what happens to wave frequency when wave receptor moves and wave source are moving relative to one another

The surface area of the frustum generated by revolving the line segment joining the points (0, 5) and (7, 7) about the x-axis can be determined using parametrization.

To find the surface area of the frustum, we can use the method of parametrization. The frustum is formed by rotating the line segment about the x-axis, and we can parametrize the curve generated by the rotation.

Let's consider a parameter t that ranges from 0 to 1. We can express the x-coordinate of the curve as x = t * 7 and the y-coordinate as y = 5 + t * 2. The parameter t represents the progression along the line segment, ranging from 0 at the point (0, 5) to 1 at the point (7, 7).

To calculate the surface area, we need to find the differential element of arc length ds. For a curve given by parametric equations x = f(t) and y = g(t), the differential element of arc length can be expressed as ds = \(\sqrt{x} ((dx/dt)^2 + (dy/dt)^2) * dt\).

Substituting the parametric equations into the formula, we have ds = \(\sqrt((7^2 + 2^2)) * dt = sqrt(53) * dt.\)

To find the surface area of the frustum, we integrate ds from t = 0 to t = 1: \(Area =\int\limits^0_1 \, dx \sqrt(53) * dt.\)

Integrating this expression yields the surface area of the frustum. Therefore, by using parametrization and evaluating the integral, the surface area of the frustum generated by revolving the line segment (0, 5) to (7, 7) about the x-axis can be determined.

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The magnitude of the magnetic field at a point inside the wire at a distance ri is given by the formula: B = μ0Jri/2, where μ0 is the permeability of free space. Therefore, the magnitude of the magnetic field is directly proportional to the distance ri from the center of the wire.

Assuming J is positive, the direction of the magnetic field at some point inside the wire is in the positive ϕϕ-direction (azimuthal direction), as determined by the right-hand rule for current-carrying wires.
The magnitude of the magnetic field at a distance r inside the wire with radius R and uniform current density J in the z-direction can be found using Ampere's Law. For a point inside the wire, we have:
B = (μ₀ * J * r) / (2 * π)
Where B is the magnetic field, μ₀ is the permeability of free space, and r is the distance from the center of the wire (ri in the question).
Regarding the direction of the magnetic field at some point inside the wire, when J is positive, the magnetic field direction follows the right-hand rule for the circular path around the z-axis. Therefore, the magnetic field will be in the positive φ direction.

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The direction of the magnetic field at some point inside the wire is positive ϕ-direction.

To determine the magnitude of the magnetic field at a point inside the wire at a distance ri, we can use the formula for the magnetic field produced by a current-carrying wire, B = μ0 * I / 2πr, where μ0 is the permeability of free space, I is the current, and r is the distance from the wire. In cylindrical coordinates, r = ri and the current density J = Jz^z, so the current I can be found by integrating J over the cross-sectional area of the wire, giving I = J * πR^2. Substituting these values into the formula for B, we get B = μ0 * J * R^2 / 2 * ri * π.
The direction of the magnetic field at some point inside the wire depends on the direction of the current. Assuming J is positive, the current flows in the positive z-direction. Using the right-hand rule, we can determine that the magnetic field produced by this current flows in the positive ϕ-direction around the wire. So, the direction of the magnetic field at some point inside the wire is positive ϕ-direction.

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Gravitational force between two masses m, and m, is represented as F = Gm₂ m₂ / r^2 where r = xi+yj + zkG, m, m₂ are nonzero constants and let's assume that I = 0

a) Calculation:For F = Gm₂ m₂ / r^2.

Using r = xi+yj + zk and let r^2 = x^2 + y^2 + z^2∴ F = Gm₂ m₂ / (x^2 + y^2 + z^2), Where G, m, m₂ are nonzero constants. Divergence of F = ∇ · F= 1/r^2(d/dx(r^2Fx) + d/dy(r^2Fy) + d/dz(r^2Fz))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)^(3/2)) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)^(3/2)) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)^(3/2)))= 1/r^2(d/dx(r^2Gm₂ m₂ x/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dy(r^2Gm₂ m₂ y/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2) + d/dz(r^2Gm₂ m₂ z/(x^2+y^2+z^2)) * (x^2+y^2+z^2)^(3/2))= 1/r^2(Gm₂ m₂ [2x(x^2+y^2+z^2)-3x^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2y(x^2+y^2+z^2)-3y^2]/(x^2+y^2+z^2)^(5/2) + Gm₂ m₂ [2z(x^2+y^2+z^2)-3z^2]/(x^2+y^2+z^2)^(5/2))= 1/r^2(Gm₂ m₂ [(2x^2+2y^2+2z^2-3x^2)/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3y^2]/(x^2+y^2+z^2)^(3/2)] + [2x^2+2y^2+2z^2-3z^2]/(x^2+y^2+z^2)^(3/2)])= 1/r^2(Gm₂ m₂ [x^2+y^2+z^2]/(x^2+y^2+z^2)^(3/2))= 0.

