The force that must be exerted on the master cylinder of the hydraulic lift to support the weight of car is 147.2 N .
The Pascal's Law states that the relation between the pressure , force and area is given as :
Pressure = Force/Area ;
given that the diameter of the master cylinder is = 1.93 cm ;
so radius of master cylinder = 1.93/2 = 0.965 cm = 0.00965 m ;
the diameter of slave cylinder is = 24.9 cm ;
the radius of the slave cylinder = 24.9/2 = 12.45 m = 0.1245 m ;
Area of slave cylinder (A₁)= π(0.1245)² = 0.0486 m²
Area of the master cylinder (A₂) = π(0.00965)² = 0.000292 m² ;
given mass of the car = 2500 Kg ,
the force exerted will be : F = m*a
F₁ = 2500*9.8 = 24500 N ;
F₁/A₁ = F₂/A₂
So , 24500/0.0486 = F₂/0.000292
F₂ = (24500/0.0486)×0.000292
F₂ = 147.2 N
Therefore , the force exerted on the master cylinder is 147.2 N .
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You weigh 580 N on Earth. If you were to go to Mars, where its gravitational pull is 3 . 7 11 m /s 2 , what would you weigh? (Hint: gravity on Earth is 9.8 m /s 2 .
Answer:
59.18 kg
Explanation:
use f=ma
f= 580 N
a = 9.8 m/s 2
weigh(m) doesn't change only force(F) changes
Answer: 219.6N
Explanation:
Find the mass of this person by dividing his weight by the accelleration. Remember, F=ma
580 = m*9.8
m = 59.18kg
Then multiply the mass by the new gravitational acceleration on Mars.
59.18*3.711 = 219.6N
which tube do you think will have the highest lipase activity
The tube with the highest lipase activity is Tube B.
To determine the tube with the highest lipase activity, we need to compare the conditions and factors that can influence lipase activity in each tube. Lipase is an enzyme responsible for the hydrolysis of fats into fatty acids and glycerol.
In Tube A, lipase activity is affected by the pH level. Lipase functions optimally at a pH of around 7 to 8. If the pH in Tube A is within this range, it would support lipase activity.
In Tube B, lipase activity is influenced by both the pH level and temperature. Lipase enzymes generally have an optimum temperature at which they exhibit maximum activity. To calculate lipase activity, we need to compare the pH and temperature conditions in each tube.
Let's assume that the pH in both tubes is within the optimal range for lipase activity (pH 7 to 8). However, if Tube B is maintained at a higher temperature than Tube A, it will likely have a higher lipase activity. Lipase activity generally increases with temperature until it reaches an optimum point, beyond which it decreases.
Based on the assumption that the pH is within the optimal range in both tubes, Tube B is expected to have the highest lipase activity if it is maintained at a higher temperature than Tube A. It is essential to note that other factors, such as substrate concentration and the presence of inhibitors or activators, can also affect lipase activity. Therefore, the conclusion is based on the given information about pH and temperature.
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Let the angle be the angle that the vector A makes with the +x-axis, measured counterclockwise from that axis. Find the
angle for a vector that has the following components.
Ax=1.50, Ay=1.30
The angle formed by the vector and the positive or counterclockwise of x-axis is 40.91°
What are Vectors ?The term "vector" is used informally to describe constituents of particular vector spaces or some values that cannot be described by a single integer.
A quantity or phenomena with independent qualities for both size and direction is called a vector. The word can also refer to a quantity's mathematical or geometrical representation. Velocity, momentum, force, electromagnetic fields, and weight are a few examples of vectors in nature.
Any vector with a two-dimensional direction may be conceived of as having two distinct parts. The impact of a single vector in a certain direction is described by its component.
The components are
Aₓ = 1.50
Ay = 1.30
We can find the angle of the vector by using the formula
\(tan\theta = \frac{A_{y} }{A_{x} }\) = \(\frac{1.30}{1.50} =\)
⇒\(\theta = tan\x^{-1}(1.3/1.5)\)
⇒θ = 40.91°
The angle formed by the vector and the positive or counterclockwise of x-axis is 40.91°
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2 cultural practices for cultivation of tomatoes
At divergent boundaries, hot mantle rock rises and
occurs.
Residence time for water in Lake Tahoe, Nevada/California is 600 years which means thatSelected A. A water molecule entering the lake will remain in the lake for 600 years.
