What happens to potential energy as the car goes up the hill?

Answer:

What natural disasters could be associated with this storm in coastal regions?

• wave surges

• tides and tsunami.

What would be the best emergency action plan?

• Evacuation of the current residents.

What would be a safe evacuation route if needed?

• in the attachment

Answer:

Natural disasters that could be associated with this storm in coastal regions could include wave surges, tides, and tsunamis. The best emergency action plan under these circumstances would be the evacuation of residents in the at risk areas. The best evacuation routes depend on where residents and/or tourists are coming from. Residents north of I-164 should take 1-64 West, toward Richmond. Residents south of I-264 and oceanfront residents/tourists should take I-264 to 1-64 East, toward Suffolk.

Explanation:

For general projectile motion with no air resistance, the horizontal component of a projectile's acceleration is always zero.

The horizontal component of a projectile's acceleration is always zero in ordinary projectile motion with no air resistance. This is because there is no horizontal force exerted on the projectile once it is in motion.

The only horizontal force acting on the projectile is its initial velocity, which remains constant throughout its travel.

As a result, the horizontal component of acceleration remains zero throughout the projectile's trajectory.

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The input impedance of the circuit is approximately Zin = 67.71 - j × 143.95 Ω.

Given the circuit diagram for the transmission line and the provided values:

Let's calculate the characteristic impedance and input impedance at different points:

Characteristic Impedance:

The characteristic impedance of the transmission line is given by:

Z0 = √(L3 / C3)

    = √(247.4e-9 / 98.95e-12)

   = 224.81 Ω

1) Input Impedance at Point 1:

Using the formula:

Zin1 = Z0 / (j × tan(β × l1))

where

β = (2πf) / √(L1 × C1) and

f = 10 GHz

Substituting the given values:

β = (2π × 10^10) / √(494.8e-9 × 49.48e-12)

   = 2.1383

Zin1 = Z0 / (j × tan(2.1383 × 20.21e-3))

Zin1 = 224.81 / (j × tan(0.04338))

Zin1 ≈ 178.87 + j × 109.74 Ω

Input Impedance at Point 2:

Using the formula:

Zin2 = Zin1 + j × Z0 × tan(β × l2)

Substituting the given values:

Zin2 = 178.87 + j × 109.74 + 224.81 × tan(2.1383 × 5.053e-3)

Zin2 ≈ 73.21 + j × 137.89 Ω

Input Impedance at Point 3:

Using the formula:

Zin3 = (Zin2 + Z0 × tan(β × l3)) / (1 + j × Zin2 / (Z0 × tan(β × l3)))

Substituting the given values:

Zin3 = (73.21 + j × 137.89 + 224.81 × tan(2.1383 × 20.21e-3)) / (1 + j × (73.21 + j × 137.89) / (224.81 × tan(2.1383 × 20.21e-3)))

Zin3 ≈ 67.71 - j × 143.95 Ω

Hence, the input impedance of the circuit is approximately Zin = 67.71 - j × 143.95 Ω.

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Answer:

125,000

Explanation:

The thermal capacitance of the coil is neglected with respect to the tank wall and the tank liquid. Energy balance is done only on the tank liquid. Option C is the correct answer.

The consequence of neglecting the thermal dynamics of the cooling coil in a stirred tank can vary depending on the specific situation and the magnitude of the neglected effects. However, in general, neglecting the thermal capacitance of the cooling coil in relation to the tank wall and the tank liquid can have the following consequences:

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The total time the bullet is in contact with the board is 8 x 10^-5 seconds

V1 = 400ms − the initial velocity of the bullet;

V2 = 300 ms− final velocity of the bullet;

d = 10cm = 0.1m − thickness of the board;

a − acceleration inside the board.

t − total time that the bullet is in contact with the board

To find the total time that the bullet is in contact with the board we can use formula :

t =  V1 -V2 / a

where a has been found to be 1.25 x 10^6 m/s²

Substituting the values, we have that total time that the bullet is in contact with the board = 8 x 10^-5 seconds

