What's the kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s?
Question 16 options:
A)
12,000 J
B)
2,940 J
C)
6,000 J
D)
5,880 J
the kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s is 6,000 J. Option C is correct answer.
The kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s can be calculated by using the formula:
K.E = 1/2 mv²
Where, K.E = Kinetic energy of the objectm = Mass of the objectv = Velocity of the object
Putting the given values in the above formula:
K.E = 1/2 mv²K.E = 1/2 × 30 kg × (20 m/s)²K.E = 1/2 × 30 × 400K.E = 6000 joules
The correct answer is C.
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Jamal has a bowl of ice cream. He leaves it in the sun for too long and it melts into a liquid. Jamal then places the liquid ice cream into a freezer that is set at 5°F.
Which of the following best explains how the liquid ice cream will change in the freezer?
Answer:
It will turn back into a solid but it will take some time.
Explanation:
HI PLEASE HELP ON QUESTION ASAP I ALREADY KNOW ANSWER =75 IF ANSWER IS CORRECT, ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST!
BUT how do i work it out in an exam so exam marker knows what your doing
2)the mean of 6 numbers is 25. If one of the remaining numbers is removed, the average of the remaining numbers is 15. What is the number that was removed?
The mean of 6 numbers is 25. If one of the remaining numbers is removed, the average of the remaining numbers is 15. The number that was removed is 75.
To solve this problem, we can use the concept of the mean (average) and apply it to the given information. Let's go through the steps to determine the number that was removed.
Step 1: Find the sum of the 6 numbers.
Since the mean of the 6 numbers is 25, we can multiply the mean by the total number of values to find the sum. In this case, 25 * 6 = 150.
Step 2: Find the sum of the remaining numbers.
To find the sum of the remaining numbers, we need to subtract the number that was removed from the original sum. Let's denote the number that was removed as "x". Therefore, the sum of the remaining numbers is 150 - x.
Step 3: Determine the number of remaining numbers.
Since one number was removed, the total number of remaining numbers is 6 - 1 = 5.
Step 4: Calculate the average of the remaining numbers.
We are given that the average of the remaining numbers is 15. To find the sum of the remaining numbers, we can multiply the average by the number of remaining numbers. Therefore, 15 * 5 = 75.
Step 5: Set up the equation and solve for the removed number.
Now we can set up the equation using the information from Steps 2 and 4. We have the equation: 150 - x = 75.
Step 6: Solve the equation.
To find the value of x, we can solve the equation. Subtracting 75 from both sides gives us 150 - 75 = x, which simplifies to x = 75.
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How much power does it take to lift 30.0 N 10.0 m high in 10.00 s?
Answer:
60w
Explanation:
The power required is 30 Watt.
Let us recall that power is defined as the rate of doing work. Hence, we can write as follows;
Power = Work done/ time taken
Now;
work done = Force × distance
Force = 30.0 N
Distance = 10.0 m
work done = 30.0 N × 10.0 m = 300 J
The power expended = 300 J/10.00 s = 30 Watt
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A 2.8 kg block slides along a frictionless surface at 1.1 m/s . A second block, sliding at a faster 4.8 m/s , collides with the first from behind and sticks to it. The final velocity of the combined blocks is 2.3 m/s.
What was the mass of the second block?
Conservation of momentum is a major law of physics which states that the momentum of a system is constant if no external forces are acting on the system. It is embodied in Newton’s First Law or The Law of Inertia.the mass of the second block is 1.1Kg.
principle of momentum conservation
M1u1 plus M2u2 equals M1v1 and M2V2.
As all collisions were elastic in nature and no energy loss through friction, heat, etc. was taken into account, theoretic calculations alone cannot guarantee that there was a complete transfer of energy.
Consider the scenario where a football with mass M2 is lying on the ground and a bowling ball with mass M1 is hurled at the football at a velocity of
The formula is: (2.8 kg * 1.1 m/s) + (m2 * 4.8 m/s) = (2.3 kg + m2). 2.3 m/s
The formula is 2.8 J + (4.8 m/s m2) = 4.8 J + (2.3 m/s m2).
