Answer:
mercury, uranium, neptunium, and plutonium
octahedral complexes has two more unpaired electrons in the high-spin configuration than in the low-spin configuration?
The example of this octahedral complex which has two more unpaired electrons in the high spin configuration than in the low spin configuration is Cobalt (II) or Co2+.
What are Octahedral complexes?
Octahedral complexes are coordination complexes with an octahedral molecular geometry. This geometry is characterized by six ligands attached to a central metal atom at the corners of an octahedron. Octahedral complexes are often used as catalysts in industrial processes, and they are also found in biological systems. The ligands can be either anionic, neutral, or cationic, and the central metal atom can be any of the transition metals from groups 3-12 of the periodic table. Octahedral complexes are often described in terms of their electron configuration, which is determined by the number of electrons in the ligands and the central metal atom. These complexes are important in many areas of chemistry, including inorganic, physical, and organometallic chemistry.
Octahedral complexes contains 6 ligands. The hybridization can be d2sp3 or sp3d2.
There are two types of spin complexes
High spin complexes: When Δo>PLow spin complexes: When Δo< PFor more information refer the attached file below
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invented by Bernard Launy and Jeremie Metz, and identify the flaws in the system in terms of energy inputs and outputs.
Invented by Bernard Launy and Jeremie Metz, flaws in the system in terms of energy inputs and outputs is the overbalanced wheel in which spokes are attached
Energy is the ability to do work to cause changes in matter
The overbalanced wheel perpetual motion machine is one of the most commonly proposed perpetual motion machine designed and wheel is designed to turn clockwise just after the weighted spoke reaches the top of the wheel and the spoke flip outward to the right exerting the force downward toward the ground and some energy will be lost from friction as the mechanism rub on the inner spoke and more energy will be lost when it transferred into sound and thermal energy
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Could really use some help with this!!! What are some chemical properties of nickel?
Answer:
Nickel is silvery-white, hard, malleable, and ductile metal.
It is a good conductor of heat and electricity.
It is bivalent, that is it has a valency of two.
The metal dissolves slowly in dilute acids.
Explanation:
Answer:
Atomic number: 28
Atomic mass: 58.71 g.mol
Melting point: 1453°C
Explanation:
I answered based off what i understood lol. I dunno if this is what you meant but here you go ig
Please answer the following question using the data below: H2O vapor content: 13 grams H2O vapor capacity: 52 grams at 25 degrees Celsius 13 grams at 10 ∘
C 52 grams at 30 ∘
C What is the dew point for the conditions listed above? LCL 3π5 25C Relative Humidity =100%
Given data:H2O vapor content: 13 gramsH2O vapor capacity: 52 grams at 25 degrees Celsius 13 grams at 10∘C52 grams at 30∘CFormula used to find the dew point:$$\dfrac{13}{52}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$\frac{1}{4}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$
Where A is the constantDew Point:It is the temperature at which air becomes saturated with water vapor when the temperature drops to a point where dew, frost or ice forms. To solve this question, substitute the given data into the formula.$$13/52=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$13(17.27-A)=3\pi A(ln100)$$By simplifying the above expression, we get$$A^2-17.27A+64.78=0$$Using the quadratic formula, we get$$A=9.9,7.4$$
The dew point is 7.4 since it is less than 10°C.More than 100:The term "More than 100" has not been used in the question provided.
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The number of industrial accidents this month fell to 977 accidents from 1193 accidents last month. Find the percent of decrease.
To find the percent of decrease in the number of industrial accidents from last month to this month, we need to calculate the difference between the two numbers, divide it by the original number, and then multiply by 100. The difference between last month's number of accidents (1193) and this month's number (977) is: 1193 - 977 = 216
To get the percent decrease, we divide the difference by the original number (1193) and multiply by 100: 216/1193 x 100 = 18.1% Therefore, the percent decrease in the number of industrial accidents this month is 18.1%. This means that there were 18.1% fewer accidents this month than there were last month. It's a positive trend that indicates that safety measures may be working and that people are taking the necessary precautions to avoid accidents. It's important to continue to monitor and improve safety practices to ensure that the number of industrial accidents continues to decrease over time.
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Convert the following measurements using dimensional analysis. Set up problem using factors. Cross out the units that cancel. YOU MUST SHOW YOUR WORK* PLEASE HELP
Answer:
1) 0.423 m
2) 3.107 mi
3) 68.18 kg
4) 0.0083 mem
5) 0.528 gal
6) 4300 mL
7) 32.4 mem
8) 523.013 km
9) 70.866 in
10) 2.3 yek
Note: I can’t type the about equal to sign or the sign that shows a repeating decimal, so check the image for that and my work.
