What evidence did Alfred Wegener use to support his theory of continental drift?

A. coastline fits between different continents, similar rocks and fossils on different continents

B. Wegener had no evidence, which is why his theory was rejected.

C. coastline fits between different continents only

According to the given statement the number x is 2. The number x represents the dimensions of the term p * a in the given equation.

By comparing the dimensions of both sides of the equation, we find that x is equal to 2.

The equation given is:

Volume per second = k * (p * a) / n

Where:
- k is a constant
- p is the excess pressure (force per unit area)
- a is the radius of the pipe
- n is the frictional quantity of dimension MLT⁻¹


To find the number x, we need to determine the dimensions of each term in the equation.

1. Dimension of Volume per second:

  - Volume has the dimension L³ (length cubed)
  - Time has the dimension T (time)
  - Therefore, Volume per second has the dimension L³  / T

2. Dimension of k:

  - The equation states that k is a constant. Constants are dimensionless.

3. Dimension of p * a:

  - Pressure has the dimension M / (L * T² ) (mass divided by length and time squared)
  - Radius has the dimension L (length)
  - Multiplying pressure by radius results in the dimension M / (L * T² ) * L = M / (L²  * T² )

4. Dimension of n:

  - Given in the question, n has the dimension MLT⁻¹
(mass times length times time to the power of -1)

Now, we can equate the dimensions:

L³  / T = k * (M / (L²  * T² )) * MLT⁻¹


Simplifying the dimensions:

L³  / T = k * M / (L²  * T² ) * MLT⁻¹


L³  / T = k * M / L²  * M / T²  * L^-1 * T⁻¹


L³  / T = k * M²  / L²  * T⁻¹


To equate the dimensions, both sides of the equation must have the same dimensions. Therefore:

L³ / T = k * M² / L² * T⁻¹


Comparing the dimensions on both sides, we can conclude:

L³ / T = k * M² / L²* T⁻¹

The dimensions on the left side are L^3 / T, and the dimensions on the right side are (k * M²) / (L² * T).

Therefore, the number x is 2.

The number x represents the dimensions of the term p * a in the given equation.

By comparing the dimensions of both sides of the equation, we find that x is equal to 2.

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To solve this problem, you can use the equations of motion for rotational motion under constant acceleration:

ωf = ωi + αt --(1)

θ = ωit + 0.5αt^2 --(2)

where ωi is the initial angular velocity, ωf is the final angular velocity, α is the angular acceleration, t is the time elapsed, and θ is the angular displacement.

Using equation (1), we can find the angular acceleration of the wheel:

α = (ωf - ωi)/t

= (30.0 rad/s - 10.0 rad/s)/20.0 s

= 1.0 rad/s^2

Using equation (2), we can find the total angular displacement of the wheel during the 20.0 seconds:

θ = ωit + 0.5αt^2

= 10.0 rad/s × 20.0 s + 0.5 × 1.0 rad/s^2 × (20.0 s)^2

= 400.0 rad

To find the time at which the wheel has undergone half of this angular displacement, we can use equation (2) again:

θ/2 = ωit + 0.5αt^2

Rearranging and solving for t, we get:

t = [(-ωi) ± sqrt(ωi^2 + 2αθ)]/α

Since we are looking for a positive time, we take the positive root:

t = [(-10.0 rad/s) ± sqrt((10.0 rad/s)^2 + 2 × 1.0 rad/s^2 × 400.0 rad)]/1.0 rad/s^2

≈ 12.4 s

Therefore, the answer is B, 12.4 s.

Explanation:

she human activity for

Using part 1 of the fundamental theorem of calculus, we can find the derivative of g(x) as follows: g′(x) = (d/dx)∫[1,x] x7t3 dt = 7x6(x3)1 = 7x9.

