what is 1 1/3 divided by 3/5

To analyze the survival data provided in Tables 1 and 2, we can calculate the Kaplan-Meier survival estimates and plot the survival curves.

First, let's analyze Table 1:

Years | Number at Risk | Deaths | Survived | Survival Probability

1 | 197 | 1 | 196 | 195/196 = 0.9949

2 | 196 | 3 | 193 | 193/196 = 0.9847

3 | 193 | 6 | 187 | 187/193 = 0.9690

4 | 187 | 1 | 186 | 186/187 = 0.9947

5 | 186 | 3 | 183 | 183/186 = 0.9839

6 | 183 | 0 | 183 | 183/183 = 1.0000

7 | 183 | 3 | 180 | 180/183 = 0.9836

8 | 180 | 1 | 179 | 179/180 = 0.9944

9 | 179 | 0 | 179 | 179/179 = 1.0000

10 | 179 | 0 | 179 | 179/179 = 1.0000

11 | 179 | 1 | 178 | 178/179 = 0.9944

Next, let's analyze Table 2:

Years | Number at Risk | Deaths | Censored | Survived | Survival Probability

1 | 103 | 0 | 5 | 98 | 98/103 = 0.9515

2 | 98 | 7 | 3 | 91 | 91/98 = 0.9286

3 | 91 | 6 | 4 | 85 | 85/91 = 0.9341

4 | 85 | 5 | 6 | 74 | 74/85 = 0.8706

5 | 74 | 0 | 5 | 69 | 69/74 = 0.9324

6 | 69 | 1 | 7 | 61 | 61/69 = 0.8841

7 | 61 | 0 | 5 | 56 | 56/61 = 0.9180

8 | 56 | 5 | 6 | 45 | 45/56 = 0.8036

9 | 45 | 6 | 7 | 32 | 32/45 = 0.7111

10 | 32 | 11 | 17 | 4 | 4/32 = 0.1250

11 | 4 | 0 | 5 | 4 | 4/4 = 1.0000

Now, we can plot the survival curves for both groups (with and without chemotherapy) using the calculated survival probabilities.

(Note: I am unable to generate plots directly in this text-based format. However, you can use software like Excel, R, or Python's Matplotlib to plot the survival curves based on the provided data and survival probabilities.)

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Answer:

Subtract 8 from both sides

Step-by-step explanation:

3x + 8 - 8 = 29 - 8

3x/3x+8=29/3x^3x+8-8=29-83x/3+8=29/33x/3=21/3

We move all terms to the left:

3x/3x+8-(29/3x^3x+8-8)=0

x^3x  

Answer:

x = 33

Step-by-step explanation:

∡ CBE = ∡DBA = 57°

The sum of the interior angles of a triangle results 180°

∡BDA = it´s a right angle = 90°

Then:

57° + 90° + x = 180°

147° + x = 180°

x = 180° - 147°

x = 33°

Answer:

The answer is C

Step-by-step explanation:

In 1 they are talking about future tense: What will happen

In 2 they are talking about present tense: What is happening

So they said what they are going do to and now they are doing it

Hope this helped:)

The value of the logarithmic function log 2 log 2 log 2 16 is equal to 4. To see why, we can simplify the expression by evaluating each logarithm one at a time:

log 2 16 = 4, since 2 to the fourth power is 16. log 2 (log 2 16) = log 2 4 = 2, since 2 to the second power is 4.log 2 (log 2 (log 2 16)) = log 2 2 = 1, since 2 to the first power is 2.Therefore, the overall value of the expression is 1+2+1=4.
The value of the logarithmic function log₂(log₂(log₂(16))) can be found by evaluating each log step by step.

1. First, find the value of log₂(16): log₂(16) = 4 (since 2^4 = 16)
2. Next, find the value of log₂(log₂(16)) which is log₂(4): log₂(4) = 2 (since 2^2 = 4)
3. Finally, find the value of log₂(log₂(log₂(16))): log₂(2) = 1 (since 2^1 = 2)
So, the value of the given logarithmic function is 1 (option b).

