Answer: SEE EXPLANATION!
Explanation:
When waves travel from one medium to another the frequency never changes. As waves travel into the denser medium, they slow down and wavelength decreases. Part of the wave travels faster for longer causing the wave to turn. The wave is slower but the wavelength is shorter meaning frequency remains the same.
I hope this helps you!
Explain what the purpose of projectile motion is, and the different equations used. Explain what each equation does.
Answer:
MY friend has already described the purpose of projectile motion so I will quickly go through the uses of each equation ...
Explanation:
TIME OF FLIGHT = it is given as 2Usin tita/g...it is the total time taken to and fro...it is 2x of the time taken ....
TIME taken ..t= Usin tita / g.....is the time taken to reach the maximum height which is 1/2 the TOTALTIME OF FLIGHT GIVEN ABOVE ..
MAXIMUM HEIGHT: the maximum height is the height attained by the projectile when projected ...it is calculate using the formula = U^2 sin^2 tita / 2g
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An object launched into projectile motion will have an initial launch angle anywhere from 0 to 90 degrees. The range of an object, given the initial launch angle and initial velocity is found with: R=v2isin2θig R = v i 2 sin 2 θ i g .
What objects did harlow shapley use as signposts to figure out the extent of the milky way galaxy and the location of its center?
Harlow Shapley used Cepheid variables in globular clusters to estimate the extent of the Milky Way and its center, which he found to be in the direction of the constellation Sagittarius.
Harlow Shapley used a particular type of star known as Cepheid variables as signposts to determine the extent of the Milky Way galaxy and the location of its center. Cepheid variables are stars that pulsate in a regular pattern, with the brightness of the star directly correlated to its pulsation period.
Shapley observed these stars in globular clusters, which are dense groupings of stars in the outer reaches of the galaxy. By measuring the period of pulsation of Cepheid variables in these clusters, he was able to estimate the distance to them. He found that these clusters were distributed around the galaxy in a spherical shape, indicating that the Milky Way was much larger than previously thought.
Shapley also observed the distribution of these clusters in the night sky and found that they were more concentrated in one direction, towards the constellation Sagittarius. This led him to conclude that the center of the Milky Way was in that direction, and he was able to estimate the distance to the galactic center based on the distribution of these clusters.
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4. What is a good definition for Period?
O The height of a wave
O The distance between the high points of two waves
The middle-point of a wave
оооо
O The number of waves that occur every second
O The time it takes for one wave to go through one cycle
Answer:
D
Explanation:
The time taken for a wave to complete one circle meaning time to reach the same successive crest or through of a wave.
can someone help me with a)
Answer:
what's your problem. How may I help you Buddy
why discharge does not take place at very low pressure
Answer:
read explanation
Explanation:
Due to this reason a gas (air) a conductor of electricity at low pressure. ... It is because when the gas is at very low pressure positive charged ions are not available to eject out the electron from the cathode hence the discharge current stops.No, vacuum cannot conduct electricity.
Describe some things that Ye-Jun could do each day to increase the healthiness of his lifestyle.
Answer:
Eat more healthy foods and keep more active.
Explanation:
Ideas for uniform circular motion?This is for a physics lab if u can help please do
The time of motion of the satellite is 1.65 hours. The speed of the satellite from the centre of the Earth is 26,945.35 km/h.
What is the time of motion of the satellite?This is the motion of an object in which the object travels in a straight line and its velocity remains constant along that line as it covers equal distances in equal intervals of time, regardless of time duration.
The time of motion of the satellite in hours is calculated as follows;
t = ( 99 min / 1 ) x ( 1 hour / 60 min )
t = 1.65 hours
The speed of the satellite from the centre of the Earth in km/h is calculated as follows;
v = ( 2πr ) / ( t )
where;
r is the distance of the satellite from the centre of the Earth
The position of the satellite above the surface of the Earth = 705 km
The radius of Earth = 6,371 km
The total distance of the satellite from the centre of the Earth = 705 km + 6,371 km = 7,076 km
v = ( 2π x 7076 ) / ( 1.65 )
v = 26,945.35 km/h
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The complete question is attached with the answer below.