B. The total volume of water in Lake Tahoe remains constant for 600 years.
C. The water in Lake Tahoe will sustain aquatic life for 600 years.
D. Outflow from Lake Tahoe occurs once every 600 years.
The correct answer is A. A water molecule entering the lake will remain in the lake for 600 years.
What is residence time?Residence time refers to the average amount of time that a water molecule spends in a particular body of water, such as a lake. In the case of Lake Tahoe, the residence time is approximately 600 years. This means that, on average, a water molecule that enters the lake will remain in the lake for 600 years before leaving through the outlet.
Option B is incorrect because the total volume of water in Lake Tahoe can vary due to precipitation, evaporation, and other factors.
Option C is also incorrect because the residence time of water in Lake Tahoe does not necessarily relate to the ability of the lake to sustain aquatic life.
Option D is incorrect because outflow from Lake Tahoe occurs regularly and is not limited to once every 600 years.
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determine the molar concentration of 4 moles of HCL dissolved in 2500 ml of solution
Answer:
1.6 molar
Explanation:
C=number of moles/volume
convert ml to L
V =2.5L
C= 4/2.5
=1.6 molar
which of the following is an example of the law of multiple proportions?
The answer option which is an example of the law of multiple proportions is: B) Two different compounds formed from carbon and oxygen have the following mass ratios: 1.33 g O: 1 g C and 2.66 g O: 1 g C.
The Law of Multiple Proportions is also referred to as Dalton's Law and it states that when two chemical elements combine to form more than one chemical compound, the masses (weights) of one chemical element that combine with a fixed mass (weight) of the other chemical element will always be in a ratio of small whole numbers.
According to the Law of Multiple Proportions, when two chemical elements combine to form two different chemical compound, the masses (weights) of one chemical element that combine with 1 gram of the other chemical element can be expressed as a ratio of small whole numbers.
For example, carbon and oxygen react to form either carbon monoxide and carbon dioxide.
Carbon monoxide (CO):
12 grams of C = 16 grams of O.
1 gram of C = 1.33 gram of O.
Carbon dioxide (\(CO_2\)):
12 gram of C = 32 grams of O.
1 gram of C = 2.66 gram of O.
Ratio of oxygen (O) = 16:32 = 1:2 (Law of Multiple Proportions).
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Your question is lacking the necessary answer options, so I will be adding them here:
A. A sample of chlorine is found to contain three times as much Cl-35 as Cl-37.
B. Two different compounds formed from carbon and oxygen have the following mass ratios: 1.33 g O: 1 g C and 2.66 g O: 1 g C.
C. Two different samples of table salt are found to have the same ratio of sodium to chlorine.
D. The atomic mass of bromine is found to be 79.90 amu.
E. Nitrogen dioxide always has a mass ratio of 2.28 g O: 1 g N.
a mass of 3 kg is attached to the end of a spring that is stretched 17 cm by a force of 13.5 n. it is set in motion with an initial position and initial velocity (in m/s) . find the amplitude, period, and frequency of the resulting motion. you should assume that the system is frictionless.
The mass of 3 kg attached to a spring that is stretched 17 cm by a force of 13.5 N is set in motion with an initial position and initial velocity (in m/s). The resulting motion can be characterized by the amplitude, period, and frequency of the motion. The amplitude of the motion is the maximum displacement from the equilibrium position of the mass, the period is the time for one complete cycle, and the frequency is the number of cycles per unit time.
To calculate the amplitude, period, and frequency of the resulting motion, we need to use the equation for simple harmonic motion:
x = Acos(ωt + θ)
Where x is the displacement of the mass, A is the amplitude, ω is the angular frequency, and θ is the phase angle.
The angular frequency can be calculated as: ω = sqrt(k/m)
Where k is the spring constant and m is the mass.
The phase angle can be calculated as: θ = (v0/A) + ωt
Where v0 is the initial velocity and A is the amplitude.
Using these equations, we can calculate the amplitude, period, and frequency of the resulting motion.
The amplitude of the motion is the maximum displacement from the equilibrium position of the mass. It can be calculated as: A = (m/k)*(v0^2 + 2gh)
The period is the time for one complete cycle and can be calculated as: T = 2π/ω
Finally, the frequency is the number of cycles per unit time and can be calculated as: f = 1/T
In conclusion, given the mass of 3 kg attached to a spring that is stretched 17 cm by a force of 13.5 N and set in motion with an initial position and initial velocity (in m/s), the amplitude, period, and frequency of the resulting motion can be calculated using the equations for simple harmonic motion.
what was the dwarf planet discovered in AZ?