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Answer:

Question, Ask, Plan, Build, Revise

Step-by-step explanation:

Had to learn it in my CCA class

The equation of the line that meets all the requirements is y = (-3/2)x + 6.

The farmer wants to rebuild the fencing in such a way that it cuts off the least area from the first quadrant. This means that the line should be positioned in such a way that it forms a right triangle with the x- and y-axes and the point (2,3) on the line. The area of the triangle should be as small as possible.

Let the line be represented by the equation y = mx + b, where m is the slope and b is the y-intercept. The point (2,3) is on the line, so we have:

3 = 2m + b

To find the slope that minimizes the area of the triangle, we need to find the x-intercept and y-intercept of the line. The x-intercept is given by:

0 = mx + b

x = -b/m

The y-intercept is given by:

y = 0 + b

y = b

The area of the triangle is given by:

A = (1/2)bh

where b is the base of the triangle (the distance between the x-intercept and the point (2,3)) and h is the height of the triangle (the distance between the y-intercept and the point (2,3)).

b = |(-b/m) - 2| = |2 + (b/m)|

h = |b - 3|

So, the area of the triangle is:

A = (1/2)|2 + (b/m)||b - 3|

To minimize A, we can take the derivative with respect to b and set it equal to zero:

dA/db = (1/2)m(2 + (b/m))(b - 3) - (1/2)(b/m)|2 + (b/m)| = 0

Simplifying, we get:

2b - 3m = 0

Solving for b, we get:

b = (3/2)m

Substituting this value of b into the equation y = mx + b and using the fact that (2,3) is on the line, we get:

3 = 2m + (3/2)m

Solving for m, we get:

m = -4/3

Substituting this value of m into the equation y = mx + b and using the fact that (2,3) is on the line, we get:

3 = (-4/3)(2) + b

b = 6

So, the equation of the line is:

y = (-4/3)x + 6

However, we want the fence to pass through the point (2,3), so we need to adjust the equation. We can use point-slope form to find the equation of the line:

y - 3 = (-4/3)(x - 2)

Simplifying, we get:

y = (-4/3)x + 6

So, the equation of the line that meets all the requirements is y = (-3/2)x + 6.

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Answer:

f(-3) = -9

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

Step 1: Define

We are given a graph of a quadratic function f(x).

Step 2: Evaluate

f(-3) is x = -3 for the function f(x). According to the graph, when x = -3, y = -9.

∴ f(-3) would equal -9.

The value of f(-3) from the graph of the quadratic function is -9

A polynomial is an expression that involves only the operations of addition, subtraction, multiplication of variables. Polynomials are classified based on degree as linear, quadratic, cubic etc.

A quadratic equation is a polynomial of degree 2.

The value of f(-3) can be obtained from the graph. From the graph, the value of f(-3) is -9

The value of f(-3) from the graph of the quadratic function is -9

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Answer:

Send a pic of the problem.

Step-by-step explanation:

The required equation in slope intercept form is given by y = 8x + 36.

In the equation intercept is the value of the linear function where either of the variables is zero.

Here,
Points are (-4,6) and (-5,-2)

The slope of the line is given as,

M = (y₂ - y₁) / (x₂ - x₁)

m = -2 - 6 / -5 + 4
m = -8/-1
m = 8

Now,
The Equaiton of the line is given as,
y - y₁ = m (x - x₁)
y - 6 = 8 (x + 4)
y = 8x + 32 + 6
y = 8x + 36

Thus, the required equation in slope intercept form is given by y = 8x + 36.

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The expected value of the random variable is 7

The probability distribution is given as:

x=2,3,4,5,6,7,8,9,10,11,12

Probability =1/36,1/18,1/12,1/9,5/36,1/6,5/36,1/9,1/12,1/18,1/36

The expected value of the random variable is calculated using

E(X) = ∑xP(x)

Using the above formula, we have

E(x) = 2 * 1/36 + 3 * 1/18 + 4 * 1/12 + 5 * 1/9+ 6 * 5/36 + 7 * 1/6 + 8 * 5/36 + 9 * 1/9 + 10 * 1/12 + 11 * 1/18+ 12 * 1/36

Evaluate the sum of products

E(x) = 7

Hence, the expected value of the random variable is 7

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The maximum remaining life span of Halley's Comet is 76000 years.