Why does the chlorine atom have a partial negative charge in a molecule of hydrogen chloride?
Answer:The molecule is represented by the conventional Lewis structure, even though the shared electron pair is associated to a larger extent with chlorine than with hydrogen. The unequal sharing of the bonding pair results in a partial negative charge on the chlorine atom and a partial positive charge on the hydrogen atom.
Explanation:
A material kept at high temperature is seen to emit photons with energies of 0.3 eV, 0.5eV, 0.8 eV, 2.0 eV, 2.5 eV, and 2.8 eV. These are the only photon energies observed. It is now cooled down to a very low temperature so that it is not emitting photons anymore. If a beam of light with a continuous range of energies from 0.01 eV to 10 eV shines on the material, what photon energies in this beam will correspond to dark absorption lines?
1. 0.3 eV, 0.5 eV, 2.8 eV
2. 0.3 eV, 0.5 eV, 0.8 eV
3. 0.3 eV, 0.8 eV, 2.8 eV
4. 0.8 eV, 2.0 eV, 2.8 eV
5. 0.5 eV, 0.8 eV, 2.8 eV
6. 0.3 eV, 2.5 eV, 2.8 eV
Answer:
the correct one is 2
Explanation:
The emission and arcion spectra are similar, in the emission spectra a heated material emits photons for the internal transitions of the electrons, in the absorption spectrum the continuous emission of a lamp is absorbed at the energies that the material has transitions.
In our case the material is low early, so all the electrons are in their base states.
As the light beam has all wavelengths, those corresponding to the first emission of the material will be observed.
When reviewing the answers, the correct one is 2
Un globo es inflado hasta obtener 1.5 atm, con un volumen de 500 cm³ a 273 K. Luego, es colocado en el frezzer ¿Cuál será su temperatura, con 1.2 atm y 300 cm³?
Respuesta: T2 = 131.04K
Explicación: Dado lo siguiente:
Presión, P1 = 1.5 atm = 1.5 × 760 = 1140 mmHg
Presión, P2 = 1.2 atm = 1.2 × 760 = 912 mmHg
Volumen, V1 = 500cm3 Volumen, V2 = 300cm3
Temperatura, T1 = 273K Temperatura, T2 =?
Usando la fórmula de gas combinada:
P1V1 / T1 = P2V2 / T2
Ingresando nuestros valores:
(1140 × 500) / 273 = (912 × 300) / T2
T2 × (1140 × 500) = 912 × 300 × 273
T2 = 74692800/570000 T2 = 131.04K
Velocity time graph question. What is the position of the dog at t = 3 s, what is the velocity of the dog for interval A. and what is the average velocity of the dog over intervals A and B?
Given:
The position and the time graph of a dog is shown in the figure given in the question.
To find:
the position of the dog at t=3 s, velocity of the dog for interval A, and the average velocity of the dog over intervals A and B.
Explanation:
The position of the dog at t=3 s, is,
\(y=8\text{ m \lparen from graph\rparen}\)The final position after interval A is,
\(8\text{ m}\)The initial position before the interval A is,
\(5\text{ m}\)The velocity for the interval A is,
\(\begin{gathered} \frac{The\text{ displacement}}{The\text{ time interval}} \\ =\frac{8-5}{2-0} \\ =\frac{3}{2} \\ =1.5\text{ m/s} \end{gathered}\)The change in position at interval B is 0, so the velocity at interval B is 0.
The average velocity over the interval A and B is,
\(\begin{gathered} \frac{The\text{ velocity at interval A+The velocity at interval B}}{2} \\ =\frac{(1.5)+\text{0}}{2} \\ =\frac{1.5}{2} \\ =0.75\text{ m/s} \end{gathered}\)Hence, the position of the particle after the required time is 8 m, The velocity after interval A is 1.5 m/s, and the average velocity over the interval A and B is 0.75 m/s.