The first part of the fundamental theorem of calculus is used for finding the derivative of a function. If a function is defined as the integral of another function, then the derivative of the function is the integrand. Mathematically, it is expressed as: g′(x) = (d/dx) ∫[a, x] f(t) dt

Here, g(x) = x7t3 1 dt  can be written as: g(x) = ∫[1,x] t3 dt

Since the upper limit of integration contains x, we use the chain rule for differentiation: g′(x) = (d/dx) x7t3 1 dt= (d/dx) ∫[1,x] t3 dt= x3(d/dx) [x7]= 7x6(x3)1= 7x9

Therefore, the derivative of g(x) is 7x9.

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The truck applies the same force to the car that the car applies to the truck. The truck applies the same force to the car that the car applies to the truck. According to Newton's third law, action and reaction have the same magnitude and move in the opposite direction.

Force is an external agent that can change the state of rest or motion of a body. It has a magnitude as well as a direction.

The direction of the force is the point where force is applied, and the application of force is the point where force is applied.

The concept of force is commonly explained in terms of Isaac Newton's three laws of motion, which are laid out in his Principia Mathematica.

The truck exerts the very same force on the car as the car exerts on the truck. The truck exerts this very same force on the car as the car exerts on the truck.

Action and reaction have the same amplitude and move in the opposite direction, according to Newton's third law.

Thus, this can be the comparison in the given scenario.

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Your question seems incomplete, the complete question is:

Consider the collision between a car and a

light truck whose weights are equal (M = m). If they are moving at the same speed when they collide, compare the size (or magnitude) of the forces between the car and the truck. Friction is so small that it can be ignored.

Compare the forces if the light truck is standing

still when the car hits it.

Answer:

d I believe so

Explanation:

d yes?????

a. The proper time (τ) is the time you observe, which is the time the searchlight blinks on for, given as 0.150 s.

b. The speed of the spacecraft relative to Earth is approximately 0.9999922 times the speed of light c

To determine the proper time and the speed of the spacecraft relative to Earth, we can use the concept of time dilation from special relativity. Let's denote the proper time as τ and the measured time on the spacecraft as t.

(a) To determine which of the measured times is the proper time, we need to find the time that would be measured by an observer at rest relative to the event. In this case, we assume that you, standing in your backyard, are at rest relative to the event.

Therefore, the proper time (τ) is the time you observe, which is the time the searchlight blinks on for, given as 0.150 s.

(b) To calculate the speed of the spacecraft relative to Earth, expressed as a fraction of the speed of light (c), we can use the time dilation formula,

t = γτ

where γ (gamma) is the Lorentz factor given by:

γ = 1 / √(1 - v²/c²)

Here, v represents the velocity of the spacecraft, and c is the speed of light.

We have t = 12.0 ms (converted to seconds) and τ = 0.150 s.

12.0 ms = γ * 0.150 s

γ = (12.0 ms) / (0.150 s)

= 80

To find the velocity v of the spacecraft relative to Earth, we rearrange the Lorentz factor equation,

γ = 1 / √(1 - v²/c²)

Squaring both sides of the equation, we have,

γ² = 1 / (1 - v²/c²)

Rearranging the equation to solve for v²/c², we get,

v²/c² = 1 - 1/γ²

= 1 - 1/80²

= 1 - 1/6400

= 6399/6400

To find v/c, we take the square root of both side,

v/c = √(6399/6400)

≈ 0.9999922

Therefore, the speed of the spacecraft relative to Earth is approximately 0.9999922 times the speed of light c.

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Answer:

Three (3).

Explanation:

The octet rule is a rule in chemistry that states that, chemical elements would either gain or loss electrons in their outermost shell in order to attain a stable electronic configuration i.e having eight (8) valence electrons in their outermost shell such as chemical elements found in group 8 (2-8-8) known as noble gas.

A phosphorus atom needs to gain three (3) electrons to achieve a full octet because the atomic number of phosphorus is 15 and as such it has the electronic configuration of 2-8-5 and needs three electron in order to become a stable element.

Known :

S = 205 m

t = 0.6 s

Solution :

Sound speed

v = S/t

v = (205 m)/(0.6 s)

v = 341.67 m/s

Air Temperature

v² = γRT

(341.67 m/s)² = (1.4)(286 m²/s²·K)(T)

T = 291.5 K

Electromagnetic radiation in order of their increasing frequency are as:

visible light ; ultraviolet radiation ; X-rays

From highest to lowest energy, the sections of the EM spectrum are in order as : gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation and radio waves.