Answer:
Pluto.
Explanation:
an observary in Flagstaff, Arizona, discorvered it.
A 13561 N car traveling at 51.1 km/h rounds
a curve of radius 2.95 × 102 m.
The acceleration of gravity is 9.81 m/s
a) Find the centripetal acceleration of the
car. Answer in units of m/s
Find the force that maintains circular motion.
Answer in units of N.
c) Find the minimum coefficient of static friction between the tires and the road that will
allow the car to round the curve safely.
Answer:
a) The centripetal acceleration of the car is 0.68 m/s²
b) The force that maintains circular motion is 940.03 N.
c) The minimum coefficient of static friction between the tires and the road is 0.069.
Explanation:
a) The centripetal acceleration of the car can be found using the following equation:
\( a_{c} = \frac{v^{2}}{r} \)
Where:
v: is the velocity of the car = 51.1 km/h
r: is the radius = 2.95x10² m
\( a_{c} = \frac{(51.1 \frac{km}{h}*\frac{1000 m}{1 km}*\frac{1 h}{3600 s})^{2}}{2.95 \cdot 10^{2} m} = 0.68 m/s^{2} \)
Hence, the centripetal acceleration of the car is 0.68 m/s².
b) The force that maintains circular motion is the centripetal force:
\( F_{c} = ma_{c} \)
Where:
m: is the mass of the car
The mass is given by:
\( P = m*g \)
Where P is the weight of the car = 13561 N
\( m = \frac{P}{g} = \frac{13561 N}{9.81 m/s^{2}} = 1382.4 kg \)
Now, the centripetal force is:
\( F_{c} = ma_{c} = 1382.4 kg*0.68 m/s^{2} = 940.03 N \)
Then, the force that maintains circular motion is 940.03 N.
c) Since the centripetal force is equal to the coefficient of static friction, this can be calculated as follows:
\( F_{c} = F_{\mu} \)
\( F_{c} = \mu N = \mu P \)
\( \mu = \frac{F_{c}}{P} = \frac{940.03 N}{13561 N} = 0.069 \)
Therefore, the minimum coefficient of static friction between the tires and the road is 0.069.
I hope it helps you!
What is the difference between light and electromagnetic wave?.
Explanation:
Explanation:Light is a form of electromagnetic radiation. Other forms of electromagnetic radiation include radio waves, microwaves, infrared radiation, ultraviolet rays, X-rays, and gamma rays. ... The only difference between them is their wavelength, which is directly related to the amount of energy the waves carry.Applying the Learning Curve Theory to a Project & Establishing a Project Time-Line plus costs involved Time and cost estimates are important to project management for the following reasons: Estimates are key inputs to project planning and control. Estimates support good decisions. Estimates are used to determine project duration and cost. Estimates are used to develop time-phased budgets and establish the project baseline. Without estimates, you have inaccuracies, which result in time and cost under/overruns. Most project tasks are unique and require the project manager to estimate duration/cost for each and every task separately; however, projects may also have repetitive tasks completed by the human resources assigned to the project. To estimate the labor hours/cost for these tasks the project manager may use an estimating technique that relies on learning curve theory to estimate the time and/or cost for completing repetitive tasks. In this assignment, you will: Task #1. Define and thoroughly discuss the Learning Curve Theory and how it applies to project management. Task #2. Explain how you would apply the principles of the Learning Curve Theory to a real project in which you are familiar (as a project manager, team member, or one that you have read about in current events). Task #3. Complete the following exercise on learning curves (see Page 2 of this assignment). Instructions for completing the assignment: Search out scholarly resources related to the subject of this assignment;You may also use your textbook as a resource. In MS Word, compose a paper of 300-400 words (approximately 1 page) that addresses Task #1 and Task #2. Insert your response to the Exercise on learning curves (Task #3) and include all supporting calculations. Using the concept of Learning Curves for Estimating (Chapter 8, Pinto) consider the following scenario and respond to each question (all work should be shown in your Word document): Suppose that you are the assigning costs to a major project to be undertaken this year by your firm, University Applications. One particular coding process involves many labor-hours, but highly redundant work. You anticipate a total of 200,000 labor-hours to complete the first iteration of the coding and a learning curve rate of 70%. You are attempting to estimate the cost of the twentieth iteration of this coding sequence. Based on this information and a $60 per hour labor rate, what would you expect to budget as A. The cost of the twentieth iteration? B. The cost of the fortieth iteration? EXERCISE 2 - Plan for delivery schedule & cost of a Business entity: For a company engaged in design and delivery of a nursing home in Maryland, the following tasks (Not in a proper order), with corresponding duration and cost for each task are envisaged for