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Answer:

8.158 Kilograms Force

Explanation:

Answer:

8.1577297038

Explanation:

pls give brainlest

Answer:

gas moves around the most so it would have the most kinetic energy and solids would have the least as they only vibrate a tiny bit(not visible to the naked eye)

Answer:

the mass of the car is very big

Explanation:

its heavy

Answer:A

Explanation

B a compound can ha e the same properties as it’s elements

C water is H2O- Hydrogen and oxygen

D water is the most common compound

Therefore A must be correct

If silicon-28 becomes silicon-29, we know that it gained a neutron and not a proton because all isotopes have same atomic number but different atomic mass.

Number of protons = Atomic number

So, even though the isotopes of silicon differ, the atomic number is same for all the isotopes. So number of protons is neither gained nor lost in different isotopes of the same element.  

Atomic mass = Number of Protons + Number of Neutrons

Number of Neutrons = Atomic mass - Number of  Protons

Since the atomic mass differs for different isotopes, the number of neutrons varies in different isotopes.

Therefore, if silicon-28 becomes silicon-29, we know that it gained a neutron and not a proton because all isotopes have same atomic number but different atomic mass.

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To find the volume of a three-dimensional symmetrical shape using integration, we can use the method of cylindrical shells. This method involves dividing the shape into thin cylindrical shells and then integrating their volumes.

Let's say we have designed a symmetrical solid in the shape of a sphere with a cylindrical cavity running through its center. We will place the flat side (R) of the sphere against the x-y plane. The sphere will be revolving around the z-axis since it is symmetrical about that axis.

To find the volume, we first need to determine the equations for the sphere and the cavity.

The equation for a sphere centered at the origin with radius R is:

x^2 + y^2 + z^2 = R^2

The equation for the cylindrical cavity with radius r and height h is:

x^2 + y^2 = r^2,  -h/2 ≤ z ≤ h/2

The volume of the solid can be found by subtracting the volume of the cavity from the volume of the sphere. Using the method of cylindrical shells, the volume of each shell can be calculated as follows:

dV = 2πrh * dr

where r is the distance from the axis of rotation (the z-axis), and h is the height of the shell.

Integrating this expression over the appropriate range of r gives the total volume:

V = ∫[r1, r2] 2πrh * dr

where r1 and r2 are the radii of the cavity and the sphere, respectively.

Substituting the expressions for r and h, we get:

V = ∫[-h/2, h/2] 2π(R^2 - z^2) dz - ∫[-h/2, h/2] 2π(r^2 - z^2) dz

Simplifying and evaluating the integrals, we get:

V = π(R^2h - (1/3)h^3) - π(r^2h - (1/3)h^3)

V =  πh( R^2 - r^2 ) - (1/3)πh^3

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Answer:

negative acceleration of 4 m/s2

Explanation:

The final speed of both playdoughs which stick together after the collision is 0.5 m/s

The mass of the first playdough = 0.5 kg

The mass of the second playdough = 0.25 kg

The initial speed of the first playdough =  1.5 m/s

The initial speed of the second playdough = 2 m/s

The final speed of both playdoughs can be found using the formula,

       m₁u₁ + m₂u₂ = (m₁ + m₂) v

where m₁,m₂ is the mass of the first and second playdough respectively

           u₁,u₂ is the initial speed of the first and second playdough respectively

           v is the final speed of both playdough

Let us substitute the known values in the above equation, we get

          0.5 x 1.5 + 0.25 x 2 = (0.5 + 0.25) v

                         0.75 x 0.5 = 0.75v

                                  0.375 = 0.75v

                                         v = 0.375 / 0.75

                                            = 0.5 m/s

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The width of the slit is 0.212 mm.

The wavelength of light is defined as “The distance between the two successive crests or troughs of the light wave”.