Electromagnetic radiation comprises of waves of the electromagnetic field, that propagate through space and carry electromagnetic radiant energy. It has radio waves, microwaves, infrared, light, ultraviolet, X-rays, and gamma rays and all of these waves form part of the electromagnetic spectrum.

Electromagnetic radiation is produced when a charged particle like electron, changes its velocity that is whenever accelerated or decelerated. The energy of the electromagnetic radiation are produced from the charged particle and is therefore lost by it.

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Answer:

k.e.

1/2 ×2×4=4

1/2×6×4=12

m.

16×2÷4=8

20×2÷4=10

The equation that is not the correct relation for centripetal force is option (a) ᶠ = ᵐ * (ᵛ² / ᵗ)

The equation for centripetal force is given by:

F = m * (ᵛ² / r)

Where:

F is the centripetal force,

m is the mass of the object,

v is the linear velocity of the object,

r is the radius of the circular path,
which states that option (a) is correct.

Alternatively, the equation can be expressed using angular velocity:

F = m * a_c

Where:

F is the centripetal force,

m is the mass of the object,

a_c is the centripetal acceleration.
which means option (c) is correct.
Both equations represent the relationship between centripetal force, mass, and the characteristics of the circular motion. Hence, The equation that is not the correct relation for centripetal force is option (a) F = m * (ᵛ² / t)
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Answer:

90 is the best it's reasonable time

Given that the elevation of Lake Havasu is 400 feet and Lake Tahoe is 6200 feet, we need to determine which lake has a lower concentration of oxygen gas.

Higher elevation generally corresponds to lower atmospheric pressure, which affects the availability of oxygen. Therefore, Lake Havasu, located at a lower elevation, is likely to have a higher concentration of oxygen gas compared to Lake Tahoe.

The concentration of oxygen gas in water is influenced by several factors, including atmospheric pressure and temperature. As elevation increases, atmospheric pressure decreases. Lower atmospheric pressure at higher elevations results in less oxygen dissolved in water compared to lower elevations.

Lake Tahoe, situated at an elevation of 6200 feet, experiences lower atmospheric pressure compared to Lake Havasu, which is at 400 feet. Therefore, Lake Havasu is expected to have a higher concentration of oxygen gas in its water compared to Lake Tahoe.

It's important to note that factors such as temperature, circulation patterns, and biological processes also influence oxygen concentration in lakes. However, given the same water temperatures, the difference in elevation between the two lakes suggests that Lake Havasu would likely have a relatively higher concentration of oxygen gas.

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A cylindrical bit of graphite with a radius of 0.7 mm is subjected to a potential differential of 24 V along its length by the student.

Pencils, lubricants, crucibles, casting facings, polishes, arc lights, batteries, electric motor brushes, and nuclear reactor cores all include graphite. China, India, Brazil, N.korea, and Canada all mine large amounts of it. Graphite was inadvertently created for the first time by Edward G.

It is special in that it possesses traits common to both metals and non-metals, including flexibility without being elastic, high thermal and electrical conductivity, high refractoriness, and chemical inertness. Due to its low X-ray and neutron absorption, graphite is a particularly useful material.

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If one end of the pipe is closed, the maximum number of harmonics that can be heard in the normal hearing range of 20 to 20,000 Hz is approximately 56.

A closed organ pipe is a sound-producing element of the pipe organ that resonates at a specific pitch when pressurized air is driven through it [1]. The sound is produced by a pressure wave that reflects off the closed end of the pipe, creating a standing wave in the pipe. This standing wave produces harmonics at specific frequencies, which vary depending on the length of the pipe. The harmonics are multiples of the fundamental frequency.