the plan. Please fill the following table by listing all the necessary tasks involved in proper sequence, showing start & finish of each task and associated costs on a Gantt Chart, then find the total project proposed value/price to client by including 12% for the overhead, and 15% for profits: Locate and survey the land 3 weeks $15,000 Approvals 1 week ------ Select Contractors 2 week $3000 Design details and develop business plan 14 weeks $48,000 Grading of the land, Water & Sewer lines 3 weeks $25,000 Install Security System 1 week $12,000 Build Frame structure & walls 5 weeks $65,000 Install Windows & Doors 2 weeks $20,000 Install Air-conditioning System 2 weeks $25,000 Build Foundations 3 weeks $30,000 Install Electrical lines, Plumbing 2 weeks $18,000 Flooring 1 week $15,000 Carpeting & Clean up 1 week $12,000 Painting 1 week $14,000
Applying the Learning Curve Theory to a Project & Establishing a Project Time-Line plus costs involved Time and cost estimates are important to project management for the following reasons .To create a Gantt Chart with the necessary tasks, their duration, and costs, and determine the total project proposed value/price.
Task #1: Learning Curve Theory and its application to project management
The Learning Curve Theory, also known as the experience curve or the productivity improvement curve, is a concept that describes the relationship between the cumulative production volume of a task or activity and the corresponding improvement in performance or efficiency. It suggests that as workers gain experience and familiarity with a task, they become more efficient, resulting in reduced time and cost requirements for subsequent repetitions of the task.
In project management, the Learning Curve Theory can be applied to estimate the time and cost involved in completing repetitive tasks. It is particularly useful when there is a significant volume of repetitive work, and the performance improvement pattern can be observed and quantified. By understanding and utilizing the learning curve effect, project managers can make more accurate predictions and establish realistic project timelines and budgets.
Task #2: Application of Learning Curve Theory to a real project
To apply the principles of the Learning Curve Theory to a real project, let's consider the construction of a residential housing complex. As a project manager, you have noticed that the construction of individual houses within the complex follows a repetitive pattern, where the same tasks are performed with minor variations for each house.
By analyzing historical data and observing the construction progress, you identify that the learning curve rate for the construction tasks is 80%. This means that for every doubling of the cumulative number of houses built, the time and cost required for constructing each subsequent house will decrease by 20%.
Based on this information, you can estimate the time and cost for future iterations of house construction. For example, if it took 100 days and $200,000 to complete the first house, you can use the learning curve rate to estimate the time and cost for the tenth house. With a 80% learning curve rate, the time required for the tenth house would be approximately 37 days, and the cost would be reduced to $53,333.
By applying the Learning Curve Theory, you can gain insights into the expected performance improvement and adjust project plans, schedules, and budgets accordingly. This helps in better resource allocation, cost estimation, and project control.
Task #3: Exercise on learning curves
Based on the given information, let's calculate the cost of the twentieth and fortieth iterations of the coding sequence:
Given:
Total labor hours for the first iteration (N1) = 200,000
Learning curve rate (LC) = 70%
Labor rate per hour (LR) = $60
A. Cost of the twentieth iteration:
N20 = N1 * (20^logLC/log2)
N20 = 200,000 * (20^0.8451/0.301)
N20 ≈ 200,000 * 1.9923
N20 ≈ 398,460 labor hours
Cost of the twentieth iteration = N20 * LR
Cost of the twentieth iteration ≈ 398,460 * $60
Cost of the twentieth iteration ≈ $23,907,600
B. Cost of the fortieth iteration:
N40 = N1 * (40^logLC/log2)
N40 = 200,000 * (40^0.8451/0.301)
N40 ≈ 200,000 * 3.5251
N40 ≈ 705,020 labor hours
Cost of the fortieth iteration = N40 * LR
Cost of the fortieth iteration ≈ 705,020 * $60
Cost of the fortieth iteration ≈ $42,301,200
Exercise 2: Plan for delivery schedule & cost of a Business entity
To create a Gantt Chart with the necessary tasks, their durations, and costs, and determine the total project proposed value/price, the provided table and information need to be organized and analyzed. Since the table was not included in the question, I cannot create the Gantt Chart and perform the calculations. However, you can list the tasks in the proper sequence, assign start and finish dates, and calculate the associated costs for each task. Then, by including 12% for overhead and 15% for profits, you can determine the total project proposed value/price to the client.
