

Given functions:

\(H(t)=-16t^2+64t+12\)

\(g(t)=10+10.4t\)

Substitute the values of t = 1, 2, 3 and 4 into the two functions:

\(H(1)=-16(1)^2+64(1)+12=60\)

\(H(2)=-16(2)^2+64(2)+12=76\)

\(H(3)=-16(3)^2+64(3)+12=60\)

\(H(4)=-16(4)^2+64(4)+12=12\)

\(g(1)=10+10.4(1)=20.4\)

\(g(2)=10+10.4(2)=30.8\)

\(g(3)=10+10.4(3)=41.2\)

\(g(4)=10+10.4(4)=51.6\)

Create a table with the found values:

\(\begin{array}{|c|c|c|}\cline{1-3} t & H(t) & g(t)\\\cline{1-3} 1 & 60 & 20.4\\\cline{1-3} 2 & 76 & 30.8\\\cline{1-3} 3 & 60 & 41.2\\\cline{1-3} 4 & 12 & 51.6\\\cline{1-3} \end{array}\)

The solution to H(t) = g(t) is between 3 and 4 seconds as:

When t = 3, H(t) > g(t)

When t = 4, H(t) < g(t)

To prove this, equate the equations and solve for t:

\(\implies -16t^2+64t+12=10+10.4t\)

\(\implies -16t^2+53.6t+2=0\)

Using the Quadratic Formula to solve for t:

\(x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0\)

\(\implies t=\dfrac{-53.6 \pm \sqrt{53.6^2-4(-16)(2)} }{2(-16)}\)

\(\implies t=\dfrac{53.6 \pm \sqrt{3000.96}}{32}\)

\(\implies t=3.39, -0.04\:\:(\sf 2\:d.p.)\)

As time is positive, t = 3.39 s (which is between 3 and 4 seconds).

When the two baseballs are at the same height they will collide.

Therefore, the baseballs will collide between 3 and 4 seconds (when t = 3.39 s).

Answer:

correct

Step-by-step explanation:

Answer:

hello

Step-by-step explanation:

İ from Turkish

thanks :)

My name is Elfida

Answer:

This is your answer.

Step-by-step explanation:

There are different kinds of angles:

Angles below 90= Acute

90= Right

91–179= Obtuse

180= Straight Angle

181–359= Reflex Angle

360= Complete Angle or Circle.

Because 80 degrees is less than 90 degrees, Angle ABC is an acute angle.

Answer:

x = -4

Step-by-step explanation:

Step 1: Write equation

-5x - 10 = 10

Step 2: Solve for x

Step 3: Check

Plug in x to verify it's a solution.

-5(-4) - 10 = 10

20 - 10 = 10

10 = 10

Answer:

35% of the chocolate made is dark

The flux of the vector field F = < -y, x, 1> across the cylinder y = 5x2, for 0 ≤ x ≤ 4, 0 ≤ z ≤ 2 is  -8537/6 + 1/20.

To find the flux of the vector field F = < -y, x, 1> across the cylinder y = 5x^2, for 0 ≤ x ≤ 4, 0 ≤ z ≤ 2, we will use the flux integral formula:

Φ = ∫∫S F · dS,

where S is the surface of the cylinder, F is the given vector field, dS is the differential surface element, and · represents the dot product.

To find the normal vector to the surface S, we can take the gradient of the equation y = 5x^2:

grad(y) = <∂y/∂x, ∂y/∂y, ∂y/∂z> = <10x, 1, 0>.

Since the normal vectors point in the general direction of the positive y-axis, we can take the negative of the gradient:

n = -<10x, 1, 0>.

Now, we can parameterize the surface of the cylinder as follows:

r(x,z) = <x, 5x^2, z>.

To find the differential surface element dS, we can take the cross product of the partial derivatives of r with respect to x and z:

dr/dx = <1, 10x, 0>
dr/dz = <0, 0, 1>
dS = ||dr/dx x dr/dz|| dxdz
= ||<10x, 0, 1>|| dxdz
= √(100x^2 + 1) dxdz.

