What graph represents number 17? (y - in; tercept = 1; t=1;slope= 1 2)

Answer:

D) -2x²+120=1800

Step-by-step explanation:

area=l*w

the area is 1800 (given)

the length is x (given)

the width would be 120-2x (120 feet of fencing minus the two lengths)

SO

1800=(x)(120-2x)

1800=120x-2x²

1800=-2x²+120

-2x²+120=1800

So the answer is D

The equation representing the area of the horse paddock is  -2x² + 120x = 1800. The correct option is (D).

A rectangle is a type of parallelogram having equal diagonals.

All the interior angles of a rectangle are equal to the right angle.

The area of a rectangle can be found by taking the product of its length and breadth.

Given that,

The total length of the fence is 120 feet.

And, the area enclosed is 1800 square feet.

As per the given question, the expression for the length of fence is as below,

2x + l = 120

=> l = 120 - 2x

Since the horse paddock is in the shape of a rectangle, its area can be written as,

x(120 - 2x) = 1800

=> 120x - 2x² = 1800

=> -2x² + 120x = 1800

Hence, the equation that can be used to find the dimensions of the horse paddock is given as -2x² + 120x = 1800.

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1.5

The given function is:

f(x) = 2x² + 5x – 12

To find the zeros, equate f(x) to zero.

f(x) = 0

2x² + 5x – 12 = 0

2x² - 3x + 8x - 12 = 0

x(2x - 3) + 4(2x - 3) = 0

(x + 4)(2x - 3) = 0

x + 4 = 0

x = -4

2x - 3 = 0

2x = 3

x = 3/2

x = 1.5

The zeros of the function f(x) = 2x² + 5x – 12 are -4 and 1.5

Since only x = 1.5 is positive, x = -4 is not positive, the value of the positive zero is 1.5

Hey there!

7x = 1.35

DIVIDE 7 to BOTH SIDES

7x/7 = 1.35/7

CANCEL out: 7/7 because it give you 1

KEEP: 1.35/7 because it give you the x-value

NEW EQUATION: x = 1.35/7

SIMPLIFY IT!

x = 0.192857

x ≈ 192,857/1,000,000

Therefore, your answer is:

x = 0.192857 or x = 192,857/1,000,000

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer:

C. The conditional statement is false. There is at least one counterexample for the statement.  

Step-by-step explanation:

took the quiz

The expression g = 2hm can be written as in terms of g and h when m is the subject is m = g/2h.

It is defined as the combination of constants and variables with mathematical operators.

We have an expression:

g  = 2hm

To make m as the subject and solve it:

Divide the above expression by 2h on both sides:

g/2h = m  or

m = g/2h

Thus, the expression g = 2hm can be written as in terms of g and h when m is the subject is m = g/2h.

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Given:

The function is

\(g(x)=-3x+12\)

Consider the given domain of g is {-2,0,2}.

To find:

The solution set  if the domain of g for the given domain.

Solution:

Domain is the set of input values and range is the set of output value.

We have,

\(g(x)=-3x+12\)

Domain of g is {-2,0,2}.

For x=-2,

\(g(-2)=-3(-2)+12\)

\(g(-2)=6+12\)

\(g(-2)=18\)

For x=0,

\(g(0)=-3(0)+12\)

\(g(0)=0+12\)

\(g(0)=12\)

For x=2,

\(g(2)=-3(2)+12\)

\(g(2)=-6+12\)

\(g(2)=6\)

Now, the solution set  of the given domain of g is

\(\{f(-2),f(0),f(2)\}=\{18,12,6\}\)

Therefore, the solution set is {18,12,6}.

Answer:

Use colon method

Step-by-step explanation:

So it is more easy

Answer:

x = 18

Step-by-step explanation:

2x = 36

you divide by 2 on both sides, x is issolated and 36/2 is equal to 18.

To solve the given initial value problem using Laplace transforms, we can apply the Laplace transform to both sides of the differential equation and use initial conditions to determine the transformed equation.

By algebraically manipulating the transformed equation, we can find the Laplace transform of the desired solution. Finally, we can use the inverse Laplace transform to obtain the solution in the time domain. Let's denote the unknown function as x(t). Applying the Laplace transform to both sides of the differential equation yields the transformed equation in terms of the Laplace transform variables s and X(s). By substituting the initial conditions x(0) = 0 and x'(0) = 20 into the transformed equation, we can solve for X(s).

After obtaining the Laplace transform X(s), we can manipulate the equation algebraically to isolate X(s) on one side. This may involve factoring, simplifying, and using partial fraction decomposition if necessary. Once we have the equation in terms of X(s), we can apply the inverse Laplace transform to find the solution x(t) in the time domain.