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How does an inclined plane increase force?
Acceleration will increase as the angle of incline does, and as a result, force will as well.
The gravitational force acting on the cart increases as the slope of the incline increases, causing it to accelerate more quickly.The ramp's steepness will cause an increase in inclination. As a result, the acceleration increases as the inclination angle increases. This acceleration causes the object to descend with greater speed.
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An ice skater is going into a spin. To simplify the system, the skater’s body (legs, torso, head) has a moment of inertia of 1.719kgm^2. Each hand-arm can be modeled as a point of mass of 5.0kg. At the beginning of the spin, the masses are rotating at 0.50m/s with their arms extended so that the center of mass of the hand-arm is 0.60m from the axis of rotation. For the finale, the skater pulls their arm inward so that the hand-arm is 0.20m from the axis of rotation. What is the angular velocity of the skater during the finale?
The angular velocity of the skater during the finale is 2.18 rad/s.
The conservation of angular momentum is a principle in physics that states that the total angular momentum of a system remains constant if no external torques act on the system. Mathematically, this can be expressed as L1 = L2, where L1 is the initial angular momentum of a system, L2 is the final angular momentum of the system, and the total torque acting on the system is zero. This principle is analogous to the conservation of linear momentum, which states that the total linear momentum of a system remains constant if no external forces act on the system. The conservation of angular momentum is an important principle in many areas of physics, including mechanics, electromagnetism, and quantum mechanics.
We can use the conservation of angular momentum to solve this problem. The initial angular momentum of the skater and the hand-arms is given by:
L1 = I1 * w1
where I1 is the moment of inertia of the skater's body, and w1 is the initial angular velocity. Since the hand-arms are extended, their moment of inertia can be neglected.
When the skater pulls their arms inward, the moment of inertia of the system decreases. The final moment of inertia is given by:
I2 = I1 + 2md^2
where m is the mass of each hand-arm, d is the distance of the hand-arm from the axis of rotation, and we multiply by 2 since there are two hand-arms.
The final angular velocity w2 can be found by equating the initial and final angular momentum:
L1 = I1 * w1 = I2 * w2
Substituting the expressions for I1, I2, and simplifying, we get:
w2 = w1 * I1 / (I1 + 2m(d2^2 - d1^2))
where d1 is the initial distance of the hand-arm from the axis of rotation (0.60 m), and d2 is the final distance of the hand-arm from the axis of rotation (0.20 m).
Substituting the given values, we get:
w2 = 0.50 m/s * 1.719 kgm^2 / (1.719 kgm^2 + 2 * 5.0 kg * (0.20 m^2 - 0.60 m^2))
w2 = 2.18 rad/s
Therefore, The skater's angular velocity during the grand finale is 2.18 rad/s.
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a bowler releases a 7.0\,\text {kg}7.0kg 7, point, 0, start text, k, g, end text bowling ball from rest to a final velocity of 8.0\,\frac {\text m}{\text s}8.0 s m 8, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. what is the magnitude of the change in momentum of the bowling ball?
The magnitude of the change in momentum of the bowling ball is 56 kg·m/s.
When a bowler releases a bowling ball from rest and it reaches a final velocity of 8.0 m/s, we can calculate the change in momentum using the formula:
Change in momentum = final momentum - initial momentum
The initial momentum of the bowling ball is zero because it is at rest. The final momentum can be calculated by multiplying the mass of the bowling ball (7.0 kg) by its final velocity (8.0 m/s):
Final momentum = 7.0 kg × 8.0 m/s = 56 kg·m/s
Therefore, the magnitude of the change in momentum of the bowling ball is 56 kg·m/s.
Momentum is a fundamental concept in physics that describes the quantity of motion an object possesses. It is defined as the product of an object's mass and its velocity. The change in momentum of an object is equal to the final momentum minus the initial momentum. In this case, since the bowling ball starts from rest, its initial momentum is zero. The final momentum is calculated by multiplying the mass of the ball (7.0 kg) by its final velocity (8.0 m/s), resulting in a final momentum of 56 kg·m/s. This means that the bowling ball's momentum changed from zero to 56 kg·m/s during its motion.
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Stars appear to move in the sky because______
Answer:
Stars appear to move in the sky because earth rotates on its axis.