Explanation:
What is the percent composition by mass of chlorine in LiCI
Answer: Lithium (Li) 16.373%
Chlorine (Cl) 83.627%
Explanation:
Explain all the ways in which CO2 (carbon dioxide) is transported in your body and finally exhaled from your lungs.
How many molecules of carbon dioxide, CO2, are in 38.5 moles?
Answer:
2.31847E25
Explanation:
One mole of anything contains 6.022 x 10^23 items.
I need help with these questions
The definition of astronomic bodies are indicated below with the sentences defining them.
What are astronomic bodies?Astronomic bodies are celestial objects that occur naturally in space.
Here are their definitions below:
a. Supernova exhibits strong gravitational pull such that no light can escape
b. A nebula a large cloud of gas or dust in space.
c. A white dwarf is what a medium-mass star becomes at the end of it's life.
d. Protostar is the earliest stage of a star's life.
e. Black dwarf is a star left at the core of a planetary nebula.
f. Neutron stars are the remains of a high mass star.
g. A supernova is what occurs when a red supergiant star explodes.
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True or False all non - metal elements are gassed at room temperature.
Answer:
false
Explanation:
you have bromine , its a non metal and liquid in room temperature
Balance the following chemical equation (if necessary): Ca(CâHâOâ)â(aq) + NaâCOâ(aq) â CaCOâ(s) + NaCâHâOâ(aq)
Balance the chemical equation, which involves the terms "balance" and "equation". Here's the balanced equation for the reaction: Ca(C₂H₃O₂)₂(aq) + Na₂CO₃(aq) → CaCO₃(s) + 2 NaC₂H₃O₂(aq)
In this equation, calcium acetate (Ca(C₂H₃O₂)₂) reacts with sodium carbonate (Na₂CO₃) to form calcium carbonate (CaCO₃) and sodium acetate (NaC₂H₃O₂). To achieve balance, coefficients are added before the chemical formulas to ensure that the number of atoms of each element is equal on both sides of the equation. In this case, the balanced equation has a coefficient of 2 in front of sodium acetate (NaC₂H₃O₂) on the product side. This ensures that the number of atoms of each element is conserved throughout the reaction, adhering to the principle of mass conservation in chemical reactions.
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What is the volume of 6.9 mol of oxygen at 233 K and a pressure of 4.0 atm
The volume of 6.9 mol of oxygen at 233 K and a pressure of 4.0 atm is approximately 12.0L.
To calculate volume of a gas, we can make use of Ideal Gas Law equation. It is a fundamental equation in thermodynamics that describes the behaviour of an ideal gas under certain circumstances. It relates pressure(P), volume(V), number of moles (n), and temperature(T) of an ideal gas using the equation:
PV = nRT
Where P = Pressure of the gas,
V = Volume of the gas,
n = Number of moles of the gas,
R = Ideal gas constant commonly expressed as 0.0821 L·atm/(mol·K) or 8.314 J/(mol·K),
T = Temperature of the gas.
In the question, we are given with:
n = 6.9 mol
T = 233 k
P = 4.0 atm
Substituting the above values in the equation to find the volume, we get:
4.0 * V = 6.9 * 0.0821 * 233
V = (6.9 * 0.0821 * 233) / 4.0
V = 11.9997 (approximately 12.0)
Therefore, The volume of 6.9 mol of oxygen at 233 K and a pressure of 4.0 atm is approximately 12.0L.
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what will be the result of the reaction
(CH3COO)2+redP +Cl2
Answer:
(CH3COO)2 + redP + Cl2 → ClCH2COOH + HCl
Explanation:
This is an example of halogenation of carboxylic acids at alpha carbon atom. In this reaction, red phosphorus and chlorine are treated with carboxylic acids having alpha hydrogen atom followed by hydrolysis to form alpha chloro carboxylic acid.
the number of unpaired electrons in an oxygen atom is
The number of unpaired electrons in an oxygen atom is 2.
An oxygen atom has six electrons in its outermost energy level, known as the valence shell. In its ground state, these electrons are distributed as follows: two electrons in the 2s orbital and four electrons in the 2p orbitals (two electrons in each of the three 2p orbitals).
For an oxygen atom, each of the three 2p orbitals can accommodate a maximum of two electrons.
