Answer: The functional groups are the aldehyde and hydroxyl groups. 1. Because of these polar functional groups, glucose (and other monosaccharides) are highly soluble in water (1.5 g/mL at 25 ºC). 2. it is also a reducing sugar
Answer:
The functional groups are the aldehyde and hydroxyl groups and are reducing sugars
Explanation:
All monosaccharides are reducing sugars. Glucose, fructose, and galactose are monosaccharides and are all reducing sugars.
A reversible exothermic synthesis (combination) reaction produces one mole of gaseous product from two moles of gaseous
reactant. Which set of condtions will shift the reaction farthest toward the products?
A)
low temperature, low pressure
B)
low temperature, high pressure
9
high temperature, low pressure
D)
high temperature, high pressure
A 2.0g piece of Mg reacts with HNO3. Which conditions would produce the GREATEST reaction rate?
Factors that will increase product formation are;
low temperature and high pressure increasing the surface area and concentrationWhat factors affect chemical equilibrium?The position of chemical equilibrium is affected by the following factors:
temperature concentration pressure for gasesWhen equilibrium is altered by an external factor, the reaction shifts to annul the effect of that change.
For the reversible exothermic synthesis, low temperature and high pressure will shift the reaction farthest toward the products.
For the reaction of the 2.0g piece of Mg with HNO3. increasing the surface area of magnesium metal as well as increasing the concentration of HNO3 would produce the GREATEST reaction rate.
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If your equation includes 7(CrO4)2, how many Cr's are there?
If your equation includes 7(CrO4)2, how many O's are there?
If an equation includes 7(CrO₄)₂, the numbers of Cr's and O's atoms that are there are 14 and 56 respectively.
How to calculate number of atoms?The number of atoms present in a chemical compound can be calculated by multiplying the subscript of the particular element by any coefficient.
According to this question, 7 moles of chromate with the chemical formula; (CrO₄)₂ is given. The number of oxygen and chromium atoms in this compound can be calculated as follows:
Chromium = 7 (coefficient) × 2 = 14 atomsOxygen = 7 (coefficient) × 8 = 56 atomsLearn more about no of atoms at: https://brainly.com/question/14190064
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Write a summary of the science of muscle growth?
Answer:Muscle growth or “skeletal muscle hypertrophy,” as it's called at science parties) is the result of a complex process that adds more myosin “filaments” to each muscle fiber. This makes the “engine” of the cell bigger and stronger over time. ... This process is called muscle protein synthesis, or MPS. Skeletal muscle is composed of thread-like myofibrils and sarcomeres that form a muscle fiber and are the basic units of contraction. The 650 skeletal muscles in the human body contract when they receive signals from motor neurons, which are triggered from a part of the cell called the sarcoplasmic reticulum.
If 6.34 g of CuNO, is dissolved in water to make a 0.720 M solution, what is the volume of the solution in milliliters?
V=n/M
V=(6.34:125.55 g/mol)/0.72
V=0.07 L = 70 ml
Menstruation occurs on a ______ interval from puberty until menopause
A. Three months
B. Two months
C. Half month
D. One month
The mass of an empty crucible was 17.556g. The mass of the crucible and a hydrate was 21.018 g. The mass of the crucible and anhydrous salt (after heating) was 19.641g. A. Calculate the mass of water lost due to heating. B. Calculate the mass percentage of water.
Answer:
A. 1.377 g
B. 16.5%
Explanation:
To find the water loss, subtract the salt and crucible mass from the hydrate and crucible mass
21.018 - 19.641 = 1.377
To find the water mass percentage, divide the empty crucible mass by the mass of the hydrate and crucible. Then, subtract that number from 1.
17.556 ÷ 21.018 = 0.835284
1 - 0.835284 = 0.164716
If you want to add an extra step, multiply this number by 100 to get the percentage.