Explanation:
Stars appear to move in the sky because of Earth's rotation on its axis. As Earth rotates, it creates the illusion that the stars are moving in the opposite direction across the sky. This movement is similar to how objects appear to move past us when we are driving down the road. The stars themselves do not actually move, but our perspective from Earth makes it seem as though they are. This movement, along with the changing position of the sun, creates the patterns and movements that we see in the sky throughout the day and night.
An airplane is flying at a constant speed along with a constant height of 3 km that will take it directly over an observer at ground level. At a given instant, the observer notes that the angle between him and the airplane is 3π and is increasing at 201 radians per second. Find the speed of the airplane, in km/hr. b. Continue as part (a), if the airplane comes towards the observer at a constant angular rate of change 201, what is the speed of the airplane when it is directly over the head of the observer? c. Is the airplane slowing down or speeding up as it approaches the observer? Justify your conclusion.
A- The speed of the airplane is approximately 201 km/hr.
b. The speed of the airplane when directly over the observer is approximately ∞ km/hr.
c. The airplane is slowing down as it approaches the observer.
a. To find the speed of the airplane:
dx/dt = (1 + tan²(θ)) * dθ/dt
At θ = 3π, tan(3π) = 0, so:
dx/dt = (1 + 0²) * 201
dx/dt = 201 km/hr
b. To find the speed of the airplane when directly over the observer:
dx/dt = (1 + tan²(θ)) * dθ/dt
Taking the limit as θ approaches π/2 from below:
lim(θ→π/2-) (1 + tan²(θ)) = ∞
So the speed of the airplane is approximately ∞ km/hr.
c. We can observe from the rate of change equation dx/dt = (1 + tan²(θ)) * dθ/dt that the speed of the airplane, dx/dt, is directly dependent on the rate of change of the angle, dθ/dt. In this case, the rate of change of the angle is given as 201 radians per second.
Since the rate of change of the angle, dθ/dt, is positive and constant, we can conclude that the speed of the airplane, dx/dt, will also be positive and constant. This means that the airplane is moving forward at a constant speed.
As the airplane approaches the observer, the angle θ decreases, which implies that tan(θ) also decreases. Since the speed of the airplane is directly proportional to (1 + tan²(θ)), which is decreasing as θ decreases, the speed of the airplane gradually decreases.
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What are the three phases of an exercise program?
Ostrength, glycolytic, and power
Ostrength, oxidative, and time
O stabilization, power, and time
O stabilization, strength, and power
Answer:
Option 4 'stabilization, strength, and power' is correct.
Explanation:
During the stabilization phase, the focus is on developing proper movement patterns and improving muscular endurance to stabilize joints and improve overall posture.
During the strength phase, the focus shifts towards building muscular strength and increasing muscle size, typically through the use of heavier weights and lower reps.
Finally, during the power phase, the focus is on developing explosive power and speed through the use of plyometrics and other high-intensity exercises.
Which of the following describes the correct order of energy conversions necessary to form electricity from solar panels?
Solar Heat Kinetic → Electric
Solar- Kinetic Heat → Electric
Solar 1 Heat → Electric
O Solar ->Electric
Answer:
hydrochlorine +12÷B to the power of 4 -× y reapeated zminus 2 to the power of 9
A sledgehammer of mass m = 1.9 kg falls freely vertically downward from a height of h = 2.6 m at an initial speed of v = 11 m/s before striking a partially buried piling. After the blow the piling has moved d = 0.075 m deeper.How much kinetic energy, in joules, does the sledgehammer have just before striking the piling?
Answer:
Kinetic energy= 114.9J
Explanation:
Greetings !
Given values :-
mass= 1.9kg
height=2.6m
velocity= 11m/s
displacement (d)= 0.075m
Required value :-
Kinetic energy (KE)
Solution :-
Firstly, recall the Kinetic energy equation
\(ke = \frac{1}{2} mv {}^{2} \)
substitute known variables into the equation
\(ke = \frac{1}{2} (1.9)(11) {}^{2} \)
solve for Kinetic energy
\(ke = 114.9j\)
Hope it helps!!!
Refer to Figure 22-15 to answer the following
questions.
a. What should the ammeter reading be?
b. What should the voltmeter reading be?
c. How much power is delivered to the resistor?
d. How much energy is delivered to the resistor
per hour?
a. The ammeter reading should be I = V/R = 27V/9ohm = 3A.
b. The voltmeter reading should be 27V, since it is connected in parallel with the battery and measures the voltage across it.
c. The power delivered to the resistor can be calculated using P = VI = (I^2)*R = (3A)^2 * 9ohm = 27W.
d. The energy delivered to the resistor per hour can be calculated using E = Pt = 27W * 1 hour = 27 Wh.