In the ground state, two of the 2p orbitals are fully occupied by two electrons each, while the third 2p orbital has two unpaired electrons. Therefore, there are two unpaired electrons in an oxygen atom.
These unpaired electrons are responsible for the chemical reactivity of oxygen and its ability to form covalent bonds with other atoms to complete its valence shell and achieve a more stable electron configuration.
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A sample of nitrogen gas (N2) containing 1.5 x10^23 particles has the same number of particles as a sample containing -
Select one:
2.0 moles He
0.25 mole O2
1.0 mole H2
0.50 mole Ne
The correct answer is 0.25 mole of O2 as the number of particles in 0.25 mole of O₂ is equal to the number of particles in 0.249 moles of N₂.
Given, Number of nitrogen gas (N2) particles = 1.5 × 10²³ particles
To find: Same number of particles as a sample containing = ?
To find the same number of particles as in 1.5 × 10²³ particles of nitrogen gas, we need to convert the given number of particles into moles using Avogadro's number (6.022 × 10²³ particles/mol).
So,Number of moles of N₂ = number of particles of N₂ / Avogadro's number= 1.5 × 10²³ / 6.022 × 10²³ = 0.249 moles approximately
Now, let's calculate the number of particles present in each given option.
a) 2.0 moles of He
Number of particles of He = 2.0 moles × Avogadro's number
= 2.0 × 6.022 × 10²³
= 12.044 × 10²³
b) 0.25 mole of O2
Number of particles of O₂ = 0.25 moles × Avogadro's number
= 0.25 × 6.022 × 10²³
= 1.506 × 10²³
c) 1.0 mole of H2
Number of particles of H₂ = 1.0 moles × Avogadro's number= 1.0 × 6.022 × 10²³
= 6.022 × 10²³
d) 0.50 mole of NeNumber of particles of Ne = 0.50 moles × Avogadro's number= 0.50 × 6.022 × 10²³
= 3.011 × 10²³
Hence, the correct answer is 0.25 mole of O2 as the number of particles in 0.25 mole of O₂ is equal to the number of particles in 0.249 moles of N₂.
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If the attractive forces in a substance is much less than the
molecular motion, then the substance will be in_____ state.
A) Solid
B)Liquid
C)Gaseous
D)Both A&B
in the compound h2so4, which element will be the central atom in the molecular structure?
The central atom in the molecular structure of H₂SO₄ is the sulfur atom (S). This is because the sulfur atom is bonded to four oxygen atoms and two hydrogen atoms, making it the central atom in the compound.
Molecular structure of H₂SO₄The molecular structure of H₂SO₄ can be represented as follows:
O
II
H - O - S - O - H
II
O
In this structure, the sulfur atom (S) is in the center, surrounded by oxygen atoms (O) and hydrogen atoms (H).
Therefore, the central atom in the molecular structure of H₂SO₄ is the sulfur atom (S).
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For an object to be seen, light must leave ___ and enter ___.
A. the eye; the brain
B. the object; the eye
C.the eye; the object
D.the brain; the eye
Answer:
C
Explanation:
Answer:
B. the object; the eye
Explanation:
Have a good day!
How many 15W LED bulbs could Niagara Falls power?
Complete question is;
Water flows over Niagara Falls at the average rate of 2,400,000 kg/s, and the average height of the falls is about 50 m. Knowing that the gravitational potential energy of falling water per second = mass (kg) x height (m) x gravity (9.8 m/s²), what is the power of Niagara Falls? How many 15 W LED light bulbs could it power?
Answer:
A) Power of Niagara Falls = 1.176 × 10⁹ W
B) 78.4 × 10⁶ bulbs
Explanation:
A) We are given;
The mass flow rate of Niagara falls = 2,400,000 kg/s
The average height of the fall = 50 meters
Gravitational potential energy = mass (kg) x height (m) x gravity (9.8 m/s²)
Now, formula for power is; workdone/time taken.
Thus it's potential energy/time taken.
Hence;
Power = (mass (kg) x height (m) x gravity (9.8 m/s²))/time(s)
We know that mass/time is mass flow rate.