Curl of F = ∇ × F= i(d/dy(Fz) - d/dz(Fy)) - j(d/dx(Fz) - d/dz(Fx)) + k(d/dx(Fy) - d/dy(Fx))= i(d/dy(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ y/(x^2+y^2+z^2))) - j(d/dx(Gm₂ m₂ z/(x^2+y^2+z^2)) - d/dz(Gm₂ m₂ x/(x^2+y^2+z^2))) + k(d/dx(Gm₂ m₂ y/(x^2+y^2+z^2)) - d/dy(Gm₂ m₂ x/(x^2+y^2+z^2)))= i(Gm₂ m₂ [-2xz]/(x^2+y^2+z^2)^(5/2)) - j(Gm₂ m₂ [-2yz]/(x^2+y^2+z^2)^(5/2)) + k(Gm₂ m₂ [(x^2+y^2-2z^2)]/(x^2+y^2+z^2)^(5/2))

b) Calculation:The line integral of F along a curve C can be evaluated by the following formula∫C F.dr = ∫∫ ( ∇ x F) ds, Where r is the position vector of the curve, s is the scalar parameter representing the curve, and the integral is evaluated from the initial point to the final point.

Using the curl of F obtained in part a) and for the surface with ∂S as C∫C F.dr = ∫∫ ( ∇ x F) ds= ∫∫ curl(F) ds= ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds...[1]

Let's consider the surface S as a plane perpendicular to the z-axis of the form ax+by+c=0 and the curve C as the intersection of the plane and the cylinder x^2 + y^2 = a^2.

Let's choose the unit normal to the surface S as k (along the z-axis).

The curl of F is a vector field perpendicular to the plane and along the direction of k.

Thus the integral can be written as∫C F.dr = ∫∫ ( ∇ x F) . k ds= ∫∫ (x^2+y^2-2z^2) ds...[2]

Now let's evaluate the integral over the given plane ax+by+c=0. We can write x = t, y = (c-at)/b and z = 0, where t is the scalar parameter along the line of intersection of the plane and the cylinder (x^2 + y^2 = a^2).

Since the curve C is on the cylinder of radius a, we have x^2+y^2 = a^2 ⇒ t^2+(c-at)^2/b^2 = a^2On solving for t, we have t = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2].

Substituting t in x and y, we get the curve C in the x-y plane as a function of the scalar parameter s asx = (bc±ab √(a^2-b^2-c^2))/[a^2+b^2]y = (c-at)/b= (c-(bc±ab √(a^2-b^2-c^2))/[a^2+b^2])/b.

Now we can evaluate the integral over the curve C, which is along the intersection of the plane and the cylinder.

Integral over C (x^2+y^2-2z^2) ds= ∫t₁^t₂ [(t^2 + [(c-at)^2]/b^2 - 2(0)^2)^(1/2)] dt= ∫t₁^t₂ [(a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2]^(1/2) dt.

Now we can choose the value of t₁ and t₂ such that the square root in the integrand is minimized (so that the integral is path-independent).

This can be done by choosing the value of t that gives the minimum value of (a^2-b^2-c^2)t^2+2bc(c-at)+b^2c^2-a^2b^2 over the range of t from t₁ to t₂.

On differentiation with respect to t and equating to 0, we get the value of t = bc/(a^2+b^2).

Substituting this value of t in the integrand, we get the minimum value of the square root in the integrand to be |c| √(a^2+b^2)/|b|.

Thus the integral over C is given by∫C F.dr = ∫∫ (-2xz i -2yz j + (x^2+y^2-2z^2)k) ds= ∫∫ (x^2+y^2-2z^2) ds= ∫t₁^t₂ |c| √(a^2+b^2)/|b| dt= |c| √(a^2+b^2)/|b| (t₂-t₁).