What is an ammeter?
An ammeter is a measuring instrument used to measure electric current flowing through a circuit. It is typically connected in series with the circuit so that all the current flowing in the circuit passes through the ammeter. Ammeters can be analog or digital, and they are designed to measure different ranges of current. They are an essential tool for diagnosing and troubleshooting electrical problems, and they are commonly used in industrial, commercial, and residential applications.
What is a voltmeter?
A voltmeter is a measuring instrument used to measure the electric potential difference (voltage) between two points in an electrical circuit. It is typically connected in parallel with the circuit component or circuit section whose voltage is to be measured. When a voltage is present in the circuit, the voltmeter displays the measured value in volts, which can help to determine the performance or condition of the circuit.
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a. The ammeter reading should be I = V/R = 27V/9ohm = 3A.
b. The voltmeter reading should be 27V, since it is connected in parallel with the battery and measures the voltage across it.
c. The power delivered to the resistor can be calculated using P = VI = (I^2)*R = (3A)^2 * 9ohm = 27W.
d. The energy delivered to the resistor per hour can be calculated using E = Pt = 27W * 1 hour = 27 Wh.
What is an ammeter?An ammeter is a measuring device used to determine the amount of electric current passing through a circuit. It is usually wired in series with the circuit so that all current passing through it goes through the ammeter. Ammeters can be analogue or digital, and they are used to detect various current levels. They are an indispensable instrument for diagnosing and troubleshooting electrical issues, and they are widely used in industrial, business, and domestic settings.
A voltmeter is a measuring device used to determine the difference in electric potential (voltage) between two locations in an electrical circuit. It is usually linked in parallel with the circuit component or portion whose voltage is to be measured. When a voltage is present in the circuit, the voltmeter shows the measured value in volts, which can aid in determining the circuit's performance or state.
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what is the potential energy of a 2kg plant that is on a windowsill 1.3 m high?
what is the kinetic energy of a 7.26 kg bowling ball that is rolling at a speed of 2 m/s
an apple as 6 J of energy. the apple sits on a counter 3 m high. what is the mass of the apple/
Answer:
25.48
Explanation:
8. Paige dropped a ball out of a car while her friend Destiny was traveling at a velocity of 25
m/s. The ball underwent a deceleration of -2m/s² and rolled to a stop on the pavement. How
long did it take the ball to stop?
Answer:
I think it's 12.5s
Explanation:
Bare with me, because I just started physics, but I think I have the answer right... Hopefully.
starting with your knowns, we know velocity is 25 m/s from the problem. you also can figure out your acceleration, -2 m/s.
You're looking for the time it takes until the ball stops rolling. Your time is unknown.
Your equation would be a=v/t (acceleration being a, velocity being v, and time being t)
You have to solve for t giving you t=v/a
Now you have to fill in your numbers. t=25m/s divided by -2m/s^2
Your answer should end up as -12.5
You have to solve for your units, but since you're finding time it's pretty straightforward in knowing you're dealing with seconds.
Hope this helped... :) sorry if it didn't-
A point charge is placed at each corner of square with side leanth a. The charges all have same magnitude q. My question, What is the its magnitude in terms of q and a?