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The frequency of the beam of light with a wavelength of 420 nm is 7.14×10¹⁴Hertz (2nd option)

Frequency of light wave is related to wavelength and speed of the light according to the following formula:

Velocity (v) = wavelength (λ) × frequency (f)

From the question given above, the following data were obtained:

The frequency can be obtained a as follow:

Velocity (v) = wavelength (λ) × frequency (f)

3×10⁸ = 420×10⁻⁹ × frequency of light wave

Divide both sides by 420×10⁻⁹

Frequency of light wave = 3×10⁸ / 420×10⁻⁹

Frequency of light wave = 7.14×10¹⁴Hertz

Thus, from the calculation, it is evident that the frequency is 7.14×10¹⁴Hertz (2nd option)

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The velocity of the electron is 2.2x10^3 m/s north. This is calculated by dividing the momentum (2.000x10^-27 kg m/s) by the mass (9.109x10^-31 kg) of the electron.

The momentum of an object is given by the product of its mass and velocity. In this case, the momentum is provided (2.000x10^-27 kg m/s) and the mass of the electron is given (9.109x10^-31 kg). By dividing the momentum by the mass, we can find the velocity. Thus, 2.000x10^-27 kg m/s divided by 9.109x10^-31 kg equals approximately 2.2x10^3 m/s north, which is the velocity of the electron.The velocity of the electron is 2.2x10^3 m/s north. This is calculated by dividing the momentum (2.000x10^-27 kg m/s) by the mass (9.109x10^-31 kg) of the electron.

The momentum of an object is given by the product of its mass and velocity. In this case, the momentum is provided (2.000x10^-27 kg m/s) and the mass of the bis given (9.109x10^-31 kg). By dividing the momentum by the mass, we can find the velocity.

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If the velocity of an object traveling in a circular path is doubled without changing the path, the force required to maintain the object's motion will be quadrupled.

Centripetal force is the quantity of force needed to maintain any motion in a circle. The centripetal force is inversely proportional to the radius of the circular path and directly connected to the square of the object's velocity.

When the velocity doubles, a factor of four more centripetal force is needed to keep the item moving (2² = 4). This is because doubling an object's velocity causes its kinetic energy to grow by a factor of 4, which in turn increases the centripetal force needed to keep it moving in a circle by a factor of 4.

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The equation that can be used to find the velocity (v⃗) of a satellite in a medium Earth orbit is v⃗ = √(G * mp / r).

The equation that can be used to find the velocity (v⃗) of a satellite placed into a medium Earth orbit is the formula for orbital velocity, which is derived from the gravitational force and centripetal force acting on the satellite. The equation is:

v⃗ = √(G * mp / r)

In this equation, G represents the universal gravitational constant, mp represents the mass of the planet (in this case, Earth) that the satellite is orbiting, and r represents the radius of the orbit. The orbital velocity is the speed at which the satellite must travel in order to maintain a stable orbit around the planet.

The equation is derived by equating the gravitational force between the satellite and the planet to the centripetal force required for the satellite to maintain a circular orbit. By solving for velocity, we can determine the speed at which the satellite needs to move to stay in orbit.

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The wave with the longest wavelength in the electromagnetic spectrum is a radio wave. Radio waves have the longest wavelength and the lowest frequency of all electromagnetic waves. They are used for broadcasting radio and television signals, as well as for communication purposes such as mobile phones and walkie-talkies.

The electromagnetic spectrum consists of various types of waves, each with different wavelengths and frequencies. As the wavelength decreases, the frequency of the wave increases, and the energy carried by the wave increases. After radio waves, the electromagnetic spectrum includes microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays.

The properties of electromagnetic waves make them versatile and useful in various fields, such as communication, medicine, and astronomy. They can travel through a vacuum, at the speed of light, and their energy can be absorbed or emitted by matter. This makes them useful for studying the properties of matter and the universe, as well as for transmitting information over long distances.

In conclusion, radio waves have the longest wavelength in the electromagnetic spectrum, and they are widely used for communication and broadcasting purposes. The electromagnetic spectrum is a valuable tool for scientists and engineers, allowing them to study and utilize the properties of electromagnetic waves for a variety of applications.