The position of the dog at time 't' is 3 meters, the velocity of the dog at interval A is 1.5 meters per second and the average velocity of the dog is 0.75 meters per second.
The velocity time graph of the dog at time ' t' is given to us.
We need to find,
The position at time t = 3 second,
The velocity of the dog at interval A, and
The average velocity of the dog over intervals A and B.
According to the given in the graph,
The position of the dog at time 't' = 3 seconds is 8 meters.
The position of dog at interval A = 5 meter and the position of the dog at interval B = 8 meters.
Therefore, the position of the dog from the graph in these intervals is
8-5 = 3meters.
and time = 2-0 = 2 seconds.
Therefore, the velocity = 3/2 = 1.5 meter per second.
The average between the intervals A and B is,
1.5 + 0/ 2 = 1.5/ 2
= 0.75 meter per seconds.
Therefore, the position is the dog at time 't' is 3 meters, the velocity of the dog at interval A is 1.5 meters per second and the average velocity of the dog is 0.75 meters per second.
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What is the current in a 160V circuit if the resistance is 5Ω?
Answer:
32A
Explanation:
So, 160=1*5
I = 160/5
=32 ampere
If there is 3.4 m3 of methane gas in a container with a pressure of 18.9 atm and the container expands until the methane has a pressure of 2.2 atm, what is the final volume of the methane? Temperature is constant at 305 K. A. 12.23 m3 B. 141.37 m3 C. 29.21 m3 OD. 2.53 m3
Answer:
C. 29.21 m³
Explanation:
Given the following data;
Initial volume, V1 = 3.4 m³Initial pressure, P1 = 18.9 atmFinal pressure, P2 = 2.2 atmTo find the final volume, we would use Boyle's law;
Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.
Mathematically, Boyles law is given by;
PV = K
\( P_{1}V_{1} = P_{2}V_{2} \)
Making V2 the subject of formula, we have;
\( V_{2} = \frac {P_{1}V_{1}}{P_{2}} \)
Substituting the values into the formula, we have;
\( V_{2} = \frac {18.9 * 3.4}{2.2} \)
\( V_{2} = \frac {64.26}{2.2} \)
Final volume, V2 = 29.21 m³
Water has a density of 1 gm/cm3. What would be the mass (in gms)
of 25 cm3 of water?
a) 10
b) 25
c) 30
d) 15
The density of water is 1 g/cm³, and we need to find the mass of 25 cm³ of water. The correct option is b.
We can use the formula:
Density = Mass / Volume
Rearranging the formula, we get:
Mass = Density x Volume
Thus, substituting the given values in the above formula, we get:
Mass = 1 g/cm³ x 25 cm³ = 25 g
Therefore, the mass of 25 cm³ of water is 25 grams.
This is because the density of water is 1 gm/cm3. As such, multiplying the density by the volume, gives us the mass of water. Hence, the mass of 25 cm3 of water is 25 grams or 25000 milligrams or 0.025 kilograms. The correct option is b) 25.
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a 2 kg solid ball (solid like a bowling ball) is rolling down a horizontal street at 7.5 m/s. what is its total kinetic energy? note: you can find moments of inertia in the reading.
Thus, the total kinetic energy of the solid ball rolling down the horizontal street at 7.5 m/s is 78.75 J.
To calculate the total kinetic energy of the solid ball, we need to use the formula:
KE = 0.5 * I * w^2
where KE is the kinetic energy, I is the moment of inertia, and w is the angular velocity.
Since the ball is rolling down a horizontal street, it has both translational and rotational kinetic energy. To find the total kinetic energy, we need to add these two energies together.