We know that the distance between minima is given by :

                                       \(t = (m_{f} - m_{i} ) \alpha x/d\)

where, t = distance between minima

            \(\alpha =\) wavelength

            x = distance of screen

            d = width of slit

            \((m_{f} - m_{i} ) =\) difference between minima

Given, x = 40 cm = 0.4 m

           \(\alpha = 690 nm = 690 * 10^{-9} m\)

           t = 2.60 mm = \(2.60 * 10^{-3} m\)

           \((m_{f} - m_{i} ) =\) 3 -1 = 2

Putting these values in above equation we get d = 0.212 mm

So the width of the slit is 0.212 mm.

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The force exerted by the rain on the patch is 0.231 N.

The force exerted by the raindrops on the patch can be found using the formula; F = m × v

where F will be the force, m will be the mass of each raindrop, and v is velocity of each raindrop.

The mass of each raindrop is given as 1.1 grams, which can be converted to kilograms by dividing by 1000;

m = 1.1 g / 1000 = 0.0011 kg

The velocity of each raindrop is given as 6 m/s.

Now, we need to determine the number of raindrops that strike the patch in one second. If the patch is receiving 35 raindrops per second, then the number of raindrops that strike the patch in one second is also 35.

Therefore, the total force exerted by the rain on the patch is;

F = m × v × n

where n will be the number of raindrops per second.

Plugging in the values, we get;

F = 0.0011 kg × 6 m/s × 35

F = 0.231 N

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Answer:

yes it is right because it helps us in global warming and to decrease in high population growth

Explanation:

i am not a teacher but i know thar using burning fossil fuel is harm for human beings and using renewable resiure maintain environment and our life in future generation

Answer:3 go to 2 and 4 go to 4 and 1 go 2 2 go to 1

Explanation:

Answer:

C. Increasing the vertical height from which the ball is thrown.

Explanation:

In this case, we understand that ball experiments a parabolical motion, which is the combination of horizontal uniform motion and vertical uniform accelerated motion, due to gravity. Equations of motion for the ball are described below:

\(x = x_{o}+v_{o,x}\cdot t\) (Eq. 1)

\(y = y_{o} + v_{o,y}\cdot t +\frac{1}{2}\cdot g\cdot t^{2}\) (Eq. 2)

Where:

\(x_{o}\), \(x\) - Initial and final horizontal positions, measured in meters.

\(y_{o}\), \(y\) - Initial and final vertical positions, measured in meters.

\(v_{o,x}\), \(v_{o,y}\) - Initial horizontal and vertical velocities, measured in meters per second.

\(g\) - Gravitational acceleration, measured in meters per second.

\(t\) - Time, measured in seconds.

Now we get (Eq. 2) and solve the expression for the time:

\(\frac{1}{2}\cdot g\cdot t^{2}+v_{o,y}\cdot t + (y_{o}-y) = 0\)

\(t = \frac{-v_{o,y}\pm\sqrt{v_{o,y}^{2}-2\cdot g \cdot (y_{o}-y)}}{g}\)

If \(v_{o,y} > 0\), \(g < 0\) and \(y_{o} -y < 0\), then maximum time occurs when:

\(t = \frac{-v_{o,y}+ \sqrt{v_{o,y}^{2}-2\cdot g \cdot (y_{o}-y)}}{g}\)

And,

\(v_{o,y}^{2}-2\cdot g\cdot (y_{o}-y)\geq 0\).

If \(y_{o}\) is increased, then \(y_{o} - y\) goes closer to zero and \(v_{o,y}^{2}-2\cdot g\cdot (y_{o}-y)\) becomes greater and time increased. Hence, we conclude that correct answer is C.

Answer:

your girl is very very very very very very very pretty

Answer:

very very pretty

Explanation:

Answer:

Explanation:

Momentum is equal to mass times velocity in kg and m/s, respectively. Therefore,

p = 100(15) so

p = 1500 \(\frac{kg*m}{s}\)

The cart A experienced the greatest impulse.