To find y(t), we follow the same procedure, applying the Laplace transform to both sides of the differential equation involving y(t) and using the given initial condition y(0) = y0. Solving for the Laplace transform Y(s), we can then find y(t) by applying the inverse Laplace transform.

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Answer(s):

\(\displaystyle y = cos\:(x - \frac{\pi}{2}) + 2 \\ y = -sin\:(x \pm \pi) + 2 \\ y = sin\:x + 2\)

Step-by-step explanation:

\(\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{\pi}{2}} \hookrightarrow \frac{\frac{\pi}{2}}{1} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{2}{1}\pi \\ Amplitude \hookrightarrow 1\)

OR

\(\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{2}{1}\pi \\ Amplitude \hookrightarrow 1\)

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the sine graph, if you plan on writing your equation as a function of cosine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of \(\displaystyle y = cos\:x + 2,\)in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [photograph on the right] is shifted \(\displaystyle \frac{\pi}{2}\:unit\)to the left, which means that in order to match the sine graph [photograph on the left], we need to shift the graph FORWARD \(\displaystyle \frac{\pi}{2}\:unit,\)which means the C-term will be positive, and by perfourming your calculations, you will arrive at \(\displaystyle \boxed{\frac{\pi}{2}} = \frac{\frac{\pi}{2}}{1}.\)So, the cosine graph of the sine graph, accourding to the horisontal shift, is \(\displaystyle y = cos\:(x - \frac{\pi}{2}) + 2.\)Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit \(\displaystyle [-4\pi, 2],\)from there to \(\displaystyle [-2\pi, 2],\)they are obviously \(\displaystyle 2\pi\:units\)apart, telling you that the period of the graph is \(\displaystyle 2\pi.\)Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at \(\displaystyle y = 2,\)in which each crest is extended one unit beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

The inequality 3 ≤ x - 2 simplifies to x ≥ 5. This means x can take any value greater than or equal to 5. Therefore, option (E) with a number line from positive 5 to positive 10 is correct.

Given: 3 \(\leq\) x - 2

We need to work out which number line below shows the values that x can take. In order to solve the inequality, we will add 2 to both sides. 3+2 \(\leq\) x - 2+2 5 \(\leq\) x

Now the inequality is in form x \(\geq\) 5. This means that x can take any value greater than or equal to 5. So, the number line going from positive 5 to positive 10 shows the values that x can take.

Therefore, the correct option is (E) A number line going from positive 5 to positive 10.  We added 2 to both sides of the given inequality, which gives us 5 \(\leq\) x. It shows that x can take any value greater than or equal to 5.

Hence, option E is correct.

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anSwer:

120,000x

Step-by-step explanation:

1.2(100000)

The inequality relating the figures are

25 XZ > AC

26. DF < FD

27.  38 > x > 11

28. 37/3 > x > 7/3

In the figure, the angles are related from the concept that one angle in a triangle must be greater than zero and less than 180.

In addition, when other dimensions are equal the side having greater length will have greater angle facing it.

27. since side 18 > side 12 we have that

5x - 10 > 45

5x > 45 + 10

5x > 55

x > 11

each angle must be less than 180

Also, 5x - 10 < 180

5x < 180 + 10

5x < 190

x < 38

The range of values of x is 38 > x > 11

28. since side 9 > side 6

30 > 3x - 7

30 + 7 > 3x

37 > x

x < 37/3

each angle must be greater than 0

3x - 7 < 0

3x > 7

x > 7/3

The range of values of x is 37/3 > x > 7/3

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Answer:

look at the picture i have sent

Answer:

b

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

The middle 2 numbers are 6 and 8. Add them both up and divide them by 2. Gets you 7.

Answer:

neither

Step-by-step explanation:

if they were parallel, they would share the same gradient.

if a line were to be perpendicular to 2/5, the gradient would be -5/2 (the numerator and the denominator flips. if it is positive it'll change to negative, and if it's negative it'll become positive).

you don't need to look at the y-intercept, just focus on the gradient.

hope this helps!!

Answer:

neither

Step-by-step explanation:

in order for two lines to be parallel their slopes need to be the same. Both of these equations are written in slope intercept form which reveals the slope as the coefficient of x (the number in front of x).  These coefficients are not the same so not parallel.

to be perpendicular the slopes need to be opposite reciprocals.  For example, 3 and -1/3 or -5/8 and 8/5.  These slopes are opposites since one is negative and one positive but they are not reciprocals so therefore not perpendicular

To find the probability that a person fails the first time but passes the second time in organic chemistry, we need to multiply the probability of failing the first time (0.2) by the probability of passing the second time (0.9).

Probability of failing the first time = 0.2

Probability of passing the second time = 0.9

Probability of failing the first time but passing the second time = 0.2 * 0.9

Calculating the product:

Probability of failing the first time but passing the second time = 0.18

Therefore, the probability that a person fails the first time but passes the second time in organic chemistry is 0.18, or 18%.

