What height does a frictionless playground slide need so that a 35 kg child reaches the bottom at a speed of 4.7 m/s?

Answers

Answer 1

By conservation of energy, the height of the playground slide should be 108.241 meters.

We need to know about the conservation of energy to solve this problem. The energy can not be created or destroyed, the only way is to change to another form. It can be written as

Ei = Ef

where Ei is initial energy and Ef is the final energy

From the question above, we know that

m = 35 kg

v = 4.7 m/s

The playground slide is converting the potential energy from height to kinetic energy. Hence,

Ei = Ef

PE = KE

m . g . h = 1/2 . m . v²

h = 1/2 . g . v²

h = 1/2 . 9.8 . 4.7²

h = 108.241 meters

Hence, the height of playground slide should be 108.241 meters to reach 4.7 m/s of velocity at bottom.

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Related Questions

Discretionary income equals: A) Gross income. B) Take-home pay. C) The amount being saved each month. D) Money left over after paying for housing, food, and other necessities. E) Social Security taxes.

Answers

Discretionary income equals money left over after paying for housing, food, and other necessities.

Discretionary income refers to the income that individuals have available for spending or saving after deducting taxes and essential expenses such as housing, food, transportation, and utilities. It represents the portion of income that individuals have discretion over, meaning they can choose how to allocate or use it based on their preferences. Discretionary income provides individuals with financial flexibility to spend on non-essential goods and services, such as entertainment, vacations, hobbies, or investments. It is an important economic indicator as it reflects the potential for consumer spending and can influence overall economic growth.

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A ray of light in air strikes the surface of a liquid at an angle of 65 degrees with the normal. The refracted ray is at an angle of 42 degrees with the normal. What is the index of refraction of this liquid?

Answers

The index of refraction of this liquid will be 1.28. It is found as the ratio of the sin of the angle of incidence and the angle of reflection.

What is an index of refraction?

The refractive index of a substance is a dimensionless quantity that specifies how quickly light passes through it in optics.

The given data in the problem is;

Angle of incidence (i)= 65°

Angle of refraction(r) = 42°

The formula for the index of refraction is;

\(\rm n = \frac{sin \ i }{sin \ r} \\\\ \rm n = \frac{sin 65 ^0}{sin 42^0} \\\\ n=1.28\)

Hence, the index of refraction of this liquid will be 1.28.

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magnetic force physics

Answers

Magnetic effect that can be experienced in the space around a current-carrying conductor is called magnetic field.

What is magnetic force?

Magnetic force, attraction or repulsion that arises between electrically charged particles because of their motion.

Mathematically, the formula for magnetic force is given as;

F = qVB

where;

V is the velocity of the chargeq is the magnitude of the chargeB is the magnetic field

The region of space around in which magnetic force is experience is known as magnetic field. A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials.

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The complete question is below:

magnetic force physics

Magnetic effect that can be experienced in the space around a current-carrying conductor is called?

#2
Force and Motion
O
Which two properties are used
to describe motion?
A. Speed and time
B. Mass and distance
C. Length and time
D. Distance and speed

Answers

Answer:

mass and distance

Explanation:

force is mass while motion can also be regard as distance or movement

A student pedaling a bicycle applies a net force of 250 N. The mass of the rider and the bicycle is 48 Kg. Assuming no friction is present, what is the acceleration of the bicycle and rider? (1 N= 1.0 kg-m/sec?)

Answers

5.2 m/s. F=ma so 250=48a. Divide 250 by 48 and get your acceleration

What would the acceleration of a 34kg child on a bike be if they were being pushed with Fa=57N

Answers

The acceleration of the 34 kg child on a bike when being pushed with a force of 57 N would be approximately: 1.68 meters per second squared.

To calculate the acceleration of a 34 kg child on a bike when being pushed with a force of 57 N, you can use Newton's second law of motion. Newton's second law states that the force applied on an object is equal to the mass of the object multiplied by its acceleration (F = ma).

In this case, the applied force (Fa) is 57 N, and the mass (m) of the child is 34 kg. To find the acceleration (a), you can rearrange the formula as follows:

a = Fa/m

Now, plug in the given values:

a = 57 N / 34 kg

a ≈ 1.68 m/s²

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The chart lists four different kinds of atoms.

A chart titled Different Kinds of Atoms with the entries calcium, gold, argon, iodine.

What is true about all of these atoms?

They cannot be solids.
They are the largest units of matter.
They are the only types of atoms that exist.
They cannot be divided and still keep the properties of the element.