0.164716 x 100 = 16.4716
Determine the empirical formula of a compound that contains the following percentages of elements by mass:Mo = 43.95%, O = 7.33%, Cl = 48.72%
If a compound that contains the elements by mass: Mo = 43.95%, O = 7.33%, Cl = 48.72% then the empirical formula will be Cl3MoO
The molar mass of Cl=35.453,
Molar mass of Mo=95.94,
Molar mass of O=15.9994
Converting these to moles: Cl=1.3742137477787, Mo=0.45809881175735, O=0.45814218033176
Here the smallest mole value is 0.45809881175735
Now we have to divide all components by the smallest value: Cl=2.9998194985641, Mo=1, O=1.0000946707856
If we don't consider the fractional values the closest round of values will be: Cl=3, Mo=1, O=1
So the formula becomes Cl3MoO
Therefore the required empirical formula is Cl3MoO
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Dinitrogen oxide has _____.
Answer:
Nitrogen is the answer my good sir.
Explanation:
Classify the following as either an element, compound, homogeneous mixture or
heterogeneous mixture:
milk
Answer:
HeterogeneousExplanation:
Milk seems to be homogeneous mixture but actually milk is a heterogeneous mixture and a colloid solution.What is an an example of a chemical reaction?
Answer:
nail rust!!!!!!!!!!!!!!!!!!
Answer:
2
Explanation:
Number 1 wouldn't be because it is a physical change
Number 3 wouldn't be because it is a physical change, as well
Number 4 wouldn't be because it is a physical change, too.
Therefore, it is 3
Hopefully I helped!
-Lavander Vye
A hot ballon with mass of 400 kilograms moves across the aky with 3,200 joules of kinetic energy. The velocity of the ballon is
Answer:
4 m/s
Explanation:
formula is v = (KE/.5m)^1/2
there is a calculator
https://www.calculatorsoup.com/calculators/physics/kinetic.php
What is the mass (in g) of a solid piece of iron which has a specific heat of 0.449 J/g°C if when it absorbed 948.0 J of heat the temperature rose from 24.0°C to
82.1°C? Give your answer in 3 sig figs.
Answer:
Explanation:
We can use the formula:
q = mcΔT
where q is the heat absorbed, m is the mass, c is the specific heat, and ΔT is the change in temperature.
Given:
specific heat of iron (c) = 0.449 J/g°C
initial temperature (T1) = 24.0°C
final temperature (T2) = 82.1°C
heat absorbed (q) = 948.0 J
Substituting the given values into the formula, we get:
q = mcΔT
948.0 J = m(0.449 J/g°C)(82.1°C - 24.0°C)
948.0 J = m(0.449 J/g°C)(58.1°C)
m = 948.0 J ÷ (0.449 J/g°C × 58.1°C)
m = 33.1 g
Therefore, the mass of the iron piece is 33.1 g (to three significant figures)
briefly describe how the pH of a colourless solution could be measured using a universal indicator
Answer:
Universal indicator can show us how strongly acidic or alkaline a solution is, not just that the solution is acidic or alkaline. This is measured using the pH scale , which runs from pH 0 to pH 14.
Explanation:
~Hope this helps
Which of the following elements is the most reactive?
a
Beryllium
b
Calcium
c
Magnesium
d
Barium
Explanation:
The answer would be Berium because it can mix as well with other elements in the periodic table.
Barium is regarded as the most reactive elements out of all the options
provided.
Barium is an element with symbol Ba and atomic number 56. It belongs to
Group 2 metals whose reactivity increases as we go down the group.
The alkaline earth metals which are in Group 2 of the Periodic Table include
: beryllium, magnesium, calcium, strontium, barium, and radium
The increase in reactivity down the group is as a result of the decreasing
ionization energy required to form new compounds. The Ionization energy
decreases due to more inner shells and increase in distance from the
nucleus.
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3. Copper (II) sulfide (CuS) is formed when 48.2 grams of copper are added to 35.0 grams of
sulfur.
Which reactant is the limiting reagent?
How much product is formed?
How much excess reagent remains?
(9 pts. total / 2 pts. for equation - 4 pts. for stoich - 2 pts. for limiting reagent - 1 pt. for excess
reagent.)
1. The limiting reagent would be sulfur.
3. The amount of product formed would be 34.4 grams
2. The amount of excess copper that remains would be 24.96 grams.
Sotichiometric problemCopper and sulfur react to form copper (II) sulfide according to the following balanced equation:
\(Cu + S -- > CuS\)
From the balanced equation of the reaction, the mole ratio of copper to sulfur is 1:1.