Now, we can evaluate the flux integral:

Φ = ∫∫S F · dS
= ∫0^2 ∫0^4 < -y, x, 1> · n √(100x^2 + 1) dxdz (note that y = 5x^2)
= ∫0^2 ∫0^4 <-5x^2, x, 1> · <10x, 1, 0> √(100x^2 + 1) dxdz
= ∫0^2 ∫0^4 (-50x^3 + x) √(100x^2 + 1) dxdz.

To evaluate this integral, we can use the substitution u = 100x^2 + 1, du/dx = 200x, dx = du/(2x), and the limits of integration become u(0,1) and u(400,1601). Therefore, we have:

Φ = ∫0^2 ∫0^4 (-50x^3 + x) √(100x^2 + 1) dxdz
= ∫1^1601 (-50(u-1)/200 + (u-1)/20) √u du/(2x) dz
= ∫1^1601 (-25/2 sqrt(u) + 1/20 sqrt(u)) du
= [-25/3 u^(3/2) + 1/20 u^(3/2)] evaluated from 1 to 1601
= (-25/3 (1601)^(3/2) + 1/20 (1601)^(3/2)) - (-25/3 (1)^(3/2) + 1/20 (1)^(3/2))
= -8537/6 + 1/20.

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A nonlinear programming model differs from a linear programming model in several ways. One key difference is that nonlinear models have nonproportional relationships between activity levels and the overall measure of performance.

Additionally, nonlinear models may have multiple optimal solutions, while linear models typically only have one optimal solution. Nonlinear models may also have discontinuous objective functions or constraints, while linear models have continuous objective functions and constraints.

Nonlinear programming models are used when the relationship between variables is not linear. In a linear programming model, the objective function and constraints are linear, meaning that they have a constant rate of change.

However, in a nonlinear programming model, the objective function and constraints may have nonlinear relationships, which means that they do not have a constant rate of change. This can make it more difficult to optimize the model, as it may have multiple optimal solutions or discontinuous regions. Nonlinear programming models may use techniques such as gradient descent or Newton's method to find the optimal solution, while linear programming models typically use the simplex method. Overall, nonlinear programming models are more complex than linear programming models and require more advanced mathematical techniques to solve.

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Answer: 93

Step-by-step explanation:

75+105+127= 307

307-250= 57

150-57= 93 (57 + 93 = 150)

Answer:

what are you asking?

Step-by-step explanation:

Step-by-step explanation:

5⁰= 1

2–3 means 1/2³

1/8

=0.125

There are 544,320 7-digit numbers that are all unique and arranged in increasing order.

We apply the Fundamental Counting Principle to this issue. You are aware that a number has seven digits. According to this theory, you must multiply the potential integers for each digit. There are 9 potential numbers if the initial number can't be zero. Consequently, the first digit's value is 9. Any number, but less than 1, could be used for the second digit since it was already used in the first. Thus, 10 – 1 would equal 9. The value in the third digit must be less than 1 and in the second digit. In this case, 9 – 1 Equals 8. And the list goes on.

Therefore, the number of seven-digit numbers in which all digits are different and in increasing order is:

9 × 9 × 8 × 7 × 6 × 5 × 4 = 544,320

Hence, there are 544,320 7-digit numbers with all different digits in increasing order.

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Therefore, there are 53,248 different super subs that can be made if there are 8 toppings, 6 condiments, and 6 types of homemade bread to choose from at Sandwich Station.

The super sub at Sandwich Station consists of 4 different toppings and 3 different condiments. The question is asking how many different super subs can be made if there are 8 toppings, 6 condiments, and 6 types of homemade bread to choose from.

To solve this problem, we can use the multiplication principle of counting. The multiplication principle states that if there are m ways to do one thing and n ways to do another thing, then there are m x n ways to do both things.

Let's use the multiplication principle to solve this problem. There are four different toppings, and we can choose any of the eight toppings for each of the four spots.