Answers

They cannot be divided and still keep the properties of the element true about all of these atoms. Option D is corect.

What is an atom?

The atom consists of matter that may be split without releasing electrical charges.

It's also the smallest unit of matter with chemical element features. As a result, the atom is the fundamental unit of science.

In the nucleus proton and the neutron is exists. The condition of the atom to be electrically neutral is that the number of the proton and electron should be the same.

They cannot be separated while still maintaining the element's characteristics for each and every one of these atoms.

Hence, option D is corect.

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Answer:

The correct answer is d, they cannot be divided and still keep the properties of the element.

Explanation:

You're welcome :)

when a nucleus of 235u undergoes fission, it breaks into two smaller, more tightly bound fragments. t or f

Answers

The fragments reaction is 7.59 MeV/nucleon and  8.39 MeV/nucleon

What is nucleus ?

Neutrons and protons, which have opposite electric charges, make up atomic nuclei. The strongest basic force now understood, known as the strong force, is what holds these things together. A normal atom's nucleus generally holds more than 99.9% of the atom's mass yet takes up considerably less than.01 percent of its volume.

What is fission ?

When a neutron collides with a bigger atom, it excites it and causes it to split into two smaller atoms, which are known as fission products. This process is known as fission. A chain reaction might start as a result of additional neutrons that are also emitted. Huge amounts of energy are produced during the splitting of each atom.

1) m_proton + m_netron + m_electron - m_U

= 92*1.007276466812 + 92*5.4857990943e-4 + 143*1.008664916 - (235.0439299)

= 1.9151 u

= 931.494061 * 1.9151 MeV

= 1784 MeV

= 1784/235 = 7.59 MeV/nucleon

2) m_proton + m_netron + m_electron - m_Cs

= 55*1.007276466812 + 55*5.4857990943e-4 + 82*1.008664916 - (136.9070895)

= 1.2338 u

= 931.494061 * 1.2338 MeV

= 1149 MeV

= 1145/137 = 8.39 MeV/nucleon

Therefore, the fragments reaction is 7.59 MeV/nucleon and  8.39 MeV/nucleon.

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Which variable is NOT shown on a velocity-time graph?

Answers

Acceleration is the variable that is NOT shown on a velocity-time graph

Velocity - time graph, evidently shows two variables, velocity on one axis and time on other . But as we know , that acceleration can be calculated by the formula which is

acceleration = change in velocity / time

hence , the derivative of velocity is acceleration

which mean that the slope of the Velocity - time graph shows the acceleration , which cannot be seen , but is hidden as the slope of that graph

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1. A rock is dropped off a cliff and strikes the ground with an impact velocity of 35 m/s. How
high was the cliff?

Answers

Answer:

45 m

Explanation:

Use Big Five #5 with v0 = 0 (calling down the positive direction).

a bulldozer pushed a large rock with a force of 5000 N at 2.0 m/s for 20s. how much work was done by the bulldozer​

Answers

Answer:

It is 10KJoules

Explanation:

hope it helps

How much energy is required to take 500g of ice at -40 degrees to water at room temperature (22 degrees Celsius)? Show work pls

Answers

Answer: Given that:

Mass (m) = 20 g = 0.02 Kg,

temperature (T₁) = -10°C = -10+273 = 263 K

temperature (T₂) = 10°C = 10+273 = 283 K

Specific heat of water (Cp) = 4.187 KJ/Kg k

We know that Heat transfer (Q) = m. Cp.( T₂ - T₁)

                                                   = 0.02 × 4.187 × (283-263)

                                                Q = 1.67 KJ

Heat transferred is 1.67 KJ

Explanation:

Two charges are separated by 1.68 cm. Object A has a charge of 5.0 μ C , while object B has a charge of 7.0 μ C . What is the force on Object A?

