WHAT EVEN IS THIS???

Answer:

Step-by-step explanation:

The volume of the cube is:

The volume of the cut prism:

The base is a right triangle with legs of 2.5 each.

The volume is:

Required volume of the solid is the difference of the above volumes:

Answer:

\(\Large \boxed{\sf 109.375 \ cm^3}\)

Step-by-step explanation:

Volume of remaining solid = Volume of cube - Volume of triangular prism

Volume of cube:

\(5^3=125\)

Volume of triangular prism:

\(2.5 \times 2.5 \times 0.5 \times 5=15.625\)

Volume of remaining solid:

\(125-15.625=109.375\)

Answer:

im so so so sorry, but i dont know(possibly because im only in 7th grade with a sucky teacher)

Step-by-step explanation:

The answer is y(10° ) = -5351.5

A quadratic equation is a second-order polynomial equation in a single variable, x.

To write a quadratic relationship, consider the first three points: let it be A (0,70), B (1,69.7), and C (2,69.1).

To find the constant value, we substitute the first point in the quadratic function.

i.e   \(y=ax^{2} +bx+c\)

At point A,  the equation becomes

y=0+0+c=70

i.e c=70

At point B, the equation becomes

a+b=69.7

At point C, the equation becomes

4a+2b=69.1

By solving the two equations above, we get the values of a and b.

a=-35.15 and b=104.85

Then the quadratic relationship becomes

\(y=-35.15x^{2} +104.85x+70\)

At 11:00 A.M, the temperature becomes

y(10°) =-35.15(14*14) + 104.85(14)+70

y(10°)=-5351.5

The predicted temperature at 11.00 A.M is given by,  y(10°)=-5351.5

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The error that Vera made is she used the wrong number in her inequality to claimed the solution set on the number line represents the inequality.

In mathematics, "inequality" refers to a connection between two expressions or values that are not equal to one another. The equation-like form of the formula 5x 4 > 2x + 3 has an arrowhead in lieu of the equals sign. It is an illustration of inequity. This shows that the left half, 5x 4, is bigger than the right part, 2x + 3. Finding the x numbers for which the inequality holds true is what we are most interested in. An inequality in mathematics is a relation that compares two numbers or other mathematical expressions in an unequal way. The majority of the time, size comparisons between two numbers on the number line are made.

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The correct answer will be to reject the null hypothesis and conclude the means are different.

The appropriate test is a two-tail t-test based on the difference between two means because of the small sample sizes and the lack of data regarding the population standard deviation. The following are the alternative and null hypotheses:

\(H0:¯xA=¯xB

\)

\(Ha:x¯A≠x¯B

\)

The t-value that we will now calculate

\(t= \frac{¯xB−¯xA}{ \sqrt{ \frac{ { σ }^{2}b }{nb} + \frac{ {σ}^{2} a}{na} } }

\)

\(t= \frac{3.0−2.0}{ \sqrt{ \frac{ { 0.5 }^{2} }{14} + \frac{ {1.0}^{2} }{12} } }

\)

\(t= \frac{1.0}{ \sqrt{0.0179} + 0.0833}

\)

\(t = \frac{1.0}{ \sqrt{0.1012} } \)

\( = \frac{1.0}{0.3181} \)

\( = 3.144\)

We examine the t-statistic table's probability of receiving a t-value of that size or higher. We calculate the degrees of freedom using a lower sample size of 12, which results in a number of 11. (i.e., 12 - 1). The t-table can be used to determine the critical t-value, which can be computed as 3.106 for a two-tail test at the 1% significance level. Since our calculated t-value of 3.144 is larger than the 3.106 critical value, we reject the null hypothesis.

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The value of the triple integral z dV is 256π/35.

To evaluate the triple integral z dV, we need to set up the integral using the given bounds for E.