Thus; power = mass flow rate (kg/s) × height (m) × gravity (9.8 m/s²)
Thus;
Power of Niagara Falls = 2400000 × 50 × 9.8 m/s²
Power of Niagara Falls = 1.176 × 10⁹ W
B) The number(n) of 15 W LED light bulbs Niagara falls could power is given by the relationship;
n × 15 W = 1.176 × 10⁹ W
Thus;
n = 1.176 × 10⁹ W/(15 W)
n = 78.4 × 10⁶ light bulbs
The number of 15 W LED light bulbs Niagara falls could power = 78.4 × 10⁶ bulbs
When zirconium salts are complexed with the yellow dye, alizarin, a red-colored product is formed. Fluoride ions form a complex with zirconium, displacing the dye. Balance and add phase labels to the following reaction for the fluoride test (do not include the color labels):
To balance and add phase labels to the reaction for the fluoride test, we first need the chemical equation. Since the provided information mentions the formation of a red-colored product and the displacement of alizarin dye by fluoride ions, we can assume the reaction as follows:
Zirconium salt + Alizarin (yellow dye) + Fluoride ions → Zirconium fluoride complex + Displaced dye
To balance the equation, we would need specific zirconium salts and their respective formulas. However, for the sake of demonstration, let's assume a generic zirconium salt represented as ZrXn, where X represents the anionic component of the salt, and n represents the charge.
ZrXn + Alizarin + Fluoride ions → ZrFm + Displaced dye
Now, let's add phase labels to each component:
ZrXn (aq) + Alizarin (aq) + Fluoride ions (aq) → ZrFm (s) + Displaced dye (aq)
Please note that the phase labels (aq for aqueous and s for solid) are assumed here and can vary depending on the actual zirconium salt used and the properties of the dye and fluoride ions.
Zr(Alizarin)3(aq) + 3F-(aq) → ZrF3(s) + 3Alizarin(aq)
In this reaction:
1. Zirconium complexed with alizarin (Zr(Alizarin)3) is in the aqueous phase.
2. Fluoride ions (F-) are in the aqueous phase.
3. Zirconium fluoride (ZrF3) forms as a solid.
4. The displaced alizarin dye remains in the aqueous phase.
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calculate the energy of a photon of radiation having a frequency of 3.54×10^14hertz
(I would appreciate a thanks, a rating and/or a Brainliest rating if this helped you)
Answer:
2.35 x 10^-19 joules
Explanation:
The energy (E) of a photon can be calculated using the following formula:
E = hν
where h is Planck's constant (6.626 x 10^-34 joule seconds) and ν is the frequency of the radiation.
So, to calculate the energy of a photon with a frequency of 3.54 x 10^14 hertz, we can substitute the values in the formula:
E = (6.626 x 10^-34 J s) x (3.54 x 10^14 Hz)
E = 2.35 x 10^-19 joules
Therefore, the energy of a photon of radiation with a frequency of 3.54×10^14 hertz is 2.35 x 10^-19 joules.
Which of these peptides is positively charged, which is
negatively charged, and which is neutral at physiological pH? What
is the charge on each peptide?
SDEKAINVKWQLA
SDEKAINVKWQHA
SEERAINVAWQHA
SDEK
This peptide is positively charged at physiological pH. In conclusion, SDEKAINVKWQLA and SDEKAINVKWQHA are neutral at physiological pH, SEERAINVAWQHA is negatively charged, and SDEK is positively charged.A peptide is a short chain of amino acids that are joined together with peptide bonds.
The nature of a peptide's charge depends on the overall charges of the amino acids in the sequence. At physiological pH, amino acids will either be positively charged, negatively charged, or neutral, depending on their side chains. Let's examine the peptides provided to determine their charges at physiological pH:SDEKAINVKWQLA: This peptide contains a mix of amino acids with positively charged, negatively charged, and neutral side chains. However, the positively charged amino acid (lysine) and the negatively charged amino acid (aspartic acid) are present in equal amounts.
Therefore, this peptide is considered neutral at physiological pH.SDEKAINVKWQHA: This peptide is similar to the first one but has one less amino acid (alanine instead of leucine at the end). It contains the same number of positively charged and negatively charged amino acids, and so it is also neutral at physiological pH.SEERAINVAWQHA: This peptide contains three negatively charged amino acids (aspartic acid and glutamic acid) and only one positively charged amino acid (lysine). Therefore, the peptide overall is negatively charged at physiological pH.SDEK: This peptide contains both positively charged (lysine) and negatively charged (aspartic acid) amino acids. However, there are more positively charged amino acids in the peptide than negatively charged ones.
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Will give brainliest
Please Help!