Answers

Answer:

The force on Object A = 1116.07 N

Explanation:

The separation between the two charges, d = 1.68 cm

d = 1.68/100 m

d = 0.0168 m

The charge on object A

\(\begin{gathered} q_A=5.0\mu C \\ q_A=5\times10^{-6}C \end{gathered}\)

The charge on object B

\(\begin{gathered} q_B=7.0\mu C \\ q_B=7\times10^{-6}C \end{gathered}\)

The electric constant

\(k=9\times10^9Nm^2C^{-2}\)

The force on on the charge A is calculated as shown below:

\(\begin{gathered} F_A=\frac{kq_Aq_B}{d^2} \\ F_A=\frac{9\times10^9\times5\times10^{-6}\times7\times10^{-6}}{0.0168^2} \\ F_A=\frac{0.315}{0.00028224} \\ F_A=1116.07N \end{gathered}\)

The force on Object A = 1116.07 N

wich is a better deal, 5 tickets for $12.50 or 8 tickets for $20.16

Answers

5 tickets for $ 12.50

Explanation

to figure out this we need to find the unit rate

so

Step 1

the rate is given by:

\(\text{rate}=\frac{Numbe\text{r of tickets}}{\cos t\text{ of those tickets}}\)

then

a) for 5 tickets and $12.50

replace and calculate

\(\begin{gathered} \text{rate}=\frac{Numbe\text{r of tickets}}{\cos t\text{ of those tickets}} \\ \text{rate}=\frac{5\text{ tickets}}{12.5\text{ \$}}=0.4\text{ tickets per dollar} \end{gathered}\)

b) for 8 tickets and $20.16

replace and calculate

\(\begin{gathered} \text{rate}=\frac{Numbe\text{r of tickets}}{\cos t\text{ of those tickets}} \\ \text{rate}=\frac{8\text{ tickets}}{20.16\text{ \$}}=0.396\text{ tickets per dollar} \end{gathered}\)

therefore, the better deal is 5 tickets for $ 12.50, you will get more tickets per dollar

I hope this helps you

Does guardians of the galaxy have multiple endings.

Answers

Answer: no I watch  both of them

Explanation:

If a cube of 1 mm side is divided into 1 nm-sized cubes, the total surface area will increase by a factor of:

a. 10^6>
b. 2 x 10^6
c. 6 x 10^6
d. 6 x 10^12

Answers

If a cube of 1 mm side is divided into 1 nm-sized cubes, the total surface area will increase by a factor of 6 x 10⁶, hence C is correct option.

Each face of the original cube has an area of (1 mm)² = 10⁶ nm². When we divide the cube into smaller cubes of 1 nm on each side, we increase the number of faces by a factor of (1 nm / 1 mm)² = 10⁻⁶, since each small cube has six faces. Therefore, the total surface area of the small cubes is:

= 6 x (10⁶ nm²) x (10⁶ x 10⁻⁶)

= 6 x 10⁶ nm².

This is an increase in the total surface area by a factor of 6 x 10⁶.

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Science ck-12 green house effect

Answers

Answer:

what about it i need more info

Explanation:

The electrical voltage between the ends of a resistor is equal to 8 V. A student has two voltmeters available that measure up to 6 V. The voltages of the voltmeters are equal to 500 ohms and 600 ohms, respectively. What voltages will the connected voltmeters indicate? (Fig. 3.45)​

The electrical voltage between the ends of a resistor is equal to 8 V. A student has two voltmeters available

Answers

Answer:

I = V / R

I1 = 6 / 500 = .012   amps for full scale deflection

I2 = 6 / 600 = .01   amps for full scale deflection

I = 8 / 1100 = .00727   amps thru load (actual current)

D1 = .00727 / .012 = .606 of full scale deflection

D2 = .00727 / .01 = .727    of full scale deflection

V1 = .606 * 6 = 3.64 V  (of 6 V)

V2 = .727 * 6 = 4.36 V   (of 6 V)

Check: V1 + V2 = 3.64 + 4.36 = 8 V

Three two-port circuits, namely Circuit 1 , Circuit 2 , and Circuit 3 , are interconnected in cascade. The input port of Circuit 1 is driven by a 6 A de current source in parallel with an internal resistance of 30Ω. The output port of Circuit 3 drives an adjustable load impedance ZL. The corresponding parameters for Circuit 1, Circuit 2, and Circuit 3, are as follows. Circuit 1: G=[0.167S0.5−0.51.25Ω] Circuit 2: Circuit 3: Y=[200×10−6−800×10−640×10−640×10−6]S Z=[33534000−3100310000]Ω a) Find the a-parameters of the cascaded network. b) Find ZL such that maximum power is transferred from the cascaded network to ZL. c) Evaluate the maximum power that the cascaded two-port network can deliver to ZI.

Answers

a) The A-parameters of the cascaded network are defined by (4 points)Answer:a_11 = 0.149 S^0.5 - 0.0565a_12 = -0.115 S^0.5 - 0.0352a_21 = 136 S^0.5 - 133a_22 = -89.5 S^0.5 + 135b) Find ZL such that maximum power is transferred from the cascaded network to ZL. (2 pointsZ). The maximum power transfer to load impedance ZL occurs when the load is equal to the complex conjugate of the source impedance.