Using the multiplication principle, there are

8 x 8 x 8 x 8 = 4096

ways to choose the toppings. Similarly, there are

6 x 6 x 6 = 216

ways to choose the condiments. Lastly, there are 6 different types of homemade bread to choose from. Using the multiplication principle again, there are

4096 x 216 x 6 = 53,248,

which means there are 53,248 ways to make the super subs.

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To find the 6th term of the geometric sequence, we first need to determine the common ratio (r) of the sequence. We can do this by using the formula for the nth term of a geometric sequence:

an = a1 * r^(n-1)

We know that a1 = -4,096 and a4 = 64, so we can substitute these values into the formula to get:

a4 = a1 * r^(4-1)

64 = -4,096 * r^3

Dividing both sides by -4,096 gives:

r^3 = -64/4096

r^3 = -1/64

Taking the cube root of both sides gives:

r = -1/4

Now that we know the common ratio is -1/4, we can use the formula for the nth term of a geometric sequence to find the 6th term:

a6 = a1 * r^(6-1)

a6 = -4,096 * (-1/4)^5

a6 = -4,096 * (-1/1024)

a6 = 4

Therefore, the 6th term of the geometric sequence is 4, so the answer is (b) 4.

To find the 6th term of the geometric sequence, we first need to determine the common ratio (r) of the sequence.

The 6th term of the geometric sequence where a1 = −4,096 and a4 = 64 is d. -4.

Given, a1 = -4096, a4 = 64We know that, the nth term of a geometric progression with first term a and common ratio r is given by an = ar^(n-1)Let's find the common ratio of the sequence.a4 = ar^3⟹64

= -4096r^3⟹r^3 = -\(\frac{64}{4096}\) = -\(\frac{1}{64}\)Thus, r = -\(\frac{1}{4}\)

The 6th term of the geometric sequence with first term a1 = -4096 and common ratio r = -\(\frac{1}{4}\) is given by;a6 = a1 * r^5Substituting the values of a1 and r, we get;a6 = -4096 * (-\(\frac{1}{4}\))^5⟹a6 = -4096 * \(\frac{1}{1024}\)⟹a6 = -4

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The reasoning provided, "If you build it, they will come. You build it. Therefore, they will come," is an example of deductive reasoning.

Deductive reasoning is a logical process that involves drawing specific conclusions based on general principles, premises, or known facts. In this example, the premise is "If you build it, they will come," which establishes a cause-and-effect relationship. The subsequent statement, "You build it," serves as a confirmation of the premise. From these premises, the conclusion is drawn: "Therefore, they will come." The conclusion logically follows from the premises, making it an example of deductive reasoning.

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Creating a system of equations, the cost of a notebook (n) will be: $1.25

n = note books.

b = binders.

Create a system of equation and solve for the variables.

Equation for school supplies bought by Bartholomew:

Equation for school supplies bought by Maurice:

40n + 48b = 251.6 --> Eqn. 1

24n + 48b = 231.6 --> Eqn. 2

16n = 20

n = 1.25

Therefore, creating a system of equations, the cost of a notebook (n) will be: $1.25

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Answer:

\(y=5x+10\)

Step-by-step explanation:

1) Plug numbers into slope formula to find \(b\).

\(y=mx+b\)

\(-5=5(-3)+b\)

2) Simplify to find \(b\).

\(-5=-15+b\)

\(10=b\)

3) Check work.

\(-5=-15+10\)

This statement is true.

4) Write equation.

\(y=5x+10\)

Answer:

I believe the answer is B

Answer: the answer is B—>165.89

Try all numbers 9-13 ( including 9 and 13 ) multiplies by 14.99

When you multiply 11x14.99 it equals 164.89 not 165.89 meaning B is wrong

The best estimate for the owl population is 2,378.

The population of the owl can be estimated using the concept of proportion. Proportion refers to a mathematical comparison between two numbers. According to the concept, if two sets of given numbers are increasing or decreasing in the same ratio, hence the ratios are said to be directly proportional to each other.