Recall that, mole = mass/molar mass
Mole of 48.2 grams of copper = 48.2/64
= 0.75 mol
Mole of 35.0 grams of sulfur = 35/98
= 0.36 mol
Since the stoichiometric mole ratio is 1:1, it means that sulfur is the limiting reactant or reagent while copper is in excess.
The excess amount of copper would be: 0.75 - 0.36 = 0.39 mol
Mass of 0.39 mol copper = 0.39 x 64 = 24.96 grams
With sulfur being the limiting reactant, the equivalent amount of CuS formed will be 0.36 mol considering that the mole ratio is 1:1.
Mass of 0.36 mol CuS = 0.36 x 95.6
= 34.4 grams.
In other words, the limiting reactant is sulfur, the amount of product formed is 34.4 grams, and the amount of excess copper is 24.96 grams.
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7. What happen if we don't have water?
Answer:
our bodies will dehydrate causing us to die a dreadfully excruciating painful death
Describe a chemical property of iron that you observed.
Answer:
Iron can rust in damp conditions. Or, it can dissolve readily in dilute acids.
Explanation:
What is the volume of a brick with a Length of 5cm, height of 1cm, and a
width of 2cm. *
O 8cm
O 10cm
15cm
O 12cm
all answer are cubed. I just couldn't add the cube symbol to the answer choices
Answer:
The answer is 10cm^3
Explanation:
5x1x2=10
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A chemical reaction between X and Y forms C according to the reaction below. The data for three trials to measure the
rate of this reaction are also given.
Trial
1
2
3
[X] (M)
0.01
0.01
0.02
X+Y→C
[Y] (M)
0.015
0.030
0.015
What is the rate law for this reaction?
OR=KX²M
OR=KX³M²
OR=KXM²
OR=KX²M²
Initial Rate (M/s)
7.83x10-5
BIBE
3.13x 104
1.57x10
Explanation: The rate law for a chemical reaction is an equation that relates the rate of the reaction to the concentrations of the reactants. To determine the rate law for a reaction, experiments are typically conducted with different initial concentrations of the reactants and the initial rate of the reaction is measured.
From the data provided, it appears that the reaction is of the form X + Y → C. And the concentration of X and Y are varied in three trials and the corresponding Initial rate is measured.
In the first trial, [X] = 0.01 M and [Y] = 0.015 M, and the initial rate of the reaction is 7.83x10-5 M/s.
In the second trial, [X] = 0.01 M and [Y] = 0.03 M, and the initial rate of the reaction is 3.13x104 M/s.
In the third trial, [X] = 0.02 M and [Y] = 0.015 M, and the initial rate of the reaction is 1.57x10 M/s.
Given the data, the rate law for this reaction is OR = KX²M. This is because when the concentration of X is doubled, the rate of the reaction is quadrupled, which is consistent with a rate law of the form OR = k[X]^2.
What is true about dominant alleles? a They almost never appear as the trait. b They appear as the trait only when there are two of them c They appear as the trait over a recessive allele d They appear as the trait if there is not recessive allele
They appear as the trait over a recessive allele. Statement C) is true about the dominant alleles.
Dominant alleles are genetic variants that, when present in an individual's genotype, are expressed phenotypically, meaning they determine the visible or observable traits. Dominant alleles are represented by capital letters, while recessive alleles are represented by lowercase letters in genetics.
In terms of inheritance, if an individual has at least one copy of the dominant allele, it will be expressed in the phenotype, regardless of the presence of a recessive allele. This is because dominant alleles exert their influence over recessive alleles, thus "dominating" their expression.
To illustrate this, let's consider a specific example using a trait controlled by a single gene with two possible alleles: dominant (A) and recessive (a). If an individual is homozygous dominant (AA), meaning they possess two copies of the dominant allele, the dominant trait will be expressed.
However, if an individual is homozygous recessive (aa), with two copies of the recessive allele, the recessive trait will be expressed since there are no dominant alleles to override it.