Now we can see that the integral is path-independent as it depends only on the end points t₁ and t₂ and not on the path taken to reach them.

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The induced emf is -0.7205 V, calculated using Faraday's Law and the given values of magnetic field and instantaneous rate of radius change.

EMF (electromotive force) is the voltage or potential difference generated by a source, such as a battery or generator, that drives an electric current through a circuit. It is measured in volts (V).

Faraday's Law of Electromagnetic Induction states that the emf induced in a conductor is proportional to the rate of change of the magnetic field through the conductor.

According to the given information:

The induced emf in the loop can be calculated using Faraday's Law of Electromagnetic Induction, which states that the induced emf is equal to the rate of change of magnetic flux through the loop.

The magnetic flux through the loop is given by:

Φ = BAcosθ

where B is the magnetic field, A is the area of the loop, and θ is the angle between the magnetic field and the normal to the loop. In this case, since the loop is perpendicular to the magnetic field, θ = 0 and cosθ = 1.

The area of the loop is given by:

A = π*r^2

where r is the radius of the loop.

The rate of change of the area is given by:

(dA/dt) = 2πr*(dr/dt)

where (dr/dt) is the instantaneous rate at which the radius is decreasing.

Substituting these equations into Faraday's Law, we get:

emf = -dΦ/dt = -BdA/dt = -B2πr*(dr/dt)

Substituting the given values, we get:

emf = -0.900 T * 2π * 18.0 cm * (-64.0 cm/s)

emf = 720.5 mV

Therefore, the induced emf in the loop at that instant is 720.5 mV.

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Answer:

[M1 L2 T-3 I-1]

\(\\ \rm\Rrightarrow \dfrac{1}{u}+\dfrac{1}{v}=\dfrac{1}{f}\)

\(\\ \rm\Rrightarrow \dfrac{1}{u}=\dfrac{1}{-10}+\dfrac{1}{38}\)

\(\\ \rm\Rrightarrow \dfrac{1}{u}=\dfrac{-19+5}{190}\)

\(\\ \rm\Rrightarrow \dfrac{1}{u}=\dfrac{-14}{190}\)

\(\\ \rm\Rrightarrow u=\dfrac{190}{-14}\)

\(\\ \rm\Rrightarrow u=13.6cm\)

Real

In the peak of summer, it hasn't rained in a week, and the plants are looking rough, so watering the plants for an hour is a good idea.

However, the next day, you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. Plants absorb water through their roots. The root system of a plant is responsible for drawing water and nutrients from the soil. A plant's root system must be able to absorb water quickly in order for the plant to grow and thrive. When the soil around the root system is dry, the roots will stop growing and will not be able to absorb water.

It may even start to die. Watering plants during the peak of summer is important because it will help keep the soil moist and prevent the roots from drying out. However, watering a plant too much can be harmful. If a plant is overwatered, the water may not be able to penetrate the soil and reach the roots. Instead, it may just sit on top of the soil, causing the roots to rot and die. This can cause the plant to wilt and die.To summarize, if the soil around the plant is too dry, the roots may not be able to absorb the water you gave them, causing the plant to look worse than before. Conversely, overwatering can also be harmful because the water may not be able to penetrate the soil and reach the roots, causing the roots to rot and die.

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Answer:

The Sun's layers consist of the following in this order.

1) Corona

2) Transition Region

3) Chromosphere

4) Photosphere

5) Convection Zone

6) Radiative Zone

and last but not least 7) The Core

Hope this helps ;)

Answer:

1) CO2

2) CO2 and CaO

3) MgO

4) H20 and O2

5) CaCl2, CO2, H2O

Explanation:

Now let us try to put down the reactions here;

1) C(s) + O2(g) -------> CO2(g)

2) CaCO3(s) -------> CaO(s) + CO2 (g)

3) 2Mg(s) + O2(g)------> 2MgO

4) 2H2O2(aq) --------> 2H2O(l) + O2(g)

5) CaCO3(s) + 2HCl(aq) ------> CaCl2(aq) + CO2(g) + H2O(l)

Note that a chemical reaction equation is only said to be balanced when the number of atoms of each element on both sides of the reaction equation are exactly the same.