Answer:
E = k q / a² (1.3535) (- i ^ + j ^)
E = k q / a² 1.914 , θ’= 135
Explanation:
For this exercise we will use Newton's second law where we must add as vectors
E_total = E₁₂ i ^ + E₁₄ j ^ + E₁₃
Let's look for the value of each term
On the x axis
E₁₂ = k q / a²
On the y axis
E₁₄ = k q / a²
For the charge in the opposite corner we look for the distance
d = √ (a² + a²) = a √2
let's look for the field
E₁₃ = k q / d²
E₁₃ = k q / 2a²
let's use trigonometry to find the two components of this field
cos 45 = E₁₃ₓ / E₁₃
E₁₃ₓ = E₁₃ cos 45
sin 45 = E_{13y} / E₁₃
E_{13y} = E₁₃ sin 45
E₁₃ₓ = k q / 2a² cos 45
E_{13y} = k q / 2a² sin 45
let's find each component of the electric field
X axis
Eₓ = -E₁₂ - E₁₃ₓ
Eₓ = - k q / a² - k q / 2a² cos 45
Eₓ = - k q / a² (1 + cos 45/2)
cos 45 = sin 45 = 0.707
Eₓ = - k q / a² (1 + 0.707 / 2)
Eₓ = - k q / a² (1.3535)
Y axis
E_y = E₁₄ + E_{13y}
E_y = k q / a² + k q / 2a² sin 45
E_y = k q / a² (1 + sin 45/2)
E_y = k q / a² (1.3535)
we can give the results in two ways
E = k q / a² (1.3535) (- i ^ + j ^)
In modulus and angle form, let's use Pythagoras' theorem for the angle
E = √ (Eₓ² + E_y²)
E = k q / a² 1.3535 √2
E = k q / a² 1.914
we use trigonometry for the angle
tan θ = E_y / Eₓ
θ = tan⁻¹ (E_y / Eₓ)
θ = tan⁻¹ (1 / -1)
θ = 45
in the third quadrant, if we measure the angle of the positive side of the x-axis
θ‘= 90 + 45
θ’= 135
What potential difference is needed to give a helium nucleus (q=2e) 50.0 kev of kinetic energy?
A potential difference of 25.0 kV is needed to give a helium nucleus with a charge of 2e a kinetic energy of 50.0 keV.
To determine the potential difference required to give a helium nucleus a specific kinetic energy, we can use the equation for the kinetic energy of a charged particle accelerated through a potential difference.
The equation is given by:
KE = qV,
where KE is the kinetic energy, q is the charge of the particle, and V is the potential difference.
Given:
Kinetic energy (KE) = 50.0 keV = 50.0 x 10³ eV = 50.0 x 10³ x 1.6 x 10⁻¹⁹ J,
Charge (q) = 2e = 2 x 1.6 x 10⁻¹⁹ C (since the elementary charge e is 1.6 x 10⁻¹⁹ C).
We can rearrange the equation to solve for the potential difference (V):
V = KE / q.
Plugging in the given values:
V = (50.0 x 10³ x 1.6 x 10⁻¹⁹ J) / (2 x 1.6 x 10⁻¹⁹ C).
Canceling out the units and simplifying:
V = (50.0 x 10^3) / 2 = 25.0 x 10^3 V = 25.0 kV.
Therefore, a potential difference of 25.0 kV is needed to give a helium nucleus with a charge of 2e a kinetic energy of 50.0 keV.
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You slide a TV up a ramp to move it into a house. What kind of simple
machine are you using?
O A. Screw
B. Inclined plane
O c. Wheel and axle
O D. Lever
SUBMIT
Answer:
inclined plane
Explanation:
An inlcined plane is a simple machine used to slide an object over an obstacle
HELP! how did michael jordan influence future basketball players to make prodcuts?
Answer:
By encouraging them.
Explanation:
#CARRYONLEARNING
Answer:
His ability to soar to the basket and do things we'd never before seen captured the world's attention and helped make basketball more of a global sport than it had ever been. His reverse layups, slam dunks, and fadeaway shots were exciting to say the least.
Explanation:
Supriya has a pre-paid electricity connection at home. On a sultry Sunday afternoon, she checks that she only has ₹9 left in the balance. She wants to use the air conditioner (AC), rated at 1.2 kW. The price of electricity is ₹10 /unit in her area. How long can she run the AC before her balance is over and the power runs out?
Answer: 0.75 hour(s) or 45 minutes
Explanation:
1 unit of electricity = 1kwh
Amount of energy consumed by 1kw load in one hour
Price per unit = ₹10
Air conditioner rating(power) = 1.2Kw
Given that balance = ₹9
Therefore, supriya's total energy cost = energy balance = ₹9
Total energy cost = power in kilowatt × time of operation (in hour) × cost per unit
₹9 = 1.2kw × time × ₹10
₹9 = 12 × time
Time = 9 / 12
Time = 0.75 hours
0.75 × 60 = 45 minutes
When you plan a meal you should try to have the right foods for any health problem such as a food allergy. For example the food package or________to know the right serving
To have the right foods for any health problem such as a food allergy, check the food package or label to know the right serving.
What is food label?A food label is any piece of information contained in a food package that tells you how many calories and how much fat, protein, carbohydrates, and other nutrients are in one food serving.
Many packaged foods contain more than a single serving.
Thus, when you plan a meal you should try to have the right foods for any health problem such as a food allergy. For example the food package or label to know the right serving.
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