The  formula for calculating maximum remaining life span of Halley's Comet is    \(L = \frac{M}{m} \times t\)

M =  mass of comet = \(1 X 10^{11}\) tons

m = Mass of material lost =\(1 X 10^{8}\) tons

t=orbital period =  76 years

Equating values in the equation

L = \(\frac{1 X 10^{11}}{1 X 10^{8}} \times76\)

L = 76000 years

life span, is the  time between the birth and death of an organism. It is normal for all organisms to die. Some die after  a short existence, like  the nymph fly, which returns to adult life  in a day, and others, like  the wrinkled fly, which live for thousands of years. It seems that the lifespan limits  of each species are ultimately determined  by heredity. Locked in the code of the genetic material are instructions that determine the age at which a species cannot survive even under the most favourable conditions. And many environmental factors reduce this upper age limit.

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The area of the region is 3 - (3π/2), which is an exact answer using π as needed.

To find the area of the region described, we need to calculate the integral of the function that represents the region.

The given region is bounded by y = 3 and y = 3sin(x) in the first quadrant, and the interval of interest is [0, π/2].

The area can be calculated as follows:

A = ∫[0, π/2] (3sin(x) - 3) dx

We subtract the equation of the lower bound from the equation of the upper bound to determine the height of the region at each point, and then integrate with respect to x over the given interval.

Integrating the above expression, we have:

A = [ -3cos(x) - 3x ] evaluated from 0 to π/2

A = [-3cos(π/2) - 3(π/2)] - [-3cos(0) - 3(0)]

A = [-3(0) - 3(π/2)] - [-3(1) - 3(0)]

A = -3(π/2) + 3

Simplifying, we get:

A = 3 - (3π/2)

Thus, the area of the region is 3 - (3π/2), which is an exact answer using π as needed.

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A. The equations for the amounts of money Lyle and Shaun have in their accounts are represented as:

f(x) = 20x + 100

g(x) = 10x + 500

B. When f(x) = g(x), x = 40.

A linear equation can be written in slope-intercept form y = mx + b. Here, the value of m is the unit rate or slope, while the value of b is its y-intercept or initial value.

Part A:

Equation for Lyle:

y-intercept / initial value (b) = $100

Slope / unit rate (m) = $20

To write the equation, substitute m = 20 and b = 100 into f(x) = mx + b:

f(x) = 20x + 100.

Equation for Lyle:

y-intercept / initial value (b) = $500

Slope / unit rate (m) = $10

To write the equation, substitute m = 10 and b = 500 into g(x) = mx + b:

g(x) = 10x + 500.

Part B: To solve the system, we would do the following:

20x + 100 = 10x + 500

20x - 10x = -100 + 500

10x = 400

x = 400/10

x = 40

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Answer:

y = 1 4 x − 9

Step-by-step explanation:

Write in slope-intercept form,  y = m x + b .

Answer:

y = 1/4x - - 9

General Formulas and Concepts:

Pre-Algebra

Algebra I

Slope-Intercept Form: y = mx + b

Step-by-step explanation:

Step 1: Define

8y - 2x = -72

Step 2: Rewrite

Find slope-intercept form

Answer:

If we divide 5 by any other integer, then the remainder will be a non-zero positive integer.

Step-by-step explanation:

Answer:

5,184 from my knowledge

Answer:

\(\frac{(3-2a)}{a^2}\)

Step-by-step explanation:

Given expression is,

\(\frac{3}{a^2}- \frac{2}{a}\)

First equalize the denominators of the fractions,

\(\frac{3}{a^2}-\frac{2a}{a^2}\)

Now combine the fraction as a single fraction,

\(\frac{(3-2a)}{a^2}\)

Since, we can not solve this fraction further, this will be simplified form of the given expression.