Answer:

bowling

Explanation:

bowling is an example of work because it involves hand movement.

The mass of the bullet is approximately 0.21 kg (to 2 significant figures).

We can use the principle of conservation of momentum to solve this problem. The total amount of momentum prior to and following the impact are equal.

Let the mass of the bullet be "m" kg.

The momentum of the bullet before the collision is:

p1 = m × 50 m/s = 50m

The momentum of the bullet and block after the collision is:

p2 = (m + 0.5 kg) × 15 m/s = 15(m + 0.5)

According to the principle of conservation of momentum:

p1 = p2

50m = 15(m + 0.5)

50m = 15m + 7.5

35m = 7.5

m = 7.5/35 = 0.2143 kg (rounded to 2 significant figures)

Therefore, the mass of the bullet is approximately 0.21 kg (to 2 significant figures).

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Answer: c living in a camber in an under water habitat

Explanation:

Therefore, we cannot calculate the exact time for one cycle without more information.

The time for one cycle of a planet around the Sun is determined by its orbital period, which is related to the average distance of the planet from the Sun. In this case, if the average distance of the planet from the Sun is 21 astronomical units (A.U.), we can use Kepler's Third Law to calculate the orbital period.

Kepler's Third Law states that the square of the orbital period (T) is proportional to the cube of the average distance (r) between the planet and the Sun. Mathematically, it can be expressed as:

T^2 = k * r^3

Where k is a constant.

Given that the average distance is 21 A.U., we can set up the following equation:

T^2 = k * 21^3

To solve for T, we need the value of the constant k. However, without further information or additional equations, we cannot determine the specific value of k. Therefore, we cannot calculate the exact time for one cycle without more information.

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Let's check the relationship

\(\\ \rm\hookrightarrow g=\dfrac{GM}{r^2}\)

\(\\ \rm\hookrightarrow g\propto G\)

So

Option C is wrong by now .Let's check D once

\(\\ \rm\hookrightarrow T\propto \dfrac{1}{\sqrt{g}}\)

Answer  34

Explanation:

Answer:

The dog moved 6 meters west and 34 meters total

Explanation:

Answer:

it = 5.5e-5 cm

just tyoe in on the search bar nm to cm and a calculatro comes up

Explanation:

In basin and range topography, the lowest areas are frequently occupied by a(n)  basin.

Basin and range topography is a geological feature characterized by alternating mountain ranges and elongated valleys or basins. The formation of this topography is attributed to the stretching and faulting of the Earth's crust, which leads to the uplift of mountains and the subsidence of adjacent basins.

The lowest areas in this type of topography are often occupied by basins, which are elongated depressions or low-lying regions. These basins typically collect sediment and water, forming flat or gently sloping landscapes. They can range in size from small valleys to extensive lowland areas.

The basins are important features of the basin and range topography and contribute to the unique landscape and hydrological characteristics of the region.

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The plane's speed is 450 miles per hour, and the wind speed is 50 miles per hour. This is determined by solving the equations derived from the distances and times of the flight with and against the wind.

Let's assume the speed of the plane (without considering the wind) is P, and the speed of the wind is W.

When flying into a headwind, the effective speed of the plane is reduced by the wind speed. So the equation for the outbound flight is:

P - W = 2000 miles / 5 hours

P - W = 400 miles per hour (mph)  ---(Equation 1)

When flying with a tailwind, the effective speed of the plane is increased by the wind speed. So the equation for the return flight is:

P + W = 2000 miles / 4 hours

P + W = 500 miles per hour (mph)  ---(Equation 2)

Now we have a system of two equations (Equation 1 and Equation 2) with two variables (P and W). We can solve this system to find the values of P and W.

Adding Equation 1 and Equation 2 together, we eliminate the variable W:

(P - W) + (P + W) = 400 mph + 500 mph

2P = 900 mph

P = 450 mph

Substituting the value of P back into Equation 1 or Equation 2, we can solve for W:

450 mph - W = 400 mph

W = 450 mph - 400 mph

W = 50 mph

Therefore, the plane's speed is 450 mph and the wind speed is 50 mph.

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ANSWER:

STEP-BY-STEP EXPLANATION:

The magnet is moving down with the north pole downward, and during the transition, there will be an increase in magnetic flux through the ring, which will produce the induced current through the ring.