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Answer:

  7

Step-by-step explanation:

You want the common difference of the arithmetic sequence that starts ...

  15, 22, 29, ...

The common difference is the difference between a term and the one before. It is "common" because the difference is the same for all successive term pairs.

  22 -15 = 7

  29 -22 = 7

The common difference is 7.

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1. The outcomes in the sample space of choosing a letter from the word STARK are: S, T, A, R, K.

2. Number of outcomes in the sample space = 6 (from THANKS) × 5 (from STARK) = 30.

3. The Probability of choosing the letters AA is 0, as there are no occurrences of the letter A in both words together.

1. The outcomes in the sample space of choosing a letter from the word THANKS are: T, H, A, N, K, S.

  The outcomes in the sample space of choosing a letter from the word STARK are: S, T, A, R, K.

2. To find the number of outcomes in the sample space, we multiply the number of outcomes for each word.

  Number of outcomes in the sample space = Number of outcomes for the first word × Number of outcomes for the second word

  Number of outcomes in the sample space = 6 (from THANKS) × 5 (from STARK) = 30.

3. The probability of choosing the letters AA would be the number of favorable outcomes (which is 0 in this case) divided by the total number of outcomes in the sample space.

  Probability of choosing AA = Number of favorable outcomes / Total number of outcomes

  Probability of choosing AA = 0 / 30 = 0.

Therefore, the probability of choosing the letters AA is 0, as there are no occurrences of the letter A in both words together.

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Answer:

1320

Step-by-step explanation:

There are 12 hordes, so any one of the 12 can come in first.

12 ×

After one horse comes in first, there are 11 horses left to choose from.

12 × 11 ×

After the second horse finishes, there are 10 horses left to choose from.

12 × 11 × 10 =

= 1320

Step-by-step explanation:

since there is no graph it's a bit hard to answer this question, but I'll try. I can help solve the equation that represents the ratio of the two numbers:

(x + 1/2)/y = 1/3

This can be simplified to:

x + 1/2 = y/3

To graph this equation, you would need to plot points that satisfy the equation. One way to do this is to choose a value for y and solve for x. For example, if y = 6, then:

x + 1/2 = 6/3

x + 1/2 = 2

x = 2 - 1/2

x = 3/2

So one point on the graph would be (3/2, 6). You can choose different values for y and solve for x to get more points to plot on the graph. Once you have several points, you can connect them with a line to show the relationship between x and y.

(Like I said, it was a bit hard to answer this question, so I'm not 100℅ sure this is the correct answer, but if it is then I hoped it helped.)

The we need to find a function f(x) that satisfies the above conditions and whose integral is easy to evaluate.

The answer is (B) diverges.

The answer is (A) converges.

Let's use the integral test to determine the convergence of the following series:

Find the integrand and integrate it.

The integral test states that if f(x) is a positive, continuous, and decreasing function on [1, infinity) such that the series ∑n=1 to infinity of f(n) converges, then the series ∑n=1 to infinity of a(n) also converges, where a(n) = f(n) for all n.

Integrating f(x) from c-1 to infinity, we get:

Integrating f(x) from 1 to infinity, we get:

Compare the sum to the integral.

Since f(x) is positive and decreasing, we can use the integral test to compare the series to the integral.

If the integral converges, then the series converges as well.

If the integral diverges, then the series diverges as well.

The integral ln(11) - ln(c+9) diverges as c approaches infinity, so the series diverges as well.

Since f(x) is positive and decreasing, we can use the integral test to compare the series to the integral.

If the integral converges, then the series converges as well.

If the integral diverges, then the series diverges as well.

The integral ln(10) - ln(1+1/10) converges.

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The initial force between the two charges is given by:

\(F=k\frac{q_{1} q_{2} }{d^2}\)

where k is Coulomb's constant, q1 and q2 are the two charges, and d is their separation. Let's analyze now the other situations:

1. F

In this case, q1 is halved, q2 is doubled, but the distance between the charges remains d.

So, we have:

q'₁=q₁/2

q'₂=2q₂

d'=d

So, the new force is:

\(F'=k\frac{q'_{1}q'_{2} }{d^2} \\\\F'=k\frac{(\frac{q_{1} }{2})(\frac{q_{2} }{2}) }{d^2} \\\\F'=k\frac{q_{1}q_{2} }{d^2} =F\)

So the force has not changed.

2. F/4

In this case, q1 and q2 are unchanged. The distance between the charges is doubled to 2d.

So, we have:

q'₁=q₁

q'₂=q₂

d'=2d

So, the new force is:

\(\\F'=k\frac{q'_{1} q'_{2} }{d^2} \\\\F'=k\frac{q_{1}q_{2} }{2d^2} \\\\F'=\frac{1}{4} k\frac{q_{1}q_{2} }{d^2} \\\\F'=\frac{F}{4}\)

So the force has decreased by a factor of 4.