We can calculate the source impedance as follows: Rs = 30 Ω || 1/0.167^2 = 31.2 ΩThe equivalent impedance of circuits 2 and 3 connected in cascade is: Zeq = Z2 + Z3 + Z2 Z3 Y2Z2 + Y3 (Z2 + Z3) + Y2 Y3If we substitute the corresponding values: Zeq = 6.875 - j10.75ΩNow we can determine the value of the load impedance: ZL = Rs* Zeq/(Rs + Zeq)ZL = 17.6 - j8.9Ωc) Evaluate the maximum power that the cascaded two-port network can deliver to ZI. (2 points). The maximum power that can be delivered to the load is half the power available in the source.

We can determine the available power as follows: P = (I_s)^2 * Rs /2P = 558 mW. Now we can calculate the maximum power transferred to the load using the value of ZL:$$P_{load} = \frac{V_{load}^2}{4 Re(Z_L)}$$$$V_{load} = a_{21} I_s Z_2 Z_3$$So,$$P_{load} = \frac{(a_{21} I_s Z_2 Z_3)^2}{4 Re(Z_L)}$$Substitute the corresponding values:$$P_{load} = 203.2 m W $$. Therefore, the maximum power that can be delivered to the load is 203.2 mW.

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Fig 3.1 shows the speed-time graph of a firework rocket as it rises and then falls to the ground
2
rocket
moving
upwards
speed
B
time
rocket
moving
downwards
Fig. 3.1
The rocket runs out of fuel at A It reaches its maximum height at B. Al Elt returns to the ground,
(a) (0) Starte the gradient of the graph at B. gradient
......11
00 State why the gradient has this value at B.
111

Fig 3.1 shows the speed-time graph of a firework rocket as it rises and then falls to the ground2rocketmovingupwardsspeedBtimerocketmovingdownwardsFig.

Answers

The acceleration of an object in free fall motion is the constant acceleration due to gravity

(i) The gradient of the rocket at point B is approximately -9.81 m/s²

(ii) The reason why the gradient is -9.81 m/s² is as follows;

The given graph is the speed to time graph with the upward direction taken as positive

Gradient of the speed to time graph is the acceleration

Given that at point B the object is at the maximum point, the upward motion due to the rocket stops, the motion of the rocket is then due to gravity

Therefore, the gradient at B, is given as follows;

\(Gradient = \dfrac{\Delta v}{\Delta t } = \dfrac{d(u + a \cdot t)}{dt} =a\)

Force = Mass × Acceleration

At point B the only force acting on the rocket is the force of gravity, therefore, the acceleration of the rocket at B, a = g, acceleration due to gravity ≈  9.81 m/s², and the rocket is falling due to its weight

Force acting at B = Weight = Mass × Acceleration due to gravity, g

Therefore, only gravitational force is acting on the rocket when the direction of the rocket changes and rocket falls freely, at B, and the acceleration of the rocket at B = g = 9.81 m/s²

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A jumpy squirrel is trying to cross the street. Its velocity v as a function of time t is given in the graph
below where rightwards is the positive velocity direction
v (m/s)
3
4
-2-+
-3
-4-
-5
What is the squirrel's displacement Au from t = 1s to 2 s?
Answer with two significant digits.
m
Show Calculator

Answers

Answer: 2.5 m

Explanation: 1/2(1s)(5m/s)

=2.5.

Got it from Khan Academy

in the laboratory a student finds that it takes 161 joules to increase the temperature of 11.7 grams of solid magnesium from 24.5 to 38.9 degrees celsius.

Answers

Specific heat capacity of solid magnesium is 0.9556 J/g C.

What is specific heat capacity?

When a material's temperature rises by 1 K (or 1 °C), or when its mass increases by 1 kg, the specific heat capacity is defined as the amount of heat (J) absorbed per unit mass (kg). This measurement is expressed as J/(kg K) or J/(kg °C).

According to the given question:

C = Q/m.T

T = T2 - T1 = 38.9 - 24.5 = 14.4 C

C = 11.7/(161 x 14.4) = 0.9556 J/g C

Specific heat capacity of solid magnesium is 0.9556 J/g C.

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Nicki rides her bike at a constant speed for 6 km. That part of her ride takes her 1 hour. She then rides her bike at a constant speed for another 9 km. That part of her trip takes her 2 hours. What is her average speed?