Therefore, dominant alleles appear as the trait over recessive alleles, regardless of the presence or absence of a recessive allele. The presence of even a single copy of the dominant allele is sufficient for its expression in the phenotype. Option C
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Which best describes a difference between energy transformation in power plants and dams?
Answer:
Which best describes a difference between energy transformations in power plants and dams? Only power plants use fossil fuels to transform energy. Only dams use fission to generate thermal energy. ... Only dams use mechanical energy to produce electricity.
Explanation:
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Calculate the number of moles of gas produced from the reaction of 2.00g of potassium with an excess amount of water.
The number of moles of gas produced from the reaction of 2.00g of potassium with an excess amount of water is 0.025 moles.
The reaction of potassium with an excess amount of water is:
2K + 2H\(_2\)O \(\rightarrow\) 2KOH + H\(_2\)
To calculate the moles of hydrogen gas first we need to calculate moles of potassium in 2.00g
No. of moles = (mass) / (molecular mass)
The mass given is 2.00 g and the Molecular mass is 39.09 units
∴ No. of moles = (2) / (39.09) = 0.05
From the above reaction, we get that 2 moles of potassium give 1 mole of hydrogen gas. Thus, 0.05 moles of potassium gives 0.025 moles of hydrogen gas.
Therefore, the no. of moles of hydrogen gas produced is 0.025 moles.
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The titration of 78.5 mL of an unknown concentration H3PO4 solution requires 134 mL of 0.224 M KOH solution. What is the concentration of the H3PO4 solution
Answer:
0.127 M.
Explanation:
The balanced equation for the reaction is given below:
H3PO4 + 3KOH —› K3PO4 + 3H2O
From the balanced equation above, we obtained the following data:
Mole ratio of acid, H3PO4 (nA) = 1
Mole ratio of base, KOH (nB) = 3
Data obtained from the question include:
Volume of acid, H3PO4 (Va) = 78.5 mL
Molarity of acid, H3PO4 (Ma) =...?
Volume of base, KOH (Vb) = 134 mL
Molarity of base, KOH (Mb) = 0.224 M
The concentration of the acid, H3PO4 can be obtained as follow:
MaVa / MbVb = nA/nB
Ma x 78.5 / 0.224 x 134 = 1/3
Cross multiply
Ma x 78.5 x 3 = 0.224 x 134 x 1
Divide both side by 78.5 x 3
Ma = (0.224 x 134 x 1) /(78.5 x 3)
Ma = 0.127 M
Therefore, the concentration of the acid, H3PO4 is 0.127 M.
What is a relief in relation to topography ?
Answer:
Relief is typically defined as the difference in height between the high point and the low point on a landscape, in feet or in meters.
Explanation:
Answer:
Relief is the difference in elevation between two points. It is easily calculated by subtracting the lowest elevation from the highest elevation in an area.
Explanation:
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Calculate your total body volume in liters assuming an average body density of 0.90 g/ml. (Use 130 lbs.
as your body weight.)
The volume of a substance is its mass divided by density. If the mass of your body is 130 lbs or 58.9 kg, then, volume is 65 L.
What is density ?Density of substance is the measure of its mass per unit volume. It describes how closely its particles are packed. Density depends on the bond type, temperature and pressure.
Volume of the object is the space occupied by its particles. Volume can be expressed in L, ml, cm³, dm³ etc. Only solids and liquids has a definite volume and the volume of gases is that of the container.
Give that, mass of body = 130 lbs
density = 0.90 g/ml
1 lbs = 0.453 kg or 453.5 g
then , 130 lbs = 58900 g or 58.8 kg
volume = mass/density
= 58900g / 0.90 g/ml
= 65444ml =65.44 L.
Therefore, the volume of our body will be 65.44 L.
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How many moles of nitrogen gas are produced when 36.0 g of NH4NO3 reacts?
The balanced chemical equation for the decomposition of NH4NO3 is:
NH4NO3(s) → N2(g) + 2H2O(g)
what is the molar mass of NH4NO3 ?
The molar mass of NH4NO3 is 80.04 g/mol, which means that 1 mole of NH4NO3 has a mass of 80.04 g.