The translational kinetic energy is given by:
KE_t = 0.5 * m * v^2
where m is the mass of the ball and v is its velocity. Plugging in the values given in the question, we get:
KE_t = 0.5 * 2 kg * (7.5 m/s)^2 = 56.25 J
To find the rotational kinetic energy, we need to calculate the moment of inertia of the solid ball. According to the reading, the moment of inertia of a solid sphere is:
I = 2/5 * m * r^2
where r is the radius of the sphere. Since the question doesn't give us the radius of the ball, we can't calculate the moment of inertia directly. However, we can use the fact that the ball is rolling without slipping to relate its linear velocity to its angular velocity.
The relationship between linear velocity and angular velocity is:
v = r * w
where v is the linear velocity, r is the radius, and w is the angular velocity. For a rolling ball, the linear velocity at the bottom of the ball is equal to the angular velocity times the radius:
v = r * w = 7.5 m/s
This allows us to find the radius of the ball:
r = v / w = 7.5 m/s / w
Now we can use the moment of inertia formula to find the rotational kinetic energy:
KE_r = 0.5 * I * w^2 = 0.5 * 2/5 * m * r^2 * (v / r)^2 = 0.2 * m * v^2
Plugging in the values given in the question, we get:
KE_r = 0.2 * 2 kg * (7.5 m/s)^2 = 22.5 J
Finally, we can find the total kinetic energy by adding the translational and rotational kinetic energies:
KE_total = KE_t + KE_r = 56.25 J + 22.5 J = 78.75 J
Therefore, the total kinetic energy of the solid ball rolling down the horizontal street at 7.5 m/s is 78.75 J.
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Your body image is directly linked to your personal _________.
Group of answer choices
intelligence
weight
identity
IQ
Answer:
identity is the correct answer....
Which of the following statements about this experiment is FALSE? You may assume the collision between the bob and the box is completely inelastic. Before each trial one should reshape the bob into something like a ball. The initial position for the box should be just touching the pendulum bob when it is hanging straight down. To make the box move, the pendulum bob should hit close to the bottom of the box during the collision. Use the figure to answer the rest of the questions. If A = 34 cm and the pendulum bob diameter is 2.6 cm, what is the appropriate height difference magnitude to use for evaluating the change in potential energy of the pendulum bob-earth Suppose B = 20 cm. The distance traveled by the box, modeled as a point particle, is: Suppose the friction force between the table and the box is 0.26 N and B = 20 cm. What is the work done by friction on the box?
The statement "before each trial one should reshape the bob into something like a ball" is false regarding the experiment.
The shape of the bob has no bearing on the length of the plumb bob or the collision impact of the bob on the box, if we assume that the collision between the bob and the box is fully inelastic. The second, which states that the box's initial location should be just touching the pendulum bob, is accurate. This is so that the bob's initial location, which will then become its mean position, will be where it is at its maximum kinetic energy.
The final claim, that in order for the box to move, the pendulum bob must make contact with it close to the bottom, is likewise accurate. This is due to the fact that the bottom surface encounters the greatest degree of friction, which can be significantly lessened if bobs contact closer to the bottom.
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Can someone answer 1 2 3 4 6
A stone is thrown horizontally at 15 m/s from the top of a cliff 44 meters high. How far from the base does the stone hit the ground?
Answer:
44.9 m
Explanation:
For ballistic motion in x-y coordinates, an appropriate equation can be ...
y(x) = -4.9(x·sec(α)/v)² +tan(α)x + h0
where α is the angle of launch from the horizontal, and v is the magnitude of the launch velocity.
Here, we have v = 15 m/s, and α = 0, so the equation reduces to ...
y = -4.9/225x^2 +44
For y = 0, we can find x to be ...
x^2 = (44×225/4.9) ≈ 2020.41
x ≈ 44.949
The stone hits the ground about 44.9 meters from the base of the cliff.
in the current simulation the volume flow rate is 5000l/s or 5m^3/sec. this means that 5 cubic meters of water are passing throgh the pipe in a second. the density of the water is 1000kg/m^3. what is the volume that flows through the pipe in 6 seconds
The volume that flows through the pipe in 6 seconds is 30 cubic meters, and the mass of the water is 30000 kg.