Answers

Answer:

5km/h

Explanation:

distance divided by total time

PUBE: DATE: A particle is moving in a straight line with constant acceleration. it passes point p with speed of 2ms. ten seconds later passes point q. the distance between p and q is 40 metres. find the speed of particle as it passes point q. ​

Answers

Answer:4m/s

Explanation:The car is moving with constant acceleration therefore average speed is equal to distance over time to find the distance covered we multiple the speed by the time which gives 20 metres meaning after every 20 metres it uses a speed of 2m/s so for 40 metres it's going to be 40 x2 over 20 giving us 4m/s

You have 2 oppositely charged objects. How would you position them to give them the lowest PE?

Answers

To position two oppositely charged objects to give them the lowest potential energy (PE), they should be placed as close together as possible.

This is because the PE of a charged object is inversely proportional to the distance between the objects. As the distance between the objects decreases, the PE also decreases.

Therefore, to minimize the PE( potential energy ) between two oppositely charged objects, they should be positioned as close together as possible, without actually touching each other.

This configuration represents the state of maximum stability and minimum potential energy, as the attractive electrostatic forces between the objects are maximized when they are in close proximity.

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A 1.2-lb slider is propelled upward at A along the fixed curved bar which lies in a vertical plane. If the slider is observed to have a speed of 9.2 ft/sec as it passes position B, determine (a) the magnitude N of the force exerted by the fixed rod on the slider and (b) the rate at which the speed of the slider is changing (positive if speeding up, negative if slowing down). Assume that friction is negligible.

Answers

The given mass of the slider is 1.2 lb. The speed of the slider when it reaches point B is 9.2 ft/s. The curve along which the slider moves is smooth, and no friction is present. Determine the magnitude of the force exerted by the rod on the slider.

Determine the rate at which the slider's speed is changing (positive if speeding up, negative if slowing down).Given that, Mass of the slider, m = 1.2 l b Velocity of the slider at point B, V = 9.2 f t/s Let's assume N be the normal force acting on the slider.

Hence the weight acting on the slider is mg, where g is acceleration due to gravity. The forces acting on the slider are resolved along the vertical and horizontal directions.

Rate of change of velocity of the slider is the acceleration acting on the slider. As the motion is along a vertical plane, the only force acting on the slider in the vertical direction is the weight of the slider.

Therefore the rate of change of the velocity of the slider is negative. The rate of change of the speed of the slider is given by the derivative of the velocity function.

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1) A spring with a spring constant of 0.70 N/m is stretched 1.5 m. What was the force? 2) The same spring is stretched 5 m. What was the force?​

1) A spring with a spring constant of 0.70 N/m is stretched 1.5 m. What was the force? 2) The same spring

Answers

Answer:

K= F/∆lF=K•∆l∆l=F/Kso we know that the K is 0.70N/mthe ∆l which is the elongation is 1.5 mto find the force which is F u have to apply the formula. by applying the formula you get 1.05Nfor the second force you get 3.5N

Which of the broad area of I-O psychology interest you the most and why?​

Answers

The I & O Psychology researchers are most interested in areas such as personnel selection, job analysis, performance management, organizational development etc..

What are different areas of interest in i & O Psychology?

The personnel selection is a critical area that involves developing methods to identify the most qualified candidates for job positions. This area encompasses techniques such as job analysis, interview strategies and personality assessments.

Another area is performance management which involves developing effective performance appraisal systems, feedback mechanisms and coaching strategies to enhance employee performance. These are examples of diverse areas of interest within Industrial and Organizational Psychology.

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A 9.0-volt battery delivers a 0.50-A current to a bulb connected across its terminals. What power is delivered to the bulb?
(A) 0.056 W
(B) 4.5 W
(C) 18 W
(D) 41 W

Answers

The answer for “A 9.0-volt battery delivers a 0.50-A current to a bulb connected across its terminals. delivered What power is to the bulb? (A) 0.056 W (B) 4.5 W (C) 18 W (D) 41 W” would be B. Answer is B!!!
A 9.0-volt battery delivers a 0.50-A current to a bulb connected across its terminals. What power is

the graph below shows the position vs. time for a 932 kg cart moving along a horizontal track. To the nearest tenth of a kilojoule, what is the car's kinetic energy at 8.0 seconds?​

Answers

Answer:use 1/2 x M x V^2

Explanation:

to calculate the kinetic energy, observe the velocity from the graph at 8.0 seconds. and use the formula!

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