We can use cylindrical coordinates to represent the bounds of E. In cylindrical coordinates, the paraboloid \(z = x^2 + y^2\) is represented as \(z = r^2\), and the plane z = 4 is still z = 4. Thus, we have:

0 ≤ θ ≤ 2π (since we're integrating over the full circle)

0 ≤ r ≤ 2 (since the paraboloid intersects the plane z = 4 at z = \(2^2 = 4\))

\(r^2\) ≤ z ≤ 4 (since \(z = r^2\) for the paraboloid)

Using this, we can set up the integral:

∫∫∫ z dV = ∫\(0^2\) ∫\(0^{2\pi}\) ∫\(r^{2^{4}}\) zr dz dθ dr

Evaluating the innermost integral first, we get:

∫\(r^{2^{4}} zr dz\) = [1/2 \(z^2\)]\(r^{2^{4}}\) =\(8r^6/2 - r^4/2 = 4r^6 - r^4/2\)

Substituting this back into the integral and evaluating the next integral:

∫∫∫ z dV = ∫\(0^2 \int 0^2\pi (4r^6 - r^4/2)\)dθ dr ∫∫∫ z dV

= ∫\(0^2 (4r^6 - r^4/2)(2\pi) dr\)

\(= 2\pi [(4/7)r^7 - (1/10)r^5]\)from 0 to 2

\(= 2\pi [(4/7)(2^7) - (1/10)(2^5)] = 256\pi/35\)

Thus, the value of the triple integral z dV is 256π/35.

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Answer:

2(x - 7)(x + 2)

Step-by-step explanation:

Given

2x² - 10x - 28 ← factor out 2 from each term

= 2(x² - 5x - 14) ← factor the quadratic

Consider the factors of the constant term (- 14) which sum to give the coefficient of the x- term (- 5)

The factors are - 7 and + 2 , since

- 7 × 2 = - 14 and - 7 + 2 = - 5 , thus

x² - 5x - 14 = (x - 7)(x + 2) and

2x² - 10x - 28 = 2(x - 7)(x + 2)

Is this a real question? If so I don’t know, if not cuz people are cruel.

the sample size should be used if we would like to estimate the mean age of the college students at a particular campus with 99% confidence is 0.7168

The formula to find the sample size is given by:-

n= ( z- σ / E)^2

, where σ is the population standard deviation, z is the z-value for the

( 1-\(\alpha\))  confidence interval and E is the margin of error .

As per given , we have

Population standard deviation : σ=4.5

z-value for 95% confidence interval : z= 1.960

Margin of error : E= 3

Then, the required minimum sample :-

n= (1.96- 4.5/3)^2

this implies n = 0.7168

Hence, the required minimum sample size = 0.7168

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Answer: The fact of being correct and without any mistakes:

Step-by-step explanation: Hope this helps!

The P-value for the hypothesis test described below is ≈ 0.330677.

Given:

Use technology to find the P-value for the hypothesis test described below.

The claim is that for 12 AM body temperatures, the mean is μ<98.6°F. The sample size is n = 6 and the test statistic is

t = -1.077.

we know that ,

degrees of freedom df = n - 1

n = sample size

df = n - 1

= 6-1

= 5

t = -1.077 and df = 5

Using calculator or t table:

P-value ≈ 0.330677

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Answer:

I mean, I think it varies by house and by location but a general range would be:

Min: 64 *F

Max: 74 *F

Answer:

-120

Step-by-step explanation:

Answer:

P=6x+2

Step-by-step explanation:

P=2L+2w

P=2(2x-1)+2(x+2)

P=4x-2+2x+4                     can i get brainliest please?

P=6x+2

Answer:

The graph of a proportional relationship has the same unit rate, is a straight line, and starts at the origin.

Step-by-step explanation:

this the answer

The graph of a proportional relationship is a straight line.

The general equation of a straight line is -

y = mx + c

where -

[m] → is slope of line which tells the unit rate of change of [y] with respect to [x].

[c] → is the y - intercept i.e. the point where the graph cuts the [y] axis.