4.8 m/s m2 = 2.8 J plus (2.3 m/s m2)
4.8 m2 = 2.8 + 2.3 m2
2.3 m2 on each side of the equation
2.5 m = 2.8 m = 2.8 / 2.5\sm = 1.1kg
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At t = 0, Ball 1 is dropped from the top of a 22 m-high building. At the same instant Ball 2 is thrown straight up from the base of the building with an initial velocity of +12 m/s. Assume that Ball 1 starts from rest and that air friction can be ignored. At what height will the two balls pass each other? What is the velocity of each ball at the moment they are at the same height?
Answer:
The two balls pass each other at a height of 5.53 m
vf1=17.97 m/s
vf2=-5.96 m/s
Explanation:
Vertical Motion
An object thrown from the ground at speed vo, is at a height y given by:
\(y=vo.t-g.t^2/2\)
Where t is the time and \(g=9.8\ m/s^2\)
Furthermore, an object dropped from a certain height h will fall a distance y, given by:
\(y=g.t^2/2\)
Thus, the height of this object above the ground is:
\(H = h-g.t^2/2\)
The question describes that ball 1 is dropped from a height of h=22 m. At the same time, ball 2 is thrown straight up with vo=12 m/s.
We want to find at what height both balls coincide. We'll do it by finding the time when it happens. We have written the equations for the height of both balls, we only have to equate them:
\(vo.t-g.t^2/2=h-g.t^2/2\)
Simplifying:
\(vo.t=h\)
Solving for t:
\(t=h/vo=22/12=1.833\ s\)
The height of ball 1 is:
\(H = 22-9.8.(1.833)^2/2\)
H = 5.53 m
The height of ball 2 is:
\(y=12\cdot(1.833)-9.8\cdot(1.833)^2/2\)
y=5.53 m
As required, both heights are the same.
The speed of the first ball is:
\(vf1=g.t=9.8\cdot 1.833=17.97\ m/s\)
vf1=17.97 m/s
The speed of the second ball is:
\(vf2=vo-gt=12-9.8\cdot 1.833=-5.96\ m/s\)
vf2=-5.96 m/s
This means the second ball is returning to the ground when both balls meet
How do astronauts overcome this obstacle when communicating in space?
3HYETGGTETFEETEETETETETETETTETETEET
Answer:
By having specialized instruments onboard NASA spacecrat, they do this to detect how they behave
Explanation:
I really hope this is right have a stellar day.
A taxi hurries with a constant speed of 60 miles per hour. How long will it take to travel a distance of 130 miles
Answer:
2.17 hrs
Explanation:
time = distance / velocity
We know that distance = 130 miles and velocity = 60 miles/h.
t = d / v
t = 130 miles / 60 miles/h
t = 2.17 hrs
It takes about 2.17 hours to travel a distance of 130 miles. Hope this helps, thank you !!
An 8.0 kg ball travelling at 4 m/s collides head on with a 3 kg ball
travelling at 14 m/s. The balls bounce off each other and travel
back the way they came. The 8.0 kg ball travels away at
2 m/s. Calculate:
a) the velocity of the 3 kg ball after the collision
b) the kinetic energy before and after the collision.
c)
State whether or not the collision is elastic and explain your
answer.
a) The velocity of the 3 kg ball after the collision will be 19.33 m/sec.
b) The kinetic energy before and after the collision IS 294 and 560 J.
c)The collision is elastic in nature.