3/1H + 2/1H → 1/0n + ?
a. 4/4Be
b. 2/1H
c. 3/0n
d. 4/2He
Answer:
I'm pretty sure the answer Is c because I think I remember doing something like that so yeah
The ocean contains a large amount of carbon in the dissolved form.
A. Atmospheric CO2 in the Southern Hemisphere is higher in January than it is in July.
B. The following is NOT true regarding the carbon cycle: C. Trees grow faster when atmospheric CO2 is higher. D. The amount of carbon in the atmosphere depends on processes occurring both on land and in the ocean.
E. The flux of CO2 into of the ocean is currently greater than the flux of carbon out of the ocean.
The one that is NOT true regarding the carbon cycle is option C: Trees grow faster when atmospheric CO2 is higher.
In reality, trees do tend to benefit from increased atmospheric CO2 levels through a process known as carbon fertilization. Higher concentrations of CO2 can enhance photosynthesis and stimulate plant growth to some extent. However, the relationship between increased CO2 and tree growth is not a universal rule. The growth response of trees to elevated CO2 levels can vary depending on various factors, such as nutrient availability, water availability, temperature, and species-specific characteristics.
Regarding the other statements:
A. Atmospheric CO2 in the Southern Hemisphere is higher in January than it is in July: This statement is generally true. Seasonal variations in CO2 levels occur due to the interplay of factors such as vegetation growth, temperature, and atmospheric circulation patterns.
B. The amount of carbon in the atmosphere depends on processes occurring both on land and in the ocean: This statement is true. The carbon cycle involves exchanges of carbon between the atmosphere, land, and ocean through processes such as photosynthesis, respiration, combustion, and oceanic absorption.
E. The flux of CO2 into the ocean is currently greater than the flux of carbon out of the ocean: This statement is also true. Human activities, particularly the burning of fossil fuels, have increased the concentration of CO2 in the atmosphere. As a result, the ocean acts as a sink, absorbing more CO2 than it releases.
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Calculate the average atomic mass element X
Answer:
39.02 amu
Explanation:
The average atomic mass of an element can be calculated as follows :
\(X=\dfrac{9.67\times 38+78.68\times 39+11.34\times 40+0.31\times 41}{100}\\\\X=\dfrac{3902.29}{100}\\\\X=39.02\ amu\)
So, the atomic mass of the element X is 39.02 amu.
Which of the following is used to measure the large amount of liquids necessary for reagents?
A. Hemocytometer
B. Volumetric Beaker
C. Pipette
A C. pipette is used to measure the large amounts of liquid necessary for reagents. A hemocytometer is used to count cells, while a volumetric beaker is used for measuring fixed volumes of liquids accurately.
A pipette is used to measure the large amounts of liquid necessary for reagents. It allows for accurate and precise liquid transfer and measurement, making it a suitable choice for handling reagents in various applications.
A pipette (sometimes spelled pipette) is a laboratory instrument used in chemistry, biology, and medicine to transfer liquids, often media. Pipettes come in many designs with varying levels of accuracy and precision for different purposes, from single glass pipettes to multi-process or electronic pipettes.
Many types of pipettes work by creating a partial vacuum above the liquid holding chamber and selectively releasing this vacuum to draw in and release the liquid. Accurate measurement is different from measurement.
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If 5.50 mol of a gas occupies 230 L at constant temperature and pressure, how many moles are there if the volume is decreased to 176 L?
Answer:
4.21 moles are the moles of the gas when the volume decreases
Explanation:
Based on Avogadro's law, the moles of a gas are proportional to its volume under pressure and temperature constants. The formula is:
\(\frac{V_1}{n_1} =\frac{V_2}{n_2}\)
Where V₁ is initial volume (230L)
n₁ is initial moles (5.50mol)
V₂ is final pressure (176L)
And n₂ are final moles:
176L * 5.50mol / 230L = n₂ =
4.21 moles are the moles of the gas when the volume decreaseswhy can flame tests be effectively utilized to identify a cation in a solution?
The flame test can be effectively used to identify a cation in a solution because when a cation is placed in a flame, it will emit a different color with
visibile light.
Ions are charged particles that form when atoms gain or lose electrons. When an atom gains electrons, it forms negatively charged ions called negative ions. On the other hand, positively charged ions, called cations, are formed when atoms lose electrons. These ions can be detected in solution using special tests. The flame test involves exposing a joint to a flame and identifying the joint by flame color. The color of the flame test is due to the fact that electrons in metal cations are excited and jump to higher energy levels.
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