Other possible equations of lines are -

For any function y = f(x), Domain is the set of all possible values of [y] that exists for different values of [x]. Range is the set of all values of [x] for which [y] exists.

We have a graph of Molly’s garden.

Since, the graph is not given, i will write the condition for proportional relationship. The graph of a proportional relationship is a straight line whose equation is given by -

y = mx + c

Therefore, the graph of a proportional relationship is a straight line.

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Answer: 7/16

Step-by-step explanation:

Vowels: A, E, I, O, and U.

Number of Vowels in the phrase: "Do not run on Ichiro": 7

Now the total numbers of letters in the Phrase "Do not run on Ichiro": 16

For probability it is selected amount/  total amount

So 7/16, and this fraction is in its most simplified (reduced) form.

If this helped please mark me brainliest  

The probability is \(7\div 16\)

Vowels: A, E, I, O, and U.

Number of Vowels in the phrase: "Do not run on Ichiro": 7

Now the total numbers of letters in the Phrase "Do not run on Ichiro": 16

So, the probability is the same.

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Answer:

The ordered pair that is the solution to the system lies in Quadrant IV

The x-coordinate of the solution is 9

The y-coordinate of the solution is -8

Step-by-step explanation:

Answer:   \(q=\frac{112}{501}\)

Step-by-step explanation:

1) Add similar elements: 11q < 512q - 112

2) Subtract 512q from both sides: 11q - 512q < 512q - 112 - 512q

3) Simplify: -501q < -112

4) Multiply both sides by -1 to reverse the inequality: (-501q)(-1) > (-112)(-1)

5) Simplify: 501q > 112

6) Divide both sides by 501: \(\frac{501q}{501} > \frac{112}{501}\)

7) Simplify: \(q=\frac{112}{501}\)

Answer:

9.2 ft

Step-by-step explanation:

The area of a square is A = s^2 where s is the side length

A = s^2

85 = s^2

Take the square root of each side

sqrt(85) = sqrt(s^2)

sqrt(85) = s

9.219544457 =s

9.2 ft  is about the length of each side

24 divided by 11 is 2.18, repeated!

In other words, 2.1818181818... et cetera!

Hope this helps!

Answer:

2.18 (the .18 repeating)

Step-by-step explanation:

Answer:

The Domain is X and Range is Y

Step-by-step explanation:

Top values are domain and bottom values are Range

Length of the ladder = 13 m

Foot of the ladder from the wall = 5 m.

The upper end of the ladder is (13^2–5^2)^0.5 = 12 m above the ground.

In 1 second the foot of the ladder is 7 m from the wall, while the top end is (13^2–7^2)^0.5 = (169–49)^0.5 = 120^0.5 = 10.95 m. Then the top moves 1.05 m downwards.

In 2 seconds, the foot of the ladder is 9 m from the wall, while the top end is (13^2–9^2)^0.5 = (169–81)^0.5 = 88^0.5 = 9.38 m. Then the top moves 3.62 m downwards.

In 3 seconds, the foot of the ladder is 11 m from the wall, while the top end is (13^2–11^2)^0.5 = (169–121)^0.5 = 48^0.5 or 6.93 m. Then the top moves 6.07 m downwards.

So, if the foot of the ladder moves at a constant rate of 2 m/s the top end of the ladder moves downwards which varies from second to second.Answer: The lader will form the hypotenuse. Length of hypotenuse = 13m.

Let us take the horizontal distance between the wall and the ladder as ‘ground’. This g = 5m

wall ^ 2 + ground ^ 2 = 13^2 = 169

w^2 + g^2 = 169

w^2 + 25 = 169. Thus, w^2 = 144. Thus, w = 12

Rate of change of ground distance = dg / dt = 2m/s (given).

In the equation w^2 + g^2 = 169, differentiate the equation with respect to time.