What is the law of conservation of momentum?According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
a)
According to the law of conservation of momentum;
Momentum before collision =Momentum after collision
\(\rm m_1u_1+m_2u_2=m_1v_1+m_2v_2 \\\\\ 8 \times 4 +3 \times 14 = 8 \times 2 + 3 \times v_2 \\\\ v_2 = 19.33 \ m/sec\)
b)
The kinetic energy before the collision is:
\(\rm KE_1 = \frac{1}{2} mu_1^2 \\\\ \rm KE_1 = \frac{1}{2} \times 3 \times 14 ^2 \\\\ KE_1=294 \ J\)
The kinetic energy after the collision is:
\(\rm KE_2 = \frac{1}{2} mv_2^2 \\\\ \rm KE_1 = \frac{1}{2} \times 3 \times (19.33) ^2 \\\\ KE_2=560.47 \ J\)
c)
This is an elastic collision because the kinetic energy before the collision is equal to the kinetic energy after the impact.
Hence, the velocity of the 3 kg ball after the collision will be 19.33 m/sec and the collision is elastic in nature.
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How will you determine the direction
of a torque? Explain.
which of the following is not a good working habit in doing an embroidery
Answer:
Where is following ??
Post proper Ques
2. What's the total resistance in a circuit that contains three 60 Ω resistors connected in series?
A. 60 Ω
Ο Β. 20 Ω
Ο C. 120 Ω
Ο D. 180 Ω
Answer:
d) 180 Ω
Explanation:
The total resistance in a circuit with resistors connected in series is:
Req = R1 + R2 + R3
Req = 60 Ω + 60 Ω + 60 Ω
Req = 180 Ω
The total resistance in the given series resistance circuit is 180 Ω. So, D is the correct option.
What is meant by series combination of resistors ?A circuit is said to be in series combination of resistors, when the same amount of current is flowing through all the resistors.
Here,
The resistors in the circuit are connected through a series combination.
Resistance of each resistors, R = 60 Ω
Number of resistors connected in series, n = 3
The effective resistance in a series resistance circuit is given as,
Reff = R₁ + R₂ + R₃
The three resistances here are same.
Therefore, Reff = nR
Reff = 3 x 60
Reff = 180 Ω
Hence,
The total resistance in the given series resistance circuit is 180 Ω.
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Each rarefraction on a longitudinal wave correspond to what point on a transverse wave?
The answer of a and b
Answer:
a) 30.65
b) 71.51
Explanation:
Question 19 of 25
The diagram below shows the velocity vectors for two cars that are moving
relative to each other.
45 m/s west
25 m/s east
- Car 1
Car 2
From the frame of reference of car 1, what is the velocity of car 2?
OA. 70 m/s east
O B. 20 m/s west
O c. 70 m/s west
D. 20 m/s east
The velocity of car 2, from the frame of reference of car 1, is 20 m/s west. (Answer: B)
When considering the frame of reference of car 1, we need to subtract the velocity of car 1 from the velocity of car 2 to determine the relative velocity. Since car 1 is moving at 45 m/s west and car 2 is moving at 25 m/s east, we can subtract these velocities to find the relative velocity of car 2 with respect to car 1.
45 m/s (west) - 25 m/s (east) = 20 m/s (west)
Therefore, car 2 has a velocity of 20 m/s west when observed from the frame of reference of car 1. It is important to note that velocities are vector quantities, which means they have both magnitude and direction. In this case, the direction is west because car 2 is moving in the opposite direction of car 1. (Answer: B)
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You are interested in a new sports car that can go from 0 m/s to 120 m/s in 12 s. What is the acceleration of the car?
Formula
image
A.
0.1
m
s
2
B.
10
m
s
2
C.
60
m
s
2
D.
1440
m
s
2
Answer:
A
Explanation:
Option B) 10m/s² is the correct answer.
Hence, the acceleration of the new sports car in the given period of time is 10m/s².
What is Motion?Motion is simply the change in position of an object over time.
From the First Equation of Motion;
v = u + at
Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.