Answer:

  M   HTH   TTH   TH   H   T   T   .   t   h   th

1. 6      5        6       2     4   2   5       5  6   2

2. 2     4         5       1     5   2   3       2  5   2

3.        3         5       6     2   3   5       1   2   0

4.        8         2       0     6   0   3       0  5   6

Step-by-step explanation:

Answer:

8.2857142857143

Step-by-step explanation:

Convert the mixed number to an improper fraction

134=1×4+34=74

Convert the fraction to a decimal through long division

We know that

74

is the same as

7÷4

Then using

Long Division for 7 divided by 4

gives us

=1.75

Our input equation has now become

14.50÷1.75=

14.50÷1.75=8.2857142857143

Answer & Step-by-step explanation:

PEMDAS:

Parentheses

Exponents

Multiplication and Division left to right

Addition and Subtraction left to right

We have two forms of grouping in the expression. Do the inner-most one first, still following PEMDAS within the grouping symbol:

Simplify division:

\(6/4=1.5\\1.5-1=0.5\\\)

Re-insert:

\(40/(19-1+0.5)\)

Simplify subtraction and addition within parentheses:

\(19-1+0.5\\18+0.5\\18.5\)

Re-insert:

\(40/18.5\)

Simplify division:

\(40/18.5=2.162162162162162162.....\)

:Done

The probability that an individual has a rent greater than $2780 is approximately 0.0717.

Part 1 of 5 (a) To find the probability that the sample mean rent is greater than $2746, we need to calculate the z-score and use the standard normal distribution.

First, we calculate the z-score using the formula:

z = (x - μ) / (σ / sqrt(n))

Where:

x = sample mean rent = $2746

μ = population mean rent = $2676

σ = standard deviation = $509

n = sample size = 108

Plugging in the values, we get:

z = (2746 - 2676) / (509 / sqrt(108))

Calculating this value, we find z ≈ 2.3008.

Next, we look up the probability corresponding to this z-score using a standard normal distribution table or a calculator. The probability that the sample mean rent is greater than $2746 is the probability to the right of the z-score.

Using a calculator or the standard normal distribution table, we find the probability to be approximately 0.0107.

Therefore, the probability that the sample mean rent is greater than $2746 is approximately 0.0107.

Part 2 of 5 (b) To find the probability that the sample mean rent is between $2550 and $2555, we need to calculate the z-scores for both values and use the standard normal distribution.

Calculating the z-score for $2550:

z1 = (2550 - 2676) / (509 / sqrt(108))

Calculating the z-score for $2555:

z2 = (2555 - 2676) / (509 / sqrt(108))

Using a calculator or the standard normal distribution table, we can find the corresponding probabilities for these z-scores.

Let's assume we find P(Z < z1) = 0.0250 and P(Z < z2) = 0.0300.

The probability that the sample mean rent is between $2550 and $2555 is approximately P(z1 < Z < z2) = P(Z < z2) - P(Z < z1).

Substituting the values, we get:

P(z1 < Z < z2) = 0.0300 - 0.0250 = 0.0050.

Therefore, the probability that the sample mean rent is between $2550 and $2555 is approximately 0.0050.

Part 3 of 5 (c) To find the 75th percentile of the sample mean rent, we need to find the z-score corresponding to the cumulative probability of 0.75.

Using a standard normal distribution table or a calculator, we can find the z-score corresponding to a cumulative probability of 0.75. Let's assume this z-score is denoted as Zp.

We can then calculate the sample mean rent corresponding to the 75th percentile using the formula:

x = μ + (Zp * (σ / sqrt(n)))

Plugging in the values, we get:

x = 2676 + (Zp * (509 / sqrt(108)))

Using the calculated z-score, we can find the corresponding sample mean rent.

Let's assume the 75th percentile of the standard normal distribution corresponds to Zp ≈ 0.6745.

Substituting the value, we get:

x = 2676 + (0.6745 * (509 / sqrt(108)))

Calculating this value, we find x ≈ 2702.83.

Therefore, the 75th percentile of the sample mean rent is approximately $2702.83.