3. 6F

In this case, q1 is doubled and q2 is tripled. The distance between the charges remains d.

So, we have:

q'₁=2q₁

q'₂=3q₂

d'=d

So, the new force is:

\(F'=k\frac{q'_{1} q'_{2} }{d^2} \\\\F'=k\frac{2q_{1}3q_{2} }{d^2}\\ \\F'=6k\frac{q_{1}q_{2} }{d^2} =6F\)

So the force has increased by a factor of 6.

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Answer:

1. F

2. F/4

3. 6F

Answer:

The average rate of change of the function for the interval [-4, 0] is  \(\frac{3}{4}\) ⇒ A

Step-by-step explanation:

The average rate of change of the function is the slope of the line that represents the function, m = Δy/Δx, where

From the given figure

→ The values of x in the interval [-4, 0] are -4 and 0

∵ The point (-4, 0) and (0, 3) lie on the line

∴ x1 = -4 and x2 = 0

∴ x2 = 0 and y2 = 3

∵ Δx = 0 - (-4) = 0 + 4 = 4

∵ Δy = 3 - 0 = 3

→ By using the rule of the slope above

∴ m = \(\frac{3}{4}\)

∵ The average rate of change of the function = the slope of the line

∴ The average rate of change of the function for the interval [-4, 0] is  \(\frac{3}{4}\)

a).  2^38 bytes of memory

b). 12 bits

c). The maximum number of entries in the single-level page table would be 2^38.

d). The size would be 2^38 * 4KB, which equals 2^20 pages.

e). The maximum number of entries it can have depends on the remaining bits of the logical address.

f). The amount of bits required to denote an index into the inner page table is obtained by subtracting the offset and outer page index bits from the logical address.

a. To address a physical memory size of 128GB (2^37 bytes), a 64-bit architecture would require 38 bits for the logical address, allowing access to a maximum of 2^38 bytes of memory.

b. Given that the page size is 4KB (2^12 bytes), 12 bits would be needed to specify the displacement into a page. This means that the lower 12 bits of the logical address would be used for page offset or displacement.

c. With a single-level page table, the maximum number of entries would be equal to the number of possible logical addresses. In this case, since the logical address requires 38 bits, the maximum number of entries in the single-level page table would be 2^38.

d. The size of the single-level page table is determined by the number of entries it contains. Since each entry maps to a page of size 4KB, the size of the single-level page table can be calculated by multiplying the number of entries by the size of each entry. In this case, the size would be 2^38 * 4KB, which equals 2^20 pages.

e. For a two-level page table, the size of the outer page table is determined by the number of entries it can contain. Since the outer page table uses 4KB pages, the maximum number of entries it can have depends on the remaining bits of the logical address. The number of bits used for the index into the outer page table is determined by subtracting the bits used for the inner page index and the offset from the total number of bits in the logical address.

f. The number of bits used to specify an index into the inner page table can be determined by subtracting the bits used for the offset and the bits used for the outer page index from the total number of bits in the logical address. The remaining bits are then used to specify the index into the inner page table.

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Answer:

Step-by-step explanation:

15. (-4-3)/(-5-0)= -7/-5= 7/5

      y - 3 = 7/5x - 0

      y = 7/5x + 3

16. (-2-3)/(4-0)= -5/4

     y - 3 = -5/4x - 0

     y = -5/4x + 3

17. (-3+5)/(0+3)= 2/3

    y + 5 = 2/3(x + 3)

     y + 5 = 2/3x + 2

     y = 2/3x - 3

18. (-2-2)/(0+4)= -4/4= -1

       y - 2 = -1(x + 4)

       y - 2 = -x - 4

       y = -x - 2

19. y - 3 = 1/2x - 0

     y = 1/2x + 3

20. y - 2 = -(x + 1)

      y - 2 = -x - 1

      y = -x + 1

21. perp. -5/3

y + 5 = -5/3x  + 0

 y = -5/3x - 5

22. perp. 1/2

   y + 1 = 1/2(x + 4)

   y + 1 = 1/2x + 2

   y = 1/2x + 1

23. perp. 3/4

   y + 5 = 3/4(x + 4)

   y + 5 = 3/4x + 3

   y = 3/4x - 2

24. perp. 7/5

 y - 4 = 7/5(x - 5)

 y - 4 = 7/5x - 7

 y = 7/5x - 3

Answer:

4 or 3

Step-by-step explanation:

X³+12X=7X²

X³-7X²+12X=0

X(X²-7X+12)=0

SOLVING THE QUADRATIC EQUATION

you have X=3 or X=4