Given the data in the question;
Initial velocity of the sport car u = 0m/sFinal velocity of the sport car v = 120m/sElapsed time t = 12sAcceleration of the sports car a = ?To determine the acceleration of the new sports car, we substitute our given values into the expression above.
v = u + at
120m/s = 0m/s + (a × 12s)
a × 12s = 120m/s - 0m/s
a × 12s = 120m/s
a = 120m/s ÷ 12s
a = 10m/s²
Option B) 10m/s² is the correct answer.
Hence, the acceleration of the new sports car in the given period of time is 10m/s².
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If you could cut the paper in half 20 times, would the paper be bigger or smaller than the following: 1 hair--------------------, a germ-------------------- and an atom---------------------.
Do you think you could keep cutting the paper forever?-----------------------------------------
------------------------------------------------------------------------------------------------------------
Science
Answer:
Maybe???
Explanation:
but how big is the paper?
but I think even the paper is super big, the ending result will still be too small to observe …
What is the force on a 1,250 kg elevator that is in free fall at 9.8 m/s²? Ignore air
resistance, round your answer to the nearest tenth and use appropriate units.
Answer:
\(\boxed{12250N}\)
Explanation:
Assuming we disregard air resistance, the only force acting on the elevator will be its weight.
\(F \implies w=m\cdot g\)
where:
\(F=\) force
\(w=\) weight
\(m=\) mass → 1250kg
\(g=\) gravity acceleration → 9.8m/s^2
Then:
\(F= 1250kg \cdot 9.8m/s^2\\F=12250 kg\cdot m/s^2= 12250N\)
Hope it helps.
\(\text{-B$\mathfrak{randon}$VN}\)
After coming down a slope, a 60-kg skier is coasting northward on a level, snowy surface at a constant 15 m>s. Her 5.0-kg cat, initially running southward at 3.8 m>s, leaps into her arms, and she catches it. (a) Determine the amount of kinetic energy converted to internal energy in the Earth reference frame. (b) What is the velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat’s kinetic energy does not change?
The velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat's kinetic energy does not change is equal to the velocity of the skier before the collision. The velocity of the skier before the collision is 15 m/s.
What is law of conservation of momentum?According to the law of conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision. This can be expressed as m1*v1 + m2*v2 = (m1 + m2)*vf, where m1 and m2 are the masses of the skier and the cat respectively, v1 is the velocity of the skier, and vf is the velocity of the skier and the cat after the collision.
The kinetic energy converted to internal energy in the Earth reference frame can be determined by applying the law of conservation of momentum.
The amount of kinetic energy converted to internal energy can be calculated as follows:
m1*v1 = (m1 + m2)*vf
vf = (m1*v1)/(m1 + m2)
KE = (1/2)*m2*v2²
KE converted = KE initial - KE final
KE converted = (1/2)*m2*v2² - (1/2)*m2*((m1*v1)/(m1 + m2))²
KE converted = (1/2)*m2*v2² - (1/2)*m2*((60*15)/(60 + 5))²
KE converted = (1/2)*5*3.8² - (1/2)*5*(15²/65)
KE converted = 28.8 - 22.15
KE converted = 6.65 J
The velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat's kinetic energy does not change is equal to the velocity of the skier before the collision.
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What exactly are molecules, how do they function?
Answer:
molecule, a group of two or more atoms that form the smallest identifiable unit into which a pure substance can be divided and still retain the composition and chemical properties of that substance.Molecules are made up of atoms that are held together by chemical bonds. These bonds form as a result of the sharing or exchange of electrons among atoms. The atoms of certain elements readily bond with other atoms to form molecules. ... The atoms of some elements do not easily bond with other atoms. l
You are driving home from school steadily at 94 kn/h for 190km . It then begins to rain and you slow to 61 km/h instantly. You arrive home after driving 5.0 hours , How far is your hometown from school?