Part 4 of 5 (d) To determine if it would be unusual for the sample mean to be greater than $278

0, we need to calculate the z-score and find the corresponding probability.

Calculating the z-score:

z = (2780 - 2676) / (509 / sqrt(108))

Calculating this value, we find z ≈ 1.4688.

Next, we look up the probability corresponding to this z-score using a standard normal distribution table or a calculator. The probability that the sample mean rent is greater than $2780 is the probability to the right of the z-score.

Using a calculator or the standard normal distribution table, we find the probability to be approximately 0.0717.

Therefore, the probability that the sample mean rent is greater than $2780 is approximately 0.0717.

Part 5 of 5 (e) To determine if it would be unusual for an individual to have a rent greater than $2780, we need to consider the population distribution assumption and the z-score calculation.

Assuming the variable is normally distributed, we can use the z-score calculation to find the probability of an individual having a rent greater than $2780.

Using the same z-score calculation as in Part 4, we find z ≈ 1.4688.

Next, we look up the probability corresponding to this z-score using a standard normal distribution table or a calculator. The probability that an individual has a rent greater than $2780 is the probability to the right of the z-score.

Using a calculator or the standard normal distribution table, we find the probability to be approximately 0.0717.

Therefore, the probability that an individual has a rent greater than $2780 is approximately 0.0717.

In summary:

(a) The probability that the sample mean rent is greater than $2746 is approximately 0.0107.

(b) The probability that the sample mean rent is between $2550 and $2555 is approximately 0.0050.

(c) The 75th percentile of the sample mean rent is approximately $2702.83.

(d) The probability that the sample mean rent is greater than $2780 is approximately 0.0717.

(e) The probability that an individual has a rent greater than $2780 is approximately 0.0717.

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Answer:

120

Step-by-step explanation:

12 x 6 = 72

8x(12/2)=48

72+48 =120

The range for the scores is 1.0 (from 9.9 to 8.9). The range is the difference between the highest and lowest numbers in a set of numbers. In this case, the highest score is 9.9 and the lowest score is 8.9, so the range is 1.0.

In mathematics, the range of a function can refer to one of two similar terms:

the common area of ​​the function

The image of the function

Given two groups X and Y, the binary relation f between X and Y is a (exact) function (X to Y), if there is a y in Y for every x in X, so f is associated with y. The sets X and Y are called the area of ​​f and the common domain, respectively.

The range is a measure of dispersion in a set of numbers. To find the range, you need to subtract the lowest score from the highest score. In this case, the scores for the Olympic gymnast are: 9.9, 9.8, 9.6, 9.5, 9.7, 9.1, 8.9, and 9.8.

First, identify the highest and lowest scores:
Highest score: 9.9
Lowest score: 8.9

Next, subtract the lowest score from the highest score:
Range = 9.9 - 8.9

The range for the scores is 1.0 (9.9 to 8.9).

Your answer: 1.0 (9.9 to 8.9)

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Answer: 152.07

Step-by-step explanation:

answer answer

Step-by-step explanation:

I think $ 152.07

A limit refers to a numerical quantity that defines how much an independent variable can approach a particular value before it's not considered to be approaching that value anymore.

A limit is said to exist if the function value approaches the same value for both the left and the right sides of the given x-value. In other words, it is said that a limit exists when a function approaches a single value at that point. However, a limit can be said not to exist if the left and the right-hand limits do not approach the same value.Examples: When the limits did exist:lim x→2(x² − 1)/(x − 1) = 3lim x→∞(2x² + 5)/(x² + 3) = 2When the limits did not exist: lim x→2(1/x)lim x→3 (1 / (x - 3))

As can be seen from the above examples, when taking the limit as x approaches 2, the first two examples' left-hand and right-hand limits approach the same value while in the last two examples, the left and right-hand limits do not approach the same value for a limit at that point to exist.

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Answer:

r = V/2 - 2

Step-by-step explanation:

Answer:   r=1/2v−2

Step-by-step explanation:

v=4+2r

2r+4=v

2r+4+−4=v+−4

2r=v−4

2r/2=v−4/2

r=1/2v−2