Based on the provided information, 29 owls are tagged and released as part of a research project. Assume that the total number of owl populations is x. At the later time, researchers counted 902 owls and found the 11 were tag. Hence, there are 18 tagged owls which are not accounted for. Assuming that the proportional of tagged owls to number of owls counted applies to the remaining population, the total number of owls can be best estimated as:

x = (902/11)*29 = 2,378

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Answer: See below

Step-by-step explanation:

Using a graphing approach:

If the graph is increasing, then the left-sum is an underestimate of the actual value and the right-sum is an overestimate

If the curve is decreasing then the right-sums are underestimates and the left-sums are overestimates

The Answer: Gain — Previous bull markets gained between 74% (1970–1973) and 582% (1987–2000), with an average gain of 185% and a median gain of 132%.

Hope this was helpful to you

Answer:

Step-by-step explanation:

f(x)=-2x³+x-3

-f(x)=2x³-x+3

f(-x)=-2(-x)³+(-x)-3

=2x³-x-3

it is not equal to f(x) or -f(x)

so it is neither even or odd.

\(f(x)=\frac{x+5}{x} \\f(-x)=\frac{-x+5}{-x} =\frac{x-5}{x} \\it ~is~neither~equal~to~f(x)~or~-f(x)\\\)

it is neither even or odd.

f(x)=x^4-x^2+10

f(-x)=(-x)^4-(-x)^2+10=x^4-x^2+10=f(x)

it is an even function.

\(f(x)=\frac{5}{-x^2+1} \\f(-x)=\frac{5}{-(-x)^2+1} =\frac{5}{-x^2+1} =f(x)\\\)

it is an even function.

\(f(x)=\frac{-2}{5x} \\f(-x)=\frac{-2}{-5x} =\frac{2}{5x} =-f(x)\\it~ is ~an ~odd ~function.\\\)

f(x)=x^9-x^5+4x^3

f(-x)=(-x)^9-(-x)^5+4(-x)^3

=-x^9+x^5-4x^3

=-(x^9-x^5+4x^3)

=-f(x)

it is an odd function.

Answer:

(-3,2) i think not sure sorry if its wrong

From the given table it is visible that the value of s(5)=4.2

When the variables and constants in a mathematical expression are given values, the outcome of the computation it describes is the expression's value. The amount that the function assumes for these argument values is the value of a function, given the value(s) assigned to its argument(s).

functions with return values and arguments. Functions with arguments and no return values.... This function takes arguments and returns a value.

functions with return values and no arguments.

without return values and without arguments

Function value can mean: The result of applying a function to an argument in mathematics. a closure in computer science.

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Let R be a relation on set {1, 2, 3, 4} with R = {(1,1), (1,4), (2,3), (3,1), (3,4)}. Find the reflexive, symmetric, and transitive closure of R.

For the given set, Delta = {(1, 1), (2, 2), (3, 3), (4, 4)}. So the reflexive closure of R is R cup Delta = {(1,1), (1,4), (2,2), (2,3), (3,1), (3,3),  (3,4), (4,4)}

For the symmetric closure we need the inverse of R, which is

R^{-1} = {(1,1), (1,3), (3,2), (4,1), (4,3)}.

The symmetric closure of R is-

{(1,1), (1,3), (1,4), (2,3), (3,1), (3,2), (3,4), (4,1), (4,3)}

For the transitive closure, we need to find R^*.

therefore we need to find R^1, R^2, ... , until R^{n} = R^{n-1}. We stop when this condition is achieved since finding higher powers of R would be the same.

R^{1} = {(1,1), (1,4), (2,3), (3,1), (3,4)}

R^{2} = {(1,1), (1,4), (2,1), (2,4), (3,1), (3,4)}

R^{3} = {(1,1), (1,4), (2,1), (2,4), (3,1), (3,4)}

Since, R^{2} = R^{3} we stop the process.

Transitive closure, R^* = R^1 \cup R^2 –

{(1,1), (1,4), (2,1), (2,3), (2,4), (3,1), (3,4)}

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12 dollars is discounted off, making the price 28 dollars.

Step-by-step explanation:

10 percent is 4$, 4×3=12