The distance of my hometown from school if I arrive home after driving 5.0 hours is 373 kilometers
v = d / t
v = Velocity
d = Distance
t = Time
For first half,
v = 94 km / h
d = 190 km
t = d / v
t = 190 / 94
t = 2 hours
For second half,
v = 61 km / h
t = 5 - 2
t = 3 hours
d = v * t
d = 61 * 3
d = 183 kilometers
Total distance = 190 + 183
Total distance = 373 kilometers
Therefore, the distance of my hometown from school is 373 km
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The activation energy, Ea, for a particular reaction is 37.8 kJ/mol. If the rate constant at 280 K is 0.178 M/s, what is the value of the rate constant at 457 K? (R = 8.314 J/mol K)
The value of the rate constant at 457 K is 0.478 M/s.
The rate constant, k, at a given temperature can be related to the activation energy, Ea, and the gas constant, R, through the Arrhenius equation:
\(k = Ae^{(-Ea/RT)}\)
where A is the pre-exponential factor and T is the temperature in Kelvin.
Given k1 = 0.178 M/s at T1 = 280 K, and Ea = 37.8 kJ/mol, we can calculate the rate constant, k2, at T2 = 457 K as:
k2 = A * \(e^{(-Ea/R * T2)}\) = 0.178 * \(e^{(-37.8 kJ/mol / (8.314 J/mol K) * 457 K)}\) = 0.478 M/s.
This means that the reaction will proceed faster at 457 K than it does at 280 K, due to the increase in temperature leading to an increase in the rate constant, k.
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A wire is 24.5 m long at 4.00°C and is 1.40 cm longer at 34.0°C. Find the wire's coefficient of linear expansion (in (°C)−1)
Answer:
1.9×10⁻⁵ °C⁻¹
Explanation:
Coefficient of linear expansion: This can be defined as as increase in length of a material, per unit length per degree rise in temperature, The S.I unit is (K⁻¹).
From the question above,
α = ΔL/L(T₂-T₁)................... Equation 1
Where α = coefficient of linear expansion, ΔL = Change in length, L = original length, T₁ = Initial Temperature, T₂ = Final temperature.
Given: ΔL = 1.4 cm = 0.014 m, L = 24.5 m, T₁ = 4.00°C, T₂ = 34°C
Substitute these values into equation 1
α = 0.014/[24.5(34-4)]
α = 0.014/735
α = 1.9×10⁻⁵ °C⁻¹
which object has a weight of about 22.5 n the book the rock the box the fish
Answer: The rock
Explanation:
What are the two main processes carried out by the excretory system?
If something travels 4 meters in one second, what is its speed?
Answer:
speed =distance /time
speed =4/1
speed 4m/s
give two examples of uses of the expansion and contraction of materials
if we hold a very hot glass tumbler under cold water, it cracks. This is because the outer surface of the glass comes in direct contact with cold water and contracts more as compared to the inner surface. We observed that water expanded on heating.
Railway tracks consist of two parallel metal rails joined together. Small gaps, called expansion gaps, are deliberately left between the rails as there is an expansion of the rails in hot weather. Water expands on heating.
A basketball leaves a player's hands at a height of 2.00 m above the floor. The basket is 3.05 m above the floor. The player likes to shoot the ball at a 36.0 degree angle. If the shot is made from a horizontal distance of 12.00 m and must be accurate to ±0.27 m (horizontally), what is the range of initial speeds allowed to make the basket?
Enter your answers numerically separated by a comma.
Answer:
The range of initial speeds allowed to make the basket is 33.9 m/s to 34.3 m/s.
A revolving door continues to rotate even after the person pushing it exits. Is it Newton's first law of motion, Newton's second law of motion. or Newton's third law of motion?
Answer:
Newton's third Law
Explanation:
Newton’s first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.
how much force is needed to accelerate a 2500kg car at a rate of 4m/s2
Answer:
10,000 N
Explanation:
Using Newton's Second Law of Motion, Force = Mass*Acceleration.
Plugin 2500 kg for the mass and 4 m/s^2 for the acceleration.
Force = 2500 kg*4 m/s^2 = 10000 Newtons
(SI unit of force is Newtons)