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Answer:

i. + 22.5 m ii. 4.0 m

Explanation:

i. Image distance

Using the lens formula

1/u + 1/v = 1/f where f = focal length = + 18.0 m, u = object distance = distance of shark away from lens = + 90.0 m and v = image distance from lens = unknown

So, we find v

1/v = 1/f - 1/u

= 1/+18 - 1/+90

= (5 - 1)/90

= 4/90

v = 90/4

= + 22.5 m

So the image is real and formed 22.5 m away on the other side of the lens.

ii Length of Shark

Using the magnification formula, m = image height/object height = image distance/object distance. image height = 1.0 m where object height = length of shark.

m = image distance/object distance

= v/u

= +22.5/+90

= 0.25

0.25 = image height/object height

So,

object height = image height/0.25

= 1.0 m/0.25

= 4.0 m

So, the length of the shark is 4.0 m

Answer:

true

Explanation:

they can cause skin damage

Answer:

B. where tectonic plates meet

Explanation:

Most volcanoes occur near tectonic plate boundaries. For example, a large amount are found on the Ring of Firez connecting several plates.

Answer:

B negatively charged. C negatively charged. D positively charged.

Explanation:

If A Is negative and B is repelled by it this means that B has to have the same charge as A therefore B is negatively charged.

B is repelled By C therefore meaning they both have the same charge so C has to be negatively charged.

B is attracted to D. attraction occurs between oppositely charged objects. Therefore D has to have the opposite charge of B. Since B is negative D has to be positive in order for that attraction to occur.

The speed of the ball released is 7.75 m/s.

The speed of the can be determined from the principle of conservation of energy as shown  below;

supplied energy of the dispenser = kinetic energy of the ball

Power x time = kinetic energy of the ball

10 x 15 = ¹/₂ x 5 x v²

150 = 2.5v²

v² = 150/2.5

v² = 60

v = √60

v = 7.75 m/s

Thus, the speed of the ball released is 7.75 m/s.

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Part A - The apparent displacement of the mark is 4 cm.

The refractive index of a material, n = real depth, D/apparent depth, L.

So, n = D/L

Since the refractive index of the triangular glass prism is 1.5, n = 1.5. Also, the triangular glass prism is 12 cm thick and placed on a mark on a piece of paper resting on a horizontal bench. So, the real depth of the mark on the piece of paper through the triangular prism is D = 12 cm and its apparent depth is L.

Since n = D/L,

making L, subject of the formula, we have

L = D/n

Substituting the values of the variables into the equation, we have

L = D/n

L = 12 cm/1.5

L = 8 cm

so, the apparent depth of the mark is 8 cm.

So, the apparent displacement of the mark is d = D - L = 12 cm - 8 cm = 4 cm

Thus the apparent displacement of the mark is 4 cm.

Part B - The refractive index of water, n = 1.33.

The refractive index of a material, n = real depth, D/apparent depth, L.

So, n = D/L

Since the depth of water in the jar is 24 cm, the real depth, D = 24 cm.

Also, the bottom of the jar appears to be raised by 6 cm. So, the apparent depth, L = 24 cm - 6 cm = 18 cm

Since n = D/L, the refractive index of water n = D/L

Substituting the values of the variables into the equation, we have

n = D/L

= 24 cm/18 cm

= 1.33

So, the refractive index of water, n = 1.33.

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A 20-cm long stick of m = 0.800 kg is lifted by a rope tied 6.0 cm from the upper end. The magnitude of the normal reaction from the floor on the stick is 0.234 N.

Given:

Length of the stick (L) = 20 cm = 0.20 m

Mass of the stick (m) = 0.800 kg

Distance of the rope from the upper end (d) = 6.0 cm = 0.06 m

Angle with the floor (θ) = 0° (stick is horizontal)

The magnitude of the normal force from the floor is given by:

N(A) = mg(L ÷ 2)cosΘ

N(A) = 0.400 × 9.8 × 10 × 10⁻² cosΘ

N(A) = 0.39 cosΘN

cosΘ = 7 ÷ 20

cosΘ = 0.35

Θ = 69.5°

N(A) = 0.39 × 0.35N

N(A) = 0.234 N

Therefore, the magnitude of the normal reaction from the floor on the stick is 0.234 N.

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