If 5 cubic meters of water pass through the pipe in 1 second, then in 6 seconds, the volume that flows through the pipe would be:
5 m^3/s * 6 s = 30 m^3
To find the mass of the water that flows through the pipe, we can use the density of water:
mass = density * volume
mass = 1000 kg/m^3 * 30 m^3 = 30000 kg
So, the volume that flows through the pipe in 6 seconds is 30 cubic meters, and the mass of the water is 30000 kg.
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How to change a flat tire presentation?
Having a flat tire is one of the predominant inconveniences of riding. A guide car jack is designed to raise the vehicle high sufficient to eliminate the flat tire.
Converting a tire is definitely an alternative bodily trauma. we need to place a few muscles in getting the lug nuts off and cranking the jack, after which you need to bend down and lift the tire. regularly, oldsters will try to do all of this in a rush to get on their way, however, it really is a mistake.
To change eliminate the flat tire. The following steps should be followed:-
A spare tire. A lug wrench or torque wrench.Wheel wedges.A transportable tire inflator.A tire gauge to read the endorsed tire strain.Having a flat tire is one of the predominant inconveniences of riding. while a terrific spare is unavailable, you both have to call a tow truck or repair the tire ourselves. luckily, the process of fixing it yourself is noticeably sincere and requires only a few gears.
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The potential energy of an apple is 6.00 joules. The apple is 3.00-meters high. What is the mass of the apple?
Answer:
\(pe = mgh\)
from
pe=mghm=pe÷(gh)take g=9.8m=6÷(9.8×3)
m=0.2g
What is the difference between an object with a constant accleration and a constant velocity?
a. There is no difference between constant velocity and constant acceleration.
b. If an object has a constant velocity it will not have an acceleration- the velocity does not change. A constant acceleration means an objects velocity will increase or decrease by the same amount in each interval of time.
c. If an object has a constant acceleration it will not have a velocity. A constant velocitty means an object will increase or decrease displacement by the same amount in each interval of time
d. If an object has a constant acceleration on a velocity vs time graph the slope of the line will = zero.
To summarize, an object moving in uniform circular motion is moving around the perimeter of the circle with a constant speed. While the speed of the object is constant, its velocity is changing. Velocity, being a vector, has a constant magnitude but a changing direction.
can u figure it out from there but if anything i think it is C
To summarize, an object moving in uniform circular motion is moving around the perimeter of the circle with a constant speed. While the speed of the object is constant, its velocity is changing. Velocity, being a vector, has a constant magnitude but a changing direction.
can u figure it out from there but if anything i think it is C
When a meteor enters the Earth's atmosphere, three forces act on the meteor. Gravity and upthrust are two of these forces. Give the name of the other force. [1 mark]
Answer:
The other force acting on a meteor as it enters the Earth's atmosphere is air resistance or drag force.
Explanation:
Air resistance or drag force is the force that opposes the motion of an object as it moves through a fluid (such as air or water). When a meteor enters the Earth's atmosphere, it encounters a large amount of air resistance due to the high speed at which it is moving relative to the atmosphere.
As the meteor moves through the atmosphere, air molecules collide with the meteor, creating a resistance force that acts in the opposite direction to the meteor's motion. This force increases as the meteor's speed increases, and can cause the meteor to slow down and heat up due to friction with the surrounding air molecules.
The force of air resistance is particularly important for meteors because they are typically travelling at very high speeds relative to the atmosphere, and can experience significant heating and deceleration as they enter the denser lower atmosphere. Without air resistance, meteors would continue to travel at their original speeds and would not experience the bright trails or fireballs that are commonly associated with meteors.