To find the number of moles of N2 produced, we first need to determine how many moles of NH4NO3 are present in 36.0 g:
moles of NH4NO3 = mass / molar mass
moles of NH4NO3 = 36.0 g / 80.04 g/mol
moles of NH4NO3 = 0.4498 mol
According to the balanced equation, 1 mole of NH4NO3 produces 1 mole of N2. Therefore, the number of moles of N2 produced is also 0.4498 mol.
The balanced chemical equation for the decomposition of NH4NO3 is:
NH4NO3(s) → N2(g) + 2H2O(g)
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How to balance the following equations using algebraic method ( A value is 2 ) ( please include explanation )1- KNO3 + H2CO3 = K2CO3 + HNO32- Pb(OH)4 + Cu2O = PbO2 + CuOH3- Cr(NO2)2 + (NH4)2SO4 = CrSO4 + NH4NO24- KOH + Co3(PO4)2 = K3PO4 + Co(OH)25- Sn(NO2)4 + Pt3N4 = Sn3N4 + Pt(NO2)46-B2Br6 + HNO3 = B(NO3)3 + HBr7-ZnS + AlP = Zn3P2 + Al2S3
To balance the given equation using algebraic method, assign variables to the coefficients of each substance, for example, in this case:
\(a\cdot KNO_3+b\cdot H_2CO_3\to c\cdot K_2CO_3+d\cdot HNO_3\)The coefficient of KNO3 is a, for H2CO3 is b, for K2CO3 is c and for HNO3 is d.
Now, make an element balance per each element present in the reaction. For example, for potassium, in the reactants it is present a times, in the products it is present 2c (coefficient times subscript), it means that:
\(a=2c\)For oxygen, in the reactants it is present 3a+3b times, in the products it is present 3c+3d times:
\(3a+3b=3c+3d\)For nitrogen:
\(a=d\)For hydrogen:
\(2b=d\)For carbon:
\(b=c\)Now, the statement tells us to use 2 as the value of a. Using this value and the algebraic equations stated, we can find the b, c and d:
\(\begin{gathered} a=2c \\ 2c=a \\ c=\frac{a}{2} \\ c=\frac{2}{2} \\ c=1 \end{gathered}\)\(\begin{gathered} b=c \\ b=1 \end{gathered}\)\(\begin{gathered} a=d \\ d=a \\ d=2 \end{gathered}\)Now, that we have the values for a, b, c and d, we can replace them in the chemical equation to obtain the balanced equation:
\(2KNO_3+H_2CO_3\to K_2CO_3+2HNO_3\)Describe how to calculate the Rf value for a spot on a TLC plate.
Answer:
In thin-layer chromatography, the retention factor (Rf) is used to compare and help identify compounds. The Rf value of a compound is equal to the distance traveled by the compound divided by the distance traveled by the solvent front (both measured from the origin).
Is a .5% glucose solution or a .5 M glucose solution more concentrated.
0.5 M glucose solution is more concentrated.
ExplanationsWhat is concentration?Concentration is defined as the measure of how much of a given substance there is mixed with another substance.
From the question given, we are to determine which of the solution is more concentrated.
For the 0.5% glucose solution, we will convert it to molarity as shown:
0.5% glucose solution means that there are 0.5 grams for each 100mL of the solution.
Since the molarity is obtained in mol/L of solution, 1L of the solution will conatin 5g of glucose.
Molarity = Mass/Molar mass of glucose
Molarity = 5g/180.156 = 0.028M
Since 0.028M glucose solution is less than 0.5M glucose solution, this shows that 0.5 M glucose solution is more concentrated.
NaOH(aq) is transferred into a test tube. CaCl2(aq) is added to the tube. What is the formula for the precipitate (if any) that forms
Answer:
2NaOH (aq) + CaCl2 (aq) -> 2NaCl(aq) + Ca(OH)2(s)
Formula of precipitate: Ca(OH)2 (s)
Explanation:
First, we do the double replacement reaction to determine our chemical equation between the reactants and products. Once we have our products, with a solubility chart (I added one below) we can determine which of the products is soluble or insoluble.
In this case NaCl is soluble or aqueous (meaning it can dissolve in water) and Ca(OH)2 is insoluble (meaning that when the reactions takes place, these two will form a solid/precipitate)