The given parameters;

Impulse is defined as the product of the applied force  and time of action of the applied force.

J = Ft

where;

J is the impulse

F is the applied force

t is the time of action

The impulse experienced by cart A;

J = 2 x 2 = 4 Ns

The impulse experienced by cart B;

J = 1 x 3 = 3 Ns

Thus, the cart A experienced the greatest impulse.

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Stopping from 55 mph requires the most work done by the brakes of a car.

Hence, the correct option is B.

When a car slows down or comes to a complete stop, the work done by the brakes is directly related to the change in kinetic energy of the car. The kinetic energy of an object is given by the equation:

Kinetic energy = (1/2) * mass * \(velocity^2\)

Comparing the options:

A. Slowing down from 80 mph to 55 mph: In this case, the car is experiencing a decrease in velocity, resulting in a decrease in kinetic energy. However, the change in kinetic energy is less compared to option B.

B. Stopping from 55 mph: In this case, the car comes to a complete stop, resulting in a significant decrease in velocity and a substantial change in kinetic energy. The brakes need to dissipate the entire kinetic energy of the car, requiring the most work.

C. Equal amounts of work for both: This option is incorrect. Slowing down from a higher speed to a lower speed (option A) requires less work than coming to a complete stop (option B). The work done by the brakes is directly proportional to the change in kinetic energy, and stopping from a higher speed involves a greater change in kinetic energy.

Therefore, Stopping from 55 mph requires the most work done by the brakes of a car.

Hence, the correct option is B.

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The transfer function is Vc(s)/Vs(s) = (R + 1/(sC)) / (sL + R + 1/(sC)), the pole-zero map includes poles at -R/L and zeros at -1/(sC), the response to Vs(t) = u(t)V can be calculated using inverse Laplace transform techniques and the response to Vs(t) = o(t)V can also be determined using inverse Laplace transform techniques.

To find Vc(s)/Vs(s), we need to consider the given electrical system with components R, L, and C. By applying Kirchhoff's laws and solving for the output voltage Vc(s) and input voltage Vs(s) in the Laplace domain, we can derive the transfer function as (R + 1/(sC)) / (sL + R + 1/(sC)).

The pole-zero map provides insights into the stability and behavior of the system. In this case, the transfer function has poles at -R/L, indicating a time constant associated with the system's dynamics. The transfer function also has zeros at -1/(sC), which affect the frequency response characteristics.

To find the response to Vs(t) = u(t)V, where u(t) represents the unit step function, we can apply inverse Laplace transform techniques to the transfer function Vc(s)/Vs(s). This will yield the time-domain response of the system to a step input.

Similarly, to find the response to Vs(t) = o(t)V, where o(t) represents the unit impulse function, we can use inverse Laplace transform techniques on the transfer function Vc(s)/Vs(s). This will give us the time-domain response of the system to an impulse input.

By calculating the inverse Laplace transforms of the transfer functions in cases 3) and 4), we can obtain the time-domain responses of the electrical system to the respective inputs.

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If both the bottom and one side of the loop were placed in the magnetic field (but not the top or other side), the net direction of the force upon this loop would be upwards.

When an electric current flows through a wire in a magnetic field, a magnetic force is generated on the wire. This force is perpendicular to both the direction of the current and the direction of the magnetic field, according to Fleming's Left-Hand Rule. In the scenario described in the question, the current is flowing through the wire on one side of the loop and not on the other side. As a result, the magnetic force will act on the side of the loop where the current is flowing, in a direction perpendicular to both the current and the magnetic field. This will cause the loop to move upwards, as the force acting on the side of the loop will be greater than the force acting on the bottom. Therefore, the net direction of the force upon this loop will be upwards.

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Answer:

kenitec energy

Explanation:

because kinetic and mass have same

Answer:

The answer is "Y → X → Z".

Explanation:

In this question, the chart is missing and the question is not complete that's why we search this question and only give its correct answer that's is defined above, and please find the complete question in the attached file.