2 w dw/dt + 2 g dg/dt = 0

2 (12) (dw/dt) + 2 (5) (2) = 0. So, 24 dw/dt + 20 = 0

dw/dt = -20 / 24 = -5 / 6

Thus, the height of the wall is decreasing at a rate of -5/6 m / s (that is, -0.833m/s)

The minus sign denotes that the height of the ladder is falling.

Step-by-step explanation:

Answer:

8:31

Step-by-step explanation:

all of them are equal with 1:4 except 8:31

The average cost per item over the interval (1,000,1,010] is (C(1010) - C(1000)) / (1010 - 1000) = (10,000 + 5(1010) - 10,000 - 5(1000)) / 10 = $5.50.

The average cost per item over the interval [999.5, 1000] is (C(1000) - C(999.5)) / (1000 - 999.5) = (10,000 + 5(1000) - 10,000 - 5(999.5)) / 0.5 = $5.00.

The given function C(x) represents the cost in dollars to manufacture x items. To find the average cost per item over a given interval, we use the formula: (C(b) - C(a)) / (b - a), where a and b are the endpoints of the interval.

For the interval (1,000,1,010], we substitute a = 1000 and b = 1010 into the formula to obtain (C(1010) - C(1000)) / (1010 - 1000). Simplifying the expression using the given function C(x) yields ($10,000 + $5(1010) - $10,000 - $5(1000)) / 10 = $5.50 per item.

For the interval [999.5, 1000], we substitute a = 999.5 and b = 1000 into the formula to obtain (C(1000) - C(999.5)) / (1000 - 999.5). Simplifying the expression using the given function C(x) yields ($10,000 + $5(1000) - $10,000 - $5(999.5)) / 0.5 = $5.00 per item.

To find C'(1000), we differentiate the function C(x) with respect to x, which gives C'(x) = 5. The value of C'(1000) is therefore 5, rounded to 1 decimal place.

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Answer:

78.54 millimeters

Step-by-step explanation:

A=πr^2

A= 3.14 times 5 millimeter squared

A=78.54

Answer: 15

Step-by-step explanation:

Answer:

(x+3)(x+9)=x²+12x+27

2x²+24x+54=374

2x²+24x-320=0

x²+12x-160=0

x=-20 x=8  

2cm,(-20+3)cm,(-20+9)cm

L=2cm W=-17cm H=-11

Step-by-step explanation:

Expand (x+3) and (x+9) -----> x^2+12x+27

Multiply the answer by two 2x^2+24x+54

Move 374 to the side by taking away ----->54-374=320

Divide the whole equation by 2 ---> x^2+12x-160

Factorise

The Width of cuboid is 11cm and Height of cuboid is 17 cm

An algebraic equation of the second degree in x is a quadratic equation. The quadratic equation is written as ax²+ bx + c = 0, where x is the variable, a and b are the coefficients, and c is the constant term. First, there must be a term other than zero in the coefficient of x² (a≠ 0) for an equation to be a quadratic equation. The x² term is written first when constructing a quadratic equation in standard form, then the x term, and finally the constant term. The numerical values of a, b, and c are often expressed as integral values rather than fractions or decimals.

Given:

Volume of Cuboid= 374

length= 2cm

width= x+ 3

height= x+ 9

Now, Volume of cuboid= length x width x height

2(x+3)(x+9)=374

2(x² + 12x +27)= 374

x² + 12x +27 = 187

x² + 12x -160=0

Now, factorizing

x² + 20x -8x-160=0

x( x+20) -8(x+ 20)=0

(x+ 20)(x -  8)=0

x= 8 and x= - 20

As. the dimensions cannot be negative.

So, Width= x+3 = 8+3 = 11cm

Height= x+9 = 3+9 = 17 cm

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A) f(x) = 4•(2)^x

When substituting in the values of x and y into the functions, the only function that works for both (0,4) and (1,8) is A.

8 = 4•(2)^1 = 4 x 2 = 8

4 = 4•(2)^0 = 4 x 1 = 4