A force of 150 N is exerted 22° north of east. What is the
eastward component of this force?
a ) 120 N
B) 139 N
C ) 108 N
D ) 98 N
Answer: B
Explanation:
Choose ALL that apply: Read the story below and choose every sphere shown directly in the story. A volcano erupts on a mountain side. It creates a huge cloud of smoke and ash which block out the sun, making it harder for plants to grow.
Question 3 options:
Biosphere
Geosphere
Hydrosphere
Atmosphere
Answer:
biosphere
Explanation:
pretty sure bc it is ground
the energy of a photon is 7.05 × 10−20 j. what is its wavelength (in nanometers)?
The wavelength of a photon with an energy of 7.05 × 10^-20 J is approximately 299.7 nm.
The energy of a photon is related to its wavelength by the equation:
E = hc/λ
where E is the energy of the photon, λ is its wavelength, h is Planck's constant, and c is the speed of light. To find the wavelength of a photon with an energy of 7.05 × 10^-20 J, we can rearrange this equation to solve for λ:
λ = hc/E
Substituting the given values, we get:
λ = \((6.626 \times 10^-34) \times\frac{(2.998 \times 10^8 )}{ (7.05 \times 10^-20 )}\)
Simplifying the expression, we get:
λ = 2.997 × 10^-7 m
To convert this value to nanometers, we can multiply by 10^9 nm/m, giving:
λ = 299.7 nm
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The S.I. unit of E is NC^-1 and that of B is NA^-1 m^-1, then unit of E/B is
The S.I. unit of E is NC^-1 and that of B is NA^-1 m^-1, then unit of E/B is A m/C (ampere meter per coulomb). This unit represents the ratio between the electric field and the magnetic field, indicating the strength and direction of the electromagnetic field.
The SI unit of electric field (E) is NC^(-1) (newton per coulomb) and the SI unit of magnetic field (B) is NA^(-1) m^(-1) (tesla). To determine the unit of E/B, we need to divide the unit of E by the unit of B.
Dividing the unit of E (NC^(-1)) by the unit of B (NA^(-1) m^(-1)), we can simplify the expression:
E/B = (NC^(-1))/(NA^(-1) m^(-1))
To simplify this expression, we can cancel out the common units in the numerator and denominator:
E/B = (N/C)/(N/(A m))
Now, let's simplify further by dividing the numerator and denominator:
E/B = (N/C) * (A m/N)
Canceling out the common units:
E/B = (A m)/(C)
Therefore, the unit of E/B is A m/C (ampere meter per coulomb).
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Which frequency would be the third harmonic in a series for an open-pipe resonator if the fundamental is 440 Hz
Answer:
1320 Hz
Explanation:
The third harmonic is given as 3fo, where fo is the fundamental frequency.
The fundamental frequency is the lowest frequency that can occur in a pipe. In an open pipe, both even and odd harmonics occur which are multiples of the fundamental frequency fo. Hence the harmonics in an open pipe are; 2fo, 3fo,4fo..... etc.
For the third harmonic; 3fo = 3 (440 Hz) = 1320 Hz
A 75-kg man stands on his toes by exerting an upward force through the Achilles tendon, as in Figure 9.43. (a) What is the force in the Achilles tendon if he stands on one foot? (b) Calculate the force at the pivot of the simplified lever system shown—that force is representative of forces in the ankle joint.
707.25N is representative of forces in the ankle joint.
Which equation is used to determine force?
Force (N) = mass (kg) x acceleration (m/s2) is a concise expression for it. In light of this, an object with constant mass accelerates in direct proportion to the force exerted. Newton's second equation of motion provides the definition of the force formula: F = m a, where m is the mass of the object and an is its acceleration. This formula requires the use of SI units for force (in Newtons), mass (in kilograms), and acceleration (in meters per second squared).
Newton's second equation of motion provides the definition of the force formula: F = m a, where m is the mass of the object and an is its acceleration.
75 × 9.43 = 707.25N.
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