When the bar is moved toward loop the flux will increase and the induced current will counter this flux.

The induced current tries to oppose the change in magnetic flux and this is possible just if the current direction is counterclockwise.

Result: The current direction is counterclockwise

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Option A, The magnitude of the net force acting on the object is more than 20 N.

We can find the magnitude of the net force following up on the item by utilizing the Pythagorean hypothesis.

The north force and then the east force are opposite to one another, so they can be treated as the different sides of a right triangle, and the net force is the hypotenuse.

Utilizing the Pythagorean hypothesis:

net force² = (toward the north force)² + (toward the east force)²

net force² = 10² + 10²

net force² = 200

Taking the square base of the two sides:

net force = √(200) = 14.14 N

Subsequently, the extent of the net force following up on the item is more prominent than 20 N (choice A).

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When a large truck and a small car have a head-on collision, B: "the car has the greater acceleration because it has the smaller mass".

Acceleration refers to the rate of change of velocity, reflecting that acceleration means the speed is changing. Based on the scenario when a large truck and a small car have a head-on collision, the car will exert a higger acceleration in comparison to the acceleration of the truck because the car has smaller mass.

It is because the acceleration is far greater for the lighter or smaller vehicles which would be subjected to a far greater velocity/speed change at the same time (duration of collision).

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The average force exerted by the club on the ball is 838,400 N. Force can be characterized by its magnitude, direction, and point of application.

It can be a push or pull, and it can cause an object to start moving, stop moving, or change its direction of motion.

Force is indeed a physical factor that alters or has the potential to alter an object's state at rest or motion as well as its shape. Newton is the SI unit of force.

Finally, the average force exerted by the club on the ball is:

F = I / t = (1676.8 N·s) / (0.0020 s) = 838,400 N

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The intensity of the electric current of a circuit is 123A and the electric charge is 1.7C to find the time interval in which the electric charge is transported.

Given that,

Current, I = 123 A

Electric charge, q = 1.7 C

To find,

The time interval in which the charge is transported.

Solution,

The electric current is given by electric charge per unit time. So,

\(I=\dfrac{q}{t}\\\\t=\dfrac{q}{I}\\\\t=\dfrac{1.7}{123}\\\\t=0.0138\ s\)

So, the required time is 0.0138 seconds.

Hi! The SI base unit used for measuring luminous intensity is the candela (cd).

The terms "SI," "unit," and "intensity" refer to the International System of Units (SI) as the standard for measurement, the specific unit being discussed, and the property being measured, which in this case is luminous intensity.

The intensity I, of light received at a source, varies inversely as the

  square of the distance d, from the source

→ That means I × d² = k, where k is the constant of variation

∴ I × d² = k

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Answer:

TO answer this question i need wave speed

Explanation:

Answer:

the correct answer is D

Explanation:

When the star explodes the radiation travels through empty space at the speed of light c= 3 10⁸ m/s

This speed has been experimentally proven to be constant, therefore two two instruments arrive at the same time

Therefore the correct answer is D

Answer:

Originally Answered: What is the unit of measurement of pressure in the atmosphere? The SI derived unit of pressure is the pascal , abbreviated Pa. This is a pressure exerted by a force of 1 newton acting over an area of 1m².

Explanation:

Hope this helps you a lot my boo!

The dark absorption lines on the continous spectrum represents absoprtion of some of the light before the observation of the spectrum.

The continous spectrum of helium represents the star is made up of helium.

The dark absorption lines superimposed on the sontinous spectrum represents the light from the star has passed through a cloud of helium in which helium atoms absorbs the emitted helium light from the star.

Hence, option D is a correct answer.

The study of radioactivity by Marie Curie marked a significant turning point in the realm of physics and had a significant influence on scientific knowledge. Now let's get into the specifics.

"Radioactivity" is the term Marie Curie coined to describe the phenomenon whereby materials emit radiation that can fog photographic plates. During her uranium investigation in 1896, she made this discovery. This game-changing discovery opened the door for more research into and comprehension of radioactivity, which resulted in important developments in the field of nuclear physics.

Marie Curie's research on radioactivity served as a springboard for additional nuclear physics research and has profound ramifications for other fields of science and medicine. It resulted in improvements in our knowledge of atomic structure, the creation of radiation therapy for the treatment of cancer, and the eventual exploitation of nuclear energy.

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